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  • Is my class structure good enough?

    - by Rivten
    So I wanted to try out this challenge on reddit which is mostly about how you structure your data the best you can. I decided to challenge my C++ skills. Here's how I planned this. First, there's the Game class. It deals with time and is the only class main has access to. A game has a Forest. For now, this class does not have a lot of things, only a size and a Factory. Will be put in better use when it will come to SDL-stuff I guess A Factory is the thing that deals with the Game Objects (a.k.a. Trees, Lumberjack and Bears). It has a vector of all GameObjects and a queue of Events which will be managed at the end of one month. A GameObject is an abstract class which can be updated and which can notify the Event Listener The EventListener is a class which handles all the Events of a simulation. It can recieve events from a Game Object and notify the Factory if needed, the latter will manage correctly the event. So, the Tree, Lumberjack and Bear classes all inherits from GameObject. And Sapling and Elder Tree inherits from Tree. Finally, an Event is defined by an event_type enumeration (LUMBERJACK_MAWED, SAPPLING_EVOLUTION, ...) and an event_protagonists union (a GameObject or a pair of GameObject (who killed who ?)). I was quite happy at first with this because it seems quite logic and flexible. But I ended up questionning this structure. Here's why : I dislike the fact that a GameObject need to know about the Factory. Indeed, when a Bear moves somewhere, it needs to know if there's a Lumberjack ! Or it is the Factory which handles places and objects. It would be great if a GameObject could only interact with the EventListener... or maybe it's not that much of a big deal. Wouldn't it be better if I separate the Factory in three vectors ? One for each kind of GameObject. The idea would be to optimize research. If I'm looking do delete a dead lumberjack, I would only have to look in one shorter vector rather than a very long vector. Another problem arises when I want to know if there is any particular object in a given case because I have to look for all the gameObjects and see if they are at the given case. I would tend to think that the other idea would be to use a matrix but then the issue would be that I would have empty cases (and therefore unused space). I don't really know if Sapling and Elder Tree should inherit from Tree. Indeed, a Sapling is a Tree but what about its evolution ? Should I just delete the sapling and say to the factory to create a new Tree at the exact same place ? It doesn't seem natural to me to do so. How could I improve this ? Is the design of an Event quite good ? I've never used unions before in C++ but I didn't have any other ideas about what to use. Well, I hope I have been clear enough. Thank you for taking the time to help me !

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  • global member creation

    - by Akash
    how the global members can be created in vc++ 6.0 mfc project. if i select globals option in WizardBar(WizardBar C++ class). then (WizardBar C++ members),it display (No members - Create New Class...). How to create the members for this globals class please give the steps to create.

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  • Where are config files for class libraries physically located?

    - by BadNinja
    My guess is that this question will fall under the category of "duh", but, nevertheless, I'm confused. When using config files in, for example, a Windows Forms Application, the config file can be found in C:\Program files\CompanyName\ProductName\Application.exe.config. However, with the class library I'm developing I do not see a "ClassLibrary.dll.config" file in the install folder after installing it (in tandem with another project) from Visual Studio. Even though I do not see the file anywhere, retrieving data from it works correctly. Plus, running the following code from a method within the class library returns the path you would expect: C:\Program files\CompanyName\ProductName\ClassLibrary.dll.config. If someone could shed some light on what I'm missing here, that would be really awesome. public static string MyMethod() { Assembly assem = Assembly.GetExecutingAssembly(); Configuration config = ConfigurationManager.OpenExeConfiguration(assem.Location); return "The assembly location was: " + assem.Location + Environment.NewLine + "The config file path was: " + config.FilePath; // Gives me "C:\Program files\CompanyName\ProductName\ClassLibrary.dll.config" }

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  • need to print 5 column list in alpha order, vertically

    - by Brad
    Have a webpage that will be viewed by mainly IE users, so CSS3 is out of the question. I want it to list like: A D G B E H C F I Here is the function that currently lists like: A B C D E F G H I function listPhoneExtensions($group,$group_title) { $adldap = new adLDAP(); $group_membership = $adldap->group_members(strtoupper($group),FALSE); sort($group_membership); print " <a name=\"".strtolower($group_title)."\"></a> <h2>".$group_title."</h2> <ul class=\"phone-extensions\">"; foreach ($group_membership as $i => $username) { $userinfo = $adldap->user_info($username, array("givenname","sn","telephonenumber")); $displayname = "<span class=\"name\">".substr($userinfo[0]["sn"][0],0,9).", ".substr($userinfo[0]["givenname"][0],0,9)."</span><span class=\"ext\">".$userinfo[0]["telephonenumber"][0]."</span>"; if($userinfo[0]["sn"][0] != "" && $userinfo[0]["givenname"][0] != "" && $userinfo[0]["telephonenumber"][0] != "") { print "<li>".$displayname."</li>"; } } print "</ul><p class=\"clear-both\"><a href=\"#top\" class=\"link-to-top\">&uarr; top</a></p>"; } Example rendered html: <ul class="phone-extensions"> <li><span class="name">Barry Bonds</span><span class="ext">8281</span></li> <li><span class="name">Gerald Clark</span><span class="ext">8211</span></li> <li><span class="name">Juan Dixon</span><span class="ext">8282</span></li> <li><span class="name">Omar Ebbs</span><span class="ext">8252</span></li> <li><span class="name">Freddie Flank</span><span class="ext">2281</span></li> <li><span class="name">Jerry Gilmore</span><span class="ext">4231</span></li> <li><span class="name">Kim Moore</span><span class="ext">5767</span></li> <li><span class="name">Barry Bonds</span><span class="ext">8281</span></li> <li><span class="name">Gerald Clark</span><span class="ext">8211</span></li> <li><span class="name">Juan Dixon</span><span class="ext">8282</span></li> <li><span class="name">Omar Ebbs</span><span class="ext">8252</span></li> <li><span class="name">Freddie Flank</span><span class="ext">2281</span></li> <li><span class="name">Jerry Gilmore</span><span class="ext">4231</span></li> <li><span class="name">Kim Moore</span><span class="ext">5767</span></li> <li><span class="name">Barry Bonds</span><span class="ext">8281</span></li> <li><span class="name">Gerald Clark</span><span class="ext">8211</span></li> <li><span class="name">Juan Dixon</span><span class="ext">8282</span></li> <li><span class="name">Omar Ebbs</span><span class="ext">8252</span></li> <li><span class="name">Freddie Flank</span><span class="ext">2281</span></li> <li><span class="name">Jerry Gilmore</span><span class="ext">4231</span></li> <li><span class="name">Kim Moore</span><span class="ext">5767</span></li> </ul> Any help is appreciated to getting it to list alpha vertically.

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  • jQuery DOM element creation vs innerHTML

    - by Mohammad
    While having one of my questions answered, cletus mentioned that when creating elements in jQuery it's better to use direct DOM element creation, instead of innerHTML. I tried googling it but I wasn't able to find a good article with comparisons. I've provided this code bellow as an example and I was wondering if someone could help me rewrite it in direct DOM element creation form in hope that i would also learn the difference afterwards. var img = $(this); img.append('<p class="cap"><a href="'+img.parent().attr('href')+'">'+ img.attr('title')+'</p></a>'); Thanks so much.

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  • CorePlot linker errors after upgrading iOS SDK

    - by JustinXXVII
    This seems like it's happened before but somehow ended up working itself out. It's happened again and I can't seem to get this fixed. I use the CorePlot Cocoa Touch framework. Everything was fine until I upgraded to the new 4.3 beta. Now my project won't compile, and is giving me linker errors for unknown symbols having to do with CorePlot. I've become a pro at adding the framework to my project, and I've checked and rechecked the instructions trying to do it again. Is there a button I can click or anything to just make this work again? I've used these instructions to try to re-add the framework, to no avail EDIT: By the way, this compiles just fine for simulator and runs graphs no problem. Compiling for the device gives me the linker errors, as follows: "_OBJC_CLASS_$_CPPlotRange", referenced from: objc-class-ref in GraphStatsWindow.o objc-class-ref in iPadGraphView.o objc-class-ref in GraphTrendView.o "_OBJC_CLASS_$_CPXYGraph", referenced from: objc-class-ref in GraphStatsWindow.o objc-class-ref in iPadGraphView.o objc-class-ref in GraphTrendView.o "_OBJC_CLASS_$_CPTextStyle", referenced from: objc-class-ref in GraphStatsWindow.o objc-class-ref in iPadGraphView.o objc-class-ref in GraphTrendView.o "_OBJC_CLASS_$_CPLineStyle", referenced from: objc-class-ref in GraphStatsWindow.o objc-class-ref in iPadGraphView.o objc-class-ref in GraphTrendView.o "_OBJC_CLASS_$_CPScatterPlot", referenced from: objc-class-ref in GraphStatsWindow.o objc-class-ref in iPadGraphView.o objc-class-ref in GraphTrendView.o "_OBJC_CLASS_$_CPAxisLabel", referenced from: objc-class-ref in GraphStatsWindow.o objc-class-ref in iPadGraphView.o objc-class-ref in GraphTrendView.o "_OBJC_CLASS_$_CPPlotSymbol", referenced from: objc-class-ref in GraphStatsWindow.o objc-class-ref in iPadGraphView.o objc-class-ref in GraphTrendView.o "_OBJC_CLASS_$_CPColor", referenced from: objc-class-ref in GraphStatsWindow.o objc-class-ref in iPadGraphView.o objc-class-ref in GraphTrendView.o "_OBJC_CLASS_$_CPFill", referenced from: objc-class-ref in GraphStatsWindow.o objc-class-ref in iPadGraphView.o objc-class-ref in GraphTrendView.o "_CPDecimalFromFloat", referenced from: -[GraphStatsWindow setNewGraph] in GraphStatsWindow.o -[iPadGraphView viewDidLoad] in iPadGraphView.o -[GraphTrendView setNewGraph] in GraphTrendView.o "_kCPPlainWhiteTheme", referenced from: -[GraphStatsWindow setNewGraph] in GraphStatsWindow.o -[iPadGraphView viewDidLoad] in iPadGraphView.o -[GraphTrendView setNewGraph] in GraphTrendView.o "_OBJC_CLASS_$_CPTheme", referenced from: objc-class-ref in GraphStatsWindow.o objc-class-ref in iPadGraphView.o objc-class-ref in GraphTrendView.o ld: symbol(s) not found for architecture armv7

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  • Response is not available in this context when creation cookie's

    - by Sadegh
    hi i defined one class to create cookie by received parameter's from user. when i want to add cookie to context i receive an exception. My Class public static class ManageCookies { public static void Create(string name, string value) { HttpCookie cookie = new HttpCookie(name); cookie.Value = value; cookie.Expires = DateTime.Now.AddYears(1); HttpContext.Current.Response.Cookies.Add(cookie); } } Occured Exception: Response is not available in this context.

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  • VS 2010 Class Diagram Error "The type cannot be edited..."

    - by Eric J.
    A few of the classes on a VS 2010 class diagram are displayed with a red title. The Class Details window shows all of the methods, properties, fields and correctly shows no events. However, there's an entry under each of methods, properties, fields and events that states where the name should be: "The type cannot be edited because the source code file contains an error." However, the source file builds with no errors or warnings. Anyone seen this? Any idea how to fix it?

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  • jquery typeWatch with Dynamic input fields added on the fly.

    - by mtyagi
    How can i get the Id of the input field added on the fly? My script adds the input fields on click on the button , using var ix = 1; $(template2(ix++)).appendTo("#dataTable tbody"); var template2 = jQuery.format($("#template2").val()); I also add this , line after the insertion of the new fields, so it adds the typeWatch to all the .email class fields. $(".email").typeWatch( { highlight:true, callback:function(){alert("changed search text"); }, wait:750 } ); now, in the callback function , I want to get the Id of the input field typeWatch Callback is triggered. Please advice. Thanks

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  • how do I use html block snippets with dynamic content inside a django template that extends another

    - by stackoverflowusername
    Hi. Can someone please help me figure out a way to achieve the following (see snippets below) in Django templates? I know that you cannot use more than one extends, but I am new to django and I do not know the proper syntax for something like this. I want to be able to do this so that I can use my nested div layout for css reasons without having to type it like that each time and risking a typo. In words, I want to be able to have a page template extend my base.html file and then use html snippets of dynamic template content (i.e. template for loops or other template logic devices, not just a context variable I set from my view controller). ------------------------------------------------------------ base.html ------------------------------------------------------------ <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <meta http-equiv="Content-Type" content="text/html;charset=utf-8" /> <title>{% block title %}Title{% endblock %}</title> </head> <body> <div class="wrapper"> <div class="header"> This is the common header </div> <div class="nav"> This is the common nav </div> {% if messages %} <div class="messages"> <ul> {% for message in messages %} <li{% if message.tags %} class="{{ message.tags }}"{% endif %}>{{ message }}</li> {% endfor %} </ul> </div> {% endif %} <div class="content"> {% block content %}Page Content{% endblock %} </div> <div class="footer"> This is the common footer </div> </div> </body> </html> ------------------------------------------------------------ columnlayout2.html ------------------------------------------------------------ <div class="twocol container2"> <div class="container1"> <div class="col1"> {% block twocol_col1 %}{% endblock %} </div> <div class="col2"> {% block twocol_col2 %}{% endblock %} </div> </div> </div> ------------------------------------------------------------ columnlayout3.html ------------------------------------------------------------ <div class="threecol container3"> <div class="container2"> <div class="container1"> <div class="col1"> {% block threecol_col1 %}{% endblock %} </div> <div class="col2"> {% block threecol_col2 %}{% endblock %} </div> <div class="col3"> {% block threecol_col3 %}{% endblock %} </div> </div> </div> </div> ------------------------------------------------------------ page.html ------------------------------------------------------------ {% extends "base.html" %} {% block content %} {% extends "columnlayout2.html" %} {% block twocol_col1 %}twocolumn column 1{% endblock %} {% block twocol_col2 %}twocolumn column 2{% endblock %} {% extends "columnlayout3.html" %} {% block threecol_col1 %}threecol column 1{% endblock %} {% block threecol_col2 %}threecol column 2{% endblock %} {% block threecol_col3 %}threecol column 3{% endblock %} {% endblock %} ------------------------------------------------------------ page.html output ------------------------------------------------------------ <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <meta http-equiv="Content-Type" content="text/html;charset=utf-8" /> <title>Title</title> </head> <body> <div class="wrapper"> <div class="header"> This is the common header </div> <div class="nav"> This is the common nav </div> <div class="content"> <div class="twocol container2"> <div class="container1"> <div class="col1"> twocolumn column 1 </div> <div class="col2"> twocolumn column 2 </div> </div> </div> <div class="threecol container3"> <div class="container2"> <div class="container1"> <div class="col1"> threecol column 1 </div> <div class="col2"> threecol column 2 </div> <div class="col3"> threecol column 3 </div> </div> </div> </div> </div> <div class="footer"> This is the common footer </div> </div> </body> </html>

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  • C++ method declaration, class definition problem

    - by John Fra.
    I have 2 classes: A and B. Some methods of class A need to use class B and the opposite(class B has methods that need to use class A). So I have: class A; class B { method1(A a) { } } class A { method1(B b) { } void foo() { } } and everything works fine. But when I try to call foo() of class A from B::method1 like this: class B { method1(A a) { a.foo(); } } I get as result compile errors of forward declaration and use of incomplete type. But why is this happening? (I have declared class A before using it?)

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  • Howto write a class where a property can be accessed without naming it.

    - by SchlaWiener
    I have a (dump) question regarding VB/C# I often use third party classes where I can access a child object with only specifying the id or key. Example: Instead of writing: DataRow row = GetAPopulatedDataRowSomeWhere(); Object result = row.Items[1]; // DataRow has no Items property Object result = row.Items["colName"]; // Also not possible I use this code to access the members: DataRow row = GetAPopulatedDataRowSomeWhere(); Object result = row[1]; Object result = row["colName"]; Can someone tell me how a class has to look like to support this syntax? My own class has a Dictionary that I want to access this way. MyClass["key"]; // <- that's what I want MyClass.SubItems["key"]; // <- that's how I use it now

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  • Watir question regarding exist on a class for testing purposes.

    - by AJ
    I have a button on my page that changes depending on what radio button is clicked. The button has the same text on it with the same id, but different classes. How do I test if the two different buttons exist depending on the radio. <a id="submit" class="on" href="javascript:submit();">Submit</a> <a id="submit" class="off" href="javascript:submit();">Submit</a> How do i test if the second button appears instead of the first one. I used something like, browser.link(:text, 'Submit').exist? but this doesn't work cause it will return true no matter what. thanks

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  • How can I create a new class instance from a class within a (static) class?

    - by Mervin
    I'm new to Java (have experience with C#), This is what i want to do: public final class MyClass { public class MyRelatedClass { ... } } public class OtherRandomClass { public void DoStuff() { MyRelatedClass data = new MyClass.MyRelatedClass(); } } which gives this error in Eclipse: "No enclosing instance of type BitmapEffects is accessible. Must qualify the allocation with an enclosing instance of type BitmapEffects (e.g. x.new A() where x is an instance of BitmapEffects)." this is possible in C# with static classes , how should it be done here?

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  • Should I use Enumeration or Class stereotype in UML to represent a type directory table?

    - by Ivan
    Let's take 2 UML class model entities: One represents an actual Order and another represents an Orede Type. Any Order corresponds to one Type. A 2-way-naviglabe many Orders to one Type relation is meant. Order Type instances are, for example, "Request availability", "Request price", "Preorder", "Buy", "Cancel", "Request support", etc. Order Types are to be addable and editable in the resulting application. Should I model Order Type as Class or as Enumeration? From the data perspective I can't see the difference actually.

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  • PHP 5.3: Late static binding doesn't work for properties when defined in parent class while missing in child class

    - by DavidPesta
    Take a look at this example, and notice the outputs indicated. <?php class Mommy { protected static $_data = "Mommy Data"; public static function init( $data ) { static::$_data = $data; } public static function showData() { echo static::$_data . "<br>"; } } class Brother extends Mommy { } class Sister extends Mommy { } Brother::init( "Brother Data" ); Sister::init( "Sister Data" ); Brother::showData(); // Outputs: Sister Data Sister::showData(); // Outputs: Sister Data ?> My understanding was that using the static keyword would refer to the child class, but apparently it magically applies to the parent class whenever it is missing from the child class. (This is kind of a dangerous behavior for PHP, more on that explained below.) I have the following two things in mind for why I want to do this: I don't want the redundancy of defining all of the properties in all of the child classes. I want properties to be defined as defaults in the parent class and I want the child class definition to be able to override these properties wherever needed. The child class needs to exclude properties whenever the defaults are intended, which is why I don't define the properties in the child classes in the above example. However, if we are wanting to override a property at runtime (via the init method), it will override it for the parent class! From that point forward, child classes initialized earlier (as in the case of Brother) unexpectedly change on you. Apparently this is a result of child classes not having their own copy of the static property whenever it isn't explicitly defined inside of the child class--but instead of throwing an error it switches behavior of static to access the parent. Therefore, is there some way that the parent class could dynamically create a property that belongs to the child class without it appearing inside of the child class definition? That way the child class could have its own copy of the static property and the static keyword can refer to it properly, and it can be written to take into account parent property defaults. Or is there some other solution, good, bad, or ugly?

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  • Having a Link Only Appear If a Logged-In User Appears on a Dynamic List

    - by John
    Hello, For the function below, I would like the link <div class="footervote"><a href="http://www...com/.../footervote.php">Vote</a></div> to only appear if the logged in user currently appears on editorlist.php. (I. e. if the loginid in the function corresponds to any of the usernames that currently appear in editorlist.php.) Appearing on editorlist.php is something that is dynamic. How can I do this? Thanks in advance, John function show_userbox() { // retrieve the session information $u = $_SESSION['username']; $uid = $_SESSION['loginid']; // display the user box echo '<div id="userbox"> <div class="username">'.$u.'</div> <div class="submit"><a href="http://www...com/.../submit.php">Submit an item.</a></div> <div class="changepassword"><a href="http://www...com/.../changepassword.php">Change Password</a></div> <div class="logout"><a href="http://www...com/.../logout.php">Logout</a></div> <div class="footervote"><a href="http://www...com/.../footervote.php">Vote</a></div> </div>'; } On editorlist.php: $sqlStr = "SELECT l.loginid, l.username, l.created, DATEDIFF(NOW(), l.created) AS days, COALESCE(s.total, 0) AS countSubmissions, COALESCE(c.total, 0) AS countComments, COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore, DATEDIFF(NOW(), l.created) + COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore2 FROM login l LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM submission GROUP BY loginid ) s ON l.loginid = s.loginid LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM comment GROUP BY loginid ) c ON l.loginid = c.loginid GROUP BY l.loginid ORDER BY totalScore2 DESC LIMIT 10"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec1edit\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1edit1"><a href="http://www...com/.../members/index.php?profile='.$row["username"].'">'.stripslashes($row["username"]).'</a></td>'; echo '<td class="sitename1edit2">'.($row["countSubmissions"]).'</td>'; echo '<td class="sitename1edit2">'.($row["countComments"]).'</td>'; echo '<td class="sitename1edit2">'.($row["days"]).'</td>'; echo '<td class="sitename1edit2">'.($row["totalScore2"]).'</td>'; echo '</tr>'; } echo "</table>";

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  • What happens to a class in PHP once its been instantiated?

    - by Caylem
    Hi I'm just playing around with some PHP and was wondering what happens when an object from a class is created within another PHP script? I assume once its created and been processed their is no way of then going back and 'playing' around with it from another script? The idea is i'm trying to create a kind of deck of cards using a card class, each card has specific data that is added to each individual object to make it unique, suit, value etc. Once its created i need to be able to go back to specific cards to use them. In java i'd have an arraylist of card objects, i'm not sure how to approach the same area in PHP. Thanks.

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  • Pass Session data to a Class Library without using a bunch of constructors?

    - by sah302
    Hi all, I've got my application here where literally every object has a lastUpdatedBy property. The information I put into here is the person's username, which is retrieved from the session("username") variable. How can I pass this data to my DAL in the class library? At first I was just passing in the value into each method, but this is ridiculous I thought, there should be no reason to do that every time a method is called. Then I thought well if I just put it in a constructor for each of the DAL related classes, that will make it even easier. However, even still on any given page, I've got a plethora of New() declarations, for which every single line I need to pass in the session username casted as a string. Is there an even still more efficient way of doing this so that I could only declare this in one place, and everything will know what it is and I can pass it to classes in a class library?

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  • In java can i have more than one class/object in a file?

    - by David
    So the way i've been told to do things is you have your file and the file name is Classname.java and then the code is something like this: class ClassName { SOME METHODS main {} } and then thats all. I'd like to have two objects defined and used within the same .java file. (i don't want to have to put the other class in a difernt file just because i'd like to send this to someone and i want to avoid hasstle of atatching multiple files to an email [the lazy do make good programers though if you think about it]) is it possible to do this? do i have to do anything special and if so what? what are some mistakes i'm likely to make or that you have made in the past when doing this?

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