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  • IE jQuery ajax results in a stack overflow

    - by dave
    I have the following code that in IE gives me an error in jQuery for "open(G,M.url,M.async" $("#submitButton").click(function(){ $.ajax({ type: "POST", url: "http://url.com/postChat.php", data: "comment="+$("#userInput").val(), success: function(msg){ } }); }); Any ideas as to why this would happen in IE?

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  • jquery ajax callback out of the function scope

    - by vasion
    function checkauth(){ jQuery.getJSON("/users/checkauthjson", null, function(xhr){ if(xhr.success){ return true;}else{ return false;} }); } Obviously, that does not work, but it illustrates what i want to achieve. I want checkauth to return a value which is checked against an ajax server script. How do i do this?

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  • how to get post content with groovy listening on a port?

    - by Amir Raminfar
    I wrote the following simple groovy code that handles a request. if (init) data = "" if (line.size() > 0) { data += "--> " + line + "\n" } else { println "HTTP/1.1 200 OK\n" println data println "----\n" return "success" } I then run it by doing groovy -l 8888 ServerTest.groovy However, it doesn't seem to print any POST data. I am testing it by doing curl -d "d=test" http://localhost:8888/ Does anybody know how to get that data in groovy?

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  • jquery load a specific #Div content from multiple html files

    - by Vikram
    Hello friends I am trying to make a Content Slider for my site. I have multiple HTML files and the structure of these files is like this: <div id="title"><h2>Title of the Slide</h2></div> <div id="image"><a href="http://mylink.com"><img src="image.jpg" width="600" height="300" alt="image"</a></div> <div id="content">Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy text ever since the 1500s.</div> I have been trying to use the following script get content (but no success): <?php function render($position="") { ob_start(); foreach(glob("/slides/*.html") as $fileName) { $fname = basename( $fileName ); $curArr = file($fname); $slides[$fname ]['title'] = $curArr[0]; $slides[$fname ]['image'] = $curArr[1]; $slides[$fname ]['content'] = $curArr[2]; foreach($slides as $key => $value){ ?> <div id="slide-title"> <?php echo $value['title'] ?> </div> <div id="slide-content"> <?php echo $value['image'] ?> </div> <div id="slide-image"> <?php echo $value['content'] ?> </div> <?php }} ?> <?php return ob_get_clean(); } But then I came to know about a jQuery function.... (again no success) jQuery.noConflict(); (function($){ $(document).ready(function () { $('#slide-title').load('slides/slide1.html #title'); $('#slide-content').load('slides/slide1.html #content'); $('#slide-image').load('slides/slide1.html #image'); }); })(jQuery); Now My questions are..... Am I using the right syntax. How do I get the content from multiple files using jQuery. Please Note : My knowledge on Programming is almost '0'. I have just started learning it.

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  • Rails on IronRuby (IIS 6)

    - by Fossmo
    I'm trying to get Rails running on a IIS 6 webserver using IronRuby, but without success. I have followed this webcast and got it running on IIS 7, but can't make it work on a IIS 6 server. I need some help to get this to work. Any ideas?

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  • Parsing json in ios

    - by gaps
    i have the follwing json string ,can anybody tell me how to get the value of role_name {"response":"success","user":{"created_at":"2011-11-16T05:48:31Z","ud_id":"1234567890","last_sign_in_ip":"182.72.141.194","updated_at":"2011-11-19T08:58:27Z","account_id":21,"last_name":"dfg","role_name":"Parent","email":"[email protected]","first_name":"abc"},"status":"200"} code for parsing is NSString *responseString = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding]; NSLog(@"resp--- %@",responseString); NSArray* latestLoans = [(NSDictionary*)[responseString JSONValue] objectForKey:@"user"]; NSDictionary* loan = [latestLoans objectAtIndex:0]; NSString* name = [loan objectForKey:@"last_name"];

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  • Submiting a Form without Refreshing the page with jQuery and Ajax Not updating MySQL database.

    - by HEEEEEEELP
    I'm a newbie to JQuery and have a problem, when I click submit button on the form everything says registration was successful but my MYSQL database was not updated everything worked fine until I tried to add the JQuery to the picture. Can someone help me fix this problem so my database is updated? Thanks Here is the JQuery code. $(function() { $(".save-button").click(function() { var address = $("#address").val(); var address_two = $("#address_two").val(); var city_town = $("#city_town").val(); var state_province = $("#state_province").val(); var zipcode = $("#zipcode").val(); var country = $("#country").val(); var email = $("#email").val(); var dataString = 'address='+ address + '&address_two=' + address_two + '&city_town=' + city_town + '&state_province=' + state_province + '&zipcode=' + zipcode + '&country=' + country + '$email=' + email; if(address=='' || address_two=='' || city_town=='' || state_province=='' || zipcode=='' || country=='' || email=='') { $('.success').fadeOut(200).hide(); $('.error').fadeOut(200).show(); } else { $.ajax({ type: "POST", url: "http://localhost/New%20Project/home/index.php", data: dataString, success: function(){ $('.success').fadeIn(200).show(); $('.error').fadeOut(200).hide(); } }); } return false; }); }); Here is the PHP code. if (isset($_POST['contact_info_submitted'])) { // Handle the form. // Query member data from the database and ready it for display $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.*, contact_info.* FROM users INNER JOIN contact_info ON contact_info.user_id = users.user_id WHERE users.user_id=3"); $user_id = mysqli_real_escape_string($mysqli, htmlentities('3')); $address = mysqli_real_escape_string($mysqli, htmlentities($_POST['address'])); $address_two = mysqli_real_escape_string($mysqli, htmlentities($_POST['address_two'])); $city_town = mysqli_real_escape_string($mysqli, htmlentities($_POST['city_town'])); $state_province = mysqli_real_escape_string($mysqli, htmlentities($_POST['state_province'])); $zipcode = mysqli_real_escape_string($mysqli, htmlentities($_POST['zipcode'])); $country = mysqli_real_escape_string($mysqli, htmlentities($_POST['country'])); $email = mysqli_real_escape_string($mysqli, strip_tags($_POST['email'])); //If the table is not found add it to the database if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO contact_info (user_id, address, address_two, city_town, state_province, zipcode, country, email) VALUES ('$user_id', '$address', '$address_two', '$city_town', '$state_province', '$zipcode', '$country', '$email')"); } //If the table is in the database update each field when needed if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE contact_info SET address = '$address', address_two = '$address_two', city_town = '$city_town', state_province = '$state_province', zipcode = '$zipcode', country = '$country', email = '$email' WHERE user_id = '$user_id'"); } if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); return; } } Here is the XHTML code. <form method="post" action="index.php"> <fieldset> <ul> <li><label for="address">Address 1: </label><input type="text" name="address" id="address" size="25" class="input-size" value="<?php if (isset($_POST['address'])) { echo $_POST['address']; } else if(!empty($address)) { echo $address; } ?>" /></li> <li><label for="address_two">Address 2: </label><input type="text" name="address_two" id="address_two" size="25" class="input-size" value="<?php if (isset($_POST['address_two'])) { echo $_POST['address_two']; } else if(!empty($address_two)) { echo $address_two; } ?>" /></li> <li><label for="city_town">City/Town: </label><input type="text" name="city_town" id="city_town" size="25" class="input-size" value="<?php if (isset($_POST['city_town'])) { echo $_POST['city_town']; } else if(!empty($city_town)) { echo $city_town; } ?>" /></li> <li><label for="state_province">State/Province: </label> <?php echo '<select name="state_province" id="state_province">' . "\n"; foreach($state_options as $option) { if ($option == $state_province) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="zipcode">Zip/Post Code: </label><input type="text" name="zipcode" id="zipcode" size="5" class="input-size" value="<?php if (isset($_POST['zipcode'])) { echo $_POST['zipcode']; } else if(!empty($zipcode)) { echo $zipcode; } ?>" /></li> <li><label for="country">Country: </label> <?php echo '<select name="country" id="country">' . "\n"; foreach($countries as $option) { if ($option == $country) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else if($option == "-------------") { echo '<option value="' . $option . '" disabled="disabled">' . $option . '</option>'; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="email">Email Address: </label><input type="text" name="email" id="email" size="25" class="input-size" value="<?php if (isset($_POST['email'])) { echo $_POST['email']; } else if(!empty($email)) { echo $email; } ?>" /><br /><span>We don't spam or share your email with third parties. We respect your privacy.</span></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="contact_info_submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form>

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  • Send and receive data in same ajax request with jquery

    - by Pedro Esperança
    What is the best way to send data and receive a response dependent on that data? Consider the php file used for the request: $test = $_POST['test']; echo json_encode($test); I have tried unsucessfully to achieve this with: $.ajax({ type: "POST", dataType: "json", data: '{test : worked}', url: 'ajax/getDude.php', success: function(response) { alert(response); } });

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  • parsing JSON in java ?

    - by bukuai
    How to parsing JSON in java? { "code": 100, "message": "SUCCESS", "result": { "list": [ { "cardNumber": "ALUFZZ5SZ1Q5", "expireTime": 1270742400, "surplusThreshold": 4, "uid": 771292, "useTime": 1270214375, "wareId": 1145 }, { "cardNumber": "ALUFZZ5SZ1QD", "expireTime": 1270828800, "surplusThreshold": 7, "uid": 784289, "useTime": 1270302200, "wareId": 1145 }, { "cardNumber": "ALUFZZ5SZ1RC", "expireTime": 1270828800, "surplusThreshold": 10, "uid": 773664, "useTime": 1270300871, "wareId": 1145 }, { "cardNumber": "ALUFZZ5SZ1UM", "expireTime": 1270828800, "surplusThreshold": 10, "uid": 779560, "useTime": 1270282841, "wareId": 1145 }, { "cardNumber": "ALUFZZ5SZ1VT", "expireTime": 1270656000, "surplusThreshold": 2, "uid": 754099, "useTime": 1270106775, "wareId": 1145 } ], "pageCount": 61, "pageIndex": 2, "pageSize": 5, "recordCount": 308 } }

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  • PHPFOG and MySql

    - by jim dif
    I am playing around with PHPFog and as a result I ended up with a MySql database. I am trying to figure out how to connect to it with a success message. PHPFog says use this: mysql_connect( $server = getenv('MYSQL_DB_HOST'), $username = getenv('MYSQL_USERNAME'), $password = getenv('MYSQL_PASSWORD')); mysql_select_db(getenv('MYSQL_DB_NAME')); So I basically plug my variables into the above? Or Do I do something different? Thanks, Jim

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  • How do I change the curosr during a jQuery synchronous browser blocking POST?

    - by Tommy
    $.ajax({ url: "/cgi-bin/stats.exe", method: "post", async: false, data: { refresh: "a41" } }); Using ajax post synchronously - "async: false". While it blocks the browser during the active request, what is the most efficient way to change the cursor to the hourglass or display a wait .gif? Perhaps set the cursor as it enters this function then change it back in the success or complete function? Any advice is appreciated. Thank You.

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  • AutoMapper: setup member name matching convention

    - by epitka
    I tried setting up a member name mapping convention so that the source members ending with a "Id" are mapped to destination members without Id. For example UserId - User How does one do this? I tried using SourceMemberNameTransformer without success. Also tried using RecognizePostfixes(). this.SourceMemberNameTransformer = s => { return s.Replace("Id", string.Empty); };

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  • Suppress "Done, but with errors on page" in IE

    - by calebthorne
    I have a website using lots of jQuery and JavaScript that produces a "Done, but with errors on page" message in the footer of IE. Everything on the site works perfectly, so I don't want to spend the time troubleshooting the exact error. All I would like to do is suppress the "Done, but with errors on page" message so that clients don't freak out. I tried the following at the top of the page with no success: window.onerror = function() {return true;}

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  • Jquery ajax POST label/value pair

    - by aus_fas
    I want to pass label/value pair in Ajax .POST but cannot find any solution. Any help please. $.ajax({ url:"allfields.php", type:"POST", // dataType:"json", data: $("#frmRequest").serialize(), success: function(msg){ alert("Form Submitted: "+ msg); return msg; }, error: function() { alert('Error occured'); } });

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  • Changing the UIBackButtonItem title

    - by Alpinista
    I have a navigationController-based app. I want to change the title of the back button for the root view controller. I have tried the following code in the rootViewController's viewDidLoad method, but no success: self.navigationItem.backBarButtonItem.title = @"Back"; Any ideas?

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  • iframe change event

    - by acidzombie24
    i have an iframe with a form that the user fills and submits. When the form is finished submitting i would like some js code using jquery to tell the main page (which holds this iframe) that the user has submitted the form. What event can i use to check this? i tried .change(function () without success

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  • How to convert string to XML object in JavaScript?

    - by Jack Roscoe
    Hi, I am aware of this question already existing, but it has given me no luck. I have an application which loads a physicial XML document via the following method: jQuery.ajax( { type: "GET", url: fileName, dataType: "xml", success: function(data) { etc... I parse the XML and convert it into a string which is saved into a variable so that it can easily be stored in a database. How can I now convert the data in this variable back into an XML object so that it can be parsed as such?

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  • Ajax call not working...

    - by Probocop
    Hi, I have a form that submits to a PHP script with Jquery and Ajax. The PHP script returns some XML. For some reason the Ajax success function is not firing, and the error ones is. Can anybody see where I'm going wrong? My Jquery is as follows $('#submit-excuse').submit(function (event) { event.preventDefault(); ws_url = 'http://jacamo.epiphanydev2.co.uk/content/inc/excuse-submit.php?excuse='+$('input#excuse').val(); $.ajax({ type: 'GET', url: ws_url, dataType: "xml", beforeSend: function() { $('p#response').text('Sending.'); }, success: function(xmlIn) { results = xmlIn.getElementsByTagName("ReportID"); }, error: function() { $('p#response').text('Error.'); } }); }); And my PHP script is as follows: $excuse = $_GET['excuse']; $badwords = array ( 'one', 'two', 'three', 'four', 'five' ); if ($excuse == '') { $error = 'enter something'; } else { foreach ($badwords as $word) { $pos = strpos($excuse, $word); if($pos !== false) { $passed = false; } } if ($passed !== false) { $username = 'xxxxx'; $password = 'xxxxx'; $message = $excuse; $url = 'http://twitter.com/statuses/update.xml'; $curl_handle = curl_init(); curl_setopt($curl_handle, CURLOPT_URL, "$url"); curl_setopt($curl_handle, CURLOPT_CONNECTTIMEOUT, 2); curl_setopt($curl_handle, CURLOPT_RETURNTRANSFER, 1); curl_setopt($curl_handle, CURLOPT_POST, 1); curl_setopt($curl_handle, CURLOPT_POSTFIELDS, "status=$message"); curl_setopt($curl_handle, CURLOPT_USERPWD, "$username:$password"); $buffer = curl_exec($curl_handle); curl_close($curl_handle); $passed = 'yes'; } echo "<?xml version='1.0' encoding='UTF-8'?>\n"; echo "\t<result>\n"; echo "\t\t<passed>" . $passed . "</passed>\n"; echo "\t</result>"; } Thanks

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  • jquery sucess dropdown

    - by mckenzie
    hi, //codes success: function(html){ // this is for input box - working document.getElementById('val').value=''; $('#val').value=''; // how do i set it for dropdown box to reset after sucess? document.getElementById('val2').value=''; $('#val2').value=''; } Once user submit dropdown box, i need it to reset to value="" but now it sticks with user option even after submitted. Any idea how to achieve that?

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  • RubyMine Folder Tree doesn't refresh

    - by user336514
    Hi Using RubyMine 2.0.2 for the first time today, on Mac OSX Leopard. If I create files in the filesystem (with, say, script/generate) those new files do not appear in rubymine. I have had limited success with restarting the program, in that the files in the db/ folder are added and removed, but unfortunately new folders in the views directory are not shown. Pardon my french, but wtf? Thanks

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