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  • In Drupal 6, is there a way to take a custom field from the latest post to a taxonomy term, and disp

    - by user278457
    The title for this question pretty much sums up what I'm asking. I've got a list of taxonomy terms, and I'm using a view to display the latest post to each one. I'd like to also display a custom field set up in CCK just under this. Currently, I'm just using "date updated" of the taxonomy term itself which was easy to set up in views. I'd like to drill a little deeper and get the custom "event date" field I've added to the content type last posted to the taxonomy term I'm "viewing". I've got a feeling I'm going to have to write my own database query for this. If (I can avoid that){ How do I set up such a view? } Else{ What's the best practice for including lower level database queries alongside views? }

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  • Do I have to use mysql_real_escape_string if I bind parameters?

    - by Babak
    I have the following code: function dbPublish($status) { global $dbcon, $dbtable; if(isset($_GET['itemId'])) { $sqlQuery = 'UPDATE ' . $dbtable . ' SET active = ? WHERE id = ?'; $stmt = $dbcon->prepare($sqlQuery); $stmt->bind_param('ii', $status, $_GET['itemId']); $stmt->execute(); $stmt->close(); } } Do I need to mysql_real_escape_string in this case or am i okay?

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  • Remove accents from a JSON response using the raw content.

    - by Pentium10
    This is a follow up of this question: Remove accents from a JSON response. The accepted answer there works for a single item/string of a raw JSON content. But I would like to run a full transformation over the entire raw content of the JSON without parsing each object/array/item. What I've tried is this function removeAccents($jsoncontent) { $obj=json_decode($jsoncontent); // use decode to transform the unicode chars to utf $content=serialize($obj); // serialize into string, so the whole obj structure can be used string as a whole $a = 'ÀÁÂÃÄÅÆÇÈÉÊËÌÍÎÏÐÑÒÓÔÕÖØÙÚÛÜÝÞßàáâãäåæçèéêëìíîïðñòóôõöøùúûýýþÿRr'; $b = 'aaaaaaaceeeeiiiidnoooooouuuuybsaaaaaaaceeeeiiiidnoooooouuuyybyRr'; $content=utf8_decode($content); $jsoncontent = strtr($content, $a, $b); // at this point the accents are removed, and everything is good echo $jsoncontent; $obj=unserialize($jsoncontent); // this unserialization is returning false, probably because we messed up with the serialized string return json_encode($obj); } As you see after I decoded JSON content, I serialized the object to have a string of it, than I remove the accents from that string, but this way I have problem building back the object, as the unserialize stuff returns false. How can I fix this?

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  • PHP5 : Applying a method from an extended class on an object from the original (parent) class.

    - by Glauber Rocha
    Hello, I'm trying to extend two native PHP5 classes (DOMDocument and DOMNode) to implement 2 methods (selectNodes and selectSingleNode) in order to make XPath queries easier. I thought it would be rather straighforward, but I'm stuck in a problem which I think is an OOP beginner's issue. class nDOMDocument extends DOMDocument { public function selectNodes($xpath){ $oxpath = new DOMXPath($this); return $oxpath->query($xpath); } public function selectSingleNode($xpath){ return $this->selectNodes($xpath)->item(0); } } Then I tried to do extend DOMNode to implement the same methods so I can perform an XPath query directly on a node: class nDOMNode extends DOMNode { public function selectNodes($xpath){ $oxpath = new DOMXPath($this->ownerDocument,$this); return $oxpath->query($xpath); } public function selectSingleNode($xpath){ return $this->selectNodes($xpath)->item(0); } } Now if I execute the following code (on an arbitrary XMLDocument): $xmlDoc = new nDOMDocument; $xmlDoc->loadXML(...some XML...); $node1 = $xmlDoc->selectSingleNode("//item[@id=2]"); $node2 = $node1->selectSingleNode("firstname"); The third line works and returns a DOMNode object $node1. However, the fourth line doesn't work because the selectSingleNode method belongs to the nDOMNode class, not DOMNode. So my question: is there a way at some point to "transform" the returned DOMNode object into a nDOMNode object? I feel I'm missing some essential point here and I'd greatly appreciate your help. (Sorry, this is a restatement of my question http://stackoverflow.com/questions/2573820/)

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  • DDD and MVC: Difference between 'Model' and 'Entity'

    - by Nathan Loding
    I'm seriously confused about the concept of the 'Model' in MVC. Most frameworks that exist today put the Model between the Controller and the database, and the Model almost acts like a database abstraction layer. The concept of 'Fat Model Skinny Controller' is lost as the Controller starts doing more and more logic. In DDD, there is also the concept of a Domain Entity, which has a unique identity to it. As I understand it, a user is a good example of an Entity (unique userid, for instance). The Entity has a life-cycle -- it's values can change throughout the course of the action -- and then it's saved or discarded. The Entity I describe above is what I thought Model was supposed to be in MVC? How off-base am I? To clutter things more, you throw in other patterns, such as the Repository pattern (maybe putting a Service in there). It's pretty clear how the Repository would interact with an Entity -- how does it with a Model? Controllers can have multiple Models, which makes it seem like a Model is less a "database table" than it is a unique Entity. So, in very rough terms, which is better? No "Model" really ... class MyController { public function index() { $repo = new PostRepository(); $posts = $repo->findAllByDateRange('within 30 days'); foreach($posts as $post) { echo $post->Author; } } } Or this, which has a Model as the DAO? class MyController { public function index() { $model = new PostModel(); // maybe this returns a PostRepository? $posts = $model->findAllByDateRange('within 30 days'); while($posts->getNext()) { echo $posts->Post->Author; } } } Both those examples didn't even do what I was describing above. I'm clearly lost. Any input?

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  • Pulling data and printing it in an HTML table

    - by John
    Hello, From a MySQL table called "submission" containing the fields "loginid, submissionid, title, url, datesubmitted, displayurl", I would like to print an HTML table thats contains all "title" and corresponding "datesubmitted" where "loginid" equals "$profile." The code I am trying to use is below. It isn't working. Any ideas why it isn't working? Thanks in advance, John $profile = $_GET['profile']; $sqlStr = "SELECT loginid, submissionid, title, url, datesubmitted, displayurl FROM submission WHERE loginid = $profile ORDER BY datesubmitted DESC"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1"><a href="http://www.'.$row["url"].'">'.$row["title"].'</a></td>'; echo '</tr>'; echo '<tr>'; echo '<td class="sitename2">'.$row["datesubmitted"].'</a></td>'; echo '</tr>'; } echo "</table>";

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  • problem with adding url variable with javascript

    - by Richard
    Hello, Can someone help me with this I am trying to set and catch the url variable It begins with a form wich has the standard action set to "/autorisation/logout" Then a button with an inline javascript function function tbPayout() { parent.location = "/autorisation/logout?rcgo=payout"; return true; } <input src="/images/go02.gif" type=image border=0 name="go1" onClick="return tbPayout();"> In the autorisation controller I try to catch it if ( isset($_GET['rcgo']) ) { but it doesn't work and I can't see the variable in the url and therefore the default forms action is performed? I also have another redirect page with content="3; url=http://www.domain.nl/index/index?rcgo=logout" /> and that works fine How can I get the javascript to work because I have three submit buttons that need to be set to different get variables. Thanks, Richard

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  • MYSQL Select and group by date

    - by Gil
    I'm not sure how create a right query to get the result I'm looking for. What I have is 2 tables. first has ID, Name columns and second has date and adminID, which is referenced from table 1 column ID. Now, what I want to get is basically number of times each admin loged in per day during the month. From structure like this one I want to get per day and month data so result would be similar to 1, 2, 2 march total 5 for admin 4. ID | Date ------------------ 4 | 2010/03/01 4 | 2010/03/04 4 | 2010/03/04 4 | 2010/03/05 4 | 2010/03/05

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  • Zend Server experiences

    - by Luke
    The other day I was looking into Zend Server and I was wondering why I would use this? OK, they say it's all tested and mission critical and Enterprise ready etc. But to me that's just the marketing department talking. Is anyone out there using this product and if so can you share your experiences with it and maybe you could also elaborate on the reason on why you choose this product for your application(s). Did you find any real benefits to using Zend server?

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  • Using custom request and custom redirect with Contact Form 7

    - by Scott B
    I have several sites that I want to link back to the main site which hosts the contact form (using contact form 7). I would like to capture the request parameter "site-url" on incoming links to the contact form. Then when the user submits the form, I would like to redirect them back to the site specified in the site-url. Any ideas if this is possible with contact form 7? I would also like to add a special field in the contact form which would insert the site-url into the email that i get so that I know which site they were referred from.

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  • Place Query Results into Array then Implode?

    - by jason
    Basically I pull an Id from table1, use that id to find a site id in table2, then need to use the site ids in an array, implode, and query table3 for site names. I cannot implode the array correctly first I got an error, then used a while loop. With the while loop the output simply says: Array $mysqli = mysqli_connect("server", "login", "pass", "db"); $sql = "SELECT MarketID FROM marketdates WHERE Date = '2010-04-04 00:00:00' AND VenueID = '2'"; $result = mysqli_query($mysqli, $sql) or die(mysqli_error($mysqli)); $dates_id = mysqli_fetch_assoc ( $result ); $comma_separated = implode(",", $dates_id); echo $comma_separated; //This Returns 79, which is correct. $sql = "SELECT SIteID FROM bookings WHERE BSH_ID = '1' AND MarketID = '$comma_separated'"; $result = mysqli_query($mysqli, $sql) or die(mysqli_error($mysqli)); // This is where my problems start $SIteID = array(); while ($newArray = mysqli_fetch_array($result, MYSQLI_ASSOC)) { $SIteID[] = $newArray[SIteID]; } $locationList = implode(",",$SIteID); ?> Basically what I need to do is correctly move the query results to an array that I can implode and use in a 3rd query to pull names from table3.

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  • curl_init undefined?

    - by udaya
    Hi I am importing the contacts from gmail to my page ..... The process doesnot work due to this error 'curl_init' is not defined The suggestion i got is to 1.uncomment destination curl.dll 2.copy the following libraries to the windows/system32 dir. ssleay32.dll libeay32.dll 3.copy php_curl.dll to windows/system32 After trying all these i refreshed my xampp Even then error occurs This is my page where i am trying to import the gmail contacts ` // set URL and other appropriate options curl_setopt($ch, CURLOPT_URL, "http://www.example.com/"); curl_setopt($ch, CURLOPT_HEADER, 0); // grab URL and pass it to the browser curl_exec($ch); // close cURL resource, and free up system resources curl_close($ch); ? "HOSTED_OR_GOOGLE", "Email" = $_POST['Email'], echo "Passwd" = $_POST['Passwd'], "service" = "cp", "source" = "tutsmore/1.2" ); //Now we are going to post these datas to the clientLogin url. // Initialize the curl object with the $curl = curl_init($clientlogin_url); //Make the post true curl_setopt($curl, CURLOPT_POST, true); //Passing the above array of parameters. curl_setopt($curl, CURLOPT_POSTFIELDS, $clientlogin_post); //Set this for authentication and ssl communication. curl_setopt($curl, CURLOPT_HTTPAUTH, CURLAUTH_ANY); //provide false to not to check the server for the certificate. curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, false); //Tell curl to just don't echo the data but return it to a variable. curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1); //The variable containing response $response = curl_exec($curl); //Check whether the user is successfully login using the preg_match and save the auth key if the user //is successfully logged in preg_match("/Auth=([a-z0-9_-]+)/i", $response, $matches); $auth = $matches[1]; // Include the Auth string in the headers $headers = array("Authorization: GoogleLogin auth=" . $auth); // Make the request to the google contacts feed with the auth key $curl = curl_init('http://www.google.com/m8/feeds/contacts/default/full?max-results=10000'); //passing the headers of auth key. curl_setopt($curl, CURLOPT_HTTPHEADER, $headers); //Return the result in a variable curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1); //the variable with the response. $feed = curl_exec($curl); //Create empty array of contacts echo "contacts".$contacts=array(); //Initialize the DOMDocument object $doc=new DOMDocument(); //Check whether the feed is empty //If not empty then load that feed. if (!empty($feed)) $doc-loadHTML($feed); //Initialize the domxpath object and provide the loaded feed $xpath=new DOMXPath($doc); //Get every entry tags from the feed. $query="//entry"; $data=$xpath-query($query); //Process each entry tag foreach ($data as $node) { //children of each entry tag. $entry_nodes=$node-childNodes; //Create a temproray array. $tempArray=array(); //Process the child node of the entry tag. foreach($entry_nodes as $child) { //get the tagname of the child node. $domNodesName=$child-nodeName; switch($domNodesName) { case 'title' : { $tempArray['fullName']=$child-nodeValue; } break; case 'email' : { if (strpos($child-getAttribute('rel'),'home')!==false) $tempArray['email_1']=$child-getAttribute('address'); elseif(strpos($child-getAttribute('rel'),'work')!=false) $tempArray['email_2']=$child-getAttribute('address'); elseif(strpos($child-getAttribute('rel'),'other')!==false) $tempArray['email_3']=$child-getAttribute('address'); } break; } } if (!empty($tempArray['email_1']))$contacts[$tempArray['email_1']]=$tempArray; if(!empty($tempArray['email_2'])) $contacts[$tempArray['email_2']]=$tempArray; if(!empty($tempArray['email_3'])) $contacts[$tempArray['email_3']]=$tempArray; } foreach($contacts as $key=$val) { //Echo the email echo $key.""; } } else { //The form ? " method="POST" Email: Password: tutsmore don't save your email and password trust us. ` code is completely provided for debugging if any optimization is needed i will try to optimize the code

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  • pagination with css

    - by bsandrabr
    Hi I've tried every combination I can think of but I can't get this to work. Can you help? I'm trying to put some css onto my pagination and have read all the examples but they all contain so many backslashes and concatenation that I just dont know how to apply it Here is my pagination code (which works fine) along with my feeble attempt at styling it if ($st > 0) { $st3=$st; print "< Previous Page "; } $f=$st+3; for($i2=$st+1;$i2<=$f;$i2++) { $i3=$i2-3; if ($i3 0) { print "$i3 "; if($i2 % 3 == 0) { print ""; } } } $g=$st+3; for($i=$st+1;$i<=$g;$i++) { print "$i "; if($i % 3 == 0) { print ""; } } $st2=$st+2; print " Next Page "; Here is the css that I took from the website /* CSS Document */ body { background: #2D2D2D; font-family:Verdana, fantasy; font-size:13px; color: white; scrollbar-base-color: black; scrollbar-arrow-color: red; scrollbar-DarkShadow-Color: black; } a:visited,a:active,a:link { color: white;text-decoration: none; } a:hover { color: red;text-decoration: overline underline;background: none; } table,tr,td { font-family:Palatino Linotype; color: #FFFFFF;font-size: 12px; } .button { font-family:Verdana, fantasy; font-size:13; color:#FFFFFF; background-color: red; } input,textarea,dropdown{ font-family:Verdana, fantasy; font-size:13; color: #FFFFFF; background-color: #000000; border: 1px solid; } textarea,.submit input{ font-family:Verdana, fantasy; font-size:13; color:#ffffff; background-color: black; } .table { background-color:#000000; } .table3 { background-color:#000000; } .table td { color: #000000; background-color:#DEDEDE; height:22px; } .table3 td { background-color:#CCCCCC; } td .alt { background-color:#EEEEEE; height:22px; } td .h { background-image:url(tablehgrad.png); background-repeat:repeat-x; font-weight: bold; background-color: #D6D6D6; } .table th { background-image:url(tablehgrad.png); background-repeat:repeat-x; color: #000000; font-weight: bold; background-color: #D6D6D6; } .menu th { font-font-size: 12px; color: silver; background-image:url(th.png); background-repeat:repeat-x; font-weight: bold; background-color: #4B4B4B; } .stats td { font-font-size: 12px; color: white; font-weight: bold; } .menu td { font-size: 12px; text-align: center; color: white; background-image:url(tdover.png); background-repeat:repeat-x; font-weight: bold; background-color: #4B4B4B; } .menu td:hover{ color: white; background-image:url(td.png); div.pagination { padding: 3px; margin: 3px; } div.pagination a { padding: 2px 5px 2px 5px; margin: 2px; border: 1px solid #AAAADD; text-decoration: none; /* no underline */ color: #000099; } div.pagination a:hover, div.pagination a:active { border: 1px solid #000099; color: #000; } div.pagination span.current { padding: 2px 5px 2px 5px; margin: 2px; border: 1px solid #000099; font-weight: bold; background-color: #000099; color: #FFF; } div.pagination span.disabled { padding: 2px 5px 2px 5px; margin: 2px; border: 1px solid #EEE; color: #DDD; } thanks

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  • problem showing pictures stored outside web root folder

    - by David
    On a website users can upload pictures. For security reasons these are stored outside the webroot (public_html) folder. When I need to display the picture, I send the headers and have "readfile" read and output the picture data, like so: header("Pragma: public"); header("Expires: 0"); // set expiration time header("Cache-Control: must-revalidate, post-check=0, pre-check=0"); header('Content-type: image/jpg'); header('Content-Length: ' . $filesize); readfile($path_url . '/' . $photo); This works great, but the site is growing and this is starting to be a burden on the server. Question: is there a way to send the picture or picture data to the user, without the server first having to load the picture (obviously with the picture still being stored outside the webroot folder)? Thanks! David

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  • Codeigniter Strip HTML tags from input

    - by Mithun
    What is the best method to strip htnl tags from the input? How can i remove the HTML tags while validating the input $this->form_validation->set_rules('description', 'Description', 'trim|xss_clean'); Do I need to add custom call back method to validation rules?

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  • HTTP request failed! HTTP/1.1 505 HTTP Version Not Supported error

    - by shyam
    I'm trying to use file_get_contentsO() to get the response from a server and this error was encountered. Could someone tell me what is the reason and how to fix it? The portion of the code is: $api = "http://smpp5.routesms.com:8080/bulksms/sendsms?username=$username&password=$password&source=$source&destination=$destin&dlr=$dlr&type=$type&message=$message"; $resp = file_get_contents($api); The server responded correctly while I pasted the url in the browser. I learned that this is caused by the server rejecting the client's HTTP version, but I have no idea why that is happening in my case. Any help is much appreciated. Thanks in advance

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  • Help with mysql sum and group query and managing jquery graph results.

    - by Scarface
    Hey guys, I have a system I am trying to design that will retrieve information from a database, so that it can be plotted in a jquery graph. I need to retrieve the information and somehow put it in the necessary format (for example two coordinates var d = [[1269417600000, 10],[1269504000000, 15]];). My table that I am selecting from is a table that stores user votes with fields: points_id (1=vote up ,2=vote down), user_id, timestamp, and topic_id. What I need to do is select all the votes and somehow group them into respective days and then sum the difference between 1 votes and 2 votes for each day. I then need to somehow display the data in the appropriate plotting format shown earlier. For example April 1, 4 votes. The data needs to be separated by commas, except the last plot entry, so I am not sure how to approach that. I showed an example below of the kind of thing I need but it is not correct, echo "var d=["; $query=mysql_query("SELECT *, SUM(IF(points_id = \"1\", 1,0))-SUM(IF([points_id = \"2\", 1,0)) AS 'total' FROM points LEFT JOIN topic on topic.topic_id=points.topic_id WHERE topic.creator='$user' GROUP by timestamp HAVING certain time interval"); while ($row=mysql_fetch_assoc($query)){ $timestamp=$row['timestamp']; $votes=$row['total']; echo "[$timestamp,$vote],"; } echo "];";

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  • How to do an IF statement based on the value of a MySQL table cell?

    - by Susan
    How can I do an if statement based on the value of a mysql table cell. For example, I have a table of people with a column called marital_status. This column has one of two values: yes or no. But this doesn't work: $query = mysql_query("SELECT marital_status FROM people WHERE first_name = 'John'"); while ($row = mysql_fetch_assoc($query)) { $maritalStatus = $row['marital_status']; } if ($maritalStatus == "yes") { echo "This person is married."; } else { echo "This person is NOT married."; } $maritalStatus == "yes" doesn't return as true even though that is exactly the value in that cell.

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  • Opposite of nl2br? Is it str_replace?

    - by Julian H. Lam
    So the function nl2br is handy. Except in my web app, I want to do the opposite, interpret line breaks as new lines, since they will be echoed into a pre-filled form. str_replace can take <br /> and replace it with whatever I want, but if I put in \n, it echoes literally a backslash and an n. It only works if I put a literal line break in the middle of my script, and break the indentation (so there are no trailing space). See: <?=str_replace('<br />',' ',$foo)?> Am I missing escape characters? I think I tried every combination...

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  • Kohana 3 ORM: How to get data from pivot table? and all other tables for that matter

    - by zenna
    I am trying to use ORM to access data stored, in three mysql tables 'users', 'items', and a pivot table for the many-many relationship: 'user_item' I followed the guidance from http://stackoverflow.com/questions/1946357/kohana-3-orm-read-additional-columns-in-pivot-tables and tried $user = ORM::factory('user',1); $user->items->find_all(); $user_item = ORM::factory('user_item', array('user_id' => $user, 'item_id' => $user->items)); if ($user_item->loaded()) { foreach ($user_item as $pivot) { print_r($pivot); } } But I get the SQL error: "Unknown column 'user_item.id' in 'order clause' [ SELECT user_item.* FROM user_item WHERE user_id = '1' AND item_id = '' ORDER BY user_item.id ASC LIMIT 1 ]" Which is clearly erroneous because Kohana is trying to order the elements by a column which doesn't exist: user_item.id. This id doesnt exist because the primary keys of this pivot table are the foreign keys of the two other tables, 'users' and 'items'. Trying to use: $user_item = ORM::factory('user_item', array('user_id' => $user, 'item_id' => $user->items)) ->order_by('item_id', 'ASC'); Makes no difference, as it seems the order_by() or any sql queries are ignored if the second argument of the factory is given. Another obvious error with that query is that the item_id = '', when it should contain all the elements. So my question is how can I get access to the data stored in the pivot table, and actually how can I get access to the all items held by a particular user as I even had problems with that? Thanks

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