Filtering Filenames with bash
- by Stefan Liebenberg
I have a directory full of log files in the form
${name}.log.${year}{month}${day}
such that they look like this:
logs/
production.log.20100314
production.log.20100321
production.log.20100328
production.log.20100403
production.log.20100410
...
production.log.20100314
production.log.old
I'd like to use a bash script to filter out all the logs older than x amount of month's and dump it into *.log.old
X=6 #months
LIST=*.log.*;
for file in LIST; do
is_older = file_is_older_than_months( ${file}, ${X} );
if is_older; then
cat ${c} >> production.log.old;
rm ${c};
fi
done;
How can I get all the files older than x months? and... How can I avoid that *.log.old file is included in the LIST attribute?
Thank you
Stefan
