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  • Is there a mechanism to distribute an app with its own JRE?

    - by user179997
    Hello all, These fine folks are my users: http://www.youtube.com/watch?v=o4MwTvtyrUQ If you don't want to enjoy the video here is the gist: my users can't tell between a file and a folder, between a browser and a web site. I need to create a Java web app (Tomcat or Jetty) and deploy it in as many of their computers, Windows and Mac. The question is: Is there a mechanism to distribute an app with its own JRE? (in the Tcl world there are starpacks and starkits, in the Python world there's py2exe and others, that's the idea). And also, is it legal? I know the VM is open source but I'm not clear about the libraries, and I know about GNU Classpath but I don't know if all the packages are there. I don't want to depend on the installed JRE or on the user having enough privileges to install one. On the Mac I don't want to depend on Apple (I had to switch from Tiger to Snow Leopard just to have Java 1.6, I can't put my users in that position) Any info greatly appreciated. Thanks! jb

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  • Merge object from list by comparing one value

    - by Bala
    I have two List of Objects (one is master list and other is error list) and if there is a match of one value when compared two lists then merge all other error list values into mast list value (only one object). Other than iterating is there any other way to compare a value and then merge that object. Object is a Value object with some setters and getters. Appreciate your help. List<OrderVO> masterList; List<OrderVO> errorList; If errorList.OrderVO.getOrderID = masterList.OrderVO.getOrderID then masterList.OrderVO.merge(errorList.OrderVO) or copy all values of masterList.OrderVO.copy(errorList.OrderVO). Hoper this is clear

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  • Dividing a list in specific number of sublists

    - by Surya
    I want to divide a list in "a specific number of" sublists. That is, for example if I have a list List(34, 11, 23, 1, 9, 83, 5) and the number of sublists expected is 3 then I want List(List(34, 11), List(23, 1), List(9, 83, 5)). How do I go about doing this? I tried grouped but it doesn't seem to be doing what I want. PS: This is not a homework question. Kindly give a direct solution instead of some vague suggestions.

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  • Printing a list using reflection

    - by TFool
    public class Service{ String serviceName; //setter and getter } public class Version{ String VersionID; //setter and getter } public void test(Object list){ //it shd print the obtained list } List< Service list1; //Service is a Bean List< Version list2; //Version is a Bean test(list1); test(list2); Now the test method shd print the obtained list - (i.e) If the list is of type Service ,then serviceName should be printed using its getter. If the list type is Version versionID should be printed. Is it possible to achieve this without using Interface or abstract class?

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  • Saudi Arabian Retail Distribution Business Ajlan & Bros Selects Oracle Commerce

    - by Marie-Christin Hansen
    Ajlan & Bros has selected Oracle Commerce in a bid to improve its customer engagement capabilities and drive its expansion plans. The large Middle Eastern retail distribution business, which specializes in the design, manufacture and supply of clothing across the Middle East, is seeking to expand its operations, which consist of a distribution network of more than 7,000 points of sale and represent more than 15 international brands. The business is aiming to build brand awareness globally with an interest in the European and American markets. Choosing Oracle Commerce will provide Ajlan & Bros with the capability to optimize each customer engagement, which will help to increase cross-channel promotion and improve a unified online, mobile and social experience for customers. The company will be able to leverage Oracle Commerce’s advanced marketing and personalization capabilities, with enhanced integrated search and content management functionality across its channels. The selection of Oracle Commerce followed an extensive evaluation of competitor solutions, with Oracle selected due to the solutions strong capabilities in cross-channel ecommerce and customer experience management, as well as a solid track record of maintaining best practice. Press release: Ajlan & Bros Selects Oracle Commerce to Support Expansion Strategy

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  • Format all elements of a list

    - by Curious2learn
    I want to print a list of numbers, but I want to format each member of the list before it is printed. For example, theList=[1.343465432, 7.423334343, 6.967997797, 4.5522577] I want the following output printed given the above list as an input: [1.34, 7.42, 6.97, 4.55] For any one member of the list, I know I can format it by using, print "%.2f" % member Is there a command/function that can do this for the whole list. I can write one, but was wondering if one already exists. Thanks.

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  • Combining List<>'s in .NET

    - by Maxim Z.
    I have a few List< objects that hold many objects of one specific type. My goal is to combine these List<'s into one List<. Of course, I could just loop through each List's contents and add them into one final List, but is there a more efficient way?

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  • std::list or std::multimap

    - by Tamir
    Hey, I right now have a list of a struct that I made, I sort this list everytime I add a new object, using the std::list sort method. I want to know what would be faster, using a std::multimap for this or std::list, since I'm iterating the whole list every frame (I am making a game). I would like to hear your opinion, for what should I use for this incident.

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  • How to slice a list of objects in association of the object attributes

    - by gizgok
    I have a list of fixtures.Each fixture has a home club and a away club attribute.I want to slice the list in association of its home club and away club.The sliced list should be of homeclub items and awayclub items. Easier way to implement this is to first slice a list of fixtures.Then make a new list of the corresponding Home Clubs and Away Clubs.I wanted to know if we can do this one step.

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  • python how to find the median of a list

    - by user3450574
    I'm trying to write a function named median that takes a list as an input and returns the median value of the list. I'm working with Python 2.7.2 The list can be of any size and the numbers are not guaranteed to be in any particular order. If the list contains an even number of elements, the function should return the average of the middle two. This is the code I'm starting with: def median(list): print(median([7,12,3,1,6,9]))

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  • How to use a list of values in Excel as filter in a query

    - by Luca Zavarella
    It often happens that a customer provides us with a list of items for which to extract certain information. Imagine, for example, that our clients wish to have the header information of the sales orders only for certain orders. Most likely he will give us a list of items in a column in Excel, or, less probably, a simple text file with the identification code:     As long as the given values ??are at best a dozen, it costs us nothing to copy and paste those values ??in our SSMS and place them in a WHERE clause, using the IN operator, making sure to include the quotes in the case of alphanumeric elements (the database sample is AdventureWorks2008R2): SELECT * FROM Sales.SalesOrderHeader AS SOH WHERE SOH.SalesOrderNumber IN ( 'SO43667' ,'SO43709' ,'SO43726' ,'SO43746' ,'SO43782' ,'SO43796') Clearly, the need to add commas and quotes becomes an hassle when dealing with hundreds of items (which of course has happened to us!). It’d be comfortable to do a simple copy and paste, leaving the items as they are pasted, and make sure the query works fine. We can have this commodity via a User Defined Function, that returns items in a table. Simply we’ll provide the function with an input string parameter containing the pasted items. I give you directly the T-SQL code, where comments are there to clarify what was written: CREATE FUNCTION [dbo].[SplitCRLFList] (@List VARCHAR(MAX)) RETURNS @ParsedList TABLE ( --< Set the item length as your needs Item VARCHAR(255) ) AS BEGIN DECLARE --< Set the item length as your needs @Item VARCHAR(255) ,@Pos BIGINT --< Trim TABs due to indentations SET @List = REPLACE(@List, CHAR(9), '') --< Trim leading and trailing spaces, then add a CR\LF at the end of the list SET @List = LTRIM(RTRIM(@List)) + CHAR(13) + CHAR(10) --< Set the position at the first CR/LF in the list SET @Pos = CHARINDEX(CHAR(13) + CHAR(10), @List, 1) --< If exist other chars other than CR/LFs in the list then... IF REPLACE(@List, CHAR(13) + CHAR(10), '') <> '' BEGIN --< Loop while CR/LFs are over (not found = CHARINDEX returns 0) WHILE @Pos > 0 BEGIN --< Get the heading list chars from the first char to the first CR/LF and trim spaces SET @Item = LTRIM(RTRIM(LEFT(@List, @Pos - 1))) --< If the so calulated item is not empty... IF @Item <> '' BEGIN --< ...insert it in the @ParsedList temporary table INSERT INTO @ParsedList (Item) VALUES (@Item) --(CAST(@Item AS int)) --< Use the appropriate conversion if needed END --< Remove the first item from the list... SET @List = RIGHT(@List, LEN(@List) - @Pos - 1) --< ...and set the position to the next CR/LF SET @Pos = CHARINDEX(CHAR(13) + CHAR(10), @List, 1) --< Repeat this block while the upon loop condition is verified END END RETURN END At this point, having created the UDF, our query is transformed trivially in: SELECT * FROM Sales.SalesOrderHeader AS SOH WHERE SOH.SalesOrderNumber IN ( SELECT Item FROM SplitCRLFList('SO43667 SO43709 SO43726 SO43746 SO43782 SO43796') AS SCL) Convenient, isn’t it? You can find the script DBA_SplitCRLFList.sql here. Bye!!

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  • How to hide distribution group from "All Groups" Address Book in Outlook 2010?

    - by cparker4486
    I'm working with Outlook 2010 and Exchange 2010 and while writing this post I found another post on the topic but it was for Exchange 2007. It mentioned Address List Segregation which, as it turns out, is not supported in Exchange 2010. So it seems another method is required. I've successfully hidden a distribution group from the GAL by removing the Authenticated Users group but the group is still visible in the Address Book called "All Groups". I would expect it to be hidden in all address books not just the GAL. Are there any other security groups I should remove to hide it from All Groups? To give visibility in the GAL I am manually adding the user (the group is being used for Send As purposes). In the image below the green line represents where the group is visible and the red line indicates the opposite.

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  • How to store a linked list in a struct in C

    - by LuckySlevin
    typedef struct child_list {int count; char vo[100]; child_list*next;} child_list; typedef struct parent_list { char vo[100]; child_list * head; int count; parent_list * next; } parent_list; As you can see there are two structures. child_list is used to create a linked list. And this list will be stored in a linked list of parent list. My problem is to display the child list which in the parent_list. My desire to get while displaying the linked list of parent_list: This lists work with this logic. I already made append and other stuff. For example if i enter ab cd ab ja cd ab Word Count List ab 3 cd->ja cd 2 ab->ab ja 1 cd The problematic part is displaying child_list which is in the parent_list nodes(List column of output). I don't know my question is clear please ask for further info.

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  • Approach For Syncing One SharePoint List With One or More SharePoint Lists

    - by plattnum
    What would be the best approach or strategy for configuring, customizing or developing in SharePoint a solution that allows me to keep one or more SharePoint lists in sync with a SharePoint list I have designated as a master or parent list. I would like to be able to create a master/parent list of some information that can be extended or used by different parts of the organization without them being able to CRUD any items on the actual columns of the master list. (I have seen some commercial web parts that offer column security on SharePoint lists and although that’s one way of potentially meeting my needs I would like to explore other options.) Scenario: I have a list called FOO: FOO Title Description I would like to create a new list BAR based off of FOO (BAR is managed by sub-organization that doesn't have access to FOO List): BAR FOO.Title (Read-Only) FOO.Description (Read-Only) NewColumn1 NewColumn2 Actions: Create- If a new item is entered in FOO I would like the new item added to BAR. Read - N/A Update - If the title or description is changed in FOO I would like it changed in BAR. Delete- No Deletes in the scenario. (Deletes are handled by the business with status column.) Templates with content extraction offer me this but it’s a one time shot at list creation. Just not sure what the best approach or strategy would be for this in MOSS 2007. Thanks!

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  • Problem with inheritance and List<>

    - by Jagd
    I have an abstract class called Grouping. I have a subclass called GroupingNNA. public class GroupingNNA : Grouping { // blah blah blah } I have a List that contains items of type GroupingNNA, but is actually declared to contain items of type Grouping. List<Grouping> lstGroupings = new List<Grouping>(); lstGroupings.Add( new GroupingNNA { fName = "Joe" }); lstGroupings.Add( new GroupingNNA { fName = "Jane" }); The Problem: The following LINQ query blows up on me because of the fact that lstGroupings is declared as List< Grouping and fName is a property of GroupingNNA, not Grouping. var results = from g in lstGroupings where r.fName == "Jane" select r; Oh, and this is a compiler error, not a runtime error. Thanks in advance for any help on this one! More Info: Here is the actual method that won't compile. The OfType() fixed the LINQ query, but the compiler doesn't like the fact that I'm trying to return the anonymous type as a List< Grouping. private List<Grouping> ApplyFilterSens(List<Grouping> lstGroupings, string fSens) { // This works now! Thanks @Lasse var filtered = from r in lstGroupings.OfType<GroupingNNA>() where r.QASensitivity == fSens select r; if (filtered != null) { **// Compiler doesn't like this now** return filtered.ToList<Grouping>(); } else return new List<Grouping>(); }

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  • Scaling Out the Distribution Database

    Replication is a great technology for moving data from one server to another, and it has a great many configuration options. David Poole brings us a technique for scaling out with multiple distribution databases.

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  • Online Content Distribution is a Valuable SEO Tool

    Online content distribution is quite possibly one of the best and easiest ways to boost your search engine rankings if done properly. It is quite common however to overlook the importance this strategy can play in our optimization efforts. Read on to see 5 ways in which using content can boost your SEO efforts leading to even more exposure and traffic.

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  • Cisco 800 series won't forward port

    - by sam
    Hello ServerFault, I am trying to forward port 444 from my cisco router to my Web Server (192.168.0.2). As far as I can tell, my port forwarding is configured correctly, yet no traffic will pass through on port 444. Here is my config: ! version 12.3 service config no service pad service tcp-keepalives-in service tcp-keepalives-out service timestamps debug uptime service timestamps log uptime service password-encryption no service dhcp ! hostname QUESTMOUNT ! logging buffered 16386 informational logging rate-limit 100 except warnings no logging console no logging monitor enable secret 5 -removed- ! username administrator secret 5 -removed- username manager secret 5 -removed- clock timezone NZST 12 clock summer-time NZDT recurring 1 Sun Oct 2:00 3 Sun Mar 3:00 aaa new-model ! ! aaa authentication login default local aaa authentication login userlist local aaa authentication ppp default local aaa authorization network grouplist local aaa session-id common ip subnet-zero no ip source-route no ip domain lookup ip domain name quest.local ! ! no ip bootp server ip inspect name firewall tcp ip inspect name firewall udp ip inspect name firewall cuseeme ip inspect name firewall h323 ip inspect name firewall rcmd ip inspect name firewall realaudio ip inspect name firewall streamworks ip inspect name firewall vdolive ip inspect name firewall sqlnet ip inspect name firewall tftp ip inspect name firewall ftp ip inspect name firewall icmp ip inspect name firewall sip ip inspect name firewall fragment maximum 256 timeout 1 ip inspect name firewall netshow ip inspect name firewall rtsp ip inspect name firewall skinny ip inspect name firewall http ip audit notify log ip audit po max-events 100 ip audit name intrusion info list 3 action alarm ip audit name intrusion attack list 3 action alarm drop reset no ftp-server write-enable ! ! ! ! crypto isakmp policy 1 authentication pre-share ! crypto isakmp policy 2 encr 3des authentication pre-share group 2 ! crypto isakmp client configuration group staff key 0 qS;,sc:q<skro1^, domain quest.local pool vpnclients acl 106 ! ! crypto ipsec transform-set tr-null-sha esp-null esp-sha-hmac crypto ipsec transform-set tr-des-md5 esp-des esp-md5-hmac crypto ipsec transform-set tr-des-sha esp-des esp-sha-hmac crypto ipsec transform-set tr-3des-sha esp-3des esp-sha-hmac ! crypto dynamic-map vpnusers 1 description Client to Site VPN Users set transform-set tr-des-md5 ! ! crypto map cm-cryptomap client authentication list userlist crypto map cm-cryptomap isakmp authorization list grouplist crypto map cm-cryptomap client configuration address respond crypto map cm-cryptomap 65000 ipsec-isakmp dynamic vpnusers ! ! ! ! interface Ethernet0 ip address 192.168.0.254 255.255.255.0 ip access-group 102 in ip nat inside hold-queue 100 out ! interface ATM0 no ip address no atm ilmi-keepalive dsl operating-mode auto ! interface ATM0.1 point-to-point pvc 0/100 encapsulation aal5mux ppp dialer dialer pool-member 1 ! ! interface Dialer0 bandwidth 640 ip address negotiated ip access-group 101 in no ip redirects no ip unreachables ip nat outside ip inspect firewall out ip audit intrusion in encapsulation ppp no ip route-cache no ip mroute-cache dialer pool 1 dialer-group 1 no cdp enable ppp pap sent-username -removed- password 7 -removed- ppp ipcp dns request crypto map cm-cryptomap ! ip local pool vpnclients 192.168.99.1 192.168.99.254 ip nat inside source list 105 interface Dialer0 overload ip nat inside source static tcp 192.168.0.2 444 interface Dialer0 444 ip nat inside source static tcp 192.168.0.51 9000 interface Dialer0 9000 ip nat inside source static udp 192.168.0.2 1433 interface Dialer0 1433 ip nat inside source static tcp 192.168.0.2 1433 interface Dialer0 1433 ip nat inside source static tcp 192.168.0.2 25 interface Dialer0 25 ip classless ip route 0.0.0.0 0.0.0.0 Dialer0 ip http server no ip http secure-server ! ip access-list logging interval 10 logging 192.168.0.2 access-list 1 remark The local LAN. access-list 1 permit 192.168.0.0 0.0.0.255 access-list 2 permit 192.168.0.0 access-list 2 remark Where management can be done from. access-list 2 permit 192.168.0.0 0.0.0.255 access-list 3 remark Traffic not to check for intrustion detection. access-list 3 deny 192.168.99.0 0.0.0.255 access-list 3 permit any access-list 101 remark Traffic allowed to enter the router from the Internet access-list 101 permit ip 192.168.99.0 0.0.0.255 192.168.0.0 0.0.0.255 access-list 101 deny ip 0.0.0.0 0.255.255.255 any access-list 101 deny ip 10.0.0.0 0.255.255.255 any access-list 101 deny ip 127.0.0.0 0.255.255.255 any access-list 101 deny ip 169.254.0.0 0.0.255.255 any access-list 101 deny ip 172.16.0.0 0.15.255.255 any access-list 101 deny ip 192.0.2.0 0.0.0.255 any access-list 101 deny ip 192.168.0.0 0.0.255.255 any access-list 101 deny ip 198.18.0.0 0.1.255.255 any access-list 101 deny ip 224.0.0.0 0.15.255.255 any access-list 101 deny ip any host 255.255.255.255 access-list 101 permit tcp 67.228.209.128 0.0.0.15 any eq 1433 access-list 101 permit tcp host 120.136.2.22 any eq 1433 access-list 101 permit tcp host 123.100.90.58 any eq 1433 access-list 101 permit udp 67.228.209.128 0.0.0.15 any eq 1433 access-list 101 permit udp host 120.136.2.22 any eq 1433 access-list 101 permit udp host 123.100.90.58 any eq 1433 access-list 101 permit tcp any any eq 444 access-list 101 permit tcp any any eq 9000 access-list 101 permit tcp any any eq smtp access-list 101 permit udp any any eq non500-isakmp access-list 101 permit udp any any eq isakmp access-list 101 permit esp any any access-list 101 permit tcp any any eq 1723 access-list 101 permit gre any any access-list 101 permit tcp any any eq 22 access-list 101 permit tcp any any eq telnet access-list 102 remark Traffic allowed to enter the router from the Ethernet access-list 102 permit ip any host 192.168.0.254 access-list 102 deny ip any host 192.168.0.255 access-list 102 deny udp any any eq tftp log access-list 102 permit ip 192.168.0.0 0.0.0.255 192.168.99.0 0.0.0.255 access-list 102 deny ip any 0.0.0.0 0.255.255.255 log access-list 102 deny ip any 10.0.0.0 0.255.255.255 log access-list 102 deny ip any 127.0.0.0 0.255.255.255 log access-list 102 deny ip any 169.254.0.0 0.0.255.255 log access-list 102 deny ip any 172.16.0.0 0.15.255.255 log access-list 102 deny ip any 192.0.2.0 0.0.0.255 log access-list 102 deny ip any 192.168.0.0 0.0.255.255 log access-list 102 deny ip any 198.18.0.0 0.1.255.255 log access-list 102 deny udp any any eq 135 log access-list 102 deny tcp any any eq 135 log access-list 102 deny udp any any eq netbios-ns log access-list 102 deny udp any any eq netbios-dgm log access-list 102 deny tcp any any eq 445 log access-list 102 permit ip 192.168.0.0 0.0.0.255 any access-list 102 permit ip any host 255.255.255.255 access-list 102 deny ip any any log access-list 105 remark Traffic to NAT access-list 105 deny ip 192.168.0.0 0.0.0.255 192.168.99.0 0.0.0.255 access-list 105 permit ip 192.168.0.0 0.0.0.255 any access-list 106 remark User to Site VPN Clients access-list 106 permit ip 192.168.0.0 0.0.0.255 any dialer-list 1 protocol ip permit ! line con 0 no modem enable line aux 0 line vty 0 4 access-class 2 in transport input telnet ssh transport output none ! scheduler max-task-time 5000 ! end any ideas? :)

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  • Accessing elements of List<List<string>>

    - by shiv09
    Hello Friends........... Can anyone let me know how can access an element of a list that has been added to a list of list............. I'll mention the code............ List str = new List(); List stud = new List(); A method has been defined that inserts data into str and after the method gets over......... stud.Add(str); The method and stud.Add(str) is on a button click...... so, each time str contains different data....... the problem is I want to search in whole of stud i.e. all the str created, whether str[0]==textBox3.Text; I'm confused in the For loops...how to reach to all the str[0] in stud to verify the condition...................

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  • List of dict in Python

    - by plalex
    Hi everybody, I've got a list of dict in Python: dico_cfg = {'name': entry_name, 'ip': entry_ip, 'vendor': combo_vendor, 'stream': combo_stream} self.list_cfg.append(dico_cfg) I append to my list a lot of dict in the same way. Now I would like to delete one dict and only one dict in this list? What is the best way to proceed? I've try with the index of the list, but when I remove a dict from the list, the index is modify, so after some random remove my index doesn't correspond anymore to the dict I want to remove in my list. I hope that is clear. Maybe I can add an "id" row in my dict, so I can ask to remove more preciously the dict I want. I'll ask to remove the dict where id is equal to the id's dict I want to remove. How can I do that? I hope I'm enough clear. Sorry but I'm a newbie in Python.

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