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  • Django multiple generic_inline_formset in a view

    - by Can Burak Cilingir
    We have a bunch of formsets: EmailAddressInlineFormSet = generic_inlineformset_factory( EmailAddress, extra=1, exclude=["created_by","last_modified_by"]) emailaddressformset = EmailAddressInlineFormSet( instance=person, prefix="emailaddress") # [ more definitions ] and, in the view, we process them as: emailaddressformset = EmailAddressInlineFormSet( request.POST, instance=person, prefix="emailaddress") # [ more definitions ] So, nothing fancy or unordinary. The unfortunate or unordinary fact is, we have 15 of these formsets, one for email addresses, other for phone numbers etc. so the view code is ugly and not-so-manageable. What would be the most unhackish way to handle this number of formsets in a single view? At the end -i guess- I'm looking for a class or a functionality like multiple_generic_inline_formset and open to all kind of suggestions or discussions.

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  • get average from set of objects in django

    - by dotty
    Hay, i have a simple rating system for a property. You give it a mark out of 5 (stars). The models are defined like this def Property(models.Model) # stuff here def Rating(models.Model) property = models.ForeignKey(Property) stars = models.IntegerField() What i want to do is get a property, find all the Rating objects, collect them, then get the average 'stars' from them. any ideas how to do this?

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  • Check request type in Django

    - by Art
    While it is recommended to use the following construct to check whether request is POST, if request.method == 'POST': pass It is likely that people will find if request.POST: pass to be more elegant and concise. Are there any reasons not to use it, apart from personal preference?

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  • django handling file uploads - target different than media folder

    - by Tom Tom
    Hi, I want to enable the user to upload media which will not be saved in the media folder. When I use the following line of code data will be uploaded to media/upload/logo . logo_img = models.FileField(upload_to='upload/logo', blank=True) I'm wondering how I can change this behaviour. I would try to write a custom FileField and a view that serves the data based on the database entries. I do not want to place the data the user uploads to the media folder, since it is no public data. Is this approach correct? Are there solutions out there which do exactly what I want and I would reinvent the wheel with implementing this by myself? Would appreciate any help!

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  • Django/jQuery - read file and pass to browser as file download prompt

    - by danspants
    I've previously asked a question regarding passing files to the browser so a user receives a download prompt. However these files were really just strings creatd at the end of a function and it was simple to pass them to an iframe's src attribute for the desired effect. Now I have a more ambitious requirement, I need to pass pre existing files of any format to the browser. I have attempted this using the following code: def return_file(request): try: bob=open(urllib.unquote(request.POST["file"]),"rb") response=HttpResponse(content=bob,mimetype="application/x-unknown") response["Content-Disposition"] = "attachment; filename=nothing.xls" return HttpResponse(response) except: return HttpResponse(sys.exc_info()) With my original setup the following jQuery was sufficient to give the desired download prompt: jQuery('#download').attr("src","/return_file/"); However this won't work anymore as I need to pass POST values to the function. my attempt to rectify that is below, but instead of a download prompt I get the file displayed as text. jQuery.get("/return_file/",{"file":"c:/filename.xls"},function(data) { jQuery(thisButton).children("iframe").attr("src",data); }); Any ideas as to where I'm going wrong? Thanks!

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  • Django: problem with merging querysets after annotation

    - by Björn Lilja
    Hi I have a manager for "Dialog" looking like this: class AnnotationManager(models.Manager): def get_query_set(self): return super(AnnotationManager, self).get_query_set().annotate( num_votes=Count('vote', distinct=True), num_comments=Count('comment', distinct=True), num_commentators = Count('comment__user', distinct=True), ) Votes and Comments has a ForeignKey to Dialog. Comments has a ForeignKey to User. When I do this: dialogs_queryset = Dialog.public.filter(organization=organization) dialogs_popularity = dialogs_queryset.exclude(num_comments=0) | dialogs_queryset.exclude(num_votes=0) ...dialogs_popularity will never returned the combination, but only the dialogs with more than 0 comments, or if I change the order of the OR, the dialogs with more than 0 votes! To me, the expected behavior would be to get the dialogs with more than 0 votes AND the dialogs with more than 0 comments. What am I missing? Or is there a bug in the annotation behavior here?

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  • Model objects versions in Django

    - by pablo
    Hi I'm building an e-commerce website. I have a Product and Order models. It's possible that a customer order a product and then the admin change its price or other fields before the customer actually get it. A possible solution is to add a 'version' field to the Product model. When the admin update a product field I'll add a timestamp and create a new object instead of updating the old one. An Order will have a reference to a specific product version. Does this make sense? Will overriding the Product Save method be sufficient to make it work? Thanks

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  • Create hyperlink in django template of object that has a space

    - by Ed
    I am trying to create a dynamic hyperlink that depends on a value passed from a function: {% for item in field_list %} <a href={% url index_view %}{{ item }}/> {{ item }} </a> <br> {% endfor %} The problem is that one of the items in field_list is "Hockey Player". The link for some reason is dropping everything after the space, so it creates the hyperlink on the entire "Hockey Player", but the address is http://126.0.0.1:8000/Hockey How can I get it to go to http://126.0.0.1:8000/Hockey Player/ instead?

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  • django m2m how can i get m2m table elements in a view

    - by dana
    i have a model using m2m feature: class Classroom(models.Model): user = models.ForeignKey(User, related_name = 'classroom_creator') classname = models.CharField(max_length=140, unique = True) date = models.DateTimeField(auto_now=True) open_class = models.BooleanField(default=True) members = models.ManyToManyField(User,related_name="list of invited members", through = 'Membership') and i want to take all members of one class in a view and display them using the template system. In the view, i'm trying to take all the members from a classroom like that: def inside_classroom(request,classname): try: theclass = Classroom.objects.get(classname = classname) members = Members.objects.all() etc but it doesn't work,(though the db_table is named Classroom_Members) i guess i have to use another query for getting all the members from the classroom classname. also, i want to verify if the request.user is a member using (if request.user in members) how can i het those members? Thanks in advance!

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  • Django: Applying Calculations To A Query Set

    - by TheLizardKing
    I have a QuerySet that I wish to pass to a generic view for pagination: links = Link.objects.annotate(votes=Count('vote')).order_by('-created')[:300] This is my "hot" page which lists my 300 latest submissions (10 pages of 30 links each). I want to now sort this QuerySet by an algorithm that HackerNews uses: (p - 1) / (t + 2)^1.5 p = votes minus submitter's initial vote t = age of submission in hours Now because applying this algorithm over the entire database would be pretty costly I am content with just the last 300 submissions. My site is unlikely to be the next digg/reddit so while scalability is a plus it is required. My question is now how do I iterate over my QuerySet and sort it by the above algorithm? For more information, here are my applicable models: class Link(models.Model): category = models.ForeignKey(Category, blank=False, default=1) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) modified = models.DateTimeField(auto_now=True) url = models.URLField(max_length=1024, unique=True, verify_exists=True) name = models.CharField(max_length=512) def __unicode__(self): return u'%s (%s)' % (self.name, self.url) class Vote(models.Model): link = models.ForeignKey(Link) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) def __unicode__(self): return u'%s vote for %s' % (self.user, self.link) Notes: I don't have "downvotes" so just the presence of a Vote row is an indicator of a vote or a particular link by a particular user.

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  • Django/Python: Save an HTML table to Excel

    - by kchau
    I have an HTML table that I'd like to be able to export to an Excel file. I already have an option to export the table into an IQY file, but I'd prefer something that didn't allow the user to refresh the data via Excel. I just want a feature that takes a snapshot of the table at the time the user clicks the link/button. I'd prefer it if the feature was a link/button on the HTML page that allows the user to save the query results displayed in the table. Is there a way to do this at all? Or, something I can modify with the IQY? I can try to provide more details if needed. Thanks in advance.

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  • [Django] Change state of obiects

    - by gameboy
    hi I have following problem. I have model: class Towar(models.Model): nrSeryjny=models.CharField(max_length=100) opis=models.CharField(max_length=255) naStanie=models.NullBooleanField(null=True) def __unicode__(self): return "%s" % self.opis def lowerName(self): return self.__class__.__name__.lower() def checkState(self): return self.naStanie def changeState(self,state): self.naStanie=state class Meta: ordering=['nrSeryjny'] app_label = 'baza' permissions=(("view_towar","mozna miec podglad dla towar"),) and model : class Wypozyczenie(models.Model): dataPobrania=models.DateField() pracownik=models.ForeignKey(User,null=True) kontrahent=models.ForeignKey(Kontrahenci,null=True) towar=models.ForeignKey(Towar,null=True) objects=WypozyczenieManager() default_objects=models.Manager() ZwrotyObjects=WypozyczenieZwrotyManager() def lowerName(self): return self.__class__.__name__.lower() def __unicode__(self): if self.towar == None: return "Dla:%s -- Kto:%s -- Kiedy:%s -- Co:%s" % (self.kontrahent,self.pracownik,self.dataPobrania,"Brak") else: return "Dla:%s -- Kto:%s -- Kiedy:%s -- Co:%s" % (self.kontrahent,self.pracownik,self.dataPobrania,self.towar) class Meta: ordering=['dataPobrania'] app_label = 'baza' permissions=(("view_wypozyczenie","mozna miec podglad dla wypozyczenie"),) and view to adding models: def modelAdd(request,model,modelForm): mod=model() if request.user.has_perm('baza.add_%s' % mod.lowerName()): if request.method=='POST': form=modelForm(request.POST) if form.is_valid(): form.save() return HttpResponseRedirect('/'+ mod.lowerName() + '/') else: form=modelForm() v=RequestContext(request,{'form':form}) return render_to_response('add_form.html',v) and i whant do that, when i add Wypozyczenie and save it then the Towar that is stored by Wypozyczenie change his na stanie from True to False Greets

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  • Combining regroup with get_foo_display in Django templates

    - by shacker
    I'm using the regroup template tag to group queryset output on a Choices field. In the model: RESOURCE_TYPES = ( ('tut','External tutorial'), ('read','Additional reading'), ('org','Company or organization'), ) restype = models.CharField('Resource type',max_length=6,choices=RESOURCE_TYPES) in the view: resources = Resource.objects.filter(tutorial=tutorial) in the template: {% regroup resources by restype as resource_list %} {% for type in resource_list %} <h3>{{type.grouper}}</h3> So type.grouper renders as 'tut' or 'org' on the page, rather than the long form. Normally you would use the get_foo_display syntax to get at the value of the choice, rather than the key. But the value doesn't seem to be available after going through regroup. There's no way I can find to use get_foo_display on {{type.grouper}}. It makes sense when you think about it, but what's the workaround? Thanks.

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  • Filtering foreign keys with AJAX in Django admin

    - by cnobile
    I have most of this figured out already. I have AJAX returning the region/state/province when a country is selected. The correct foreign key is saved to the database, however, when the record is viewed afterwards the selected state is not shown in the select nor are any states for the selected country. I understand why this is happening as, the admin view is not aware of the relation between the state and the country. So here is the question. Is there a hook in the admin view that will allow me to load the correct states for the country and set the selected attribute on the option in the select tag? Or how can I override the admin view for any forms that require the country and region/state/province set? I am using jQuery and Djando-1.1. Thanks

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  • what is this 'map' mean..in django

    - by zjm1126
    this is the code: def create(request, form_class=MapForm, template_name="maps/create.html"): map_form = form_class(request.POST or None) if map_form.is_valid(): map = map_form.save(commit=False) and the map_form is : class MapForm(forms.ModelForm): slug = forms.SlugField(max_length=20, help_text = _("a short version of the name consisting only of letters, numbers, underscores and hyphens."), #error_message = _("This value must contain only letters, numbers, underscores and hyphens.")) ) def clean_slug(self): if Map.objects.filter(slug__iexact=self.cleaned_data["slug"]).count() > 0: raise forms.ValidationError(_("A Map already exists with that slug.")) return self.cleaned_data["slug"].lower() def clean_name(self): if Map.objects.filter(name__iexact=self.cleaned_data["name"]).count() > 0: raise forms.ValidationError(_("A Map already exists with that name.")) return self.cleaned_data["name"] class Meta: model = Map fields = ('name', 'slug', 'description')

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  • Saving model object in django throws no error but attribute value doesn't change

    - by Pilgrim
    Hi. I get a model object, change an attribute, save it and it still has the old attribute: >>> g = SiteProfile.objects.get(pk=3) >>> g.renew_date datetime.date(2010, 4, 11) >>> g.renew_date = date.today()+timedelta(days=365) >>> g.renew_date datetime.date(2011, 4, 11) >>> g.save() >>> g.renew_date datetime.datetime(2010, 4, 11, 16, 57, 4, 192684) Anyone know if this is an issue with the database or something else?

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  • Django Admin: Many-to-Many listbox doesn't show up with a through parameter

    - by NP
    Hi All, I have the following models: class Message(models.Model): date = models.DateTimeField() user = models.ForeignKey(User) thread = models.ForeignKey('self', blank=True, null=True) ... class Forum(models.Model): name = models.CharField(max_length=24) messages = models.ManyToManyField(Message, through="Message_forum", blank=True, null=True) ... class Message_forum(models.Model): message = models.ForeignKey(Message) forum = models.ForeignKey(Forum) status = models.IntegerField() position = models.IntegerField(blank=True, null=True) tags = models.ManyToManyField(Tag, blank=True, null=True) In the admin site, when I go to add/change a forum, I don't see the messages listbox as you'd expect. However, it shows up if I remove the 'through' parameter in the ManyToManyField declaration. What's up with that? I've registered all three models (plus Tag) to the admin site in admin.py. TIA

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  • django url - link problem

    - by dana
    i have an application, and in my urls.py i have something like that: urlpatterns = patterns('', url(r'^profile_view/(?P<id>\d+)/$', profile_view, name='profile_view'),) meaning that the profile_view function has id as a parameter. Now, i want to call that function from my template, using a link like Reply The problem is that i don't know how to use the above url as a link, meaning how can i 'pass the id parameter to a link'? thank you

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  • How to save to Django Model that Have Mulitple Foreign Keys Fields

    - by Spikie
    I have Models for business Apps class staff_name(models.Model): TITLE_CHOICES = ( ('Mr', 'Mr'), ('Miss', 'Miss'), ( 'Mrs', 'Mrs'), ( 'chief', 'chief'), ) titlename = models.CharField(max_length=10,choices=TITLE_CHOICES) firstname = models.CharField(max_length=150) surname = models.CharField(max_length=150) date = models.DateTimeField(auto_now=True) class meta: ordering = ["date"] get_latest_by = "date" class inventory_transaction(models.Model): stock_in = models.DecimalField(blank=True, null=True,max_digits=8, decimal_places=2) stock_out = models.DecimalField(blank=True,null=True,max_digits=8, decimal_places=2) Number_container = models.ForeignKey(container_identity) staffs = models.ForeignKey(staff_name) goods_details = models.ForeignKey(departments) balance = models.DecimalField(max_digits=8, decimal_places=2) date = models.DateTimeField(auto_now=True) What i want to accomplish is check if the staff have made entry to the table before if yes add the value for the stock in plus (last) balance field and assign to balance if no just assign stock in value to balance field and save these are my codes These are my codes: try: s = staffname.staffs_set.all().order_by("-date").latest() # staffname is the instant of the class model staff_name e = s.staffs_set.create(stockin=vdataz,balance=s.balance + vdataz ) # e is the instant of the class model inventory_transaction e.save e.staffs.add(s) e.from_container.add(containersno) e.goods_details.add(department) except ObjectDoesNotExist: e = staff_name.objects.create(stockin=vdataz,balance=vdataz ) e.save e.staffs.add(staffname) e.from_container.add(containersno) e.goods_details.add(department) I will really appreciate a solution Thanks I hope it make more sense now. iam on online if you need more explanation just ask in the comment.Thank you for your help

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  • Django finding which field matched in a multiple OR query

    - by Greg Hinch
    I've got a couple models which are set up something like this: class Bar(models.Model): baz = models.CharField() class Foo(models.Model): bar1 = models.ForeignKey(Bar) bar2 = models.ForeignKey(Bar) bar3 = models.ForeignKey(Bar) And elsewhere in the code, I end up with an instance of Bar, and need to find the Foo it is attached to in some capacity. Right now I came up with doing a multiple OR query using Q, something like this: foo_inst = Foo.objects.get(Q(bar1=bar_inst) | Q(bar2=bar_inst) | Q(bar3=bar_inst)) What I need to figure out is, which of the 3 cases actually hit, at least the name of the member (bar1, bar2, or bar3). Is there a good way to do this? Is there a better way to structure the query to glean that information?

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  • Django - foreignkey problem

    - by realshadow
    Hey, Imagine you have this model: class Category(models.Model): node_id = models.IntegerField(primary_key = True) type_id = models.IntegerField(max_length = 20) parent_id = models.IntegerField(max_length = 20) sort_order = models.IntegerField(max_length = 20) name = models.CharField(max_length = 45) lft = models.IntegerField(max_length = 20) rgt = models.IntegerField(max_length = 20) depth = models.IntegerField(max_length = 20) added_on = models.DateTimeField(auto_now = True) updated_on = models.DateTimeField(auto_now = True) status = models.IntegerField(max_length = 20) node = models.ForeignKey(Category_info, verbose_name = 'Category_info', to_field = 'node_id' The important part is the foreignkey. When I try: Category.objects.filter(type_id = type_g.type_id, parent_id = offset, status = 1) I get an error that get returned more than category, which is fine, because it is supposed to return more than one. But I want to filter the results trough another field, which would be type id (from the second Model) Here it is: class Category_info(models.Model): objtree_label_id = models.AutoField(primary_key = True) node_id = models.IntegerField(unique = True) language_id = models.IntegerField() label = models.CharField(max_length = 255) type_id = models.IntegerField() The type_id can be any number from 1 - 5. I am desparately trying to get only one result where the type_id would be number 1. Here is what I want in sql: SELECT n.*, l.* FROM objtree_nodes n JOIN objtree_labels l ON (n.node_id = l.node_id) WHERE n.type_id = 15 AND n.parent_id = 50 AND l.type_id = 1 Any help is GREATLY appreciated. Regards

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