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  • perl + shell script + remove all not uniq lines except the first line uniq (FILE NAME) + perl in she

    - by yael
    hi I have the following file How to remove by sed all FILE NAME lines except the first uniq FILE NAME For example need to remove all FILE NAME lines from the file except the first: FILE NAME: /dir1/dir2/dir3/dir4/dir5/file FILE NAME: /dirA/dirB/dirC/dirD/dirE/file the file: FILE NAME: /dir1/dir2/dir3/dir4/dir5/file PARAMETER NAME: blablabla TARGET FILE: 12 SOURCE FILE: 565 FILE NAME: /dir1/dir2/dir3/dir4/dir5/file PARAMETER NAME: blablabla TARGET FILE: 18 SOURCE FILE: 552 FILE NAME: /dir1/dir2/dir3/dir4/dir5/file PARAMETER NAME: blablabla TARGET FILE: 14 SOURCE FILE: 559 FILE NAME: /dirA/dirB/dirC/dirD/dirE/file PARAMETER NAME: blablabla TARGET FILE: 134 SOURCE FILE: 344 FILE NAME: /dirA/dirB/dirC/dirD/dirE/file PARAMETER NAME: blablabla TARGET FILE: 13 SOURCE FILE: 445 FILE NAME: /dirA/dirB/dirC/dirD/dirE/file PARAMETER NAME: blablabla TARGET FILE: 13

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  • tried to update hudson via dashboard and now it doesn;t work (windows)

    - by Tim
    I get the following now in the output log. I really wish I hadn't attempted to update teh version. What a hassle. Can anyone diagnose the issue here? Running from: C:\hudson\hudson.war [Winstone 2010/06/14 23:33:54] - Beginning extraction from war file hudson home directory: C:\hudson [Winstone 2010/06/14 23:33:56] - Error during HTTP listener init or shutdown java.net.SocketException: Unrecognized Windows Sockets error: 0: JVM_Bind at java.net.PlainSocketImpl.socketBind(Native Method) at java.net.PlainSocketImpl.bind(Unknown Source) at java.net.ServerSocket.bind(Unknown Source) at java.net.ServerSocket.(Unknown Source) at java.net.ServerSocket.(Unknown Source) at winstone.HttpListener.getServerSocket(HttpListener.java:102) at winstone.HttpListener.run(HttpListener.java:116) at java.lang.Thread.run(Unknown Source) [Winstone 2010/06/14 23:33:56] - HTTP Listener shutdown successfully [Winstone 2010/06/14 23:33:56] - Winstone Servlet Engine v0.9.10 running: controlPort=disabled [Winstone 2010/06/14 23:33:56] - Error during AJP13 listener init or shutdown java.net.SocketException: Unrecognized Windows Sockets error: 0: JVM_Bind at java.net.PlainSocketImpl.socketBind(Native Method) at java.net.PlainSocketImpl.bind(Unknown Source) at java.net.ServerSocket.bind(Unknown Source) at java.net.ServerSocket.(Unknown Source) at java.net.ServerSocket.(Unknown Source) at winstone.ajp13.Ajp13Listener.run(Ajp13Listener.java:99) at java.lang.Thread.run(Unknown Source) [Winstone 2010/06/14 23:33:56] - AJP13 Listener shutdown successfully Running from: C:\hudson\hudson.war [Winstone 2010/06/14 23:38:49] - Beginning extraction from war file hudson home directory: C:\hudson [Winstone 2010/06/14 23:38:51] - Winstone Servlet Engine v0.9.10 running: controlPort=disabled [Winstone 2010/06/14 23:38:51] - Error during AJP13 listener init or shutdown java.net.SocketException: Unrecognized Windows Sockets error: 0: JVM_Bind at java.net.PlainSocketImpl.socketBind(Native Method) at java.net.PlainSocketImpl.bind(Unknown Source) at java.net.ServerSocket.bind(Unknown Source) at java.net.ServerSocket.(Unknown Source) at java.net.ServerSocket.(Unknown Source) at winstone.ajp13.Ajp13Listener.run(Ajp13Listener.java:99) at java.lang.Thread.run(Unknown Source) [Winstone 2010/06/14 23:38:51] - AJP13 Listener shutdown successfully [Winstone 2010/06/14 23:38:51] - Error during HTTP listener init or shutdown java.net.SocketException: Unrecognized Windows Sockets error: 0: JVM_Bind at java.net.PlainSocketImpl.socketBind(Native Method) at java.net.PlainSocketImpl.bind(Unknown Source) at java.net.ServerSocket.bind(Unknown Source) at java.net.ServerSocket.(Unknown Source) at java.net.ServerSocket.(Unknown Source) at winstone.HttpListener.getServerSocket(HttpListener.java:102) at winstone.HttpListener.run(HttpListener.java:116) at java.lang.Thread.run(Unknown Source) [Winstone 2010/06/14 23:38:51] - HTTP Listener shutdown successfully

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  • How to use Java on Google App Engine without exceeding minute quotas?

    - by Geo
    A very simple java code inside a doGet() servlet is getting more than a second of cpu time on GAE. I have read some quota related documentation and apparently I am not doing anything wrong. //Request the user Agent info String userAgent = req.getHeader("User-Agent"); I wanted to know what was using the CPU the most, I use a google help recommendation. //The two lines below will get the CPU before requesting User-Agent Information QuotaService qs = QuotaServiceFactory.getQuotaService(); long start = qs.getCpuTimeInMegaCycles(); //Request the user Agent info String userAgent = req.getHeader("User-Agent"); //The three lines below will get the CPU after requesting User-Agent Information // and informed it to the application log. long end = qs.getCpuTimeInMegaCycles(); double cpuSeconds = qs.convertMegacyclesToCpuSeconds(end - start); log.warning("CPU Seconds on geting User Agent: " + cpuSeconds); The only thing that the code above tells me is that inspecting the header will use more than a second (1000ms) of cpu time, which for Google is a warning on the log panel. That seems to be a very simple request and still is using more than a second of cpu. What I am missing?

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  • Append to a file in Java. Is it a joke?

    - by Roman
    I need to append some data to existing file. I started to browse Internet to find out how to do it. And I found this mini (as they say) application to do that: http://www.devdaily.com/java/edu/qanda/pjqa00009.shtml Well I was already annoyed by the fact how complicated are things in Java (in comparison with Python, for example). But this is too much! I just want to add to a file! It should be one line! Not 50! Or do I get something wrong?

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  • How to pass a resource file string to a function in an external .js file

    - by hima
    Hi , There is a Messages.resx file under App_GlobalResources in my solution. Everytime i create a string and give a value to the string internal static string Alert_EnterUserName { get { return ResourceManager.GetString("Alert_EnterUserName", resourceCulture); } } is created automatically. Can anybody guide me how to use this string in a function which is present in a seperate .js file? Thanks in advance

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  • java label setText and setBounds clashing?

    - by java
    I would like to have a JLabel changint color to a random one, while jumping to a random position, and while changing its text. but the setText and setBounds seem to clash and i don't know why. if you comment out the setText then the setBounds will work, but they won't work together. import java.awt.*; import java.util.*; import javax.swing.*; public class test2 extends JFrame { private static JLabel label = new JLabel("0"); private static Random gen = new Random(); public test2() { JPanel panel = new JPanel(); panel.add(label); this.add(panel); } public static void move() { for (int i = 0; i < 10; i++) { int n = gen.nextInt(254)+1; int nn = gen.nextInt(254)+1; int nnn = gen.nextInt(254)+1; label.setText(""+i); //the setBounds command will not work with the setText command. why? label.setBounds(n*2, nn*2, 20, 20); label.setForeground(new Color(n, nn, nnn)); try { Thread.sleep(200); } catch (Exception e) {} } } public static void main(String[] args) { test2 frame = new test2(); frame.setVisible(true); frame.setSize(600, 600); frame.setResizable(true); frame.setLocationRelativeTo(null); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); move(); } }

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  • How to upload a file into database by using Servlet?

    - by user1765496
    Hi all iam working on servlets, so i need to upload a file by using servlet as follows my code. package com.limrasoft.image.servlets; import java.io.*; import javax.servlet.*; import javax.servlet.http.*; import javax.servlet.annotation.*; import java.sql.*; @WebServlet(name="serv1",value="/s1") public class Account extends HttpServlet{ public void doPost(HttpServletRequest req,HttpServletResponse res)throws ServletException,IOException{ try{ Class.forName("oracle.jdbc.driver.OracleDriver"); Connecection con=null; try{ con=DriverManager.getConnection("jdbc:oracle:thin:@localhost:1521:xe","system","sajid"); PrintWriter pw=res.getWriter(); res.setContentType("text/html"); String s1=req.getParameter("un"); string s2=req.getParameter("pwd"); String s3=req.getParameter("g"); String s4=req.getParameter("uf"); PreparedStatement ps=con.prepareStatement("insert into account(?,?,?,?)"); ps.setString(1,s1); ps.setString(2,s2); ps.setString(3,s3); File file=new File("+s4+"); FileInputStream fis=new FileInputStream(fis); int len=(int)file.length(); ps.setBinaryStream(4,fis,len); int c=ps.executeUpdate(); if(c==0){pw.println("<h1>Registratin fail");} else{pw.println("<h1>Registration fail");} } finally{if(con!=null)con.close();} } catch(ClassNotFoundException ce){pw.println("<h1>Registration Fail");} catch(SQLException se){pw.println("<h1>Registration Fail");} pw.flush(); pw.close(); } } I have written the above code for file upload into database, but it giving error as "HTTP Status 500 - Servlet3.java (The system cannot find the file specified)" Could you plz help me to do this code,thanks in advanse.

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  • Is method reference caching a good idea in Java 8?

    - by gexicide
    Consider I have code like the following: class Foo { Y func(X x) {...} void doSomethingWithAFunc(Function<X,Y> f){...} void hotFunction(){ doSomethingWithAFunc(this::func); } } Consider that hotFunction is called very often. Would it then be advisable to cache this::func, maybe like this: class Foo { Function<X,Y> f = this::func; ... void hotFunction(){ doSomethingWithAFunc(f); } } As far as my understanding of java method references goes, the Virtual Machine creates an object of an anonymous class when a method reference is used. Thus, caching the reference would create that object only once while the first approach creates it on each function call. Is this correct? Should method references that appear at hot positions in the code be cached or is the VM able to optimize this and make the caching superfluous? Is there a general best practice about this or is this highly VM-implemenation specific whether such caching is of any use?

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  • How do I read and write to a file using threads in java?

    - by WarmWaffles
    I'm writing an application where I need to read blocks in from a single file, each block is roughly 512 bytes. I am also needing to write blocks simultaneously. One of the ideas I had was BlockReader implements Runnable and BlockWriter implements Runnable and BlockManager manages both the reader and writer. The problem that I am seeing with most examples that I have found was locking problems and potential deadlock situations. Any ideas how to implement this?

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  • creating objects from trivial graph format text file. java. dijkstra algorithm.

    - by user560084
    i want to create objects, vertex and edge, from trivial graph format txt file. one of programmers here suggested that i use trivial graph format to store data for dijkstra algorithm. the problem is that at the moment all the information, e.g., weight, links, is in the sourcecode. i want to have a separate text file for that and read it into the program. i thought about using a code for scanning through the text file by using scanner. but i am not quite sure how to create different objects from the same file. could i have some help please? the file is v0 Harrisburg v1 Baltimore v2 Washington v3 Philadelphia v4 Binghamton v5 Allentown v6 New York # v0 v1 79.83 v0 v5 81.15 v1 v0 79.75 v1 v2 39.42 v1 v3 103.00 v2 v1 38.65 v3 v1 102.53 v3 v5 61.44 v3 v6 96.79 v4 v5 133.04 v5 v0 81.77 v5 v3 62.05 v5 v4 134.47 v5 v6 91.63 v6 v3 97.24 v6 v5 87.94 and the dijkstra algorithm code is Downloaded from: http://en.literateprograms.org/Special:Downloadcode/Dijkstra%27s_algorithm_%28Java%29 */ import java.util.PriorityQueue; import java.util.List; import java.util.ArrayList; import java.util.Collections; class Vertex implements Comparable<Vertex> { public final String name; public Edge[] adjacencies; public double minDistance = Double.POSITIVE_INFINITY; public Vertex previous; public Vertex(String argName) { name = argName; } public String toString() { return name; } public int compareTo(Vertex other) { return Double.compare(minDistance, other.minDistance); } } class Edge { public final Vertex target; public final double weight; public Edge(Vertex argTarget, double argWeight) { target = argTarget; weight = argWeight; } } public class Dijkstra { public static void computePaths(Vertex source) { source.minDistance = 0.; PriorityQueue<Vertex> vertexQueue = new PriorityQueue<Vertex>(); vertexQueue.add(source); while (!vertexQueue.isEmpty()) { Vertex u = vertexQueue.poll(); // Visit each edge exiting u for (Edge e : u.adjacencies) { Vertex v = e.target; double weight = e.weight; double distanceThroughU = u.minDistance + weight; if (distanceThroughU < v.minDistance) { vertexQueue.remove(v); v.minDistance = distanceThroughU ; v.previous = u; vertexQueue.add(v); } } } } public static List<Vertex> getShortestPathTo(Vertex target) { List<Vertex> path = new ArrayList<Vertex>(); for (Vertex vertex = target; vertex != null; vertex = vertex.previous) path.add(vertex); Collections.reverse(path); return path; } public static void main(String[] args) { Vertex v0 = new Vertex("Nottinghill_Gate"); Vertex v1 = new Vertex("High_Street_kensignton"); Vertex v2 = new Vertex("Glouchester_Road"); Vertex v3 = new Vertex("South_Kensignton"); Vertex v4 = new Vertex("Sloane_Square"); Vertex v5 = new Vertex("Victoria"); Vertex v6 = new Vertex("Westminster"); v0.adjacencies = new Edge[]{new Edge(v1, 79.83), new Edge(v6, 97.24)}; v1.adjacencies = new Edge[]{new Edge(v2, 39.42), new Edge(v0, 79.83)}; v2.adjacencies = new Edge[]{new Edge(v3, 38.65), new Edge(v1, 39.42)}; v3.adjacencies = new Edge[]{new Edge(v4, 102.53), new Edge(v2, 38.65)}; v4.adjacencies = new Edge[]{new Edge(v5, 133.04), new Edge(v3, 102.53)}; v5.adjacencies = new Edge[]{new Edge(v6, 81.77), new Edge(v4, 133.04)}; v6.adjacencies = new Edge[]{new Edge(v0, 97.24), new Edge(v5, 81.77)}; Vertex[] vertices = { v0, v1, v2, v3, v4, v5, v6 }; computePaths(v0); for (Vertex v : vertices) { System.out.println("Distance to " + v + ": " + v.minDistance); List<Vertex> path = getShortestPathTo(v); System.out.println("Path: " + path); } } } and the code for scanning file is import java.util.Scanner; import java.io.File; import java.io.FileNotFoundException; public class DataScanner1 { //private int total = 0; //private int distance = 0; private String vector; private String stations; private double [] Edge = new double []; /*public int getTotal(){ return total; } */ /* public void getMenuInput(){ KeyboardInput in = new KeyboardInput; System.out.println("Enter the destination? "); String val = in.readString(); return val; } */ public void readFile(String fileName) { try { Scanner scanner = new Scanner(new File(fileName)); scanner.useDelimiter (System.getProperty("line.separator")); while (scanner.hasNext()) { parseLine(scanner.next()); } scanner.close(); } catch (FileNotFoundException e) { e.printStackTrace(); } } public void parseLine(String line) { Scanner lineScanner = new Scanner(line); lineScanner.useDelimiter("\\s*,\\s*"); vector = lineScanner.next(); stations = lineScanner.next(); System.out.println("The current station is " + vector + " and the destination to the next station is " + stations + "."); //total += distance; //System.out.println("The total distance is " + total); } public static void main(String[] args) { /* if (args.length != 1) { System.err.println("usage: java TextScanner2" + "file location"); System.exit(0); } */ DataScanner1 scanner = new DataScanner1(); scanner.readFile(args[0]); //int total =+ distance; //System.out.println(""); //System.out.println("The total distance is " + scanner.getTotal()); } }

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  • Convert Java program to C

    - by imicrothinking
    I need a bit of guidance with writing a C program...a bit of quick background as to my level, I've programmed in Java previously, but this is my first time programming in C, and we've been tasked to translate a word count program from Java to C that consists of the following: Read a file from memory Count the words in the file For each occurrence of a unique word, keep a word counter variable Print out the top ten most frequent words and their corresponding occurrences Here's the source program in Java: package lab0; import java.io.File; import java.io.FileReader; import java.util.ArrayList; import java.util.Calendar; import java.util.Collections; public class WordCount { private ArrayList<WordCountNode> outputlist = null; public WordCount(){ this.outputlist = new ArrayList<WordCountNode>(); } /** * Read the file into memory. * * @param filename name of the file. * @return content of the file. * @throws Exception if the file is too large or other file related exception. */ public char[] readFile(String filename) throws Exception{ char [] result = null; File file = new File(filename); long size = file.length(); if (size > Integer.MAX_VALUE){ throw new Exception("File is too large"); } result = new char[(int)size]; FileReader reader = new FileReader(file); int len, offset = 0, size2read = (int)size; while(size2read > 0){ len = reader.read(result, offset, size2read); if(len == -1) break; size2read -= len; offset += len; } return result; } /** * Make article word by word. * * @param article the content of file to be counted. * @return string contains only letters and "'". */ private enum SPLIT_STATE {IN_WORD, NOT_IN_WORD}; /** * Go through article, find all the words and add to output list * with their count. * * @param article the content of the file to be counted. * @return words in the file and their counts. */ public ArrayList<WordCountNode> countWords(char[] article){ SPLIT_STATE state = SPLIT_STATE.NOT_IN_WORD; if(null == article) return null; char curr_ltr; int curr_start = 0; for(int i = 0; i < article.length; i++){ curr_ltr = Character.toUpperCase( article[i]); if(state == SPLIT_STATE.IN_WORD){ article[i] = curr_ltr; if ((curr_ltr < 'A' || curr_ltr > 'Z') && curr_ltr != '\'') { article[i] = ' '; //printf("\nthe word is %s\n\n",curr_start); if(i - curr_start < 0){ System.out.println("i = " + i + " curr_start = " + curr_start); } addWord(new String(article, curr_start, i-curr_start)); state = SPLIT_STATE.NOT_IN_WORD; } }else{ if (curr_ltr >= 'A' && curr_ltr <= 'Z') { curr_start = i; article[i] = curr_ltr; state = SPLIT_STATE.IN_WORD; } } } return outputlist; } /** * Add the word to output list. */ public void addWord(String word){ int pos = dobsearch(word); if(pos >= outputlist.size()){ outputlist.add(new WordCountNode(1L, word)); }else{ WordCountNode tmp = outputlist.get(pos); if(tmp.getWord().compareTo(word) == 0){ tmp.setCount(tmp.getCount() + 1); }else{ outputlist.add(pos, new WordCountNode(1L, word)); } } } /** * Search the output list and return the position to put word. * @param word is the word to be put into output list. * @return position in the output list to insert the word. */ public int dobsearch(String word){ int cmp, high = outputlist.size(), low = -1, next; // Binary search the array to find the key while (high - low > 1) { next = (high + low) / 2; // all in upper case cmp = word.compareTo((outputlist.get(next)).getWord()); if (cmp == 0) return next; else if (cmp < 0) high = next; else low = next; } return high; } public static void main(String args[]){ // handle input if (args.length == 0){ System.out.println("USAGE: WordCount <filename> [Top # of results to display]\n"); System.exit(1); } String filename = args[0]; int dispnum; try{ dispnum = Integer.parseInt(args[1]); }catch(Exception e){ dispnum = 10; } long start_time = Calendar.getInstance().getTimeInMillis(); WordCount wordcount = new WordCount(); System.out.println("Wordcount: Running..."); // read file char[] input = null; try { input = wordcount.readFile(filename); } catch (Exception e) { // TODO Auto-generated catch block e.printStackTrace(); System.exit(1); } // count all word ArrayList<WordCountNode> result = wordcount.countWords(input); long end_time = Calendar.getInstance().getTimeInMillis(); System.out.println("wordcount: completed " + (end_time - start_time)/1000000 + "." + (end_time - start_time)%1000000 + "(s)"); System.out.println("wordsort: running ..."); start_time = Calendar.getInstance().getTimeInMillis(); Collections.sort(result); end_time = Calendar.getInstance().getTimeInMillis(); System.out.println("wordsort: completed " + (end_time - start_time)/1000000 + "." + (end_time - start_time)%1000000 + "(s)"); Collections.reverse(result); System.out.println("\nresults (TOP "+ dispnum +" from "+ result.size() +"):\n" ); // print out result String str ; for (int i = 0; i < result.size() && i < dispnum; i++){ if(result.get(i).getWord().length() > 15) str = result.get(i).getWord().substring(0, 14); else str = result.get(i).getWord(); System.out.println(str + " - " + result.get(i).getCount()); } } public class WordCountNode implements Comparable{ private String word; private long count; public WordCountNode(long count, String word){ this.count = count; this.word = word; } public String getWord() { return word; } public void setWord(String word) { this.word = word; } public long getCount() { return count; } public void setCount(long count) { this.count = count; } public int compareTo(Object arg0) { // TODO Auto-generated method stub WordCountNode obj = (WordCountNode)arg0; if( count - obj.getCount() < 0) return -1; else if( count - obj.getCount() == 0) return 0; else return 1; } } } Here's my attempt (so far) in C: #include <stdio.h> #include <stdlib.h> #include <stdbool.h> #include <string.h> // Read in a file FILE *readFile (char filename[]) { FILE *inputFile; inputFile = fopen (filename, "r"); if (inputFile == NULL) { printf ("File could not be opened.\n"); exit (EXIT_FAILURE); } return inputFile; } // Return number of words in an array int wordCount (FILE *filePointer, char filename[]) {//, char *words[]) { // count words int count = 0; char temp; while ((temp = getc(filePointer)) != EOF) { //printf ("%c", temp); if ((temp == ' ' || temp == '\n') && (temp != '\'')) count++; } count += 1; // counting method uses space AFTER last character in word - the last space // of the last character isn't counted - off by one error // close file fclose (filePointer); return count; } // Print out the frequencies of the 10 most frequent words in the console int main (int argc, char *argv[]) { /* Step 1: Read in file and check for errors */ FILE *filePointer; filePointer = readFile (argv[1]); /* Step 2: Do a word count to prep for array size */ int count = wordCount (filePointer, argv[1]); printf ("Number of words is: %i\n", count); /* Step 3: Create a 2D array to store words in the file */ // open file to reset marker to beginning of file filePointer = fopen (argv[1], "r"); // store words in character array (each element in array = consecutive word) char allWords[count][100]; // 100 is an arbitrary size - max length of word int i,j; char temp; for (i = 0; i < count; i++) { for (j = 0; j < 100; j++) { // labels are used with goto statements, not loops in C temp = getc(filePointer); if ((temp == ' ' || temp == '\n' || temp == EOF) && (temp != '\'') ) { allWords[i][j] = '\0'; break; } else { allWords[i][j] = temp; } printf ("%c", allWords[i][j]); } printf ("\n"); } // close file fclose (filePointer); /* Step 4: Use a simple selection sort algorithm to sort 2D char array */ // PStep 1: Compare two char arrays, and if // (a) c1 > c2, return 2 // (b) c1 == c2, return 1 // (c) c1 < c2, return 0 qsort(allWords, count, sizeof(char[][]), pstrcmp); /* int k = 0, l = 0, m = 0; char currentMax, comparedElement; int max; // the largest element in the current 2D array int elementToSort = 0; // elementToSort determines the element to swap with starting from the left // Outer a iterates through number of swaps needed for (k = 0; k < count - 1; k++) { // times of swaps max = k; // max element set to k // Inner b iterates through successive elements to fish out the largest element for (m = k + 1; m < count - k; m++) { currentMax = allWords[k][l]; comparedElement = allWords[m][l]; // Inner c iterates through successive chars to set the max vars to the largest for (l = 0; (currentMax != '\0' || comparedElement != '\0'); l++) { if (currentMax > comparedElement) break; else if (currentMax < comparedElement) { max = m; currentMax = allWords[m][l]; break; } else if (currentMax == comparedElement) continue; } } // After max (count and string) is determined, perform swap with temp variable char swapTemp[1][20]; int y = 0; do { swapTemp[0][y] = allWords[elementToSort][y]; allWords[elementToSort][y] = allWords[max][y]; allWords[max][y] = swapTemp[0][y]; } while (swapTemp[0][y++] != '\0'); elementToSort++; } */ int a, b; for (a = 0; a < count; a++) { for (b = 0; (temp = allWords[a][b]) != '\0'; b++) { printf ("%c", temp); } printf ("\n"); } // Copy rows to different array and print results /* char arrayCopy [count][20]; int ac, ad; char tempa; for (ac = 0; ac < count; ac++) { for (ad = 0; (tempa = allWords[ac][ad]) != '\0'; ad++) { arrayCopy[ac][ad] = tempa; printf("%c", arrayCopy[ac][ad]); } printf("\n"); } */ /* Step 5: Create two additional arrays: (a) One in which each element contains unique words from char array (b) One which holds the count for the corresponding word in the other array */ /* Step 6: Sort the count array in decreasing order, and print the corresponding array element as well as word count in the console */ return 0; } // Perform housekeeping tasks like freeing up memory and closing file I'm really stuck on the selection sort algorithm. I'm currently using 2D arrays to represent strings, and that worked out fine, but when it came to sorting, using three level nested loops didn't seem to work, I tried to use qsort instead, but I don't fully understand that function as well. Constructive feedback and criticism greatly welcome (...and needed)!

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  • File format for animated scene

    - by stephelton
    I've got a custom OpenGL based rendering engine and I'd like to add support for cinema-type scene animation. The artist that is helping me uses primarily 3DSMax. I'd like a file format for exporting and importing this data. I'm also in need of a file format for skeletal animation data, which may have an impact here. I've been looking at MAXScript to manually export this stuff, which would buy me the most flexibility, but I have virtually no experience with 3DSMax itself, so I get a little lost when it comes to terminology. So I'd like to know what file formats exist for animated scene data, and whether they are appropriate for my use (my fear is that they will be way too broad for my fairly simple needs.) The way I view animated scene data is basically a bunch of references to [animated] models with keyframe-based matrices describing their orientation over time. And probably some special camera stuff to handle perspective. I might also want some event type stuff for adding/removing objects. Is this a sane concept?

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  • copying same file name from client to server using tcp protocol with same size of file

    - by user3686570
    This is the client and server program where a client sends a file to server to save in the server. There is a issuse in that same file name is not getting copied on the server with same file size Please help me in this Client program import socket import sys s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) s.connect(("localhost",9999)) path=raw_input("Please enter the complete PATH of your file : ") f=open (path, "rb") l = f.read(256) while (l): s.sendall(l) l = f.read(10000) s.close() Server Program import socket import sys s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) s.bind(("localhost",9999)) s.listen(10) while True: s, address = s.accept() print address i=1 f = open( str(i),'wb') #open in binary #i=i+1 while (True): l=s.recv(256) #while (l): f.write(l) l=s.recv(256) print 'File recieve succesfully' f.close() #sc.close() s.close() Thanks in advance

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  • How to limit concurrent file access on a Samba share?

    - by JPbuntu
    I have a Ubuntu 12.04 file server running Samba. There are 6 windows machines that access the server, as well as two people that will occasionally access files remotely. The problem that I am having is that the CAD/CAM software we are using doesn't seem to request file locks, meaning if two people open a file at the same time, the first person to close the file will get their changes overwritten if the second person saves the file. I tried changing the smb.conf to strict locking = yes but this doesn't seem to have any effect. File locking with excel seems to work fine, so I know that Samba is using the file locks...if they were put on the file in the first place. Is there a way (either in Samba or Ubuntu) to only allow one user to have a file open at a time? If not does anyone have any suggestions for managing a problem like this?

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  • how to read an arraylist from a txt file in java?

    - by lox
    how to read an arraylist from a txt file in java? my arraylist is the form of: public class Account { String username; String password; } i managed to put some "Accounts" in the a txt file, but now i don't know how to read them. this is how my arraylist look in the txt file: username1 password1 | username2 password2 | etc this is a part of the code i came up with, but it doesn't work. it looks logic to me though... :) . public static void RdAc(String args[]) { ArrayList<Account> peoplelist = new ArrayList<Account>(50); int i,i2,i3; String[] theword = null; try { FileReader fr = new FileReader("myfile.txt"); BufferedReader br = new BufferedReader(fr); String line = ""; while ((line = br.readLine()) != null) { String[] theline = line.split(" | "); for (i = 0; i < theline.length; i++) { theword = theline[i].split(" "); } for(i3=0;i3<theline.length;i3++) { Account people = new Account(); for (i2 = 0; i2 < theword.length; i2++) { people.username = theword[i2]; people.password = theword[i2+1]; peoplelist.add(people); } } } } catch (IOException ex) { System.out.println("Could not read from file"); } }

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  • File Access problems with SLES 10 SP2 OES2 SP1

    - by Blackhawk131
    We have identified a couple of repeatable, demonstrable scenarios with unexplained rejected folder access on our servers for Mac users. Hopefully, this can be presented to Novell for a solution. What we did to demonstrate scenario 1; 1. setup a PC and Mac side-by-side 2. login to our server and open up to a central location on both Mac and PC 3. on the PC in that central location create a folder 4. on the Mac in that central location drag the created folder to the Mac desktop, this should work fine, no problem 5. on the PC rename that folder 6. on the Mac drag a file to that renamed folder, this should error with the following message; a. You cannot copy some of these items to the destination because their names are too long for the destination. Do you want to skip copying these items and continue copying the other items? b. Select skip, response is the filename is copied to the location with zero or small byte size. Try opening it and you get file is corrupted error message. What we did to demonstrate scenario 2; 1. setup a PC and Mac side-by-side 2. login to our server and open up to a central location on both Mac and PC 3. on the PC in that central location create a folder then create a subfolder 4. copy some content into the subfolder 5. on the Mac in that central location drag the created top level folder to the Mac desktop, this should work fine, no problem 6. on the PC rename that subfolder 7. on the Mac drag that top level folder to the Mac desktop, this should error on the Mac with the following; a. The operation cannot be completed because you do not have sufficient privileges for b. The operation cannot be completed because you do not have sufficient privileges for 8. on the Mac, if you open that subfolder you can see the file copied in step 4 above but, you can not open that file, you get the following message if you try; a. There was an error opening this document. You do not have permission to open this file. 9. on the PC drag some content into the top level folder 10. on the Mac you can open that file directly from the server or copy it locally, no problem, however-the subfolder is still corrupted or locked, whichever 11. on the PC rename the top level folder 12. on the Mac that same file just opened in step 10 above is now not accessible, get the following message; a. The document could not be opened. I have observed some variances in the above. For instance, a change on the PC side may take a moment before you can observer or act on the Mac side - kind of like the server is slow to respond. Also, the error message may vary. However, the key is once a folder, or subfolder, gets renamed by a PC, Mac problems commence. The solution is to create a new folder from a PC and copy the contents of the corrupted folder to the new folder and not rename the folder name. This has to be done on a PC because the corrupted folder is not accessible by a Mac user. Another problem that dovetails with the above is that we know certain characters are not allowed for PC folder or filenames. If a Mac user creates a folder with a slash in the file name, from the PC the user does not see that slash in the name. As soon as the PC user copies a file to that folder, the Mac user is locked from that folder. Will get the following error message; - Sorry, the operation could not be completed because an unexpected error occurred. - (Error code - 50) In addition to the above mentioned character issue with folders, the problem is more evil with filenames. If, for example, you create a file with a slash in the filename on a Mac and copy it to the server you will get the following error message; - You cannot copy some of these items to the destination because their names are too long for the destination. Do you want to skip copying these items and continue copying the other items? Select either Stop or Skip buttons. It does not matter which button is selected. The file name gets copied to the destination location at a reduced size. Depending on the file type, the icon associated with the file may or may not be present. Furthermore, if you open that file on the server you will get the following message; - Couldnt open the file. It may be corrupt or a file format that doesnt recognize. From the users perspective, if they are not observant of the icon or file size, they may disregard the error message and think their file has copied as intended. Only later do they discover the file is corrupt if they open that file. I want to make a note on this problem. It is the PC causing the issue. You can change folder and file names all day on a MAC and you don't have a problem as long as a character is not the issue. Once you change the file name or folder name from a PC the entire folder structure from that level down is corrupted. But it has to be resolved from a PC by creating a new folder and copying the contents to the new folder like stated above. Is something not configured correctly? SUSE Linux Enterprise Server 10 (x86_64) VERSION = 10 PATCHLEVEL = 2 LSB_VERSION="core-2.0-noarch:core-3.0-noarch:core-2.0-x86_64:core-3.0-x86_64" Novell Open Enterprise Server 2.0.1 (x86_64) VERSION = 2.0.1 PATCHLEVEL = 1 BUILD Note: We use Novell clients on all windows systems to connect to the servers for file access and network storage. We use AFP to allow OSx systems to connect to servers.

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  • File Access problems with SLES 10 SP2 OES2 SP1

    - by Blackhawk131
    We have identified a couple of repeatable, demonstrable scenarios with unexplained rejected folder access on our servers for Mac users. Hopefully, this can be presented to Novell for a solution. What we did to demonstrate scenario 1; 1. setup a PC and Mac side-by-side 2. login to our server and open up to a central location on both Mac and PC 3. on the PC in that central location create a folder 4. on the Mac in that central location drag the created folder to the Mac desktop, this should work fine, no problem 5. on the PC rename that folder 6. on the Mac drag a file to that renamed folder, this should error with the following message; a. You cannot copy some of these items to the destination because their names are too long for the destination. Do you want to skip copying these items and continue copying the other items? b. Select skip, response is the filename is copied to the location with zero or small byte size. Try opening it and you get file is corrupted error message. What we did to demonstrate scenario 2; 1. setup a PC and Mac side-by-side 2. login to our server and open up to a central location on both Mac and PC 3. on the PC in that central location create a folder then create a subfolder 4. copy some content into the subfolder 5. on the Mac in that central location drag the created top level folder to the Mac desktop, this should work fine, no problem 6. on the PC rename that subfolder 7. on the Mac drag that top level folder to the Mac desktop, this should error on the Mac with the following; a. The operation cannot be completed because you do not have sufficient privileges for b. The operation cannot be completed because you do not have sufficient privileges for 8. on the Mac, if you open that subfolder you can see the file copied in step 4 above but, you can not open that file, you get the following message if you try; a. There was an error opening this document. You do not have permission to open this file. 9. on the PC drag some content into the top level folder 10. on the Mac you can open that file directly from the server or copy it locally, no problem, however-the subfolder is still corrupted or locked, whichever 11. on the PC rename the top level folder 12. on the Mac that same file just opened in step 10 above is now not accessible, get the following message; a. The document could not be opened. I have observed some variances in the above. For instance, a change on the PC side may take a moment before you can observer or act on the Mac side - kind of like the server is slow to respond. Also, the error message may vary. However, the key is once a folder, or subfolder, gets renamed by a PC, Mac problems commence. The solution is to create a new folder from a PC and copy the contents of the corrupted folder to the new folder and not rename the folder name. This has to be done on a PC because the corrupted folder is not accessible by a Mac user. Another problem that dovetails with the above is that we know certain characters are not allowed for PC folder or filenames. If a Mac user creates a folder with a slash in the file name, from the PC the user does not see that slash in the name. As soon as the PC user copies a file to that folder, the Mac user is locked from that folder. Will get the following error message; - Sorry, the operation could not be completed because an unexpected error occurred. - (Error code - 50) In addition to the above mentioned character issue with folders, the problem is more evil with filenames. If, for example, you create a file with a slash in the filename on a Mac and copy it to the server you will get the following error message; - You cannot copy some of these items to the destination because their names are too long for the destination. Do you want to skip copying these items and continue copying the other items? Select either Stop or Skip buttons. It does not matter which button is selected. The file name gets copied to the destination location at a reduced size. Depending on the file type, the icon associated with the file may or may not be present. Furthermore, if you open that file on the server you will get the following message; - Couldnt open the file. It may be corrupt or a file format that doesnt recognize. From the users perspective, if they are not observant of the icon or file size, they may disregard the error message and think their file has copied as intended. Only later do they discover the file is corrupt if they open that file. I want to make a note on this problem. It is the PC causing the issue. You can change folder and file names all day on a MAC and you don't have a problem as long as a character is not the issue. Once you change the file name or folder name from a PC the entire folder structure from that level down is corrupted. But it has to be resolved from a PC by creating a new folder and copying the contents to the new folder like stated above. Is something not configured correctly? SUSE Linux Enterprise Server 10 (x86_64) VERSION = 10 PATCHLEVEL = 2 LSB_VERSION="core-2.0-noarch:core-3.0-noarch:core-2.0-x86_64:core-3.0-x86_64" Novell Open Enterprise Server 2.0.1 (x86_64) VERSION = 2.0.1 PATCHLEVEL = 1 BUILD Note: We use Novell clients on all windows systems to connect to the servers for file access and network storage. We use AFP to allow OSx systems to connect to servers.

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  • How I use RegExp in my Java program? [migrated]

    - by MIH1406
    I have the following string examples: 00001 1 12 123 00002 3 7 321 00003 99 23 332 00004 192 50 912 In a separate text file. Numbers are separated by tabs not spaces. I tried to read the file and print each line if it matches a given RegExp, but I could not find the suitable RegExp for these lines. private static void readFile() { String fileName = "processes.lst"; FileReader file = null; String result = ""; try { file = new FileReader(fileName); BufferedReader reader = new BufferedReader(file); String line = null; String regEx = "[0-9]\t[0-9]\t[0-9]\t[0-9]"; while((line = reader.readLine()) != null) { if(line.matches(regEx)) { result += "\n" + line; } } } catch(Exception e) { System.out.println(e.getMessage()); } finally { if(file != null) try { file.close(); } catch(Exception e) { System.out.println(e.getMessage()); } } System.out.println(result); } I ended up without any string being printed!!

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  • java AbstractMethodError

    - by Akhil
    How to handle this error in lucene: java.lang.AbstractMethodError: org.apache.lucene.store.Directory.listAll()[Ljava/lang/String; at org.apache.lucene.index.SegmentInfos$FindSegmentsFile.run(SegmentInfos.java:568) at org.apache.lucene.index.DirectoryReader.open(DirectoryReader.java:69) at org.apache.lucene.index.IndexReader.open(IndexReader.java:316) at org.apache.lucene.index.IndexReader.open(IndexReader.java:188) I am making a lucene function call but unfortunately it itself calls an abstract method of some class, as is evident from the error above. What is the work around for this? Thanks, --Akhil

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  • Java applets vs Silverlight vs Flash (Flex)

    - by Peter Gfader
    Everybody talks about Silverlight and Flash and Flex and how cool etc... Java applets are very similar to Silverlight and Flex, but Java applets exist since 1995. What is the reason we don't have any cool Java applet applications around? My guesses so far: start up time of Java applet, restricted network connectivity, lack of dev tools, ... Are there any cool Java applets around? Please post links

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  • Connecting to MSSQL 2008 from Java

    - by Xinus
    I am trying to connect to MSSQL 2008 server from Java here is a program import java.sql.*; public class connectURL { public static void main(String[] args) { // Create a variable for the connection string. String connectionUrl = "jdbc:sqlserver://localhost/SQLEXPRESS/Databases/HelloWorld:1433;";// + //"databaseName=HelloWorld;integratedSecurity=true;"; // Declare the JDBC objects. Connection con = null; Statement stmt = null; ResultSet rs = null; try { // Establish the connection. Class.forName("com.microsoft.sqlserver.jdbc.SQLServerDriver"); con = DriverManager.getConnection(connectionUrl); // Create and execute an SQL statement that returns some data. String SQL = "SELECT TOP 10 * FROM Person.Contact"; stmt = con.createStatement(); rs = stmt.executeQuery(SQL); // Iterate through the data in the result set and display it. while (rs.next()) { System.out.println(rs.getString(4) + " " + rs.getString(6)); } } // Handle any errors that may have occurred. catch (Exception e) { e.printStackTrace(); } finally { if (rs != null) try { rs.close(); } catch(Exception e) {} if (stmt != null) try { stmt.close(); } catch(Exception e) {} if (con != null) try { con.close(); } catch(Exception e) {} } } } But it shows error as com.microsoft.sqlserver.jdbc.SQLServerException: The TCP/IP connection to the host localhost/SQLEXPRESS/Databases/HelloWorld, port 1433 has failed. Error: "null. Verify the connection properties, check that an instance of SQL Server is running on the host and accepting TCP/IP connections at the port, and that no firewall is blocking TCP connections to the port.". at com.microsoft.sqlserver.jdbc.SQLServerException.makeFromDriverError(SQLServerException.java:170) at com.microsoft.sqlserver.jdbc.SQLServerConnection.connectHelper(SQLServerConnection.java:1049) at com.microsoft.sqlserver.jdbc.SQLServerConnection.login(SQLServerConnection.java:833) at com.microsoft.sqlserver.jdbc.SQLServerConnection.connect(SQLServerConnection.java:716) at com.microsoft.sqlserver.jdbc.SQLServerDriver.connect(SQLServerDriver.java:841) at java.sql.DriverManager.getConnection(Unknown Source) at java.sql.DriverManager.getConnection(Unknown Source) at connectURL.main(connectURL.java:43) I have given followed all the instructions as given in http://teamtutorials.com/database-tutorials/configuring-and-creating-a-database-in-ms-sql-2008 What can be the problem ?

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