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  • JSF works only with the .xhtml ending

    - by ThreeFingerMark
    Hello, i start with the programming of a JSF Website. At the moment all files have the .xhtml ending. When i go to http://localhost:8080/myProject/start.jsf everything is all right. But when i rename the file from start.xhtml to start.jsf i became a NoClassDefFound Error. What is my mistake? <servlet-name>Faces Servlet</servlet-name> <servlet-class>javax.faces.webapp.FacesServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>Faces Servlet</servlet-name> <url-pattern>*.jsf</url-pattern> </servlet-mapping> <context-param> <param-name>javax.faces.PROJECT_STAGE</param-name> <param-value>Development</param-value> </context-param>

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  • What is design principle behind Servlets being Singleton

    - by Sandeep Jindal
    A servlet container "generally" create one instance of a servlet and different threads of the same instance to serve multiple requests. (I know this can be changed using deprecated SingleThreadModel and other features, but this is the usual way). I thought, the simple reason behind this is performance gain, as creating threads is better than creating instances. But it seems this is not the reason. On the other hand, creating instances have little advantage that developers never have to worry about thread safety. I am trying to understand the reason for this decision over the trade-off of thread-safety.

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  • Help with a sort method

    - by Capsud
    Hi there, If i have an array of strings for example Static final String[] TEST = new String[] { "g","a","b","t","e" }; How would i go about sorting this in alphabetical order please?

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  • Using inheritance and polymorphism to solve a common game problem

    - by Barry Brown
    I have two classes; let's call them Ogre and Wizard. (All fields are public to make the example easier to type in.) public class Ogre { int weight; int height; int axeLength; } public class Wizard { int age; int IQ; int height; } In each class I can create a method called, say, battle() that will determine who will win if an Ogre meets and Ogre or a Wizard meets a Wizard. Here's an example. If an Ogre meets an Ogre, the heavier one wins. But if the weight is the same, the one with the longer axe wins. public Ogre battle(Ogre o) { if (this.height > o.height) return this; else if (this.height < o.height) return o; else if (this.axeLength > o.axeLength) return this; else if (this.axeLength < o.axeLength) return o; else return this; // default case } We can make a similar method for Wizards. But what if a Wizard meets an Ogre? We could of course make a method for that, comparing, say, just the heights. public Wizard battle(Ogre o) { if (this.height > o.height) return this; else if (this.height < o.height) return o; else return this; } And we'd make a similar one for Ogres that meet Wizard. But things get out of hand if we have to add more character types to the program. This is where I get stuck. One obvious solution is to create a Character class with the common traits. Ogre and Wizard inherit from the Character and extend it to include the other traits that define each one. public class Character { int height; public Character battle(Character c) { if (this.height > c.height) return this; else if (this.height < c.height) return c; else return this; } } Is there a better way to organize the classes? I've looked at the strategy pattern and the mediator pattern, but I'm not sure how either of them (if any) could help here. My goal is to reach some kind of common battle method, so that if an Ogre meets an Ogre it uses the Ogre-vs-Ogre battle, but if an Ogre meets a Wizard, it uses a more generic one. Further, what if the characters that meet share no common traits? How can we decide who wins a battle?

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  • Returning a variable in a public void...

    - by James Rattray
    Hello, I'm abit new to programming Android App's, however I have come across a problem, I can't find a way to make global variables -unlike other coding like php or VB.NET, are global variables possible? If not can someone find a way (and if possible implement the way into the code I will provide below) to get a value from the variable 'songtoplay' so I can use in another Public Void... Here is the code: final Spinner hubSpinner = (Spinner) findViewById(R.id.myspinner); ArrayAdapter adapter = ArrayAdapter.createFromResource( this, R.array.colours, android.R.layout.simple_spinner_item); adapter .setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item); hubSpinner.setAdapter(adapter); // hubSpinner.setOnItemSelectedListener(new OnItemSelectedListener() { public void onItemSelected(AdapterView<?> parentView, View selectedItemView, int position, long id) { //code Object ttestt = hubSpinner.getSelectedItem(); final String test2 = ttestt.toString(); Toast message1 = Toast.makeText(Textbox.this, test2, Toast.LENGTH_LONG); message1.show(); String songtoplay = test2; // Need songtoplay to be available in another 'Public Void' } public void onNothingSelected(AdapterView<?> parentView) { //Code } }); Basically, it gets the value from the Spinner 'hubSpinner' and displays it in a Toast. I then want it to return a value for string variable 'songtoplay' -or find a way to make it global or useable in another Public Void, (Which is will a button, -loading the song to be played) Please help me, Thanks alot. James

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  • apache cxf: multiple endpoint /multipleCXFServlet servlet

    - by robinmag
    Hi, I've a cxf webservice with multiple endpoint. I've succesfully deploy it. The problem is all endpoint's WSDL appear in the same servlet URL. Can i have 2 org.apache.cxf.transport.servlet.CXFServlet servlet in the same web.xml and each servlet serve one endpoint so that i have endpoint1 at http:/locahost/app/endpoint1 and endpoint2 at http:/locahost/app/endpoint2 . Thank you.

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  • How to Canonicalize a Stax XML object.

    - by Enrique San Martín
    Hello, i want to Canonicalize a Stax object, the program it's doing it with DOM, but dom can't manage big XML documents (like 1GB), so STAX it's the solution. The Code that i have it's: File file=new File("big-1gb.xml"); org.apache.xml.security.Init.init(); DocumentBuilderFactory dfactory = DocumentBuilderFactory.newInstance(); DocumentBuilder documentBuilder = dfactory.newDocumentBuilder(); Document doc = documentBuilder.parse(file); Canonicalizer c14n = Canonicalizer.getInstance("http://www.w3.org/TR/2001/REC-xml-c14n-20010315"); outputBytes = c14n.canonicalizeSubtree(doc.getElementsByTagName("SomeTag").item(0)); The idea it's do the code below with Stax... Thx :)

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  • 500 Worker Threads, what kind of thread pool?

    - by Submerged
    I am wondering if this is the best way to do this. I have about 500 threads that run indefinitely, but Thread.sleep for a minute when done one cycle of processing. ExecutorService es = Executors.newFixedThreadPool(list.size()+1); for (int i = 0; i < list.size(); i++) { es.execute(coreAppVector.elementAt(i)); //coreAppVector is a vector of extends thread objects } The code that is executing is really simple and basically just this class aThread extends Thread { public void run(){ while(true){ Thread.sleep(ONE_MINUTE); //Lots of computation every minute } } } I do need a separate threads for each running task, so changing the architecture isn't an option. I tried making my threadPool size equal to Runtime.getRuntime().availableProcessors() which attempted to run all 500 threads, but only let 8 (4xhyperthreading) of them execute. The other threads wouldn't surrender and let other threads have their turn. I tried putting in a wait() and notify(), but still no luck. If anyone has a simple example or some tips, I would be grateful! Well, the design is arguably flawed. The threads implement Genetic-Programming or GP, a type of learning algorithm. Each thread analyzes advanced trends makes predictions. If the thread ever completes, the learning is lost. That said, I was hoping that sleep() would allow me to share some of the resources while one thread isn't "learning"

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  • Case Insensitive Ternary Search Tree

    - by Yan Cheng CHEOK
    I had been using Ternary Search Tree for a while, as the data structure to implement a auto complete drop down combo box. Which means, when user type "fo", the drop down combo box will display foo food football The problem is, my current used of Ternary Search Tree is case sensitive. My implementation is as follow. It had been used by real world for around 1++ yeas. Hence, I consider it as quite reliable. My Ternary Search Tree code However, I am looking for a case insensitive Ternary Search Tree, which means, when I type "fo", the drop down combo box will show me foO Food fooTBall Here are some key interface for TST, where I hope the new case insentive TST may have similar interface too. /** * Stores value in the TernarySearchTree. The value may be retrieved using key. * @param key A string that indexes the object to be stored. * @param value The object to be stored in the tree. */ public void put(String key, E value) { getOrCreateNode(key).data = value; } /** * Retrieve the object indexed by key. * @param key A String index. * @return Object The object retrieved from the TernarySearchTree. */ public E get(String key) { TSTNode<E> node = getNode(key); if(node==null) return null; return node.data; } An example of usage is as follow. TSTSearchEngine is using TernarySearchTree as the core backbone. Example usage of Ternary Search Tree // There is stock named microsoft and MICROChip inside stocks ArrayList. TSTSearchEngine<Stock> engine = TSTSearchEngine<Stock>(stocks); // I wish it would return microsoft and MICROCHIP. Currently, it just return microsoft. List<Stock> results = engine.searchAll("micro");

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  • Getting .jar file onto a mobile phone error

    - by me123
    Hello, I am trying to get a .jar file onto my mobile device. I have written a j2me application and I want to get it onto my phone. I have developed it in eclipse galileo and I export my project folder to a jar. When I try to download the jar file from the internet onto my phone I get an "incorrect description" error. Does anyone know how to get a j2me application onto a mobile device or why I may be getting this error? Thanks in advance.

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  • using internationalization on list data

    - by singh
    i am using Struts2 in application. <s:iterator value="listObject"> <s:component template="abc.vm"> <s:param name="text" value="listValue" /> <s:param name="prefix" value="listIndex" /> </s:component> </s:iterator> listValue is a values of list. i am using iterator to traverse the list. now on listValue, i want to put here internationalization concept.so that all the list value can be display based on Locale which store in a list. please suggest!

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  • Adding additional components to a web page after rendering by Wicket

    - by Andrew Fielden
    I have a requirement to create a web page using Wicket 1.5, which can present a variable number of panels to capture user input. All the panels have the same structure. The page would start off with one panel, and includes a button to dynamically add more as required. So the number of panels is unknown at the time the page is initially rendered. Effectively I'd be altering the structure of the page dynamically. This is possible in Javascript, using document.addElement() I've done a similar thing in the past by creating all the components on page load, and selectively showing/hiding components. The difference here is that the number of components (panels) is initially unknown. I'm unsure as to how this would be achieved with Wicket.

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  • How can one extra rdf:about or rdf:ID properties from triples using SPARKQL?

    - by lennyks
    It seemed a trivial matter at the beginning but so far I had not managed to get unique identifier for a given resource using SPARKQL. What I mean is given and then some properties identifiying this resource in perfect world I want to first know how to retrieve an individual triple given some uri. I have tried naive approaches by writing statements in a WHERE clause such as ?x rdf:about ?y and ?x rdfs:about ?y. I hope I am being precise.

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  • jpa @version optimistic locking

    - by cometta
    I loaded same entity record on 2 separate browser window then press submit (hibernate template.merge), version number incremented for both browser window, but never caught any problem with optimistic lock.. so how to test this? my save() look like this hibernatetemplate().merge(..); setJPAObject(null); //reset after save

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  • hibernate c3p0 broken pipe

    - by raven_arkadon
    Hi, I'm using hibernate 3 with c3p0 for a program which constantly extracts data from some source and writes it to a database. Now the problem is, that the database might become unavailable for some reasons (in the simplest case: i simply shut it down). If anything is about to be written to the database there should not be any exception - the query should wait for all eternity until the database becomes available again. If I'm not mistaken this is one of the things the connection pool could do for me: if there is a problem with the db, just retry to connect - in the worst case for infinity. But instead i get a broken pipe exception, sometimes followed by connection refused and then the exception is passed to my own code, which shouldn't happen. Even if I catch the exception, how could i cleanly reinitialize hibernate again? (So far without c3p0 i simply built the session factory again, but i wouldn't be surprised if that could leak connections (or is it ok to do so?)). The database is Virtuoso open source edition. My hibernate.xml.cfg c3p0 config: <property name="hibernate.connection.provider_class">org.hibernate.connection.C3P0ConnectionProvider</property> <property name="hibernate.c3p0.breakAfterAcquireFailure">false</property> <property name="hibernate.c3p0.acquireRetryAttempts">-1</property> <property name="hibernate.c3p0.acquireRetryDelay">30000</property> <property name="hibernate.c3p0.automaticTestTable">my_test_table</property> <property name="hibernate.c3p0.initialPoolSize">3</property> <property name="hibernate.c3p0.minPoolSize">3</property> <property name="hibernate.c3p0.maxPoolSize">10</property> btw: The test table is created and i get tons of debug output- so it seems it actually reads the config.

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  • Parse Nested XML tags with the same name

    - by footose
    Let's take a simple XML document: <x> <e> <e> <e>Whatever 1</e> </e> </e> <e> <e> <e>Whatever 2</e> </e> </e> <e> <e> <e>Whatever 3</e> </e> </e> </x> Using the standard org.w3c.dom, I can get the nodes in X by doing.. NodeList fullnodelist = doc.getElementsByTagName("x"); But if I want to return the next set of "e" I try to use something like .. Element element = (Element) fullnodelist.item(0); NodeList nodes = pelement.getElementsByTagName("e"); Expecting it to return "3" nodes (because there are 3 sets of "e"), but instead, it returns "9" - becuase it gets all entries with "e" apperently. This would be fine in the above case, because I could probably iterate through and find what I'm looking for. The problem I'm having is that when the XML file looks like the following: <x> <e> <pattern>whatever</pattern> <blanks> <e>Something Else</e> </blanks> </e> <e> <pattern>whatever</pattern> <blanks> <e>Something Else</e> </blanks> </e> </x> When I request the "e" value, it returns 4, instead of (what i expect) 2. Am I just not understanding how the DOM parsing works? Typically in the past I have used my own XML documents so I would never name the items like this, but unfortunately this is not my XML file and I have no choice to work like this. What I thought I would do is write a loop that "drills down" nodes so that I could group each node together... public static NodeList getNodeList(Element pelement, String find) { String[] nodesfind = Utilities.Split(find, "/"); NodeList nodeList = null; for (int i = 0 ; i <= nodesfind.length - 1; i++ ) { nodeList = pelement.getElementsByTagName( nodesfind[i] ); pelement = (Element)nodeList.item(i); } // value of the nod we are looking for return nodeList; } .. So that if you passed "s/e" into the function, it would return the 2 nodes that I'm looking for (or elements, maybe I'm using the terminology incorrect?). instead it returns all of the "e" nodes within that node. I'm using J2SE for this, so options are rather limited. I can't use any third party XML Parsers. Anyway, if anyone is still with me and has a suggestion, it would be appreciated.

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  • OO vs Simplicity when it comes to user interaction

    - by Oetzi
    Firstly, sorry if this question is rather vague but it's something I'd really like an answer to. As a project over summer while I have some downtime from Uni I am going to build a monopoly game. This question is more about the general idea of the problem however, rather than the specific task I'm trying to carry out. I decided to build this with a bottom up approach, creating just movement around a forty space board and then moving on to interaction with spaces. I realised that I was quite unsure of the best way of proceeding with this and I am torn between two design ideas: Giving every space its own object, all sub-classes of a Space object so the interaction can be defined by the space object itself. I could do this by implementing different land() methods for each type of space. Only giving the Properties and Utilities (as each property has unique features) objects and creating methods for dealing with the buying/renting etc in the main class of the program (or Board as I'm calling it). Spaces like go and super tax could be implemented by a small set of conditionals checking to see if player is on a special space. Option 1 is obviously the OO (and I feel the correct) way of doing things but I'd like to only have to handle user interaction from the programs main class. In other words, I don't want the space objects to be interacting with the player. Why? Errr. A lot of the coding I've done thus far has had this simplicity but I'm not sure if this is a pipe dream or not for larger projects. Should I really be handling user interaction in an entirely separate class? As you can see I am quite confused about this situation. Is there some way round this? And, does anyone have any advice on practical OO design that could help in general?

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  • How can I tell NetBeans to use the latest available version of a JAR for a library?

    - by Freiheit
    I have a Netbeans project with a library defined which includes several JARs. These JARs are versioned like lib\blah\com.blah.wibble.jar_0.6.1.201004161543 . These are nightly builds from another project so that version changes often. I know I can point NetBeans at the specific JARs with the version name, but this means that every time I get a new version I have to update the NetBeans library. I can also strip the version name from the JARs, but this makes it hard to track down bugs. "What version of the blah JARs?" is usually the second thing we ask when we find a bug. Is it possible to tell Netbeans to use included com.blah.wibble.jar_[??????] where ???? is some sort of automatic pointer to use the latest available version?

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  • Is nested synchronized block necessary?

    - by Dan
    I am writing a multithreaded program and I have a method that has a nested synchronized blocks and I was wondering if I need the inner sync or if just the outer sync is good enough. public class Tester { private BlockingQueue<Ticket> q = new LinkedBlockingQueue<>(); private ArrayList<Long> list = new ArrayList<>(); public void acceptTicket(Ticket p) { try { synchronized (q) { q.put(p); synchronized (list) { if (list.size() < 5) { list.add(p.getSize()); } else { list.remove(0); list.add(p.getSize()); } } } } catch (InterruptedException ex) { Logger.getLogger(Consumer.class.getName()).log(Level.SEVERE, null, ex); } } } EDIT: This isn't a complete class as I am still working on it. But essentially I am trying to emulate a ticket machine. The ticket machine maintains a list of tickets in the BlockingQueue q. Whenever a client adds a ticket to the machine, the machine also keeps track of the price of the last 5 tickets (ArrayList list)

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