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  • Categorising a large mysql result with php while?

    - by Ryan
    I'm using the following to grab my large result set from a mysql db: $discresult = 'SELECT t.id, t.subject, t.topicimage, t.topictype, c.user_id, c.disc_id FROM topics AS t LEFT JOIN collections AS c ON t.id=c.disc_id WHERE c.user_id='.$user_id; $userdiscs = $db->query($discresult) or error('Error.', __FILE__, __LINE__, $db->error()); This returns a list of all items that the user owns. I'm then needing to categorise these items based on the value of the "topictype" column, which Im currently doing by using: <h2>Category 1</h2> <?php while ($cur_img = mysql_fetch_array($userdiscs)) { if ($cur_img['topictype']=="cat-1") { if ($cur_img['topicimage']!="") { echo "<div><a href=\"viewtopic.php?id=".$cur_img['id']."\" title=\"".$cur_img['subject']."\"><img src=\"".$cur_img['topicimage']."\" style=\"width:60px; height: 60px\" /></a><br /><a href=\"viewtopic.php?id=".$cur_img['id']."\" title=\"".$cur_img['subject']."\">".$cur_img['subject']."</a></div>"; } else { echo "<div><a href=\"viewtopic.php?id=".$cur_img['id']."\" title=\"".$cur_img['subject']."\"><img src=\"img/no-disc-art.jpg\" style=\"width:60px; height: 60px\" /></a><br /><a href=\"viewtopic.php?id=".$cur_img['id']."\" title=\"".$cur_img['subject']."\">".$cur_img['subject']."</a></div>"; } } } mysql_data_seek($userdiscs, 0); ?> <h2>Category 2</h2> <?php while ($cur_img = mysql_fetch_array($userdiscs)) { if ($cur_img['topictype']=="cat-2") { if ($cur_img['topicimage']!="") { echo "<div><a href=\"viewtopic.php?id=".$cur_img['id']."\" title=\"".$cur_img['subject']."\"><img src=\"".$cur_img['topicimage']."\" style=\"width:60px; height: 60px\" /></a><br /><a href=\"viewtopic.php?id=".$cur_img['id']."\" title=\"".$cur_img['subject']."\">".$cur_img['subject']."</a></div>"; } else { echo "<div><a href=\"viewtopic.php?id=".$cur_img['id']."\" title=\"".$cur_img['subject']."\"><img src=\"img/no-disc-art.jpg\" style=\"width:60px; height: 60px\" /></a><br /><a href=\"viewtopic.php?id=".$cur_img['id']."\" title=\"".$cur_img['subject']."\">".$cur_img['subject']."</a></div>"; } } } mysql_data_seek($userdiscs, 0); ?> This works fine when I rinse and repeat the code, but as the site grows I expect I'll run into problems as the number of "topictype" options increases (expecting around 30 categories). I dont want to have to make seperate queries for each categorised group of discs either, as Id eventually have 30 queries being run as categories increase, so hoping to hear some suggestions or alternative approaches :) Thanks

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  • Can someone explain the true landscape of Rails vs PHP deployment, particularly within the context of Reseller-based web hosting (e.g., Hostgator)?

    - by rcd
    Currently, I have a reseller account with the company HostGator. I design websites, which up until now have occasionally been wrapped in Wordpress CMSs and the like (PHP applications). I then sell hosting (of the site I've designed) to the client, which is pretty simple, in that I can simply click a button and add a new shared hosting account/site with whatever settings I want. Furthermore, I then utilize WHMCS to automate billing and account management. It's a nice package and pretty simple. I pay something like $25 a month, and can sell a hundred accounts under this (because my clients bandwidth requirements are low). Now I am finding the need to develop more customized applications, including a minimalist CMS and several proprietary things. I soon anticipate developing these apps for clients as well. Thus, I've spent the past few months learning Rails, and it's coming along well now. The thing that has nagged at me all along, though, is the deployment issue. I can't wrap my brain around it. It seems like all of the popular options (Heroku, etc) have nice automation with git and are set up in the "Rails Way". I get that (sort of). But it's terribly expensive... a single dyno, a helper, and the cheapest database (which they say is mainly suitable for testing) that isn't limited to 5MB runs $51. This is for ONE app!!! Throw in a "production" DB and you're over $200. This is like... the same prices as getting a server somewhere, right? Meanwhile, going back to what I guess is a "traditional" hosting environment with Hostgator, their server only has Ruby 1.8.7 and Rails 2.3.5... No Rails 3. AND, no Passenger (not that I really understand the difference in CGI or mod_rails or whatever, but they say Passenger is the simplest). So I'm to understand that if I build an app in Rails 3, it won't run at all on this host? But damn, I already have these accounts under my reseller account there, all running static html and/or PHP stuff, right? So what now? How do I get all of this under one simple (and affordable) roof? Forgive my ignorance, but I just don't get it. Managing a VPS is cool and all, but entails learning server admin stuff and security... And it's expensive. I get that a shared and/or reseller "server-based" (forgive the terminology) may be inadequate for large-scale apps that use a lot of bandwidth... But what about for those of us who are building real (but small and low bandwidth) apps (with Rails) and who want to deploy them simply, cheaply, using the same conceptual approach as PHP? Even after learning all of this Ruby and Rails stuff for months, I'm questioning whether it's worth it when it comes to deployment. I want to build a small app, upload it to my home directory on a shared server account, and just make it run. Why should that be so hard? Am I just choosing the wrong language/framework? Forgive my ignorance in the subject; these questions are not rhetorical; just trying to learn here. So: 1) I'd appreciate if someone could give me a good rundown of how to understand deployment in Rails vs. PHP. 2) I'd appreciate if someone could address my issue with running a hosting/web business around reseller hosting (Hostgator) while also being able to host Rails apps. Can it be done? And how can a company like Hostgator completely ignore what's current in Rails/Ruby? Thanks.

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  • I am trying to link my php form and my sql but having difficulties

    - by user1912599
    I am not sure what I am doing wrong as far as my php goes but I can't get my form to link with my sql. Here are the codes for my form and php code for my link to sql <?php echo displayform(); function displayForm() { $r = ''; //build it $r .='<form action="database.php" method="post">'; //table $r .=displayNiceFormBegin(); $r .=displayRow('FirstName:', '<input type="text" name="fname" id="fname"/>'); $r .=displayRow('LastName:', '<input type="text" name="lname" id="lname"/>'); $r .=displayRow('Address:', '<input type="text" name="address" id ="address"/>'); $r .=displayRow('Phone:', '<input type="text" name="phone" id ="phone"/>'); $r .=displayRow('Deparment:', '<input type="text" name="department"id="department"/>'); $r .=displayRow('', '<input type="submit" value="Submit Registration" />'); $r .=displayNiceFormEnd(); $r .='</form>'; return $r; } function displayRow($left, $right) { $r .= ''; //build it $r .='<tr>'; $r .= '<td>' . $left . '</td>'; $r .= '<td>' . $right . '</td>'; $r .='</tr>'; return $r; } function displayNiceFormBegin(){ $r .=''; //build it $r .= '<table style="background-color: beige; border: 1px dashed #999"><tr><td>'; $r .='<table style="margin:10px">'; return $r; } function displayNiceFormENd() { $r .=''; //build it $r .='</table>'; $r .='</td></tr><table>'; return $r; } ?> <?php $host="localhost"; // Host name $username="695788_ogems"; // Mysql username $password="opd69715"; // Mysql password $db_name="ottawaglandorfems_zzl_ogems"; // Database name $tbl_name=".*"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // Get values from form $fname=$_POST['fname']; $lname=$_POST['lname']; $address=$_POST['address']; $phone=$_POST['phone']; $department=$_POST['deparment']; // Insert data into mysql $sql="INSERT INTO $tbl_name(FirstName,LastName,Address,Phone,Department)VALUES('$fname', '$lname', '$address','$phone','$deparment')"; $result=mysql_query($sql); // if successfully insert data into database, displays message "Successful". if($result){ echo "Successful"; echo "<BR>"; echo "<a href='ottawa-glandorfems.org/form3.php'>Back to main page</a>"; } else { echo "ERROR"; } ?> <?php // close connection mysql_close(); ?> I keep getting an error. Thank you!!!!

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  • Validating form dropdown in CodeIgniter

    - by Gaz
    Hi, I am using CodeIgniter's form helper and form validation library to build my forms. I'm having trouble making the dropdown 'sticky' and also finding appropriate validation rules. This is how I'm populating the drodown: foreach($events as $event){ $options[$event->event_title] = $event->event_title; } $firstItem = '<option>Please select one...</option>'; echo form_dropdown('events', $options, '', $firstItem); This is building the options from events stored in the database. The form looks fine and is populating tall the fields correctly. Hwoever, when I come to submit the form, the dropdown isn't holding onto the value selected? Also, how should I validate it, I want to make it required but I also want to make sure that I dont except the first option in the dropdown 'Please select one...' Thanks in advance. Cheers, Gaz

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  • "Trying to get property of non-object" error with SimpleXML and PHP

    - by SooDesuNe
    I'm using a PHP script with SimpleXML to parse an XML feed. I have no control over the content of the XML. try { $xml = @new SimpleXMLElement($fetchResult); } catch (Exception $e) { errorHandle($e->getMessage());} $userNick = $xml->View->ScrollView->VBoxView->View->MatrixView->VBoxView[0]->HBoxView->TextView->SetFontStyle->b; foreach ($xml->View->ScrollView->VBoxView->View->MatrixView->VBoxView[0]->VBoxView as $pathToSubTree){ foreach ($pathToSubTree->MatrixView->View->VBoxView->VBoxView->HBoxView[0]->VBoxView->MatrixView->VBoxView as $canopy){ //Do some stuff now that we've found the canopy of the tree } $canopy = $pathToSubTree->MatrixView->View->VBoxView->VBoxView->HBoxView[0]->VBoxView->MatrixView->VBoxView; if(is_null($canopy)){ //Do some stuff stuff is the canopy was not traceable } } $pathToSubTree = $xml->View->ScrollView->VBoxView->View->MatrixView->VBoxView[0]->VBoxView; if(is_null($pathToSubTree)){ //Do some stuff stuff is the subTree path was not traceable } unset($xml); I'm getting lots of two errors, which I'm sure are related to the same cause: PHP Notice: Trying to get property of non-object in myScript.php on line 45 PHP Warning: Invalid argument supplied for foreach() in myScript.php on line 45 PHP Notice: Trying to get property of non-object in myScript.php on line 76 Line 45 is (from above): foreach ($pathToSubTree->MatrixView->View->VBoxView->VBoxView->HBoxView[0]->VBoxView->MatrixView->VBoxView as $canopy){ Line 76 is (from above): $canopy = $pathToSubTree->MatrixView->View->VBoxView->VBoxView->HBoxView[0]->VBoxView->MatrixView->VBoxView; I'm pretty sure this error is caused by one of the arrays in my path not being an array for the particular XML, but some times it CAN be an array. What's the correct way to deal with these?

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  • jQuery partial page refresh after form submit

    - by heeboir
    When using jQuery to submit a form is it possible to place the resulting page (after the submit) inside another HTML element? I'll try to make this clearer. Up to now I've been using Callback methods that among others do a document.forms['form'].submit(); whenever a form has been updated with new information and needs to be refreshed. However, this results in a full page refresh. I'm implementing Partial Page Refresh using jQuery and thought of using something like var newContent = jQuery('#form').submit(); jQuery('#div').load(newContent); However, that does not seem to work as the page is still fully refreshed. The content is correct, however the behaviour seems to be exactly the same as before - so I'm not really sure if what I want is actually possible with jQuery. Any hints and pointers would be helpful. Thanks.

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  • Zend Form, table decorators

    - by levacjeep
    Hello, I am having an incredibly difficult time to decorate a Zend form the way I need to. This is the HTML structure I am in need of: <table> <thead><tr><th>one</th><th>two</th><th>three</th><th>four</th></thead> <tbody> <tr> <td><input type='checkbox' id='something'/></td> <td><img src='src'/></td> <td><input type='text' id='something'/></td> <td><input type='radio' group='justonegroup'/></td> </tr> <tr> <td><input type='checkbox' id='something'/></td> <td><img src='src'/></td> <td><input type='text' id='something'/></td> <td><input type='radio' group='justonegroup'/></td> </tr> </tbody> </table> The number of rows in the body is determined by my looping structure inside my form class. All ids will be unique of course. All radio buttons in the form belongs to one group. My issue really is that I am unsure how to create and then style the object Zend_Form_Element_MultiCheckbox and Zend_Form_Element_Radio inside my table. Where/how would I apply the appropriate decoraters to the checkboxes and radio buttons to have a form structure like above? My Form class so far: class Form_ManageAlbums extends Zend_Form { public function __construct($album_id) { $photos = Model_DbTable_Photos::getAlbumPhotos($album_id); $selector = new Zend_Form_Element_MultiCheckbox('selector'); $radio = new Zend_Form_Element_Radio('group'); $options = array(); while($photo = $photos->fetchObject()) { $options[$photo->id] = ''; $image = new Zend_Form_Element_Image('image'.$photo->id); $image->setImageValue('/dog/upload/'.$photo->uid.'/photo/'.$photo->src); $caption = new Zend_Form_Element_Text('caption'.$photo->id); $caption->setValue($photo->caption); $this->addElements(array($image, $caption)); } $selector->addMultiOptions($options); $radio->addMultiOptions($options); $this->addElement($selector); $this->setDecorators(array( 'FormElements', array('HtmlTag', array('tag' => 'table')), 'Form' )); } } I have tried a few combination of decoraters for the td and tr, but no success to date. Thank you for any help, very appreciated. JP Levac

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  • the data can't display in the form....

    - by shimaTun
    i wrote code to view data after user fill the form...but the data can't display.... this the code : <?php include "connectioncomplaint.php"; $userid = $_GET['userid']; $secname = $_GET['secname']; $subject = $_GET['subject']; $comment = $_GET['comment']; //Tarik data dari sini $queryDetail = " SELECT * FROM campuscomplaint " . " WHERE userid = '". $userid . "' AND secname = '". secname . "' "; $resultDetail = mysql_query($queryDetail); $detail = mysql_fetch_array($resultDetail); ?> and this code for form: <tr> <td height="400" colspan="7" bgcolor="#FFFFFF"> <table width="67%" align="center" border="1" bordercolor="#ABD519" cellpadding="2" cellspacing="2"> <tr bordercolor="#0000FF" bgcolor="#000033"> <td colspan="2" align="center" valign="top" bgcolor="#ABD519"> --- Complaint Detail --- &nbsp;</td> </tr> <tr bordercolor="#FFFFFF"> <td width="40%" class="register">User ID:</td> <td width="62%" class="register"><?php echo $detail['userid']; ?></td></tr> <tr bordercolor="#FFFFFF"> <td width="40%" class="register">Section Name:</td> <td width="62%" class="register"><?php echo $detail['secname']; ?></td></tr> <tr> <td width="40%" bordercolor="#FFFFFF" bgcolor="#FFFFFF" class="register">Subject:</td> <td width="62%" bordercolor="#FFFFFF" bgcolor="#FFFFFF" class="register"><?php echo $detail['subject']; ?></td></tr> <tr> <td width="40%" bordercolor="#FFFFFF" bgcolor="#FFFFFF" class="register">Comment:</td> <td width="62%" bordercolor="#FFFFFF" bgcolor="#FFFFFF" class="register"><?php echo $detail['comment']; ?></td></tr> <tr bordercolor="#0000FF" bgcolor="#ABD519"> <td colspan="2" align="center" valign="top">&nbsp;</td> </tr> </table> how to view data from dbase?.... help me...

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  • php symfony and apache2 - inst't serving .phtml

    - by pmoniq
    Hi, I have a problem with apache2 settings (Ubuntu system). I would like to run symfony project on my localhost but instead of serving .phtml files, browser is trying to download files. this is my file .host: 127.0.0.3 test this is apache2/sites-available/default file < VirtualHost 127.0.0.3:80 ServerName test DocumentRoot "/home/m/Pr/workspace/php/test/web" DirectoryIndex frontend_dev.php < Directory "/home/m/Pr/workspace/php/test/web" AllowOverride All Allow from All Alias /sf /home/m/Pr/workspace/php/test/lib/vendor/symfony/data/web/sf < Directory "/home/m/Pr/workspace/php/test/lib/vendor/symfony/data/web/sf" AllowOverride All Allow from All </Directory> and this is .htaccess in /test RewriteEngine On RewriteRule ^(.*)$ /web/$1 Options +FollowSymLinks +ExecCGI AddHandler application/x-httpd-php5 .php .phtml and this is .htaccess in /test/web Options +FollowSymLinks +ExecCGI RewriteEngine On # uncomment the following line, if you are having trouble # getting no_script_name to work RewriteBase / # we skip all files with .something #RewriteCond %{REQUEST_URI} ..+$ #RewriteCond %{REQUEST_URI} !.html$ #RewriteRule .* - [L] # we check if the .html version is here (caching) RewriteRule ^$ index.html [QSA] RewriteRule ^([^.]+)$ $1.html [QSA] RewriteCond %{REQUEST_FILENAME} !-f # no, so we redirect to our front web controller RewriteRule ^(.*)$ index.php [QSA,L] Another problem is I think apache don't read .htaccess files. What am i doing wrong? Maybe I forgot about something? Please, help me becouse i have no idea.

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  • Open Fancybox (or equiv) from Form input type="submit"

    - by nickmorss
    is there a way to get a fancybox (http://fancy.klade.lv/) or any other lightbox from submitting a FORM (with an image button)? HTML looks like this: <form action="/ACTION/FastFindObj" method="post"> <input name="fastfind" class="fastfind" value="3463" type="text"> <input name="weiter" type="submit"> </form> These won't do: $("form").fancybox(); $("input").fancybox(); $("input[name='weiter']").fancybox(); Anyone spotting my mistake or having a workaround or an alternative script? Thanks in advance

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  • Success function not being called when form is submitted. jQuery / validationEngine / PHP form proce

    - by Tom Hartman
    Hi, I've been trying to figure out why the following script's success function isn't running. Everything in my form works perfectly, and the form contents are being emailed correctly, but the success function isn't being called. If anyone could review my code and let me know why my success function isn't being called I would very much appreciate it! Here is the HTML form with notification divs, which are hidden via css: <div id="success" class="notification"> <p>Thank you! Your message has been sent.</p> </div> <div id="failure" class="notification"> <p>Sorry, your message could not be sent.</p> </div> <form id="contact-form" method="post" action="" class="jqtransform"> <label for="name">Name:</label> <input name="name" id="name" type="text" class="validate[required] input" /> <label for="company">Company:</label> <input name="company" id="company" type="text" class="input" /> <label for="phone">Phone:</label> <input name="phone" id="phone" type="text" class="input" /> <label for="email">Email:</label> <input name="email" id="email" type="text" class="validate[required,email] input" /> <div class="sep"></div> <label for="subject">Subject:</label> <input name="subject" id="subject" type="text" class="validate[required] input" /> <div class="clear"></div> <label for="message">Message:</label> <textarea name="message" id="message" class="validate[required]"></textarea> <div id="check-services"> <input type="checkbox" name="services[]" value="Contractor Recommendation" /> <div>Contractor Recommendation</div> <input type="checkbox" name="services[]" value="Proposal Review" /> <div>Proposal Review</div> <input type="checkbox" name="services[]" value="Existing Website Review" /> <div>Existing Website Review</div> <input type="checkbox" name="services[]" value="Work Evaluation" /> <div>Work Evaluation</div> <input type="checkbox" name="services[]" value="Layman Translation" /> <div>Layman Translation</div> <input type="checkbox" name="services[]" value="Project Management" /> <div>Project Management</div> </div> <div class="sep"></div> <input name="submit" id="submit" type="submit" class="button" value="Send" /> <input name="reset" id="reset" type="reset" class="button" value="Clear" onclick="$.validationEngine.closePrompt('.formError',true)" /> </form> Here is the javascript: // CONTACT FORM VALIDATION AND SUBMISSION $(document).ready(function(){ $('#contact-form').validationEngine({ ajaxSubmit: true, ajaxSubmitFile: 'lib/mail.php', scroll: false, success: function(){ $('#success').slideDown(); }, failure: function(){ $('#failure').slideDown(); $('.formError').animate({ marginTop: '+30px' }); } }); }); And here is my PHP mailer script: <?php $name = $_POST['name']; $company = $_POST['company']; $phone = $_POST['phone']; $email = $_POST['email']; $subject = $_POST['subject']; $message = $_POST['message']; $services = $_POST['services']; $to = '[email protected]'; $subject = 'THC - Contact'; $content .= "You received a message from ".$name.".\r\n\n"; if ($company): $content .= "They work for ".$company.".\r\n\n"; endif; $content .= "Here's the message:\r\n\n".$message."\r\n\n"; $content .= "And they are interested in the services below:\r\n\n"; $content .= implode("\r\n",$services); if ($phone): $content .= "\r\n\nYou can reach them at ".$phone."."; else: $content .= "\r\n\nNo phone number was provided."; endif; $headers = "From: ".$name."\r\n"; $headers .= "Reply-To: ".$email."\r\n"; if (mail($to,$subject,$content,$headers)): return true; else: return false; endif; ?>

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  • $.Post with Form submit

    - by Michael
    ...Some form gets submitted... $.("form").submit(function() { saveFormValues($(this), "./../.."; } function saveFormValues(form, path) { var inputs = getFormData(form); var params = createAction("saveFormData", inputs); var url = path + "/scripts/sessions.php"; $.post(url, params); } The weird thing is that if i add a function to the $.post(url, params, function(data) { alert(data); } I get a blank alert statement. Within scripts/sessions.php i have a function to save whatever the $_POST information is to a file, and the sessions.php never saves this saveFormValues call. It never shows up to the file. But if i keep trying to get it to save, about once every 15 will actually allow it to be saved. This leads me to believe that the forms POST is somehow blocking this value saving post. Any help?

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  • Wordpress form handling

    - by Ron
    I need to add a basic form page in the website, that runs on WordPress framework. I have the following raw materials ready: Client side: html form layout,css and jquery validation code. Server side: form handler php function that processes the $_POST[] data. My problem is to integrate this code in the Wordpress framework. I have looked at some plugins but they are doing much more than I would like and also they have their own validation which is cumbersome to change. Could anyone suggest a good form plugin that allows just the framework hooks ? Or is it worthwhile that I should write the plugin myself. Thanks.

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  • Django Upload form to S3 img and form validation

    - by citadelgrad
    I'm fairly new to both Django and Python. This is my first time using forms and upload files with django. I can get the uploads and saves to the database to work fine but it fails to valid email or check if the users selected a file to upload. I've spent a lot of time reading documentation trying to figure this out. Thanks! views.py def submit_photo(request): if request.method == 'POST': def store_in_s3(filename, content): conn = S3Connection(AWS_ACCESS_KEY_ID, AWS_SECRET_ACCESS_KEY) bucket = conn.create_bucket(AWS_STORAGE_BUCKET_NAME) mime = mimetypes.guess_type(filename)[0] k = Key(bucket) k.key = filename k.set_metadata("Content-Type", mime) k.set_contents_from_file(content) k.set_acl('public-read') if imghdr.what(request.FILES['image_url']): qw = request.FILES['image_url'] filename = qw.name image = filename content = qw.file url = "http://bpd-public.s3.amazonaws.com/" + image data = {image_url : url, user_email : request.POST['user_email'], user_twittername : request.POST['user_twittername'], user_website : request.POST['user_website'], user_desc : request.POST['user_desc']} s = BeerPhotos(data) if s.is_valid(): #import pdb; pdb.set_trace() s.save() store_in_s3(filename, content) return HttpResponseRedirect(reverse('photos.views.thanks')) return s.errors else: return errors else: form = BeerPhotoForm() return render_to_response('photos/submit_photos.html', locals(),context_instance=RequestContext(request) forms.py class BeerPhotoForm(forms.Form): image_url = forms.ImageField(widget=forms.FileInput, required=True,label='Beer',help_text='Select a image of no more than 2MB.') user_email = forms.EmailField(required=True,help_text='Please type a valid e-mail address.') user_twittername = forms.CharField() user_website = forms.URLField(max_length=128,) user_desc = forms.CharField(required=True,widget=forms.Textarea,label='Description',) template.html <div id="stylized" class="myform"> <form action="." method="post" enctype="multipart/form-data" width="450px"> <h1>Photo Submission</h1> {% for field in form %} {{ field.errors }} {{ field.label_tag }} {{ field }} {% endfor %} <label><span>Click here</span></label> <input type="submit" class="greenbutton" value="Submit your Photo" /> </form> </div>

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  • Access custom error messages for InArray validator when using Zend_Form_Element_Select

    - by Ben Waine
    Hello, I'm using Zend Framework 1.62 (becuase we are deploying the finished product to a Red Hat instance, which doesn't have a hgih enough PHP version to support ZF1.62). When creating a Form using Zend Form, I add a select element, add some multi options. I use the Zend Form as an in-object validation layer, passing an objects values through it and using the isValid method to determine if all the values fall within normal parameters. Zend_Form_Element_Select works exactly as expected, showing invalid if any other value is input other than one of the multi select options I added. The problem comes when I want to display the form at some point, I cant edit the error message created by the pre registered 'InArray' validator added automatically by ZF. I know I can disable this behaviour, but it works great apart from the error messages. I've tryed the following: $this->getElement('country')->getValidator('InArray')->setMessage('The country is not in the approved lists of countries'); // Doesn't work at all. $this->getElement('country')->setErrorMessage('The country is not in the approved lists of countries'); // Causes a conflict elswhere in the application and doesnt allow granular control of error messages. Anyone have any ideas? Ben

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  • why the data can't dispaly in the form???(error-mysql_fetch_array():)

    - by shimaTun
    I've created a code to view the data. Now it seem contain an error. When I run this page this error display: Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in C:\Program Files\xampp\htdocs\e-Complaint(FYP)\userView.php on line 93 the code : <?php //======================================================================================================================= PROCESS DATA ======================================================= START. include "connectioncomplaint.php"; ?> <?php $subject = $_GET['type']; $comment = $_GET['id']; //echo 'test : ' . $name; //Tarik data dari sini $queryDetail = " SELECT * FROM campuscomplaint " . " WHERE subject = '" . $subject . "' AND comment = '" . $comment . "' "; //echo 'QUERY DETAIL :' . $queryDetail . '<br>' ; $resulDetail = mysql_query($queryDetail); //echo 'RESULT DETAIL :' . $resultDetail + 0 . '<br>' ; $detail = mysql_fetch_array($resultDetail); //echo $detail . '<br>'; //echo 'detail subject is : ' . $detail['subject'] . '<br>'; //echo 'detail comment is : ' . $detail['comment'] . '<br>'; //echo $detail[$x] . '<br>'; ?> code for form: <tr> <td bordercolor="#FFFFFF" bgcolor="#FFFFFF" class="register style5">From:</td> <td bordercolor="#FFFFFF" bgcolor="#FFFFFF" class="register style5"><input type="text" name="to" size="40" maxlength="80" value="<?php echo $detail['userid']; ?>"/></td> </tr> <tr> <td width="38%" bordercolor="#FFFFFF" bgcolor="#FFFFFF" class="register style5">Subject:</td> <td width="62%" bordercolor="#FFFFFF" bgcolor="#FFFFFF" class="register style5"><input type="text" name="subject" size="40" maxlength="80" value="<?php echo $detail['subject']; ?>"/></td> </tr> <tr> <td bordercolor="#FFFFFF" bgcolor="#FFFFFF" class="register style5">Comment:</td> <td bordercolor="#FFFFFF" bgcolor="#FFFFFF" class="register style5"><textarea name="comment" rows="5" cols="40"><?php echo $detail['message']; ?></textarea></td> </tr> <tr> <td bordercolor="#FFFFFF" bgcolor="#FFFFFF" class="register style5"><p>&nbsp;</p> <p>&nbsp;</p></td> <td bordercolor="#FFFFFF" bgcolor="#FFFFFF" class="register style5"><input type="submit" name="submit" value="Submit Comment" onClick="return OnButton1();"/></td> </tr>

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  • Semi-transparent PNG Image on transparent Form

    - by Marco Bruggmann
    Hello, I have a problem dealing with transparent images on transparent Forms. I have been trying and looking for a solution but nothing useful came up. The problem is: I have a Form, this Form has a Panel and the Panel has a PictureBox. Form and Panel are transparent. Now, if the image of the PictureBox has no semi-transparent it works. But if there is a gradient transparency then the "transparent color" is shown. I need the Panel and the PictureBox, so the PerPixelAlpha does not apply for this case. The Form will also have more Controls that should be visible and non transparent (just the PNG image should be transparent). The image below shows: [Left] When the Panel is not transparent. [Center] When the Panel is transparent. [Right] Desired effect (done with PerPixelAlpha). http://www.freeimagehosting.net/uploads/3937fe974d.jpg THX Marco

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  • javascript form validation in rails?

    - by Elliot
    Hey guys, I was wondering how to go about form validation in rails. Specifically, here is what I'm trying to do: The form lets the user select an item from a drop down menu, and then enter a number along with it. Using RJS, the record instantly shows up in a table below the form. Resetting the form with AJAX isn't a problem. The issue is, I don't want the person to be able to select the same item from that drop down menu twice (in 1 day at least). Without using ajax, this isn't a problem (as I have a function for the select statement currently), but now that the page isn't reloading, I need a way to make sure people cant add the same item twice in one day. That said, is there a way to use some javascript/ajax validation to make sure the same record hasn't been submitted during that day, before a duplicate can be created? Thanks in advance! Elliot

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  • login form using ajax, to submit without refreshing

    - by Brad
    I am using this tutorial to create a login form http://www.ryancoughlin.com/2008/11/04/use-jquery-to-submit-form/ It authenticates against w/ our ldap server. What I am having a problem with is the line success: function(){ $('form#submit').hide(function(){$('div.success').fadeIn();}); It runs success even though we don't even know if the username and password binded successfully. Is there a way to only run success if the username and password posted was binded successfully?

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  • Parsing Line Breaks in PHP/JavaScript

    - by Matt G
    I have a text area in my PHP application where users can enter notes in a project. Sometimes this is displayed on the page via PHP and sometimes it is displayed via javascript. The problem is, if the note is across multiple lines (i.e. the user presses enter while entering notes in the text area), it causes the JS to fail. It's fine when it's being done by the PHP. The line of code in question is: var editnotes='<textarea class="desc_text" style="width:20em;" id="notes_editor"><?php print $notes; ?></textarea>'; So, if the note is over multiple lines, the PHP builds the pager as: var editnotes='<textarea class="desc_text" style="width:20em;" id="notes_editor">This is a test note over multiple lines </textarea>'; And this obviously causes problems for the js. So my question is, what can I do to prevent this? As the code is being built by PHP before it even gets to the browser, I'm thinking that the best approach may be to parse it in the PHP so that the output is something more like this: var editnotes='<textarea class="desc_text" style="width:20em;" id="notes_editor">This is<br/>a test note<br/>over multiple lines<br/></textarea>'; Will this work? How would I do it? Thanks

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  • PHP Form POST to external URL with Redirect to another URL

    - by Marlon
    So, what I am trying to accomplish is have a self-posting PHP form, POST to an external page (using CURL) which in turn redirects to another page. Currently, what is happening is that once I click "Submit" on the form (in contact.php) it will POST to itself (as it is a self-posting form). The script then prepares the POST using CURL and performs the post. The external page does its processing and then, the external page is supposed to redirect back to another page, in a referring domain. However, what happens instead, is that it seems like the contact.php page loads the HTML from the page the external page redirected to, and then, the contact.php's HTML loads after that, ON THE SAME PAGE. The effect, is what looks like two separate pages rendered as one page. Naturally, I just want to perform the POST and have the browser render the page it is supposed to redirect to as specified by the external page. Here is the code I have so far: <?php if(isset($_POST['submit'])) { doCURLPost(); } function doCURLPost() { $emailid = "2, 4"; $hotel = $_POST['hotel']; //you will need to setup an array of fields to post with //then create the post string $data = array ( "recipient" => $emailid, "subject" => "Hotel Contact Form", "redirect" => "http://www.localhost.com/thanx.htm", "Will be staying in hotel: " => $_POST['hotel'], "Name" => $_POST['Name'], "Phone" => $_POST['Phone'], "Comments" => $_POST['Comments']); $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, "http://www.externallink.com/external.aspx"); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true); curl_setopt($ch, CURLOPT_POST, true); curl_setopt($ch, CURLOPT_POSTFIELDS, $data); curl_setopt($ch, CURLOPT_HTTPHEADER, array("Referer: http://www.localhost.com/contact.php")); $output = curl_exec($ch); $info = curl_getinfo($ch); curl_close($ch); } ?>

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  • PHP form values after POST in dropdown

    - by FFish
    I have a form with 'selected' values pulled from the database. Now I want the user to edit the values. When the data is send I want to show the new values. When I submit my form I always get the 'green' value? What am I doing wrong here? <?php // pulled from db $color = "blue"; // update if (isset($_POST['Submit'])) { echo "write to db: " . $_POST['name'] . " + " . $_POST['color']; } ?> <html> <form name="form1" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <label for="name">Name:</label> <input type="text" name="name" size="30" value="<?php echo (isset($_POST['name'])) ? $_POST['name'] : ""; ?>"> <br /> <label for="color">Color:</label> <select name="color"> <option <?php echo (isset($_POST['color']) || $color == "red") ? 'selected="selected"' : ''; ?> value="red">red</option> <option <?php echo (isset($_POST['color']) || $color == "blue") ? 'selected="selected"' : ''; ?> value="blue">blue</option> <option <?php echo (isset($_POST['color']) || $color == "green") ? 'selected="selected"' : ''; ?> value="green">green</option> </select> <br /> <input type="submit" name="Submit" value="Update"> </form> </html>

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  • Two different actions on form submit

    - by Pankaj Khurana
    Hi, I have a form with a submit button. I have called a function on click of submit button. function actionPage(form1) { form1.action="action1.php"; form1.submit(); return(true); } Now i want that the form data should be submitted to two different pages. These pages are on different servers. I know that we can send the data to a particular page according to the conditions but i am not sure whether we can submit to two different pages at the same time i.e: function actionPage(form1) { form1.action="action1.php"; form1.submit(); return(true); form1.action="action2.php"; form1.submit(); return(true); } Right now it is showing action1.php Please guide me on this . Regards, Pankaj

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  • PHP header redirection does nor reload <iframe> in IE

    - by Marco Demaio
    When displaying data from DB usually I'm in this situation I'm in page A.php that shows data from DB, user performs some action (like edit/delete etc) and page B.php is loaded to perform the action, once page B performed the action, it redirects browser to page A, page A is auto reloaded during step (3) therefor it shows an updated situation of the data In order to make page B to redirect to page A i use a simple PHP header("Location: " . "A.php", TRUE, 302); This works well in all situations, except when pages A.php is displaied into an <iframe>: in such a case it does not reload (step 4 does not get done). This seems to happen only in IE7 (don't know about IE8), it works perfectly on FF/Safari. And only when using an <iframe>, if page A.php is not in <iframe> it gest refreshed also in IE7. In order to solve this I simply added a couple of headers in page A.php to set it to not be cached: header("Cache-Control: no-cache, must-revalidate"); // HTTP/1.1 header("Expires: Sat, 26 Jul 1997 05:00:00 GMT"); // Date in the past But I was curious if you migt have exeperienced the same issue too in the past, and if you good give me some advises about this. Thanks!

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  • PHP Magento SOAP-ERROR: Parsing WSDL: Couldn't load from urlpath

    - by dan.codes
    I am trying to create a soap client by passing a url that is hosted on my local machine, my dev environment and I keep getting this error. I use to be able to make this call and it worked just fine. Basically all I am doing is this $client = new SoapClient('http://virtual.website.com:81/api/?wsdl'); If I go to the url in a browser it comes up, so I know it is the right location. On the Magento forums there are some similar posts but I don't know that this is a Magento specific problem. Everything they mention as a solution I already have. They say to edit the hosts file for example 127.0.0.1 website.com I already have this since it is setup as a virtual host. Here is the error in my error_log [Fri Jun 04 12:30:37 2010] [error] [client 127.0.0.1] PHP Fatal error: SOAP-ERROR: Parsing WSDL: Couldn't load from 'http://virtual.website.com:81/api/soap/?wsdl' : XML declaration allowed only at the start of the document\n in /usr/local/sites/virtual.website.com/www/CUSTOMSCRIPTS/removeProductImages.php on line 6 [Fri Jun 04 12:30:37 2010] [error] [client 127.0.0.1] PHP Stack trace: [Fri Jun 04 12:30:37 2010] [error] [client 127.0.0.1] PHP 1. {main}() /usr/local/sites/virtual.website.com/www/CUSTOMSCRIPTS/removeProductImages.php:0 [Fri Jun 04 12:30:37 2010] [error] [client 127.0.0.1] PHP 2. SoapClient->SoapClient(*uninitialized*) /usr/local/sites/virtual.website.com/www/CUSTOMSCRIPTS/removeProductImages.php:6

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