Search Results

Search found 38453 results on 1539 pages for 'java card'.

Page 770/1539 | < Previous Page | 766 767 768 769 770 771 772 773 774 775 776 777  | Next Page >

  • Create javadoc with multiple src dirs

    - by Ed Marty
    I have a Util package with source files in three seperate directories, defined like so: src/com/domain/util src/Standard/com/domain/util src/Extended/com/domain/util The package is built with the first set of files and either one of the second or third set, to create a total of two different implementations of the same interface. Now, I want to generate javadoc based on those files. How can I specify that? What I really want to do is javadoc com.domain.util -sourcepath ./src;./src/Standard to build the javadoc for the standard util package, and javadoc com.domain.util -sourcepath ./src;./src/Extended to build the javadoc for the extended util package. This doesn't work. The only way I've found so far to actually make it work is to merge the directory structure of the common classes and the Standard classes into another location and run with that for the standard javadoc, then do the same for the Extended package. Is there another way?

    Read the article

  • How to recursively serialize an object using reflection ?

    - by Tony
    I want to navigate to the N-th level of an object, and serialize it's properties in String format. For Example: class Animal { public String name; public int weight; public Animal friend; public Set<Animal> children = new HashSet<Animal>() ; } should be serialized like this: {name:"Monkey", weight:200, friend:{name:"Monkey Friend",weight:300 ,children:{...if has children}}, children:{name:"MonkeyChild1",weight:100,children:{... recursively nested}} } And you may probably notice that it is similar to serializing an object to json. I know there're many libs can do this, can you give me some instructive ideas on how to write this?

    Read the article

  • Error getting SVN repo of Liferay in Eclipse

    - by Tim
    Hello, Im using Eclipse Galileo and have installed Subclipse. I looked at the svn repo url at http://www.liferay.com/web/brian.chan/blog/-/blogs/changes-to-anonymous-access-to-liferay-s-svn and then tried to get Liferay from their SVN repository in Eclipse, using svn://svn.liferay.com/repos/public --username guest,but i get the following error message: Error validating location: "org.tigris.subversion.javahl.ClientException:No connection could be made because the target machine actively refused it. svn: Cant connect to host 'svn.liferay.com':No connection could be made because the target machine actively refused it Any way to fix this ? Thank You

    Read the article

  • Generate webservice soap client from wsdl when server using Windows Integrated Authentication

    - by James Black
    There is an SAP server that has some webservices I need to use, so I am trying to use wsimport to generate the client stubs. I don't want to find all the wsdls and schemas that are referenced and modify them to do it locally, as that isn't sustainable, if they service should change. So, how can I use wsimport to fetch a wsdl and generate the client stubs when the server is using Windows Integrated Authentication, where even the wsdl requires credentials.

    Read the article

  • IVR-style dialog system

    - by unbeli
    I need to build a dialog system similar to IVR used in call centers. My system is not phone-based, but the dialog is similar. Something like System: "Main menu: Enter [1] for menu1, [2] for menu2" User: [1] System: "menu1: enter [1] for apples, [2] for oranges, [3] for main menu" User: [7] System: "What??" System: "menu1: enter [1] for apples, [2] for oranges, [3] for main menu" User: [2] ... and so on I want to have a nice declarative description of all the possible options and a nice way to run through that tree, guided by user input. Already considered: ANTLR-generated lexer/parser (seems to be an overkill), SCXML-based state machine (seems like only transitions can be declared, the rest needs to be coded)

    Read the article

  • Eclipselink read complex oject model in an ordered way

    - by Raven
    Hi, I need to read a complex model in an ordered way with eclipselink. The order is mandantory because it is a huge database and I want to have an output of a small portion of the database in a jface tableview. Trying to reorder it in the loading/quering thread takes too long and ordering it in the LabelProvider blocks the UI thread too much time, so I thought if Eclipselink could be used that way, that the database will order it, it might give me the performance I need. Unfortunately the object model can not be changed :-( The model is something like: @SuppressWarnings("serial") @Entity public class Thing implements Serializable { @Id @GeneratedValue(strategy = GenerationType.TABLE) private int id; private String name; @OneToMany(cascade=CascadeType.ALL) @PrivateOwned private List<Property> properties = new ArrayList<Property>(); ... // getter and setter following here } public class Property implements Serializable { @Id @GeneratedValue(strategy = GenerationType.TABLE) private int id; @OneToOne private Item item; private String value; ... // getter and setter following here } public class Item implements Serializable { @Id @GeneratedValue(strategy = GenerationType.TABLE) private int id; private String name; .... // getter and setter following here } // Code end In the table view the y-axis is more or less created with the query Query q = em.createQuery("SELECT m FROM Thing m ORDER BY m.name ASC"); using the "name" attribute from the Thing objects as label. In the table view the x-axis is more or less created with the query Query q = em.createQuery("SELECT m FROM Item m ORDER BY m.name ASC"); using the "name" attribute from the Item objects as label. Each cell has the value Things.getProperties().get[x].getValue() Unfortunately the list "properties" is not ordered, so the combination of cell value and x-axis column number (x) is not necessarily correct. Therefore I need to order the list "properties" in the same way as I ordered the labeling of the x-axis. And exactly this is the thing I dont know how it is done. So querying for the Thing objects should return the list "properties" "ORDER BY name ASC" but of the "Item"s objects. My ideas are something like having a query with two JOINs. Joing Things with Property and with Item but somehow I was unable to get it to work yet. Thank you for your help and your ideas to solve this riddle.

    Read the article

  • algorithm for image comparison

    - by Rajnikant
    Please consider following use case, I have one bigger image, lets called is master image. Now from some where else, I am getting one small image. I want to check whether this small image is subset of master image or not. important points are, smaller image might have different file format, smaller image might captured from comparatively different view. smaller image may have different light intensity. At this stage of algorithm/computation advancement, which level of accuracy I could expect? Any algorithm/open source implementation that would have such implementation? Thanks, Rajnikant

    Read the article

  • How to display image within cell boundary

    - by Jessy
    How can I place an image within the cell boundary? I mean without taking the space of other cell? In the code below, random cells were selected to display images. One image in one cell. The problem is that, the image seems to take other cells as well. ... setPreferredSize(new Dimension(600,600)); final int ROWS = 6; final int COLS = 6; final int IMAGES = 10; setLayout(new GridBagLayout()); GridBagConstraints gc = new GridBagConstraints(); gc.weightx = 1d; gc.weighty = 1d; gc.insets = new Insets(0, 0, 0, 0);//top, left, bottom, and right gc.fill = GridBagConstraints.NONE; JLabel[][] label = new JLabel[ROWS][COLS]; Random rand = new Random(); // fill the panel with labels for (int i=0;i<IMAGES;i++){ ImageIcon icon = createImageIcon("myImage.jpg"); int r, c; do{ //pick random cell which is empty to avoid overlap image in the same cell r = (int)Math.floor(Math.random() * ROWS); c = (int)Math.floor(Math.random() * COLS); } while (label[r][c]!=null); //scale the image int x = rand.nextInt(20)+30; int y = rand.nextInt(20)+30; Image image = icon.getImage().getScaledInstance(x,y, Image.SCALE_SMOOTH); icon.setImage(image); JLabel lbl = new JLabel(icon); gc.gridx = r; gc.gridy = c; add(lbl, gc); //add image to the cell label[r][c] = lbl; }

    Read the article

  • How to display image within cell boundary

    - by Jessy
    How can I place an image within the cell boundary? I mean without taking the space of other cell? In the code below, random cells were selected to display images. One image in one cell. The problem is that, the image seems to take other cells as well. ... setPreferredSize(new Dimension(600,600)); final int ROWS = 6; final int COLS = 6; final int IMAGES = 10; setLayout(new GridBagLayout()); GridBagConstraints gc = new GridBagConstraints(); gc.weightx = 1d; gc.weighty = 1d; gc.insets = new Insets(0, 0, 0, 0);//top, left, bottom, and right gc.fill = GridBagConstraints.NONE; JLabel[][] label = new JLabel[ROWS][COLS]; Random rand = new Random(); // fill the panel with labels for (int i=0;i<IMAGES;i++){ ImageIcon icon = createImageIcon("myImage.jpg"); int r, c; do{ //pick random cell which is empty to avoid overlap image in the same cell r = (int)Math.floor(Math.random() * ROWS); c = (int)Math.floor(Math.random() * COLS); } while (label[r][c]!=null); //scale the image int x = rand.nextInt(20)+30; int y = rand.nextInt(20)+30; Image image = icon.getImage().getScaledInstance(x,y, Image.SCALE_SMOOTH); icon.setImage(image); JLabel lbl = new JLabel(icon); gc.gridx = r; gc.gridy = c; add(lbl, gc); //add image to the cell label[r][c] = lbl; }

    Read the article

  • Convert scientific notation to decimal notation

    - by Ankur
    There is a similar question on SO which suggests using NumberFormat which is what I have done. I am using the parse() method of NumberFormat. public static void main(String[] args) throws ParseException{ DecToTime dtt = new DecToTime(); dtt.decToTime("1.930000000000E+02"); } public void decToTime(String angle) throws ParseException{ DecimalFormat dform = new DecimalFormat(); //ParsePosition pp = new ParsePosition(13); Number angleAsNumber = dform.parse(angle); System.out.println(angleAsNumber); } The result I get is 1.93 I didn't really expect this to work because 1.930000000000E+02 is a pretty unusual looking number, do I have to do some string parsing first to remove the zeros? Or is there a quick and elegant way?

    Read the article

  • batch file command to run jar file

    - by Arivu2020
    I am created jar file.The jar file is an executable one.But how can i run the jar file from the out side,using created batch file.I want to know the batch file coding to run the jar file without mentioning class path. Or is there any way to do it?

    Read the article

  • Android Location Error

    - by Christopher
    I've singled out my problem to a few lines of code lm = (LocationManager)getSystemService(Context.LOCATION_SERVICE); Location location = lm.getLastKnownLocation(LocationManager.GPS_PROVIDER); lm.requestLocationUpdates(LocationManager.GPS_PROVIDER, 1000L, 5.0f, this); lat = location.getLatitude(); lng = location.getLongitude(); //lat = new Double(40.431682); //lng = new Double(-74.2021819); pLocation = new GeoPoint((int)(lat * 1000000), (int)(lng * 1000000)); My onLocationChanged if you were wondering public void onLocationChanged(Location location) { if (location != null) { lat = location.getLatitude(); lng = location.getLongitude(); pLocation = new GeoPoint((int)(lat * 1000000), (int)(lng * 1000000)); } } My application crashes if I try to get the LastKnownLocation But it works fine if I feed it a Location manually I have no idea currently whats wrong

    Read the article

  • how to accept valid e-mail id in text box?

    - by giri
    Hi I have designed a chat application using servlets and jsp. I have designed a page for user login, where I accept used id and his mail-id.How can i ensure that user has typed proper mail-id. I need a code to validate email-id.I mean for example user can not type anything in the text box.

    Read the article

  • Setting up new project in eclispe

    - by kbrin80
    So I set up a new project into eclipse and created a build.xml that creates a war file. The problem that I am having is that the only files that are included in the war are whats in the WEB-INF. How do you include my web folder into the war. Project src web WEB-INF

    Read the article

  • Hibernate MySQL transaction configuration issue

    - by James
    I'm having trouble starting a transaction with Hibernate and MySQL while running in JUnit. I'm getting a HibernateException which states: "No TransactionManagerLookup specified". I believe this error is because I don't have a proper configuration setting for hibernate.transaction.manager_lookup_class. I see that under the namespace of org.hibernate.transaction there are quite a few different lookup classes that I could use. All of the documentation that I could find on these was very vague. My question is what is the appropriate one for MySQL?

    Read the article

  • Algorithm to compare people names to detect identicalness

    - by Pentium10
    I am working on address book synchronization algorithm. I would like to reuse some code if there exists, but couldn't find one yet. Does someone know about an algorithm that will tell me in numbers/float/procent how much two names are identical. Levenstein distance is not good in this approach, as names and our adddress books are matching the begining of each of the name sections. John Smith should match Smith Jon, Jonathan Smith, Johnny Smith

    Read the article

  • Hibernate one-to-one mapping

    - by Andrey Yaskulsky
    I have one-to-one hibernate mapping between class Student and class Points: @Entity @Table(name = "Users") public class Student implements IUser { @Id @Column(name = "id") private int id; @Column(name = "name") private String name; @Column(name = "password") private String password; @OneToOne(fetch = FetchType.EAGER, mappedBy = "student") private Points points; @Column(name = "type") private int type = getType(); //gets and sets... @Entity @Table(name = "Points") public class Points { @GenericGenerator(name = "generator", strategy = "foreign", parameters = @Parameter(name = "property", value = "student")) @Id @GeneratedValue(generator = "generator") @Column(name = "id", unique = true, nullable = false) private int Id; @OneToOne @PrimaryKeyJoinColumn private Student student; //gets and sets And then i do: Student student = new Student(); student.setId(1); student.setName("Andrew"); student.setPassword("Password"); Points points = new Points(); points.setPoints(0.99); student.setPoints(points); points.setStudent(student); Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); session.save(student); session.getTransaction().commit(); And hibernate saves student in the table but not saves corresponding points. Is it OK? Should i save points separately?

    Read the article

  • WHich Implemtation of JSF 1.1 to USe MyFaces or Sun RI

    - by Macvin
    Hi, We want make a choice between SUN RI 1.1 JSF implementaiton and MyFaces . Appserver we will be using is Weblogic 8.1. Could you please rpovide main points for Comparison between the two Which one is better. Can we USe Facelets in SUN RI 1.1_02 . Which is the better choice if want to move the Application to JSF 1.2 and JDK 1.5 in Future. Thanks Mac

    Read the article

  • Why is ContextConfiguration location different in idea and eclipse

    - by jakob
    Hello experts. In my team we work both in Eclipse and Idea. That works pretty good, except for one minor issue that I can't figure out how to solve. When setting the ContextConfiguration location in our tests and running them inside Eclipse everything works like a charm: @Test(groups = { "database" }) @ContextConfiguration(locations = {" file:src/main/webapp/WEB-INF/applicationContext.xml" }) But in my Idea env I get "could not find applicationContext" error. I need to set the location like this(project name is services): @Test(groups = { "database" }) @ContextConfiguration(locations = {" file:services/src/main/webapp/WEB-INF/applicationContext.xml" }) The project structure is like this: parent.pom with two child poms: services.pom and other.pom. When running the test in the terminal from the service project like this: mvn -Dtest=com.mytest.service.somepackage.TheTest test there are no issues. I guess that since my project structure is parent-with-two-children the need of /service is necessary(The project is created by pointing out the parent pom). Is there a way to fix this? Could you please help me with a solution. thx

    Read the article

< Previous Page | 766 767 768 769 770 771 772 773 774 775 776 777  | Next Page >