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  • SQL return ORDER BY result as an array

    - by EarthMind
    Is it possible to return groups as an associative array? I'd like to know if a pure SQL solution is possible. Note that I release that I could be making things more complex unnecessarily but this is mainly to give me an idea of the power of SQL. My problem: I have a list of words in the database that should be sorted alphabetically and grouped into separate groups according to the first letter of the word. For example: ape broom coconut banana apple should be returned as array( 'a' => 'ape', 'apple', 'b' => 'banana', 'broom', 'c' => 'coconut' ) so I can easily created sorted lists by first letter (i.e. clicking "A" only shows words starting with a, "B" with b, etc. This should make it easier for me to load everything in one query and make the sorted list JavaScript based, i.e. without having to reload the page (or use AJAX). Side notes: I'm using PostgreSQL but a solution for MySQL would be fine too so I can try to port it to PostgreSQL. Scripting language is PHP.

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  • How to get XML nodes content when names include special Characters?

    - by paoloi
    Im trying to navigate an XML block similar to this one ($doc) using PHP simplexml_load_string and using xpath on $doc to get only the 'Day' block like this: $myday = $doc->xpath ('//Day'); that lets me access all data from the block as an object, meaning $doc-AdultCount returns 1 and $doc-Id returns "6a0" however I can't access "SpecialDeals" content not using: $doc-SpecialDeals nor using: $doc-SpecialDeals-a:string Whats is the right syntax in this case? Thanks in advance. <Days> <DaysId>687</DaysId> <Day> <AdultsCount>1</AdultsCount> <Availability>Available</Availability> <Id>6a0</Id> <RoomType>Studio</RoomType> <SpecialDeals xmlns:a="http://microsoft.com/2003/Arrays"> <a:string>Best Day Ever</a:string> </SpecialDeals> </Day> <DaysPrice>247.4</DaysPrice> </Days>");

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  • how can i redirect page while download box appears?

    - by Ronnie Chester Lynwood
    Now I got this code; <?php $file = "pain.png"; if (file_exists($file)) { header('Content-Description: File Transfer'); header('Content-Type: application/octet-stream'); header('Content-Disposition: attachment; filename='.basename($file)); header('Content-Transfer-Encoding: binary'); header('Expires: 0'); header('Cache-Control: must-revalidate, post-check=0, pre-check=0'); header('Pragma: public'); header('Content-Length: ' . filesize($file)); ob_clean(); flush(); readfile($file); exit; } ?> This code appears a download box. But I want to redirect this page to "Thank You" page while download box still here. How can i do this? Thanks...

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  • Replacing mysql user authentication with openid

    - by David
    So, I'm working with a really old system which uses a person's mysql database credentials to authenticate to a web site (the database was originally only accessed from the command line, but is now accessed from a php frontend). Because of some internal reasons (and to preserve the user's history), I have to leave the old authentication intact. I've been charged with adding openid authentication to this system. Somehow I need to be able to retrieve a users mysql username and password upon logging into the site through openid (using the Zend framework, by the way). I've thought of simply requiring registration at the first login, where the user must provide their mysql credentials, but I'd rather not store the password plain text. I've also considered blanking everyone's mysql passwords, and just setting the user's mysql username manually (rather than having the user provide this, since they could provide any username). This is turning into a security nightmare. Does anyone have any suggestions for alternatives? This is running on a Linux server, by the way. Also, I can't use mysql pluggable authentication because the mysql version is 5.0 (pluggable authentication requires mysql 5.5), and no, I can't update it.

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  • Anything wrong with my cURL code (http status of 0)?

    - by Ilya
    Consistently getting a status of 0 even though if I copy and paste the url sent into my browser, I get a json object right back <?php $mainUrl = "https://api.xxxx.com/?"; $co = "xxxxx"; $pa = "xxxx"; $par = "xxxx"; $part= "xxxx"; $partn = "xxxx"; $us= "xxx"; $fields_string; $fields = array( 'co'=>urlencode($co), 'pa'=>urlencode($pa), 'par'=>urlencode($par), 'part'=>urlencode($part), 'partn'=>urlencode($partn), 'us'=>urlencode($us) ); foreach($fields as $key=>$value) { $fields_string .= $key . '=' . $value . '&' ;} $fields_string = rtrim($fields_string, "&"); $fields_string = "?" . $fields_string; $url = "https://api.xxxxx.com/" . $fields_string; $request = $url; $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_RETURNTRANSFER,1); curl_setopt($ch, CURLOPT_TIMEOUT,'3'); $content = trim(curl_exec($ch)); $http_status = curl_getinfo($ch, CURLINFO_HTTP_CODE); curl_close($ch); print $url; print $http_status; print $content; ?>

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  • Recreating http request with cURL incl. files

    - by Toby
    I consistently get the error 'failed creating formpost data' from the below code, the same thing works perfectly on my local testing server, but on my shared host it throws the error. The sample part is just to simulate building the array with both files and non-file data. Essentially all I'm trying to do here is redirect the same http request to another server, but I'm running into so many troubles. $count=count($_FILES['photographs']['tmp_name']); $file_posts=array('samplesample' => 'ladeda'); for($i=0;$i<$count;$i++) { if(!empty($_FILES['photographs']['name'][$i])) { $fn = genRandomString(); $file_posts[$fn] = "@".$_FILES['photographs']['tmp_name'][$i]; } } $ch = curl_init(); curl_setopt($ch,CURLOPT_URL,"http://myurl/wp-content/plugins/autol/rec.php"); curl_setopt($ch,CURLOPT_USERAGENT, "Mozilla/4.0 (compatible; MSIE 5.01; Windows NT 5.0)"); curl_setopt($ch,CURLOPT_HEADER,TRUE); curl_setopt($ch,CURLOPT_POST,TRUE); curl_setopt($ch,CURLOPT_POSTFIELDS,$file_posts); curl_exec($ch); print curl_error($ch); curl_close($ch);

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  • Facebook Page Statuses API

    - by Simon R
    I've got a curl function in php which posts a status update to our facebook page. However, when I post the update it makes the status appear from me personally rather than me the group. Does anyone know how you can post as administrator of the group. The script is as follows; $xPost['access_token'] = "[key]" $xPost['message'] = "Posting a message test."; $query = http_build_query($xPost); $ch = curl_init('https://graph.facebook.com/broadland/feed'); curl_setopt($ch, CURLOPT_VERBOSE, 1); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_HEADER, 1); curl_setopt($ch, CURLOPT_TIMEOUT, 120); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, $query); curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 1); curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0); curl_setopt($ch, CURLOPT_CAINFO, NULL); curl_setopt($ch, CURLOPT_CAPATH, NULL); curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 0); $result = curl_exec($ch);

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  • Why changing the images name on server results in calling the old ones?

    - by moderns
    I am running a slideshow on Ubuntu 12.04.1 that loads the images (slide1.jpg, slide2.jpg, slide3.jpg.., slide5.jpg) using the Javascript and styles as below: document.getElementById('slide_area').className='slide'+step; .slide1{background-image: url(../upload/slide1.jpg)} .slide2{background-image: url(../upload/slide2.jpg)} .slide3{background-image: url(../upload/slide3.jpg)} .slide4{background-image: url(../upload/slide4.jpg)} .slide5{background-image: url(../upload/slide5.jpg)} When I change the images names (show1.jpg, show2.jpg, show3.jpg.., show5.jpg) and also change the style as below: .slide1{background-image: url(../upload/show1.jpg)} .slide2{background-image: url(../upload/show2.jpg)} .slide3{background-image: url(../upload/show3.jpg)} .slide4{background-image: url(../upload/show4.jpg)} .slide5{background-image: url(../upload/show5.jpg)} And open the network section on Chrome, I see the server is calling the new name and old name for images! I added the header in the index.php: header("Cache-Control: no-store, no-cache, must-revalidate, max-age=0"); header("Expires: Sat, 26 Jul 1997 05:00:00 GMT"); // Date in the past header("Cache-Control: post-check=0, pre-check=0", false); header("Pragma: no-cache"); Nothing worked out with me and the slideshow doesn't work properly when I change the name of images even when clearing the browser cache as I load images sequentially (one by one) depending on imageObject.complete property! But without changing the name everything is going perfect and the images are loaded smoothly! Thank you for your help!

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  • localhost yes but phpmyadmin blank

    - by Giskin Leow
    WAMP people having problem with both localhost and phpmyadmin loads blank which usually the port problem. Mine is only phpmyadmin blank. sqlbuddy and phpinfo no problem. tried uninstall reinstalled wamp. tried xampp, same problem, all works well, not phpmyadmin. mysql log: 120905 8:03:08 [Note] Plugin 'FEDERATED' is disabled. 120905 8:03:08 InnoDB: The InnoDB memory heap is disabled 120905 8:03:08 InnoDB: Mutexes and rw_locks use Windows interlocked functions 120905 8:03:08 InnoDB: Compressed tables use zlib 1.2.3 120905 8:03:09 InnoDB: Initializing buffer pool, size = 128.0M 120905 8:03:09 InnoDB: Completed initialization of buffer pool 120905 8:03:09 InnoDB: highest supported file format is Barracuda. 120905 8:03:09 InnoDB: Waiting for the background threads to start 120905 8:03:10 InnoDB: 1.1.8 started; log sequence number 1595675 120905 8:03:11 [Note] Server hostname (bind-address): '(null)'; port: 3306 120905 8:03:11 [Note] - '(null)' resolves to '::'; 120905 8:03:11 [Note] - '(null)' resolves to '0.0.0.0'; 120905 8:03:11 [Note] Server socket created on IP: '0.0.0.0'. 120905 8:03:13 [Note] Event Scheduler: Loaded 0 events 120905 8:03:13 [Note] wampmysqld: ready for connections. apache log [Wed Sep 05 08:03:09 2012] [notice] Apache/2.2.22 (Win32) PHP/5.4.3 configured -- resuming normal operations [Wed Sep 05 08:03:09 2012] [notice] Server built: May 13 2012 13:32:42 [Wed Sep 05 08:03:09 2012] [notice] Parent: Created child process 3812 [Wed Sep 05 08:03:09 2012] [notice] Child 3812: Child process is running [Wed Sep 05 08:03:09 2012] [notice] Child 3812: Acquired the start mutex. [Wed Sep 05 08:03:09 2012] [notice] Child 3812: Starting 64 worker threads. [Wed Sep 05 08:03:09 2012] [notice] Child 3812: Starting thread to listen on port 80. [Wed Sep 05 08:03:09 2012] [notice] Child 3812: Starting thread to listen on port 80. [Wed Sep 05 08:04:14 2012] [error] [client 127.0.0.1] File does not exist: C:/wamp/www/favicon.ico [Wed Sep 05 08:09:50 2012] [error] [client 127.0.0.1] File does not exist: C:/wamp/www/favicon.ico [Wed Sep 05 08:41:03 2012] [error] [client 127.0.0.1] File does not exist: C:/wamp/www/phpMyAdmin

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  • Zend dubugger in eclipse - timeout everytime

    - by jax
    I am running a virtual server in the US. I am trying to get my eclipse machine at home (outside the USA), to connect to the USA server. I have setup Zend on the server. When I run phpinfo() I get the following zend output. Note: 1.2.3.4 will be the external WAN IP address of my ADSL router at home. Directive Local Value Master Value zend_debugger.allow_hosts 127.0.0.1,1.2.3.4 127.0.0.1,1.2.3.4 zend_debugger.allow_tunnel no value no value zend_debugger.deny_hosts no value no value zend_debugger.expose_remotely always always zend_debugger.httpd_uid -1 -1 zend_debugger.max_msg_size 2097152 2097152 zend_debugger.tunnel_max_port 65535 65535 zend_debugger.tunnel_min_port 1024 1024 So zend looks like it is working ok on the server side. When I run a debug session and select 'Test Debugger' I get a timeout every time. I have already added dummy.php to the root folder of the server. In 'installed debuggers' I double clicked on Zend and have put my external WAN IP address. I noticed that the port is 10000, I also have webmin running on this port on the server, will there be a conflict?

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  • Taking wrong database configuration array

    - by user309076
    Hi, I have one application in which i have used 2 database connections. In my database config file i have given two arrays as below. $active_group = ‘default’; $active_record = TRUE; FIRST ARRAY $db[‘default’][‘hostname’] = ‘hostname’; .............. .......... SECOND ARRAY $db[‘another_db’][‘hostname’] = ‘hostname’; .............. .......... this is working fine. Now, I copied the entire CI folder to develop another application in which only one database connection needed. So, now, in the database config file, i deleted the second configuration array. But, the db class is taking first application’s second array i.e. “another_db” and it is giving the below error. “You have specified an invalid database connection group.” When i change the default (only one) array name to “another_db” in configuration file. It is working fine. Can’t understand from where it is taking the group name as “another_db”. My application autoloads database library. I have debugged the ci_auto_loader in Loader.php class where it calls $this-database() function with no parameters. But in function database($params, $, $) {}, if I echo $params it shows “another_db”.

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  • mysql query not running correctly from inside the application

    - by Mala
    I am completely stumped. Here is my php (CodeIgniter) code: function mod() { $uid = $this->session->userdata('uid'); $pid = $this->input->post('pid'); if ($this->_verify($uid,$pid)) { $name = $this->input->post('name'); $price = $this->input->post('price'); $curr = $this->input->post('curr'); $url = $this->input->post('url'); $query = $this->db->query("UPDATE items SET name=".$this->db->escape($name).", price=".$this->db->escape($price).", currency=".$this->db->escape($curr),", url=".$this->db->escape($url)." WHERE pid=".$this->db->escape($pid)." LIMIT 1"); } header('location: '.$this->session->userdata('current')); } The purpose of this code is to modify the properties (name, price, currency, url) of a row in the 'items' table (priary key is pid). However, for some reason, allowing this function to run once modifies the name, price, currency and url of ALL entries in the table, regardless of their pid and of the LIMIT 1 thing I tacked on the end of the query. It's as if the last line of the query is being completely ignored. As if this wasn't strance enough, I replaced "$query = $this->db->query(" with an "echo" to see the SQL query being run, and it outputs a query much like I would expect: UPDATE items SET name='newname', price='newprice', currency='newcurrency', url='newurl' WHERE pid='10' LIMIT 1 Copy-pasting this into a MySQL window acts exactly as I want: it modifies the row with the selected pid. What is going on here???

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  • Error after redirection using CakePHP

    - by Praveen kalal
    I have created some code called LoginController. Whenever Admin gets successfully logged in I redirect the page to index. However, I got an error like "problem on loading page". This is my code: <?php class LoginController extends AdminAppController { var $name = 'Login'; var $uses = array('Admin.Login'); var $sessionkey= ''; /*function beforeFilter() { if($this->Session->read('user')=='Admin' || $this->params['action']=='login') { echo "in"; exit; } else { echo "else"; exit; $this->Session->setFlash('Login first','flash_failure'); $this->redirect(array('action'=>'login')); } }*/ function index() { } function login() { //pr($this->data); exit; if(!empty($this->data)) { $results = $this->Login->findByEmail($this->data['Login']['email']); if(!empty($results) && $results['Login']['password']== md5($this->data['Login']['password'])) { $this->Session->write('user', 'Admin'); $results['Login']['last_login']=date("Y-m-d H:i:s"); $this->Login->save($results); $this->Session->setFlash('Login successfully.', 'flash_success'); $this->redirect(array('controller'=>'login','action' => 'index')); } } } } ?> Can anyone help me? Thanks.

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  • Undefined Variable? But I defined it...

    - by Rob
    Well before anyone claims that theres a duplicate question... (I've noticed that people who can't answer the question tend to run and look for a duplicate, and then report it.) Here is the duplicate you are looking for: http://stackoverflow.com/questions/2481382/php-claims-my-defined-variable-is-undefined However, this isn't quite a duplicate. It gives me a solution, but I'm not really looking for this particular solution. Here is my problem: Notice: Undefined variable: custom Now here is my code: $headers = apache_request_headers(); // Request the visitor's headers. $customheader = "Header: 7ddb6ffab28bb675215a7d6e31cfc759"; //This is what the header should be. foreach ($headers as $header => $value) { $custom .= "$header: $value"; } Clearly, $custom is defined. According to the other question, it's a global and should be marked as one. But how is it a global? And how can I make it a (non-global)? The script works fine, it still displays what its supposed to and acts correctly, but when I turn on error messages, it simply outputs that notice as well. I suppose its not currently necessary to fix it, but I'd like to anyway, as well as know why its doing this.

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  • Sample twitter App

    - by Jack
    I am now running my code on a web hosting service http://xtreemhost.com/ <?php function updateTwitter($status) { $username = 'xxxxxx'; $password = 'xxxx'; $url = 'http://twitter.com/statuses/update.xml'; $postargs = 'status='.urlencode($status); $responseInfo=array(); $ch = curl_init($url); curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 2); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt ($ch, CURLOPT_POST, true); // Give CURL the arguments in the POST curl_setopt ($ch, CURLOPT_POSTFIELDS, $postargs); // Set the username and password in the CURL call curl_setopt($ch, CURLOPT_USERPWD, $username.':'.$password); // Set some cur flags (not too important) $response = curl_exec($ch); if($response === false) { echo 'Curl error: ' . curl_error($ch); } else { echo 'Operation completed without any errors<br/>'; } // Get information about the response $responseInfo=curl_getinfo($ch); // Close the CURL connection curl_close($ch); // Make sure we received a response from Twitter if(intval($responseInfo['http_code'])==200){ // Display the response from Twitter echo $response; }else{ // Something went wrong echo "Error: " . $responseInfo['http_code']; } curl_close($ch); } updateTwitter("Just finished a sweet tutorial on http://brandontreb.com"); ?> I get the following error now Curl error: Couldn't resolve host 'api.twitter.com' Error: 0 Please somebody solve my problem

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  • unicode convertion problem

    - by bhoomi-nature
    Hai frnds i am bhoomi new to php,i am having having below problem in my coding please can you help anyone 1.first i want to open one word document which is having content and i wann to edit it 2.for that i am opening word document from the server and at that time its opening with garbage value(i thing its not converting to utf8 format) 3.wen i delete that garbage value and insert something from textarea to that file it is going to insert and next time onwords its its getting open properly. 4.actually i wann that doc file should open with english words wats there in that doc instead of garbage value..first time opening only its giving problem. i am using below code for that please do the needful $filename = 'test.doc'; if(isset($_REQUEST['Submit'])){ $somecontent = stripslashes($_POST['somecontent']); // Let's make sure the file exists and is writable first. if (is_writable($filename)) { // In our example we're opening $filename in append mode. // The file pointer is at the bottom of the file hence // that's where $somecontent will go when we fwrite() it. if (!$handle = fopen($filename, 'w')) { echo "Cannot open file ($filename)"; exit; } // Write $somecontent to our opened file. if (fwrite($handle, $somecontent) === FALSE) { echo "Cannot write to file ($filename)"; exit; } echo "Success, wrote ($somecontent) to file ($filename) - Continue - "; fclose($handle); } else { echo "The file $filename is not writable"; } } else{ // get contents of a file into a string $handle = fopen($filename, 'r'); $somecontent = fread($handle, filesize($filename)); ? Edit file

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  • Is it possible to limit outside connections to a subdomain with .htaccess or similar?

    - by digidave0205
    I host a web application. This application serves static html pages that are refreshed at various intervals. Some as often as every 30 secs. At this time I have about 300 unique pages that are accessed via 300 unique subdomains. Some clients have at most 50 visitors to their unique page and it refreshes every 30 secs, no problem. Other clients have up to 1000 or more visitors to their page. These clients are killing my server. There was no predefined limit upon signup but now I have to impose such a limit to remain afloat financially. I would like to define a finite number of connections allowed for each individual subdomain in my hosting account. Connections attempted out of range of this finite value would either be rejected or redirected. I have access to .htaccess and php.ini. Is something of this nature possible? Oh, I have a dedicated/managed server at 1and1.

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  • How to search within an xml data set?

    - by user187580
    Hi, I have some xml data and I am trying to keyword search data. For example, if I search "some" for the following data it returns me the <id> and <title>. <resource> <id>101</id> <title>Test Environment</title> <description><b>Some</b> description. </description> <type>classroom</type> </resource> <resource> <id>102</id> <title>ABC Test Environment</title> <description><b>Some</b> another description. </description> <type>classroom</type> </resource> ... I had a look on on xpath e.g. $xml->xpath('//title') but looks for elements only. Basically what I need to do is to create a functionality where users can keyword search within the above data set which I receive from third party api in the above format. Any ideas how I can achieve this? using PHP/ Javascript etc. Thanks.

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  • Problem with using Jquery.ajax over .load on Zend

    - by Matthew
    Right now, what i'm trying to do is to replace a label on the front page with a block of html. Right now, the page basically has: <label id="replace"></label> the js currently has: $(document).ready(function(){ $("#replace").load('/test'); }); the Zend class function has: public function indexAction(){ $this->_helper->layout()->disableLayout(); $this->_view->message = "This is from TestController index"; } and finally the index.phtml template simply has: <?php echo $this->message;?> Right now, I want to change the code around so that instead of just replacing that label with the same message, it would do a POST where the function will pull out a parameter, do something (like for instance, go to the database and pull something out with the POST parameter) and then return the message. I've tried editing the js so that it would look like: $.post('/test', {param : "test_param"}, function(data) {$("#replace").html(data);}); or $.ajax({ type: 'POST', url: '/test', data: "{param:test_param}", contentType: "application/json; charset=utf-8", dataType: "json", success: function(data) {$("#replace").html(data);} }); and neither worked. I took a step back and tried to replicate the .load functionality and do: $.ajax({ url: '/test', success: function(data) { $('#replace').html(data); alert('Load was performed.'); } }); and it doesn't work either. Anyone have any tips on how to go about doing this?

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  • Converting json data to an HTML table

    - by dnaluz
    I have an array of data in php and I need to display this data in a HTML table. Here is what an example data set looks like. Array( Array ( [comparisonFeatureId] => 1182 [comparisonFeatureType] => Category [comparisonValues] => Array ( [0] => Not Available [1] => Standard [2] => Not Available [3] => Not Available ) [featureDescription] => Rear Seat Heat Ducts ),) The dataset is a comparison of 3 items (shown in the comparisonValues index of the array) In the end I need the row to look similar to this <tr class="alt2 section_1"> <td><strong>$record['featureDescription']</strong></td> <td>$record['comparisonValues'][0]</td> <td>$record['comparisonValues'][1]</td> <td>$record['comparisonValues'][2]</td> <td>$record['comparisonValues'][3]</td> </tr> The problem I am coming across is how to best do this. Should I create the entire table HTML on the server side pass it over an ajax call and just dump pre-rendered HTML data into a div or pass the json data and render the table client side. Any elegant suggestions? Thanks in advanced.

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  • [Concept] How does unlink() find the file to delete?

    - by Prasad
    My app has a 'Photo' field to store URL. It uses sfWidgetFormInputFileEditable for the widget schema. To delete the old image when a new image is uploaded, I use unlink before setting the value in the over-ridden setter and it works!!! if (file_exists($this->_get('photo'))) unlink($this->_get('photo')); Photos are stored in uploads/photos and when saving 'Photo' only the file name xxx-yyy.zzz is saved (and not the full path). However, I wish to know how symfony/php knows the full path of the file to be deleted? Part 2: I am using sfThumbnailPlugin to generate thumbnails. So the actual code looks like this: public function setPhoto($value) { if(!empty($value)) { Contact::generateThumbnail($value); // delete current Photo & create thumbnail $this->_set('photo',$value); // setting new value after deleting old one } } public function generateThumbnail($value) { $uploadDir = sfConfig::get('app_photo_upload'); // path to upload folder if (file_exists($this->_get('photo'))) { unlink($this->_get('photo')); // delete full-size image // path to thumbnail $thumbpath = $uploadDir.'/thumbnails/'.$this->get('photo'); // read a blog, tried setting dir manually, doesn't work :( //chdir('/thumbnails/'); // tried closing the file too, doesn't work! :( //fclose($thumbpath) or die("can't close file"); //unlink($this->_get('photo')); // doesn't work; no error :( unlink($thumbpath); // doesn't work, no error :( } $thumbnail = new sfThumbnail(150, 150); $thumbnail->loadFile($uploadDir.'/'.$value); $thumbnail->save($uploadDir.'/thumbnails/'.$value, 'image/png'); } Why can't the thumbnail be deleted using unlink()? is the sequence of ops incorrect? Is it because the old thumbnail is displayed in the sfWidgetFormInputFileEditable widget? I've spent hours trying to figure this out, but unable to nail down the real cause. Thanks in advance.

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  • jQuery not working as expected on HTTPS Internet explorer

    - by jat
    When I try to run my code on any other webbrowsers apart from the Internet explorer it works fine. But when I try to run the code on Internet explorer I do get an alert box saying HERE along with an Ok button. but the problem is when I click on that OK button I do not get anything. Ideally I should be getting another alert box. <!DOCTYPE html> <html> <head> <script src="js/jquery-1.4.2.min.js"></script> <script type="text/javascript"> $(document).ready(function(){ $("#submit").click(function(event) { alert("here"); $.post('process.php', {name:'test1',email:'test.com'}, function(data) { $('#results').html(data); alert(data); }); }); }); </script> </head> <body> <form name="myform" id="myform" action="" method="POST"> <label for="name" id="name_label">Name</label> <input type="text" name="name" id="name" size="30" value=""/> <br> <label for="email" id="email_label">Email</label> <input type="text" name="email" id="email" size="30" value=""/> <br> <input type="button" name="submit" id="submit" value="Submit"> </form> <div id="results"><div> </body> </html> Any help on this is very much appreciated. Edit: I found out that Internet Explorer which has HTTP works perfectly fine but not on Internet Explorer which uses HTTPS.

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  • Logging in with sha1() encryption.

    - by Samir Ghobril
    Hey guys, I added this to my sign up code : $password=mysql_real_escape_string(sha1($_POST['password'])); and now it inserts the password into the database while its encrypted. But signing in doesn't seem to work anymore. Here is the login code. function checklogin($username, $password){ global $mysqli; $password=sha1($password); $result = $mysqli->prepare("SELECT * FROM users WHERE username = ? and password=?"); $result->bind_param("ss", $username, $password); $result->execute(); if($result != false){ $dbArray=$result->fetch(); if(!$dbArray){ echo '<p class="statusmsg">The username or password you entered is incorrect, or you haven\'t yet activated your account. Please try again.</p><br/><input class="submitButton" type="button" value="Retry" onClick="location.href='."'login.php'\">"; return; } $_SESSION['username']=$username; if(isset($_POST['remember'])){ setcookie("jmuser",$username,time()+60*60*24*356); setcookie("jmpass",$password ,time()+60*60*24*356); } redirect(); }

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  • MySQL COUNT() total posts within a specific criteria?

    - by newbtophp
    Hey, I've been losing my hair trying to figure out what I'm doing wrong, let me explain abit about my MySQL structure (so you get a better understanding) before I go straight to the question. I have a simple PHP forum and I have a column in both tables (for posts and topics) named 'deleted' if it equals 0 that means its displayed (considered not deleted/exists) or if it equals 1 it hidden (considered deleted/doesn't exist) - bool/lean. Now, the 'specific criteria' I'm on about...I'm wanting to get a total post count within a specific forum using its id (forum_id), ensuring it only counts posts which are not deleted (deleted = 0) and their parent topics are not deleted either (deleted = 0). The column/table names are self explanatory (see my efforts below for them - if needed). I've tried the following (using a 'simple' JOIN): SELECT COUNT(t1.post_id) FROM forum_posts AS t1, forum_topics AS t2 WHERE t1.forum_id = '{$forum_id}' AND t1.deleted = 0 AND t1.topic_id = t2.topic_id AND t2.deleted = 0 LIMIT 1 I've also tried this (using a Subquery): SELECT COUNT(t1.post_id) FROM forum_posts AS t1 WHERE t1.forum_id = '{$forum_id}' AND t1.deleted = 0 AND (SELECT deleted FROM forum_topics WHERE topic_id = t1.topic_id) = 0 LIMIT 1 But both don't comply with the specific criteria. Appreciate all help! :)

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  • HELP A NEWB (AGAIN) PLZ

    - by Ken
    Okay, I must be an idiot, because this is my 3rd question for today. Here's my code: date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "********"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db("`users`, $con) or die(mysql_error()"); $query = ("INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password'))"); mysql_query('$query') or die(mysql_error()); mysql_close($con); echo("Thank you for registering!"); I always get the error returned as: "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '$query' at line 1. Help a newbie. I'm about to stab my monitor.

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