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  • syntax for MySQL INSERT with an array of columns

    - by Mike_Laird
    I'm new to PHP and MySQL query construction. I have a processor for a large form. A few fields are required, most fields are user optional. In my case, the HTML ids and the MySQL column names are identical. I've found tutorials about using arrays to convert $_POST into the fields and values for INSERT INTO, but I can't get them working - after many hours. I've stepped back to make a very simple INSERT using arrays and variables, but I'm still stumped. The following line works and INSERTs 5 items into a database with over 100 columns. The first 4 items are strings, the 5th item, monthlyRental is an integer. $query = "INSERT INTO `$table` (country, stateProvince, city3, city3Geocode, monthlyRental) VALUES ( '$country', '$stateProvince', '$city3', '$city3Geocode', '$monthlyRental')"; When I make an array for the fields and use it, as follows: $colsx = array('country,', 'stateProvince,', 'city3,', 'city3Geocode,', 'monthlyRental'); $query = "INSERT INTO `$table` ('$colsx') VALUES ( '$country', '$stateProvince', '$city3', '$city3Geocode', '$monthlyRental')"; I get a MySQL error - check the manual that corresponds to your MySQL server version for the right syntax to use near ''Array') VALUES ( 'US', 'New York', 'Fairport, Monroe County, New York', '(43.09)' at line 1. I get this error whether the array items have commas inside the single quotes or not. I've done a lot of reading and tried many combinations and I can't get it. I want to see the proper syntax on a small scale before I go back to foreach expressions to process $_POST and both the fields and values are arrays. And yes, I know I should use mysql_real_escape_string, but that is an easy later step in the foreach. Lastly, some clues about the syntax for an array of values would be helpful, particularly if it is different from the fields array. I know I need to add a null as the first array item to trigger the MySQL autoincrement id. What else? I'm pretty new, so please be specific.

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  • Image download from mysql results

    - by rozatrra
    i need to give my users the opportunity to download all the images I display in my project. images are displayed from a mysql query like this: $query = mysql_query("SELECT tl.customername, tl.visitdate, tl.employeename, pz.webpath from table tl inner join pictures pz on pz.visitid = tl.visitid and pz.groupid = tl.groupid inner join agenti ag on ag.idh = tl.employeeid WHERE tl.visitdate >= '$from' AND tl.visitdate <= '$to' AND tl.employeename like '$r_employee' AND tl.customerowner like '$r_customer' AND tl.customername like '$r_customername' AND tl.visitdate like '$r_date' group by pz.webpath order by tl.customername") or die(mysql_error()); while( $associate = mysql_fetch_assoc($query)) { echo '<li> <figure> <img src="../core/includes/timthumb.php?src='.$associate['webpath'].'&w=200&h=200" /> <figcaption> <h3>'.$associate['customername'].'</h3> <h6>'.$associate['employeename'].'</h6> <h6>'.$associate['visitdate'].' </h6> '; echo '<a class="fancybox" rel="gallery" href="'.$associate['webpath'].'" title=" '.$associate['visitdate'].' / '.$associate['customername'].'">Big picture</i></a>'; echo '</figcaption> </figure> </li>'; $zip->addFromString(pathinfo ( urldecode($associate['webpath']), PATHINFO_BASENAME), urldecode($associate['webpath'])); } How can i add a download button which will save all the images as zip on user computer?

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  • Undefined Variable? But I defined it...

    - by Rob
    Well before anyone claims that theres a duplicate question... (I've noticed that people who can't answer the question tend to run and look for a duplicate, and then report it.) Here is the duplicate you are looking for: http://stackoverflow.com/questions/2481382/php-claims-my-defined-variable-is-undefined However, this isn't quite a duplicate. It gives me a solution, but I'm not really looking for this particular solution. Here is my problem: Notice: Undefined variable: custom Now here is my code: $headers = apache_request_headers(); // Request the visitor's headers. $customheader = "Header: 7ddb6ffab28bb675215a7d6e31cfc759"; //This is what the header should be. foreach ($headers as $header => $value) { $custom .= "$header: $value"; } Clearly, $custom is defined. According to the other question, it's a global and should be marked as one. But how is it a global? And how can I make it a (non-global)? The script works fine, it still displays what its supposed to and acts correctly, but when I turn on error messages, it simply outputs that notice as well. I suppose its not currently necessary to fix it, but I'd like to anyway, as well as know why its doing this.

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  • How to open a file and remove the last line?

    - by sologhost
    I am looking to open up a file, grab the last line in the file where the line = "?", which is the closing tag for a php document. Than I am wanting to append data into it and add back in the "?" to the very last line. I've been trying a few approaches, but I'm not having any luck. Here's what I got so far, as I am reading from a zip file. Though I know this is all wrong, just needing some help with this please... // Open for reading is all we can do with zips and is all we need. if (zip_entry_open($zipOpen, $zipFile, "r")) { $fstream = zip_entry_read($zipFile, zip_entry_filesize($zipFile)); $fp = fopen($curr_lang_file, 'r+b'); while (!feof($fp)) { $output = fgets($fp, 16384); if (trim($output) == '?>') break; fwrite($fp, $output); } fclose($fp); file_put_contents($curr_lang_file, $fstream, FILE_APPEND); } $curr_lang_file is a filepath string to the actual file that needs to have the fstream appended to it, but after we remove the last line that equals '?'

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  • Problem with using Jquery.ajax over .load on Zend

    - by Matthew
    Right now, what i'm trying to do is to replace a label on the front page with a block of html. Right now, the page basically has: <label id="replace"></label> the js currently has: $(document).ready(function(){ $("#replace").load('/test'); }); the Zend class function has: public function indexAction(){ $this->_helper->layout()->disableLayout(); $this->_view->message = "This is from TestController index"; } and finally the index.phtml template simply has: <?php echo $this->message;?> Right now, I want to change the code around so that instead of just replacing that label with the same message, it would do a POST where the function will pull out a parameter, do something (like for instance, go to the database and pull something out with the POST parameter) and then return the message. I've tried editing the js so that it would look like: $.post('/test', {param : "test_param"}, function(data) {$("#replace").html(data);}); or $.ajax({ type: 'POST', url: '/test', data: "{param:test_param}", contentType: "application/json; charset=utf-8", dataType: "json", success: function(data) {$("#replace").html(data);} }); and neither worked. I took a step back and tried to replicate the .load functionality and do: $.ajax({ url: '/test', success: function(data) { $('#replace').html(data); alert('Load was performed.'); } }); and it doesn't work either. Anyone have any tips on how to go about doing this?

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  • How can I send an std::vector<std::string> over a UNIX socket?

    - by Mike
    For my application, I need to be able to send an std::vector<std::string> over a UNIX socket(local), and get a copy of the vector on the other end of the socket. What's the easiest way to do this with O(1) messages relative to the size of the vector(i.e. without sending a message for each string in the vector)? Since this is all on the same host, and because I control both ends of the socket, I'm not concerned with machine-specific issues such as endinness or vector/string representation.

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  • unicode convertion problem

    - by bhoomi-nature
    Hai frnds i am bhoomi new to php,i am having having below problem in my coding please can you help anyone 1.first i want to open one word document which is having content and i wann to edit it 2.for that i am opening word document from the server and at that time its opening with garbage value(i thing its not converting to utf8 format) 3.wen i delete that garbage value and insert something from textarea to that file it is going to insert and next time onwords its its getting open properly. 4.actually i wann that doc file should open with english words wats there in that doc instead of garbage value..first time opening only its giving problem. i am using below code for that please do the needful $filename = 'test.doc'; if(isset($_REQUEST['Submit'])){ $somecontent = stripslashes($_POST['somecontent']); // Let's make sure the file exists and is writable first. if (is_writable($filename)) { // In our example we're opening $filename in append mode. // The file pointer is at the bottom of the file hence // that's where $somecontent will go when we fwrite() it. if (!$handle = fopen($filename, 'w')) { echo "Cannot open file ($filename)"; exit; } // Write $somecontent to our opened file. if (fwrite($handle, $somecontent) === FALSE) { echo "Cannot write to file ($filename)"; exit; } echo "Success, wrote ($somecontent) to file ($filename) - Continue - "; fclose($handle); } else { echo "The file $filename is not writable"; } } else{ // get contents of a file into a string $handle = fopen($filename, 'r'); $somecontent = fread($handle, filesize($filename)); ? Edit file

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  • Read all sub directories within a certain folder to display a random image.

    - by Andy
    I have this code i have been using....but i need a conditional where it will read all the sub directories of /bg to select an image as opposed to a specific folder if they were on a subpage. Heres my code so far which works perfectly for all subpages to display specific images: //This would tell us its on the homepage if it helps: $this->level() == 0 //This is the code so far $path = '/home/sites/mydomain.co.uk/public_html/public/images/bg/'.$this->slug; $homepagefile = URL_PUBLIC.'public/images/bg/'.$this->slug.'/main.jpg'; $bgimagearray = array(); $iterator = new DirectoryIterator($path); foreach ($iterator as $fileinfo) { if ($fileinfo->isFile() && !preg_match('\.jpg$/', $fileinfo->getFilename())) { $bgimagearray[] = "'" . $fileinfo->getFilename() . "'"; } } $bgimage = array_rand($bgimagearray); ?> <div id="bg"> <div> <table cellspacing="0" cellpadding="0"> <tr> <td><img src="<?php echo $file.trim($bgimagearray[$bgimage], "'"); ?>" alt=""/></td> </tr> </table> </div> </div> Any help would be appreciated, im sure its not rocket science but ive tried a few ways and cant get my head around it. Thanks in advance.

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  • Which of these methods provides for the fastest page loading?

    - by chromedude
    I am building a database in MySQL that will be accessed by PHP scripts. I have a table that is the activity stream. This includes everything that goes on on the website (following of many different things, liking, upvoting etc.). From this activity stream I am going to run an algorithm for each user depending on their activity and display relevant activity. Should I create another table that stores the activity for each user once the algorithm has been run on the activity or should I run the algorithm on the activity table every time the user accesses the site? UPDATE:(this is what is above except rephrased hopefully in an easier to understand way) I have a database table called activity. This table creates a new row every time an action is performed by a user on the website. Every time a user logs in I am going to run an algorithm on the new rows (since the users last login) in the table (activity) that apply to them. For example if the user is following a user who upvoted a post in the activity stream that post will be displayed when the user logs in. I want the ability for the user to be able to access previous content applying to them. Would it be easiest to create another table that saved the rows that have already been run over with the algorithm except attached to individual users names? (a row can apply to multiple different users)

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  • Is a server side script necessary to process a form?

    - by jitendra
    Is a server side script necessary to send a form to email? For example, suppose I want to submit this form. Is it only possible with php asp.net etc. or it can be done with javascript only? <HTML> <HEAD> <TITLE>HTML form tutorial example</TITLE> </HEAD> <BODY> <H1>HTML form tutorial example</H1> <FORM> Name: <INPUT TYPE="TEXT" NAME="Name" VALUE="" SIZE="25" MAXLENGTH="50"> <BR> Email: <INPUT TYPE="TEXT" NAME="Email" VALUE="" SIZE="25" MAXLENGTH="50"><BR> <INPUT TYPE="SUBMIT" NAME="submit" VALUE="Sign Me Up!"> </FORM> </BODY> </HTML>

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  • Good Hosting Providers With Zend Framework Support

    - by manyxcxi
    I currently use ixwebhosting for my hosting services. They're cheap and work (most of the time). The databases are horribly slow, the servers are horribly slow, and their support (though usually prompt) is tough to deal with. That being said, they're cheap, I've got like 20 domains hosted in my account, none of them are high volume, and they work JUST good enough- until today. This isn't meant to be a condemnation of ixwh though. Their prices are very low for what they do offer and most things work just fine, most of the time. I need to be able to host web apps written with Zend Framework in a fairly easy fashion. The server performance can't be worse than what I've already had (a pretty low hurdle to clear), and I don't want to spend $30/mo. These are not money making websites- they're projects. My requirements are PHP 5.3, ZF support, MySQL databases, multiple domains- not much. Who should I look at, and who should I look out for? Also- I put this on SO instead of SF because of the Zend Framework specific requirement. If I'm wrong, do as you wish.

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  • saving mySql row checkpoint in table ?

    - by Keet
    hello, I am having a wee problem, and I am sure there is a more convenient/simpler way to achieve the solution, but all searches are throw in up a blanks at the moment ! I have a mysql db that is regularly updated by php page [ via a cron job ] this adds or deletes entries as appropriate. My issue is that I also need to check if any details [ie the phone number or similar] for the entry have changed, but doing this at every call is not possible [ not only does is seem to me to be overkill, but I am restricted by a 3rd party api call limit] Plus this is not critical info. So I was thinking it might be best to just check one entry per page call, and iterate through the rows/entires with each successive page call. What would be the best way of doing this, ie keeping track of which entry/row in the table that the should be checked next? I have 2 ideas of how to implement this: 1 ) The id of current row could be save to a file on the server [ surely not the best way] 2) an extra boolean field [check] is add to the table, set to True on the first entry and false to all other. Then on each page call it; finds 'where check = TRUE' runs the update check on this row, 'set check = FALSE' 'set [the next row] check = TRUE' Si this the best way to do this, or does anyone have any better sugestion ? thanks in advance ! .k PS sorry about the title

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  • Link my tag on other website search

    - by kresna kurdang
    This is my search code <div id="search"> <form method="get" action="http://www.other-website.com/search"> <input type="hidden" name="f" value=""> <input type="text" placeholder="Temukan informasi, komunitas & produk yang kamu cari disini" accesskey="s" name="q"> <input type="submit" value="Search"> </form> </div> This is the tag code (display only text "do not link") <?php $posttags = get_the_tags(); if ($posttags) { foreach($posttags as $tag) { echo $tag->name . ' '; } } ?> The code can apply well on the website, but I have to enter text to the search. I just want to place my tag on that search text so my question is How to make fixed word(my tag) automatically placed on search or where I must place the tag code, the search result is mytag linked on @www.other-website.com/search so user do not have to type? I want to search my tag on other website search

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  • MySQL Delete Records Older Than X Minutes?

    - by sajanNOPPIX
    I've searched quite a bit and found a few solutions that didn't end up working for me and can't understand why. I have a table with a timestamp column. The MySQL type for this column is 'datetime'. I insert into this table the following from PHP. date('Y-m-d H:i:s') This enters, what looks like the correct value for the MySQL date time. 2012-06-28 15:31:46 I want to use this column to delete rows that are older than say 10 minutes. I'm running the following query, but it's not working. It affects 0 rows. DELETE FROM adminLoginLog WHERE timestamp < (NOW() - INTERVAL 10 MINUTE); Can anyone shed some light as to what I'm doing wrong and why it's not working properly? Thanks. Update: It looks like my first issue is that I'm using DATETIME when I should be using the TIMESTAMP data type. I'm updating my code to do that now. Thanks.

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  • Preserve name of file using cURL to transfer files

    - by Toby
    I'm transferring files from an existing http request using cURL like so... $postargs = array( 'nonfilefield' =>'nonfilevalue', 'fileentry' => '@'.$_FILES['thefile']['tmp_name'][0] ); $ch = curl_init('http://localhost/curl/rec.php'); curl_setopt($ch,CURLOPT_USERAGENT, "Mozilla/4.0 (compatible; MSIE 5.01; Windows NT 5.0)"); curl_setopt($ch,CURLOPT_RETURNTRANSFER, true); curl_setopt($ch,CURLOPT_POST,TRUE); curl_setopt($ch,CURLOPT_POSTFIELDS,$postargs); curl_exec($ch); curl_close($ch); The only way I can get this to work is using the tmp_name, without this it won't send. However, I then lose the name value for when I want to name the file later. Is there some way to do this preserving the $_FILES array as it normally would be without curl? I'm also using an array of file fields in my script, so at the moment I have to convert my multidimensional array into a single dimension for this to work

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  • md5_file() not working with IP addresses?

    - by Rob
    Here is my code relating to the question: $theurl = trim($_POST['url']); $md5file = md5_file($theurl); if ($md5file != '96a0cec80eb773687ca28840ecc67ca1') { echo 'Hash doesn\'t match. Incorrect file. Reupload it and try again'; When I run this script, it doesn't even output an error. It just stops. It loads for a bit, and then it just stops. Further down the script I implement it again, and it fails here, too: while($row=mysql_fetch_array($execquery, MYSQL_ASSOC)){ $hash = @md5_file($row['url']); $url = $row['url']; mysql_query("UPDATE urls SET hash='" . $hash . "' WHERE url='" . $url . "'") or die("MYSQL is indeed gay: ".mysql_error()); if ($hash != '96a0cec80eb773687ca28840ecc67ca1'){ $status = 'down'; }else{ $status = 'up'; } mysql_query("UPDATE urls SET status='" . $status . "' WHERE url='" . $url . "'") or die("MYSQL is indeed gay: ".mysql_error()); } And it checks all the URL's just fine, until it gets to one with an IP instead of a domain, such as: http://188.72.215.195/config.php In which, again, the script then just loads for a bit, and then stops. Any help would be much appreciated, if you need any more information just ask.

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  • MySQL COUNT() total posts within a specific criteria?

    - by newbtophp
    Hey, I've been losing my hair trying to figure out what I'm doing wrong, let me explain abit about my MySQL structure (so you get a better understanding) before I go straight to the question. I have a simple PHP forum and I have a column in both tables (for posts and topics) named 'deleted' if it equals 0 that means its displayed (considered not deleted/exists) or if it equals 1 it hidden (considered deleted/doesn't exist) - bool/lean. Now, the 'specific criteria' I'm on about...I'm wanting to get a total post count within a specific forum using its id (forum_id), ensuring it only counts posts which are not deleted (deleted = 0) and their parent topics are not deleted either (deleted = 0). The column/table names are self explanatory (see my efforts below for them - if needed). I've tried the following (using a 'simple' JOIN): SELECT COUNT(t1.post_id) FROM forum_posts AS t1, forum_topics AS t2 WHERE t1.forum_id = '{$forum_id}' AND t1.deleted = 0 AND t1.topic_id = t2.topic_id AND t2.deleted = 0 LIMIT 1 I've also tried this (using a Subquery): SELECT COUNT(t1.post_id) FROM forum_posts AS t1 WHERE t1.forum_id = '{$forum_id}' AND t1.deleted = 0 AND (SELECT deleted FROM forum_topics WHERE topic_id = t1.topic_id) = 0 LIMIT 1 But both don't comply with the specific criteria. Appreciate all help! :)

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  • How to randomly assign a partner?

    - by David
    I asked a question some time ago about creating a random circular partner assignment using php and mysql. This is a related issue. I am working from the following code to try to give two users new, randomly selected partners: $q = "SELECT user_id FROM users WHERE partner='$quit_partner' AND status='1'"; $r = mysqli_query ($dbc, $q) or trigger_error("Query: $q\n<br />MySQL Error: " . mysqli_error($dbc)); while ($row = mysqli_fetch_array($r)) { $users[] = $row[0]; } $current = end($users); $partners = array(); foreach ($users as $user) { $partners[$user] = $current; $current = $user; $q = "UPDATE users SET partner='{$partners[$user]}' WHERE user_id='{$user}'"; mysqli_query ($dbc, $q) or trigger_error("Query: $q\n<br />MySQL Error: " . mysqli_error($dbc)); } Basically, a particular user (lets say user #4) quits the activity, leaving multiple other users without a partner (hypothetically, users # 5,6,7). I need to find out who those users are, hence the first query. Once I find them, I throw them into an array. Then comes the difficult part. I want those newly partnerless users (5,6,7) to be randomly assigned new partners from everyone in the table. The current code is flawed in that it only assigns the newly partnerless users eachother. Thanks for your help.

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  • HELP A NEWB (AGAIN) PLZ

    - by Ken
    Okay, I must be an idiot, because this is my 3rd question for today. Here's my code: date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "********"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db("`users`, $con) or die(mysql_error()"); $query = ("INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password'))"); mysql_query('$query') or die(mysql_error()); mysql_close($con); echo("Thank you for registering!"); I always get the error returned as: "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '$query' at line 1. Help a newbie. I'm about to stab my monitor.

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  • Password protect user image album

    - by Poland Rocks
    Hi Im making i photo sharint site I want to give the ability for my users to prevent the public to acces their albums with a password. Then they can give the password to the ones they want to be able to see it. To password protect their albums. Im thinking something like this, cant test it on this computer, should work ok. but as im a php/mysql beginner i wanna hear what you experts think if theres a better way/approach Albums id name owner password (if it isnt null the album is considered password protected) The code $id = isset($_GET['albumID']) ? intval($_GET['albumID']) : 0; $result = mysql_query("SELECT * FROM albums WHERE id = $id"); $row = mysql_fetch_object($result); // IS it password protected? if ($row->password != NULL) { echo "This album is password protected."; // User pressed "Enter" if (!empty($_POST['password'])) { $result = mysql_query("SELECT password FROM albums WHERE password = '".mysql_real_escape_string($_POST['password'])."'"); // Was It right password? if (mysql_num_rows($result) == 1) { $authed=1; } echo << <form method="post"> <input type="text" name="password" /> EOT; exit; } else $authed=1; if $authed==1 { // render albumimages etc }

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  • Logging in with sha1() encryption.

    - by Samir Ghobril
    Hey guys, I added this to my sign up code : $password=mysql_real_escape_string(sha1($_POST['password'])); and now it inserts the password into the database while its encrypted. But signing in doesn't seem to work anymore. Here is the login code. function checklogin($username, $password){ global $mysqli; $password=sha1($password); $result = $mysqli->prepare("SELECT * FROM users WHERE username = ? and password=?"); $result->bind_param("ss", $username, $password); $result->execute(); if($result != false){ $dbArray=$result->fetch(); if(!$dbArray){ echo '<p class="statusmsg">The username or password you entered is incorrect, or you haven\'t yet activated your account. Please try again.</p><br/><input class="submitButton" type="button" value="Retry" onClick="location.href='."'login.php'\">"; return; } $_SESSION['username']=$username; if(isset($_POST['remember'])){ setcookie("jmuser",$username,time()+60*60*24*356); setcookie("jmpass",$password ,time()+60*60*24*356); } redirect(); }

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  • How to get a category listing from Magento?

    - by alex
    I want to create a page in Magento that shows a visual representation of the categories.. example CATEGORY product 1 product 2 ANOTHER CATEGORY product 3 My problem is, their database is organised very differently to what I've seen in the past. They have tables dedicated to data types like varchar, int, etc. I assume this is for performance or similiar. I haven't found a way to use MySQL to query the database and get a list of categories. I'd then like to match these categories to products, to get a listing of products for each category. Unfortunately Magento seems to make this very difficult. Also I have not found a method that will work from within a page block.. I have created showcase.phtml and put it in the XML layout and it displays and runs it's PHP code. I was hoping for something easy like looping through $this-getAllCategories(); and then a nested loop inside with something like $category-getChildProducts(); Can anyone help me? Thank you!

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  • How would i output a message that says "values inserted to table" ?

    - by ranlo
    <?php error_reporting(0); $con=mysql_connect("localhost","root",""); if (!$con) { die('could not connect:'.mysql_error()); } mysql_select_db("final?orgdocs",$con); $org_name = $_POST["org_name"]; $org_type = $_POST["org_type"]; $org_code = $_POST["org_code"]; $description = $_POST["description"]; $stmt = "INSERT INTO organization VALUES('".$org_name."','".$org_type."','".$org_code."','".$description."')"; $result = mysql_query("SELECT * FROM organization WHERE org_name = '$org_name' "); echo '<TABLE BORDER = "1">'; $result1 = $result; while ($row = mysql_fetch_array($result1)){ echo '<TR>'.'<TD>'.'Organization Name'.'</TD>'.'<TD>'.'Organization Type'.'</TD>'.'<TD>'.'Organization Code'.'</TD>'.'<TD>'.'Description'.'</TD>'.'<TD>'.'Constitution'.'</TD>'; echo '</TR>'; echo '<TR>'.'<TD>'.$row['org_name'].'</TD>'.'<TD>'.$row['org_type'].'</TD>'; echo '<TD>'.$row['org_code'].'</TD>'.'<TD>'.$row['description'].'</TD>'.'<TD>'; echo '</TR>'; } echo '</TABLE>'; ?>

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  • getting webpage contents using curl_init not working for some links

    - by Manish
    I am using this code to get contents of a url entered:- class MetaTagParser { public $metadata; private $html; private $url; public function __construct($url) { $this->url=$url; $this->html= $this->file_get_contents_curl(); $this->set_title(); $this->set_meta_properties(); } public function file_get_contents_curl() { $ch = curl_init(); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_URL, $this->url); curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1); $data = curl_exec($ch); curl_close($ch); return $data; } public function set_title() { $doc = new DOMDocument(); @$doc->loadHTML($this->html); $nodes = $doc->getElementsByTagName('title'); $this->metadata['title'] = $nodes->item(0)->nodeValue; } this class works for some pages but for some url like this one - http://www.dnaindia.com/india/report_in-a-first-upa-govt-tweets-the-press_1745346 when I try to fetch data I get this error:-"Warning: get_meta_tags(http://www.dnaindia.com/india/report_in-a-first-upa-govt-tweets-the-press_1745346): failed to open stream: HTTP request failed! HTTP/1.1 403 Forbidden in C:\xampp\htdocs\prac\index.php on line 52" it is not working, any ideas why this is happening??

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  • Cannot reach reach jQuery (in parent document ) from IFRAME

    - by Michael Joyner
    I have written a backup program for SugarCRM. My program sets a iframe to src=BACKUP.PHP My backup program sends updates to parent window with: echo "<script type='text/javascript'>parent.document.getElementById('file_size').value='".fileSize2human(filesize($_SESSION['archive_file_name']))."';parent.document.getElementById('file_count').value=".$_SESSION['archive_file_count'].";parent.document.getElementById('description').innerHTML += '".$log_entry."\\r\\n';parent.document.getElementById('description').scrollTop = parent.document.getElementById('description').scrollHeight;</script>"; echo str_repeat( ' ', 4096); flush(); ob_flush(); I have added a JQUERY UI PROGRESS BAR and I need to know how I update the progress bar on the parent window. I tried this: $percent_complete = $_SESSION['archive_file_count'] / $_SESSION['archive_total_files']; echo "<script type='text/javascript'>parent.document.jquery('#progressbar').animate_progressbar($percent_complete); </script>"; ......... and get this error in browser. Uncaught TypeError: Object [object HTMLDocument] has no method 'jquery' HOW CAN I UPDATE THE PROGRESS BAR IN PARENT DOCUMENT FROM THE IFRAME?

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