Search Results

Search found 3152 results on 127 pages for 'jq beginner'.

Page 69/127 | < Previous Page | 65 66 67 68 69 70 71 72 73 74 75 76  | Next Page >

  • Error message regarding IEnumerable.GetEnumerator().

    - by Bon_chan
    I get this error message and I can't figure out why! Error 1 'Exo5Chap12.ShortCollection<T>' does not implement interface member 'System.Collections.IEnumerable.GetEnumerator()'. 'Exo5Chap12.ShortCollection<T>.GetEnumerator()' cannot implement 'System.Collections.IEnumerable.GetEnumerator()' because it does not have the matching return type of 'System.Collections.IEnumerator'. E:\MyFolders\Dev\c#\Chapter12\Exo5Chap12\Exo5Chap12\exo5.cs 9 18 Exo5Chap12 Here is the code with an implementation of GetEnumerator(). What is wrong? public class ShortCollection<T> : IList<T> { protected Collection<T> innerCollection; protected int maxSize = 10; public IEnumerator<T> GetEnumerator() { return (innerCollection as IEnumerator<T>).GetEnumerator(); } }

    Read the article

  • Prev and next button

    - by daniel
    My website has previous and next buttons. When the page loads id like the previous button to be invisible.(on the first panel) After the user clicks the next button (to go to 2nd panel), id like the previous button to appear. Is there some javascript that will do this?

    Read the article

  • undefined GET id?

    - by Azzyh
    <?php $s = $_GET["s"]; if($s) { $hent_b = mysql_query("SELECT * FROM member_battles WHERE state = '1' ORDER BY id DESC LIMIT 0,200") or die(mysql_error()); }else{ $hent_b = mysql_query("SELECT * FROM member_battles WHERE state = '0' ORDER BY id DESC LIMIT 0,200") or die(mysql_error()); } while($vis = mysql_Fetch_array($hent_b)) { ?> I have this now i want when i enter my site (index.php) it should not come up undefined $_GET["s"]; how do i do this? but i want when you do index.php?s then it should change the query

    Read the article

  • Why is Python 3.1 throwing a SyntaxError when printing after loop? [resolved]

    - by bubersson
    Hi, I'm trying to run this snippet in Python 3.1 console and I'm getting SyntaxError: >>> while True: ... a=5 ... if a<6: ... break ... print("hello") File "<stdin>", line 5 print("hello") ^ SyntaxError: invalid syntax >>> (This is just shortened code to make a point.) Am I missing something? Is there some other Magic I don't know about? Thanks for your help (since this is my first StackOverflow question and I'm not a native English speaker)

    Read the article

  • Python: Open() using a variable

    - by nuustik
    Good day, I've ran into a problem with opening a file with randomly generated name in Python 2.6. import random random = random.randint(1,10) localfile = file("%s","wb") % random Then I get an error message about the last line TypeError: unsupported operand type(s) for %: 'file' and 'int' I just couldn't figure this out by myself nor with Google, but there has to be a cure for this, I believe. Thanks.

    Read the article

  • Representing a number in a byte array (java programming)

    - by Mark Roberts
    I'm trying to represent the port number 9876 (or 0x2694 in hex) in a two byte array: class foo { public static void main (String args[]) { byte[] sendData = new byte[1]; sendData[0] = 0x26; sendData[1] = 0x94; } } But I get a warning about possible loss of precision: foo.java:5: possible loss of precision found : int required: byte sendData[1] = 0x94; ^ 1 error How can I represent the number 9876 in a two byte array without losing precision?

    Read the article

  • If you could remove one feature of php to help newbies what would it be?

    - by Chris
    If you could remove one feature from PHP so as to discourage, prevent or otherwise help stop newer programmers develop bad habits or practices, or, to stop them falling into traps that might hinder their development skills what would it be and why? Now, before the votes to close it's not as open-ended as you might think. I'm not asking purely what is the worst feature or what feature would you really like to remove purely arbitrarily. Yes, there may not be one correct answer but I suspect there will be many similar answers which will provide me with a good idea of things I might be doing wrong, even inadvertently.

    Read the article

  • c++ projects for beginners

    - by JohnWong
    So I know this is a frequent question, but I still can't find a good one. It's a 3-week internship where I get to teach high school students. I would cover basic c++ first week, and start the project second week. What I need is a project that is doable (for them) in 2 weeks. It is interesting. Somehow I want it to be interactive (something that's cool, something that we get to use a lot or something like that)? Any idea?

    Read the article

  • Create top ten list

    - by newtech
    I'm trying to build an iPhone app where I have a list of names, and can search by year to find the top ten names for that year. How would I need to set that up in xcode?

    Read the article

  • programming help

    - by user208639
    class Person holds personal data Its constructor receives 3 parameters, two Strings representing first and last names and an int representing age public Person(String firstName, String lastName, int age) { its method getName has no parameters and returns a String with format "Lastname, Firstname" its method getAge takes no parameters and returns an int representing the current age its method birthday increases age value by 1 and returns the new age value Create the class Person and paste the whole class into the textbox below public class Person { public Person(String first, String last, int age) { getName = "Lastname, Firstname"; System.out.print(last + first); getAge = age + 1; return getAge; System.out.print(getAge); birthday = age + 1; newAge = birthday; return newAge; } } im getting errors such as "cannot find symbol - variable getName" but when i declare a variable it still not working, i also wanted to ask if i am heading in the right direction or is it all totally wrong? im using a program called BlueJ to work on.

    Read the article

  • Comparing C++ input with array values

    - by Security_Gate
    Hey everyone, Over the last couple months I've still been slowly but surely trudging through C++, and I've run into a snag that I've been meaning to figure out. I've tried asking/reading/searching, but I could never find an appropriate answer. Maybe it is simply because the question is sort of difficult to ask. What I'm trying to do is at the end of my program, have the end sequence compare the input value with values within an Array. Do I have to loop a comparison sequence? Is there an easier way around this? #include <iostream> #include <string> using namespace std; int main () { string YesAnswers[5] = {"Y", "YES", "yes" "y"}; string Name; string YN; do { cout << "Enter your name: "; getline(cin, Name); cout << "Your name is "<< Name; cout <<"\nIs this correct? Y\N: "; cin >> YN; } while(YN == YesAnswers); system("Pause"); return 0; }

    Read the article

< Previous Page | 65 66 67 68 69 70 71 72 73 74 75 76  | Next Page >