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  • Make form redirect users after posting

    - by Liso22
    I need to change a form so that instead of reloading the page after submitting it, it redirects the user to another page, this is the form: <form class="questionform" name="questionform-0" id="questionform-0"> <textarea class="question-box" cols="12" rows="5" id="question-box-' . $questionformid . '" name="title" type="text" maxlength="200" size="28"></textarea> <input type="text" class="ubicacion" value="" name="question"> <input type="button" name="ask" value="Publicar" onclick="askquestion('questionform-0'); window.location.reload(true);"> I want to remove the window.location.reload and change it for a redirect that sends users to the page their comment will appear. Which is: www.chusmix.com/s?= (the content of the second field) The problem is that the content of the second field is part of the url I want to redirect, it's not simply always the same URL. So I have no idea how to do it. How do I do it? Anyway thanks for any info or whatever that points me on the right direction. Thanks

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  • how to add multiple modules to a single page in digitalus

    - by jspeshu
    when i do some thing like this i can see the module <div id='search' class="module"> <digitalusControl type='moduleSelector' id='module' label="searchM" group='mods' /> </div> but i want to have two modules so i make something like this <div id='search' class="module"> <digitalusControl type='moduleSelector' id='modulesearch' label="searchM" group='mods' /> </div> <div id='search' class="module"> <digitalusControl type='moduleSelector' id='modulenews' label="newsM" group='mods' /> </div> plz help how can i create multiple modules since i can't create another element "digitalusControl" with id "module" i really need this plz help EDIT: even worse a template with only one module, this single line is not working for me

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  • where to put business logic in a library?

    - by fayer
    i'm going to create a library that consists of a lot of separate classes. i'm very familiar with mvc but have never created a pure library before. i wonder where i should put the business logic? the logic that is in the controller in a mvc. should it be in a class? or in a "bootstrap" file? and should one file include every class, or should only one class include its classes it uses? thanks!

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  • Replace strings differently depending if is enclosed in braces or not.

    - by peroyomas
    I want to replace all instances of an specific words between braces with something else, unless it is written between double braces, while it should show as is it was written with single braces without the filter. I have tried a code but only works for the first match. The rest are shown depending of the first one: $foo = 'a {bar} b {{bar}} c {bar} d'; $baz = 'Chile'; preg_match_all( '/(\{?)\{(tin)\}(\}?)/i', $foo, $matches, PREG_SET_ORDER ); if ( !empty($matches) ) { foreach ( (array) $matches as $match ) { if( empty($match[1]) && empty($match[3])) { $tull = str_replace( $match[0], $baz, $foo ); } else { $tull = str_replace( $match[0], substr($match[0], 1, -1), $foo ) ; } } } echo $tull;

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  • Cookies not working for password-protected Pages on WordPress

    - by KaOSoFt
    Initially I had the issue reported in this question. Now, what I noticed is that there are some browsers that accept the password, and there are some which don't. Difference? For some reason the cookie is generated when I log in into the Administration module, but it isn't when I write down the password to access the page, forcing it to simply reload. I can see the cookie created for the log-in, but I can see none for the password-protected Page. These happens on Internet Explorer, both version 7 and 8; only on some machines, though, but most of them fail this. I already tried white-listing the URL, and even letting it accept ALL cookies, to no avail. What may be the cause? If perhaps it's got something to do with question above, please help me! Thanks in advance. PS: If you know of another, cookie-free method to make a simple authentication, please link me to it. Thanks. Oh, and by the way, this is inside an Intranet with static, class C IPs.

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  • How would i stop this foreach loop after 3 iterations?

    - by Tapha
    Here is the loop. foreach($results->results as $result){ echo '<div id="twitter_status">'; echo '<img src="'.$result->profile_image_url.'" class="twitter_image">'; $text_n = $result->text; echo "<div id='text_twit'>".$text_n."</div>"; echo '<div id="twitter_small">'; echo "<span id='link_user'".'<a href="http://www.twitter.com/'.$result->from_user.'">'.$result->from_user.'</a></span>'; $date = $result->created_at; $dateFormat = new DateIntervalFormat(); $time = strtotime($result->created_at); echo "<div class='time'>"; print sprintf('Submitted %s ago', $dateFormat->getInterval($time)); echo '</div>'; echo "</div>"; echo "</div>"; Thanks!!!! alot.

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  • How do I test the speed of a mySQL query?

    - by Chris
    I have a select and query like below... $sql = "SELECT * FROM notifications WHERE to_id='".$userid."' AND (alert_read != '1' OR user_read != '1') ORDER BY alert_time DESC"; $result = mysql_query($sql); how do I test how long the query took to run?

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  • Why is Zend Framework (Zend_Db_table) rejecting this SQL Query?

    - by Michael T. Smith
    I'm working on a simple JOIN of two tables (urls and companies). I am using this query call: print $this->_db->select()->from(array('u' => 'urls'), array('id', 'url', 'company_id')) ->join(array('c' => 'companies'), 'u.company_id = c.id'); which is out putting this query: SELECT `u`.`id`, `u`.`url`, `u`.`company_id`, `c`.* FROM `urls` AS `u` INNER JOIN `companies` AS `c` ON u.company_id = c.id Now, I'd prefer the c.* to not actually appear, but either way it doesn't matter. ZF dies with this error: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1" but I can run that query perfectly fine in my MySQL CLI. Any ideas how to fix up this query?

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  • Modifying MySQL Where Statement Based on Array

    - by Ryan
    Using an array like this: $data = array ( 'host' => 1, 'country' => 'fr', ) I would like to create a MySQL query that uses the values of the array to form its WHERE clause like: SELECT * FROM table WHERE host = 1 and country = 'fr' How can I generate this query string to use with MySQL?

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  • how can i execute large mysql queries fast

    - by testkhan
    I have 4 mysql tables and have a single query with JOIN on multiple tables and I am requesting it via jquery ajax, but it takes to much long time from about 1-3 minutes while I want to execute them on average 2-5 seconds. is there any special way to execute the quries fast

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  • ModX navigation menu with "wayfinder" snippet

    - by user1219432
    I have a main navigation at the top of the site. And a subnavigation at left of my site. For example: At the top there are these topics: Cars | Trees | Jobs | ... So when you click on "Jobs" there should be the subnavigation of "Jobs" at left, like... Construction Jobs Engineering Jobs Retail Jobs ... The first (top) navigation is easy to achieve: [[!Wayfinder? &startId=0 &level=1 ]] How can I realize the second navigation, so that only the documents are listed that are under the parent document?

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  • How do I call this function in CodeIgniter controller?

    - by Jason Shultz
    I've got this code, but I'm not sure I make it work: /** * Function: youtube data grabber * * @description : * @param $ : video code, url type (embed/url) * @return : data array * @author : Mamun. * @last -modified-by: Mamun. */ if (! function_exists('youtube_data_grabber')) { function youtube_data_grabber($video_code, $link_type = "embed") { if ($video_code != '') { if ($link_type == "embed") { $splited_data = explode("=",$video_code); $video_unique_code = substr(strrchr($splited_data[4],"/"),1,-strlen(strrchr($splited_data[4],"&"))); } else if ($link_type == "url") { $splited_data = explode("=",$video_code); $video_unique_code = substr($splited_data[1],0,-strlen(strrchr($splited_data[1],"&"))); } else { return; } // set feed URL $feedURL = 'http://gdata.youtube.com/feeds/api/videos/'.$video_unique_code; // read feed into SimpleXML object $sxml = simplexml_load_file($feedURL); return $sxml; } } } // End Youtube Function I'm not sure how to activate it is what I'm trying to say. I placed it in the controller and it's within a function for one of my pages. I don't have any syntax errors. I just don't know how to wake it up and make it work. I thought I could just put youtube_data_grabber('http://www.youtube.com/watch?v=LAcrFym10ZI', 'url'); but that didn't work. I got the code from here: http://bit.ly/b7YnDt and I have the zend functionality working. I tested it earlier and had no errors. I'm just having trouble with this youtube part. Any ideas?

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  • inserting facebook app users details to database

    - by fusion
    i'm trying to insert user details, who authorize the app, into the database, but nothing seems to be happening. the data is null and no record is being inserted. is there something wrong with the code? function insertUser($user_id,$sk,$conn) { //$info = $facebook->api_client->users_getInfo($user_id, 'first_name, last_name', 'name', 'sex'); $info = $facebook->api_client->fql_query("SELECT uid, first_name, last_name, name, sex FROM user WHERE uid = $user_id"); for ($i=0; $i < count($info); $i++) { $record = $info[$i]; $first_name=$record['first_name']; $last_name=$record['last_name']; $full_name=$record['name']; $gender=$record['sex']; } $data= mysql_query("select uid from users where uid='{$user_id}'",$conn); if(mysql_num_rows($data)==0) { $sql = "INSERT INTO users (uid,sessionkey, active, fname, lname, full_name, gender) VALUES('{$user_id}','{$sk}','1', '{$first_name}', '{$last_name}', '{$full_name}', '{$gender}')"; mysql_query($sql,$conn); return true; } return false; }

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  • how should i echo the data

    - by Syom
    for example i want to generate html code, using some data from database. here is two ways of printing data <? echo '<li><img src="'.$row['image'].'" /></li>';?> or <? echo "<li><img src='$row[image]' /></li>";?> both of them are working. and if so, why people use the first method, if without spliting the row by . it works fine too.

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  • Adding a comment system to my website

    - by MJ93
    Hey everyone, I'm trying to add some type of comment system to my website for the news that I post on the main page. What I would like it to do is have anybody comment on it (they don't need to login). The comment submission form just required a Name and comment. What would be the simplest way to do this? It would also be nice to have it display how many comments there currently are on the news post. I dont need anything fancy. Thanks!

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