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  • JSON image viewer not working in firefox

    - by jarga
    I have tried to find out why JSON is not working in Firefox all over this forum and the internet. It works on tablets, ie, safari. It works on my desktop in firefox. It only does not work after uploading I've tried a few things (commented out), such as mimeType with no solution. I have tried using the $.ajax with no better luck. Firefox had no javascript errors. I'm using jQuery 1.7. Console.log is printing out the data. $(document).ready(function(){ jQuery.support.cors = true; //$.ajaxSetup({ mimeType: "application/json" }); /*$.ajaxSetup({ scriptCharset: "utf-8" , contentType: "application/json; charset=utf-8"}); */ // loading pictures $.getJSON("intro.json?format=json", function(data){ var links = ''; var imageload = ''; var title = ''; console.log(data) $.each(data, function(key, item){ links += ' <a href=' + item.image + '>' + key + '</a>'; imageload += '<img src="' + item.image + ' " />'; title += item.alt; }); $('.introCon').html(imageload); $('.introCon img').hide(); $('.introCon img:last').fadeIn(500); $('.introCon img').fadeIn(1000); rotatePics(2); }); }); function rotatePics(currentPhoto) { var numberOfPhotos = $('.introCon img').length; currentPhoto = currentPhoto % numberOfPhotos; $('.introCon img').eq(currentPhoto).fadeOut( function() { // re-order the z-index $('.introCon img').each(function(i) { $(this).css( 'zIndex', ((numberOfPhotos - i) + currentPhoto) % numberOfPhotos ); }); $(this).show(); setTimeout(function() {rotatePics(++currentPhoto);}, 3000); }); } Here is the simple JSON from a separate file. { "1" : { "image" : "portfolio/chrpic.png", "alt" : "Blah.", "detail": "Quartz"}, "2" : { "image" : "portfolio/mysspic.png", "alt" : "Landing page.", "detail": "Container"}, "3" : { "image" : "portfolio/decode-pic3.png", "alt" : "Decode this.", "detail": "Landing page 2"}, "4" : { "image" : "portfolio/simple-think-pic.png", "alt" : "Simple Think", "detail": "simpilify your life"} }

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  • Serialize JavaScript's navigator object

    - by kappa
    Hi, I'm creating a page to help diagnose the problem our users are experiencing with our web pages (you know, asking a user "What browser are you using?" usually leads to "Internet"). This page already submits to me all the HTTP headers and now I'm trying to have JavaScript give some more informations, so I thought it would be great to have the user's navigator JavaScript object and I started looking how to serialize it so I can submit it through a form. The problem is I'm not able to serialize the navigator object using any JSON library I know of, everyone returns an empty object (?!), so I decided to write an ad-hoc serializer. You can find the code here: <!DOCTYPE html> <html> <head> <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.5.0/jquery.min.js" type="text/javascript"></script> <script type="text/javascript"> function serialize (object) { var type = typeof object; if (object === null) { return '"nullValue"'; } if (type == 'string' || type === 'number' || type === 'boolean') { return '"' + object + '"'; } else if (type === 'function') { return '"functionValue"'; } else if (type === 'object') { var output = '{'; for (var item in object) { if (item !== 'enabledPlugin') { output += '"' + item + '":' + serialize(object[item]) + ','; } } return output.replace(/\,$/, '') + '}'; } else if (type === 'undefined') { return '"undefinedError"'; } else { return '"unknownTypeError"'; } }; $(document).ready(function () { $('#navigator').text(serialize(navigator)); }); </script> <style type="text/css"> #navigator { font-family: monospaced; } </style> <title>Serialize</title> </head> <body> <h1>Serialize</h1> <p id="navigator"></p> </body> </html> This code seems to work perfectly in Firefox, Opera, Chrome and Safari but (obviously) doesn't work in Internet Explorer (at least version 8.0), it complains that "Property or method not supported by the object" at line for (var item in object) {. Do you have any hint on how to fix the code or how to reach the goal (serialize the navigator object) by other means?

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  • JQuery Validation - Wrap offending field in a div.

    - by Samuurai
    Hi, It's my first time using StackOverFlow and first time trying to set up jQuery Validation. It's displaying <label> tags with the error messages as default behaviour, however the way my CSS is set up I need a div to wrap around the offending element and a message display in <p> tags. Without errors, my html looks like this: <div class="grid-26 append-2"> <p class="noMarginBottom"> <label>First Name</label> <div class="jNiceInputWrapper"> <div class="jNiceInputInner"> <input type="text" class="text jNiceInput" name="name"/> </div> </div> </p> <span class="clear"/> </div> And with Errors, it needs to look like this - Note the div with class "error" and the <p> tag. <div class="grid-26 append-2"> <div class="error"> <p>Please write your real name</p> <p class="noMarginBottom"> <label>First Name</label> <div class="jNiceInputWrapper"> <div class="jNiceInputInner"> <input type="text" class="text jNiceInput" name="name"/> </div> </div> </p> <span class="clear"/> </div> </div> My Validation code is very basic. $(document).ready(function(){ $("#contact_form").validate({ rules:{ name: { required: true } } }); }); This is my first venture into jQuery and form validation, so I'll be the first to say "I'm lost!" any help would be greatly appreciated. Thanks.

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  • Passing variables, creating instances, self, The mechanics and usage of classes: need explenation

    - by Baf
    I've been sitting over this the whole day and Im a little tired already so please excuse me being brief. Im new to python. I just rewrrote a working program, into a bunch of functions in a class and everzthings messed up. I dont know if its me but Im very surprised i couldn t find a beginners tutorial on how to handle classes on the web so I have a few questions. First of all, in the init section of the class i have declared a bunch of variables with self.variable=something. Is it correct that i should be able to access/modify these variables in every function of the class by using self.variable in that function? In other words by declaring self.variable i have made these variables, global variables in the scope of the class right? If not how do i handle self. ? Secondly how do i correctly pass arguments to the class? some example code would be cool. thirdly how do i call a function of the class outside of the class scope? some example code would be cool. fouthly how do I create an Instance of the class INITIALCLASS in another class OTHERCLASS, passing variables from OTHERCLASS to INITIALCLASS? some example code would be cool. I Want to call a function from OTHERCLASS with arguments from INITIALCLASS. What Ive done so far is. class OTHERCLASS(): def __init__(self,variable1,variable2,variable3): self.variable1=variable1 self.variable2=variable2 self.variable3=variable3 def someotherfunction(self): something=somecode(using self.variable3) self.variable2.append(something) print self.variable2 def somemorefunctions(self): self.variable2.append(variable1) class INITIALCLASS(): def __init__(self): self.variable1=value1 self.variable2=[] self.variable3='' self.DoIt=OTHERCLASS(variable1,variable2,variable3) def somefunction(self): variable3=Somecode #tried this self.DoIt.someotherfunctions() #and this DoIt.someotherfunctions() I clearly havent understood how to pass variables to classes or how to handle self, when to use it and when not, I probably also havent understood how to properly create an isntance of a class. In general i havent udnerstood the mechanics of classes So please help me and explain it to me like i have no Idea( which i dont it seems). Or point me to a thorough video, or readable tutorial. All i find on the web is super simple examples, that didnt help me much. Or just very short definitions of classes and class methods instances etc. I can send you my original code if you guys want, but its quite long. Thanks for the Help Much appreciated!

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  • reverse a linked list?

    - by sil3nt
    Hi there, Im trying to reverse the order of the following linked list, I've done so, But the reversed list does not seem to print out. Where have I gone wrong? //reverse the linked list #include <iostream> using namespace std; struct node{ int number; node *next; }; node *A; void addNode(node *&listpointer, int num){ node *temp; temp = new node; temp->number = num; temp->next = listpointer; listpointer = temp; } void reverseNode(node *&listpointer){ node *temp,*current; current = listpointer; temp = new node; while (true){ if (current == NULL){ temp = NULL; break; } temp->number = current->number; current = current->next; temp = temp->next; } listpointer = temp; } int main(){ A = NULL; addNode(A,1); addNode(A,2); addNode(A,3); while (true){ if (A == NULL){break;} cout<< A->number << endl; A = A->next; } cout<< "****" << endl; reverseNode(A); while (true){ if (A == NULL){break;} cout<< A->number << endl; A = A->next; } cout<< "****"<< endl; return 0; }

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  • sendmail.php needs some php work

    - by Chris
    I am having the hardest time to get a simple sendmail.php to work. My form html is <form action=sendmail.php id=contact-form method=post> <p> <label for=cf_name>Name *</label> <input id=cf_name name=cf_name placeholder='Enter your name...' required=required title=Name type=text /> </p> <p> <label for=cf_email>Email *</label> <input id=cf_email name=cf_email placeholder='Email address...' required=required title='Email address' type=email /> </p> <p> <label for=cf_subject>Subject *</label> <input id=cf_subject name=cf_subject placeholder='Specify subject...' required=required title=Subject type=text /> </p> <p> <label for=cf_message>Message *</label> <textarea id=cf_message name=cf_message placeholder='Message text...' required=required rows=10 title='Message text'></textarea> </p> <p> <input type=submit value='Send message'/> </p> </form> And my mailer script is: <? $cf_email = $_POST['cf_email'] ; $cf_message = $_POST['cf_message'] ; $cf_subject = $_POST['cf_subject'] ; $cf_name = $_POST['cf_name'] ; mail( "[email protected]", $cf_subject, $cf_message, $cf_name, $cf_email ); print "Congratulations your email has been sent"; ?> Just want an email to to go to my email. When it appears in the inbox, the subject they typed is the one that I will see as the subject in my inbox. The from will be their name. The email it came from will be their email And the message inside will be the message they wrote in the form. Please help.

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  • Help with basic php and xml needed

    - by Matt
    Hi, I'm really new to xml, with this being my first dip into it. I'm trying to add some text to an image using php and xml. I keep getting the following error: Parse error: syntax error, unexpected '}' in /home/a8744502/public_html/userbar.php on line 18 Below is my code. <?php header ("Content-type: image/jpeg"); $doc = new DOMDocument(); $doc->load( "http://phogue.net/feed/". LIBXML_DTDLOAD ); $procon = $doc->getElementsByTagName( "procon" ); $packages = $procon->getElementsByTagName( "package" ); $value = 0; foreach($packages as $package) { $downloadsA = $package->getElementsByTagName( "downloads" ); $downloads = $downloadsA->item(0)->nodeValue; $value = $downloads + $value } $font = "visitor1.tff"; $font = 4; $im = ImageCreateFromjpeg("procon_plugindeveloper.jpg"); $x = 360; $y = 0; $background_color = imagecolorallocate ($im, 255, 255, 255); $text_color = imagecolorallocate ($im, 255, 255, 255); imagestring ($im, $font, $x, $y, $value, $text_color); imagejpeg ($im); ?> The xml file is of the form <procon> -<packages> --<package> ---<downloads> ---</doanloads> --</package> --<package> ---<downloads> ---</doanloads> --</package> --<package> ---<downloads> ---</doanloads> --</package> -</packages> </procon> The idea is that it should print out the sum of all the downloads tags that are contained in . Any help is appreciated :-)

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  • Multiple column subselect in mysql 5 (5.1.42)

    - by rubber boots
    This one seems to be a simple problem, but I can't make it work in a single select or nested select. Retrieve the authors and (if any) advisers of a paper (article) into one row. I order to explain the problem, here are the two data tables (pseudo) papers (id, title, c_year) persons (id, firstname, lastname) plus a link table w/one extra attribute (pseudo): paper_person_roles( paper_id person_id act_role ENUM ('AUTHOR', 'ADVISER') ) This is basically a list of written papers (table: papers) and a list of staff and/or students (table: persons) An article my have (1,N) authors. An article may have (0,N) advisers. A person can be in 'AUTHOR' or 'ADVISER' role (but not at the same time). The application eventually puts out table rows containing the following entries: TH: || Paper_ID | Author(s) | Title | Adviser(s) | TD: || 21334 |John Doe, Jeff Tucker|Why the moon looks yellow|Brown, Rayleigh| ... My first approach was like: select/extract a full list of articles into the application, eg.SELECT q.id, q.title FROM papers AS q ORDER BY q.c_year and save the results of the query into an array (in the application). After this step, loop over the array of the returned information and retrieve authors and advisers (if any), via prepared statement (? is the paper's id) from the link table like:APPLICATION_LOOP(paper_ids in array) SELECT p.lastname, p.firstname, r.act_role FROM persons AS p, paper_person_roles AS r WHERE p.id=r.person_id AND r.paper_id = ? # The application does further processing from here (pseudo): foreach record from resulting records if record.act_role eq 'AUTHOR' then join to author_column if record.act_role eq 'ADVISER' then join to avdiser_column end print id, author_column, title, adviser_column APPLICATION_LOOP This works so far and gives the desired output. Would it make sense to put the computation back into the DB? I'm not very proficient in nontrivial SQL and can't find a solution with a single (combined or nested) select call. I tried sth. like SELECT q.title (CONCAT_WS(' ', (SELECT p.firstname, p.lastname AS aunames FROM persons AS p, paper_person_roles AS r WHERE q.id=r.paper_id AND r.act_role='AUTHOR') ) ) AS aulist FROM papers AS q, persons AS p, paper_person_roles AS r in several variations, but no luck ... Maybe there is some chance? Thanks in advance r.b.

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  • jQuery - Save to SQL via PHP

    - by Kenny Bones
    This is probably easy for you guys, but I can't understand it. I want to save the filename of an image to it's own row in the SQL base. Basically, I log on to the site where I have my own userID. And each user has its own column for background images. And the user can choose his own image if he wants to. So basically, when the user clicks on the image he wants, a jquery click event occurs and an ajax call is made to a php file which is supposed to take care of the actual update. The row for each user always exist so there's only an update of the data that's necessary. First, I collect the filename of the css property 'background-image' and split it so I get only the filename. I then store that filename in a variable I call 'filename' which is then passed on to this jQuery snippet: $.ajax({ url: 'save_to_db.php', data: filename, dataType:'Text', type: 'POST', success: function(data) { // Just for testing purposes. alert('Background changed to: ' + data); } }); And this is the php: <?php require("dbconnect.php") ?> <?php $uploadstring = ($_POST['filename']); mysql_query("UPDATE brukere SET brukerBakgrunn = $uploadstring WHERE brukerID=" .$_SESSION['id'] .""; mysql_close(); ?> Basically, each user has their own ID and this is called 'brukerID' The table everything is in is called 'brukere' and the column I'm supposed to update is the one called 'brukerBakgrunn' When I just run the javascript snippet, I get this message box in return where it says: Background changed to: Parse error: syntax error, unexpected ';' in /var/www/clients/client2/web8/web/save_to_db.php on line 8 I actualle get this messagebox twice, not sure why. Line 8 in 'save_to_db.php' is this one: mysql_query("UPDATE brukere SET brukerBakgrunn = $uploadstring WHERE brukerID=" .$_SESSION['id'] .""; Not sure if you need to see db_connect.php as well. I can add that later if you need to see it. So what am I missing here?

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  • hibernate annotation- extending base class - values are not being set - strange error

    - by gt_ebuddy
    I was following Hibernate: Use a Base Class to Map Common Fields and openjpa inheritance tutorial to put common columns like ID, lastModifiedDate etc in base table. My annotated mappings are as follow : BaseTable : @MappedSuperclass public abstract class BaseTable { @Id @GeneratedValue @Column(name = "id") private int id; @Column(name = "lastmodifieddate") private Date lastModifiedDate; ... Person table - @Entity @Table(name = "Person ") public class Person extends BaseTable implements Serializable{ ... Create statement generated : create table Person (id integer not null auto_increment, lastmodifieddate datetime, name varchar(255), primary key (id)) ; After I save a Person object to db, Person p = new Person(); p.setName("Test"); p.setLastModifiedDate(new Date()); .. getSession().save(p); I am setting the date field but, it is saving the record with generated ID and LastModifiedDate = null, and Name="Test". Insert Statement : insert into Person (lastmodifieddate, name) values (?, ?) binding parameter [1] as [TIMESTAMP] - <null> binding parameter [2] as [VARCHAR] - Test Read by ID query : When I do hibernate query (get By ID) as below, It reads person by given ID. Criteria c = getSession().createCriteria(Person.class); c.add(Restrictions.eq("id", id)); Person person= c.list().get(0); //person has generated ID, LastModifiedDate is null select query select person0_.id as id8_, person0_.lastmodifieddate as lastmodi8_, person0_.name as person8_ from Person person0_ - Found [1] as column [id8_] - Found [null] as column [lastmodi8_] - Found [Test] as column [person8_] ReadAll query : //read all Query query = getSession().createQuery("from " + Person.class.getName()); List allPersons=query.list(); Corresponding SQL for read all select query select person0_.id as id8_, person0_.lastmodifieddate as lastmodi8_, person0_.name as person8_ from Person person0_ - Found [1] as column [id8_] - Found [null] as column [lastmodi8_] - Found [Test] as column [person8_] - Found [2] as column [id8_] - Found [null] as column [lastmodi8_] - Found [Test2] as column [person8_] But when I print out the list in console, its being more weird. it is selecting List of Person object with ID fields = all 0 (why all 0 ?) LastModifiedDate = null Name fields have valid values I don't know whats wrong here. Could you please look at it? FYI, My Hibernate-core version : 4.1.2, MySQL Connector version : 5.1.9 . In summary, There are two issues here Why I am getting All ID Fields =0 when using read all? Why the LastModifiedDate is not being inserted?

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  • Generate navigation from a multi-dimensional array

    - by rg88
    The question: How do I generate navigation, allowing for applying different classes to different sub-items, from a multi-dimensional array? Here is how I was doing it before I had any need for multi-level navigation: Home Pics About and was generated by calling nav(): function nav(){ $links = array( "Home" => "home.php", "Pics" => "pics.php", "About" => "about.php" ); $base = basename($_SERVER['PHP_SELF']); foreach($nav as $k => $v){ echo buildLinks($k, $v, $base); } } Here is buildLinks(): function buildLinks($name, $page, $selected){ if($selected == $page){ $theLink = "<li class=\"selected\"><a href=\"$page\">$name</a></li>\n"; } else { $thelink = "<li><a href=\"$page\">$name</a></li>\n"; } return $thelink; } My question, again: how would I achieve the following nav (and notice that the visible sub navigation elements are only present when on that specific page): Home something1 something2 Pics About and... Home Pics people places About What I've tried From looking at it it would seem that some iterator in the SPL would be a good fit for this but I'm not sure how to approach this. I have played around with RecursiveIteratorIterator but I'm not sure how to apply a different style to only the sub menu items and also how to only show these items if you are on the correct page. I built this array to test with but don't know how to work with the submenu1 items individually: $nav = array( array( "Home" => "home.php", "submenu1" => array( "something1"=>"something1.php", "something2" => "something2.php") ), array("Pics" => "pics.php"), array("About" => "about.php") ); The following will print out the lot in order but how do I apply, say a class name to the submenu1 items or only show them when the person is on, say, the "Home" page? $iterator = new RecursiveIteratorIterator(new RecursiveArrayIterator($nav)); foreach($iterator as $key=>$value) { echo $key.' -- '.$value.'<br />'; }

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  • Delegates does not work properly

    - by Warrior
    I am new to iPhone development. I am converting the date to the desired format and set it to the delegate and get its value in the another view. The session restarts when I tried to get the value from delegate. If I set the original date and not the formatted date in the set delegate, then i able to get the value in the another view. If I also give any static string value, then also I am able to the static string value back. Only the formatted date which is string is set then the session restarts. If i print and check the value of the formatted date it prints the correct formatted date only.Please help me out.Here is my code for date conversion NSString *dateval=[[stories objectAtIndex: storyIndex] objectForKey:@"date"]; NSDateFormatter *inputFormatter = [[NSDateFormatter alloc] init]; [inputFormatter setDateFormat:@"EEE, MMM dd, yyyy"]; NSDate *inputDate = [inputFormatter dateFromString:dateval]; NSDateFormatter *outputFormatter = [[NSDateFormatter alloc] init]; [outputFormatter setDateFormat:@"MMMM dd"]; NSString *outputDate = [outputFormatter stringFromDate:inputDate]; AppDelegate *delegate=(AppDelegate *)[[UIApplication sharedApplication]delegate]; [delegate setCurrentDates:outputDate]; EDIT: This is displayed in console inside view did load [Session started at 2010-04-21 19:12:53 +0530.] GNU gdb 6.3.50-20050815 (Apple version gdb-967) (Tue Jul 14 02:11:58 UTC 2009) Copyright 2004 Free Software Foundation, Inc. GDB is free software, covered by the GNU General Public License, and you are welcome to change it and/or distribute copies of it under certain conditions. Type "show copying" to see the conditions. There is absolutely no warranty for GDB. Type "show warranty" for details. This GDB was configured as "i386-apple-darwin".sharedlibrary apply-load-rules all Attaching to process 4216. (gdb) In another view - (void)viewDidLoad { NSLog(@"inside view did load"); AppDelegate *delegate=(AppDelegate *)[[UIApplication sharedApplication]delegate]; NSString *titleValue=[delegate getCurrentDates]; self.navigationItem.title =titleValue ; } The get does not work properly.It works fine if i give any static string or the "dateval". Thanks.

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  • How to display image from server (newest-oldest) to a new php page?

    - by Jben Kaye
    i have a form that create images and save it on a folder in the server. What i need to do is to display ALL created images to another page, the newest on the top and so that the oldest is at the bottom. i have a form called formdisplay.php but it's just displaying a broken image and not newest to oldest. hope you can help me with this. really need to get this working. thanks in advance for your help. i have read the posts but none of those worked for me. Pull dedicated images from folder - show image + filename (strip part of filename + file-extension) How can I display latest uploaded image first? (PHP+CSS) getting images from the server and display them Displaying images from folder in php display image from server embedding php in html formcreatesave.php imagecopymerge($im, $img2, 10, 350, 0, 0, imagesx($img2), imagesy($img2), 100); $date_created = date("YmdHis");//get date created $img_name = "-img_entry.jpg"; //the file name of the generated image $img_newname = $date_created . $img_name; //datecreated+name $img_dir =dirname($_SERVER['SCRIPT_FILENAME']) ."/". $img_newname; //the location to save imagejpeg($im, $img_dir , 80); //function to save the image with the name and quality imagedestroy($im); formdisplay.php $dir = '/home3/birdieon/public_html/Amadeus/uploader/uploader'; $base_url = 'http://birdieonawire.com/Amadeus/uploader/uploader/20131027024705-img_entry.jpg'; $newest_mtime = 0; $show_file = 'BROKEN'; if ($handle = opendir($dir)) { while (false !== ($file = readdir($handle))) { if (($file != '.') && ($file != '..')) { $mtime = filemtime("$dir/$file"); if ($mtime > $newest_mtime) { $newest_mtime = $mtime; $show_file = "$base_url/$file"; } } } } print '<img src="' .$show_file. '" alt="Image Title Here">'; please feel free to edit my code. thanks :)

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  • pagerAnchorBuilder - trying to add classes

    - by Bert Murphy
    I'm using Cycle2 to build a carousel gallery and I've run into a little problem regarding styling the pager buttons. What I've gathered is that Cycle2 creates its own pager span tags for each slide which is a bummer becaus I've already styled my the sub-nav markup. This should be a minor issue as long as I can assign individual classes to the spans and change my css accordingly. However, I can't get this to work. TLDR: I was hoping that I could use pagerAnchorBuilder to create individual classes for each span. I can't. Help. The original markup (pre Cycle2) looks like the following: <div id ="sub-nav" class="sub-nav"> <ul> <li><a id="available" class="available" href="#"></a></li> <li><a id="reliable" class="reliable" href="#"></a></li> <li><a id="use" class="use" href="#"></a></li> <li><a id="reports" class="reports" href="#"></a></li> <li class="last"><a id="software" class="software" href="#"></a></li> </ul> </div> With Cycle2 it looks like this (note the addition of the span tags) <div id ="sub-nav" class="sub-nav"> <ul> <li><a id="available" class="available" href="#"></a></li> <li><a id="reliable" class="reliable" href="#"></a></li> <li><a id="use" class="use" href="#"></a></li> <li><a id="reports" class="reports" href="#"></a></li> <li class="last"><a id="software" class="software" href="#"></a></li> </ul> <span class="cycle-pager-active">•</span><span>•</span><span>•</span><span>•</span><span>•</span></nav> </div> Cycle2 $('#sliding-gallery ul').cycle({ fx: 'carousel', carouselVisible: 1, speed: 'fast', timeout: 10000, slides: '>li', next: '.next', prev: '.prev', pager: '.sub-nav', pagerAnchorBuilder: function(idx, slide) { return '.sub-nav span:eq(' + idx + ')'; } });

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  • Structures not working correctly?

    - by booby
    Fraction AddFractions(const Fraction& frac1, const Fraction& frac2) { Fraction frac3; if (frac1.denom == frac2.denom) { frac3.num = frac1.num + frac2.num; frac3.denom = frac1.denom; } else { frac3.denom = (frac1.denom * frac2.denom); frac3.num = (frac1.num * frac2.denom) + (frac2.num * frac1.denom); } return frac3; } This is my prototype and there is a structure defined as Fraction with int num and int denom when I call the function it just gives me back garbage? I don't know what's wrong with it. Please help. =( cout << "Please enter two Fractions" << endl; cout << endl; GetFraction(frac1); cout << "Your fisrt fraction is: "; PrintFraction(frac1); cout << endl; cout << endl; GetFraction(frac2); cout << "Your second fraction is: "; PrintFraction(frac2); cout << endl; do { choice1 = MathMenu(); if (choice1 == ErrorOpt) { cout << "There was an error with what you have entered" << endl; } else if(choice1 != QuitOpt) { // do the math options switch (choice1) { case AddOpt: AddFractions(frac1, frac2); break; case SubtractOpt: SubtractFractions(frac1, frac2); break; case MultiplyOpt: MultiplyFractions(frac1, frac2); break; case DivideOpt: DivideFractions(frac1, frac2); break; } //print the results PrintFraction(frac1); PrintMathOption(choice1); PrintFraction(frac2); cout << " = "; Standardize(frac3); Reduce(frac3); PrintFraction(frac3); cout << endl; Pause();

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  • jQuery question from a person who can't javascript

    - by Evilalan
    So I'm trying to adapt this Dropdown menu on Joomla the styles work great as expected so I'll post the javascript includes on the head of my website: <script type='text/javascript' src='js/jquery.js'></script> <script type='text/javascript' src='js/dropdown.js'></script> <script type='text/javascript'> $(function() { $('.menu').droppy(); }); </script> <script type='text/javascript'> $(function() { $('.menu').droppy({speed: 100}); }); </script> ok I don't know why its is not working I'll post the dropdown.js should I post the jQuery too? it's really big! $.fn.droppy = function(options) { options = $.extend({speed: 250}, options || {}); this.each(function() { var root = this, zIndex = 1000; function getSubnav(ele) { if (ele.nodeName.toLowerCase() == 'li') { var subnav = $('> ul', ele); return subnav.length ? subnav[0] : null; } else { return ele; } } function getActuator(ele) { if (ele.nodeName.toLowerCase() == 'ul') { return $(ele).parents('li')[0]; } else { return ele; } } function hide() { var subnav = getSubnav(this); if (!subnav) return; $.data(subnav, 'cancelHide', false); setTimeout(function() { if (!$.data(subnav, 'cancelHide')) { $(subnav).slideUp(options.speed); } }, 500); } function show() { var subnav = getSubnav(this); if (!subnav) return; $.data(subnav, 'cancelHide', true); $(subnav).css({zIndex: zIndex++}).slideDown(options.speed); if (this.nodeName.toLowerCase() == 'ul') { var li = getActuator(this); $(li).addClass('hover'); $('> a', li).addClass('hover'); } } $('ul, li', this).hover(show, hide); $('li', this).hover( function() { $(this).addClass('hover'); $('> a', this).addClass('hover'); }, function() { $(this).removeClass('hover'); $('> a', this).removeClass('hover'); } ); }); }; My question here is: Why is it not working! I know that this is really complex (I don't anything about JavaScript) but if you help me I'll post a tutorial and edited files that will help a lot of people! By the way I've download jQuery from the original site so I don't think that this can be the problem! Thanks in advance!

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  • jQuery UI problem: why do the elements go flying around the screen?

    - by George Edison
    Yes, I know the title sounds a little suspicious. I will try to explain this the best I can... The code below is supposed to have the blue div slide down beside the red div. The first time you hit the Show the div button, it works. Also, the Hide the div works. Then when I click to show the div again, it appears to the right of where it is supposed to be! Why is this?!? Note: You can find a live example of the code here <html> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <title>Demo</title> <style type='text/css'> #red { background-color: red; width: 200px; height: 150px; position: absolute; } #blue { background-color: blue; width: 150px; height: 200px; position: absolute; display: none; } #tester_1 { top: 300px; left: 300px; position: absolute; } #tester_2 { top: 350px; left: 300px; position: absolute; } </style> </head> <script type="text/javascript" src="jquery.js"></script> <script type='text/javascript'> function Show() { $('#blue').position({ of: $('#red'), my: 'left top', at: 'right top'}).slideDown(); } function Hide() { $('#blue').hide(); } </script> <body> <div id='red'></div> <div id='blue'></div> <button id='tester_1' onclick='Show()'>Show the <kbd>div</kbd></button> <button id='tester_2' onclick='Hide()'>Hide the <kbd>div</kbd></button> </body> </html>

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  • Returning and printing string array index in C

    - by user1781966
    I've got a function that searches through a list of names and I'm trying to get the search function to return the index of the array back to the main function and print out the starting location of the name found. Everything I've tried up to this point either crashes the program or results in strange output. Here is my search function: #include<stdio.h> #include<conio.h> #include<string.h> #define MAX_NAMELENGTH 10 #define MAX_NAMES 5 void initialize(char names[MAX_NAMES][MAX_NAMELENGTH], int Number_entrys, int i); int search(char names[MAX_NAMES][MAX_NAMELENGTH], int Number_entrys); int main() { char names[MAX_NAMES][MAX_NAMELENGTH]; int i, Number_entrys,search_result,x; printf("How many names would you like to enter to the list?\n"); scanf("%d",&Number_entrys); initialize(names,Number_entrys,i); search_result= search(names,Number_entrys); if (search_result==-1){ printf("Found no names.\n"); }else { printf("%s",search_result); } getch(); return 0; } void initialize(char names[MAX_NAMES][MAX_NAMELENGTH],int Number_entrys,int i) { if(Number_entrys>MAX_NAMES){ printf("Please choose a smaller entry\n"); }else{ for (i=0; i<Number_entrys;i++){ scanf("%s",names[i]); } } } int search(char names[MAX_NAMES][MAX_NAMELENGTH],int Number_entrys) { int x; char new_name[MAX_NAMELENGTH]; printf("Now enter a name in which you would like to search the list for\n"); scanf("%s",new_name); for(x = 0; x < Number_entrys; x++) { if ( strcmp( new_name, names[x] ) == 0 ) { return x; } } return -1; } Like I mentioned before I have tried a lot of different ways to try and fix this issue, but I cant seem to get them to work. Printing X like what I have above is just the last thing I tried, and therefor know that it doesn't work. Any suggestions on the simplest way to do this?

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  • arrayListOutOfBoundsException... Please Help?

    - by Jacob
    This is my class Debugger. Can anyone try and run it and see whens wrong? Ive spent hours on it already. :( public class Debugger { private String codeToDebug = ""; public Debugger(String code) { codeToDebug = code; } /** * This method itterates over a css file and adds all the properties to an arraylist */ public void searchDuplicates() { boolean isInside = false; ArrayList<String> methodStorage = new ArrayList(); int stored = 0; String[] codeArray = codeToDebug.split(""); try { int i = 0; while(i<codeArray.length) { if(codeArray[i].equals("}")) { isInside = false; } if(isInside && !codeArray[i].equals(" ")) { boolean methodFound = false; String method = ""; int c = i; while(!methodFound) { method += codeArray[c]; if(codeArray[c+1].equals(":")) { methodFound = true; } else { c++; } } methodStorage.add(stored, method); System.out.println(methodStorage.get(stored)); stored++; boolean stillInside = true; int skip = i; while(stillInside) { if(codeArray[skip].equals(";")) { stillInside = false; } else { skip++; } } i = skip; } if(codeArray[i].equals("{")) { isInside = true; } i++; } } catch(ArrayIndexOutOfBoundsException ar) { System.out.println("------- array out of bounds exception -------"); } } /** * Takes in String and outputs the number of characters it contains * @param input * @return Number of characters */ public static int countString(String input) { String[] words = input.split(""); int counter = -1; for(int i = 0; i<words.length; i++){ counter++; } return counter; } public static void main(String[] args) { Debugger h = new Debugger("body {margin:;\n}"); h.searchDuplicates(); } }

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  • PHP getting Twitter API JSON file contents without OAuth (Almost have it)

    - by DexCurl
    Hey guys, I have this script working fine with OAuth, but I accidentally nuked my 350 API hits with a stupid while statement :( I'm trying to get data from the Twitter API without OAuth, I can't figure it out (still pretty new), heres what I have <html> <body> <center> <hr /> <br /> <table border="1"> <tr><td>ScreenName</td><td>Followed back?</td></tr> <?php //twitter oauth deets $consumerKey = 'x'; $consumerSecret = 'x'; $oAuthToken = 'x'; $oAuthSecret = 'x'; // Create Twitter API objsect require_once("twitteroauth.php"); $oauth = new TwitterOAuth($consumerKey, $consumerSecret, $oAuthToken, $oAuthSecret); //get home timeline tweets and it is stored as an array $youfollow = $oauth->get('http://api.twitter.com/1/friends/ids.json?screen_name=lccountdown'); $i = 0; //start loop to print our results cutely in a table while ($i <= 20){ $youfollowid = $youfollow[$i]; $resolve = "http://api.twitter.com/1/friendships/exists.json?user_a=".$youfollow[$i]."&user_b=jwhelton"; $followbacktest = $oauth->get($resolve); //$homedate= $hometimeline[$i]->created_at; //$homescreenname = $hometimeline[$i]->user->screen_name; echo "<tr><td>".$youfollowid."</td><td>".$followbacktest."</td></tr>"; $i++; } ?> </table> </center> </body> </html> Neither of the two Twitter functions require authentication, so how can I get the same results? Thanks guys, Dex

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  • Newbie jQuery question: Need slideshow to rotate automatically, not just when clicking navigation.

    - by Justin
    Hi everyone, This is my first post, so please forgive me if this question has been asked a million times. I'm a self professed jQuery hack and I need a little guidance on taking this script I found and adapting it to my needs. Anyway, what I'm making is an image slide show with navigation. The script I found does this, but does not automatically cycle through the images. I'm using jQuery 1.3.2 and would rather stick with that than using the newer library. I would also prefer to edit what is already here rather than start from scratch. Anywho, here's the html: <div id="myslide"> <div class="cover"> <div class="mystuff"> <img alt="&nbsp;" src="http://www.mfhc.com/wp/wp-content/uploads/2010/05/current_Denver-skyline.jpg" /> </div> <div class="mystuff"> <img alt="&nbsp;" src="http://www.mfhc.com/wp/wp-content/uploads/2010/05/pepsi_center-IS42RF-0D111C.jpg" /> </div> <div class="mystuff"> <img alt="&nbsp;" src="http://www.mfhc.com/wp/wp-content/uploads/2010/05/columbine-2689820469_D1104.jpg" /> </div> <div class="mystuff"> <img alt="&nbsp;" src="http://www.mfhc.com/wp/wp-content/uploads/2010/05/ist2_10460354-RedRocks.jpg" /> </div> </div> <!-- end of div cover --> </div> <!-- end of div myslide --> And here's the jQuery: <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script> <script type="text/JavaScript"> $(document).ready(function (){ $('#button a').click(function(){ var integer = $(this).attr('rel'); $('#myslide .cover').css({left:-820*(parseInt(integer)-1)}).hide().fadeIn(); /*----- Width of div #mystuff (here 820) ------ */ $('#button a').each(function(){ $(this).removeClass('active'); if($(this).hasClass('button'+integer)){ $(this).addClass('active')} }); }); }); </script> Here's where I got the script: http://www.webdeveloperjuice.com/2010/04/07/create-lightweight-jquery-fade-manual-slideshow/ Again, if this question is too basic for this site please let me know and possibly provide a reference link or two. Thanks a ton!

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  • C# ApplicationContext usage

    - by rd42
    Apologies if my terminology is off, I'm new to C#. I'm trying to use an ApplicationContext file to store mysql conn values, like dbname, username, password. The class with mysql conn string is "using" the namespace for the ApplicationContext, but when I print out the connection string, the values are making it. A friend said, "I'm not initializing it" but couldn't stay to expand on what "it" was. and the "Console.WriteLine("1");" in ApplicationContext.cs never shows up. Do I need to create an ApplicationContext object and the call Initialize() on that object? Thanks for any help. ApplicationContext.cs: namespace NewApplication.Context { class ApplicationContext { public static string serverName; public static string username; public static string password; public static void Initialize() { //need to read through config here try { Console.WriteLine("1"); XmlDocument xDoc = new XmlDocument(); xDoc.Load(".\\Settings.xml"); XmlNodeList serverNodeList = xDoc.GetElementsByTagName("DatabaseServer"); XmlNodeList usernameNodeList = xDoc.GetElementsByTagName("UserName"); XmlNodeList passwordNodeList = xDoc.GetElementsByTagName("Password"); } catch (Exception ex) { // MessageBox.Show(ex.ToString()); //TODO: Future write to log file username = "user"; password = "password"; serverName = "localhost"; } } } } MySQLManager.cs: note: dbname is the same as the username as you'll see in the code, I copied this from a friend who does that. using System; using System.Collections.Generic; using System.Linq; using System.Text; using MySql.Data; using MySql.Data.MySqlClient; using NewApplication.Context; namespace NewApplication.DAO { class MySQLManager { private static MySqlConnection conn; public static MySqlConnection getConnection() { if (conn == null || conn.State == System.Data.ConnectionState.Closed) { string connStr = "server=" + ApplicationContext.serverName + ";user=" + ApplicationContext.username + ";database=" + ApplicationContext.username + ";port=3306;password=" + ApplicationContext.password + ";"; conn = new MySqlConnection(connStr); try { Console.WriteLine("Connecting to MySQL... "); Console.WriteLine("Connection string: " + connStr + "\n"); conn.Open(); // Perform databse operations // conn.Close(); } catch (Exception ex) { Console.WriteLine(ex.ToString()); } } return conn; } } } and, thanks for still reading, this is the code that uses the two previous files: class LogDAO { MySqlConnection conn; public LogDAO() { conn = MySQLManager.getConnection(); } Thank you, rd42

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  • Creating a mySQL query using PHP form dropdowns - If user ignores dropdown, do not filter by that pa

    - by user303043
    Hello, I am creating a simple MySQL query that will be built from the user selecting options from 2 dropdowns. The issue I am having is that I would like each drop down to default that if they do not actually choose an option, do not filter by that dropdown parameter. So, if they come in, and simply hit submit without choosing from a dropdown they should see everything. If they come in and pick from only one of the dropdowns, the query will basically ignore filtering by the other dropdown. I tried making <OPTION VALUE='any'>Choose but my query didn't know what to do with the 'any' and just shows no results. Here is my code. Thank you very much for whatever help you can provide. FORM <form method="POST" action="<?php echo $_SERVER['REQUEST_URI']; ?>"> <select name="GameType"> <OPTION VALUE='any'>Choose Game Type <option value="Game1">Option 1</option> <option value="Game2">Option 2</option> <option value="Game3">Option 3</option> </select> <select name="Instructor"> <OPTION VALUE='any'>Choose Instructor <option VALUE="InstructorA">Instructor A</option> <option value="InstructorB">Instructor B</option> <option value="InstructorC">Instructor C</option> </select> <input type='submit' value='Search Videos'> </form> MYSQL <?PHP connection stuff $db_handle = mysql_connect($server, $user_name, $password); $db_found = mysql_select_db($database, $db_handle); if ($db_found) { $SQL = "SELECT * FROM Videos WHERE GameType=\"{$_POST['GameType']}\" AND Instructor=\"{$_POST['Instructor']}\""; $result = mysql_query($SQL); while ($db_field = mysql_fetch_assoc($result)) { echo $db_field['ShortDescription'] . ", "; echo $db_field['LongDescription'] . ", "; echo $db_field['GameType'] . ", "; echo $db_field['NumberOfPlayers'] . ", "; echo $db_field['Instructor'] . ", "; echo $db_field['Stakes'] . ", "; echo $db_field['UserPermissionLevel'] . ", "; echo $db_field['DateCreated'] . "<BR>"; } mysql_close($db_handle); } else { print "Database NOT Found "; mysql_close($db_handle); } ?>

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  • extracting multiple tags from xml using PHP

    - by user1479431
    Here is my address.xml <?xml version="1.0" ?> <!--Sample XML document --> <AddressBook> <Addressentry> <firstName>jack</firstName> <lastName>S</lastName> <Address>2899,Ray Road</Address> <Email>[email protected]</Email> </Addressentry> <Addressentry> <firstName>Sid</firstName> <lastName>K</lastName> <Address>238,Baseline Road,TX</Address> <Email>[email protected]</Email> <Email>[email protected]</Email> </Addressentry> <Addressentry> <firstName>Satya</firstName> <lastName>Yar</lastName> <Address>6,Rural Road,Tempe,AZ</Address> <Email>[email protected]</Email> <Email>[email protected]</Email> <Email>[email protected]</Email> </Addressentry> </AddressBook> I am trying to load all the entries using PHP code as below. Each addressentry can have one or more tags. Right now from the code below I am able to extract only one tag. My question is how do I extract all tags associated with particular Addressentry. that is I want to print all emails on the same line. <?php $theData = simplexml_load_File("address.xml"); foreach($theData->Addressentry as $theAddress) { $theFirstName = $theAddress->firstName; $theLastName = $theAddress->lastName; $theAdd = $theAddress->Address; echo "<p>".$theFirstName." ".$theLastName."<br/> ".$theAdd."<br/> ".$theAddress->Email."<br/> </p>"; unset($theFirstName); unset($theLastName); unset($theAdd); unset($theEmail); } ?> Any help would be appreciated

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  • Is valgrind crazy or is this is a genuine std map iterator memory leak?

    - by Alberto Toglia
    Well, I'm very new to Valgrind and memory leak profilers in general. And I must say it is a bit scary when you start using them cause you can't stop wondering how many leaks you might have left unsolved before! To the point, as I'm not an experienced in c++ programmer, I would like to check if this is certainly a memory leak or is it that Valgrind is doing a false positive? typedef std::vector<int> Vector; typedef std::vector<Vector> VectorVector; typedef std::map<std::string, Vector*> MapVector; typedef std::pair<std::string, Vector*> PairVector; typedef std::map<std::string, Vector*>::iterator IteratorVector; VectorVector vv; MapVector m1; MapVector m2; vv.push_back(Vector()); m1.insert(PairVector("one", &vv.back())); vv.push_back(Vector()); m2.insert(PairVector("two", &vv.back())); IteratorVector i = m1.find("one"); i->second->push_back(10); m2.insert(PairVector("one", i->second)); m2.clear(); m1.clear(); vv.clear(); Why is that? Shouldn't the clear command call the destructor of every object and every vector? Now after doing some tests I found different solutions to the leak: 1) Deleting the line i-second-push_back(10); 2) adding a delete i-second; after it's been used. 3) Deleting the second vv.push_back(Vector()); and m2.insert(PairVector("two", &vv.back())); statements. Using solution 2) makes Valgring print: 10 allocs, 11 frees Is that OK? As I'm not using new why should I delete? Thanks, for any help!

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