Search Results

Search found 32302 results on 1293 pages for 'model view viewmodel'.

Page 81/1293 | < Previous Page | 77 78 79 80 81 82 83 84 85 86 87 88  | Next Page >

  • Visual View for Schema Based Editor

    - by Geertjan
    Starting from yesterday's blog entry, make the following change in the DataObject's constructor: registerEditor("text/x-sample+xml", true); I.e., the MultiDataObject.registerEditor method turns the editor into a multiview component. Now, again, within the DataObject, add the following, to register a source editor in the multiview component: @MultiViewElement.Registration(         displayName = "#LBL_Sample_Source",         mimeType = "text/x-sample+xml",         persistenceType = TopComponent.PERSISTENCE_NEVER,         preferredID = "ShipOrderSourceView",         position = 1000) @NbBundle.Messages({     "LBL_Sample_Source=Source" }) public static MultiViewElement createEditor(Lookup lkp){     return new MultiViewEditorElement(lkp); } Result: Next, let's create a visual editor in the multiview component. This could be within the same module as the above or within a completely separate module. That makes it possible for external contributors to provide modules with new editors in an existing multiview component: @MultiViewElement.Registration(displayName = "#LBL_Sample_Visual", mimeType = "text/x-sample+xml", persistenceType = TopComponent.PERSISTENCE_NEVER, preferredID = "VisualEditorComponent", position = 500) @NbBundle.Messages({ "LBL_Sample_Visual=Visual" }) public class VisualEditorComponent extends JPanel implements MultiViewElement {     public VisualEditorComponent() {         initComponents();     }     @Override     public String getName() {         return "VisualEditorComponent";     }     @Override     public JComponent getVisualRepresentation() {         return this;     }     @Override     public JComponent getToolbarRepresentation() {         return new JToolBar();     }     @Override     public Action[] getActions() {         return new Action[0];     }     @Override     public Lookup getLookup() {         return Lookup.EMPTY;     }     @Override     public void componentOpened() {     }     @Override     public void componentClosed() {     }     @Override     public void componentShowing() {     }     @Override     public void componentHidden() {     }     @Override     public void componentActivated() {     }     @Override     public void componentDeactivated() {     }     @Override     public UndoRedo getUndoRedo() {         return UndoRedo.NONE;     }     @Override     public void setMultiViewCallback(MultiViewElementCallback callback) {     }     @Override     public CloseOperationState canCloseElement() {         return CloseOperationState.STATE_OK;     } } Result: Next, the DataObject is automatically returned from the Lookup of DataObject. Therefore, you can go back to your visual editor, add a LookupListener, listen for DataObjects, parse the underlying XML file, and display values in GUI components within the visual editor.

    Read the article

  • Rails - Find Condition of two model fields

    - by ChrisWesAllen
    I'm trying to find the results of a model where it queries as the result of two conditions. I have a search tag that looks for Model.find(:all, :conditions => "name LIKE params[search]") but I'd like for the search to find all records where "name LIKE params[search] or description LIKE params[search] . Is there any way to add an OR into a condition in rails? or should I make an if statement?

    Read the article

  • Backbone: Easiest way to maintain reference to 'this' for a Model inside callbacks

    - by Garrett
    var JavascriptHelper = Backbone.Model.extend("JavascriptHelper", {}, // never initialized as an instance { myFn: function() { $('.selector').live('click', function() { this.anotherFn(); // FAIL! }); }, anotherFn: function() { alert('This is never called from myFn()'); } } ); The usual _.bindAll(this, ...) approach won't work here because I am never initializing this model as an instance. Any ideas? Thanks.

    Read the article

  • How to copy or clone model?

    - by Zeck
    I have a model Book with attributes id, name, price. I have an instance of Book: b1 = Book.new b1.name = "Blah" b1.price = 12.5 b1.save I would like to copy b1, create another instance of the Product model. I'm tryid p1=b1.clone then p1.save but it didn't work. Any idea? And my environment is: Netbeans 6.9 RC2 JRuby 1.5.0 Thanks

    Read the article

  • Child control view model event

    - by Jmsparing
    Hi, I seem to have got stuck in a situation where I have a parent and child usercontrol. I want to be able to raise an event in the child and have the parent handle this event. How do I trigger the event in my child view model and handle it in the parent view model. If anybody has a simple example that would be really good. Thanks very much.

    Read the article

  • Automark model names/attributes for translation

    - by Saosin
    Is there any way one could automatically mark all model names and attributes for translation, without specifying verbose_name/_plural on each one of them? Doesn't feel very DRY to do this every time: class Profile(models.Model): length = models.IntegerField(_('length')) weight = models.IntegerField(_('weight')) favorite_movies = models.CharField(_('favorite movies'), max_length=100) favorite_quote = models.CharField(_('favorite quote'), max_length=30) religious_views = models.CharField(_('religious views'), max_length=30) political_views = models.CharField(_('political views'), max_length=30) class Meta: verbose_name = _('profile') verbose_name_plural = _('profiles')

    Read the article

  • Retractable button bar using animations

    - by AndroidDev
    I want to create a button bar that is retractable: when the user clicks on a special "handle" button, the button bar should slide out of view partially so only the handle remains visible. When the bar is in retracted state only the handle is visible. Clicking on the handle should "slide out" the button bar so it is completely visible again. Ideally, the bar would start out in retracted state. I have tried some approaches using TranslateAnimation, including using a layout animation or calling "View.startAnimation" when the handle is clicked, but no luck so far. Do you guys have any tips how to approach this? Is there any decent documentation out there regarding Android animations? The documentation I find is sketchy at best. For instance, I found examples that cause a view to slide into view automatically using TranslateAnimation and a LayoutAnimationController when calling "addView", but when I call removeView no animation seems to be triggered at all, even if I set an animation that should create the opposite motion.

    Read the article

  • Android Dev: The constructor Intent(new View.OnClickListener(){}, Class<DrinksTwitter>) is undefined

    - by Malcolm Woods Spark
    package com.android.drinksonme; import android.app.Activity; import android.content.Intent; import android.os.Bundle; import android.view.View; import android.view.View.OnClickListener; import android.widget.Button; import android.widget.EditText; import android.widget.TextView; public class Screen2 extends Activity { // Declare our Views, so we can access them later private EditText etUsername; private EditText etPassword; private Button btnLogin; private Button btnSignUp; private TextView lblResult; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); // Get the EditText and Button References etUsername = (EditText)findViewById(R.id.username); etPassword = (EditText)findViewById(R.id.password); btnLogin = (Button)findViewById(R.id.login_button); btnSignUp = (Button)findViewById(R.id.signup_button); lblResult = (TextView)findViewById(R.id.result); // Set Click Listener btnLogin.setOnClickListener(new OnClickListener() { @Override public void onClick(View v) { // Check Login String username = etUsername.getText().toString(); String password = etPassword.getText().toString(); if(username.equals("test") && password.equals("test")){ final Intent i = new Intent(this, DrinksTwitter.class); //error on this line startActivity(i); // lblResult.setText("Login successful."); } else { lblResult.setText("Invalid username or password."); } } }); final Intent k = new Intent(Screen2.this, SignUp.class); btnSignUp.setOnClickListener(new OnClickListener() { public void onClick(View v) { startActivity(k); } }); } }

    Read the article

  • DRY way of calling a method in every rails model

    - by Tim
    Along the same lines as this question, I want to call acts_as_reportable inside every model so I can do one-off manual reports in the console in my dev environment (with a dump of the production data). What's the best way to do this? Putting acts_as_reportable if ENV['RAILS_ENV'] == "development" in every model is getting tedious and isn't very DRY at all. Everyone says monkey patching is the devil, but a mixin seems overkill. Thanks!

    Read the article

  • Need advice with a model - should I choose has_many through

    - by Martin Petrov
    I have something like a blog with posts and tags. I want to add email notification functionality - users can subscribe to one or more tags and receive email notifications when new posts are added. Currently I have a Tag model. There will be a Subscriber model (containing the user's email) Do you think I also need a Subscription table where Subscriber and Tag are joined? .. or I can skip it and directly link Subscriber with Tag?

    Read the article

  • A marketing view of SQLBits

    - by simonsabin
    One of the most enjoyable things about SQLBits is reading all the blog posts/reviews after the event. We are normally fortunate enough not to have pissed anyone off and so the posts are generally positive. Most pieces are from attendees however this piece is from a wife of a sponsor http://iknowmarketing.wordpress.com/2012/04/02/events-community-vs-commercial/ . Its a nice piece for us as it highlights how we work and that how we focus on making the event personal for all those involved. We deal...(read more)

    Read the article

  • Class name to view path

    - by Alexey Poimtsev
    Hi, I have a RoR application and model SomeModel. I have views for this model and I want to know - is there any method to get the view's path? Of course I can use for this model instance m = SomeModel.new v = m.class.class_name.pluralize.downcase It's working, but maybe you know a better way? :)

    Read the article

  • Create DB in Sql Server based on Visio Data Model

    - by Yaakov Ellis
    I have created a database model in Visio Professional (2003). I know that the Enterprise version has the ability to create a DB in Sql Server based on the data in Visio. I do not have the option to install Enterprise. Aside from going through the entire thing one table and relationship at a time and creating the whole database from scratch, by hand, can anyone recommend any tool/utility/method for converting the visio database model into a Sql Script that can be used to create a new DB in Sql Server?

    Read the article

  • Assigning Object to View, big MySQL resultset.

    - by A Finn
    Hello (Sorry for my bad English) Is it bad practice to assign object to view and call its methods in there? I use smarty as my template engine. In my controller I could do like this 1# $this->view->assign("name", $this->model->getName); and in my view <p>{$name}</p> OR 2# $this->view->assign("Object", $this->model); and in my view <p>{$Report->getName()}</p> Well my biggest problem is that I have to handle a big amount of data coming out from the MySQL and I thought that if I would made a method that would print out the data while looping mysql_fetch_row. Well at least I know that using html-tags in the model is a bad thing to do. So I would assign the object to the view to get the result to the right position on the page.. Reading a mysql-result to an array first may cause memory problems am I right? So what is the solution doing things MVC style.. And yes Im using a framework of my own.

    Read the article

  • Bind Child table data on View field- MVC ASP.Net

    - by Tassadaque
    I have two tables Contact and Addresses. Addresses is the child table of Contact. When i create view for Contact. i also want to get addresses for user as many as user wants. For contact table i bind the textbox and add validation like this <%= Html.TextBoxFor(model => model.ContactName) %> <%= Html.ValidationMessageFor(model => model.ContactName) %> Now my question is that how can i bind address field on create view screen. Regards Tassadaque

    Read the article

  • Transforming OLTP Relational Database to Data Warehousing Model

    - by Russ Cam
    What are the common design approaches taken in loading data from a typical Entity-Relationship OLTP database model into a Kimball star schema Data Warehouse/Marts model? Do you use a staging area to perform the transformation and then load into the warehouse? How do you link data between the warehouse and the OLTP database? Where/How do you manage the transformation process - in the database as sprocs, dts/ssis packages, or SQL from application code?

    Read the article

  • How to define schema for an ActiveRecord model?

    - by Eric Stanton
    I can find how to define columns only when doing migrations. However i do not need to migrate my model. I want to work with it "virtually". Does AR read columns data only from db? Any way to define columns like in DataMapper? class Post include DataMapper::Resource property :id, Serial property :title, String property :published, Boolean end Now i can play with my model without migrations/connections.

    Read the article

  • Rails saving data to model that has multiple has_many

    - by Ajey
    So I have a product model that looks like belongs_to :seller has_many :coupons And coupon model that looks like belongs_to :seller belongs_to :product And in my Products controller I use @seller = current_user @coupon = @seller.coupons.create(params[:coupon]) to create the coupons for the seller While the coupon is being created, I need to associate it with the product too, i.e When a new coupon is created it should be saved for the seller AS WELL AS for the product.

    Read the article

  • Defining EditText imeOptions when using InputMethodManager.showSoftInput(View, int, ResultReceiver)

    - by TuomasR
    In my application I have a custom view which requires some text input. As the view in itself doesn't contain any actual views (it's a Surface with custom drawing being done), I have a FrameLayout which contains the custom view and underneath it an EditText -view. When the user does a specific action, the custom view is hidden and the EditText takes over for user input. This works fine, but android:imeOptions seem to be ignored for this view. I'm currently doing this: InputMethodManager inputMethodManager = (InputMethodManager)parent.getSystemService(Context.INPUT_METHOD_SERVICE); EditText t = (EditText)parent.findViewById(R.id.DummyEditor); t.setImeOptions(EditorInfo.IME_ACTION_DONE); inputMethodManager.showSoftInput(t, 0, new ResultReceiver(mHandler) { @Override protected void onReceiveResult( int resultCode, Bundle resultData) { // We're done System.out.println("Editing done : " + ((EditText)parent.findViewById(R.id.DummyEditor)).getText()); } } ); It seems that the setImeOptions(EditorInfo.IME_ACTION_DONE) has no effect. I've also tried adding the option to the layout XML with android:imeOptions="actionDone". No help. Any ideas?

    Read the article

< Previous Page | 77 78 79 80 81 82 83 84 85 86 87 88  | Next Page >