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  • casting unused return values to void

    - by markh44
    int fn(); void whatever() { (void) fn(); } Is there any reason for casting an unused return value to void, or am I right in thinking it's a complete waste of time? Follow up: Well that seems pretty comprehensive. I suppose it's better than commenting an unused return value since self documenting code is better than comments. Personally, I'll turn these warnings off since it's unnecessary noise. I'll eat my words if a bug escapes because of it...

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  • UIView animation along a round path?

    - by david
    I need to make my little guy (in a UIIamgeView) jump forward and it has to look natural. I want to know is there a way to do it with CoreAnimation (beginAnimation/commitAnimation)? I could do it by setting a point in between in the air but the movement looks not natural :P

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  • File uploading in asp.net permission error (Access denied to path x)

    - by Arash
    I'm trying to upload some image files in my asp.net web app. Server OS: Windows server 2003 and IIS 6 I granted write permission in IIS to root and destination folder and granted FullControl Access to this users IUSer_Mashinname, Asp.net user, network services,Everyone, and all other users to the web app root folder and upload destination folder, but there is "Access denied problem".

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  • Wordpress + VMware CSS path problem

    - by Stephen Meehan
    I posted a similar question earlier today but this question is clearer. I want to locally develop my Wordpress websites (on my Mac) and test them in Internet Explorer (6,7,8) on Windows XP. I can get the MAMP welcome screen to show in Windows XP, so I know VMWare is doing it's thing. The local URL for my site (on my Mac) is: URL (http://d3creative:8888/) But the local URL under VMware/Internet Explorer is: URL (http://192.168.2.1:8888/d3creative/) This is the only way I can get it to show up, problem is all the CSS styles are referencing the local Mac URL (http://d3creative:8888/) So understandably the CSS isn't showing up. Is there a way to tell Windows that "http://192.168.2.1:8888/d3creative/" should equal "http://d3creative:8888/" I've tried editing the "hosts" file within in Windows XP and I've rebooted after making any changes, but nothing is working. My software: MAMP Pro (v1.8.2) Wordpress (v2.8.6) Windows XP (SP3) Internet Explorer (6, 7, 8) Any help would be much appreciated. Stephen Meehan

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  • php file path of server

    - by Jacksta
    I am trying to get this script to work. it opens up a directry and lists the files in the directory. I have copied this code from somewhere else and the problem is that this php file is hosted on an apache server not my localhost. what is the correct $dir_name = "c:/"; to use? The file is in this directory /domains/domainxxxx.com.au/public_html/lsitfiles.php so would I use domainxxxx.com.au/public_html/lsitfiles.php ? <?php $dir_name = "c:/"; $dir = opendir($dir_name); $file_list = "<ul>"; while ($file_name = readdir($dir)) { if(($file_name != ".") && (file_name != "..")) { $file_list .= "<li>$file_name"; } } $file_list.= "<ul>"; closedir($dir); ?> <HTML> <BODY> <p>Files in: <? echo "$dir_name"; ?></p> <? echo "$file_list"; ?> </BODY> </HTML>

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  • Problem with return 2 libc method

    - by jth
    Hi, I'am trying to understand the return2libc method. I'am using an ubuntu linux 9.10, 32 bit with ASLR disabled. In theory, it sounds quite easy, overwrite the saved eip with the address of system() (or whatever function you want), then put the address to which system() should return and after that, the parameter for system, the "/bin/bash"-string. But what happens is that my exploit keeps segfaulting the vulnerable program. I assume something with the system()-address went wrong. This is what I did so far: Determined the address of system(): (gdb) print system $1 = {<text variable, no debug info>} 0x167020 <system> (gdb) x/x system 0x167020 <system>: 0x890cec83 I used the subsequent x/x system because those 3 bytes returned by print system looks like an index in some sort of jumptable (PLT?), so I assume 0x890cec83 is the right address which is used to overwrite the saved eip. After that I determined the address of the /bin/bash string in memory, using a small C program which basically consists of this line: printf("Address of string /bin/bash: %p\n", getenv("SHELL")); Then I looked a little bit around in the memory and fount /bin/bash: (gdb) x/s 0xbffff6ca 0xbffff6ca: "/bin/bash" After I gathered this information, I filled the buffer: (gdb) b 9 Breakpoint 1 at 0x8048407: file victim.c, line 9. (gdb) r `perl -e 'print "A"x9 . "\x83\xec\x0c\x89FAKE\xca\f6\ff\bf";'` Breakpoint 1, main (argc=1111638594, argv=0xc360cca) at victim.c:10 10 return 0; (gdb) x/s 0xbffff6ca 0xbffff6ca: "/bin/bash" Stack frame looks like this: (gdb) i f Stack level 0, frame at 0xbffff440: eip = 0x8048407 in main (victim.c:10); saved eip 0x890cec83 source language c. Arglist at 0xbffff438, args: argc=1111638594, argv=0xc360cca Locals at 0xbffff438, Previous frame's sp is 0xbffff440 Saved registers: ebp at 0xbffff438, eip at 0xbffff43c This seems all right to me, saved eip was overwritten with the (hopefully) correct system()-address, return address for system was set to "FAKE" (shouldn't matter) and the address of /bin/bash also seems to be correct. When I'am continuing the execution, victim segfaults on some strange address and certainly not in 0x890cec83: (gdb) cont Continuing. Program received signal SIGSEGV, Segmentation fault. 0x0804840d in main (argc=Cannot access memory at address 0x41414149 ) at victim.c:11 11 } Has anyone an explanation or a hint what happens here and why the execution isn't redirected to 0x890cec83? Thanks in advance, any hint, and be it only vague, would be appreciated. I have no idea why this doesn't work.

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  • Windows path in python

    - by Gareth
    Hi all. What is the best way to represent a windows directory, for example "C:\meshes\as"? I have been trying to modify a script but it never works because I can't seem to get the directory right, I assume because of the '\' acting as escape character? Thanks, Gareth

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  • Calculating co-ordinate of a point on a path given a distance

    - by Alex
    I'm working on a project that surveys the condition of a road or highway using a calibrated trip computer connected to a rugged-PC. An operator keys in defect codes as they travel along a pre-defined route. I need to show an indicator on the map screen that shows the vehicles current position, taking into account the distance data from the trip computer. I know the exact lat lon co-ordinates at the starting point of each section of road, and the road is made up of a series of points. The question is: how can I calculate the lat lon co-ordinates of the vehicle assuming that it has continued on the route and traveled a certain distance (e.g. 1.4km). The co-ordinates would be 'locked onto' the road line, as shown in blue on the diagram below. Thanks, Alex

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  • changing default my.cnf path in mysql

    - by user377941
    I am having two mysql instances on same machine. The installations are on /usr/loca/mysql1 and /usr/local/mysql2. I m having separate my.cnf files located in /etc/mysql1 and /etc/mysql2. I installed the first instance of my sql using source distribution and with the --prefix=/usr/local/mysql1 option. The second one i got from copying and pastinf the same directory to /usr/local/mysql2. When i start the mysql daemon on /usr.local/mysql/libexec it reads the my.cnf file in /etc/mysql1. And if i start the mysql daemon in /usr/local/mysql2 it reads the same my.cnf file. I have separate port numbers and .sock files defined in the .cnf file in those 2 locations. I can read the my.cnf file in the second location by using --defaults-file=/etc/mysql2/my.cnf option on mysqld startup. I dnt need to enter this each and every time i start the daemon. If i am going to have more instances how can i point the correct my.cnf file to read to each and every mysql daemon. What is the retionale behind mysqld links with the my.cnf file. how can i predefine the location of my.cnf file for each instance.

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  • Building path independent mod_rewrite statements for generic .htaccess file

    - by Pekka
    Say I have three small web applications stored under a shared web root: www.example.com/app1/ www.example.com/app2/ www.example.com/app3/ www.example.com/app4/ each application has a .htaccess file containing some run-off-the-mill mod_rewrite statements to rewrite urls like RewriteCond %{REQUEST_URI} ^/app1/([^/]+)/([^/]+)\.html$ RewriteRule .* /app1/index.php?selectedProfile=%1&match=%2&%{QUERY_STRING} now, I would like to have a generic .htaccess file in each /app{n} directory. So, no RewriteBase and no /app{n} prefix in the RewriteConds. One idea I had was making the first level a wildcard directory as well: RewriteCond %{REQUEST_URI} ^/([^/]+)/([^/]+)/([^/]+)\.html$ seeing as the .htaccess file gets triggered only when the /app{n} directory is entered, this should work. Is this an acceptable solution? Are there other, better ones?

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  • Java (or possibly other languages) learning path

    - by bgo
    I am familiar (as a self-learner) with C, python and php such that i can solve some problems involving simple steps (for example, i easily do calculations for physics lab reports with python which normally would take 4x-5x times longer with a calculator). The point here is, as doing such things, i learnt the idea / concepts of programming language and problem solving along with oop or fuctional programming etc. Recently i have started Java and, with the familiarity of other languages, i am doing well for starters but i need guidence. -I am thinking of learning syntax from sun java tutorials and then practicing with codingbat.com or similar sites. I need a reference book that i can study deeper aspects of the topics i am learning. What do you suggest about these? -The problem is (and always have been) the lack of practice. I need coding and problem-solving practices sources. I stuck at the point where i can't figure out what to do next. Can you suggest any source (possibly like codingbat)? If i could plan a learning trail, i can progress faster and efficiently. So i need ideas, comments, suggestions. Thanks in advance.

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  • Suggest books/learning path for writing smartphone apps

    - by chibineku
    I have been writing a lot of HTML, CSS, PHP, MySQL and JavaScript lately working on a website, and I would like to move on to 'proper' OOP with an eye to making smartphone apps. I would like to at least cover iPhone and BlackBerry, which means learning Objective C, Cocoa and Java, before learning the specifics of interacting with the devices themselves, such as native bluetooth/GPS/internet API/methods. I would appreciate pointers to books or resources that will get me from a procedural web developer to object oriented app-maker. Most of the reviews of books on Objective C and Java have been mixed. I am about to start working my way through Beginning Java Objects (APress) which I have borrowed from my brother, so even if it's not a good intro at least it was free!

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  • How to define custom path to Interop *.dll

    - by NoviceAndNovice
    Well, I have an ActiveX (*.ocx) component, and i use it in a managed C++/CLI project: write a managed wrapper around ActiveX component[ NET has a great Interop services : provides me genarated dll so i can easily use it in my managed code] The problem is that Visual Studio (2008) automatically copy the generated Interop *.dll to the directory where my *.exe file stay.But i want put all my genarated Interop *.dll to a folder ... Suppose My directory structure is so: D:\MyProject\Output\MyProject.exe //My mamanged exe D:\MyProject\Output\Interop.XXXLib.1.0.dll // *Interop .dll I want to put Interop.XXXLib.1.0.dll into new folder D:\MyProject\Output\Interops and use it from that directory...How Can i do it? Best Wishes PS: What I found so far was using using codeBase/ probing tags in my app.config file such as <?xml version="1.0"?> <configuration> <runtime> <assemblyBinding xmlns="urn:schemas-microsoft-com.asm.v1"> <probing privatePath="Interops" /> </assemblyBinding> </runtime> </configuration> But i did not work in C++/CLI

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  • PostgreSQL - best way to return an array of key-value pairs

    - by Matt W
    I'm trying to select a number of fields, one of which needs to be an array with each element of the array containing two values. Each array item needs to contain a name (character varying) and an ID (numeric). I know how to return an array of single values (using the ARRAY keyword) but I'm unsure of how to return an array of an object which in itself contains two values. The query is something like SELECT t.field1, t.field2, ARRAY(--with each element containing two values i.e. {'TheName', 1 }) FROM MyTable t I read that one way to do this is by selecting the values into a type and then creating an array of that type. Problem is, the rest of the function is already returning a type (which means I would then have nested types - is that OK? If so, how would you read this data back in application code - i.e. with a .Net data provider like NPGSQL?) Any help is much appreciated.

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  • adding '' around a path

    - by sushant
    hi, its a very basic question, i dunno why i am not able to configure it out. lets say this is the code: a="xyz" g="abcd " & a so now the value of g = abcd xyz i want quotes around xyz i.e g should be abcd "xyz" how to do it?

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  • How to return 'null' instead of 'undefined' from select element

    - by MrW
    How can I return null instead of a 'undefined' from a select element. Basically I have 4 selects at the moment, but only the first one is populated with data at this point, but I want to grab the value from all of them when working with them. <select class="changeValue" id="drpOne"></select> <option id=1>1</option> <option id=2>2</option> <option id=3>3</option> <select class="changeValue" id="drpTwo"></select> JQuery: $('.changeValue').change(function() { var data = {}; data["Id1"] = $('#drpOne:selected').attr("id"); data["Id2"] = $('#drpTwo:selected').attr("id"); In this case, drpTwo will return 'undefined'. Is there anyway to get a null instead?

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  • upload picture to and send path to database

    - by opa.mido
    I am trying to upload picture and link it to my database and I used the codes below : Upload2.php <?php // Check if a file has been uploaded if(isset($_FILES['uploaded_file'])) { // Make sure the file was sent without errors if($_FILES['uploaded_file']['error'] == 0) { // Connect to the database $dbLink = new mysqli('localhost', 'root', '1234', 'fyp'); if(mysqli_connect_errno()) { die("MySQL connection failed: ". mysqli_connect_error()); } // Gather all required data $name = $dbLink->real_escape_string($_FILES['uploaded_file']['name']); $mime = $dbLink->real_escape_string($_FILES['uploaded_file']['type']); $data = $dbLink->real_escape_string(file_get_contents($_FILES ['uploaded_file']['tmp_name'])); $size = intval($_FILES['uploaded_file']['size']); // Create the SQL query $query = " INSERT INTO `pic` ( `Name`, `size`, `data`, `created` ) VALUES ( '{$name}', '{$mime}', {$size}, '{$data}', NOW() )"; // Execute the query $result = $dbLink->query($query); // Check if it was successfull if($result) { echo 'Success! Your file was successfully added!'; } else { echo 'Error! Failed to insert the file' . "<pre>{$dbLink->error}</pre>"; } } else { echo 'An error accured while the file was being uploaded. ' . 'Error code: '. intval($_FILES['uploaded_file']['error']); } // Close the mysql connection $dbLink->close(); } else { echo 'Error! A file was not sent!'; } // Echo a link back to the main page echo '<p>Click <a href="index.html">here</a> to go back</p>'; ?> I reached the last stage and its give error a file was not sent I don't know where I have missed. thank you

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  • Change SVN Path Entirely

    - by Tom
    Hi Guys, We have an SVN at http:/XX.XXX.XXX.XXX:1111/svn/AB/ - and the first two folders of the SVN are like http:/XX.XXX.XXX.XXX:1111/svn/AB/abc/filefolder/ The problem is we want to move the entire svn to get rid of /abc/filefolder/ - as the entire project sits under /abc/filefolder/ [created long ago and never bothered to change] (que stupid yes yes) How would we could about fixing this so we dont loose logs etc ? We dont want to have to export and create a new svn - since then we loose all our log files. But we want to "move" the svn root so for example it becomes From: http:/XX.XXX.XXX.XXX:1111/svn/AB/abc/filefolder/documents/ To: http:/XX.XXX.XXX.XXX:1111/svn/AB/documents/ Any help appreciated ? [ps - yes had to remove http:// due to link restriction]

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