Search Results

Search found 34397 results on 1376 pages for 'php socket'.

Page 834/1376 | < Previous Page | 830 831 832 833 834 835 836 837 838 839 840 841  | Next Page >

  • Which MySql line is faster:

    - by Camran
    I have a classified_id variable which matches one document in a MySql table. I am currently fetching the information about that one record like this: SELECT * FROM table WHERE table.classified_id = $classified_id I wonder if there is a faster approach, for example like this: SELECT 1 FROM table WHERE table.classified_id = $classified_id Wont the last one only select 1 record, which is exactly what I need, so that it doesn't have to scan the entire table but instead stops searching for records after 1 is found? Or am I dreaming this? Thanks

    Read the article

  • Loop through Array with conditional output based on key/value pair

    - by Daniel C
    I have an array with the following columns: Task Status I would like to print out a table that shows a list of the Tasks, but not the Status column. Instead, for Tasks where the Status = 0, I want to add a tag <del> to make the completed task be crossed out. Here's my current code: foreach ($row as $key => $val){ if ($key != 'Status') print "<td>$val</td>"; else if ($val == '0') print "<td><del>$val</del></td>"; } This seems to be correct, but when I print it out, it prints all the tasks with the <del> tag. So basically the "else" clause is being run every time. Here is the var_dump($row): array 'Task' => string 'Task A' (length=6) 'Status' => string '3' (length=1) array 'Task' => string 'Task B' (length=6) 'Status' => string '0' (length=1)

    Read the article

  • Is there a way to echo this only once and not have it repeat?

    - by Fernando
    I have the following query: $select = mysql_query("SELECT * FROM posts WHERE id = $postIds"); while ($return = mysql_fetch_assoc($select)) { $postUrl = $return['url']; $postTitle = $return['title']; echo "<h1><a href='$postUrl'>".$postTitle."</a></h1>"; } Now the problem is, the variable $postIds often times contain the same id multiple times. So the title of the post echos itself multiple times. Is there a way to have it echo only once?

    Read the article

  • What is the difference?

    - by Eragonio
    I try out CakePHP. I follow this Tutorial and can't find out why this code doesn't work. The code from the tutorial works fine. echo $html -> link('Löschen', array('action' => 'delete', 'id' => $post['Post']['id']), null, 'Sind Sie sicher?' );

    Read the article

  • Unlink deleting more than just the files passed to it.

    - by RMcLeod
    I'm creating an SQL file, placing this file into a zip file with some images and then deleting the SQL file with unlink.Strange thing is it deletes the zip file as well. if (file_put_contents($sqlFileName, $sql) !== false) { $zip = new ZipArchive; if ($zip->open($workingDir . $now . '.zip', ZipArchive::CREATE) === true) { $zip->addFile($sqlFileName, basename($sqlFileName)); if(! empty($images)) { foreach ($images as $image) { $zip->addFile($imagesDir . $image, $image); } } } unlink($sqlFileName); }

    Read the article

  • file_get_contents not displaying any data

    - by Lance
    I'm doing $info = file_get_contents('http://USERNAME:[email protected]/v2/sales?client_key=CLIENT_KEY'); $info returns nothing. However, when I put the URL into my browser, JSON appears. I tried using cURL without any luck. $data = array('client_key' => 'CLIENT_KEY'); $link = "http://api.appfigures.com/v2/sales"; $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $link); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch, CURLOPT_POST, count($data)); curl_setopt($ch, CURLOPT_POSTFIELDS, http_build_query($data)); curl_setopt($ch, CURLOPT_USERPWD, "username:password"); curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_BASIC); $jsonData = curl_exec($ch); curl_close($ch); print_r($jsonData); Thanks

    Read the article

  • Converting files to blob to save in database

    - by jimbo
    I have an old user site that we are currently updating. The site's users have previously uploaded profile pics that are stored in a directory. I am now wanting to keep these profile images in the database, (easy to backup all data) but am having trouble working out how to do it. There are a lot of tutorials talking about do ing this from files that have just been uploaded and using the tmp name etc, but how can I re-create with files that have already been uploaded? I have looked into $data = file_get_contents($filename); Which seems to create a binary file, but doesn't seem to save in database with: mysql_query("UPDATE profiles SET company_logo = mysql_real_escape_string('".$data."') WHERE id = 1 ") or die(mysql_error());

    Read the article

  • How to convert my mysql data into this?

    - by sky
    <script type="text/javascript"> var cityList = new Array(....etc), signImgList = new Array('http:\/\/pic.sitename.com:80\/file\/11\/34\/01\/22\/default\/SIGN11340122_48x48.jpg?t=1257391453468'....etc), titleList = new Array(....etc), userSex = new Array(....etc), userAge = new Array('19','26'....etc), userMid = new Array('lwowl','kylin0621'....etc); </script>

    Read the article

  • MySQL "NULL" questions

    - by Camran
    I have a table with several columns. Sometimes some of these column fields may be empty (ie. I won't use them in some cases). My questions: Would it be smart to set them to NULL in phpmyadmin? What does the "NULL" property actually do? Would I gain anything at all by setting them to NULL? Is it possible to use a NULL field the same way even though it is set to null?

    Read the article

  • Spreadsheet_Excel_Writer large data output is damaged

    - by dr3w
    I use Spreadsheet_Excel_Writer to generate .xls file and it works fine until I have to deal with a large amount of data. On certain stage it just writes some nonsense chars and quits filling certain columns. However some columns are field up to the end (generally numeric data) I'm not quite sure how the xls document is formed: row by row, or col by col... Also it is obviously not an error in a string, because when i cut out some data, the error appears a little bit further. I think there is no need in all of my code here are some essentials $filename = 'file.xls'; $workbook = & new Spreadsheet_Excel_Writer(); $workbook->setVersion(8); $contents =& $workbook->addWorksheet('Logistics'); $contents->setInputEncoding('UTF-8'); $workbook->send($filename); //here is the part where I write data down $contents->write(0, 0, 'Field A'); $contents->write(0, 1, 'Field B'); $contents->write(0, 2, 'Field C'); $ROW=1; foreach($ordersArr as $key=>$val){ $contents->write($ROW, 0, $val['a']); $contents->write($ROW, 1, $val['b']); $contents->write($ROW, 2, $val['c']); $ROW++; } $workbook->close();

    Read the article

  • Javascript in CakePHP

    - by user445803
    Hello, I had one page in Views in CakePHP, it have normal javascript block, Just inserted: <script language="JavaScript" type="text/javascript"> ---code--- </script> Inside page, and it was all working okay... But now... It doesn't show... How can I change configuration or something to enable showing javascript blocks without CakePHP commands. Javascript needs data from that page so I can't use outer file, and it's too long to use $javascript-codeBlock Is there any way to reconfigure stupid CakePHP to start showing those blocks? Some files are showing javascript, and it's working all okay, but some of them won't show... Please help...

    Read the article

  • mysql : possible to put IF statment in LEFT JOIN ?

    - by Haroldo
    Ok so i want to get an artists info from the db, but i want to know if they have any forthcoming events. To do this i need to traverse 2 tables, where events_artists is a 2 col link table... (this doesnt work but is what id like to do) SELECT art.*, events.event_id FROM art LEFT JOIN events_artists ON art.art_id = events_artists.art_id LEFT JOIN events ON events_artists.event_id = events.event_id IF ( {criteria} ) what should i be doing here to get this to work?!!

    Read the article

  • zend form check record no exists in database

    - by Yafa Su
    I have a form that check if email exists in the database within 2 tables. I'm using Zend_Validate_Db_NoRecordExists for both validate, but it only check the second one. Any idea why it's not working? class Application_Form_ReferUser extends Zend_Form { public $email, $freeDownload, $buyNow; public function init() { $this->setName('referUser'); $EmailExists = new Zend_Validate_Db_NoRecordExists( array( 'table' => 'referrals', 'field' => 'email' ) ); $EmailExists2 = new Zend_Validate_Db_NoRecordExists( array( 'table' => 'users', 'field' => 'email' ) ); $EmailExists->setMessage('This e-mail is already taken'); $EmailExists2->setMessage('This e-mail is already taken'); $this->email = $this->createElement('text', 'email') ->setLabel('Email') ->addValidator($EmailExists) ->addValidator($EmailExists2) ->addValidator('EmailAddress') ->setRequired(true); $this->freeDownload = $this->createElement('button', 'btn_free_download') ->setLabel('Free Download') ->setAttrib('type', 'submit'); $this->buyNow = $this->createElement('button', 'btn_buy_now') ->setLabel('Buy Now') ->setAttrib('type', 'submit'); $this->addElements(array($this->email, $this->freeDownload, $this->buyNow)); $elementDecorators = array( 'ViewHelper' ); $this->setElementDecorators($elementDecorators); } }

    Read the article

  • how to unzip uploaded zip file?

    - by Jaydeepsinh Jadeja
    I am trying to upload a zipped file using codeigniter framework with following code function do_upload() { $name=time(); $config['upload_path'] = './uploadedModules/'; $config['allowed_types'] = 'zip|rar'; $this->load->library('upload', $config); if ( ! $this->upload->do_upload()) { $error = array('error' => $this->upload->display_errors()); $this->load->view('upload_view', $error); } else { $data = array('upload_data' => $this->upload->data()); $this->load->library('unzip'); // Optional: Only take out these files, anything else is ignored $this->unzip->allow(array('css', 'js', 'png', 'gif', 'jpeg', 'jpg', 'tpl', 'html', 'swf')); $this->unzip->extract('./uploadedModules/'.$data['upload_data']['file_name'], './application/modules/'); $pieces = explode(".", $data['upload_data']['file_name']); $title=$pieces[0]; $status=1; $core=0; $this->addons_model->insertNewModule($title,$status,$core); } } But the main problem is that when extract function is called, it extract the zip but the result is empty folder. Is there any way to overcome this problem?

    Read the article

  • Extending Zend_Log for application-specific need

    - by spdaly
    I am building a Zend Framework application that performs jobs submitted by the user. The actions taken need to be logged to a database. I would like to correlate the job with its log entries. Instead of creating my own logging class, I would like to extend Zend_Log since it provides 99% of the functionality that I need. All I need to do is add a foreign key of the job id to the log data model. Is this possible? I'm also looking for a good example of Zend_Log writing to a database. I haven't searched SO yet. I will do that after I post this. Thanks in advance... Steve

    Read the article

  • make 2 thumbnails at once in codeigniter

    - by sonill
    hello everybody! can anyone tell me how to create 2 different thumbnails of same images with different sizes and location in codeigniter. I have created a upload function and another thumbnail generation function, it works fine but can't sort out how to create 2 different thumbnail at accordingly at once. any help will be appreciated.

    Read the article

  • check for several conditions when a user logs in

    - by paul
    I would like to accomplish the following: If a username or password field is null, notify the user. If user name already exists, do not insert into the database and notify user to create a different name. if the username is unique and password is not null, return the username to the user. As of now it always returns "Please enter a different user name." I believe the issue has to do with the database query but I am not sure. If anyone can have a look and see if I am making an error, I greatly appreciate it, thanks. if ($userName or $userPassword = null) { echo "Please enter a user name and password or return to the homepage."; } elseif (mysql_num_rows(mysql_query("SELECT count(userName) FROM logininfo WHERE userName = '$userName'")) ==1) { echo "Please enter a different user name."; } elseif ($userName and $userPassword != null) { echo "Your login name is: $userName"; }

    Read the article

  • opening word document contailning macros using textarea

    - by avani-nature
    Hai frnds i am avani here,actually 1.i amhaving one word document which contains macros i wann to open it in textarea.. 2.i am able to open the word document which is not containing macros 3.i am not able to open the document which contains macros 4.i am using below code 5.please do help me anyone i am thinking its some what impossible { //echo $aud; $filename = 'C:/xampp/htdocs/mts/sites/default/files/a.doc'; //echo $filename; if(isset($_REQUEST['Save'])){ $somecontent = stripslashes($_POST['somecontent']); // Let's make sure the file exists and is writable first. if (is_writable($filename)) { // In our example we're opening $filename in append mode. // The file pointer is at the bottom of the file hence // that's where $somecontent will go when we fwrite() it. if (!$handle = fopen($filename, 'w')) { echo "Cannot open file ($filename)"; exit; } // Write $somecontent to our opened file. if (fwrite($handle, $somecontent) === FALSE) { echo "Cannot write to file ($filename)"; exit; } echo "Success, wrote ($somecontent) to file ($filename) - Continue - "; fclose($handle); } else { echo "The file $filename is not writable"; } } else{ // get contents of a file into a string $handle = fopen($filename, "r"); $somecontent = fread($handle, filesize($filename)); $word = new COM("word.application") or die ("Could not initialise MS Word object."); $word-Documents-Open(realpath("$filename")); // Extract content. $somecontent = (string) $word-ActiveDocument-Content; //echo $somecontent; $word-ActiveDocument-Close(false); $word-Quit(); $word = null; unset($word); fclose($handle); } ? Edit file -------- ?

    Read the article

  • Creating array from two arrays

    - by binoculars
    I'm having troubles trying to create a certain array. Basicly, I have an array like this: [0] => Array ( [id] => 12341241 [type] => "Blue" ) [1] => Array ( [id] => 52454235 [type] => "Blue" ) [2] => Array ( [id] => 848437437 [type] => "Blue" ) [3] => Array ( [id] => 387372723 [type] => "Blue" ) [4] => Array ( [id] => 73732623 [type] => "Blue" ) ... Next, I have an array like this: [0] => Array ( [id] => 34141 [type] => "Red" ) [1] => Array ( [id] => 253532 [type] => "Red" ) [2] => Array ( [id] => 94274 [type] => "Red" ) I want to construct an array, which is a combination of the two above, using this rule: after 3 Blues, there must be a Red: Blue1 Blue2 Blue3 Red1 Blue4 Blue5 Blue6 Red2 Blue7 Blue8 Blue9 Red3 Note that the their can be more Red's than Blue's, but also more Blue's than Red's. If the Red's run out, it should begin with the first one again. Example: let's say there are only two Red's: Blue1 Blue2 Blue3 Red1 Blue4 Blue5 Blue6 Red2 Blue7 Blue8 Blue9 Red1 ... ... If the Blue's run out, the Red's should append until they run out too. Example: let's say there are 5 Blue's, and 5 Red's: Blue1 Blue2 Blue3 Red1 Blue4 Blue5 Red2 Red3 Red4 Red5 Note: the arrays come from mysql-fetches. Maybe it's better to fetch them while building the new array? Anyway, the while-loops got to me, I can't figure it out... Any help is much appreciated!

    Read the article

  • Magento order status change events

    - by Christian
    Hi people, I want to change via web service a remote inventory, I know that via Event Observer Method can triger my code, but I don't know which event is useful to complete my task, like on_order_complete, is there an updated list of events or more documentation?

    Read the article

  • dwoo template variables inside JavaScript?

    - by user344711
    Hi everyone! i have this code. {if $loginUrl} {literal} <script type="text/javascript"> var newwindow; var intId; function login() { var screenX = typeof window.screenX != 'undefined' ? window.screenX : window.screenLeft, screenY = typeof window.screenY != 'undefined' ? window.screenY : window.screenTop, outerWidth = typeof window.outerWidth != 'undefined' ? window.outerWidth : document.body.clientWidth, outerHeight = typeof window.outerHeight != 'undefined' ? window.outerHeight : (document.body.clientHeight - 22), width = 500, height = 270, left = parseInt(screenX + ((outerWidth - width) / 2), 10), top = parseInt(screenY + ((outerHeight - height) / 2.5), 10), features = ( 'width=' + width + ',height=' + height + ',left=' + left + ',top=' + top ); newwindow=window.open('{$loginUrl}','Login by facebook',features); if (window.focus) {newwindow.focus()} return false; } </script> {/literal} {/if} It is dwoo templates, i wonder how can i use my dwoo variables inside javascript? im trying to do it just at you can see at the code, but it doesnt work. I need to warp my code between {literal} so it can work.

    Read the article

  • MySQL Query Where Column Like Column

    - by shmeeps
    I'm working on a small project that involves grabbing a list of contacts which are stored for each group. Essentially, the database is set up so that each group has a primary and secondary contact stored as, unsurprisingly, Group.Primary and Group.Secondary. The objective is to pull every Primary and Secondary contact for each Group and display them in a sortable table. I have the sortable table all worked out, but I have come across a small problem. Each primary and secondary field can have more than one contact separated by a comma. For instance, if Primary contained 123,256 , it would need to pull both Contacts with IDs 123 and 256. I had intended to use a query formatted like this: SELECT * FROM Group G, Contacts C WHERE G.Primary LIKE %C.ID% OR G.Secondary LIKE %C.ID% so that I could just skip the comma part, but I can't seem to find a working query for this. My question to you is, am I just overlooking something here? Is there a simple query that would let me do this? Or am I better off getting the groups and contacts separately, and combine the two later. I think the former is a little easier to understand when read, which is a plus as this is a shared project, but if that is not possible I will do the latter. This code is simplified, but it gets the point across.

    Read the article

  • laravel multiple where clauses within a loop

    - by user1424508
    Pretty much I want the query to select all records of users that are 25 years old AND are either between 150-170cm OR 190-200cm. I have this query written down below. However the problem is it keeps getting 25 year olds OR people who are 190-200cm instead of 25 year olds that are 150-170 OR 25 year olds that 190-200cm tall. How can I fix this? thanks $heightarray=array(array(150,170),array(190,200)); $user->where('age',25); for($i=0;$i<count($heightarray);i++){ if($i==0){ $user->whereBetween('height',$heightarray[$i]) }else{ $user->orWhereBetween('height',$heightarray[$i]) } } $user->get(); Edit: I tried advanced wheres (http://laravel.com/docs/queries#advanced-wheres) and it doesn't work for me as I cannot pass the $heightarray parameter into the closure. from laravel documentation DB::table('users') ->where('name', '=', 'John') ->orWhere(function($query) { $query->where('votes', '>', 100) ->where('title', '<>', 'Admin'); }) ->get();

    Read the article

< Previous Page | 830 831 832 833 834 835 836 837 838 839 840 841  | Next Page >