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  • Get the names of IDs from different table

    - by user896692
    I have an array with a lot of data from a database. In the array, there are two fields called teameinsid and teamzweiid. The query is a very simple one : $spiel = mysql_query("select teameinsid, teamzweiid from begegnung", $connection) or die("Keine passende Begegnung"); What I need is to search in the database for the names of these IDs. The names are in a different table. What I have now is the following: while($tmp = mysql_fetch_array($spiel)){ $teins = $tmp['teameinsid']; $tzwei = $tmp['teamzweiid']; } So I know the two IDs, but I don't know where to save the names. If I try: $name = mysql_query("select name from team where teameinsid = $teins", $con) it gets overwritten every time. How can I manage this?

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  • How to distribute the chance to display each SWF evenly among banner collection?

    - by Michael Mao
    Hi all: I am working on The ausdcf.org to try adding several banner ads in swf format to the top. Everything starts to work, but I've got several questions that need your help: The client chose not to go with Google AdManager, but prefer a "minimal approach" to do this task. What I am trying to do is sort of "mimicking" the way Google AdManager does for banners, that is, to split the chance of each particular swf to be shown to the visitor evenly among the banner collection. Definitely I can add some jQuery code to do this from client-side, a random number generator and if-else statement would work - just $.load() it! However, what if I'd like to make sure those disabled Javascript (is there any now btw?) still be able to see different swfs in each visit. Any suggestion on how to approach this? Many thanks in advance.

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  • Module config in Zend Framework 1.10

    - by Ilomac
    I am using reccomended app. structure ( http://framework.zend.com/manual/1.10/en/project-structure.filesystem.html ) in Zend Framework but I cant get each module config working. It just doesn't load modules/mymodule/configs/application.ini file into configuration.

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  • mysql row counter

    - by David19801
    Hello, I have a mysql table. It has auto increment on the id. but I regularly delete rows so the numbers are all over the place. I need to get the last n rows out, but because of deletions, the common way of using the max of the autoincremented id column doesn't work well... 1 - Is their another way to get the bottom 50? 2 - Is their a way to get rows by actual row number? so if I have 4 rows labelled 1,2,3,4 delete row 2 then it will become 1,2,3 rather than 1,3,4?

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  • Log into file or database, readability question

    - by Fungsten
    Hi there! Right now I'm logging some info of the user in my web app in a log file to observe the usage & interest for some services, but I'm interested in checking that info in a readeable way, so I'm questioning if maybe I shall save that info in a database and then retrieve it to show it in tables or whatever. It's better to log in the database for my purposes? Or logging like now I could select/order the info of the log easily?

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  • MySQL Joining three tables

    - by text
    I am doing a query with three tables, the problem was one table has many occurrences of id of another. sample data: users: id answers: id:1 user_answer :1 id:1 user_answer :2 id:1 user_answer :3 Questions: id:1 answers :answer description id:2 answers :answer description id:3 answers :answer description How can I get all user information and all answer and its description, I used GROUP by user.id but it only returns only one answer. I want to return something like this list all of users answer: Name Q1 Q2 USERNAME ans1,ans2 ans1,ans2 comma separated description of answer here

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  • Loop through Array with conditional output based on key/value pair

    - by Daniel C
    I have an array with the following columns: Task Status I would like to print out a table that shows a list of the Tasks, but not the Status column. Instead, for Tasks where the Status = 0, I want to add a tag <del> to make the completed task be crossed out. Here's my current code: foreach ($row as $key => $val){ if ($key != 'Status') print "<td>$val</td>"; else if ($val == '0') print "<td><del>$val</del></td>"; } This seems to be correct, but when I print it out, it prints all the tasks with the <del> tag. So basically the "else" clause is being run every time. Here is the var_dump($row): array 'Task' => string 'Task A' (length=6) 'Status' => string '3' (length=1) array 'Task' => string 'Task B' (length=6) 'Status' => string '0' (length=1)

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  • Searching Arrays, array_search() issue

    - by Mikey1980
    Is there any way I can search an array for a value and return it's key, I tried array_search() with no success... below is an example of my array [0] = Array ( [value] = [text] = All Call Types ) [1] => Array ( [value] => enquiry [text] => Renovation Enquiry ) [2] => Array ( [value] => msg [text] => Message to Pass on ) ... My ultimate goal is to convert value to text. Here's what I tried: $key = array_search($row['call_type'], $type_list); $call_type_name = $type_list[$key]['text']; Thanks!

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  • Add Form In Every Row with table helper Codeigniter

    - by wibi
    Hi i am creating table using table helper, but in every row i want to add form, in html like this : <table> <form action=""> <tr> <td><input type="text" name="name2"></td> </tr> </form> <form action=""> <tr> <td><input type="text" name="name2"></td> </tr> </form> </table> But i want in table helper: I have tried this one: $this->table->add_row( form_open('myAction'). form_input('name'.$i), form_submit('Submit') form_close() ); And I use firebugs to inspect element produces, like this: <table> <tr> <form action="myAction"> <td><input type="text" name="name1"></td> </form> <td><input type="submit"></td> </tr> </table> why tag doesn't show at the last tag , but show at the first tag . Thanks

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  • Why are some classes created on the fly and others aren't in CakePHP 1.2.7?

    - by JoseMarmolejos
    I have the following model classes: class User extends AppModel { var $name= 'User'; var $belongsTo=array('SellerType' => array('className' => 'SellerType'), 'State' => array('className' => 'State'), 'Country' => array('className' => 'Country'), 'AdvertMethod' => array('className' => 'AdvertMethod'), 'UserType' => array('className' => 'UserType')); var $hasMany = array('UserQuery' => array('className' => 'UserQuery'));} And: class UserQuery extends AppModel { var $name = 'UserQuery'; var $belongsTo = array('User', 'ResidenceType', 'HomeType');} Everything works fine with the user class and all its associations, but the UserQuery class is being completely ignored by the orm (table name user_queries and the generated queries do cast it as UserQuery. Another weird thing is that if I delete the code inside the User class I get an error, but if I do the same for the UserQuery class I get no errors. So my question is why does cakephp generate a class on the fly for the UserQuery and ignores my class, and why doesn't it generate a class on the fly for the User as well ?

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  • Count number of results in a View

    - by Jukebox
    I need to count how many people belong in pre-defined groups (this is easy to do in SQL using the SELECT COUNT statement). My Views query runs fine and displays the actual data in my table, but I simply need to know how many results it found. However there doesn't seem to be a COUNT option in views. I am guessing I am going to have to use some sort of views hook, and then stick the result in the table. Here's a quick example of what i'm trying to achieve: My Table ---------------------- Group A | 20 people Group B | 63 people and so on. (I've tried using the Views_Calc module, but I get errors because it is not quite stable yet.) Anybody know of an easy way to count results in Views?

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  • Validate authenticity of website owner

    - by Cyber Junkie
    Hello all! I'm planning to develop a web app where users will list their site/blog. When people submit their sites, how can I confirm that they are the owners of it? So for instance there is a user Mark who wants to submit someone else's website without their approval. I want to restrict Mark from doing so unless he is the actual owner. My idea was to do a comparison between the user's email domain and the website domain she/he wants to submit. If they match allow the user to submit the website. However most people don't register with their website domain address.. or perhaps I'll implement a Facebook connect in the future. What other methods would you suggest?

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  • Vertically And Horizonatally center main wrap div

    - by Hello you all men
    Now i try <html> <head> <title>?????????????????</title> <style type="text/css"> body { margin-left: auto; margin-right:auto; } #wrap { background: black; margin-left: auto; margin-right:auto; height:450px; width:450px; position:absolute; top:50%; right:50%; left:50%; margin-top:-225px; } </style> </head> <body> <div id="wrap"> Hello </div> </body> </html> ?????

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  • Testing a SQL Query for True or False

    - by KickingLettuce
    $sql = "SELECT # FROM users WHERE onduty = 1 AND loc_id = '{$site}';"; $result = mysql_query($sql); I simply want to test if this is true or false. If it returns 0 rows, I want next line to be something like: if (!$result) { //do this; } However, in my test, I am getting false when I know it should be true. Is this sound logic here? (note, yes I know I should be using mysqli_query, that is not what I am asking here)

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  • Syntax problem when checking for a file

    - by Luke
    This piece of code has previously worked but I have C&P it to a new place and for some reason, it now won't work! <? $user_image = '/images/users/' . $_SESSION['id'] . 'a.jpg'; if (file_exists(realpath(dirname(__FILE__) . $user_image))) { echo '<img src="'.$user_image.'" alt="" />'; } else { echo '<img src="/images/users/small.jpg" alt="" />'; } ?> As you can see, I am checking for a file, if exists, showing it, if not, showing a placeholder. The $_SESSION['id'] variable does exist and is being used elsewhere within the script. Any ideas what the problem is? Thanks

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  • session_set_cookie_params on multi-domain sites

    - by nillls
    Hi! I'm currently developing for an application (www.domain.se, .eu) where we're experiencing problems with sessions not propagating across domains. Internet Explorer is the root cause of this, as it will differentiate sessions depending on whether we're typing in "domain.se" or "www.domain.se". Due to some unfortunate redirecting, we're not able to keep the user on the same address the user typed in, instead we're always redirecting to www.domain.se on login. Needless to say, IE users can not login when typing "domain.se". To make this error go away, we implemented a function to try and set the session to be valid across all possible domains by doing the following: if($_SERVER['HTTP_HOST'] == "domain.se") { session_set_cookie_params(3600, '/', '.domain.se', true); } There are basically a few if:s that we go through depending on what address the user typed in, but the third argument stays the same. This, however, results in no-one being able to log in, regardless of domain. I've tried reading up on how session_set_cookie_params() works but to no avail. Any help is greatly appreciated!

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  • Setting an empty default value for a char-column in MySQL?

    - by user281434
    Hi In phpMyAdmin I have a char(32) column that has no default value(ie. Default: None). When I try to insert data through a SQL query, it throws out an error saying that the column "doesn't have a default value". I need it to be empty, so instead I've just set it's default value as "As defined: " and then nothing in the value field. Is this a bad idea? And is it any better than simply throwing in an empty value for the column in the SQL query? Thanks for your time.

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  • Submit multiple forms as one

    - by Stephen Sarcsam Kamenar
    I have two forms on the page. To the user it looks like 1 form, and I actually wish it was one form. But the way I'm trying to reuse code and include things, I can't avoid two forms in the source code... trying to act as one. I don't want to do ajax submit, I want a normal post submit, my form handler has redirects in it. How can I submit both of these, and get values that make sense on the server side. something like $_POST['form1]['whatever'] $_POST['form2]['thing'] Maybe take all the inputs from form 2, rename all of them with a prefix, and append them to form 1? I can't find a non-messy way of doing this. I don't think I need code, just a plan. Least messy idea wins.

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