Search Results

Search found 33297 results on 1332 pages for 'java java ee'.

Page 870/1332 | < Previous Page | 866 867 868 869 870 871 872 873 874 875 876 877  | Next Page >

  • How do I find resources in a .jar on the classpath?

    - by Brabster
    If I have a collection of resource files in a directory on my classpath, I can enumerate them using ClassLoader.getResources(location). For example if I have /mydir/myresource.properties on the classpath, I can call the classloader's getResources("mydir") and get an enumeration of URLs containing myresource.properties. When I pack up the exact same resources into a .jar, I don't get anything in the enumeration of URLs when I make the call. I've only replaced the folder structure with a jar containing those folders (it's a webapp, so the jar is going into /WEB-INF/lib). I've also got a number of other calls using getResourceAsStream(location) to get other resources individually by name and they're all working fine. What's different about enumerating resources when the resources are in a .jar?

    Read the article

  • Instantiating spring beans in dynamically created classes.

    - by Xetius
    I am dynamically creating classes which contain spring beans, however the beans are not getting instantiated or initialised, leaving them as null. How do I make sure that a dynamically created class creates all of its spring beans properly? This is how I am dynamically creating the class: Class ctransform; try { ctransform = Class.forName(strClassName); Method handleRequestMethod = findHandleRequestMethod(ctransform); if (handleRequestMethod != null) { return (Message<?>) handleRequestMethod.invoke(ctransform.newInstance(), message); } } This leaves all spring bean objects within ctransform (of type strClassName) as null.

    Read the article

  • Deploy to web container, bundle web container or embed web container...

    - by Jason
    I am developing an application that needs to be as simple as possible to install for the end user. While the end users will likely be experience Linux users (or sales engineers), they don't really know anything about Tomcat, Jetty, etc, nor do I think they should. So I see 3 ways to deploy our applications. I should also state that this is the first app that I have had to deploy that had a web interface, so I haven't really faced this question before. First is to deploy the application into an existing web container. Since we only deploy to Suse or RedHat this seems easy enough to do. However, we're not big on the idea of multiple apps running in one web container. It makes it harder to take down just one app. The next option is to just bundle Tomcat or Jetty and have the startup/shutdown scripts launch our bundled web container. Or 3rd, embed.. This will probably provide the same user experience as the second option. I'm curious what others do when faced with this problem to make it as fool proof as possible on the end user. I've almost ruled out deploying into an existing web container as we often like to set per application resource limits and CPU affinity, which I believe would affect all apps deployed into a web container/app server and not just a specific application. Thank you.

    Read the article

  • How to give full path name in JSP programming?

    - by sujoy
    Actually when I run a particular JSP page it run perfectly(with external style sheet) but when servlet return back the control through RequestDispatcher, the page is not displaying properly means it don't took the css file path. In my program the stylesheet is present inside css directory and the page is present inside another directory named JSP. The code which include the css in the program is- <link rel="stylesheet" href="../css/stylesheet.css" type="text/css"/>

    Read the article

  • Viewing directory containing MIME encoded email messages

    - by Mark
    I have an application which generates and sends MIME encoded messages (javax.mail.internet.MimeMessage) through an SMTP server. As part of the development process only, I'd like to be able to view these messages rather than send them (I know the sending works just fine, but there are restrictions on the domains within the dev environment which makes it a little difficult) I thought the easiest way would be to save the text for each message to a directory, then point "an app" at the directory and check them over. So the question is, what would be a good app to use? Is it as simple as configuring Outlook or another email client to do it? Thanks

    Read the article

  • Connecting GPS coordinates taken from a database in Android using Overlay

    - by LordSnoutimus
    I am currently building an application that allows users to track where their phone has been on a Google Map. At the moment, when the onLocationChanged() method is called, the application stores the current GPS longitude and latitude in a database and calls the animateTo() method to the current position. Using SDK 1.5, how would I go about connecting these points with a coloured line drawn on the MapView using an Overlay?.

    Read the article

  • Playing BG Music Across Activities in Android

    - by scarface
    Hello! First time to ask a question here at stackoverflow. Exciting! Haha. We're developing an Android game and we play some background music for our intro (we have an Intro Activity) but we want it to continue playing to the next Activity, and perhaps be able to stop or play the music again from anywhere within the application. What we're doing at the moment is play the bgm using MediaPlayer at our Intro Activity. However, we stop the music as soon as the user leaves that Activity. Do we have to use something like Services for this? Or is MediaPlayer/SoundPool enough? If anyone knows the answer, we'd gladly appreciate your sharing it with us. Thanks!

    Read the article

  • How should I link two items with MouseMovementListeners?

    - by user1708810
    I'm working on a program that will display two "views" of the same set of items. So I need to have something set up so that when the top down view is changed, the side view is updated (and vice versa). Here's a brief outline of the relevant code so you can get an idea of my structure so far: public class DraggableComponent extends JComponent { //Contains code for MouseMovementListener that makes the item draggable } public class ItemGraphic extends DraggableComponent { //Code to render the graphic } public class Item { private ItemGraphic topGraphic; private ItemGraphic sideGraphic; } I'm able to get each graphic to display fine in my GUI. I can also independently drag each graphic. I'm missing the "linking." Some ideas I've been thinking about: Have one listener for the whole GUI. Loop through each Item and if the cursor is within the bounds of either graphic, move the other graphic. I'm concerned about the efficiency of this method. Multiple "paired" listeners (not quite sure how this would work, but the idea is that each graphic would have a listener for the other paired graphic)

    Read the article

  • Android game logic problem

    - by semajhan
    I'm currently creating a game and have a problem which I think I know why it is occurring but not entirely sure and even if I knew, don't know how to solve. I have a 2D array 10 x 10 and have a "player" class that takes up a tile. Now, I have created 2 instances of the player and move them around via swiping. Around the edges I have put "walls" that the player cannot walk through and everything works fine, until I remove a wall. Once I remove a wall and move the character/player to the edge of the screen, the player cannot go any further. The problem occurs here, where the second instance of the player is not at the edge of the screen but say 2 tiles from the first instance of "player" who is at the edge. If I try moving them further into the direction of the edge, I understand that the first instance of player wouldn't move or do anything but the second instance of player should still move, but it won't. This is the code that executed when the user swipes: if (player.getArrayX() - 1 != player2.getArrayX()) { player.moveLeft(); } else if (player.getArrayX() - 1 == player2.getArrayX() && player.getArrayY() != player2.getArrayY()) { player.moveLeft(); } if (player2.getArrayX() - 1 != player.getArrayX()) { player2.moveLeft(); } else if (player2.getArrayX() - 1 == player.getArrayX() && player2.getArrayY() != player.getArrayY()) { player2.moveLeft(); } In the player class I have: public void moveLeft() { if (alive) { switch (levelMaster.getLevel1(getArrayX() - 1, getArrayY())) { case 0: break; case 1: subX(); // basically moves player left setArrayX(getArrayX() - 1); // shifts x coord of player 1 within tilemap Log.d("semajhan", "x: " + getArrayX()); break; case 9: subX(); setArrayX(getArrayX() - 1); setAlive(false); break; } } } Any help on the matter or further insight would be greatly appreciated, thanks.

    Read the article

  • Issues regarding playing audio files in a JME midlet.

    - by Northernen
    I am making a midlet which is to be used to play out local audio files. It is obviously not working. I am getting a null reference on the "is" variable, in the code snippet shown below. 1. try{ 2. System.out.println("path: " + this.getClass()); 3. InputStream is = this.getClass().getResourceAsStream("res/01Track.wav"); 4. p1=Manager.createPlayer(is, "audio"); 5. p1.realize(); 6. p1.prefetch(); 7. p1.start(); 8. } 9. catch(Exception e){ 10. System.out.println(e.getMessage()); 11. } I assume there is something wrong with the "this.getClass().getResourceAsStream("res/01Track.wav")" bit, but I can not for the life of me figure out why, and I have tried referring to the file in 20 different ways. If I printline "this.getClass()" it gives me "path: class Mp3spiller". The absolute path to "01Track.wav" is "E:\Mine dokumenter\Dokumenter\workspace_mobiljava\Mp3spiller\res\01Track.wav". Am I completely wrong in thinking that I should refer relatively to "E:\Mine dokumenter\Dokumenter\workspace_mobiljava\Mp3spiller"? If anyone could point out what I am doing wrong, I would be grateful. I have basically stolen the code from a tutorial I found online, so I would have thought it would be working.

    Read the article

  • How to use a delay in a swing application

    - by M.R.
    I am building a swing application. At some point, I have to start an "animation": ... jpanel1.setBackground(Color.Black); Delay(milli) jpanel1.setBackground(Color.White); ... and so on. The gui itself and all the logic behind it work.It is just this time depended color-changing that does not. I have read, that swing is not thread safe, but all the examples I found showed me how to start another thread (for example in the background) but never how to stop the current swing-gui thread.

    Read the article

  • Struts logic:iterate input field

    - by camilos
    I currently have the following code and the data is displayed fine. <logic:iterate name="myList" id="product" indexId="iteration" type="com.mycompany.MyBean"> <tr> <td> <bean:write name="product" property="weight"/> </td> <td> <bean:write name="product" property="sku"/> </td> <td> <bean:write name="product" property="quantity"/> </td> </tr> </logic:iterate> But now I need to make the "quantity" part modifiable. The user should be able to update that field, press submit and when its sent to the server, "myList" should automatically update with the new quantities. I've tried searching for help on this but all I keep finding is examples on how to display data only, not modify it. Any help would be appreciated.

    Read the article

  • Write to text file using ArrayList

    - by Ugochukwutubelum Chiemenam
    The program is basically about reading from a text file, storing the current data into an ArrayList, then writing data (from user input) into the same text file. Kindly let me know where I am going wrong in this sub-part? The data inside the text file is as follows: abc t1 1900 xyz t2 1700 The compiler is showing an error at the line output.format("%s%s%s%n", public class justTesting { private Scanner input; private Formatter output; private ArrayList<Student> tk = new ArrayList<Student>(); public static void main(String[] args) { justTesting app = new justTesting(); app.create(); app.writeToFile(); } public void create() { Text entry = new Text(); Scanner input = new Scanner(System.in); System.out.printf("%s\n", "Please enter your name, ID, and year: "); while (input.hasNext()) { try { entry.setName(input.next()); entry.setTelNumber(input.next()); entry.setDOB(input.next()); for (int i = 0; i < tk.size(); i++) { output.format("%s%s%s%n", tk.get(i).getName(), tk.get(i) .getTelNumber(), tk.get(i).getDOB()); } } catch (FormatterClosedException fce) { System.err.println("Error writing to file."); return; } catch (NoSuchElementException nsee) { System.err.println("Invalid input. Try again: "); input.nextLine(); } System.out.printf("%s\n", "Please enter your name, ID, and year: "); } } public void writeToFile() { try { output = new Formatter("testing.txt"); } catch (SecurityException se) { System.err .println("You do not have write access permission to this file."); System.exit(1); } catch (FileNotFoundException fnfe) { System.err.println("Error opening or creating file."); System.exit(1); } } }

    Read the article

  • Generics in return types of static methods and inheritance

    - by Axel
    Generics in return types of static methods do not seem to get along well with inheritance. Please take a look at the following code: class ClassInfo<C> { public ClassInfo(Class<C> clazz) { this(clazz,null); } public ClassInfo(Class<C> clazz, ClassInfo<? super C> superClassInfo) { } } class A { public static ClassInfo<A> getClassInfo() { return new ClassInfo<A>(A.class); } } class B extends A { // Error: The return type is incompatible with A.getClassInfo() public static ClassInfo<B> getClassInfo() { return new ClassInfo<B>(B.class, A.getClassInfo()); } } I tried to circumvent this by changing the return type for A.getClassInfo(), and now the error pops up at another location: class ClassInfo<C> { public ClassInfo(Class<C> clazz) { this(clazz,null); } public ClassInfo(Class<C> clazz, ClassInfo<? super C> superClassInfo) { } } class A { public static ClassInfo<? extends A> getClassInfo() { return new ClassInfo<A>(A.class); } } class B extends A { public static ClassInfo<? extends B> getClassInfo() { // Error: The constructor ClassInfo<B>(Class<B>, ClassInfo<capture#1-of ? extends A>) is undefined return new ClassInfo<B>(B.class, A.getClassInfo()); } } What is the reason for this strict checking on static methods? And how can I get along? Changing the method name seems awkward.

    Read the article

  • problem with uploading arabic files

    - by sword101
    I am using Spring upload to upload files. When uploading an Arabic file and getting the original file name in the controller, I get something like: &#1575;&#1604;&#1605;&#1594;&#1601;&#1604;&#1610;&#1606;.png Any ideas why this problem occur?

    Read the article

  • inheritance problem OOP extend

    - by hsmit
    If a Father is a Parent and a Parent is a Person and a Person has a Father I create the following: class Person{ Father father; } class Parent extends Person{} class Father extends Parent{} Instances: Person p1 = new Person(); Person p2 = new Person(); p1.father = p2; //father is of the type Father This doesn't work... Now try casting:: Person p1 = new Person(); Person p2 = new Person(); p1.father = (Father)p2; This doesn't work either. What does work for this case?

    Read the article

  • how to handle empty selection in a jface bound combobox?

    - by guido
    I am developing a search dialog in my eclipse-rcp application. In the search dialog I have a combobox as follows: comboImp = new CCombo(grpColSpet, SWT.BORDER | SWT.READ_ONLY); comboImp.setBounds(556, 46, 184, 27); comboImpViewer = new ComboViewer(comboImp); comboImpViewer.setContentProvider(new ArrayContentProvider()); comboImpViewer.setInput(ImpContentProvider.getInstance().getImps()); comboImpViewer.setLabelProvider(new LabelProvider() { @Override public String getText(Object element) { return ((Imp)element).getImpName(); } }); Imp is a database entity, ManyToOne to the main entity which is searched, and ImpContentProvider is the model class which speaks to embedded sqlite database via jpa/hibernate. This combobox is supposed to contain all instances of Imp, but to also let empty selection; it's value is bound to a service bean as follows: IObservableValue comboImpSelectionObserveWidget = ViewersObservables.observeSingleSelection(comboImpViewer); IObservableValue filterByImpObserveValue = BeansObservables.observeValue(searchPrep, "imp"); bindingContext.bindValue(comboImpSelectionObserveWidget, filterByImpObserveValue , null, null); As soon as the user clicks on the combo, a selection (first element) is made: I can see the call to a selectionlistener i added on the viewer. My question is: after a selection has been made, how do I let the user change his mind and have an empty selection in the combobox? should I add a "fake" empty instance of Imp to the List returned by the ImpContentProvider? or should I implement an alternative to ArrayContentProvider? and one additional related question is: why calling deselectAll() and clearSelection() on the combo does NOT set a null value to the bound bean?

    Read the article

  • Help file not working

    - by meryl
    Hi, can anyone help me ? I wanto to play an audio file and whenever I press the stop button , the already played part of the file should be saved. Unfortunately , what I get is an audio file (.wav) which actually is unplayable. Thanks //**************************** void play_cut() { try { // First, we get the format of the input file final AudioFileFormat.Type fileType = AudioSystem.getAudioFileFormat(inputAudio).getType(); // Then, we get a clip for playing the audio. c = AudioSystem.getClip(); // We get a stream for playing the input file. AudioInputStream ais = AudioSystem.getAudioInputStream(inputAudio); // We use the clip to open (but not start) the input stream c.open(ais); // We get the format of the audio codec (not the file format we got above) final AudioFormat audioFormat = ais.getFormat(); c.start(); AudioInputStream startStream = new AudioInputStream(new FileInputStream(inputAudio), audioFormat, c.getLongFramePosition()); AudioSystem.write(startStream, fileType, outputAudio); } catch (UnsupportedAudioFileException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } catch (LineUnavailableException e) { e.printStackTrace(); } }// end play_cut //****************************

    Read the article

  • How to merge JOptionPane and Frame into one

    - by mike_hornbeck
    Hello. Currently I have a very basic file viewer working as follows : - in JOptionPane I browse for files, and set some variables to display (colors, line connecting etc) - previous windows loads a frame with drawn points Code : http://paste.pocoo.org/show/220066/ Now I'd like to throw it into one window, with JMenu for selecting files and changing display parameters. How to get started ? Should I rewrite everything to JDialog ?

    Read the article

< Previous Page | 866 867 868 869 870 871 872 873 874 875 876 877  | Next Page >