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  • How to create reference tables using fluent nhibernate

    - by Akk
    How can i create a 3 table schema from the following model classes. public class Product { public int Id {get; set;} public string Name {get; set;} public IList<Photo> Photos {get; set;} } public class Photo { public int Id {get; set;} public string Path {get; set;} } I want to create the following table structure in the database: Product ------- Id Name ProductPhotos ------------- ProductId (FK Products.Id) PhotoId (FK Photos.Id) Photos ------ Id Path How i can express the above Database Schema using Fluent NHibernate? I could only manage the following the Mapping but this does not get me the 3rd Photo ref table. public class ProductMap : ClassMap<Product> { public CityMap() { Id(x => x.Id); Map(x => x.Name); Table("Products"); HasMany(x => x.Photos).Table("ProductPhotos").KeyColumn("ProductId"); } }

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  • NHibernate not dropping foreign key constraints.

    - by Kendrick
    I'm new to NHibernate, so this is probably my mistake, but when I use: schema.Create(true, true); I get: SchemaExport [(null)]- There is already an object named 'XXX' in the database. System.Data.SqlClient.SqlException: There is already an object named 'XXX' in the database. I grabbed the SQL code nHibernate was using, ran it directly from MSSMS, and recieved similar errors. Looking into it, the generated code is not properly dropping the foreign key constraints. The drop looks like this: if exists (select 1 from sysobjects where id = OBJECT_ID(N'dbo[FK22212EAFBFE4C58]') AND parent_obj = OBJECT_ID('YYY')) alter table dbo.YYY drop constraint FK22212EAFBFE4C58 Doing a "select OBJECT_ID(N'dbo[FK22212EAFBFE4C58]')" I get null. If I take out the "dbo" (i.e. "select OBJECT_ID(N'[FK22212EAFBFE4C58]')") then the ID is returned. So, my question is, why is nHibernate adding the dbo, and why does that prevent the object from being returned (since the table owning the constraint is dbo.XXX) One of my mapping files: <?xml version="1.0" encoding="utf-8"?> <hibernate-mapping namespace="CanineApp.Model" assembly="CanineApp.Model" xmlns="urn:nhibernate-mapping-2.2"> <class name="MedicalLog" table="MedicalLog" schema="dbo"> <id name="MedicalLogID" type="Int64"> <generator class="identity" /> </id> <property name="InvoiceAmount" type="Decimal" not-null="true" /> ... <many-to-one name="Canine" class="Canine" column="CanineID" not-null="true" fetch="join" /> <many-to-one name="TreatmentCategory" class="TreatmentCategory" column="TreatmentCategoryID" not-null="true" access="field.camelcase-underscore" /> </class> </hibernate-mapping>

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  • Telling me my stored procedure isn't declared

    - by Scott
    Here is where the error is occuring in the stack: public static IKSList<DataParameter> Search(int categoryID, int departmentID, string title) { Database db = new Database(DatabaseConfig.CommonConnString, DatabaseConfig.CommonSchemaOwner, "pkg_data_params_new", "spdata_params_search"); db.AddParameter("category_id", categoryID); db.AddParameter("department_id", departmentID); db.AddParameter("title", title, title.Length); DataView temp = db.Execute_DataView(); IKSList<DataParameter> dps = new IKSList<DataParameter>(); foreach (DataRow dr in temp.Table.Rows) { DataParameter dp = new DataParameter(); dp.Load(dr); dps.Add(dp); } return dps; } And here is the error text: ORA-06550: line 1, column 38: PLS-00302: component 'SPDATA_PARAMS_SEARCH' must be declared ORA-06550: line 1, column 7: PL/SQL: Statement ignored Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.Data.OracleClient.OracleException: ORA-06550: line 1, column 38: PLS-00302: component 'SPDATA_PARAMS_SEARCH' must be declared ORA-06550: line 1, column 7: PL/SQL: Statement ignored Source Error: Line 161: db.AddParameter("title", title, title.Length); Line 162: Line 163: DataView temp = db.Execute_DataView(); Line 164: Line 165: IKSList dps = new IKSList(); My webconfig is pointing to the correct place and everything so idk where this is coming from.

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  • Need help with transferring data between MySQL db's using PHP

    - by JM4
    In one of the sites I manage, the client has decided to take on ACH/Bank Account administration where it was previously outsourced. As a result, the information submitted in our online form which used to simply store in a single database for processing now must sit in 'limbo' until the funds used for payment have been verified. My original plan is as follows: At the end of an enrollment, all form data is collected and stored in a single MySQL database. Our internal administrator will receive an email notification reminding him enrollments have taken place. He will process the ACH information collected and wait the 3-4 business days needed for payment to clear. Once the payment information has been returned as Good (haven't considered what I will do with the 'bad' yet), the administrator can log into a secure portal which allows him to click a button to 'process' the full information once compared and verified. the process is simplified as: Enrollment complete: data stored in DB 'A' Funds verified and link clicked: data from 'A' is copied to DB 'B' and 'A' is deleted. I have run similar processes with CSV output before and simply used //transfers old data to archive $transfer = mysql_query('INSERT INTO '.$archive.' SELECT * FROM '.$table) or die(mysql_error()); //empties existing table $query = mysql_query('TRUNCATE TABLE '.$table) or die(mysql_error()); but in those cases, ALL data returned was copied and deleted. I only want to copy and delete a single record. Any idea how to accomplish this?

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  • [PHP] MySql Proccesslist filled with "Sleep" Entries leading to "To many Connections" ?

    - by edorian
    Hi, i'd like to ask your help on a longstanding issue with php/mysql connections. Every time i execute a "SHOW PROCESSLIST" command it shows me about 400 idle (Status: Sleep) connections to the database Server emerging from our 5 Webservers. That never was much of a problem (and i didn't find a quick solution) until recently traffic numbers increased and since then MySql reports the "to many connections" Problems repeatedly, even so 350+ of those connections are in "sleep" state. Also a server can't get a mysql connection even if there are sleeping connection to that same server. All those connections vanish when a apache server is restated. The PHP Code used to create the Database connections uses the normal "mysql" Module, the "mysqli" Module, PEAR::DB and Zend Framework Db Adapter. (Different projects). NONE of the projects uses persistent connections. Raising the connection-limit is possible but doesn't seem like a good solution since it's 450 now and there are only 20-100 "real" connections at a time anyways. My question: Why are there so many connections in sleep state and how can i prevent that. Thank you for your time, if theres anything unclear or missing please let me know

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  • login/logout problem in PHP

    - by user356170
    i have a question. I have a website in which i am giving security like login id and password( as usual). No what i want is that, 1) I don't want to allow a single user to login in different machine at the same time. 2) For this i am using a column in database which is keeping the current status of user(i.e. loging/logout). I am allowing user to login only when has session has not closed and status is login. 3) So my problem is that when i am logging out manually. it is closing the session as well as updating the database with status "logout". 4) but when i am closing the window from Cross buttonat top right corner. it is closing the ssion but table data is still "login". so later on i can't be able to login into the same user. 5) So how could i solve this problem. Please help me!

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  • SQL query for the latest record for each day

    - by Mac
    I've got an Oracle 10g database with a table with a structure and content very similar to the following: CREATE TABLE MyTable ( id INTEGER PRIMARY KEY, otherData VARCHAR2(100), submitted DATE ); INSERT INTO MyTable VALUES (1, 'a', TO_DATE('28/04/2010 05:13', ''DD/MM/YYYY HH24:MI)); INSERT INTO MyTable VALUES (2, 'b', TO_DATE('28/04/2010 03:48', ''DD/MM/YYYY HH24:MI)); INSERT INTO MyTable VALUES (3, 'c', TO_DATE('29/04/2010 05:13', ''DD/MM/YYYY HH24:MI)); INSERT INTO MyTable VALUES (4, 'd', TO_DATE('29/04/2010 17:16', ''DD/MM/YYYY HH24:MI)); INSERT INTO MyTable VALUES (5, 'e', TO_DATE('29/04/2010 08:49', ''DD/MM/YYYY HH24:MI)); What I need to do is query the database for the latest record submitted on each given day. For example, with the above data I would expect the records with ID numbers 1 and 4 to be returned, as these are the latest each for 28 April and 29 April respectively. Unfortunately, I have little expertise as far as SQL is concerned. Could anybody possibly provide some insight as to how to achieve this? Thanks in advance!

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  • Generating a zend form with dynamic data?

    - by meder
    I need to access my session and based on the session property I need to grab stuff from the database to use as options in my dropdown. $_SESSION is: [sess_name] => Array( [properties] => Array( 1=> Hotel A, 2=> Hotel B ), [selected] => 1 ) I need to grab Hotel A from selected, and then access all accounts under Hotel A from the database: id title hotel_id ------------------------------ 1 Hotel A Twitter Account 1 2 Hotel B Facebook Account 2 3 Hotel A Facebook Account 1 I need ids 1 and 3 because my hotel_id is 1 in the context of: $this->addElement( 'select', 'account', array( 'multioptions' => $NEED_IT_HERE )); Here's my query / session grabbing code: $cs = new Zend_Session_Namespace( SESS_NAME ); $model = new Model_DbTable_Social; $s = " SELECT social_accounts.* FROM social_accounts LEFT JOIN social_media_outlets ON social_media_outlets.id = social_accounts.property WHERE social_accounts.property=".(int)$cs->selectedclient; I have this code in my form page, but I need to move it into my model now.

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  • The type or namespace name 'WebControls' could not be found (are you missing a using directive or an assembly reference?)

    - by user1467175
    I encountered this error: The type or namespace name 'WebControls' could not be found (are you missing a using directive or an assembly reference?) Source Error: Line 28: Login Login1 = (WebControls.Login)LoginView1.FindControl("Login1"); // here the error code Line 29: TextBox UserName = (TextBox)Login1.FindControl("UserName"); Line 30: TextBox FailureText = (TextBox)Login1.FindControl("FailureText"); I did some research and the solution was to add this into the source code: System.Web.UI.WebControls.Login but I have no idea where this code can be add into. At first I tried putting it as a namespace, but it was wrong. Anyone can tell me where should I place this code at?? EDIT protected void Login1_LoginError(object sender, System.EventArgs e) { //Login Login1 = (WebControls.Login).LoginView1.FindControl("Login1"); Login Login1 = (System.Web.UI.WebControls.Login)LoginView1.FindControl("Login1"); TextBox UserName = (TextBox)Login1.FindControl("UserName"); TextBox FailureText = (TextBox)Login1.FindControl("FailureText"); //There was a problem logging in the user //See if this user exists in the database MembershipUser userInfo = Membership.GetUser(UserName.Text); if (userInfo == null) { //The user entered an invalid username... FailureText.Text = "There is no user in the database with the username " + UserName.Text; } else { //See if the user is locked out or not approved if (!userInfo.IsApproved) { FailureText.Text = "When you created your account you were sent an email with steps to verify your account. You must follow these steps before you can log into the site."; } else if (userInfo.IsLockedOut) { FailureText.Text = "Your account has been locked out because of a maximum number of incorrect login attempts. You will NOT be able to login until you contact a site administrator and have your account unlocked."; } else { //The password was incorrect (don't show anything, the Login control already describes the problem) FailureText.Text = string.Empty; } } }

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  • Why is it possible to enumerate a LinqToSql query after calling Dispose() on the DataContext?

    - by DanM
    I'm using the Repository Pattern with some LinqToSql objects. My repository objects all implement IDisposable, and the Dispose() method does only thing--calls Dispose() on the DataContext. Whenever I use a repository, I wrap it in a using person, like this: public IEnumerable<Person> SelectPersons() { using (var repository = _repositorySource.GetNew<Person>(dc => dc.Person)) { return repository.GetAll(); } } This method returns an IEnumerable<Person>, so if my understanding is correct, no querying of the database actually takes place until Enumerable<Person> is traversed (e.g., by converting it to a list or array or by using it in a foreach loop), as in this example: var persons = gateway.SelectPersons(); // Dispose() is fired here var personViewModels = ( from b in persons select new PersonViewModel { Id = b.Id, Name = b.Name, Age = b.Age, OrdersCount = b.Order.Count() }).ToList(); // executes queries In this example, Dispose() gets called immediately after setting persons, which is an IEnumerable<Person>, and that's the only time it gets called. So, a couple questions: How does this work? How can a disposed DataContext still query the database for results when I walk the IEnumerable<Person>? What does Dispose() actually do? I've heard that it is not necessary (e.g., see this question) to dispose of a DataContext, but my impression was that it's not a bad idea. Is there any reason not to dispose of it?

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  • Adding linked table to Access 2003 while keeping ODBC connection info in MDB

    - by webworm
    I have an Access 2003 database MDB where all of the tables exist as linked tables within SQL Server 2005. The MDB file contains all of the ODBC information that points to the correct SQL Server and log-on credentials (trusted connection). What I would like to do is add a new linked table to the MDB file however I am not sure how to go about specifying the ODBC connection information. When I try to add a new linked table I keep getting prompted to locate or create a DSN file. I don't want to have to create a new DSN entry on every machine, rather I would like all that information stored within the Access MDB file itself. In the existing database I can "hover" over the table names and see the ODBC connection info as a tool-tip. All I need to do is add another linked table using the same connection information. I do have access to the SQL Server where the tables are linked to,. I have already created the new table I wanted to add. I just need to find a way to link to it.

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  • Pickled my dictionary from ZODB but i got a less in size one?

    - by Someone Someoneelse
    I use ZODB and i want to copy my 'database_1.fs' file to another 'database_2.fs', so I opened the root dictionary of that 'database_1.fs' and I (pickle.dump) it in a text file. Then I (pickle.load) it in a dictionary-variable, in the end I update the root dictionary of the other 'database_2.fs' with the dictionary-variable. It works, but I wonder why the size of the 'database_1.fs' not equal to the size of the other 'database_2.fs'. They are still copies of each other. def openstorage(store): #opens the database data={} data['file']=filestorage data['db']=DB(data['file']) data['conn']=data['db'].open() data['root']=data['conn'].root() return data def getroot(dicty): return dicty['root'] def closestorage(dicty): #close the database after Saving transaction.commit() dicty['file'].close() dicty['db'].close() dicty['conn'].close() transaction.get().abort() then that's what i do:- import pickle loc1='G:\\database_1.fs' op1=openstorage(loc1) root1=getroot(op1) loc2='G:database_2.fs' op2=openstorage(loc2) root2=getroot(op2) >>> len(root1) 215 >>> len(root2) 0 pickle.dump( root1, open( "save.txt", "wb" )) item=pickle.load( open( "save.txt", "rb" ) ) #now item is a dictionary root2.update(item) closestorage(op1) closestorage(op2) #after I open both of the databases #I get the same keys in both databases #But `database_2.fs` is smaller that `database_2.fs` in size I mean. >>> len(root2)==len(root1)==215 #they have the same keys True Note: (1) there are persistent dictionaries and lists in the original database_1.fs (2) both of them have the same length and the same indexes.

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  • Access to SQL Server 2005 from a non-domain machine using Windows authentication

    - by user304582
    Hi, I have a Windows domain within which a machine is running SQL Server 2005 and which is configured to support only Windows authentication. I would like to run a C# client application on a machine on the same network, but which is NOT on the domain, and access a database on the SQL Server 2005 instance. I thought that it would be a simple matter of doing something like this: string connectionString = "Data Source=server;Initial Catalog=database;User Id=domain\user;Password=password"; SqlConnection connection = new SqlConnection(connectionString); connection.Open(); However, this fails: the client-side error is: System.Data.SqlClient.SqlException: Login failed for user 'domain\user' and the server-side error is: Error 18456, Severity 14, State 5 I have tried various things including setting integrated security to true and false, and \ instead of \ in the User Id, but without success. In general, I know that it possible to connect to the SQL Server 2005 instance from a non-domain machine (for example, I am working with a Linux-based application which happily does this), but I don't seem to be able to work out how to do it from a Windows machine. Help would be appreciated! Thanks, Martin

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  • EF4 querying through the generations

    - by Hans Kesting
    I have a model withs Parents, Children and Grandchildren, in a many-to-many relationship. Using this article I created POCO classes that work fine, except for one thing I can't yet figure out. When I query the Parents or Children directly using LINQ, the SQL reflects the LINQ query (a .Count() executes a COUNT in the database and so on) - fine. The Parent class has a Children property, to access it's children. But (and now for the problem) this doesn't expose an IQueryable interface but an ICollection. So when I access the Children property on a particular parent all the Parent's Children are read. Even worse, when I access the Grandchildren (theParent.Children.SelectMany(child => child.GrandChildren).Count()) then for each and every child a separate request is issued to select it's grandchildren. Changing the type of the Children property from ICollection to IQueryable doesn't solve this. Apart from missing needed methods like Add() and Remove(), EF just doesn't recognize the property then. Are there correct ways (as in: low database interaction) of querying through children (and what are they)? Or is this just not possible?

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  • JPA 2.0 Provider Hibernate Spring MVC 3.0

    - by user558019
    Dear All i have very strange problem we are using jpa 2.0 with hibernate and spring 3.0 mvc annotations based Database generated through JPA DDL is true and MySQL as Database; i will provide some refference classes and then my porblem. public abstract class Common implements serializable{ @Id @GeneratedValue(strategy = GenerationType.AUTO) @Column(name = "id", updatable = false) private Long id; @ManyToOne @JoinColumn private Address address; //with all getter and setters //as well equal and hashCode } public class Parent extends Common{ private String name; @OneToMany(cascade = {CascadeType.MERGE,CascadeType.PERSIST}, mappedBy = "parent") private List<Child> child; //setters and rest of class } public class child extends Common{ //some properties with getter/setters } public class Address implements Serializable{ @Id @GeneratedValue(strategy = GenerationType.AUTO) @Column(name = "id", updatable = false) private Long id; private String street; //rest of class with get/setter } as in code you can see that parents and child classes extends Common class so both have address property and id , the problem occurs when change the address refference in parent class it reflect same change in all child objects in list and if change address refference in child class then on merge it will change address refference of parent as well i am not able to figure out is it is problem of jpa or hibernate or spring thanks in advance

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  • In sync query calls, one query causing other query to run slower. Why?

    - by Irchi
    Sorry for the long question, but I think this is an interesting situation and I couldn't find any explanations for it: I was involved in optimization of an application that performed a large number of sequential SELECT and INSERT statements on a single dedicated SQL Server database. The process needs to INSERT a large number of records into a table, but for each of them there should be some value mappings, which performed using SELECT statements on another table in the same database. For a specific execution, it took 90 minutes to run. I used a profiler (JProfiler - the application is Java-based) to determine how much time does each part of the application take. It yields that 60% of the time was spent on INSERT method calls, and almost 20% on SELECT calls (the rest distributed in other parts). After some trials, I came to this situation: I commented out the INSERT query that took 60% of the time. I was expecting for the total run time to be around 35 minutes, as I have removed 60% of the 90 minutes. But the whole process took the same 90 minutes (doing only SELECTs and nothing else), but each SELECT took longer this time! Everything was running sync, there were no async calls. And there was only one single thread of execution. SELECT and INSERT queries are very simple, and don't have anything special, and they are on different tables, but on the same DB. I tested with both the DB on the application machine, and on a remote network machine. I can't think of any explanation for this, as the Profiler (Application profiler, not SQL Profiler) reported the changes in the method call times, and by removing INSERT statements SELECT statements took longer to run. Can anyone give me some kind of explanation of what could have happened? (there can't be cache / query optimization stuff, because the queries were run in sync, and in a single thread, and it was far from affecting the cache this much) I should note that the bottleneck of the speed was in SQL server, using most of the CPU time.

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  • Zend_Dojo_Form not rendering in layout

    - by Grant Collins
    Hi, I have a quick question about adding Zend_Dojo_Form into Zend_layouts. I have a Zend_Dojo_Form that I want to display in the layout that is used for a particular controller. I can add the form to the layout without any issue however the dojo elements fail to render, as they would do if I added the form to a standard view. Is there any reason why this would be the case? Do I need to do something to the layout so that it will enable the components for this embedded form in the layout. Any other dojo enabled forms that are added in the view using this layout work fine. My form is created in the usual way: class QuickAddJobForm extends Zend_Dojo_Form{ public function init(){ $this->setName('quickaddjobfrm') ->setMethod('post') ->setAction('/addjob/start/); /*We now create the elements*/ $jobTitle = new Zend_Dojo_Form_Element_TextBox('jobtitle', array( 'trim' => true ) ); $jobTitle->setAttrib('style', 'width:200px;') ->addFilter('StripTags') ->removeDecorator('DtDdWrapper') ->removeDecorator('HtmlTag') ->removeDecorator('Label'); .... $this->addElements(array($jobTitle, ....)); In the controller I declare the layout and the form in the init function: public function init(){ $this->_helper->layout->setLayout('add-layout'); $form = new QuickAddJobForm(); $form->setDecorators(array(array('ViewScript', array('viewScript' => 'quickAddJobFormDecorator.phtml')))); $this->_helper->layout()->quickaddjob = $form; In my layout Where I want the form I have: echo $this->layout()->quickaddjob; Why would adding this form in the layout fail to render/add the Dojo elements? All that is currently being displayed are text boxes, rather than some of the other components such as ComboBoxes/FilteringSelects etc... Thanks in advance.

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  • Error "initializer element is not constant" when trying to initialize variable with const

    - by tomlogic
    I get an error on line 6 (initialize my_foo to foo_init) of the following program and I'm not sure I understand why. typedef struct foo_t { int a, b, c; } foo_t; const foo_t foo_init = { 1, 2, 3 }; foo_t my_foo = foo_init; int main() { return 0; } Keep in mind this is a simplified version of a larger, multi-file project I'm working on. The goal was to have a single constant in the object file, that multiple files could use to initialize a state structure. Since it's an embedded target with limited resources and the struct isn't that small, I don't want multiple copies of the source. I'd prefer not to use: #define foo_init { 1, 2, 3 } I'm also trying to write portable code, so I need a solution that's valid C89 or C99. Does this have to do with the ORGs in an object file? That initialized variables go into one ORG and are initialized by copying the contents of a second ORG? Maybe I'll just need to change my tactic, and have an initializing function do all of the copies at startup. Unless there are other ideas out there?

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  • [SOLVED]Django - Passing variables to template based on db

    - by George 'Griffin
    I am trying to add a feature to my app that would allow me to enable/disable the "Call Me" button based on whether or not I am at [home|the office]. I created a model in the database called setting, it looks like this: class setting(models.Model): key = models.CharField(max_length=200) value = models.CharField(max_length=200) Pretty simple. There is currently one row, available, the value of it is the string True. I want to be able to transparently pass variables to the templates like this: {% if available %} <!-- Display button --> {% else %} <!-- Display grayed out button --> {% endif %} Now, I could add logic to every view that would check the database, and pass the variable to the template, but I am trying to stay DRY. What is the best way to do this? UPDATE I created a context processor, and added it's path to the TEMPLATE_CONTEXT_PROCESSORS, but it is not being passed to the template def available(request): available = Setting.objects.get(key="available") if open.value == "True": return {"available":True} else: return {} UPDATE TWO If you are using the shortcut render_to_response, you need to pass an instance of RequestContext to the function. from the django documentation: If you're using Django's render_to_response() shortcut to populate a template with the contents of a dictionary, your template will be passed a Context instance by default (not a RequestContext). To use a RequestContext in your template rendering, pass an optional third argument to render_to_response(): a RequestContext instance. Your code might look like this: def some_view(request): # ... return render_to_response('my_template.html', my_data_dictionary, context_instance=RequestContext(request)) Many thanks for all the help!

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  • User clicks on Image, video starts playing

    - by cf_PhillipSenn
    I have an image, and I would like to make the image link to an embedded YouTube video, such that if the user clicks on the image, it starts playing in the place where the picture used to be. <div id="myvideo"> <a href="http://www.youtube.com/watch?v=Msef24JErmU&playnext_from=TL&videos=dgzKE_Lyv7o"> <img src="starryeyedsurprise.jpg"></a> </div> Something like what the above code does, except not just hyperlink to it. So I know I have to have javaScript replace what's in #myvideo with: <object width="425" height="344"><param name="movie" value="http://www.youtube.com/v/Msef24JErmU&hl=en_US&fs=1&rel=0&color1=0x2b405b&color2=0x6b8ab6"></param><param name="allowFullScreen" value="true"></param><param name="allowscriptaccess" value="always"></param><embed src="http://www.youtube.com/v/Msef24JErmU&hl=en_US&fs=1&rel=0&color1=0x2b405b&color2=0x6b8ab6" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="425" height="344"></embed></object> And then automatically start playing. I guess I don't need it to be a YouTube video per se, I could just host the video on my own site (it's so low volume that I don't have to worry about serving up a video every once in a while).

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  • PHP login, getting wrong count value from query / fetch array

    - by Chris
    Hello, *EDIT*Thanks to the comments below it has been figured out that the problem lies with the md5, without everything works as it should. But how do i implent the md5 then? I am having some troubles with the following code below to login. The database and register system are already working. The problem lies that it does not find any result at all in the query. IF the count is 0 it should redirect the user to a secured page. But this only works if i write count = 0, but this should be 0 , only if the user name and password is found he should be directed to the secure (startpage) of the site after login. For example root (username) root (password) already exists but i cannot seem to properly login with it. <?php session_start(); if (!empty($_POST["send"])) { $username = ($_POST["username"]); $password = (md5($_POST["password"])); $count = 0; $con = mysql_connect("localhost" , "root", ""); mysql_select_db("testdb", $con); $result = mysql_query("SELECT name, password FROM user WHERE name = '".$username."' AND password = '".$password."' ") or die("Error select statement"); $count = mysql_num_rows($result); if($count > 0) // always goes the to else, only works with >=0 but then the data is not found in the database, hence incorrect { $row = mysql_fetch_array($result); $_SESSION["username"] = $row["name"]; header("Location: StartPage.php"); } else { echo "Wrong login data, please try again"; } mysql_close($con); } ?>

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  • Difficulty Inserting from HTML form into MySQL (created in Workbench)

    - by Chaya Cooper
    I created a MySQL database in Workbench 5.2.35 for purposes of storing and using information submitted in html forms but I'm having difficulty inserting records from the html form. The relevant SQL script was saved as Demo2.sql, the schema is C2F, and the table is customer_info. I wasn't sure if that was the problem, so I tried replacing the database name (Demo2) with the schema name, but that didn't work either. My html file includes: form action="insert.php" method="post" The insert.php file states: ?php $con = mysql_connect("localhost","root","****"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("Demo2", $con); $sql="INSERT INTO customer_info(fname, lname, user, password, reminder, answer) VALUES ('$_POST[fname]','$_POST[lname]','$_POST[user]','$_POST[password]','$_POST[reminder]','$_POST[answer]')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "1 record added"; mysql_close($con) ? I've also tried INSERT INTO c2f.customer_info(fname, lname, etc. and INSERT INTO 'c2f'.'customer_info'

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  • TV Guide script - getting current date programmes to show

    - by whitstone86
    This is part of my TV guide script: //Connect to the database mysql_connect("localhost","root","PASSWORD"); //Select DB mysql_select_db("mytvguide"); //Select only results for today and future $result = mysql_query("SELECT programme, channel, episode, airdate, expiration, setreminder FROM mediumonair where airdate >= now()"); The episodes show up, so there are no issues there. However, it's getting the database to find data that's the issue. If I add a record for a programme that airs today this should show: Medium showing on TV4 8:30pm "Episode" Set Reminder Medium showing on TV4 May 18th - 6:25pm "Episode 2" Set Reminder Medium showing on TV4 May 18th - 10:25pm "Episode 3" Set Reminder Medium showing on TV4 May 19th - 7:30pm "Episode 3" Set Reminder Medium showing on TV4 May 20th - 1:25am "Episode 3" Set Reminder Medium showing on TV4 May 20th - 6:25pm "Episode 4" Set Reminder but this shows instead: Medium showing on TV4 May 18th - 6:25pm "Episode 2" Set Reminder Medium showing on TV4 May 18th - 10:25pm "Episode 3" Set Reminder Medium showing on TV4 May 19th - 7:30pm "Episode 3" Set Reminder Medium showing on TV4 May 20th - 1:25am "Episode 3" Set Reminder Medium showing on TV4 May 20th - 6:25pm "Episode 4" Set Reminder I almost have the SQL working; just not sure what the right code is here, to avoid the second mistake showing - as the record (which indicates a show currently airing) does not seem to work at present. Please can anyone help me with this? Thanks

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  • PHP foreach help

    - by sea_1987
    Hello I have an array that looks like this, Array ( [cfi_title] => Mr [cfi_firstname] => Firstname [cfi_surname] => Lastname [cfi_email] => [email protected] [cfi_subscribe_promotional] => [cfi_tnc] => [friendsName] => Array ( [0] => Firstname 1 [1] => Firstname 2 [2] => Firstname 3 ) [friendsEmail] => Array ( [0] => [email protected] [1] => [email protected] [2] => [email protected] ) [submit_form] => Submit ) My dilema is I need to save the values from the friendsName and friendsEmail arrays into a database, I know I can loop through them but how can I send the matching data, for example I need to save [friendsName][0] and friendsEmail][0] on the same row of database? I know I need to use a foreach but I just cannot figure out the logic.

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  • WPF Databinding With A Collection Object

    - by Randster
    Argh, although I've been googling, I really would appreciate it if someone could break my problem down as all the code examples online are confusing me more than assisting (perhaps it's just late)... I have a simple class as defined below: public class Person { int _id; string _name; public Person() { } public int ID { get { return _id; } set { _id = value; } } public string Name { get { return _name; } set { _name = value; } } } that is stored in a database, and thru a bit more code I put it into an ObservableCollection object to attempt to databind in WPF later on: public class People : ObservableCollection<Person> { public People() : base() { } public void Add(List<Person> pListOfPeople) { foreach (Person p in pListOfPeople) this.Add(p); } } In XAML, I have myself a ListView that I would like to populate a ListViewItem (consisting of a textblock) for each item in the "People" object as it gets updated from the database. I would also like that textblock to bind to the "Name" property of the Person object. I thought at first that I could do this: lstPeople.DataContext = objPeople; where lstPeople is my ListView control in my XAML, but that of course does nothing. I've found TONS of examples online where people through XAML create an object and then bind to it through their XAML; but not one where we bind to an instantiated object and re-draw accordingly. Could someone please give me a few pointers on: A) How to bind a ListView control to my instantiated "People" collection object? B) How might I apply a template to my ListView to format it for the objects in the collection? Even links to a decent example (not one operating on an object declared in XAML please) would be appreciated. Thanks for your time.

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