Enums, Constructor overloads with similar conversions.
- by David Thornley
Why does VisualC++ (2008) get confused 'C2666: 2 overloads have similar conversions' when I specify an enum as the second parameter, but not when I define a bool type?
Shouldn't type matching already rule out the second constructor because it is of a 'basic_string' type?
#include <string>
using namespace std;
enum EMyEnum { mbOne, mbTwo };
class test {
public:
#if 1 // 0 = COMPILE_OK, 1 = COMPILE_FAIL
test(basic_string<char> myString, EMyEnum myBool2) { }
test(bool myBool, bool myBool2) { }
#else
test(basic_string<char> myString, bool myBool2) { }
test(bool myBool, bool myBool2) { }
#endif
};
void testme() {
test("test", mbOne);
}
I can work around this by specifying a reference 'ie. basic_string &myString' but not if it is 'const basic_string &myString'.
Also calling explicitly via "test((basic_string)"test", mbOne);" also works.
I suspect this has something to do with every expression/type being resolved to a bool via an inherent '!=0'.
Curious for comments all the same :)
