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  • Autocomplete and User define keyboard

    - by Geetha
    Hi All, I am using asp:button to create a keyboard with A-Z and 0-9 for touch screen using Java script. This keyboard is linked with one textbox. If we click one button corresponding text will be displayed on the textbox. Its working fine. I have included the autocomplete feature to this textbox using jquery JQuery Autocomplete. Problem: The autocomplete is not working if i my user define keyboard. How to modify my key buttons as keyboard keys? Is it possible? Is there any other way to achieve this? Code: <asp:TextBox ID="txtSearch" runat="server"></asp:TextBox> <asp:Button ID="zero" runat="server" Text="0" CssClass="myclass" OnClientClick="return typeLetter(this);" TabIndex="20"/> function typeLetter(currentbutton) { if (previousActiveElement != null) { if (previousActiveElement == 'antSearchText'){ var position = document.getElementById('position').value; if (position == '') { alert('chk position'); } else { var existingString = document.getElementById(previousActiveElement).value; var beforeString = existingString.substring(0, position); var afterString = existingString.substring(position, existingString.length); document.getElementById(previousActiveElement).value = beforeString + currentbutton.value + afterString; setCaretPosition(document.getElementById(previousActiveElement), parseInt(position) + 1); setCaretPosition(document.getElementById(previousActiveElement), parseInt(position) + 1); } } } return false; }

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  • iPhone scrolling the view up when keyboard is open

    - by Rob
    I understand that this problem is incredibly common and I have read through quite a few answers but am having trouble understanding how the code works. This works: -(void)textFieldDidBeginEditing:(UITextField *)sender { if ([sender isEqual:txtLeaveAddyLine1]) { //move the main view, so that the keyboard does not hide it. if (self.view.frame.origin.y >= 0) { [self setViewMovedUp:YES]; } } } In this example, txtLeaveAddy is the very first UITextField that is hidden by the keyboard and it works like a charm. As I cycle through the text fields on the screen it scrolls up when the user enters into that txtLeaveAddyLine1 field. However, when I try to add the fields below the txtLeaveAddyLine1 field - nothing happens. For example: -(void)textFieldDidBeginEditing:(UITextField *)sender { if ([sender isEqual:txtLeaveAddyLine1]) { //move the main view, so that the keyboard does not hide it. if (self.view.frame.origin.y >= 0) { [self setViewMovedUp:YES]; } } if ([sender isEqual:txtLeaveAddyLine2]) { //move the main view, so that the keyboard does not hide it. if (self.view.frame.origin.y >= 0) { [self setViewMovedUp:YES]; } } } Am I not using this function correctly?

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  • antlr3StringStreamNew string input error [ at offset 0, at <EOF> : cannot match to any predicted input... ]

    - by Embeguru
    I'm using ANTLR 3.4 with simplecTreeParser example and want to give string input from main.c I'v modified input in main as mentioned bellow pANTLR3_UINT8 input_string = (pANTLR3_UINT8)"int a;"; input = antlr3StringStreamNew(input_string, ANTLR3_ENC_8BIT, sizeof(input_string),(pANTLR3_UINT8)"ABCD"); Apparently getting following error -end of input-(1) : error 3 : 23:1: declaration : ( variable | functionHeader ';' - ^( FUNC_DECL functionHeader ) | functionHeader block - ^( FUNC_DEF functionHeader block ) );, at offset 0, at : cannot match to any predicted input... The parser returned 1 errors, tree walking aborted. Any other way to give String input Regards

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  • Input system reference trouble

    - by Ockonal
    Hello, I'm using SFML for input system in my application. size_t WindowHandle; WindowHandle = ...; // Here I get the handler sf::Window InputWindow(WindowHandle); const sf::Input *InputHandle = &InputWindow.GetInput(); // [x] Error At the last lines I have to get reference for the input system. Here is declaration of GetInput from documentation: const Input & sf::Window::GetInput () const The problem is: >invalid conversion from ‘const sf::Input*’ to ‘sf::Input*’ What's wrong?

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  • input file cannot be found

    - by Eric Smith
    I am just messing around with reading input files with java until I got stumped at the most basic of steps... finding the input file! The input.txt file is in the same directory as my class file that is calling it yet eclipse still gives me an error that it cant be found: "Exception in thread "main" java.lang.Error: Unresolved compilation problem: Unhandled exception type FileNotFoundException" My code: package pa; import java.util.Scanner; public class Project { public static void main(String[] args) { java.io.File file = new java.io.File("input.txt"); System.out.println(file.getAbsolutePath()); Scanner input = new Scanner(file); } } input.txt is in the same package, same folder and everything. I'm confused :(

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  • Font-awesome, input type 'submit'

    - by denis.peplin
    It seems no class for input type 'submit' in font-awesome. Is it possible to use some class from font-awesome for button input? I've added icons to all buttons (which actually links with class 'btn' from twitter-bootstrap) in my applications, but can't add icons on 'input type submit'. Or, how to use this code: input#image-button{ background: #ccc url('icon.png') no-repeat top left; padding-left: 16px; height: 16px; } html: <input type="submit" id="image-button">Text</input> (which I took from HTML: How to make a submit button with text + image in it?) with font-awesome?

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  • How to make softkeyboard candidate view not block application view?

    - by Cedric
    Hi, I am playing with the Demo SoftKeyboard the comes with the Android SDK. In portrait mode when the candidate view is shown, it doesn't move the app up as the default android keyboard does. Hence it covers part of the application view. What should be changed in order to make the candidate view in the demo softkeyboard behave as the default android keyboard does? I've also looked at the source of the android keyboard from git but found nothing related to this behavior.

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  • Supersede users need to press enter after inputting a string in python 3.0

    - by Cimex
    I've been attempting to create a simple Rock, Paper, Scissors game in python 3.0 -- very standard task for anybody learning programming. But, as I finish up to a point, I think,"wow, that'd be awesome", or,"it'd be cool to do this!" So anyways, I keep building upon the project... I've developed a menu, a single player game vs the computer, and just finished the multiplayer game. But, I've realized, that the multiplayer game isn't very effective. It just dosen't work like the analog version of the game. Currently, it'll ask for player1's input, then player2's input, compare them, and spit out the result and the current score. What I'd rather have happen is that the program asks for both players input at the same time and both players input their choice at the same time. I understand that I can easily do that by just grabbing the index of the first and second answer and compare the 2 inputs -- easy. But what I'd rather have happen is that after both players enter their one character answers at the same time (r for rock, p for paper, or s for scissors), then the program will auto enter the input. Not needing someone to press enter. The input would be dictated by the fact that 2 characters have been entered. I guess my question is: Is there any way to dictate what can be used as an input for 'enter'?

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  • Use JQuery to check a checkbox in a parent list-item?

    - by Daniel O'Connor
    Hey Everyone, I'm brand new to Javascript and JQuery, so I've been reading up on it and am trying to check (and set inactive) a checkbox in a parent list-item when one of the children are checked. If this doesn't make any sense, take a look at the list structure. <ul> <li><input type="checkbox" name="items[]" value="88712003" id="88712003" /> Parent 1</li> <li><input type="checkbox" name="items[]" value="88712003" id="88712003" /> Parent 2 <ul> <li><input type="checkbox" name="items[]" value="21312341" id="21312341" /> Child 1</li> <li><input type="checkbox" name="items[]" value="21312341" id="21312341" /> Child 2</li> </ul> </li> <li><input type="checkbox" name="items[]" value="88712003" id="88712003" /> Parent 3</li> <li><input type="checkbox" name="items[]" value="88712003" id="88712003" /> Parent 4</li> </ul> If Child 1 or Child 2 is checked, I want the input in Parent 2 to be checked and set inactive. I've started working on it, but got stuck here: $(function(){ $('.child').click(function() { $(this).parent().parent().parent().toggle(); }); }); As you can see, I didn't make it far. Any help would be appreciated. Thanks!

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  • HTML javascript form submitted when image input button

    - by DreamU
    I have a form that contains this single input field, which is nothing more than a button to Print the current web page: <div align="center"> <input type="image" src="../Images/print.jpg" value="Print" onclick="printpage();" /></div> </div> After the printing, the page re-submits itself (to itself). Why does it do this and can I stop it? If I just change the type to "input", this code does not re-submit itself after printing: <div align="center"> <input type="input" src="../Images/print.jpg" value="Print" onclick="printpage();" /></div> </div> Unfortunately, our style conventions require me to use that button image rather than the standard input button.

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  • ActionScript shiftKey Not Working In Full Screen Mode?

    - by Chunk1978
    i've drawn an ellipse sprite and added it to the display list of a container, which is added to the display list of the stage. to move the sprites with the keyboard arrows, it appears that my shiftModifier:Number variable is not working when the stage's display state is set to full screen. shiftModifier works as it should when the stage's display state is set to Normal. stage.addEventListener(KeyboardEvent.KEY_DOWN, onKeyboardDown); function onKeyboardDown(evt:KeyboardEvent):void { var shiftModifier:Number = 0.25; if (evt.shiftKey) {shiftModifier = 10;} if (evt.keyCode == Keyboard.UP) {ellipse1.y -= shiftModifier;} if (evt.keyCode == Keyboard.DOWN) {ellipse1.y += shiftModifier;} if (evt.keyCode == Keyboard.LEFT) {ellipse1.x -= shiftModifier;} if (evt.keyCode == Keyboard.RIGHT) {ellipse1.x += shiftModifier;} } fsm.addEventListener(MouseEvent.CLICK, toggleFullScreenMode); function toggleFullScreenMode(evt:MouseEvent):void { if (stage.displayState == StageDisplayState.FULL_SCREEN) {stage.displayState = StageDisplayState.NORMAL;} else {stage.displayState = StageDisplayState.FULL_SCREEN;} } full screen is tested in Safari and Firefox.

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  • textview.selectedRange.location in UITextview show 2147483647

    - by Risma
    hi i have a textview and i want to get the selectedRange.location value from that textview. in the first time when the keyboard appear, the location value always show an integer point such as 110, or others. But if i dissappear the keyboard and then appear the keyboard again, the location value always show 2147483647. What is this 2147483647 mean and how to get the real location value? This is my code in the keyboard will appear method : -(void)keyboardWillAppear:(NSNotification *)notification { [UIView beginAnimations:nil context:NULL]; [UIView setAnimationDuration:[[[notification userInfo] objectForKey:UIKeyboardAnimationDurationUserInfoKey] doubleValue]]; CGRect keyboardEndingUncorrectedFrame = [[[notification userInfo] objectForKey:UIKeyboardFrameEndUserInfoKey ] CGRectValue]; CGRect keyboardEndingFrame = [self.view convertRect:keyboardEndingUncorrectedFrame fromView:nil]; [UIView commitAnimations]; NSRange selectedRange = textview.selectedRange; NSLog(@"selected Range location : %f", selectedRange.location); }

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  • identify the input that is multiple of 11 and odd or even java

    - by Bolor Ch
    i am trying to write code to determine the nature of input using if statement only. The nature of input could be following: a multiple of 11 even or odd. For the code below, when I enter my input, it does not display the result as "input:NOT:ODD". Also how can I check multiple conditions with if statement? (else is not considered) import java.util.Scanner; public class test { public static void main( String args[] ) { Scanner input = new Scanner( System.in ); int x; int EO; int Mult; System.out.print ( "Enter value: " ); x = input.nextInt(); EO = x % 2; Mult = x % 11; if (EO > 0 && Mult > 0) { System.out.printf ("%d:NOT:ODD"); } } }

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  • HTML5 Search Input: No Background Image in Chrome?

    - by Jason
    I have been pulling my hair out trying to get Chrome to style my search input with a background image. Firefox has no problem, but I fear it's because it treats the input as a regular text input. Is this simply not possible? Try this as a demo: <input type="search" /> ?input[type="search"] { background: transparent url(http://google.com/intl/en_ALL/images/srpr/logo1w.png) no-repeat 0 0; }?????? If it worked correctly, it should put Google's logo (or part of it) as the background image for the "Search" input. But as you will see when you look at this in Chrome, it DOES NOT WORK. Any ideas, or is this just one of HTML5's quirks? :\

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  • USB-keyboard & mouse powered off in windows-7

    - by sinned
    I have a problem with a pc where usb devices are not getting any power as soon as windows starts up (it works in preboot). This pc has no ps/2, so there is no chance for input, also not in secure boot mode. I "tidied up" using sysinternals autostart, so there is a chance I messed something up here, although I'm quite sure I only deleted some old printer drivers from autostart. I do not know how to reset this, I cant even log in because there is no input possible. I could use a linux live cd, but I don't know what to do there because there is no sysinternals from linux into a not running windows... To make things even worse, I have the windows installation completely encrypted with truecrypt, so I haven't even tried windows recovery cd yet. There is no loss of data since I can access the disc with a live-linux, I only want to use it again without resetting up everything. Any suggestions?

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  • iPhone Settings app and keyboard control?

    - by randallmeadows
    So I'm putting my app's preference settings into the Settings app. One of the settings is an edit text field (PSTextFieldSpecifier). When touched, the keyboard dutifully appears, I can make the edits, but when I press Return....nothing. Well, the editing is completed, but the keyboard remains. I see no way to make the keyboard go away. I also notice this same behavior in other Settings panes, including those from Apple. Do I assume correctly that this is just standard behavior and I need to just accept the fact that my Settings table has now been reduced to half size, and just deal? Furthermore, I gather there is no approved way to have a "rich" child pane display, such as that seen in Settings-General-About-Legal? Or a way to do what appears to be a -presentModalViewController, a la Settings-General-Passcode Lock?

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  • vlc python bindings - how to receive keyboard input?

    - by itsadok
    I'm trying to use VLC's python bindings to create my own little video player. The demo implementation is quite simple and nice, but it requires all the keyboard commands to be typed into the console from which the script was run. Is there any way I can handle keyboard input also when the video player itself has focus? Specifically, I care about controlling the video while in fullscreen mode. Perhaps there's a way to keep the keyboard focus in the console (or maybe another window) while showing the video? I'm using Windows XP, if that has any relevance.

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  • Modal View Controller with keyboard on landscape iPad changes location when dismissed

    - by Roi
    I present a modal view controller on my on my iPad with UIModalPresentationFormSheet presentation style and UIModalTransitionStyleCoverVertical transition style. The Modal View Controller contains a UIWebView with some TextFields on it. When the user taps one of the text fields the keyboard comes up. I have noticed that in landscape mode after the keyboard is shown, if I try to dismiss the modal view controller with animation the view changes its position from the center of the screen to the left side just before the animation starts.. This happens only if the keyboard is up and only in landscape mode on the iPad. If the user closes the modal view without pressing on any text field this doesn't happen. Anyone familiar with this strange behavior?

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  • Scroll UITableViewCell above keyboard for small tableview

    - by JK
    I have a tableview which is added to a UIViewController as the tableview only fills the bottom 3/4 of the screen.The rows contain editable UITextFields. When a field is tapped, the keyboard appears but the table does not scroll upwards as would normally be the case. Consequently, the keyboard obscures the field being edited. I have tried calling [tableView scrollToRowAtIndexPath:(NSIndexPath *)indexPath atScrollPosition:(UITableViewScrollPosition)scrollPosition animated:(BOOL)animated] but this has no effect if the table contains only a few rows. How can I get the table to scroll a specific cell above the keyboard? Thank you

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  • Virtual Keyboard doesn't appear when rotate the screen?

    - by user164589
    Hi guys. I am facing to a problem related virtual keyboard. I've created a layout that contains Button, TextView and EditText. When its screen orientation is Portrait, it can show the Virtual Keyboard by one touching on the EditText. Then I've changed screen orientation to Landscape. At this moment Virtual Keyboard hasn't been appeared. What is wrong here ? How to fix it ? I think this is big problem for my application. Please help. guys. Thanks.

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  • Keyboard shortcut for Jump to Definition

    - by Arne Evertsson
    I'm looking for a keyboard only shortcut for Jump to Definition. The built-in shortcut requires the mouse: Cmd + Double click. I've tried to add a regular keyboard shorcut for the Edit / Find / Jump to Defintion menu command, but, alas, it will only work when the method name is selected. I'd like to be able to position the cursor within the method name, class name, or other symbol, and hit something like Cmd+Shift+L. Does anyone know of a solution, perhaps using a script, for the problem? Update: The keyboard shortcut works sometimes and sometimes not. When I position the text cursor on a method call with no parameters and press Cmd+Shift+L it takes me to the definition. But it doesn't work for a method that takes an (id) parameter. However it works if the parameter is an int. I have submitted a bug report to Apple.

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  • Handling input from a keyboard wedge

    - by JDibble
    Following on from the question asked by Mykroft Best way to handle input from a keyboard “wedge” http://stackoverflow.com/questions/42437/best-way-to-handle-input-from-a-keyboard-wedge. I need to write a class that intercepts key strokes, if the input is determined to be from the keyboard wedge (as described in the above post) the data will be directed to POS classes to handle, otherwise they keystrokes must be passed on to be handled in windows in the normal manner. This raises two questions How can I intercept key strokes when not in a WinForm. How can I pass on the keypresses to windows. Thanks JDibble

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  • Static keyboard in uitableview

    - by Martin
    I have a UITableView that holds just two cells with a textfield in each. As my tableview is just for editing the text in these textfields I always want the keyboard to be shown static in the bottom of the screen. So in viewDidLoad I set the first textfield to become first responder. Something I have noticed though is that when I push the UITableViewController into the UINavigationController the keyboard show up a little bit slower so you can see it animate into the screen. It would be much better if it was there already there when the uitableview shows up. I also tried making the textfield first responder before pushing it as recommended but that didn't made the keyboard show at all: MyTableViewController *myTableViewController = [[MyTableViewController alloc] initWithNibName:@"MyTableViewController" bundle:nil]; [myTableViewController.textField becomeFirstResponder]; [self.navigationController pushViewController:myTableViewController animated:YES]; [myTableViewController release]; How can I accomplish this? Thanks!

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