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• INSERT INTO error MYSQL/PHP

  - by bat

  I get this error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'order (total, addy, cc) VALUES ('798' , '123 sadf' , '12124123')' at line 1 $total = addslashes(($_SESSION['total'])); $addy = addslashes(($_POST['addy'])); $cc = addslashes(($_POST['cc'])); echo "$total"; echo "$addy"; echo "$cc"; mysql_query("INSERT INTO order (total, addy, cc) VALUES ('$total' , '$addy' , '$cc')") or die(mysql_error()); help plz =]

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• Mysql Date formats and url query

  - by jasmine

  I want to make a url query with date. I have confused a little : There is a mysql table: calDate : varchar The query : $sql="select * from calTbl"; $result = mysql_query($sql); while ($row = mysql_fetch_array($result)) { $n = str_replace("/", "",$row['calDate']); echo '<a href="index.php?p='.$n.'">'.$n.'</a>'; } I want to see related event from query. Can I set apart month, day and year from this? Or what is the correct table design here? Thanks in advance

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• Compare range of ip addresses with start and end ip address in MySQL

  - by Maarten

  I have a MySQL table where I store IP ranges. It is setup in the way that I have the start address stored as a long, and the end address (and an id and some other data). Now I have users adding ranges by inputting a start and end ip address, and I would like to check if the new range is not already (partially) in the database. I know I can do a between query, but that doesn't seem to work with 2 different columns, and I also cannot figure out how to pass a range to compare it. Doing it in a loop in PHP is a possibility, but would with a range of e.g. 132.0.0.0-199.0.0.0 be quite a big amount of queries..

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• Displaying mysql results as an object?

  - by Michael

  If I have a database with the structure: ___id_____|____value____ 1 | value1 2 | value2 3 | value3 How can I pull data from this MySQL database in PHP and have it formatted like this: Array ( [0] => stdClass Object ( [id] => 1 [value] => value1 ) [1] => stdClass Object ( [id] => 2 [value] => value2 ) [2] => stdClass Object ( [id] => 3 [value] => value3 ) )

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• inserting date timestamp value to mysql thru php in godaddy hosting site

  - by Suj

  Hi all, I'm using GoDaddy's Shared Linux hosting. Using php i am inserting or updating the mysql database with create date or modified date using the variables $datestring = "%Y:%m:%d %h:%i:%s"; $time = time(); $createdate= mdate($datestring, $time); In this $createdate will be the variable i use to insert or update the table. But its updating the wrong value. ITs not the server time or localtime. mostly its 30 mins delay with godaddy's server time. Pls help.

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• MYSQL Event Scheduler DELIMITER using PHP

  - by user1440918

  I'm having an issue with my PHP code trying to create events within MySQL. I begin with creating a string like this: $sql="DELIMITER $$ CREATE EVENT `$test_name` ON SCHEDULE EVERY $time1 $sched2 STARTS '$start_date $start_time' DO BEGIN "; $sql .="INSERT INTO blah (foo,bar); "; $sql .="END$$ DELIMITER ;" mysql_query($sql,$dbh); But I keep getting Syntax Errors starting with DELIMITER $$ CREATE EVENT. Without the semicolon behind (foo,bar); the event triggers with a unexecuted payload. Any ideas on where I'm going wrong? Thanks!

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• MySQL: filling empty fields with zeroes when using GROUP BY

  - by SaltLake

  I've got MySQL table CREATE TABLE cms_webstat ( ID int NOT NULL auto_increment PRIMARY KEY, TIMESTAMP_X timestamp DEFAULT CURRENT_TIMESTAMP, # ... some other fields ... ) which contains statistics about site visitors. For getting visits per hour I use SELECT hour(TIMESTAMP_X) as HOUR , count(*) AS HOUR_STAT FROM cms_webstat GROUP BY HOUR ORDER BY HOUR DESC which gives me | HOUR | HOUR_STAT | | 24 | 15 | | 23 | 12 | | 22 | 9 | | 20 | 3 | | 18 | 2 | | 15 | 1 | | 12 | 3 | | 9 | 1 | | 3 | 5 | | 2 | 7 | | 1 | 9 | | 0 | 12 | And I'd like to get following: | HOUR | HOUR_STAT | | 24 | 15 | | 23 | 12 | | 22 | 9 | | 21 | 0 | | 20 | 3 | | 19 | 0 | | 18 | 2 | | 17 | 0 | | 16 | 0 | | 15 | 1 | | 14 | 0 | | 13 | 0 | | 12 | 3 | | 11 | 0 | | 10 | 0 | | 9 | 1 | | 8 | 0 | | 7 | 0 | | 6 | 0 | | 5 | 0 | | 4 | 0 | | 3 | 5 | | 2 | 7 | | 1 | 9 | | 0 | 12 | How should I modify the query to get such result? Thanks.

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• Mysql two table query

  - by Sergio

  I'm using two tables. First (friendlist), which contains users who are on the list of friends and the other table (members) that contains the basic data of the users. Friendlist looks like: id | myid | date | user ----------------------------------------- 001 | 50624 | 2010-01-01 | 32009 002 | 41009 | 2010-05-05 | 50624 003 | 50624 | 2010-03-02 | 23007 The column "myid" contains members who added other users (those from column "user") to their frindlist. I want to get the list of all users that I have added to list and those who add me to their friendlist. In this example, if my id is 50624, the list would look like: | allfriends | --------------- 32009 41009 23007 Then I need to check all users from "allfriend" list with data from the table "members". I want to get only the users with status 1. The members table looks like: id | status | photo -------------------------------- 32009 | 0 | 1.jpg 41009 | 1 | 2.jpg 23007 | 1 | 3.jpg How this mysql query should look like? Thanks for any help.

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• Insertion failed error in MySQL.

  - by theband

  while($row=mysql_fetch_array($result2)){ //return $row['ProjectID']; $sql="INSERT INTO `tycodashboard` (ProjectID,DesignationID,ReqcompID,IntOrgID,FinishedTimeID,ProjectStatusID,PhaseID ) VALUES('{$row['ProjectID']}','$pm,'$req','$initiating,'$initiating','$ftime,'$ProjectStatus,'$Phase)"; $result=mysql_query($sql); if(!$result){ if(mysql_errno() == ER_DUP_ENTRY){ throw new Exception("INSERT FAILED.\n\nThe database already contains a Project with the Project Name \"$ldesc\", please pick another."); }else{ throw new Exception("INSERT FAILED.\n\n".mysql_error()); } } }//exits INSERT FAILED. You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '3','2,'2','2,'2,'3)' at line 2

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• Automated URL checking from a MySQL table

  - by Rob

  Okay, I have a list of URLs in a MySQL table. I want the script to automatically check each link in the table for 404, and afterward I want it to store whether the URL was 404'd or not, as well as store a time for last checked. Is this even possible to do automatically, even if no one runs the script? ie, no one visits the page for a few days, but even with no one visiting the page, it automatically ran the test. If its possible, how could I go about making a button to do this?

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• MySQL Conventions?

  - by Moe

  Hi There, I just moved my website to a new server (Shared to VPS) I expected errors, and the only error that is really puzzling me is this SQL statement. echo mysql_query("SELECT COUNT(*) FROM users_online_now") This returns nothing! And if I try the mysql_num_rows, it returns mysql_num_rows(): supplied argument is not a valid MySQL result resource.. If I query another table though eg: echo mysql_query("SELECT COUNT(*) FROM users") It works fine. I'm guessing it's something to do with the naming of the table? It worked fine on my previous host, is there some setting I should modify?

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• searching a mysql database

  - by Bill Parson

  currently i have a database of music that i have db'd in mysql, now i am writing a php frontend for it, and it will list out everything in a table, it works, but if i search "the beatles" it gives me 453 results(correct) however if i just search "beatles" it results in 0 rows, how would i go about making it able to search for something like that? heres my current line: $query2 = "SELECT * From `songs` WHERE `Artist` like '".$_REQUEST['q']."' OR `Album` like '".$_REQUEST['q']."' OR `Genre` like '".$_REQUEST['q']."' OR `Title` like '".$_REQUEST['q']."';";

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• MySQL Many to Many with Unique keys and Update/Select if Exists otherwise Insert

  - by Jayrox

  In my goal to have a Many-to-Many relationship in my MySQL database I have arrived at another bridge to build. Current Tables: Users (id, name) Tags (id, name) User_Tags (user_id, tag_id) Here is the goal: I would like to have the ability to take a tag i.e: #fb and insert it into my Tags database which has a unique constraint on name and if the tag exists I would like to return it's id I would like to insert the tag.id and the current user's user.id into User_Tags. I do not have any unique constraints on the User_Tags table because I would like to be able to track the user's most commonly used tags and present them in a list ordered by frequency of use. I am currently developing this project in PHP using prepared statements. Additionally, performance is not currently an issue as my user count is still fairly small, but it is steadily growing and may be an issue in the future.

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• Help me for creating huge database in Mysql

  - by user90552

  We are building a website for business on global wise, for every country major cities are covered in this concept. I need some suggestions from PHP Mysql People. Can i create single databse for all cities or multiple databases. Because in this system contains some relations between cities ,every chamber need nearly 50 tables for networking and some other tables. If I can create separate databases for every chamber there would be nearly 50*1000 tables need because we have 1000 cities. So Please give suggestions how can i build database for my system. Thank you Ravi

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• Why is this MySQL Join Statement not Working?

  - by Timmy

  Here is my code: $query2 = mysql_query("SELECT * FROM categories WHERE parent = $id JOIN SELECT * FROM posts WHERE main_nav_page = '$idTwo'"); while ($row2 = mysql_fetch_assoc($query2)) { $id = $row2['id']; $name = $row2['name']; $slug = $row2['slug']; $subMenuOrder = $row2['sub_menu_order']; echo "<tr>\n"; echo "<td>&nbsp; -- $name</td>\n"; echo "</tr>\n"; } Is my syntax wrong? EDIT: the error message is: Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in /home/studentw/public_html/new_nav.php on line 30

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• mySQL php query - news/ friends feed

  - by rpsep2

  I want to show a user the recent uploads from their friends. I have the users friends id's in an array: $friends A user could have, potentially, thousands of friends. I can select the uploads from 1 of a users friends with: $row = $mysqli->query("SELECT * FROM photos WHERE uploader_id = ".$friend." ORDER BY date_uploaded DESC LIMIT ".$page.", 25"); But I need to find all of a users friends uploads. I thought about doing this in a loop iterating over the $friends array, but then I'd be potentially running thousands of mysql queries. How can I do this most efficiently? so to clarify: search a 'photos' table for photos which are uploaded by specific users(friends), held in $friends variable, sort by date_uploaded and limit to x results so I can have pages 1, 2, 3 etc.

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• Mysql on duplicate key update + sub query

  - by jwzk

  Using the answer from this question: http://stackoverflow.com/questions/662877/need-mysql-insert-select-query-for-tables-with-millions-of-records new_table * date * record_id (pk) * data_field INSERT INTO new_table (date,record_id,data_field) SELECT date, record_id, data_field FROM old_table ON DUPLICATE KEY UPDATE date=old_table.data, data_field=old_table.data_field; I need this to work with a group by and join.. so to edit: INSERT INTO new_table (date,record_id,data_field,value) SELECT date, record_id, data_field, SUM(other_table.value) as value FROM old_table JOIN other_table USING(record_id) ON DUPLICATE KEY UPDATE date=old_table.data, data_field=old_table.data_field, value = value; I can't seem to get the value updated. If I specify old_table.value I get a not defined in field list error.

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• MYSQL Inserting rows that reference main rows.

  - by Andrew M

  I'm transferring my access logs into a database. I've got two tables: urlRequests id : int(10) host : varchar(100) path: varchar(300) unique index (host, path) urlAccesses id : int(10) request : int(10) <-- reference to urlRequests row ip : int(4) query : varchar(300) time : timestamp I need to insert a row into urlAccesses for every page load, but first a row in urlRequests has to exist with the requested host and path so that urlAccesses's row can reference it. I know I can do it this way: A. check if a row exists in urlRequests B. insert a row in urlRequests if it needs it C. insert a row into urlAccesses with the urlRequests's row id referenced That's three queries for every page load if the urlRequests row doesn't exist. I'm very new to MySQL, so I'm guessing that there's a way to go about this that would be faster and use less queries.

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• MySQL ON DUPLICATE KEY UPDATE issue

  - by user644347

  Hi could some one look at this and tell me where I am going wrong. I have an SQL statement that when I echo using php I get this to screen INSERT INTO 'moviedb'.'genre' SET 'GenreID' = '18' , 'GenreName' = 'Drama' ON DUPLICATE KEY UPDATE 'GenreName' = 'Drama' WHERE 'GenreID' = '18' INSERT INTO 'moviedb'.'genre' SET 'GenreID' = '16' , 'GenreName' = 'Animation' ON DUPLICATE KEY UPDATE 'GenreName' = 'Animation' WHERE 'GenreID' = '16' And here is the statement $sql="INSERT INTO 'moviedb'.'genre' SET 'GenreID' = '{$genresID[$i]}' , 'GenreName' = '{$genreName[$i]}' ON DUPLICATE KEY UPDATE 'GenreName' = '{$genreName[$i]}' WHERE 'GenreID' = '{$genresID[$i]}'"; This is the error I recieve: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''moviedb'.'genre' SET 'GenreID' = '18' , 'GenreName' = 'Drama' ON DUPLICATE KEY ' at line 1 Any help would be greatly appreciated, thanks in advance.

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• Why doesn't MySQL support millisecond / microsecond precision?

  - by Byron Whitlock

  So I just found the most frustrating bug ever in MySQL. Apparently the TIMESTAMP field, and supporting functions do not support any greater precision than seconds!? So I am using PHP and Doctrine, and I really need those microseconds (I am using the actAs: [Timestampable] property). I found a that I can use a BIGINT field to store the values. But will doctrine add the milliseconds? I think it just assigns NOW() to the field. I am also worried the date manipulation functions (in SQL) sprinkled through the code will break. I also saw something about compiling a UDF extension. This is not an acceptable because I or a future maintainer will upgrade and poof, change gone. Has anyone found a suitable workaround?

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• MySQL order by error in PHP

  - by theflyinghaiwian

  Hi, I'm making a simple cms system for a site I'm making for non-tech users to edit... So far so good but when I try and run this code I keep getting: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''pages' ORDER BY 'pages'.'pageOrder' ASC LIMIT 0 , 30' at line 1 By the error it looks like a problem with the order by section and indeed it works without it... $sql = "SELECT * FROM 'pages' ORDER BY 'pages'.'pageOrder' ASC LIMIT 0 , 30"; $result = mysql_query($sql) or die(mysql_error()); Now I know there is nothing wrong with the code because originally I wrote my own SQL but then after it failed I robbed some from phpmyadmin and it still gives the error but it works in phpmyadmin... I'm really at my wits end with this, help is very much appreciated thank you...

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• mySQL INSERT INTO SELECT not working

  - by Industrial

  Hi everyone, I am trying to implement the "Closure Table" structure in a php/mySQL webapp from Bill Karwins "SQL Antipatterns" slideshare presentation: http://www.slideshare.net/billkarwin/sql-antipatterns-strike-back The first step is to insert some stuff into my tree (page 73 in slide): Easy to insert a new child of comment #5: INSERT INTO Comments ... (Generates comment #8) INSERT INTO TreePaths (ancestor, descendant) VALUES (8, 8); INSERT INTO TreePaths (ancestor, descendant) SELECT ancestor, 8 FROM TreePaths WHERE descendant = 5; I try to translate all this into Codeigniters active record db-style language, and that's about where I get stuck. I cant understand how the second insert gets it's values. Is there anyone out there who can help me out with this?

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• trying to put an mysql result into a string

  - by user1583432

  I'm trying to put an mysql query result into an string I tried to find an answer but all the similar posts were getting subquery answers which is not what I'm trying to do. for example Fruits_tbl ID Fruit Color Number __________________________________ 2 Apple Red 5 $sql = "select Fruits,Color,Number from Fruits_tbl where ID = 2"; $result = $pdo->query($sql); $row = $result->fetch(); print_r($row); This will give me something like Array([0]="Apple", [1]="Red", [2]="5", [Fruit]="Apple", [Color]="Red", [Number]="5") implode will give me 2 of each I want just need a string = "Apple, Red, 5" what I currently have is $string = $row[Fruit].", ".$row[Color].", ".$row['Number'] As you can see that's rather tedious. Is there something like implode but only return the index array or something?

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• mysql - check if data exists across multiple tables

  - by Dd Daym

  I am currently running this query inside MySQL to check if the specified values exists within the table associated with them. SELECT COUNT(artist.artist_id), COUNT(album.album_id), COUNT(tracks.track_id) FROM artist, album, tracks WHERE artist.artist_id = 320295 OR album.album_id = 1234 OR tracks.track_id = 809 The result I get from running this query is all 1, meaning that all the statements after the WHERE clause is true. To further check the query's reliability, I changed the tracks.track_ = 809 to 802, which I know does not match. However the results displayed are still all 1, meaning that they were all successfully matched even when I purposefully inserted a value which would not have matched. How do I get it to show 1 for a match and 0 for no matches within the same query? EDIT: I have inserted an image of the query running

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• Mysql query help needed

  - by Me-and-Coding

  Hi, i have two tables category and hotels where category.id should be equal to hotels.catid. Now how do i select 3 rows from each different category from the hotels table. I have this query: select h.* from hotels h inner join category c on h.catid = c.id order by h.catid, h.hid this selects all records, but i want to select three rows per different category so in all it should return 9 rows with 3 rows for each category. If this can not be done in mysql, you could also suggest php code please. Thanks

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