Search Results

Search found 27519 results on 1101 pages for 'sql learner'.

Page 679/1101 | < Previous Page | 675 676 677 678 679 680 681 682 683 684 685 686  | Next Page >

  • adding count( ) column on each row

    - by Arsenal
    I'm not sure if this is even a good question or not. I have a complex query with lot's of unions that searches multiple tables for a certain keyword (user input). All tables in which there is searched are related to the table book. There is paging on the resultset using LIMIT, so there's always a maximum of 10 results that get withdrawn. I want an extra column in the resultset displaying the total amount of results found however. I do not want to do this using a seperate query. Is it possible to add a count() column to the resultset that counts every result found? the output would look like this: ID Title Author Count(...) 1 book_1 auth_1 23 2 book_2 auth_2 23 4 book_4 auth_.. 23 ... Thanks!

    Read the article

  • Why do these seemingly similar queries have such drastically different run times?

    - by Jherico
    I'm working with an oracle DB trying to tune some queries and I'm having trouble understanding why working a particular clause in a particular way has such a drastic impact on the query performance. Here is a performant version of the query I'm doing select * from ( select a.*, rownum rn from ( select * from table_foo ) a where rownum < 3 ) where rn >= 2 The same query by replacing the last two lines with this ) a where rownum >=2 rownum < 3 ) performs horribly. Several orders of magnitude worse ) a where rownum between 2 and 3 ) also performs horribly. I don't understand the magic from the first query and how to apply it to further similar queries.

    Read the article

  • How should I solve this MySql problem (PHP) ? (Beginner)

    - by Camran
    I have several tables in a MySql database. I have a classifieds website, and at the bottom I display the users last visited classifieds. I do this by storing the ID:s of the ads to an array in the cookie. Now, my db is made up like this kindof: Main Table: // Stores global information, ie these fields have to be filled out in every record, never be blank ID Price category Seller Item Table: // Stores descriptive info about whats for sale ID AD_ID (FK) //This is the same as ID in the MAIN TABLE Color Size Mileage etc My problem is that I need to know what category the ad is in, in order to query mysql for the right information I think. So I need two variables, but the cookie only has one (ID) stored. Offcourse I could make two queries, first one just matching the ID to the main_table and fetch the category from the Main_table. Then make the second query and fetch all other info from the right table. Here is an example if the category was Vehicles: SELECT * FROM main_table, vehicles_table, WHERE main_table.id=$id_from_cookie AND main_table.ad_id=vehicles_table.ad_id As you can see above, I need the category to write in what table to check, right? But I think there must be a smarter way, like fetching them in one single query using only one variable (id from cookie)? How should I do this? Understand? Let me know if you need more input... Thanks

    Read the article

  • Database copy between servers - user logins corrupted

    - by Steve
    When I copy a database from one server to another via backup and restore, I find I have to recreate the users in the database. I can't login as them right after the copy - I get cannot open default database, when the database that was just copied is the default database. Why is this? The logins exist on the target copy server.

    Read the article

  • What would be a good Database strategy to manage these two product options?

    - by bemused
    I have a site that allows users to purchase "items" (imagine it as an Advertisement, or a download). There are 2 ways to purchase. Either a subscription, 70 items within 1 month (use them or lose them--at the end of the month your count is 0) or purchase each item individually as you need it. So the user could subscribe and get 70/month or pay for 10 and use them when they want until the 10 are gone. Maybe it's the late hour, but I can't isolate a solution I like and thought some users here would surely have stumbled upon something similar. One I can imagine is webhosts. They sell hosting for monthy fees and sell counts of things like you get 5 free domains with our reseller account. or something like a movie download site, you can subscribe and get 100 movies each month, or pay for a one-time package of 10 movies. so is this a web of tables and where would be a good cross between the product a user has purchased and how many they have left? products productID, productType=subscription, consumable, subscription&consumable subscriptions SubscriptionID, subscriptionStartDate, subscriptionEndDate, consumables consumableID, consumableName UserProducts userID,productID,productType ,consumptionLimit,consumedCount (if subscription check against dates), otherwise just check that consumedCount is < than limit. Usually I can layout my data in a way that I know it will work the way I expect, but this one feels a little questionable to me. Like there is a hidden detail that is going to creep up later. That's why I decided to ask for help if someone in the vast expanse can enlighten me with their wisdom and experience and clue me in to a satisfying strategy. Thank you.

    Read the article

  • Persisting Serializable Objects in Hibernate

    - by VeeArr
    I am attempting to persist objects that contain some large Serializable types. I want Hibernate to automatically generate my DDL (using Hibernate annotations). For the most part, this works, but the default database column type used by Hibernate when persisting these types is tinyblob. Unfortunately, this causes crashes when attempting to persist my class, because these types will not fit within the length of tinyblob. However, if I manually set the type (using @Column(columnDefinition="longblob")), it works fine. Is there any way to make the default binary type longblob instead of tinyblob, so that I don't need to manually specify the @Column annotation on each field?

    Read the article

  • How to set up a specific registration on Database

    - by ymorenz
    I'm creating a database so I can access names of people from a university. But I would like to create a registration ID for each person like 1012607, of which the first 2 numbers would be the year (11 for 2011) and the third digit would be the semester they registered (1 in the beginning of the year and 2 in the end of the year). The other 4 digits would be incremental. I don't know how to code a prefixed number in MySQL that can change only the last 4 digits and after a year change the first 2 digits every time you have a new registration. Can someone please help me?

    Read the article

  • least value in count

    - by Nyfer
    i have a table employee(id,dept_id,salary,hire_date,job_id) . the following query i have to execute. Show all the employee who were hired on the day of the week on which least no of employee were hired. i have done the query, but am not able to get the least. please check if am correct. select id, WEEKDAY(hire_date)+1 as days,count(WEEKDAY(hire_date)+1) as count from test.employee group by days

    Read the article

  • Strange SQL problem selecting multiple values for same column

    - by Nubber
    Hello there, Been at this for a few hours now and I can't make any sense of it. I've used this way of selecting multiple values for same column a few times, but there is something weird with this one. SELECT * FROM employee as s INNER JOIN works AS w1 ON w1.name = s.name INNER JOIN employee AS w2 ON w2.name = s.name INNER JOIN employee AS w3 ON w3.name = s.name WHERE w2.city = 'Washington' Basically what I want to do is find all companies which have people in all the cities. The company name is under 'works'. The problem is however that if I have the WHERE w2.city='Washington' it will make ALL the cities match Washington when it should only touch w2 and leave w3 alone so I could match it with another value. Anyone know why its doing this? Or know a better way to do it. Thank you very much in advance.

    Read the article

  • Sorting results by a char(1) column

    - by Brandon
    I have a stored procedure which basically does something like select top 1 expiryDate, flag, (bunch of other columns) from someTable (bunch of joins) order by expiryDate desc So this will grab the record that expires last. This works for most cases, except some records have a flag that are just a char(1). Most of the time it's just Y or N. So it'll return something like 2010-12-31 N 2010-10-05 Y 2010-08-05 N 2010-03-01 F 2010-01-31 N This works, most of the time, but is there any way to order it by the Flag column as well? So I'd want to group the results by Y, then N, and F and any other flags can go last in any order. I thought this would just be an order by, but since the flags are not weighted by the alphabetic value, I'm a little stumped. (Note: These are not my tables, I don't know if using the characters like this was a good idea or not, but it's not something I can change).

    Read the article

  • SqlCE Flush Interval - Will the default setting lead to corruption?

    - by NormD
    SqlCE has a parameter set on the Connect String called Flush Interval. It is defined as: The interval time (in seconds) before all committed transactions are flushed to disk. If not specified, the default value is 10. I thought that a committed transaction, by definition, is a transaction that has been flushed to disk, specifically the database file. If a transaction is only stored in RAM then cannot the transaction be easily lost? I thought that transactions were first written to a log file and then applied to the database file itself, so perhaps this parameter could mean the time to wait until the transaction log is applied to the database file? I would have thought that this parameter should be 0.

    Read the article

  • Is a JOIN more/less efficient than EXISTS IN when no data is needed from the second table?

    - by twpc
    I need to look up all households with orders. I don't care about the data of the order at all, just that it exists. Is it more efficient to say something like this: SELECT HouseholdID, LastName, FirstName, Phone FROM Households INNER JOIN Orders ON Orders.HouseholdID = Households.HouseholdID or this: SELECT HouseholdID, LastName, FirstName, Phone FROM Households WHERE EXISTS (SELECT HouseholdID FROM Orders WHERE Orders.HouseholdID = Households.HouseholdID)

    Read the article

  • Performance problem on a query.

    - by yapiskan
    Hi, I have a performance problem on a query. First table is a Customer table which has millions records in it. Customer table has a column of email address and some other information about customer. Second table is a CommunicationInfo table which contains just Email addresses. And What I want in here is; how many times the email address in CommunicationInfo table repeats in Customers table. What could be the the most performer query. The basic query that I can explain this situation is; Select ci.Email, count(*) from Customer c left join CommunicationInfo ci on c.Email1 = ci.Email or c.Email2 = ci.Email Group by ci.Email But sure, it takes about 5, 6 minutes in execution. Thanks in Advance.

    Read the article

  • How do I display/compare a dynamic value of a mysql row in a if statement?

    - by Ralph The Mouf
    I have a checkboxes on my site that when unchecked, update their row in in the db as unchecked, and if checked,update their row in the db as checked. I am creating an ifstatement that will commence with its command if checked, and not if unchecked. I have echoed the variable and it is holding the proper value (checked or unchecked) but not sure if I am syntactically correct on displaying the state of the row in the db. This is what I am trying and will not work. I am new at php still and thank you very much for any help. if($auth->check_prof == 'checked'){// do the stuff in here}

    Read the article

  • make select @@IDENTITY; a long?

    - by acidzombie24
    I am grabbing the last rowid and i am doing this select @@IDENTITY pk = (long)cmd.ExecuteScalar(); I get an invalid typecast bc this is int instead of long. Why doesnt this return a long? can i make it return long? Solution for now is to use pk = Convert.ToInt64(cmd.ExecuteScalar());

    Read the article

  • TSQL to Map User to Database

    - by dtrick
    So I'm not able to user enterprise manager to do this... If I was I wouldn't even be asking this question. So I'm wondering if there is a way through TSQL to execute a command that maps a User to a particular Database and grants them 'owner' permissions. Thanks...

    Read the article

  • MySQL join not returning rows

    - by John
    I'm attempting to create an anti-bruteforcer for the login page on a website. Unfortunately, my query is not working as expected. I would like to test how many times an IP address has attempted to login, and also return the ID of the user for my next step in the login process. However, I'm having a problem with the query... for one thing, this would only return rows if it was the same user as they had been trying to login to before. I need it to be any user. Secondly, regardless of whether I use LEFT JOIN, RIGHT JOIN, INNER JOIN or JOIN, it will not return the user's ID unless there is a row for the user in login_attempts. SELECT COUNT(`la`.`id`), `u`.`id` FROM `users` AS `u` LEFT JOIN `login_attempts` AS `la` ON `u`.`id` = `la`.`user_id` WHERE `u`.`username` = 'admin' AND `la`.`ip_address` = '127.0.0.1' AND `la`.`timestamp` >= '1'

    Read the article

  • Please help translate this in linq to ef

    - by user3487644
    StringBuilder sb = new StringBuilder(); sb.AppendLine("SELECT"); sb.AppendLine(String.Format(" (SELECT TOP 1 CAST(ProspectID AS VARCHAR(5)) FROM Lead_Import_Fail Where ProspectID < {0} AND ProspectFullName = '{1}')", Convert.ToInt64(lead.LeadID), lead.Name)); sb.AppendLine(String.Format(", (SELECT TOP 1 CAST(ProspectID AS VARCHAR(5)) FROM Lead_Import_Fail Where ProspectID < {0} AND ProspectNRICPassport = '{1}')", Convert.ToInt64(lead.LeadID), lead.NRIC)); Thanks in advance.

    Read the article

< Previous Page | 675 676 677 678 679 680 681 682 683 684 685 686  | Next Page >