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  • overriding the Home Key Long press in a category.HOME activity.

    - by Profete162
    Hello all, I just created my own "Home" to replace the stock android one or Sense. All is working fine and I get all I want. My only problem is to replace to long press on home key ( that usually show the last 6 activities you launched) by my own launcher. I successfully replace the long press on MENU button with this code: @Override public boolean onKeyDown(int keyCode, KeyEvent event) { //Log.i(TAG,"Keycode: "+keyCode); if (keyCode == KeyEvent.KEYCODE_MENU) { // this tells the framework to start tracking for // a long press and eventual key up. it will only // do so if this is the first down (not a repeat). event.startTracking(); return true; } (...) and this part part for the long press: @Override public boolean onKeyLongPress(int keyCode, KeyEvent event) { //Log.i(TAG,"LONG"+keyCode); Toast.makeText(Launcher.this,"LONG "+keyCode, Toast.LENGTH_SHORT).show(); if (keyCode == KeyEvent.KEYCODE_MENU) { (...) But the problem is that I wasn't able to replace the KeyEvent.KEYCODE_MENU with KeyEvent.KEYCODE_HOME is that something locked in the code that avoid user to use a Home long press? Thank a lot for all the information you woulg give me.

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  • iPhone TableView alternative options for Check Mark Accessory

    - by jimsis
    I'm looking for the best approach to this problem. In my tableview I have a list of options from which you can select one and only one. The problem is the selection to choose is not obvious without displaying more details on the option. If I use the disclosure indicator or button for the more detail, I lose the checkmark functionality. In searching around I see some have used the cell Image as a work around. I see others instead of using the standard disclosure button have created custom disclosure button looking like a checkmark. Haven't seen this one but is it viable (HIG) to add a button in the cell ('more info') to launch the next tableview. My thought was to use a disclosure indicator and on the second view in the navigation bar (where the edit button usually is) add a 'selectMe' button. I think I am probably manage to code either of the above, am just asking for information on what is the best (HIG) way. Example Option 1 Option 2 Option 3 (x) Option 4 Where x is the checked one But in order to know which is the best choice you need to see Option 3 (Header) Option 3-a Option 3-b Option 3-c Option 3-d Where even at this level option 3-c might have additional information. Any guidance you can provide would appreciated.

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  • VS2008 javascript debugger IE8 "there is no source code available for the current location"

    - by Jeff Keslinke
    I have almost the same problem as this unanswered question. The only difference is I'm using VS2008, but I'm in an MVC project calling this javascript function: function CompanyChange(compCtrl) { alert(compCtrl.value); debugger; var test; for (var i = 0; i < document.all.length; i++) { test = document.all[i]; } } I hit the alert, then I get the message "there is no source code available for the current location." At which point the page becomes unresponsive and I have to manually stop the debugger just to shut it down. I've logged into another machine and ran this exact code and it works fine, I hit the debugger and can step through. I've checked to make sure all settings in VSToolsOptionsDebugging are identical as well as IEOptionsAdvanced and they are. Both machines are Windows 7 Enterprise edition 32-bit, VS2008, IE8. I've also tried attaching a process manually in VS, and using the 'Developer Tools' in IE which didn't work (said there already was a process attached). I was hoping someone may have had this problem and found a work-around because I've already done a lot of searching and tried all the options I've read. Anyone else run into this? Thank you, Jeff

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  • How to improve Java perfomance on Informix for Windows

    - by Michal Niklas
    I have problem with performance of Java UDR functions on Informix on Windows. On this server I already have some functions in C and SPL. I chose one function to write it in those 3 languages and I measured performance of this function on test table. Function calculates some kind of checksum so it not use any db libraries etc. only string and math operations. I observed performance on 30k records with SQL like: select function(txt) from _tmp_perf_test and I changed function to 'function_c, function_spl or function_java. My performance tests showed that C function is the fastest, SPL function is about 5 times slower, where Java is 100 (one hundred!) times slower than C. I checked it few times and 1:100 ratio didn't improve. I changed Java function to simply return length of the string but even this do not help so it looks, that there is general problem with Java function invocation, because there was no difference in time between Java function that calculate checksum and Java function that returns length of the string. I increased JVM_MAX_HEAP_SIZE to 128 and it not helped too. I use IBM Informix Dynamic Server Version 11.50.TC6DE. The same test on Linux server: IBM Informix Dynamic Server Version 11.50.FC6 show more "normal" results, i.e. Java is slower from C and SPL but only 2 to 5 times. What can I do to improve Java performance on Informix server on Windows? More info about Java on servers: c:\Informix\extend\krakatoa\jre\bin>java -version java version "1.5.0" Java(TM) 2 Runtime Environment, Standard Edition (build pwi32dev-20081129a (SR9-0 )) IBM J9 VM (build 2.3, J2RE 1.5.0 IBM J9 2.3 Windows Server 2003 x86-32 j9vmwi3223-20081129 (JIT enabled) J9VM - 20081126_26240_lHdSMr JIT - 20081112_1511ifx1_r8 GC - 200811_07) JCL - 20081129 [root@informix11 bin]# ./java -version java version "1.5.0" Java(TM) 2 Runtime Environment, Standard Edition (build pxa64devifx-20071025 (SR6b)) IBM J9 VM (build 2.3, J2RE 1.5.0 IBM J9 2.3 Linux amd64-64 j9vmxa6423-20071005 (JIT enabled) J9VM - 20071004_14218_LHdSMr JIT - 20070820_1846ifx1_r8 GC - 200708_10) JCL - 20071025

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  • appstats broken filename in callstack

    - by Ray Yun
    When I visit appstats page and expand callstack, the file path has <path[N]> prefix. So click the file link then emit no such file or directory error. Stack: /google/appengine/datastore/datastore_rpc.py:951 make_rpc_call() /google/appengine/datastore/datastore_query.py:993 _make_query_result_rpc_call() /google/appengine/datastore/datastore_query.py:714 run_async() /google/appengine/datastore/datastore_query.py:685 run() /google/appengine/api/datastore.py:1281 GetBatcher() /google/appengine/api/datastore.py:1351 Get() /google/appengine/ext/db/init.py:1831 fetch() /google/appengine/ext/db/init.py:1778 get() /apps/fbapp/fbutil.py:232 oauth_load_fb_user() /apps/fbapp/fbutil.py:84 require_account() the error message for appengine source: [Errno 2] No such file or directory: u'/Applications/GoogleAppEngineLauncher.app/Contents/Resources/GoogleAppEngine-default.bundle/Contents/Resources/google_appengine/lib/ipaddr/google/appengine/datastore/datastore_rpc.py' the error message for my source: IOError [Errno 2] No such file or directory: u'/Applications/GoogleAppEngineLauncher.app/Contents/Resources/GoogleAppEngine-default.bundle/Contents/Resources/google_appengine/lib/antlr3/apps/fbapp/fbutil.py' I guess this was path problem and found some official comment from google. If your request handlers modify sys.path, you must make the same modifications to sys.path in appengine_config.py so the Appstats web interface can see all files. Actually I'm using appengine_django and two path was inserted to sys.path. I did it same again at appengine_django.py but also failed. Maybe some custom setting with appengine_config.py can solve this problem but doesn't figure out how to fix it. What can I do?

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  • WCF timeout exception on calling service on 11th time

    - by Sergej Andrejev
    I'm creating a WCF service and stumbled with request timeout problem. When I load test the service the 11th call always fails with "System.Net.WebException: The operation has timed out". I have read that would happen if serviceThrotling is set to defaults so I added following lines to my service configuration file <behavior name="ServiceBehavior"> <!-- ... --> <serviceThrottling maxConcurrentCalls="100" maxConcurrentSessions="100" maxConcurrentInstances="100" /> </behavior> But this doesn't help. I thought that closing the proxy might be a problem, but I do close all proxies. try { response = service.GetCustomerHdQuotes(request); } finally { try { if (service.State != CommunicationState.Faulted) service.Close(); else service.Abort(); // Abort if the State is Faulted. } catch (Exception) { service.Abort(); } } I also have an idea that inside service some resources pile up preventing service to accept new connections, but the fact that this is always 11th request points that this is more likely due to some configuration problems. Can anybody help me with that?

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  • HttpServletRequest#login() not working in Java.

    - by Nitesh Panchal
    Hello, j_security_check just doesn't seem enough for me to perform login process. So, instead of submitting the form to j_security_check i created my own servlet and in that i am programmatically trying to do login. This works but i am not able to redirect to my restricted resource. Can anybody tell me what can be the problem? This is processRequest method of my servlet :- protected void processRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { response.setContentType("text/html;charset=UTF-8"); PrintWriter out = response.getWriter(); try { String strUsername = request.getParameter("txtusername"); String strPassword = request.getParameter("txtpassword"); if(strUsername == null || strPassword == null || strUsername.equals("") || strPassword.equals("")) throw new Exception("Username and/or password missing."); request.login(strUsername, strPassword); System.out.println("Login succeeded!!"); if(request.isUserInRole(ROLES.ADMIN.getValue())){//enum System.out.println("Found in Admin Role"); response.sendRedirect("/Admin/home.jsf"); } else if (request.isUserInRole(ROLES.GENERAL.getValue())) response.sendRedirect("/Common/index.jsf"); else //guard throw new Exception("No role for user " + request.getRemoteUser()); }catch(Exception ex){ //patch work why there needs to be blogger here? System.out.println("Invalid username and/or password!!"); response.sendRedirect("/Common/index.jsf"); }finally { out.close(); } } Everything works fine and i can even see message "Found in Admin Role" but problem is even after authenticating i am not able to redirect my request to some other page. Please help geeks.

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  • Why is document.body == null in Firefox but not Safari

    - by dlamblin
    I have a problem with a page where I am trying to get colorbox (a kind of lightbox for jQuery) working. It doesn't work apparently due to the document.body being null in FireFox (3.5.3). This is not the case in Safari (4.0.3) where the colorbox works. Something that jumps out at me is that (I'm using Drupal 6) drupal has appended a script tag to set some JavaScript variables at the very bottom of the page, below the closing body and html tags. Otherwise I don't see a problem. Unfortunately I'm having a lot of trouble getting it not to do that. Could it be this that's causing FF to have issues with the body? Using colorbox's example files in Firefox does work (and the document.body is defined there). Is there any way I could use jQuery to refill the document.body property with something from $() perhaps, or should I keep banging at drupal to not put a script tag outside the html tags (easier said than done)? To clarify the document.body is null even after the page is done loading. Here's a Firebug console capture: >>> document.body null >>> $().attr('body') null

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  • Fix common library functions, or abandon then?

    - by Ian Boyd
    Imagine i have a function with a bug in it: Boolean MakeLocation(String City, String State) { //Given "Springfield", "MO" //return "Springfield, MO" return City+", "+State; } So the call: MakeLocation("Springfield", "MO"); would return "Springfield, MO" Now there's a slight problem, what if the user called: MakeLocation("Springfield, MO", "OH"); The called it wrong, obviously. But the function would return "Springfield, MO, OH". The system was functioning like this for many years, until i noticed the function being used wrong, and i corrected it. And i also updated the original function to catch such an obvious mistake - in case it's happening elsewhere: Boolean MakeLocation(String City, String State) { //Given "Springfield", "MO" //return "Springfield, MO" if (City.Contains, ",") throw new EMakeLocationException("City name contains a comma. You probably didn't mean that"); return City+", "+State; } And testing showed the problem fixed. Except we missed an edge case, and the customer found it. So now the moral dillema. Do you ever add new sanity checks, safety checks, assertions to exising code? Or do you call the old function abandoned, and have a new one: Boolean MakeLocation(String City, String State) { //Given "Springfield", "MO" //return "Springfield, MO" return City+", "+State; } Boolean MakeLocation2(String City, String State) { //Given "Springfield", "MO" //return "Springfield, MO" if (City.Contains, ",") throw new EMakeLocationException("City name contains a comma. You probably didn't mean that"); return City+", "+State; } The same can apply for anything: Question FetchQuestion(Int id) { if (id == 0) throw new EFetchQuestionException("No question ID specified"); ... } Do you risk breaking existing code, at the expense of existing code being wrong?

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  • Does Perl's Net::Cassandra module support UTF-8?

    - by knorv
    I've run into a really strange UTF-8 problem with Net::Cassandra::Easy (which is built upon Net::Cassandra): UTF-8 strings written to Cassandra are garbled upon retrieval. The following code shows the problem: use strict; use utf8; use warnings; use Net::Cassandra::Easy; binmode(STDOUT, ":utf8"); my $key = "some_key"; my $column = "some_column"; my $set_value = "\x{2603}"; my $cassandra = Net::Cassandra::Easy->new(keyspace => "Keyspace1", server => "localhost"); $cassandra->connect(); $cassandra->mutate([$key], family => "Standard1", insertions => { $column => $set_value }); my $result = $cassandra->get([$key], family => "Standard1", standard => 1); my $get_value = $result->{$key}->{"Standard1"}->{$column}; if ($set_value eq $get_value) { # this is the path I want. print "OK: $set_value == $get_value\n"; } else { # this is the path I get. print "ERR: $set_value != $get_value\n"; } When running the code above $set_value eq $get_value evaluates to false. What am I doing wrong?

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  • Is it possible to make a non-nullable column nullable when used in a view? (sql server)

    - by Matt
    Hi, To start off I have two tables, PersonNames and PersonNameVariations. When a name is searched, it finds the closest name to one of the ones available in PersonNames and records it in the PersonNameVariations table if it's not already in there. I am using a stored proc to search the PersonNames for a passed in PersonNameVariationand return the information on both the PersonName found and the PersonNameVariation that was compared to it. Since I am using the Entity Framework, I needed return a complex type in the Import Function but for some reason it says my current framework doesn't support it. My last option was to use an Entity to return in my stored proc instead. The result that I needed back is the information on both the PersonName that was found and the PersonNameVariation that was recorded. Since I cannot return both entities, I created a view PersonSearchVariationInfo and added it into my Entity Framework in order to use it as the entity to return. The problem is that the search will not always return a Person Name match. It needs to be able to return only the PersonNameVariation data in some cases, meaning that all the fields in the PersonSearchVariationInfo pertaining to PersonName need to be nullable. How can I take my view and make some of the fields nullable? When I do it directly in the Entity Framework I get a mapping error: Error 4 Error 3031: Problem in mapping fragments starting at line 1202:Non-nullable column myproject_vw_PersonSearchVariationInfo.DateAdded in table myproject_vw_PersonSearchVariationInfo is mapped to a nullable entity property. C:\Users\Administrator\Documents\Visual Studio 2010\Projects\MyProject\MyProject.Domain\EntityFramework\MyProjectDBEntities.edmx 1203 15 MyProject.Domain Anyone have any ideas? Thanks, Matt

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  • Hibernate: "Field 'id' doesn't have a default value"

    - by André Neves
    Hi, all. I'm facing what I think is a simple problem with Hibernate, but can't get over it (Hibernate forums being unreachable certainly doesn't help). I have a simple class I'd like to persist, but keep getting: SEVERE: Field 'id' doesn't have a default value Exception in thread "main" org.hibernate.exception.GenericJDBCException: could not insert: [hibtest.model.Mensagem] at org.hibernate.exception.SQLStateConverter.handledNonSpecificException(SQLStateConverter.java:103) at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:91) [ a bunch more ] Caused by: java.sql.SQLException: Field 'id' doesn't have a default value [ a bunch more ] The relevant code for the persisted class is: package hibtest.model; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.Inheritance; import javax.persistence.InheritanceType; @Entity @Inheritance(strategy = InheritanceType.JOINED) public class Mensagem { protected Long id; protected Mensagem() { } @Id @GeneratedValue public Long getId() { return id; } public Mensagem setId(Long id) { this.id = id; return this; } } And the actual running code is just plain: SessionFactory factory = new AnnotationConfiguration() .configure() .buildSessionFactory(); { Session session = factory.openSession(); Transaction tx = session.beginTransaction(); Mensagem msg = new Mensagem("YARR!"); session.save(msg); tx.commit(); session.close(); } I tried some "strategies" within the GeneratedValue annotation but it just doesn't seem to work. Initializing id doesn't help either! (eg Long id = 20L). Could anyone shed some light? EDIT 2: confirmed: messing with@GeneratedValue(strategy = GenerationType.XXX) doesn't solve it SOLVED: recreating the database solved the problem

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  • Objective-C classes, pointers to primitive types, etc.

    - by Toby Wilson
    I'll cut a really long story short and give an example of my problem. Given a class that has a pointer to a primitive type as a property: @interface ClassOne : NSObject { int* aNumber } @property int* aNumber; The class is instantiated, and aNumber is allocated and assigned a value, accordingly: ClassOne* bob = [[ClassOne alloc] init]; bob.aNumber = malloc(sizeof(int)); *bob.aNumber = 5; It is then passed, by reference, to assign the aNumber value of a seperate instance of this type of class, accordingly: ClassOne* fred = [[ClassOne alloc] init]; fred.aNumber = bob.aNumber; Fred's aNumber pointer is then freed, reallocated, and assigned a new value, for example 7. Now, the problem I'm having; Since Fred has been assigned the same pointer that Bob had, I would expect that Bob's aNumber will now have a value of 7. It doesn't, because for some reason it's pointer was freed, but not reassigned (it is still pointing to the same address it was first allocated which is now freed). Fred's pointer, however, has the allocated value 7 in a different memory location. Why is it behaving like this? What am I minsunderstanding? How can I make it work like C++ does?

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  • Algorithm to get through a maze

    - by Sam
    Hello, We are currently programming a game (its a pretty unknown language: modula 2), And the problem we encountered is the following: we have a maze (not a perfect maze) in a 17 x 12 grid. The computer has to generate a way from the starting point (9, 12) to the end point (9, 1). I found some algorithms but they dont work when the robot has to go back: xxxxx x => x x xxx or: xxxxx x xxxxxx x x x x x xxxxxx x => x xxxxxxxxx I found a solution for the first example type but then the second type couldn't be solved and the solution I made up for the second type would cause the robot to get stuck in the first type of situation. It's a lot of code so i'll give the idea: WHILE (end destination not reached) DO { try to go right, if nothing blocks you: go right if you encounter a block, try up until you can go right, if you cant go up anymore try going down until you can go right, (starting from the place you first were blocked), if you cant go down anymore, try one step left and fill the spaces you tested with blocks. } This works for the first type of problem ... not for the second one. Now it could be that i started wrong so i am open for better algorithms or solutions specificaly to how i could improve my algorithm. Thanks a lot!!

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  • C# Menu Toolstrip Get Status

    - by Yeti
    So I have a project where there is some automatic initialization going on through some classes that are created automatically as global variables (deah they are static instances). At a point inside this (it has no relation with the C# GUI for the user, so it isn't derived from any C# class) I need to see if a flag is set or not. I use toolstrip menu with checked and unchecked status in order to set or unset the flag. The problem is that I have difficulties to see if the flag is checked or not from this static class. My class is inside a different project/namespace and a DLL is created what later is linked to the GUI of the application. The GUI depends from this Manager class so making the Manager class to depend from the GUI is not an option. Nevertheless, I should be able to see its state knowing its name or through some other means. I have tried the following: if(Application.OpenForms[1].Owner.Controls["useLocalImageForInitToolStripMenuItem"].Enabled) { }; Now the problem is that on the upper code snippet I get a nasty error. So how do I do this?

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  • Ajax render attribute don't work in a h:dataTable in JSF2

    - by u2ix
    Hello everybody, I have some problem's with a simple application in JSF 2.0. I try to build a ToDo List with ajax support. I have some todo strings which I display using a datatable. Inside this datatable I have a commandLink to delete a task. The problem is now that the datatable don't get re-rendered. <h:dataTable id="todoList" value="#{todoController.todos}" var="todo"> <h:column> <h:commandLink value="X" action="#{todoController.removeTodo(todo)}"> <f:ajax execute="@this" render="todoList" /> </h:commandLink> </h:column> <h:column> <h:outputText value="#{todo}"/> </h:column> </h:dataTable> Thanks for your help. Edit (TodoController): @ManagedBean @SessionScoped public class TodoController { private String todoStr; private ArrayList<String> todos; public TodoController() { todoStr=""; todos = new ArrayList<String>(); } public void addTodo() { todos.add(todoStr); } public void removeTodo(String deleteTodo) { todos.remove(deleteTodo); } /* getter / setter */ }

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  • How to handle One View with multiple ViewModel and fire different Commands

    - by Naresh
    Hi All, I have senario in which one view and view has binding with multiple ViewModel. Eg. One View displaying Phone Detail and ViewModel as per bellow: Phone basic features- PhoneViewModel, Phone Price Detail- PhoneSubscriptionViewModel, Phone Accessories- PhoneAccessoryViewModel For general properties- PhoneDetailViewModel I have placed View's general properties to PhoneViewModel.Now senario is like this: By default View displays Phone Basic feaures which is bind with ObservationCollection of PhoneViewModel. My view have button - 'View Accessories', onclick of this button one popup screen- in my design I have display/hide Grid and bind it with ObservationCollection of PhoneAccessoryViewModel. Now problem begins- Accessory List also have button 'View Detail' onclick I have to open one popup screen, here also I had placed one Grid and Visible/Hide it. I have bind 'ViewAccessoryDetailCommand' command to 'View Detail' button. And on command execution one function fires and set property which Visible the Popup screen. Using such programming command fires, function calls but the property change not raises and so my view does not display popup. Summary: One View-- ViewModel1--Grid Bind view ViewModel2 --Grid Have Button and Onclick display new Grid which binded with ViewModel3-this Command fires but property not raises. I think there is some problem in my methodology, Please, give your suggetions.

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  • Configuration Error ASP.NET password format specified is invalid

    - by salvationishere
    I am getting the above error in IIS 6.0 now when I browse my C# / SQL web application. This was built in VS 2008 and SS 2008 on a 32-bit XP OS. The application was working before I added Login controls to it. However, this is my first time configuring Login/password controls so I am probably missing something really basic. This error doesn't happen until I try to login. Here are the details of my error from IIS; I get the same error in VS: Parser Error Message: Password format specified is invalid. Source Error: Line 31: <add Line 32: name="SqlProvider" Line 33: type="System.Web.Security.SqlMembershipProvider" Line 34: connectionStringName="AdventureWorksConnectionString2" Line 35: applicationName="AddFileToSQL2" Source File: C:\Inetpub\AddFileToSQL2\web.config Line: 33 And the relevant contents of my web.config are: <connectionStrings> <add name="Master" connectionString="server=MSSQLSERVER;database=Master; Integrated Security=SSPI" providerName="System.Data.SqlClient" /> <add name="AdventureWorksConnectionString" connectionString="Data Source=SIDEKICK;Initial Catalog=AdventureWorks;Integrated Security=True" providerName="System.Data.SqlClient" /> <add name="AdventureWorksConnectionString2" connectionString="Data Source=SIDEKICK;Initial Catalog=AdventureWorks;Integrated Security=True; " providerName="System.Data.SqlClient" /> </connectionStrings> <system.web> <membership defaultProvider="SqlProvider" userIsOnlineTimeWindow="15"> <providers> <clear /> <add name="SqlProvider" type="System.Web.Security.SqlMembershipProvider" connectionStringName="AdventureWorksConnectionString2" applicationName="AddFileToSQL2" enablePasswordRetrieval="false" enablePasswordReset="true" requiresQuestionAndAnswer="true" requiresUniqueEmail="false" passwordFormat="encrypted" /> </providers> </membership> <!-- Set compilation debug="true" to insert debugging symbols into the compiled page. Because this affects performance, set this value to true only during development. --> <roleManager enabled="true" /> <compilation debug="true"> <assemblies> <add assembly="System.Core, Version=3.5.0.0, Culture=neutral, PublicKeyToken=B77A5C561934E089"/> <add assembly="System.Data.DataSetExtensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=B77A5C561934E089"/> <add assembly="System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35"/> <add assembly="System.Xml.Linq, Version=3.5.0.0, Culture=neutral, PublicKeyToken=B77A5C561934E089"/> </assemblies> </compilation> <!-- The <authentication> section enables configuration of the security authentication mode used by ASP.NET to identify an incoming user. --> <authentication mode="Forms"> <forms loginUrl="Password.aspx" protection="All" timeout="30" name="SqlAuthCookie" path="/FormsAuth" requireSSL="false" slidingExpiration="true" defaultUrl="default.aspx" cookieless="UseCookies" enableCrossAppRedirects="false" /> </authentication> <!--Authorization permits only authenticated users to access the application --> <authorization> <deny users="?" /> <allow users="*" /> </authorization> <!-- The <customErrors> section enables configuration of what to do if/when an unhandled error occurs during the execution of a request. Specifically, it enables developers to configure html error pages to be displayed in place of a error stack trace. <customErrors mode="RemoteOnly" defaultRedirect="GenericErrorPage.htm"> <error statusCode="403" redirect="NoAccess.htm" /> <error statusCode="404" redirect="FileNotFound.htm" /> </customErrors> --> <pages> <controls> <add tagPrefix="asp" namespace="System.Web.UI" assembly="System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35"/> <add tagPrefix="asp" namespace="System.Web.UI.WebControls" assembly="System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35"/> </controls> </pages> <httpHandlers> <remove verb="*" path="*.asmx"/> <add verb="*" path="*.asmx" validate="false" type="System.Web.Script.Services.ScriptHandlerFactory, System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35"/> <add verb="*" path="*_AppService.axd" validate="false" type="System.Web.Script.Services.ScriptHandlerFactory, System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35"/> <add verb="GET,HEAD" path="ScriptResource.axd" type="System.Web.Handlers.ScriptResourceHandler, System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35" validate="false"/> </httpHandlers> <httpModules> <add name="ScriptModule" type="System.Web.Handlers.ScriptModule, System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35"/> </httpModules> </system.web> <system.codedom> <compilers> <compiler language="c#;cs;csharp" extension=".cs" warningLevel="4" type="Microsoft.CSharp.CSharpCodeProvider, System, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089"> <providerOption name="CompilerVersion" value="v3.5"/> <providerOption name="WarnAsError" value="false"/> </compiler> </compilers> </system.codedom> <!-- The system.webServer section is required for running ASP.NET AJAX under Internet Information Services 7.0. It is not necessary for previous version of IIS. --> <system.webServer> <validation validateIntegratedModeConfiguration="false"/> <modules> <remove name="ScriptModule"/> <add name="ScriptModule" preCondition="managedHandler" type="System.Web.Handlers.ScriptModule, System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35"/> </modules> <handlers> <remove name="WebServiceHandlerFactory-Integrated"/> <remove name="ScriptHandlerFactory"/> <remove name="ScriptHandlerFactoryAppServices"/> <remove name="ScriptResource"/> <add name="ScriptHandlerFactory" verb="*" path="*.asmx" preCondition="integratedMode" type="System.Web.Script.Services.ScriptHandlerFactory, System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35"/> <add name="ScriptHandlerFactoryAppServices" verb="*" path="*_AppService.axd" preCondition="integratedMode" type="System.Web.Script.Services.ScriptHandlerFactory, System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35"/> <add name="ScriptResource" preCondition="integratedMode" verb="GET,HEAD" path="ScriptResource.axd" type="System.Web.Handlers.ScriptResourceHandler, System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35"/> </handlers> </system.webServer> <runtime> <assemblyBinding xmlns="urn:schemas-microsoft-com:asm.v1"> <dependentAssembly> <assemblyIdentity name="System.Web.Extensions" publicKeyToken="31bf3856ad364e35"/> <bindingRedirect oldVersion="1.0.0.0-1.1.0.0" newVersion="3.5.0.0"/> </dependentAssembly> <dependentAssembly> <assemblyIdentity name="System.Web.Extensions.Design" publicKeyToken="31bf3856ad364e35"/> <bindingRedirect oldVersion="1.0.0.0-1.1.0.0" newVersion="3.5.0.0"/> </dependentAssembly> </assemblyBinding> </runtime> <system.net> <mailSettings> <smtp from="[email protected]"> <network host="SIDEKICK" password="" userName="" /> </smtp> </mailSettings> </system.net> </configuration> I checked and I do have an aspnetdb database in my SSMS. The Network Service account has SELECT, EXECUTE, INSERT, UPDATE access to this database. But one problem I see is that all of the tables in this database are empty except for aspnet_SchemaVersions, which just has 2 records (common and membership). Is this right? I added users and roles via ASP.NET Configuration wizard, and I believe I set this up correctly since I followed the Microsoft tutorial at http://msdn.microsoft.com/en-us/library/ms998347.aspx. One other problem I see from VS is after adding content to my Page_Load on my initial login Password.aspx.cs file, I'm getting an invalid cast problem below. I googled this problem also but the solutions I saw confused me even more. The Page_Load section I added is: protected void Page_Load(object sender, EventArgs e) { Response.Write("Hello, " + Server.HtmlEncode(User.Identity.Name)); FormsIdentity id = (FormsIdentity)User.Identity; FormsAuthenticationTicket ticket = id.Ticket; Response.Write("<p/>TicketName: " + ticket.Name); Response.Write("<br/>Cookie Path: " + ticket.CookiePath); Response.Write("<br/>Ticket Expiration: " + ticket.Expiration.ToString()); Response.Write("<br/>Expired: " + ticket.Expired.ToString()); Response.Write("<br/>Persistent: " + ticket.IsPersistent.ToString()); Response.Write("<br/>IssueDate: " + ticket.IssueDate.ToString()); Response.Write("<br/>UserData: " + ticket.UserData); Response.Write("<br/>Version: " + ticket.Version.ToString()); } And the VS exception I'm getting: System.InvalidCastException was unhandled by user code Message="Unable to cast object of type 'System.Security.Principal.GenericIdentity' to type 'System.Web.Security.FormsIdentity'." Source="AddFileToSQL" StackTrace: at AddFileToSQL.Password.Page_Load(Object sender, EventArgs e) in C:\Documents and Settings\Admin\My Documents\Visual Studio 2008\Projects\AddFileToSQL2\AddFileToSQL\Password.aspx.cs:line 22 at System.Web.Util.CalliHelper.EventArgFunctionCaller(IntPtr fp, Object o, Object t, EventArgs e) at System.Web.Util.CalliEventHandlerDelegateProxy.Callback(Object sender, EventArgs e) at System.Web.UI.Control.OnLoad(EventArgs e) at System.Web.UI.Control.LoadRecursive() at System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) InnerException:

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  • Create Zip File In Windows and Extract Zip File In Linux

    - by Yan Cheng CHEOK
    I had created a zip file (together with directory) under Windows as follow : package sandbox; import java.io.File; import java.io.FileInputStream; import java.io.FileOutputStream; import java.io.IOException; import java.util.zip.ZipEntry; import java.util.zip.ZipOutputStream; /** * * @author yan-cheng.cheok */ public class Main { /** * @param args the command line arguments */ public static void main(String[] args) { // These are the files to include in the ZIP file String[] filenames = new String[]{"MyDirectory" + File.separator + "MyFile.txt"}; // Create a buffer for reading the files byte[] buf = new byte[1024]; try { // Create the ZIP file String outFilename = "outfile.zip"; ZipOutputStream out = new ZipOutputStream(new FileOutputStream(outFilename)); // Compress the files for (int i=0; i<filenames.length; i++) { FileInputStream in = new FileInputStream(filenames[i]); // Add ZIP entry to output stream. out.putNextEntry(new ZipEntry(filenames[i])); // Transfer bytes from the file to the ZIP file int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } // Complete the entry out.closeEntry(); in.close(); } // Complete the ZIP file out.close(); } catch (IOException e) { e.printStackTrace(); } } } The newly created zip file can be extracted without problem under Windows, by using http://www.exampledepot.com/egs/java.util.zip/GetZip.html However, I realize if I extract the newly created zip file under Linux, using http://www.exampledepot.com/egs/java.util.zip/GetZip.html, I will get a file named "MyDirectory\MyFile.txt" instead of MyFile.txt being placed under folder MyDirectory. I try to solve the problem by changing the zip file creation code to String[] filenames = new String[]{"MyDirectory" + "/" + "MyFile.txt"}; But, is this an eligible solution, by hard-coded the seperator? Will it work under Mac OS? (I do not have a Mac to try out)

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  • How does Visual Studio decide the order in which stack variables should be allocated?

    - by Jason
    I'm trying to turn some of the programs in gera's Insecure Programming by example into client/server applications that could be used in capture the flag scenarios to teach exploit development. The problem I'm having is that I'm not sure how Visual Studio (I'm using 2005 Professional Edition) decides where to allocate variables on the stack. When I compile and run example 1: int main() { int cookie; char buf[80]; printf("buf: %08x cookie: %08x\n", &buf, &cookie); gets(buf); if (cookie == 0x41424344) printf("you win!\n"); } I get the following result: buf: 0012ff14 cookie: 0012ff64 buf starts at an address eighty bytes lower than cookie, and any four bytes that are copied in buf after the first eighty will appear in cookie. The problem I'm having is when I place this code in some other function. When I compile and run the following code, I get a different result: buf appears at an address greater than cookie's. void ClientSocketHandler(SOCKET cs){ int cookie; char buf[80]; char stringToSend[160]; int numBytesRecved; int totalNumBytes; sprintf(stringToSend,"buf: %08x cookie: %08x\n",&buf,&cookie); send(cs,stringToSend,strlen(stringToSend),NULL); The result is: buf: 0012fd00 cookie: 0012fcfc Now there is no way to set cookie to arbitrary data via overwriting buf. Is there any way to tell Visual Studio to allocate cookie before buf? Is there any way to tell beforehand how the variables will be allocated? Thanks, Jason

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  • jQuery draggable + droppable: how to snap dropped element to dropped-on element

    - by 10goto10
    I have my screen divided into two DIVs. In the left DIV I have a few 50x50 pixel DIVs, in the right DIV I have an empty grid made of 80x80 LIs. The DIVs on the left are draggable, and once dropped on a LI, they should snap to center of that LI. Sounds simple, right? I just don't know how to get this done. I tried by manipulating the dropped DIV's top and left CSS properties to match those of the LI they're dropped into, but the left and top properties are relative to the left DIV. How can I best have the dropped element snap to the center of the element it's dropped into? That's gotta be simple, right? Edit: I'm using jQuery UI 1.7.2 with jQuery 1.3.2. Edit 2: For whoever else has this problem, this is how I fixed it: I used Keith's solution of removing the dragged element and placing it inside the dropped-on element in the drop callback of the droppable plugin: function gallerySnap(droppedOn, droppedElement) { $(droppedOn).html('<div class="drop_styles">'+$(droppedElement).html()+'</div>' ); $(droppedElement).remove(); } I don't the dropped element to be draggable again, but if you do, just bind draggable to it again. For me this method also solved the problem I had when positioning the dropped elements (which would be relative to the left DIV) and scrolling inside the second DIV. (Elements would remain fixed on page, now they scroll along). I did play with the snap options to make it look good while dragging, so thanks to karim79 for that suggestion. I probably won't win any Awesome Code prizes with this, so if you see room for improvement, please share!

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  • Need Advice on building the database. all in one table or split?

    - by Ibrahim Azhar Armar
    hello, i am developing an application for a real-estate company. the problem i am facing is about implementing the database. however i am just confused on which way to adopt i would appreciate if you could help me out in reasoning the database implementation. here is my situation. a) i have to store the property details in the database. b) the properties have approximately 4-5 categories to which it will belong for ex : resedential, commnercial, industrial etc. c) now the categories have sub-categories. for example. a residential category will have sub category such as. Apartment / Independent House / Villa / Farm House/ Studio Apartment etc. and hence same way commercial and industrial or agricultural will too have sub-categories. d) each sub-categories will have to store the different values. like a resident will have features like Bedrooms/ kitchens / Hall / bathroom etc. the features depends on the sub categories. for an example on how i would want to implement my application you can have a look at this site. http://www.magicbricks.com/bricks/postProperty.html i could possibly think of the solution like this. a) create four to five tables depending upon the categories which will be existing(the problem is categories might increase in the future). b) create different tables for all the features, location, price, description and merge the common property table into one. for example all the property will have the common entity such as location, total area, etc. what would you advice for me given the current situation. thank you

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  • SQL Server slow in production environment

    - by Lieven Cardoen
    I have a weird problem in a customer's production environment. I can't give any details on the infrastructure, except that SQL server runs on a virtual server. The data, log and filestream file are on another storage server (data and filestream together and log on a separate server). In our local Test environment, there's one particular query that executes with these durations: first we clear the cache 300ms (First time it takes longer, but from then on it's cached.) 20ms 15ms 17ms In the customer's production environment, the SQL Server is more powerful, these are the durations (I didn't have the rights to clear the cache. Will try this tomorrow). 2500ms 2600ms 2400ms The servers in the customer's production environment are more powerful but they do have virtual servers (we don't). What could be the cause... Not enough memory? Fragmentation? Physical storage? How would you tackle this performance problem? EDIT: Some people have asked me if the data set is equal and it is. I restored their database on our environment. It's true that this was the first thing I looked at. (@Everyone: I added the edit because it will be the first thing that many will think off).

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  • Ruby on Rails undefined method `camelize' for "app":String

    - by Lukasz
    Hi! I just tried to play with Ruby on Rails on Snow Leopard. I was following this tutorial: http://developer.apple.com/tools/rubyonrails.html Whatever I try to do with rails I end up with: MacBook-Pro-lm:~ lukasz$ rails blog **undefined method `camelize' for "app":String** MacBook-Pro-lm:~ lukasz$ rails --help **undefined method `camelize' for "app":String** Really basic things... however - verbosing rails works: MacBook-Pro-lm:bin lukasz$ rails -v Rails 2.3.5 MacBook-Pro-lm:~ lukasz$ ruby -v ruby 1.8.7 (2010-01-10 patchlevel 249) [i686-darwin10] MacBook-Pro-lm:bin lukasz$ gem -v 1.3.7 So it seems I have installed and upgarded ruby (using macports), rubygems and rails successfully (according to terminal). There are also few other packages installed to support we development like passenger and mysql5, etc... I can find ruby installed in the /opt/local/bin directory. My environment PATH variable is: PATH=/opt/local/bin:/opt/local/sbin:/opt/local/bin:/opt/local/sbin:/usr/bin:/bin:/usr/sbin:/sbin:/usr/local/bin:/usr/X11/bin The is something fishy going on. It must be some stupid basic problem. Google says that there could be a problem with ruby-iconv library but I can not find/install this package using port or gem commands. Plese help.... what am I missing here?

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  • JSF: How to get the selected item from selectOneMenu if its rendering is dynamic?

    - by Dzmitry Zhaleznichenka
    At my view I have two menus that I want to make dependent, namely, if first menu holds values "render second menu" and "don't render second menu", I want second menu to be rendered only if user selects "render second menu" option in the first menu. After second menu renders at the same page as the first one, user has to select current item from it, fill another fields and submit the form to store values in database. Both the lists of options are static, they are obtained from the database once and stay the same. My problem is I always get null as a value of the selected item from second menu. How to get a proper value? The sample code of view that holds problematic elements is: <h:selectOneMenu id="renderSecond" value="#{Bean.renderSecondValue}" valueChangeListener="#{Bean.updateDependentMenus}" immediate="true" onchange="this.form.submit();" > <f:selectItems value="#{Bean.typesOfRendering}" /> </h:selectOneMenu><br /> <h:selectOneMenu id="iWillReturnYouZeroAnyway" value="#{Bean.currentItem}" rendered="#{Bean.rendered}" > <f:selectItems value="#{Bean.items}" /> </h:selectOneMenu><br /> <h:commandButton action="#{Bean.store}" value="#Store" /> However, if I remove "rendered" attribute from the second menu, everything works properly, except for displaying the menu for all the time that I try to prevent, so I suggest the problem is in behavior of dynamic rendering. The initial value of isRendered is false because the default item in first menu is "don't render second menu". When I change value in first menu and update isRendered with valueChangeListener, the second menu displays but it doesn't initialize currentItem while submitting. Some code from my backing bean is below: public void updateDependentMenus(ValueChangeEvent value) { String newValue = (String) value.getNewValue(); if ("render second menu" == newValue){ isRendered = true; } else { isRendered = false; } } public String store(){ System.out.println(currentItem); return "stored"; }

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