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  • PHP displaying error for already used Username and empty field

    - by Pixel Reaper
    I want PHP to make sure the username is not already used and also check to see if the field is empty. Sorry I am a huge noob when it comes to php. Here is my code: // Check for an Username: $dup = mysql_query("SELECT user_username FROM users WHERE user_username='".$_POST['user_username']."'"); if(mysql_num_rows($dup) >0){ $errors[] = 'Username already used.'; } else{ $un = mysqli_real_escape_string($dbc, trim($_POST['user_username'])); echo '<b>Congrats, You are now Registered.</b>'; } else { $errors[] = 'You forgot to enter your Username.'; }

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  • problem with logout script in php

    - by user225269
    I'm a beginner in php, and I am trying to create a login and logout. But I am having problems in logging out. My logout just calls for the login form which is this: <? session_start(); session_destroy(); ?> <table width="300" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC"> <tr> <form name="form1" method="post" action="checklogin.php"> <td> <table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF"> <tr> <td colspan="3"><strong>Member Login </strong></td> </tr> <tr> <td width="78">Username</td> <td width="6">:</td> <td width="294"><input name="myusername" type="text" id="myusername"></td> </tr> <tr> <td>Password</td> <td>:</td> <td><input name="mypassword" type="text" id="mypassword"></td> </tr> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login"></td> </tr> </table> </td> </form> </tr> </table> My problem is, when I try to press the back button in the browser. Whoever user is using it can still access what is not supposed to be accessed when a user hasn't logged in. Do I need to add a code on the user page? I have this code on the user page: <? session_start(); if(!session_is_registered(myusername)){ header("location:main_login.php"); } ?> What can you recommend that I would do so that a script will prompt to enter the username and password again when a user clicks on the back button.

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  • Stop Submit With empty and error Input Values Using PHP

    - by user3615781
    I am using the following code for sending data to database, but it sends the data even the values of the fields are incorrect or empty. So can anyone help me solve this by using php? Here is my code: <?php //Connecting to sql db $connect = mysqli_connect("localhost","root","","form"); /* check connection */ if (!$connect) { die('Connect Error: ' . mysqli_connect_error()); } //Sending data to sql db $result = mysqli_query($connect,"INSERT INTO students(name,email,website,comment,gender) VALUES('$name','$email','$website','$comment','$gender')"); if (!$result) { die('Query Error:'. mysqli_error($connect)); } ?>

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  • retrieve value from db in php

    - by wangdoo
    I have a db in which 1 column value will be always null.I want it to pass to next page but it is passing all values of other column except this null value column. This is my code $row=mysql_query("SELECT * FROM `thirdpartycategorymaster` WHERE ISNULL(`delete`)"); while($row1=mysql_fetch_array($row)) { <td><b><a href="catdel.php?head1=<?php echo $row1['ThirdPartyCategoryName'] . '&&msg1=' . $row1['ThirdPartyCategoryID'] . '&&ctdel=' . $row1['delete']; ?> ">Delete</a></b></td> This my db table ThirdPartyCategoryID ThirdPartyCategoryName delete 29 ecommerce NULL

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  • How to check if a checkbox/ radio button is checked in php

    - by user225269
    I have this html code: <tr> <td><label><input type="text" name="id" class="DEPENDS ON info BEING student" id="example">ID</label></td> </tr> <tr> <td> <label> <input type="checkbox" name="yr" class="DEPENDS ON info BEING student"> Year</label> </td> </tr> But I don't have any idea on how do I check this checkboxes if they are checked using php, and then output the corresponding data based on the values that are checked. Please help, I'm thinking of something like this. But of course it won't work, because I don't know how to equate checkboxes in php if they are checked: <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $id = mysql_real_escape_string($_POST['idnum']); if($_POST['id'] == checked & $_POST['yr'] ==checked ){ $result2 = mysql_query("SELECT * FROM student WHERE IDNO='$id'"); echo "<table border='1'> <tr> <th>IDNO</th> <th>YEAR</th> </tr>"; while($row = mysql_fetch_array($result2)) { echo "<tr>"; echo "<td>" . $row['IDNO'] . "</td>"; echo "<td>" . $row['YEAR'] . "</td>"; echo "</tr>"; } echo "</table>"; } mysql_close($con); ?>

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  • How to know record has been updated successfully in php

    - by Lisa Ray
    $sql = "UPDATE...."; if(mysql_query($sql)) { $_SESSION['Trans']="COMMIT"; header("location:result.php"); exit; } else { $_SESSION['Trans']="FAIL"; $_SESSION['errors'] = "Error: Sorry! We are unable to update your Profile, Please contact to PNP HelpDesk."; header("location:result.php"); exit; }//end IF data is getting updated then why compiler is not coming inside IF condition.

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  • PHP from database and query

    - by Kyle R
    I have a table: id, affiliate Each time somebody clicks a link, a new row is inserted, ID being the ID of the page, and affiliate being the ID of the affiliate. For example: Page ID: 9 Affiliate ID: 1 Page ID: 9 Affiliate ID: 2 Page ID: 9 Affiliate ID: 3 I only have 3 affiliates. I want to select this information, and group them by affiliate, for the ID. I have tried this query: SELECT COUNT(*) FROM table WHERE id = '9' GROUP BY affiliate It works fine when I do it in php my admin, how do I get the info in PHP? I have tried: $q = mysql_query("SELECT COUNT(*) FROM table WHERE id = '" . $id . "' GROUP BY affiliate"); $r = mysql_fetch_array($q); When trying to print the data onto the page, I am only getting one result. Do I need to use a foreach/while loop to get all 3? How would I go about doing this? Thank you!

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  • Executing multiple update statements in PHP

    - by theband
    I have three update statements to be executed in PHP, i am getting the values of all these as return parameters. How to execute each statement independely and finally show the end user the result that it has been successfully updated. <?php public function name($parameter1,$parameter2.... $parametern) { $records=array(); $sql=""; $sql2=""; $sql3=""; $result=mysql_query($sql); //return $result; if(!$result){throw new Exception(mysql_error());} if(mysql_num_rows($result)==0){return $records;} while($row=mysql_fetch_assoc($result)){$records[]=$row;} return $records; } ?> Then how finally we can get the result in my row object.

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  • PHP - Internal APIs/Libraries - What makes sense?

    - by Mark Locker
    I've been having a discussion lately with some colleagues about the best way to approach a new project, and thought it'd be interesting to get some external thoughts thrown into the mix. Basically, we're redeveloping a fairly large site (written in PHP) and have differing opinions on how the platform should be setup. Requirements: The platform will need to support multiple internal websites, as well as external (non-PHP) projects which at the moment consist of a mobile app and a toolbar. We have no plans/need in the foreseeable future to open up an API externally (for use in products other than our own). My opinion: We should have a library of well documented native model classes which can be shared between projects. These models will represent everything in our database and can take advantage of object orientated features such as inheritance, traits, magic methods, etc. etc. As well as employing ORM. We can then add an API layer on top of these models which can basically accept requests and route them to the appropriate methods, translating the response so that it can be used platform independently. This routing for each method can be setup as and when it's required. Their opinion: We should have a single HTTP API which is used by all projects (internal PHP ones or otherwise). My thoughts: To me, there are a number of issues with using the sole HTTP API approach: It will be very expensive performance wise. One page request will result in several additional http requests (which although local, are still ones that Apache will need to handle). You'll lose all of the best features PHP has for OO development. From simple inheritance, to employing the likes of ORM which can save you writing a lot of code. For internal projects, the actual process makes me cringe. To get a users name, for example, a request would go out of our box, over the LAN, back in, then run through a script which calls a method, JSON encodes the output and feeds that back. That would then need to be JSON decoded, and be presented as an array ready to use. Working with arrays, as appose to objects, makes me sad in a modern PHP framework. Their thoughts (and my responses): Having one method of doing thing keeps things simple. - You'd only do things differently if you were using a different language anyway. It will become robust. - Seeing as the API will run off the library of models, I think my option would be just as robust. What do you think? I'd be really interested to hear the thoughts of others on this, especially as opinions on both sides are not founded on any past experience.

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  • PHP File upload fails with blank screen when size exceeds 742 KB.

    - by user284839
    Hi friends, This is one of the most bizarre errors I've come across. So I've written a little file upload web app for my friend and it works fine for any file less than or equal to 742kB in size. Needless to say, I arrived at this precise number based on relentless testing. Weird part is that if the file size is just a few KB more, for example 743 or 750, I get an error saying "MySQL has gone away". But if it is 1MB or more, then I just get a blank screen. And it happens in less than 2 seconds after I hit the upload button. So it doesn't look like a time-out to me. I checked out the PHP.ini file for post size and upload size, they are all set to 5 MB or more. And the timeout is set to 60 seconds. The uploaded file sits in MySQL database in a field of datatype mediumblob. I tried changing that to longblob. But that didn't help either. Any help? Thanks for reading, Girish

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  • PHP's PDO Prepare Method Fails While in a Loop

    - by Andrew G. Johnson
    Given the following code: // Connect to MySQL up here $example_query = $database->prepare('SELECT * FROM table2'); if ($example_query === false) die('prepare failed'); $query = $database->prepare('SELECT * FROM table1'); $query->execute(); while ($results = $query->fetch()) { $example_query = $database->prepare('SELECT * FROM table2'); if ($example_query === false) die('prepare failed'); //it will die here } I obviously attempt to prepare statements to SELET everything from table2 twice. The second one (the one in the WHILE loop) always fails and causes an error. This is only on my production server, developing locally I have no issues so it must be some kind of setting somewhere. My immediate thought is that MySQL has some kind of max_connections setting that is set to 1 and a connection is kept open until the WHILE loop is completed so when I try to prepare a new query it says "nope too many connected already" and shits out. Any ideas? EDIT: Yes I know there's no need to do it twice, in my actual code it only gets prepared in the WHILE loop, but like I said that fails on my production server so after some testing I discovered that a simple SELECT * query fails in the WHILE loop but not out of it. The example code I gave is obviously very watered down to just illustrate the issue.

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  • PHP PDO changes remote host to local hostname

    - by Wade Urry
    I'm trying to connect to a remote mysql server using PDO. However, regardless of the hostname or ip address i supply in the dsn, when the script is run it always reverts the address to the hostname of the local server where the webserver is running. Google suggests this could be something to do with SELinux and apaches ability to connect to remote databases, however i have SELinux disabled. Distro: Ubuntu 11.04 x64 Apache version: 2.2.17 PHP Version: PHP 5.3.5-1ubuntu7.11 with Suhosin-Patch (cli) Edit: Added code as requested. Though i dont believe this is an issue with my coding as it works fine on the local server, but doesnt allow remote connection. public function db_connect($driver, $dbhost, $dbname, $user, $pass) { $dsn = $driver . ':host=' . $dbhost . ';dbname=' . $dbname; try { $this->DB = new PDO($dsn, $user, $pass); } catch (PDOException $err) { print 'Database Connection Failed: ' . $err->getMessage(); die(); } } $remote_db = new DB('mysql', 'remote_server.domain.tld', 'database_name', 'user_name', 'password'); This is the error message i am receiving. Database Connection Failed: SQLSTATE[28000] [1045] Access denied for user 'user_name'@'local_server.domain.tld' (using password: YES)

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  • Tomcat6 can't connect to MySql (The driver has not received any packets from the server)

    - by Tobias Wiesenthal
    Hi all, i'm running an Apache Tomcat 6.0.20 / MySQL 5.1.37-lubuntu / sun-java6-jdk /sun-java6-jre / sun-java6-bin on my local machine using Ubuntu 9.10 as OS. I'm trying to get a simple DB-query example running for 2 days now, but i still get this Exception: org.apache.jasper.JasperException: javax.servlet.ServletException: javax.servlet.jsp.JspException: Unable to get connection, DataSource invalid: "org.apache.commons.dbcp.SQLNestedException: Cannot create PoolableConnectionFactory (Communications link failure The last packet sent successfully to the server was 0 milliseconds ago. The driver has not received any packets from the server.)" org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:522) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:398) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:342) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:267) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) root cause javax.servlet.ServletException: javax.servlet.jsp.JspException: Unable to get connection, DataSource invalid: "org.apache.commons.dbcp.SQLNestedException: Cannot create PoolableConnectionFactory (Communications link failure The last packet sent successfully to the server was 0 milliseconds ago. The driver has not received any packets from the server.)" org.apache.jasper.runtime.PageContextImpl.doHandlePageException(PageContextImpl.java:862) org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:791) org.apache.jsp.index_jsp._jspService(index_jsp.java:104) org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:374) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:342) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:267) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) root cause javax.servlet.jsp.JspException: Unable to get connection, DataSource invalid: "org.apache.commons.dbcp.SQLNestedException: Cannot create PoolableConnectionFactory (Communications link failure The last packet sent successfully to the server was 0 milliseconds ago. The driver has not received any packets from the server.)" org.apache.taglibs.standard.tag.common.sql.QueryTagSupport.getConnection(QueryTagSupport.java:285) org.apache.taglibs.standard.tag.common.sql.QueryTagSupport.doStartTag(QueryTagSupport.java:168) org.apache.jsp.index_jsp._jspx_meth_sql_005fquery_005f0(index_jsp.java:274) org.apache.jsp.index_jsp._jspx_meth_c_005fotherwise_005f0(index_jsp.java:216) org.apache.jsp.index_jsp._jspx_meth_c_005fchoose_005f0(index_jsp.java:130) org.apache.jsp.index_jsp._jspService(index_jsp.java:93) org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:374) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:342) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:267) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) my web.xml looks like this : <?xml version="1.0" encoding="utf-8"?> <web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5"> <resource-ref> <description>DB Connection</description> <res-ref-name>jdbc/testDB</res-ref-name> <res-type>javax.sql.DataSource</res-type> <res-auth>Container</res-auth> </resource-ref> </web-app> the context.xml looks like this : <?xml version="1.0" encoding="UTF-8"?> <Context path="/my1stApp" docBase="/var/www/jsp/my1stApp" debug="5" reloadable="true" crossContext="true"> <Resource name="jdbc/testDB" auth="Container" type="javax.sql.DataSource" maxActive="5" maxIdle="5" maxWait="10000" username="user" password="password" driverClassName="com.mysql.jdbc.Driver" url="jdbc:mysql://localhost:3306/some"/> </Context> and the jsp file looks like this: <%@ page contentType="text/html" %> <%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core" %> <%@ taglib prefix="fn" uri="http://java.sun.com/jsp/jstl/functions" %> <%@ taglib prefix="fmt" uri="http://java.sun.com/jsp/jstl/fmt" %> <%@ taglib prefix="sql" uri="http://java.sun.com/jsp/jstl/sql" %> <html> <head> <title>DroneLootTool</title> </head> <body bgcolor="white"> <sql:query var="res" dataSource="jdbc/testDB"> select name, othername from mytable </sql:query> <h2>Results</h2> <c:forEach var="row" items="${res.rows}"> Name ${row.name}<br/> MoreName ${row.othername}<br/><br/> </c:forEach> </body> </html> read lots of forum entries / tried lots of different settings (always changed back to original settings when it didnt' work) set TOMCAT6_SECURITY=no in /etc/default/tomcat6 because TOMCAT6_SECURITY=yes was causing trouble too the skip-networking flag is not set for the DB (BIND 127.0.0.1 is set) firewall is swiched off (sudo ufw disable) MySQL works (tested several times with user used in this skript) telnet localhost 3306 says Trying ::1... Trying 127.0.0.1... Connected to localhost. Escape character is '^]'. Connection closed by foreign host. The TestConnection.java produced the following output: me@my-laptop:~/Desktop$ java -classpath '/usr/share/java/mysql.jar:./' TestConnection com.mysql.jdbc.Driver jdbc:mysql://localhost:3306/testDB myuser mypassword com.mysql.jdbc.CommunicationsException: Communications link failure Last packet sent to the server was 0 ms ago. at com.mysql.jdbc.SQLError.createCommunicationsException(SQLError.java:1070) at com.mysql.jdbc.ConnectionImpl.createNewIO(ConnectionImpl.java:2103) at com.mysql.jdbc.ConnectionImpl.<init>(ConnectionImpl.java:718) at com.mysql.jdbc.ConnectionImpl.getInstance(ConnectionImpl.java:298) at com.mysql.jdbc.NonRegisteringDriver.connect(NonRegisteringDriver.java:282) at java.sql.DriverManager.getConnection(DriverManager.java:582) at java.sql.DriverManager.getConnection(DriverManager.java:185) at TestConnection.checkConnection(TestConnection.java:40) at TestConnection.main(TestConnection.java:21) Caused by: com.mysql.jdbc.CommunicationsException: Communications link failure Last packet sent to the server was 0 ms ago. at com.mysql.jdbc.SQLError.createCommunicationsException(SQLError.java:1070) at com.mysql.jdbc.MysqlIO.readPacket(MysqlIO.java:666) at com.mysql.jdbc.MysqlIO.doHandshake(MysqlIO.java:1069) at com.mysql.jdbc.ConnectionImpl.createNewIO(ConnectionImpl.java:2031) ... 7 more Caused by: java.io.EOFException: Can not read response from server. Expected to read 4 bytes, read 0 bytes before connection was unexpectedly lost. at com.mysql.jdbc.MysqlIO.readFully(MysqlIO.java:2431) at com.mysql.jdbc.MysqlIO.readPacket(MysqlIO.java:590) ... 9 more Connection failed. i don't know if there is a difference between the way the java driver connects to the DB and the Perl DBI module does, but this PERL skript works #!/usr/bin/perl -w use CGI; use DBI; use strict; print CGI::header(); my $dbh = DBI->connect("dbi:mysql:some:localhost", "user", "password"); my $sSql = "SELECT * from mytable"; my $ppl = $dbh->selectall_arrayref( $sSql ); foreach my $pl (@$ppl) { my @array = @$pl; print @array; } $dbh->disconnect; enabled --log-warnings on the mysql, but i didn't get any new warnings. When i was searching the logs for warnings i found this messages when i restart the tomcat, don't know if it helps to find the problem : Feb 2 19:50:37 tobias-laptop jsvc.exec[3129]: 02.02.2010 19:50:37 org.apache.catalina.startup.HostConfig checkResources#012INFO: Undeploying context [/myapp] Feb 2 19:50:37 tobias-laptop jsvc.exec[3129]: 02.02.2010 19:50:37 org.apache.catalina.loader.WebappClassLoader clearReferencesThreads#012SCHWERWIEGEND: A web application appears to have started a thread named [MySQL Statement Cancellation Timer] but has failed to stop it. This is very likely to create a memory leak. Feb 2 19:50:37 tobias-laptop jsvc.exec[3129]: 02.02.2010 19:50:37 org.apache.catalina.startup.HostConfig deployDescriptor#012INFO: Deploying configuration descriptor myapp.xml

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  • Separate php.ini file for each Apache virtual host?

    - by Calvin L
    Is it possible to have a separate php.ini file that overrides the default php.ini file for each virtual host? I'm running Apache/2.2.14, PHP 5.3.2-1. For example I have several vhosts pointing to domains in my /var/www/ directory: /var/www/website1.com /var/www/website2.com What I'd like is to be able to place a custom php.ini file in each directory that would override the default values only for that vhost, but keep the original defaults if the value isn't specified: /var/www/website1.com/htdocs/ /var/www/website1.com/php.ini

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  • cURL works but PHP cURL fails to internet [migrated]

    - by wrk2bike
    Trying to diagnose an issue using PHP to cURL to an Internet location on a RedHat Linux server. cURL is installed and working, and: <?php var_dump(curl_version()); ?> shows all the correct information in the output. The issue is I can use PHP to cURL to localhost on the box itself, but not the Internet (see below). Normally I'd suspect the firewall, but I can cURL from the command line to the Internet without a problem. The box can also update it's own software packages, etc. What am I missing? My test is: <?php function http_head_curl($url,$timeout=30) { $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_TIMEOUT, $timeout); curl_setopt($ch, CURLOPT_HEADER, 1); curl_setopt($ch, CURLOPT_NOBODY, 1); curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); $res = curl_exec($ch); if ($res === false) { throw new RuntimeException("cURL exception: ".curl_errno($ch).": ".curl_error($ch)); } return trim($res); } // Succeeds, displaying headers echo(http_head_curl('localhost')); // Fails: echo(http_head_curl('www.google.com')); ?>

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  • Web Application: Combining View Layer Between PHP and Javascript-AJAX

    - by wlz
    I'm developing web application using PHP with CodeIgniter MVC framework with a huge real time client-side functionality needs. This is my first time to build large scale of client-side app. So I combine the PHP with a large scale of Javascript modules in one project. As you already know, MVC framework seperate application modules into Model-View-Controller. My concern is about View layer. I could be display the data on the DOM by PHP built-in script tag by load some data on the Controller. Otherwise I could use AJAX to pulled the data -- treat the Controller like a service only -- and display the them by Javascript. Here is some visualization I could put the data directly from Controller: <label>Username</label> <input type="text" id="username" value="<?=$userData['username'];?>"><br /> <label>Date of birth</label> <input type="text" id="dob" value="<?=$userData['dob'];?>"><br /> <label>Address</label> <input type="text" id="address" value="<?=$userData['address'];?>"> Or pull them using AJAX: $.ajax({ type: "POST", url: config.indexURL + "user", dataType: "json", success: function(data) { $('#username').val(data.username); $('#dateOfBirth').val(data.dob); $('#address').val(data.address); } }); So, which approach is better regarding my application has a complex client-side functionality? In the other hand, PHP-CI has a default mechanism to put the data directly from Controller, so why using AJAX?

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  • I want to install and get to building a personal MySQL DB

    - by Ari Hall
    So how do I go from installing MySQL from the Software Center to inputing data into fields and bringing in a comma delimited file? I've only had brief experience with MSAccess and OOo Base a long time ago, so details are appreciated, I just want to get up and running. I have Ubuntu 10.10, 64 bit, if that affects much. If you can link me to a howto that does exactly what I'm looking for, that would work. Again, Thanks!

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  • apc.stat causes 500 internal server error

    - by Legit
    When I turn off apc.stat it causes a 500 internal server error. I checked the apache error_log and it's something about: [Tue Jun 26 10:02:59 2012] [error] [client 127.0.0.1] PHP Warning: require(): Filename cannot be empty in /var/www/site1/public/index.php on line 17 [Tue Jun 26 10:02:59 2012] [error] [client 127.0.0.1] PHP Fatal error: require(): Failed opening required '' (include_path='.:/usr/share/pear:/usr/share/php') in /var/www/site1/public/index.php on line 17 I checked that line and here's what it contains: require('./wp-blog-header.php'); I don't see anything wrong with it. Here's my current APC config: APC version: 3.1.10 PHP Version: 5.4.4 How do I resolve this error when i disable apc.stat?

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  • How to Map a CSV or Tab Delimited File to MySQL Multi-Table Database [migrated]

    - by Keefer
    I've got a pretty substantial XLS file a client provided 830 total tabs/sheets. I've designed a multi table database with PHPMyAdmin (MySQL obviously) to house the information that's in there, and have populated about 5 of those sheets by hand to ensure the data will fit into the designed database. Is there a piece of software or some sort of tool that will help me format this XLS document and map it to the right places in the database?

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  • How to change root password for mysql and phpmyadmin

    - by Jon
    I've set up mysql and phpmyadmin and chose not to set a password when installing hoping that once set up i could login with root and no password but i get the following error from phpmyadmin Login without a password is forbidden by configuration (see AllowNoPassword) I have previously moved the phpmyadmin folder to /var/www/ I have tried changing the following line $cfg['Servers'][$i]['AllowNoPassword'] = false; to $cfg['Servers'][$i]['AllowNoPassword'] = true; but still had no success, so i am wondering is there a way i can change the root passwords for both so i can access phpmyadmin and create databases. Thanks

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  • Design pattern to handle queries using multiple models

    - by coderkane
    I am presented with a dilemma while trying to re-designing the class structure for my PHP/MySQL application to make it more elegant and conform it to the SOLID principle. The problem goes like this: Let as assume, there is an abstract class called person which has certain properties to define a generic person, such as name, age, date of birth etc. There are two classes, student, and teacher, that implements this abstract class. They add their own unique properties to it. I have designed all the three classes to include all the operational logic (details of which are not relevant in context of the question). Now, I need to create views/reports/data grids which contain details from multiple classes, for example, say, a list of all students doing projects in Chemistry mentored by a teacher whose name is the parameter to the query. This is just one example of a view, there are many different views in the application, which uses data from 3-4 tables, and each of them have multiple input parameters to generate them. Considering this particular example, I have written the relevant query using JOIN and the results are as expected and proper, now here is the dilemma: Keeping in mind the single responsibility principle, where should I keep this query? It does not belong to either Student class, or Teacher class or any other classes currently present. a) Should I create a new class, say dataView class, and design it as a MVC pattern and keep the query there? What about the other views? how do they fit in this architecture? b) Should I not keep the query in code at all, and make it DB View ? c) Am I completely wrong in the approach? If so what is the right approach? My considerations are as follows: a) should be easy to add new views later on if requirement comes, without having to copy-paste-modify code b) would like to make it as loosely coupled as possible so that if minor db structure changes happen, it does not break I did google searches on report design and OOP report generators, but all the result seem to focus on the visual design of the report rather than fetching the data. I have already taken care of the visual aspect of the report using MVC with html templates. I am sure this is a very fundamental problem with known solution, but I am somehow not able to find it (maybe searching with wrong keyword). Edit1: Modified the title to make it more relevant Edit2: The accepted answer got me thinking in the right direction and identify my design flaws, which eventually led me to find this question and the solution in Stack Overflow which gave me the detailed answer to clear the confusion.

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  • PHP frameworks - should I use them?

    - by 30secondstosam
    First of all let me explain who I am: I am a PHP Developer working for a company developing their CMS which handles online stores, data feeds and other content like blogs. I have been programming for 6 years and 4 of those have been in PHP. (I used to be a C# developer). My question is regarding PHP frameworks. I see so many jobs asking for zend, cakephp and other MVC types of frameworks. However, even as an experienced developer I have never used a PHP framework. Should I start learning? If so where do I even start as there are so many. I am about to re-write so much of my work's CMS and I'm wondering whether I could help myself a lot by using a framework. What do people think? Considering I will be re-writing a lot of the online store stuff... I am experienced in OO and I have used the .NET framework in the past. Thanks in advance for the replies.

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  • Assuming "clean code/architecture" is there a difference in "effort" between PHP or Java/J2EE web application development?

    - by PhD
    A client asked us to estimate effort when selecting PHP as the implementation language for his next web-based application. We spent about a week exploring PHP, prototyping, testing etc., We are quite new to this language - may have hacked around it in the past but, let's go with PHP-noobs but application development experts (for the lack of a better, less flattering word :) It seems, that if we write, clean maintainable code, follow separation of concerns, enterprise architecture patters (DAOs etc.) the 'effort' in creating an object-oriented PHP based web-application seems to be the same for a Java based one. Here's our equation for estimating the effort (development/delivery time): ConstructionEffort = f(analysis, design, coding, testing, review, deployment) We were specifically comparing effort estimates in creating an enterprise application with the following: PHP + CakePHP/CodeIgniter (should we have considered others?) Java + Spring + Restlet It's an end-to-end application: Client: Javascript/jQuery + HTML/CSS Middle tier/Business Logic - (Still evaluating PHP/Java) Database: MySQL The effort estimates of the 1st and 3rd tier are constant and relatively independent of the middle tier's technology. At a high level with an initial breakdown into user stories of the requested features as well as a high-level SWAG on the sheer number of classes/SLOC that would be required for PHP doesn't seem to differ by much from what is required of the same in Java. Is this correct? We are basing our initial estimates on the initial prototyping/coding we've done with PHP - we are currently disregarding fluency with the language as a factor, since that'll be an initial hurdle and not a long term impediment IMHO (we also have sufficient time to become quite fluent with PHP). I'm interested in knowing the programmers' perspective with respect to effort when creating similar applications with either of the languages to justify choosing one over the other. Are we missing something here? It seems we are going against popular belief of PHP being quicker to market (or we being very fluent with Java have our vision clouded). It doesn't seem to have any coding/programming effort saving from what we/ve played around with.

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  • How to install MySQL 5.6?

    - by Ross Smith II
    I just installed Ubuntu 12.10 (amd64), and want to install a recent version of MySQL 5.6. If possible, I would like to install (not upgrade) it the "Debian Way' (i.e., using apt-get or dpkg). The only binaries I could find are here. Unfortunately, they are incomplete, as they only install files in /usr/share. If binaries aren't available, how could I install it from source, using the standard Debian method of installing from source. Thanks for any assistance.

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  • Upgrade MySQL to 5.5 on Lucid, upgrade server to Precise or switch to Percona?

    - by xref
    Looking into upgrading mysql on our development server to which is running 10.04 so is stuck at MySQL 5.1, as it appears there is no apt-get support for upgrading to 5.5 except by certain 3rd party PPAs. So I'm looking for which route to take and what other people have done: a) Follow a couple year old guide to manually install MySQL 5.5 and then invest ongoing time into manually downloading and installing security updates every month or two? b) Upgrade 10.04 to 12.04, and from other peoples experience I work with spend several days working out the kinks of that large upgrade, then I'll have access to mysql 5.5 and easy apt-get installation of future security updates? c) Switch from MySQL to Percona Server 5.5 and get all the benefits of that version of mysql, plus easy apt-get updates with their PPA? d) Something else?

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