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  • windows vms unpredictibly require login

    - by marrrkus
    I have a cluster of vms on a number of cloned servers using libvirt/qemu. Occassionally the windows 7 vms randomly require a login screen, even though I've done everything I can think of and can google to turn off a login screen. I've used netplwiz to turn off requiring a password (http://pcsupport.about.com/od/windows7/ht/auto-logon-windows-7.htm) manually changed the regsistry using the instructions here: http://superuser.com/a/28654 changed requiring a password in the power saving settings in the control panel if the screen goes to sleep told the screen to never go to sleep (in the control panel) Even with all of these things, some of the vms *still* randomly require a login. I have no idea what else to try. Any ideas??

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  • Circumventing a manual HTML login page for "unclassified" websites

    - by auramo
    The IT department just made my life a little bit harder again: they introduced a manual HTML login page for all websites they have not "classified". This means that all the applications which try to access unclassified websites for e.g. downloading plugins do not work. Examples: Eclipse plugin installation, Maven builds etc. What would be the easiest workaround for this? The best I've come up with is try to extend/customize Ruby's httpproxy.rb that comes with Webrick. I would automate the manual login process whenever that login response page is detected. This sounds quite painful, and I think there might/should be simpler options?

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  • RDP locks up login, doesn't unlock on Windows

    - by private_meta
    From time to time, my system, when I try to login TRHOUGH or AFTER a remote connection, locks up the login session. I can't login anymore, the screen turns black (the monitor is still active, the image is black). Especially in the recent case, the system did not come back from the lock-up, and I had to reset the computer. Any idea what might be the issue here? More information: Both Computers are Windows 7, The RDP Server has a wired connection, the Client has either Wireless or Wired. The network card involved on the server is a "Realtek RTL8168C(P)/8111C(P) Family PCI-E Gigabit Ethernet NIC (NDIS 6.20)" card built-in on an ASRock Mainboard. I'm using either local LAN or internet connection through NAT/Router.

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  • Cannot login to fresh Kubuntu installation as admin, but only as guest

    - by Cedric Reichenbach
    I just installed a fresh Kubuntu 12.10 on a machine beside Windows 7. After successful installation, I rebooted and wanted to login. But when I type my password and hit Enter, some command line screen shows up for the split of a second and then it thows me back to the login screen without any error message. It's hard to spot what the command line text says, but I couldn't see any error or something like that. Anyway, when I log in as guest (without password), everything works finely. Also, when going to a system command line (using Ctrl+Alt+F1), I can login with my account without any problems. Does anyone have a clue what is going on and how to fix it?

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  • What are people using as Login scripts in large enterprises

    - by beakersoft
    Hi, We have recently been tasked with looking after the user login side of things in our enterprise (windows clients in active directory). We have a system at the moment that uses a vbscript login/loggof script to call a couple of DLL written in vb 6. The DLL's actions are controled by some config files based on users/groups witch is administrated from a central app. This is quite a good system, but kind of want to come away from vb6 for the dll's (maybe port them to c++ but them you have to make them com+ to call them from vbscripts etc) and possibly away from vbscript for the actual login scripts themselves. Just wondered what other people are using, what people can suggest etc Thanks Luke

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  • Mavericks: Safari does not login in into web services

    - by Roberto
    Since when I upgraded ML to Mavericks Safari is no longer able to log me into Facebook. When I go to the login page it suggests me the correct credentials, I hit the Login button, the page refreshes but nothing happens, like if the credentials where empty. Firefox works perfectly, I even logged out and back in to make sure the credentials are the same that Safari suggests, and so they are. Needless to say for a different user on the same Mavericks Safari logs in correctly. The same happens with most web pages that need a login, web mails for instances, I have tow accounts on different webmail providers and none of them works. Of course using the same mail services with POP3 works fine. Even on this very site I cannot post a thing with Safari, I'm going to switch to Firefox to be able to post this question. Again, Firefox or a different user are OK. Do you have any idea/suggestion?

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  • Circumventing a manual HTML login page for "unclassified" websites (automation purposes, credentials

    - by auramo
    The IT department just made my life a little bit harder again: they introduced a manual HTML login page for all websites they have not "classified". This means that all the applications which try to access unclassified websites for e.g. downloading plugins do not work. Examples: Eclipse plugin installation, Maven builds etc. What would be the easiest workaround for this? The best I've come up with is try to extend/customize Ruby's httpproxy.rb that comes with Webrick. I would automate the manual login process whenever that login response page is detected. This sounds quite painful, and I think there might/should be simpler options?

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  • Iterating through controls on a Windows Form

    - by icemanind
    I seem to have some weird issue going on that I am sure will turn out to be a simple thing. I have a Windows Form and on the form I have 1 panel called MainPanel and inside MainPanel, I got another panel with a button inside and a label that is inside MainPanel, but not in the second panel. 2 controls. What I am trying to do is copy all the controls inside MainPanel over to another panel object. I am using the following C# code to do this: GUIPanel gp = new GUIPanel(); foreach (System.Windows.Forms.Control ctrl in gp.Controls["MainPanel"].Controls) { m_OptionsControl.Controls.Add(ctrl); } When I run this code, it copies over the panel with the button, but not the label. What's even more odd is when I set a breakpoint and run it through the debugger, and I type "?gp.Controls["MainPanel"].Controls.Count" in the immediate window, it returns 2, just like it should. However, when stepping through the code, it only executes the foreach loop once. What am I missing here?

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  • How can I loop thru all controls (including ToolStripItems) C#

    - by Murray
    I need to save and restore settings for specific controls on a form. I loop thru all controls and return the one whose name matches the one I want, like so: private static Control GetControlByName(string name, Control.ControlCollection Controls) { Control thisControl = null; foreach (Control c in Controls) { if (c.Name == name) { thisControl = c; break; } if (c.Controls.Count > 0) { thisControl = GetControlByName(name, c.Controls); if (thisControl != null) { break; } } } return thisControl; } From this I can determine the type of control and therefore the property that should be / has been stored. This works well unless the control is one of the ToolStrip family which has been added to a toolstrip. e.g. this.toolStrip.Items.AddRange(new System.Windows.Forms.ToolStripItem[] { this.lblUsername, // ToolStripLabel this.toolStripSeparator1, this.cbxCompany}); // ToolStripComboBox In this case I can see the control I'm interested in (cbxCompany) when debugging, but the name property has no value so the code does not match to it. Any suggestions on how I can get to these controls too? Cheers, Murray

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  • Avoid concurrent login (logout former login session) in ASP.net membership

    - by Billy
    I am learning the ASP.net membership feature. I am wondering how I can implement so that later login session logout former login session to avoid concurrent login. I know how to check whether the user is online (by Membership.IsOnline()) and logout the current user (by FormsAuthentication.SignOut()). But I don't know how to logout the previous login session. Any code or reference that I can read?

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  • Windows XP long login (15 minutes +)

    - by Emily Pinkerton
    I'm having a lot of issues with our Windows XP SP3 machines (about 5, but every week another gets on the bandwagon of this issue). They take forever (15 minutes) to apply the user settings once our employee's enter their username and password to login to our domain. It only happens say if a user has reboot the machine and then when they go to log back in then it hangs forever. Reboot and restart are the key words for sure I've noticed with this issue. Here are things I have tested: •Made sure the DNS was set to point to our two servers (Server01 & Server02 are DNS Domain Controllers, 01 is primary and 02 backup). •No major changes have been applied to our network. •All profiles are local, so I have deleted out local profiles that aren't being used on those machines that run slow. •Also I have tried to enable and disable the Enable Fast Login under the local machines GP. It was not configured originally and when I tested both, it made the computer hang on "applying computer settings" for about 15 minutes. When it finally came up to the login screen the it was very quick to login to the domain. However this doesn't fix my issue, and even more frustrating upon setting it back to being not configured it now still takes for forever to apply computer settings. •I enabled the userenv log and here is what I see, but my experience is limited and I'm not sure how to read it exactly. (see below for log, this isn't the whole thing because it's really long) USERENV(2ec.2f0) 10:50:41:843 LoadUserProfile: LoadUserProfileP succeeded USERENV(2ec.2f0) 10:50:41:843 LoadUserProfile: Returning success. Final Information follows: USERENV(2ec.2f0) 10:50:41:843 lpProfileInfo-UserName = USERENV(2ec.2f0) 10:50:41:843 lpProfileInfo-lpProfilePath = < USERENV(2ec.2f0) 10:50:41:843 lpProfileInfo-dwFlags = 0x0 USERENV(2ec.2f0) 10:50:41:843 LoadUserProfile: Returning TRUE. hProfile = <0x818 USERENV(2ec.2f0) 10:50:41:984 IsSyncForegroundPolicyRefresh: Synchronous, Reason:NonCachedCredentials USERENV(2ec.248) 10:50:41:984 IsSyncForegroundPolicyRefresh: Synchronous, Reason:NonCachedCredentials USERENV(3c4.3dc) 10:51:26:166 LibMain: Process Name: C:\WINDOWS\system\wbem\wmiprvse.exe USERENV(2ec.5cc) 11:05:08:741 ProcessGPOs: network name is 192.168.49.0 USERENV(4a8.888) 11:05:08:804 GetProfileType: Profile already loaded. USERENV(4a8.888) 11:05:08:804 LoadProfileInfo: Failed to query central profile with error 2 USERENV(4a8.888) 11:05:08:804 GetProfileType: ProfileFlags is 0 Also this error is in the file quite a lot: USERENV(328.5bc) 11:05:29:733 GetUserDNSDomainName: Failed to impersonate user USERENV(328.834) 11:05:29:733 ImpersonateUser: Failed to impersonate user with 5. I'm really not sure what else to do with my limited experience, but I'm hoping someone can help me. I feel like I'm dealing with an issue way above my level and any knowledge I can gain out of getting this issue fixed would be amazing.

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  • Telnet disconnected on login failure

    - by LinuxPenseur
    Hi, I have two servers running Linux 2.6.9 kernel. When i telnet to server1 , the telnet will be disconnected only after 3 login failures. While, when i telnet to server2, telnet will be disconnected after the first login failure. I expect server2 to behave the same way as server1 when telnet is executed. Kindly tell me where i should tweak my servers so that i could achieve what i expect. Thanks, LinuxPenseur

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  • Login window language has changed after update on Snow Leopard

    - by Leonardo
    After the latest update (beginning of Dec. 2012) on Snow Leopard my login window language has changed. My system is set to be in english but the login windows now is in french. Currently I am in France so I suspect that during the update something has revealed my location and installed something in the locale of the current location. It doesn't seem fair to me, I want to switch it back to english but I couldn't find a way to do it.

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  • Can't login as root but I can SU while logged with another user

    - by Rhyuk
    What I was doing before this happened?: I was tinkering trying to setup X server so I can open an app's GUI remotely so I installed "X Window System", "xclock" and uncommented "# ForwardX11 yes" from my "/etc/ssh/ssh_config". (never got it working but thats a whole other question) Since that moment I'm not able to login as root from Putty (I get Access Denied). I can login as another user and I can "su" successfully so I know the password is right. How can have direct access with root again?

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  • mysql, how to log login attempts

    - by CarlosH
    From time to time there are failed login attempts in our mysql production server (mysql dashboard alert us). Is there a way to log every single success and failed login to mysql server without enabling the 'general_log'?. We thing general_log is not an option due it's a production server with high load.

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  • hardening a server: disallow password-login for sudoers and log unusual ips

    - by Fabian Zeindl
    Two question regarding sudo-login into an ubuntu-system (debian tips welcome as well): Is it possible to require sudoers on my box to only login with publickey-authentication? Is it possible to log which ip sudoers log in from and check that for "unusual activity" or take actions? I'm thinking about temporarily removing sudo-rights if sudoers don't log in from whitelisted IPs. Or is that too risky to be exploited?

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  • Force gdm login screen to the primary monitor

    - by JIa3ep
    I have two monitors attached to my video card. Primary monitor has a resolution equal to 1280x1024 and second has 1920x1200. My gdm login screen always appears on the second monitor even if it is switched off. My question is how to force gdm to show login screen always on primary monitor with resolution 1280x1024? I use Ubuntu 10.04.

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  • windows 2008 server login screen remote desktop

    - by Marki
    how can I access a GRAPHICAL login screen (like on earlier Windows versions, or like VNC) instead of the Username/Password prompt via RDP? I'm asking because we have several servers where we have no passwords but the shutdown/reboot option is given via group policy on the login screen. Thus, instead of having to go the hardware console I'd like to be able to perform reboot/shutdown actions via terminal services. Regards, Marki

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  • javax.security.auth.login.LoginException: Login failed

    - by abdeslam
    I'm trying to run a hadoop job (version 18.3) on my windows machine but I get the following error: Caused by: javax.security.auth.login.LoginException: Login failed: CreateProcess: bash -c groups error=2 at org.apache.hadoop.security.UnixUserGroupInformation.login(UnixUserGroupInformation.java:250) at org.apache.hadoop.security.UnixUserGroupInformation.login(UnixUserGroupInformation.java:275) at org.apache.hadoop.mapred.JobClient.configureCommandLineOptions(JobClient.java:557) ... 3 more The same job works fine in an another windows machine. Do I have may be something wrong in the settings variabls? How can I fix this problem?

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  • Is this PHP/MySQL login script secure?

    - by NightMICU
    Greetings, A site I designed was compromised today, working on damage control at the moment. Two user accounts, including the primary administrator, were accessed without authorization. Please take a look at the log-in script that was in use, any insight on security holes would be appreciated. I am not sure if this was an SQL injection or possibly breach on a computer that had been used to access this area in the past. Thanks <?php //Start session session_start(); //Include DB config require_once('config.php'); //Error message array $errmsg_arr = array(); $errflag = false; //Connect to mysql server $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } //Select database $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } //Function to sanitize values received from the form. Prevents SQL injection function clean($str) { $str = @trim($str); if(get_magic_quotes_gpc()) { $str = stripslashes($str); } return mysql_real_escape_string($str); } //Sanitize the POST values $login = clean($_POST['login']); $password = clean($_POST['password']); //Input Validations if($login == '') { $errmsg_arr[] = 'Login ID missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'Password missing'; $errflag = true; } //If there are input validations, redirect back to the login form if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; session_write_close(); header("location: http://tapp-essexvfd.org/admin/index.php"); exit(); } //Create query $qry="SELECT * FROM user_control WHERE username='$login' AND password='".md5($_POST['password'])."'"; $result=mysql_query($qry); //Check whether the query was successful or not if($result) { if(mysql_num_rows($result) == 1) { //Login Successful session_regenerate_id(); //Collect details about user and assign session details $member = mysql_fetch_assoc($result); $_SESSION['SESS_MEMBER_ID'] = $member['user_id']; $_SESSION['SESS_USERNAME'] = $member['username']; $_SESSION['SESS_FIRST_NAME'] = $member['name_f']; $_SESSION['SESS_LAST_NAME'] = $member['name_l']; $_SESSION['SESS_STATUS'] = $member['status']; $_SESSION['SESS_LEVEL'] = $member['level']; //Get Last Login $_SESSION['SESS_LAST_LOGIN'] = $member['lastLogin']; //Set Last Login info $qry = "UPDATE user_control SET lastLogin = DATE_ADD(NOW(), INTERVAL 1 HOUR) WHERE user_id = $member[user_id]"; $login = mysql_query($qry) or die(mysql_error()); session_write_close(); if ($member['level'] != "3" || $member['status'] == "Suspended") { header("location: http://members.tapp-essexvfd.org"); //CHANGE!!! } else { header("location: http://tapp-essexvfd.org/admin/admin_main.php"); } exit(); }else { //Login failed header("location: http://tapp-essexvfd.org/admin/index.php"); exit(); } }else { die("Query failed"); } ?>

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  • Cannot login to ISCSI Target - hangs after sending login details

    - by Frank
    I have an ISCSI target volume, to which i am trying to connect using CentOS Linux server. Everything works fine, but cannot its stuck at login. Here are the steps i am performing: [root@neon ~]# iscsiadm -m node -l iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session20 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session21 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session22 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session23 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session30 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session31 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session78 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session79 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session80 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session81 Logging in to [iface: eql.eth2, target: iqn.2001-05.com.equallogic:0-8a0906-ab4764e0b-55ed2ef5cf350a66-neon105, portal: 10.10.1.1,3260] (multiple) After this step, its stucks, waits for some time and then gives this output: Logging in to [iface: iface1, target: iqn.2001-05.com.equallogic:0-8a0906-ab4764e0b-55ed2ef5cf350a66-neon105, portal: 10.10.1.1,3260] (multiple) iscsiadm: Could not login to [iface: eql.eth2, target: iqn.2001-05.com.equallogic:0-8a0906-ab4764e0b-55ed2ef5cf350a66-neon105, portal: 10.10.1.1,3260]. My iscsi.conf is this: node.startup = automatic node.session.timeo.replacement_timeout = 15 # default 120; RedHat recommended node.conn[0].timeo.login_timeout = 15 node.conn[0].timeo.logout_timeout = 15 node.conn[0].timeo.noop_out_interval = 5 node.conn[0].timeo.noop_out_timeout = 5 node.session.err_timeo.abort_timeout = 15 node.session.err_timeo.lu_reset_timeout = 20 node.session.initial_login_retry_max = 8 # default 8; Dell recommended node.session.cmds_max = 1024 # default 128; Equallogic recommended node.session.queue_depth = 32 # default 32; Equallogic recommended node.session.iscsi.InitialR2T = No node.session.iscsi.ImmediateData = Yes node.session.iscsi.FirstBurstLength = 262144 node.session.iscsi.MaxBurstLength = 16776192 node.conn[0].iscsi.MaxRecvDataSegmentLength = 262144 discovery.sendtargets.iscsi.MaxRecvDataSegmentLength = 32768 node.conn[0].iscsi.HeaderDigest = None node.session.iscsi.FastAbort = Yes Also, in access control, i have given full access to Any IP, Any CHAP user and fixed iscsi initiator name. With same access level, all other volumes on rest of servers are working, except this one.

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  • Controls resize based on screen resolution

    - by user337173
    I have panel control. More controls are in panel.I set the dock property for panel as 'fill' .The panel are resized based on screen resolution. but the controls remains same.The controls in the panel are not resized based on screen solution. i have more labels and panels and text-boxs and button in the same page. How to set the dock property to resize all controls in page based on screen resolution? Thanks for any help

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  • Is QtQuick.Controls available on Ubuntu 13.10

    - by javascript is future
    I was looking to do UI development in QML, and I really want it to look native. I found the QtQuick.Controls (http://qt-project.org/doc/qt-5.1/qtquickcontrols/qtquickcontrols-index.html), but when I try make a simple application, it tells me that QtQuick.Controls isn't installed. main.qml: import QtQuick 2.1 import QtQuick.Controls 1.0 Rectangle { height: 200 width: 200 } terminal: $ qmlscene main.qml file:///tmp/main.qml:2 module "QtQuick.Controls" is not installed Also, I downloaded the source from https://qt.gitorious.org/qt/qtquickcontrols/source/stable, ran qmake && make, but this returned the following output: cd src/ && ( test -e Makefile || /usr/lib/i386-linux-gnu/qt5/bin/qmake /tmp/qtquickcontrols/src/src.pro -o Makefile ) && make -f Makefile make[1]: Går til katalog '/tmp/qtquickcontrols/src' cd controls/ && ( test -e Makefile || /usr/lib/i386-linux-gnu/qt5/bin/qmake /tmp/qtquickcontrols/src/controls/controls.pro -o Makefile ) && make -f Makefile make[2]: Går til katalog '/tmp/qtquickcontrols/src/controls' g++ -c -g -O2 -fstack-protector --param=ssp-buffer-size=4 -Wformat -Werror=format-security -D_FORTIFY_SOURCE=2 -O2 -fvisibility=hidden -fvisibility-inlines-hidden -std=c++0x -fno-exceptions -Wall -W -D_REENTRANT -fPIC -DQT_NO_XKB -DQT_NO_EXCEPTIONS -D_LARGEFILE64_SOURCE -D_LARGEFILE_SOURCE -DQT_NO_DEBUG -DQT_PLUGIN -DQT_QUICK_LIB -DQT_QML_LIB -DQT_WIDGETS_LIB -DQT_NETWORK_LIB -DQT_GUI_LIB -DQT_CORE_LIB -I/usr/share/qt5/mkspecs/linux-g++ -I. -I/usr/include/qt5 -I/usr/include/qt5/QtQuick -I/usr/include/qt5/QtQml -I/usr/include/qt5/QtWidgets -I/usr/include/qt5/QtNetwork -I/usr/include/qt5/QtGui -I/usr/include/qt5/QtGui/5.1.1 -I/usr/include/qt5/QtGui/5.1.1/QtGui -I/usr/include/qt5/QtCore -I/usr/include/qt5/QtCore/5.1.1 -I/usr/include/qt5/QtCore/5.1.1/QtCore -I.moc/release-shared -o .obj/release-shared/qquickaction.o qquickaction.cpp qquickaction.cpp:49:39: fatal error: private/qguiapplication_p.h: No such file or directory #include <private/qguiapplication_p.h> ^ Is there some PPA I could use, or do I have to wait for Trusty to get out, before I can use native controls from Qt? Regards

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  • How to wake from screensaver directly to the login screen in Ubuntu

    - by torbengb
    (a.k.a. How to switch users without entering password, part II) (see part I) I've got Ubuntu 9.10 with a user account for my wife, and one for myself. "Wake-from-screensaver" should result in "choose user" without having to enter any password. I know how to do that in Windows, but I'm not good with Linux (yet). Part of this was answered in my earlier question which helped me get past the login screen without passwords (after booting, and after choosing "switch user"), but once the screensaver kicks in and I wake it up again, the system does not present the "choose user" screen. Instead, it either turns off the screensaver and presents the desktop of the most recent user, or (if the screensaver is set to lock the screen) prompt for the user's password (which can be handily surpassed by clicking the "switch user" button and choosing the same user again). So, the login ("choose user") screen has been dealt with. How do I make the (any) screensaver return to the login screen at wake, rather than to the current user's desktop? Windows can do this, I'm sure Linux can too - but how?

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  • login form whith java/sqlite

    - by tuxou
    hi I would like to create a login form for my application with the possibility to add or remove users for an sqlite database, i have created the table users(nam, pass) but i can't unclud it in my login form, it someone could help me this is my login code: import java.awt.*; import java.awt.event.*; import javax.swing.*; public class login extends JFrame { // Variables declaration private JLabel jLabel1; private JLabel jLabel2; private JTextField jTextField1; private JPasswordField jPasswordField1; private JButton jButton1; private JPanel contentPane; // End of variables declaration public login() { super(); create(); this.setVisible(true); } private void create() { jLabel1 = new JLabel(); jLabel2 = new JLabel(); jTextField1 = new JTextField(); jPasswordField1 = new JPasswordField(); jButton1 = new JButton(); contentPane = (JPanel)this.getContentPane(); // // jLabel1 // jLabel1.setHorizontalAlignment(SwingConstants.LEFT); jLabel1.setForeground(new Color(0, 0, 255)); jLabel1.setText("username:"); // // jLabel2 // jLabel2.setHorizontalAlignment(SwingConstants.LEFT); jLabel2.setForeground(new Color(0, 0, 255)); jLabel2.setText("password:"); // // jTextField1 // jTextField1.setForeground(new Color(0, 0, 255)); jTextField1.setSelectedTextColor(new Color(0, 0, 255)); jTextField1.setToolTipText("Enter your username"); jTextField1.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent e) { jTextField1_actionPerformed(e); } }); // // jPasswordField1 // jPasswordField1.setForeground(new Color(0, 0, 255)); jPasswordField1.setToolTipText("Enter your password"); jPasswordField1.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent e) { jPasswordField1_actionPerformed(e); } }); // // jButton1 // jButton1.setBackground(new Color(204, 204, 204)); jButton1.setForeground(new Color(0, 0, 255)); jButton1.setText("Login"); jButton1.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent e) { jButton1_actionPerformed(e); } }); // // contentPane // contentPane.setLayout(null); contentPane.setBorder(BorderFactory.createEtchedBorder()); contentPane.setBackground(new Color(204, 204, 204)); addComponent(contentPane, jLabel1, 5,10,106,18); addComponent(contentPane, jLabel2, 5,47,97,18); addComponent(contentPane, jTextField1, 110,10,183,22); addComponent(contentPane, jPasswordField1, 110,45,183,22); addComponent(contentPane, jButton1, 150,75,83,28); // // login // this.setTitle("Login To Members Area"); this.setLocation(new Point(76, 182)); this.setSize(new Dimension(335, 141)); this.setDefaultCloseOperation(WindowConstants.EXIT_ON_CLOSE); this.setResizable(false); } /** Add Component Without a Layout Manager (Absolute Positioning) */ private void addComponent(Container container,Component c,int x,int y,int width,int height) { c.setBounds(x,y,width,height); container.add(c); } private void jTextField1_actionPerformed(ActionEvent e) { } private void jPasswordField1_actionPerformed(ActionEvent e) { } private void jButton1_actionPerformed(ActionEvent e) { System.out.println("\njButton1_actionPerformed(ActionEvent e) called."); String username = new String(jTextField1.getText()); String password = new String(jPasswordField1.getText()); if(username.equals("") || password.equals("")) // If password and username is empty Do this { jButton1.setEnabled(false); JLabel errorFields = new JLabel("You must enter a username and password to login."); JOptionPane.showMessageDialog(null,errorFields); jTextField1.setText(""); jPasswordField1.setText(""); jButton1.setEnabled(true); this.setVisible(true); } else { JLabel optionLabel = new JLabel("You entered "+username+" as your username. Is this correct?"); int confirm =JOptionPane.showConfirmDialog(null,optionLabel); switch(confirm){ // Switch Case case JOptionPane.YES_OPTION: // Attempt to Login user jButton1.setEnabled(false); // Set button enable to false to prevent 2 login attempts break; case JOptionPane.NO_OPTION: // No Case.(Go back. Set text to 0) jButton1.setEnabled(false); jTextField1.setText(""); jPasswordField1.setText(""); jButton1.setEnabled(true); break; case JOptionPane.CANCEL_OPTION: // Cancel Case.(Go back. Set text to 0) jButton1.setEnabled(false); jTextField1.setText(""); jPasswordField1.setText(""); jButton1.setEnabled(true); break; } // End Switch Case } } public static void main(String[] args) { JFrame.setDefaultLookAndFeelDecorated(true); JDialog.setDefaultLookAndFeelDecorated(true); try { UIManager.setLookAndFeel("com.sun.java.swing.plaf.windows.WindowsLookAndFeel"); } catch (Exception ex) { System.out.println("Failed loading L&F: "); System.out.println(ex); } new login(); }; }

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