Search Results

Search found 40248 results on 1610 pages for 'php mysql'.

Page 86/1610 | < Previous Page | 82 83 84 85 86 87 88 89 90 91 92 93  | Next Page >

  • Using replacement to get possible outcomes to then search through HUGE amount of data

    - by Samuel Cambridge
    I have a database table holding 40 million records (table A). Each record has a string a user can search for. I also have a table with a list of character replacements (table B) i.e. i = Y, I = 1 etc. I need to be able to take the string a user is searching for, iterate through each letter and create an array of every possible outcome (the users string, then each outcome with alternative letters used). I need to check for alternatives on both lower and uppercase letters in the word A search string can be no longer than 10 characters long. I'm using PHP and a MySQL database. Does anyone have any thoughts / articles / guidance on doing this in an efficient way?

    Read the article

  • PHP/MySQL Interview - How would you have answered?

    - by martincarlin87
    I was asked this interview question so thought I would post it here to see how other users would answer: Please write some code which connects to a MySQL database (any host/user/pass), retrieves the current date & time from the database, compares it to the current date & time on the local server (i.e. where the application is running), and reports on the difference. The reporting aspect should be a simple HTML page, so that in theory this script can be put on a web server, set to point to a particular database server, and it would tell us whether the two servers’ times are in sync (or close to being in sync). This is what I put: // Connect to database server $dbhost = 'localhost'; $dbuser = 'xxx'; $dbpass = 'xxx'; $dbname = 'xxx'; $conn = mysql_connect($dbhost, $dbuser, $dbpass) or die (mysql_error()); // Select database mysql_select_db($dbname) or die(mysql_error()); // Retrieve the current time from the database server $sql = 'SELECT NOW() AS db_server_time'; // Execute the query $result = mysql_query($sql) or die(mysql_error()); // Since query has now completed, get the time of the web server $php_server_time = date("Y-m-d h:m:s"); // Store query results in an array $row = mysql_fetch_array($result); // Retrieve time result from the array $db_server_time = $row['db_server_time']; echo $db_server_time . '<br />'; echo $php_server_time; if ($php_server_time != $db_server_time) { // Server times are not identical echo '<p>Database server and web server are not in sync!</p>'; // Convert the time stamps into seconds since 01/01/1970 $php_seconds = strtotime($php_server_time); $sql_seconds = strtotime($db_server_time); // Subtract smaller number from biggest number to avoid getting a negative result if ($php_seconds > $sql_seconds) { $time_difference = $php_seconds - $sql_seconds; } else { $time_difference = $sql_seconds - $php_seconds; } // convert the time difference in seconds to a formatted string displaying hours, minutes and seconds $nice_time_difference = gmdate("H:i:s", $time_difference); echo '<p>Time difference between the servers is ' . $nice_time_difference; } else { // Timestamps are exactly the same echo '<p>Database server and web server are in sync with each other!</p>'; } Yes, I know that I have used the deprecated mysql_* functions but that aside, how would you have answered, i.e. what changes would you make and why? Are there any factors I have omitted which I should take into consideration? The interesting thing is that my results always seem to be an exact number of minutes apart when executed on my hosting account: 2012-12-06 11:47:07 2012-12-06 11:12:07

    Read the article

  • Site loads Extremely slowly over HTTPS; loads perfectly over HTTP - Sudden and new issue

    - by guest234239048
    My business' website suddenly started loading extremely slowly over HTTPS last night and continues through today. The facts: Page loadtime via HTTPS - 2 minutes +, HTTP - 3 seconds max. NO updates were done on any site files in the past 2 weeks. This is on Shared Hosting HTTPS has worked perfectly over the past 9 months then suddenly failed yesterday. Hosting company and SSL issuer say there are no problems on their end. - Searches for others having similar issues return no results, it appears to be just me... Site is primarily run via php/mysql Currently attempted troubleshooting: Tried all major browsers and different versions - same result. Tried 2 separate ISPs - same result. Tried proxies - same result. Tried 3 separate computers - same result. I'm basically at a total loss here. Does anyone know what could cause such a thing to happen? Please help guide troubleshooting.

    Read the article

  • MySQLi Insert prepared statement via PHP

    - by Jimmy
    Howdie do, This is my first time dealing with MySQLi inserts. I had always used mysql and directly ran the queries. Apparently, not as secure as MySQLi. Anywho, I'm attempting to pass two variables into the database. For some reason my prepared statement keeps erroring out. I'm not sure if it's a syntax error, but the insert just won't work. I've updated the code to make the variables easier to read Also, the error is specifically, Error preparing statement. I've updated the code, but it's not a pHP error. It's a MySQL error as the script runs but fails at the execution of: if($stmt = $mysqli - prepare("INSERT INTO subnets (id, subnet, mask, sectionId, description, vrfId, masterSubnetId, allowRequests, vlanId, showName, permissions, pingSubnet, isFolder, editDate) VALUES ('', ?, ?, '1', '', '0', '0', '0', '0', '0', '{"3":"1","2":"2"}', '0', '0', 'NULL')")) { I'm going to enable MySQL error checking. I honestly didn't know about that. <?php error_reporting(E_ALL); function InsertIPs($decimnal,$cidr) { error_reporting(E_ALL); $mysqli = new mysqli("localhost","jeremysd_ips","","jeremysd_ips"); if(mysqli_connect_errno()) { echo "Connection Failed: " . mysqli_connect_errno(); exit(); } if($stmt = $mysqli -> prepare("INSERT INTO subnets (id, subnet, mask,sectionId,description,vrfld,masterSubnetId,allowRequests,vlanId,showName,permissions,pingSubnet,isFolder,editDate) VALUES ('',?,?,'1','','0','0','0','0','0', '{'3':'1','2':'2'}', '0', '0', NULL)")) { $stmt-> bind_param('ii',$decimnal,$cidr); if($stmt-> execute()) { echo "Row added successfully\n"; } else { $stmt->error; } $stmt -> close; } } else { echo 'Error preparing statement'; } $mysqli -> close(); } $SUBNETS = array ("2915483648 | 18"); foreach($SUBNETS as $Ip) { list($TempIP,$TempMask) = explode(' | ',$Ip); echo InsertIPs($Tempip,$Tempmask); } ?> This function isn't supposed to return anything. It's just supposed to perform the Insert. Any help would be GREATLY appreciated. I'm just not sure what I'm missing here

    Read the article

  • Is it possible to download a large database using mysql query

    - by Rose
    i am downloading files from server using WinSCP.Is it possible to write a query to download a large database using mysql query? Or using any other method i have tried with this code but i am not able to get the whole database structure <?php if(file_exists('backup_sql/my_backup.zip')) { unlink('backup_sql/my_backup.zip'); } $tables='*'; $host='MY HOST NAME'; $user='MY_USERNAME'; $pass='MYPASSWORD'; $name='MY_DB_NAME'; $link = mysql_connect($host,$user,$pass); mysql_select_db($name,$link); //get all of the tables if($tables == '*') { $tables = array(); $result = mysql_query('SHOW TABLES'); while($row = mysql_fetch_row($result)) { $tables[] = $row[0]; } } else { $tables = is_array($tables) ? $tables : explode(',',$tables); } $return=''; //cycle through foreach($tables as $table) { $result = mysql_query('SELECT * FROM '.$table); $num_fields = mysql_num_fields($result); //$return.= 'DROP TABLE '.$table.';'; $row2 = mysql_fetch_row(mysql_query('SHOW CREATE TABLE '.$table)); $return.= "\n\n".$row2[1].";\n\n"; for ($i = 0; $i < $num_fields; $i++) { while($row = mysql_fetch_row($result)) { $return.= 'INSERT INTO '.$table.' VALUES('; for($j=0; $j<$num_fields; $j++) { $row[$j] = addslashes($row[$j]); //$row[$j] = ereg_replace("\n","\\n",$row[$j]); if (isset($row[$j])) { $return.= '"'.$row[$j].'"' ; } else { $return.= '""'; } if ($j<($num_fields-1)) { $return.= ','; } } $return.= ");\n"; } } $return.="\n\n\n"; } $rand_var=time(); $files_to_zip = array( "'backup_sql/db-backup-'.$rand_var.'.sql'", ); $name = 'db-backup-'.$rand_var.'.sql'; $data = $return; ?> any one please help me... thank you

    Read the article

  • Ways to prevent multiple email notification with php&mysql

    - by Louis Loudog Trottier
    My 1st post, but i got many great answers and tips from stackoverflow so far. This one was a close call- How does facebook, gmail send the real time notification? but not exactly, so let brainstorm this together. I have CMS system with mail notification when a change is made on the site. Everything wotk very well but i want to prevent multiple notification if somene make another quick change to, let say, fix a typo. Using php mail(), obviously. I've tough of 2 ways, one simple, and one.... let just say, pretty heavy... cough. the 3rd one was inspired by Implementing Email Notification but really doesn't look appealing to me to send bunch of email at once. Use a timestamp to check if another change was made in the 'let say' last 5 minutes. Record the last change, and compare it to the new one. Could be usefull for backup at the same time since i'll have to save the change somewhere, but text can be long and making an sql search would be painfull. Wouldn't it? Use cron to send changes every x minutes... convince me if you ythink it is a suitable solution. Any ideas, comment or suggestion of your own? Looking forward for your inputs, and since i now registered, i'll do my best to help around. Cheers, all llt

    Read the article

  • Sort MySQL query result by a alphanumeric field

    - by Jason Shultz
    I'm querying a table in a db using php. one of the fields is a column called "rank" and has data like the following: none 1-bronze 2-silver 3-gold ... 10-ambassador 11-president I want to be able to sort the results based on that "rank" column. any results where the field is "none" get excluded, so those don't factor in. As you can already guess, right now the results are coming back like this: 1-bronze 10-ambassador 11-president 2-silver 3-gold Of course, I would like for it to be sorted so it is like the following: 1-bronze 2-silver 3-gold ... 10-ambassador 11-president Right now the query is being returned as an object. I've tried different sort options like natsort, sort, array_multisort but haven't got it to work the way I'm sure it can. I would prefer keeping the results in an object form if possible. I'm passing the data on to a view in the next step. although, it's perfectly acceptable to pass the object to the view and then do the work there. so it's not an issue after all. :) thank you for your help. i'm hoping I'm making sense.

    Read the article

  • Adding up row number and displaying total using COUNT (PHP MySQL)

    - by Yvonne
    I'm attempting to run a query that adds up the total number of subjects in a class. A class has many subjects. There is a 'teachersclasses' table between teachers (the user table) and classes. The principles sounds pretty simple but I'm having some trouble in getting my page to display the number of subjects for each class (directly associated with the teacher) This is what I have so far, trying to make use of the COUNT with a nested SELECT: SELECT (SELECT count(*) FROM subjects WHERE subjects.classid = class.classid) AS total_subjects, class.classname, class.classid FROM class Then I am calling up 'num_subjects' to present the total within a while loop: <?php echo $row['total_subjects']?> From the above, I am receiving the total subjects for a class, but within the same table row (for one class) and my other while loop doesnt run anymore, which returns all of the classes associated with a teacher :( ... Bit of a mess now! I know to return the classes for a particular teacher, I can do an additional WHERE clause on the session of 'teacherid' but I think my query is getting too complicated for me that errors are popping up everywhere. Anyone have a quick fix for this! Thanks very much

    Read the article

  • PHP/MySQL Problem

    - by Scott
    Why does this only print the sites specific content under the first site, and doesn't do it for the other 2? <?php echo 'NPSIN Data will be here soon!'; // connect to DB $dbhost = 'localhost'; $dbuser = 'root'; $dbpass = 'root'; $conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to DB'); $dbname = 'npsin'; mysql_select_db($dbname); // get number of sites $query = 'select count(*) from sites'; $result = mysql_query($query) or die ('Query failed: ' . mysql_error()); $resultArray = mysql_fetch_array($result); $numSites = $resultArray[0]; echo "<br><br>"; // get all sites $query = 'select site_name from sites'; $result = mysql_query($query); // get site content $query2 = 'select content_name, site_id from content'; $result2 = mysql_query($query2); // get site files // print info $count = 1; while ($row = mysql_fetch_array($result, MYSQL_NUM)) { echo "Site $count: "; echo "$row[0]"; echo "<br>"; $contentCount = 1; while ($row2 = mysql_fetch_array($result2, MYSQL_NUM)) { $id = $row2[1]; if ($id == ($count - 1)) { echo "Content $contentCount: "; echo "$row2[0]"; echo "<br>"; } $contentCount++; } $count++; } ?>

    Read the article

  • Updating multiple rows with an array

    - by Copephobia
    I have a table that holds user information. One of the columns holds the position of the user in the game they are in. When a game is being created, I need to update the positions of the users of each team. Here is an example: Game id : 7 Team 1 users : 1,2 Team 2 users : 3,4 team1_position : array(1,2) team2_position : array(13,14) What I want to do is update the user table using the array of positions in the SET area. My goal is to be able to update the users without the need for their id (I have different size game boards, so I have multiple position arrays for each board size) How can I do something like this: UPDATE user SET position='(team1_position)' WHERE game = '7' AND team = '1' I feel like it would be a waste of resources to select all the id's of each team and update them separately.

    Read the article

  • How to optimize this MYSQL table?

    - by Lost_in_code
    This is for an upcoming project. I have two tables - first one keeps tracks of photos, and the second one keeps track of the photo's rank Photos: +-------+-----------+------------------+ | id | photo | current_rank | +-------+-----------+------------------+ | 1 | apple | 5 | | 2 | orange | 9 | +-------+-----------+------------------+ The photo rank keeps changing on a regular basis and this is the table that tracks it: Ranks: +-------+-----------+----------+-------------+ | id | photo_id | ranks | timestamp | +-------+-----------+----------+-------------+ | 1 | 1 | 8 | * | | 2 | 2 | 2 | * | | 3 | 1 | 3 | * | | 4 | 1 | 7 | * | | 5 | 1 | 5 | * | | 6 | 2 | 9 | * | +-------+-----------+----------+-------------+ * = current timestamp Every rank is tracked for reporting/analysis purpose. I talked to someone who has experience in this field and he told me that storing ranks like above is the way to go. But I'm not so sure yet. The problem here is data redundancy. There are going to be tens of thousands of photos. The photo rank changes on a hourly basis (many time within minutes) for recent photos but less frequently for older photos. At this rate the table will have millions of records within months. And since I do not have experience in working with large databases, this makes me a little nervous. I thought of this: Ranks: +-------+-----------+--------------------+ | id | photo_id | ranks | +-------+-----------+--------------------+ | 1 | 1 | 8:*,3:*,7:*,5:* | | 2 | 2 | 2:*,9:* | +-------+-----------+--------------------+ * = current timestamp That means some extra code in PHP to split the rank/time (and sorting) but that looks OK to me. Is this a correct way to optimize the table for performance? What would you recommend? Any suggestions would be great.

    Read the article

  • PHP & MySQL - Undefined variable problem?

    - by TaG
    I keep getting the following error Undefined variable: password on line 33 how do I correct this problem? So this error will stop showing. Here is the php code. $first_name = mysqli_real_escape_string($mysqli, $purifier->purify(htmlentities(strip_tags($_POST['first_name'])))); $password1 = mysqli_real_escape_string($mysqli, $purifier->purify(strip_tags($_POST['password1']))); $password2 = mysqli_real_escape_string($mysqli, $purifier->purify(strip_tags($_POST['password2']))); // Check for a password and match against the confirmed password: if ($password1 == $password2) { $sha512 = hash('sha512', $password1); $password = mysqli_real_escape_string($mysqli, $sha512); } else { echo '<p class="error">Your password did not match the confirmed password!</p>'; } //If the table is not found add it to the database if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO users (user_id, first_name, password) VALUES ('$user_id', '$first_name', '$password')"); } //If the table is in the database update each field when needed if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE users SET first_name = '$first_name', password = '$password' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; }

    Read the article

  • mysql_real_escape more than once

    - by Aran
    I was just wondering whether it makes a difference if I mysql_real_escape data more than once? So if I escaped data in one part of my website, and then again in another part of code. Would this be a problem? Or make a difference?

    Read the article

  • SELECT DISTINCT multiple field search?

    - by Patrick
    I'm trying to search multiple fields zc_city and zc_zip for when user input and then return row results for zc_city zc_state and zc_zip $q = strtolower($_GET["q"]); if (!$q) return; $sql = "SELECT DISTINCT zc_city AS zcity FROM search_zipcodes WHERE zc_city LIKE '$q%'"; $rsd = mysql_query($sql); while($rs = mysql_fetch_array($rsd)) { $zcity = $rs['zcity']; echo "$zcity\n"; }

    Read the article

  • MySQLi - Should every statement be prepared?

    - by Kerry
    I know its supposed to improve performance and clean strings, but lets say there are no variables? Might just be a SELECT COUNT( `column` ) AS count FROM `table` Should that be prepared? Is there any case that a SELECT statement should not be prepared?

    Read the article

  • PHP & MySQL delete image link problem

    - by IMAGE
    I'm trying to create a delete image link if the image is present and when the user clicks the delete image link it should delete the image. But for some reason this is not working can someone help me fix the delete image link problem? Thanks! Here is the PHP code. if (isset($_POST['delete_image'])) { $img_dir = "../members/" . $user_id . "/images/thumbs/"; $img_thmb = "../members/" . $user_id . "/images/"; $image_name = $row['image']; if(file_exists($img_dir . $image_name)){ if(unlink($img_dir.$image_name) && unlink($img_thmb.$image_name)){ $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli, "DELETE FROM users* WHERE image_id = '.$image_id.' AND user_id = '$user_id'"); }else{ echo '<p class="error">Sorry unable to delete image file!</p>'; } } } if(isset($_POST['image']) || !empty($image)) { echo '<a href="'. $_POST['delete_image'] .'">Delete Image</a>'; }

    Read the article

  • mySQL Optimization Suggestions

    - by Brian Schroeter
    I'm trying to optimize our mySQL configuration for our large Magento website. The reason I believe that mySQL needs to be configured further is because New Relic has shown that our SELECT queries are taking a long time (20,000+ ms) in some categories. I ran MySQLTuner 1.3.0 and got the following results... (Disclaimer: I restarted mySQL earlier after tweaking some settings, and so the results here may not be 100% accurate): >> MySQLTuner 1.3.0 - Major Hayden <[email protected]> >> Bug reports, feature requests, and downloads at http://mysqltuner.com/ >> Run with '--help' for additional options and output filtering [OK] Currently running supported MySQL version 5.5.37-35.0 [OK] Operating on 64-bit architecture -------- Storage Engine Statistics ------------------------------------------- [--] Status: +ARCHIVE +BLACKHOLE +CSV -FEDERATED +InnoDB +MRG_MYISAM [--] Data in MyISAM tables: 7G (Tables: 332) [--] Data in InnoDB tables: 213G (Tables: 8714) [--] Data in PERFORMANCE_SCHEMA tables: 0B (Tables: 17) [--] Data in MEMORY tables: 0B (Tables: 353) [!!] Total fragmented tables: 5492 -------- Security Recommendations ------------------------------------------- [!!] User '@host5.server1.autopartsnetwork.com' has no password set. [!!] User '@localhost' has no password set. [!!] User 'root@%' has no password set. -------- Performance Metrics ------------------------------------------------- [--] Up for: 5h 3m 4s (5M q [317.443 qps], 42K conn, TX: 18B, RX: 2B) [--] Reads / Writes: 95% / 5% [--] Total buffers: 35.5G global + 184.5M per thread (1024 max threads) [!!] Maximum possible memory usage: 220.0G (174% of installed RAM) [OK] Slow queries: 0% (6K/5M) [OK] Highest usage of available connections: 5% (61/1024) [OK] Key buffer size / total MyISAM indexes: 512.0M/3.1G [OK] Key buffer hit rate: 100.0% (102M cached / 45K reads) [OK] Query cache efficiency: 66.9% (3M cached / 5M selects) [!!] Query cache prunes per day: 3486361 [OK] Sorts requiring temporary tables: 0% (0 temp sorts / 812K sorts) [!!] Joins performed without indexes: 1328 [OK] Temporary tables created on disk: 11% (126K on disk / 1M total) [OK] Thread cache hit rate: 99% (61 created / 42K connections) [!!] Table cache hit rate: 19% (9K open / 49K opened) [OK] Open file limit used: 2% (712/25K) [OK] Table locks acquired immediately: 100% (5M immediate / 5M locks) [!!] InnoDB buffer pool / data size: 32.0G/213.4G [OK] InnoDB log waits: 0 -------- Recommendations ----------------------------------------------------- General recommendations: Run OPTIMIZE TABLE to defragment tables for better performance MySQL started within last 24 hours - recommendations may be inaccurate Reduce your overall MySQL memory footprint for system stability Enable the slow query log to troubleshoot bad queries Increasing the query_cache size over 128M may reduce performance Adjust your join queries to always utilize indexes Increase table_cache gradually to avoid file descriptor limits Read this before increasing table_cache over 64: http://bit.ly/1mi7c4C Variables to adjust: *** MySQL's maximum memory usage is dangerously high *** *** Add RAM before increasing MySQL buffer variables *** query_cache_size (> 512M) [see warning above] join_buffer_size (> 128.0M, or always use indexes with joins) table_cache (> 12288) innodb_buffer_pool_size (>= 213G) My my.cnf configuration is as follows... [client] port = 3306 [mysqld_safe] nice = 0 [mysqld] tmpdir = /var/lib/mysql/tmp user = mysql port = 3306 skip-external-locking character-set-server = utf8 collation-server = utf8_general_ci event_scheduler = 0 key_buffer = 512M max_allowed_packet = 64M thread_stack = 512K thread_cache_size = 512 sort_buffer_size = 24M read_buffer_size = 8M read_rnd_buffer_size = 24M join_buffer_size = 128M # for some nightly processes client sessions set the join buffer to 8 GB auto-increment-increment = 1 auto-increment-offset = 1 myisam-recover = BACKUP max_connections = 1024 # max connect errors artificially high to support behaviors of NetScaler monitors max_connect_errors = 999999 concurrent_insert = 2 connect_timeout = 5 wait_timeout = 180 net_read_timeout = 120 net_write_timeout = 120 back_log = 128 # this table_open_cache might be too low because of MySQL bugs #16244691 and #65384) table_open_cache = 12288 tmp_table_size = 512M max_heap_table_size = 512M bulk_insert_buffer_size = 512M open-files-limit = 8192 open-files = 1024 query_cache_type = 1 # large query limit supports SOAP and REST API integrations query_cache_limit = 4M # larger than 512 MB query cache size is problematic; this is typically ~60% full query_cache_size = 512M # set to true on read slaves read_only = false slow_query_log_file = /var/log/mysql/slow.log slow_query_log = 0 long_query_time = 0.2 expire_logs_days = 10 max_binlog_size = 1024M binlog_cache_size = 32K sync_binlog = 0 # SSD RAID10 technically has a write capacity of 10000 IOPS innodb_io_capacity = 400 innodb_file_per_table innodb_table_locks = true innodb_lock_wait_timeout = 30 # These servers have 80 CPU threads; match 1:1 innodb_thread_concurrency = 48 innodb_commit_concurrency = 2 innodb_support_xa = true innodb_buffer_pool_size = 32G innodb_file_per_table innodb_flush_log_at_trx_commit = 1 innodb_log_buffer_size = 2G skip-federated [mysqldump] quick quote-names single-transaction max_allowed_packet = 64M I have a monster of a server here to power our site because our catalog is very large (300,000 simple SKUs), and I'm just wondering if I'm missing anything that I can configure further. :-) Thanks!

    Read the article

  • Practical mysql schema advice for eCommerce store - Products & Attributes

    - by Gravy
    I am currently planning my first eCommerce application (mySQL & Laravel Framework). I have various products, which all have different attributes. Describing products very simply, Some will have a manufacturer, some will not, some will have a diameter, others will have a width, height, depth and others will have a volume. Option 1: Create a master products table, and separate tables for specific product types (polymorphic relations). That way, I will not have any unnecessary null fields in the products table. Option 2: Create a products table, with all possible fields despite the fact that there will be a lot of null rows Option 3: Normalise so that each attribute type has it's own table. Option 4: Create an attributes table, as well as an attribute_values table with the value being varchar regardless of the actual data-type. The products table would have a many:many relationship with the attributes table. Option 5: Common attributes to all or most products put in the products table, and specific attributes to a particular category of product attached to the categories table. My thoughts are that I would like to be able to allow easy product filtering by these attributes and sorting. I would also want the frontend to be fast, less concern over the performance of the inserting and updating of product records. Im a bit overwhelmed with the vast implementation options, and cannot find a suitable answer in terms of the best method of approach. Could somebody point me in the right direction? In an ideal world, I would like to offer the following kind of functionality - http://www.glassesdirect.co.uk/products/ to my eCommerce store. As can be seen, in the sidebar, you can select an attribute the glasses to filter them. e.g. male / female or plastic / metal / titanium etc... Alternatively, should I just dump the mySql relational database idea and learn mongodb?

    Read the article

  • can't load big files to server with php [closed]

    - by yozhik
    Hi all! I can't load big files to server. The problem is in that file $_FILES["filename"]["tmp_name"] is empty if file a little more bigger then 2mb. I tried to change variables in php.ini upload_max_filesize = 700M post_max_size = 16M but not working to. Also tried to add this variables to my .httaccess file - but 500 error appears. Error code while uploading=1. UPLOAD_ERR_INI_SIZE Value: 1; The uploaded file exceeds the upload_max_filesize directive in php.ini. Here is my uppload.php page, please anwer what I doing wrong? Thanx! <?php if(strlen($_FILES["filename"]["name"])) { $folder = "uploads/"; echo $folder; $error = ""; if($_FILES["filename"]["size"] > 1024*700*1024) { $error .= "<b><p class=ErrorMessage>?????? ????? ????????? 5Mb</p></b><br>"; header("Location: upload.php?error=".$error, true, 303 ); } if(!file_exists($folder.="hh/")) { if(!mkdir($folder, 0700)) $error .= "<b><p class=ErrorMessage>Folder not created</p></b><br>"; } //echo "<br>".$_FILES["filename"]["tmp_name"]."<br>"; echo $folder.$_FILES["filename"]["name"]."<br>"; echo $_FILES["filename"]["error"]."<br>"; if(move_uploaded_file($_FILES["filename"]["tmp_name"], $folder.$_FILES["filename"]["name"])) { echo("???? ??????? ???????? <br>"); echo("?????????????? ?????: <br>"); echo("??? ?????: "); echo($_FILES["filename"]["name"]); echo("<br>?????? ?????: "); echo($_FILES["filename"]["size"]); echo("<br>??????? ??? ????????: "); echo($folder.=$_FILES["filename"]["name"]); echo("<br>??? ?????: "); echo($_FILES["filename"]["type"]); } else { $error .= "<b><p class=ErrorMessage>?????? ???????? ?????</p></b><br>"; } } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>???????? ??? ????????</title> </head> <body> <?php if(isset($_REQUEST["error"])) { echo $_REQUEST["error"]; } ?> <h2><p><b> ????? ??? ???????? ?????? </b></p></h2> <form action="upload.php" method="post" enctype="multipart/form-data"> <input type="file" name="filename" READONLY><br> <input name="Upload" type="submit" value="Upload"><br> </form> </body> </html>

    Read the article

  • MySQL – Export the Resultset to CSV file

    - by Pinal Dave
    In SQL Server, you can use BCP command to export the result set to a csv file. In MySQL too, You can export data from a table or result set as a csv file in many methods. Here are two methods. Method 1 : Make use of Work Bench If you are using Work Bench as a querying tool, you can make use of it’s Export option in the result window. Run the following code in Work Bench SELECT db_names FROM mysql_testing; The result will be shown in the result windows. There is an option called “File”. Click on it and it will prompt you a window to save the result set (Screen shot attached to show how file option can be used). Choose the directory and type out the name of the file. Method 2 : Make use of OUTFILE command You can do the export using a query with OUTFILE command as shown below SELECT db_names FROM mysql_testing INTO OUTFILE 'C:/testing.csv' FIELDS ENCLOSED BY '"' TERMINATED BY ';' ESCAPED BY '"' LINES TERMINATED BY '\r\n'; After the execution of the above code, you can find a file named testing.csv in C drive of the server. Reference: Pinal Dave (http://blog.sqlauthority.com)Filed under: MySQL, PostADay, SQL, SQL Authority, SQL Query, SQL Tips and Tricks, T SQL Tagged: CSV

    Read the article

  • MySQL – Introduction to CONCAT and CONCAT_WS functions

    - by Pinal Dave
    MySQL supports two types of concatenation functions. They are CONCAT and CONCAT_WS CONCAT function just concats all the argument values as such SELECT CONCAT('Television','Mobile','Furniture'); The above code returns the following TelevisionMobileFurniture If you want to concatenate them with a comma, either you need to specify the comma at the end of each value, or pass comma as an argument along with the values SELECT CONCAT('Television,','Mobile,','Furniture'); SELECT CONCAT('Television',',','Mobile',',','Furniture'); Both the above return the following Television,Mobile,Furniture However you can omit the extra work by using CONCAT_WS function. It stands for Concatenate with separator. This is very similar to CONCAT function, but accepts separator as the first argument. SELECT CONCAT_WS(',','Television','Mobile','Furniture'); The result is Television,Mobile,Furniture If you want pipeline as a separator, you can use SELECT CONCAT_WS('|','Television','Mobile','Furniture'); The result is Television|Mobile|Furniture So CONCAT_WS is very flexible in concatenating values along with separate. Reference: Pinal Dave (http://blog.sqlauthority.com)Filed under: MySQL, PostADay, SQL, SQL Authority, SQL Query, SQL Tips and Tricks, T SQL

    Read the article

  • PHP & MySQL submit error message problem

    - by peakUC
    When I submit a new name and not a new avatar I get the following avatar error message Please upload a .gif, .jpeg, .jpg or .png image!. I want to be able to send a new name only without having to upload a new avatar each time I submit the form without getting the avatar error message Please upload a .gif, .jpeg, .jpg or .png image! can someone help me fix this problem? Here is the php code. if (isset($_POST['submitted'])) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.* FROM users WHERE user_id=3"); $first_name = mysqli_real_escape_string($mysqli, htmlentities(strip_tags($_POST['first_name']))); $user_id = '3'; if(isset($_FILES["avatar"]["name"]) && $_FILES['avatar']['size'] <= 5242880) { if($_FILES["avatar"]["type"] == "image/gif" || $_FILES["avatar"]["type"] == "image/jpeg" || $_FILES["avatar"]["type"] == "image/jpg" || $_FILES["avatar"]["type"] == "image/png" || $_FILES["avatar"]["type"] == "image/pjpeg") { if (file_exists("../members/" . $user_id . "/images/" . $_FILES["avatar"]["name"])) { echo '<p class="error">' . mysqli_real_escape_string($mysqli, htmlentities(strip_tags(basename($_FILES["avatar"]["name"])))) . ' already exists! '; } else if($_FILES["avatar"]["name"] == TRUE) { move_uploaded_file($_FILES["avatar"]["tmp_name"], "../members/" . $user_id . "/images/" . mysqli_real_escape_string($mysqli, htmlentities(strip_tags(basename($_FILES["avatar"]["name"]))))); $avatar = mysqli_real_escape_string($mysqli, htmlentities(strip_tags(basename($_FILES["avatar"]["name"])))); } } else if($_FILES["avatar"]["type"] != "image/gif" || $_FILES["avatar"]["type"] != "image/jpeg" || $_FILES["avatar"]["type"] != "image/jpg" || $_FILES["avatar"]["type"] != "image/png" || $_FILES["avatar"]["type"] != "image/pjpeg") { echo '<p class="error">Please upload a .gif, .jpeg, .jpg or .png image!</p>'; } } else if($_FILES['avatar']['size'] >= 5242880) { echo '<p class="error">Please upload a smaller pic!</p>'; } else if($_FILES["avatar"]["name"] == NULL) { $avatar = NULL; } if(isset($_FILES["avatar"]["name"]) && $_FILES['avatar']['size'] <= 5242880) { if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO users (user_id, first_name, avatar) VALUES ('$user_id', '$first_name', '$avatar')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE users SET first_name = '$first_name', avatar = '$avatar' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { print mysqli_error($mysqli); return; } } }

    Read the article

  • mySQL to .XSL help

    - by kielie
    hi guys, I have to create a script that takes a mySQL table, and exports it into .XSL format, and then saves that file into a specified folder on the web host. I got it working, but now I can't seem to get it to automatically save the file to the location without prompting the user. It needs to run every day at a specified time, so it can save the previous days leads into a .XSL file on the web host. Here is the code: <?php // DB TABLE Exporter // // How to use: // // Place this file in a safe place, edit the info just below here // browse to the file, enjoy! // CHANGE THIS STUFF FOR WHAT YOU NEED TO DO $dbhost = "-"; $dbuser = "-"; $dbpass = "-"; $dbname = "-"; $dbtable = "-"; // END CHANGING STUFF $cdate = date("Y-m-d"); // get current date // first thing that we are going to do is make some functions for writing out // and excel file. These functions do some hex writing and to be honest I got // them from some where else but hey it works so I am not going to question it // just reuse // This one makes the beginning of the xls file function xlsBOF() { echo pack("ssssss", 0x809, 0x8, 0x0, 0x10, 0x0, 0x0); return; } // This one makes the end of the xls file function xlsEOF() { echo pack("ss", 0x0A, 0x00); return; } // this will write text in the cell you specify function xlsWriteLabel($Row, $Col, $Value ) { $L = strlen($Value); echo pack("ssssss", 0x204, 8 + $L, $Row, $Col, 0x0, $L); echo $Value; return; } // make the connection an DB query $dbc = mysql_connect( $dbhost , $dbuser , $dbpass ) or die( mysql_error() ); mysql_select_db( $dbname ); $q = "SELECT * FROM ".$dbtable." WHERE date ='$cdate'"; $qr = mysql_query( $q ) or die( mysql_error() ); // Ok now we are going to send some headers so that this // thing that we are going make comes out of browser // as an xls file. // header("Pragma: public"); header("Expires: 0"); header("Cache-Control: must-revalidate, post-check=0, pre-check=0"); header("Content-Type: application/force-download"); header("Content-Type: application/octet-stream"); header("Content-Type: application/download"); //this line is important its makes the file name header("Content-Disposition: attachment;filename=export_".$dbtable.".xls "); header("Content-Transfer-Encoding: binary "); // start the file xlsBOF(); // these will be used for keeping things in order. $col = 0; $row = 0; // This tells us that we are on the first row $first = true; while( $qrow = mysql_fetch_assoc( $qr ) ) { // Ok we are on the first row // lets make some headers of sorts if( $first ) { foreach( $qrow as $k => $v ) { // take the key and make label // make it uppper case and replace _ with ' ' xlsWriteLabel( $row, $col, strtoupper( ereg_replace( "_" , " " , $k ) ) ); $col++; } // prepare for the first real data row $col = 0; $row++; $first = false; } // go through the data foreach( $qrow as $k => $v ) { // write it out xlsWriteLabel( $row, $col, $v ); $col++; } // reset col and goto next row $col = 0; $row++; } xlsEOF(); exit(); ?> I tried using, fwrite to accomplish this, but it didn't seem to go very well, I removed the header information too, but nothing worked. Here is the original code, as I found it, any help would be greatly appreciated. :-) Thanx in advance. :-)

    Read the article

< Previous Page | 82 83 84 85 86 87 88 89 90 91 92 93  | Next Page >