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  • Cakephp beforeFind() - How do I add a JOIN condition AFTER the belongsTo association is added?

    - by michael
    I'm in Model-beforeFind($queryData), trying to add a JOIN condition to the queryData on a model which has belongsTo associations. Unfortunately, the new JOIN references a table in the belongsTo association, so it must appear AFTER the belongsTo in the query. Here is my Tagged-belongsTo association: app\plugins\tags\models\tagged.php (line 192) Array ( [Tag] => Array ( [className] => Tag [foreignKey] => tag_id [conditions] => [fields] => [order] => [counterCache] => ) [Group] => Array ( [className] => Group [foreignKey] => foreign_key [conditions] => Array ( [Tagged.model] => Group ) [fields] => [order] => [counterCache] => ) ) Here is the JOIN added in Tagged-beforeFind(), notice that the belongsTo joins have not yet been added: app\plugins\tags\models\tagged.php (line 194) Array ( [conditions] => Array ( [Tag.keyname] => europe ) [fields] => Array ( [0] => DISTINCT Group.* [1] => GroupPermission.* ) [joins] => Array ( [0] => Array ( [table] => permissions [alias] => GroupPermission [foreignKey] => [type] => INNER [conditions] => Array ( [GroupPermission.model] => Group [0] => GroupPermission.foreignId = Group.id [or] => Array ( ... ) ) ) ) [limit] => [offset] => [order] => Array ( [0] => ) [page] => 1 [group] => [callbacks] => 1 [by] => europe [model] => Group ) When I check the output, it fails with "1054: Unknown column 'Group.id' in 'on clause'" because the Permissions join appeared BEFORE the Groups join. SELECT DISTINCT `Group`.*, `GroupPermission`.* FROM `tagged` AS `Tagged` INNER JOIN permissions AS `GroupPermission` ON (`GroupPermission`.`model` = 'Group' AND `GroupPermission`.`foreignId` = `Group`.`id` AND (...)) LEFT JOIN `tags` AS `Tag` ON (`Tagged`.`tag_id` = `Tag`.`id`) LEFT JOIN `groups` AS `Group` ON (`Tagged`.`foreign_key` = `Group`.`id` AND `Tagged`.`model` = 'Group') WHERE `Tag`.`keyname` = 'europe' But this SQL (with Permissions joined moved to the end) works fine: SELECT DISTINCT `Group`.*, `GroupPermission`.* FROM `tagged` AS `Tagged` LEFT JOIN `tags` AS `Tag` ON (`Tagged`.`tag_id` = `Tag`.`id`) LEFT JOIN `groups` AS `Group` ON (`Tagged`.`foreign_key` = `Group`.`id` AND `Tagged`.`model` = 'Group') INNER JOIN permissions AS `GroupPermission` ON (`GroupPermission`.`model` = 'Group' AND `GroupPermission`.`foreignId` = `Group`.`id` AND (...)) WHERE `Tag`.`keyname` = 'europe' How do I add my join in beforeFind() after the belongsTo join?

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  • Is it possible to use CASE with IN?

    - by dkackman
    I'm trying to construct a T-SQL statement with a WHERE clause determined by an input parameter. Something like: SELECT * FROM table WHERE id IN CASE WHEN @param THEN (1,2,4,5,8) ELSE (9,7,3) END I've tried all combination of moving the IN, CASE etc around that I can think of. Is this (or something like it) possible?

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  • How to pass some data to JQuery AJAX in CAKEPHP

    - by kwokwai
    Hi all, I am learning how to use JQuery to help check data availability. To start with it, I wrote a few lines of codes using cakePHP. I have written a function in a Controller for checking data input, and the URL is like this: http://www.mywebsite.com/controllers/action/avariable I was trying to pass the value in a Input TextBox field using the JQuery Ajax to the URL above,but I don't know why it is not working in passing a variable to the Controller's action. Could you help me out please? <Script language="javascript"> //<!-- $(document).ready(function(){ $(document).change(function() { var usr = $("#data\\[User\\]\\[name\\]").val(); if(usr.length >= 3){ $("#username").append('<span><img align="absmiddle" src="loader.gif" />Checking</span>'); $.ajax({ type: "POST", url: "http://www.mywebsite.com/controllers/action/", data: usr, success: function(msg){ if(msg == 'OK') { $("#username").append('<span><img align="absmiddle" src="accepted.png"/></span>'); } else { $("#username").append('<span>'+msg+'</span>'); } } }); } else { $("#username").append('<span>The username should have at least 3 characters.</span>'); } }); }); //--> </Script> <form name="adduser" id="adduser" method="post" action="/controllers/action2"> <table border=0 width="100%"> <tr> <td>Username</td> <td> <div id="username"> <input type=text name="data[User][name]" id="data[User][name]"> </div> </td> </tr> <tr> <td> <input type="submit" value="Send"> </td> </tr> </table> </form>

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  • mysql category tree search

    - by ffffff
    I have the following schema on MySQL 5.1 CREATE TABLE `mytest` ( `category` varchar(32) , `item_name` varchar(255) KEY `key1` (`category`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1; category column is filled with like that [:parent_parent_cat_id][:parent_cat_id][:leaf_cat_id] "10000200003000" if you can search all of the under categories :parent_parent_category_id SELECT * FROM mytest WHERE category LIKE "10000%"; it's using index key1; but How to use index when I wanna search :parent_cat_id? SELECT * FROM mytest WHERE category LIKE "%20000%"; Do you have a better solutions?

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  • How do I select a random record efficiently in MySQL?

    - by user198729
    mysql> EXPLAIN SELECT * FROM urls ORDER BY RAND() LIMIT 1; +----+-------------+-------+------+---------------+------+---------+------+-------+---------------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------+------+---------------+------+---------+------+-------+---------------------------------+ | 1 | SIMPLE | urls | ALL | NULL | NULL | NULL | NULL | 62228 | Using temporary; Using filesort | +----+-------------+-------+------+---------------+------+---------+------+-------+---------------------------------+ The above doesn't qualify as efficient,how should I do it properly?

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  • Change an autoincrementing field to one previous

    - by jlan
    One day, wordpress suddenly jumped from pots id 9110 to 890000000 post. Days later I'd like to move back new posts to continue from id 9111. I'm sure that id will never reach id 890000000, no problem here, but id is an autoincrement field and "ALTER TABLE wp8_posts AUTO_INCREMENT =9111" is not working. Can I force id to continue from 9111 ?

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  • Operation precedence on postgress

    - by user24691
    I have set new division on postgress pg_operator table because i want tath when is division by zero return 0. i have write this: create operator / ( procedure = zero_division, leftarg = double precision, rightarg = double precision); where zero_division is: CREATE OR REPLACE FUNCTION zero_division(double precision, double precision) RETURNS double precision AS 'select case when $2 = 0 then 0 else $1 / $2::real end;' LANGUAGE sql IMMUTABLE COST 100; when i run value/ 0 i get error of division.

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  • gauge chart is not displaying any thing

    - by Sandy
    i am trying to display the latest speed in mysql database on guage chart. i have tried so many things but gauge is not display plz any can help me...my code is attached and php part shows the correct value but dont know why guage is not display <?php $host="localhost"; // Host name $username="root"; // Mysql username $password=""; // Mysql password $db_name="mysql"; // Database name $tbl_name="gpsdb"; // Table name // Connect to server and select database. $con=mysql_connect("$host", "$username")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $data = mysql_query("SELECT speed FROM gpsdb WHERE DeviceId=1234 ORDER BY TIME DESC LIMIT 1") or die(mysql_error()); while ($nt = mysql_fetch_assoc($data)) { $speed = $nt['speed']; $jsonTable = json_encode($speed); echo $jsonTable; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="content-type" content="text/html; charset=utf-8"/> <title> Google Visualization API Sample </title> <script type="text/javascript" src="//www.google.com/jsapi"></script> <script type="text/javascript"> google.load('visualization', '1', {packages: ['gauge']}); </script> <script type="text/javascript"> function drawVisualization() { // Create and populate the data table. var data = new google.visualization.DataTable(<?=$speed?>); // Create and draw the visualization. new google.visualization.Gauge(document.getElementById('visualization')). draw(data); } google.setOnLoadCallback(drawVisualization); </script> </head> <body style="font-family: Arial;border: 0 none;"> <div id="visualization" style="width: 600px; height: 300px;"></div> </body> </html>

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  • What is the best way of inserting a datetime value using dynamic sql

    - by jaffa
    What is the best way of inserting a datetime value using a dynamic sql string, whilst at the same time being able to handle the possibility of the value being null? The current statement inserts into a table from a select statement built using a string. The datetime value is stored in a parameter and the parameter is used in the select. Like so: set @execsql = 'Insert into ( start_date ) SELECT ( ''' + CAST(start_date as VARCHAR) + ''' + ')'

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  • MySQL> Selecting from more tables (with same columns) without UNION

    - by Petr
    Hi, It is probably pretty simple but I cannot figure it out: Say I have tables A and B both with the same columns. I need to do SELECT * FROM A,B without having results merged into one row. I.e. when each table has 2 rows, I need the result to have 4 rows. EDIT: I know about JOIN but dont know how to join the tables without predicate. I need merge them. Thanks

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  • Selecting rows distinctively

    - by noway
    Lets assume my database table structure is something like | items | weight | |============|==========| | item_1 | 50 | | item_2 | 90 | | item_2 | 45 | | item_2 | 60 | | item_3 | 40 | In the select statement, I want to show an item only for once with the highest weight also ordered by height. So the result should be : | items | weight | |============|==========| | item_2 | 90 | | item_1 | 50 | | item_3 | 40 | I tried something like SELECT DISTINCT items, weight FROM mytable ORDER BY weight DESC but it didn't work because the results are actually distinct. How can I make that selection?

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  • Convert multiquery to a query using group by and so on

    - by ffffff
    -schema CREATE TABLE `ratings` ( `id` int(11) NOT NULL default '0', `rating` int(11) NOT NULL default '1', `rating_start` datetime NOT NULL default '0000-00-00 00:00:00', PRIMARY KEY (`id`) ) TYPE=MyISAM -myprogram.php foreach($ids as $id){ $sql = "SELECT rating FROM ratings WHERE id = '$id' AND rating_start >= NOW()"; $sql .= "ORDER BY rating_start DESC LIMIT 1;" $ret = $db->execute($id); } Can I teke same date from a Query? by using id IN (".implode(",",$ids).") and GROUP BY id

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  • Application crashes while using the scroll bars in winForm Datagrid view

    - by subbu
    Hi all i have a background worker thread and some unmanaged code dlls , In progress changed event of background worker . I will get the data from my database in a datatable and make this table as my DataSource. But when i use the scrollbards od DataGridView my application crashes.when I try to debug the application it gives "Unhandled exception in TestExe.exe : 0xC0000096: Privileged Instruction.

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  • SQLite trigger to update Summary Counts

    - by jrhicks
    Consider the following two (hypothetical) tables Temperature * day * time * lake_name * station * temperature_f Temperature_summary * day * lake_name * station * count_readings_over_75f * count_readings_below_75f How can I write an SQLite Trigger to update the temperature_summary table on insert. I want to increment the count. Thank You, Jeff

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  • I want to do a sql update loop statement, by using the do--while in php

    - by Jean
    Hello, I want to loop the update statement, but it only loops once. Here is the code I am using: do { mysql_select_db($database_ll, $ll); $query_query= "update table set ex='$71[1]' where field='val'"; $query = mysql_query($query_query, $ll) or die(mysql_error()); $row_domain_all = mysql_fetch_assoc($query); } while ($row_query = mysql_fetch_assoc($query)); Thanks Jean

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  • Get previous and next row from current id

    - by Hukr
    How can I do to get the next row in a table? `image_id` int(11) NOT NULL auto_increment `image_title` varchar(255) NOT NULL `image_text` mediumtext NOT NULL `image_date` datetime NOT NULL `image_filename` varchar(255) NOT NULL If the current image is 3 for example and the next one is 7 etc. this won’t work: $query = mysql_query("SELECT * FROM images WHERE image_id = ".intval($_GET['id'])); echo $_GET['id']+1; How should I do? thanks

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