variadic constructors
- by FredOverflow
Are variadic constructors supposed to hide the implicitly generated ones, i.e. the default constructor and the copy constructor?
struct Foo
{
template<typename... Args> Foo(Args&&... x)
{
std::cout << "inside the variadic constructor\n";
}
};
int main()
{
Foo a;
Foo b(a);
}
Somehow I was expecting this to print nothing after reading this answer, but it prints inside the variadic constructor twice on g++ 4.5.0 :( Is this behavior correct?
