Search Results

Search found 18395 results on 736 pages for 'admin interface'.

Page 71/736 | < Previous Page | 67 68 69 70 71 72 73 74 75 76 77 78  | Next Page >

  • Perfom python unit tests via a web interface

    - by 47
    Is it possible to perform unittest tests via a web interface...and if so how? EDIT: For now I want the results...for the tests I want them to be automated...possibly every time I make a change to the code. Sorry I forgot to make this more clear

    Read the article

  • How to create multiple inputs in yii + Q&A admin page

    - by user1764357
    In yii, i am developing page for Creating Question with multiple options using forms. So i have two tables Question QuestionId Question optionId Option OptionId Option To create multiple options, option field should be provided with add button so that after clicking add button, it should display new textbox control to get the new option. All these options displayed in a gridview. So can you please help me. I am very new to yii.

    Read the article

  • image with external interface

    - by Leo
    I need to send a picture to flash with external interface (as3)... can not be an url because don't have connection... I'm trying open the image file and send to flash like text but without success any idea?

    Read the article

  • add new records using signal in django admin

    - by ganesh
    I've a model called broadcastinfo, It has fields viz.. info,userid...userid is excluded. when i add an new info, my broadcastinfo table should get the records of all userid from user table and the given message. Im trying this via signal.Any idea is highly appreciated. Thanks

    Read the article

  • Easily reuse views, controller, layout in a command line interface

    - by Alex
    My Zend application is going to get an command line php script that should email reports. There generation depends on Zend_View, Zend_Layout and is currently already working fine in the web interface. How can I reuse this whole MVC functionality in the command line? Should I add a new controller CommandLineController and call this somehow from the commandline? How can I kick of such a Controller manually, without having a HTTP request?

    Read the article

  • There's @interface in my @implementation — why is that?

    - by Mark McDonald
    This is a pretty noobish question – I'm looking at some Cocoa sample code and there's @interface blocks in the .m files as well as the headers. For instance, in the AppDelegate class header, a UIWindow and UI navigation are defined as instance variables, but the @property declarations are actually made in the implementation file. Is there a functional reason for this, is it a stylistic choice, or… ?

    Read the article

  • Add menu option to SMS interface

    - by lq410
    Hi, I'm looking for a way to add a new custom menu item to the SMS interface. The idea is add an option like "Insert predefined message", and control the predefined message from other application. Is this possible?

    Read the article

  • Implementing a plugin interface

    - by James P.
    What's a good way of adding a plugin interface such that it's possible to have optional components? I'm aware of the Class.forName() approach (used with JDBC for example) but there is also dynamic class loading.

    Read the article

  • Default http/admin port in dropwizard project

    - by mithrandir
    I have a dropwizard project and I have maintained a config.yml file at the ROOT of the project (basically at the same level as pom.xml). Here I have specified the HTTP port to be used as follows: http: port:9090 adminPort:9091 I have the following code in my TestService.java file public class TestService extends Service<TestConfiguration> { @Override public void initialize(Bootstrap<TestConfiguration> bootstrap) { bootstrap.setName("test"); } @Override public void run(TestConfiguration config, Environment env) throws Exception { // initialize some resources here.. } public static void main(String[] args) throws Exception { new TestService().run(new String[] { "server" }); } } I expect the config.yml file to be used to determine the HTTP port. However the app always seems to start with the default ports 8080 and 8081. Also note that I am running this from eclipse. Any insights as to what am I doing wrong here ?

    Read the article

  • is it possible to get the class of the interface <Set>

    - by user1164885
    Am having some arguments say (String a, Treeset b, Set c) and i try to get the class by arguments[i].getClass(); of the above arguments.. is it possible to get the class of the interface . ex., Class[] argumentTypes = new Class [arguments.length]; for (int i = 0 ; i < arguments.length ; i++) { argumentTypes[i] = arguments[i].getClass(); }

    Read the article

  • Django and ImageField Question

    - by Hellnar
    Hello I have a such model: Foo (models.Model): slug = models.SlugField(unique=True) image = models.ImageField(upload_to='uploads/') I want to do two things with this: First of all, I want my image to be forced to resize to a specific width and height after the upload. I have tried this reading the documentation but seems to getting error: image = models.ImageField(upload_to='uploads/', height_field=258, width_field=425) Secondly, when adding an item via admin panel, I want my image's file name to be renamed as same as slug, if any issue arises (like if such named image already exists, add "_" to the end as it used to do. IE: My slug is i-love-you-guys , uploaded image such have i-love-you-guys.png at the end.

    Read the article

  • Inline editing of ManyToMany relation in Django

    - by vorpyg
    After working through the Django tutorial I'm now trying to build a very simple invoicing application. I want to add several Products to an Invoice, and to specify the quantity of each product in the Invoice form in the Django admin. Now I've to create a new Product object if I've got different quantites of the same Product. Right now my models look like this (Company and Customer models left out): class Product(models.Model): description = models.TextField() quantity = models.IntegerField() price = models.DecimalField(max_digits=10,decimal_places=2) tax = models.ForeignKey(Tax) class Invoice(models.Model): company = models.ForeignKey(Company) customer = models.ForeignKey(Customer) products = models.ManyToManyField(Product) invoice_no = models.IntegerField() invoice_date = models.DateField(auto_now=True) due_date = models.DateField(default=datetime.date.today() + datetime.timedelta(days=14)) I guess the quantity should be left out of the Product model, but how can I make a field for it in the Invoice model?

    Read the article

  • Default value for field in Django model

    - by Daniel Garcia
    Suppose I have a model: class SomeModel(models.Model): id = models.AutoField(primary_key=True) a = models.IntegerField(max_length=10) b = models.CharField(max_length=7) Currently I am using the default admin to create/edit objects of this type. How do I set the field 'a' to have the same number as id? (default=???) Other question Suppose I have a model: event_date = models.DateTimeField( null=True) year = models.IntegerField( null=True) month = models.CharField(max_length=50, null=True) day = models.IntegerField( null=True) How can i set the year, month and day fields by default to be the same as event_date field?

    Read the article

  • Can't set up image upload in Django

    - by culebrón
    I can't understand what's not working here: 1) settings MEDIA_ROOT = '/var/www/satel/media' MEDIA_URL = 'http://media.satel.culebron' ADMIN_MEDIA_PREFIX = '/media/' 2) models class Photo(models.Model): id = models.AutoField(primary_key=True) name = models.CharField(max_length = 200) desc = models.TextField(max_length = 1000) img = models.ImageField(upload_to = 'upload') 3) access rights: drwxr-xrwx 3 culebron culebron 4.0K 2010-04-14 21:13 media drwxr-xrwx 2 culebron culebron 4.0K 2010-04-14 19:04 upload 4) SQL: CREATE TABLE "photos_photo" ( "id" integer NOT NULL PRIMARY KEY, "name" varchar(200) NOT NULL, "desc" text NOT NULL, "img" varchar(100) NOT NULL ); 4) run Django test server as myself. 5) result: SuspiciousOperation at /admin/photos/author/add/ Attempted access to '/var/www/satel/upload/OpenStreetMap.png' denied. Not a PIL & jpeg issue, seems not to be access rights issue. But what's wrong?

    Read the article

  • Django Caught an exception while rendering: No module named registration

    - by Arno Smit
    I seem to have run into a bit of an issue. I am busy creating an app, and over the last few weeks setup my server to use Git, mod_wsgi to host this app. Since deploying it, everything seems to be running smoothly however, I had to go through all my files and insert the absolute url of the project to make sure it works fine. on my local machine from registration.models import UserRegistration on server from myapp.registration.models import UserRegistration Am I doing something wrong? And this has also caused an issue for me where I cannot access my django admin interface. All i get is this: Caught an exception while rendering: No module named registration Exception Value: Caught an exception while rendering: No module named registration As far as I am concerned my app has all the relevant urls, but it does not seem to work. Thank you in advance

    Read the article

  • Django make model field name a link

    - by Daniel Garcia
    what Im looking to do is to have a link on the name of a field of a model. So when im filling the form using the admin interface i can access some information. I know this doesn't work but shows what i want to do class A(models.Model): item_type = models.CharField(max_length=100, choices=ITEMTYPE_CHOICES, verbose_name="<a href='http://www.quackit.com/html/codes'>Item Type</a>") Other option would be to put a description next to the field. Im not even sure where to start from.

    Read the article

  • Alternate datasource for django model?

    - by slypete
    I'm trying to seamlessly integrate some legacy data into a django application. I would like to know if it's possible to use an alternate datasource for a django model. For example, can I contact a server to populate a list of a model? The server would not be SQL based at all. Instead it uses some proprietary tcp based protocol. Copying the data is not an option, as the legacy application will continue to be used for some time. Would a custom manager allow me to do this? This model should behave just like any other django model. It should even pluggable to the admin interface. What do you think? Thanks, Pete

    Read the article

  • Computer Vision application(+web interface) for face detection and recognition from database

    - by Kush
    My project is a computer vision java application which should implement the following : A web interface through which the form entry+images(for example a student data) will be stored into a database(Mysql) & images into directory common to my java application. Then the data & images can be retrieved from my java Gui application and I can perform the following operations of image processing through OpenCV. Actually,I want to run the face detection on images retrieved and discard the false entries(no proper face). Also the application user/admin can search an image based on text search(By Id) or By another reference image using face recognition. I am well familiar with Java but the problem is that I need a guidance on how to organise it in a stepwise manner(links appreciated).OpenCv,Php and mySql are really messy.I know doing the openCV stuff within java is real overhead but i really want to do it.But If there is any suggestion to do it elseway please guide me.So any kind of help is a ray of hope for me. Thanks.

    Read the article

< Previous Page | 67 68 69 70 71 72 73 74 75 76 77 78  | Next Page >