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  • pointer to a pointer in a linked list

    - by user1596497
    I'm trying to set a linked list head through pointer to a pointer. I can see inside the function that the address of the head pointer is changing but as i return to the main progran it becomes NULL again. can someone tell me what I'm doing wrong ?? #include <stdio.h> #include <stdlib.h> typedef void(*fun_t)(int); typedef struct timer_t { int time; fun_t func; struct timer_t *next; }TIMER_T; void add_timer(int sec, fun_t func, TIMER_T *head); void run_timers(TIMER_T **head); void timer_func(int); int main(void) { TIMER_T *head = NULL; int time = 1; fun_t func = timer_func; while (time < 1000) { printf("\nCalling add_timer(time=%d, func=0x%x, head=0x%x)\n", time, func, &head); add_timer(time, func, head); time *= 2; } run_timers(&head); return 0; } void add_timer(int sec, fun_t func, TIMER_T *head) { TIMER_T ** ppScan=&head; TIMER_T *new_timer = NULL; new_timer = (TIMER_T*)malloc(sizeof(TIMER_T)); new_timer->time = sec; new_timer->func = func; new_timer->next = NULL; while((*ppScan != NULL) && (((**ppScan).time)<sec)) ppScan = &(*ppScan)->next; new_timer->next = *ppScan; *ppScan = new_timer; }

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  • Linked List Inserting strings in alphabetical order

    - by user69514
    I have a linked list where each node contains a string and a count. my insert method needs to inset a new node in alphabetical order based on the string. if there is a node with the same string, then i increment the count. the problem is that my method is not inserting in alphabetical order public Node findIsertionPoint(Node head, Node node){ if( head == null) return null; Node curr = head; while( curr != null){ if( curr.getValue().compareTo(node.getValue()) == 0) return curr; else if( curr.getNext() == null || curr.getNext().getValue().compareTo(node.getValue()) > 0) return curr; else curr = curr.getNext(); } return null; } public void insert(Node node){ Node newNode = node; Node insertPoint = this.findIsertionPoint(this.head, node); if( insertPoint == null) this.head = newNode; else{ if( insertPoint.getValue().compareTo(node.getValue()) == 0) insertPoint.getItem().incrementCount(); else{ newNode.setNext(insertPoint.getNext()); insertPoint.setNext(newNode); } } count++; }

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  • Adding and sorting a linked list in C

    - by user1202963
    In my assignment, I have to write a function that takes as arguments a pointer to a "LNode" structure and an integer argument. Then, I have to not only add that integer into the linked list, but also put place it so that the list is in proper ascending order. I've tried several various attempts at this, and this is my code as of posting. LNode* AddItem(LNode *headPtr, int newItem) { auto LNode *ptr = headPtr; ptr = malloc(sizeof(LNode)); if (headPtr == NULL) { ptr->value = newItem; ptr->next = headPtr; return ptr; } else { while (headPtr->value > newItem || ptr->next != NULL) { printf("While\n"); // This is simply to let me know how many times the loop runs headPtr = headPtr->next; } ptr->value = newItem; ptr->next = headPtr; return ptr; } } // end of "AddItem" When I run it, and try to insert say a 5 and then a 3, the 5 gets inserted, but then the while loop runs once and I get a segmentation fault. Also I cannot change the arguments as it's part of a skeletal code for this project. Thanks to anyone who can help. If it helps this is what the structure looks like typedef struct LNode { int value; struct LNode *next; } LNode;

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  • Sorting a Singly Linked List With Pointers

    - by Mark Simson
    I am trying to sort a singly linked list using bubble sort by manipulating ONLY the pointers, no keys. The following gets stuck in the for loop and loops infinitely. I don't understand why this is. Can anybody explain to me why the end of the list is not being found? Node* sort_list(Node* head) { Node * temp; Node * curr; for(bool didSwap = true; didSwap; ) { didSwap = false; for(curr = head; curr->next != NULL; curr = curr->next) { if(curr->key > curr->next->key) { temp = curr; curr = curr->next; curr->next = temp; didSwap = true; } cout << curr->next->key << endl; } } return head; } If I change the code so that the keys (data) are swapped, then the function works properly but for some reason I am not able make it work by manipulating only pointers.

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  • List of available whitepapers as at 04 May 2010

    - by Anthony Shorten
    The following table lists the whitepapers available, from My Oracle Support, for any Oracle Utilities Application Framework based product: KB Id Document Title Contents 559880.1 ConfigLab Design Guidelines Whitepaper outlining how to design and implement a ConfigLab solution. 560367.1 Technical Best Practices for Oracle Utilities Application Framework Based Products Whitepaper summarizing common technical best practices used by partners, implementation teams and customers.  560382.1 Performance Troubleshooting Guideline Series A set of whitepapers on tracking performance at each tier in the framework. The individual whitepapers are as follows: Concepts - General Concepts and Performance Troublehooting processes Client Troubleshooting - General troubleshooting of the browser client with common issues and resolutions. Network Troubleshooting - General troubleshooting of the network with common issues and resolutions. Web Application Server Troubleshooting - General troubleshooting of the Web Application Server with common issues and resolutions. Server Troubleshooting - General troubleshooting of the Operating system with common issues and resolutions. Database Troubleshooting - General troubleshooting of the database with common issues and resolutions. Batch Troubleshooting - General troubleshooting of the background processing component of the product with common issues and resolutions. 560401.1 Software Configuration Management Series  A set of whitepapers on how to manage customization (code and data) using the tools provided with the framework. The individual whitepapers are as follows: Concepts - General concepts and introduction. Environment Management - Principles and techniques for creating and managing environments. Version Management - Integration of Version control and version management of configuration items.  Release Management - Packaging configuration items into a release.  Distribution - Distribution and installation of  releases across environments  Change Management - Generic change management processes for product implementations. Status Accounting -Status reporting techniques using product facilities.  Defect Management -Generic defect management processes for product implementations. Implementing Single Fixes - Discussion on the single fix architecture and how to use it in an implementation. Implementing Service Packs - Discussion on the service packs and how to use them in an implementation. Implementing Upgrades - Discussion on the the upgrade process and common techniques for minimizing the impact of upgrades. 773473.1 Oracle Utilities Application Framework Security Overview Whitepaper summarizing the security facilities in the framework. Updated for OUAF 4.0.1 774783.1 LDAP Integration for Oracle Utilities Application Framework based products Whitepaper summarizing how to integrate an external LDAP based security repository with the framework.  789060.1 Oracle Utilities Application Framework Integration Overview Whitepaper summarizing all the various common integration techniques used with the product (with case studies). 799912.1 Single Sign On Integration for Oracle Utilities Application Framework based products Whitepaper outlining a generic process for integrating an SSO product with the framework. 807068.1 Oracle Utilities Application Framework Architecture Guidelines This whitepaper outlines the different variations of architecture that can be considered. Each variation will include advice on configuration and other considerations. 836362.1 Batch Best Practices for Oracle Utilities Application Framework based products This whitepaper oulines the common and best practices implemented by sites all over the world. Updated for OUAF 4.0.1 856854.1 Technical Best Practices V1 Addendum  Addendum to Technical Best Practices for Oracle Utilities Application Framework Based Products containing only V1.x specific advice. 942074.1 XAI Best Practices This whitepaper outlines the common integration tasks and best practices for the Web Services Integration provided by the Oracle Utilities Application Framework. Updated for OUAF 4.0.1 970785.1 Oracle Identity Manager Integration Overview This whitepaper outlines the principals of the prebuilt intergration between Oracle Utilities Application Framework Based Products and Orade Identity Manager used to provision user and user group secuity information 1068958.1 Production Environment Configuration Guidelines (New!) Whitepaper outlining common production level settings for the products

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  • How do i make/setup a mailing list?

    - by acidzombie24
    I know i could program it myself but maybe there is a simple (thats the keyword) package. I like to add a box, snippet, form or page to my site for users to input their email address. Then i'd like it to automatically send email saying you have successfully subscribe. I'd want an unsubscribe link and i would be using smtp on google apps. I would like to send email with html so i can have a simple sentence with a complex link such as this I dont know if i'll get marked as spam if i try to send everyone an email at once? so i'd like the software to manage it. Also i'd like to get the emails in a simple format like csv. Is there a simple app that does this? if not i can write a simple form which does a simple insert (or delete when unsubscribing) and write a 200-300line app to send my emails out for me.

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  • using php to list some files in folders

    - by Terix
    I have collected many free themes from around internet. Each of them has a screenshot.jpg or png file on their folder. I want to scan all the folders for that file, and return the full file path to be used with an img html tag. I am not interested on partial path or folders where there are not screenshots. For example, if my fodler structure is: ./a/b/ ./c/d/e/screenshot.jpg ./f/ ./g/screenshot.jpg ./h/i/j/k/ ./l/m/screenshot.png ./n/o/ ./p/screenshot.jpg I want to get: ./c/d/e/screenshot.jpg ./g/screenshot.jpg ./l/m/screenshot.png ./p/screenshot.jpg I managed somehow to get a recursive function, but I figured only the way to return an array and then i can't get rid of what I don't need, and I miss png. Can anyone help me on that? the code I managed to put together is this: function getDirectoryTree( $outerDir , $x){ $dirs = array_diff( scandir( $outerDir ), Array( ".", ".." ) ); $dir_array = Array(); foreach( $dirs as $d ){ if( is_dir($outerDir."/".$d) ){ $dir_array[ $d ] = getDirectoryTree( $outerDir."/".$d , $x); }else{ if ($d==x) $dir_array[ $d ] = $d; } } return $dir_array; } $dirlist = getDirectoryTree('.','screenshot.jpg'); print_r($dirlist);

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  • Origin of common list-processing function names

    - by Heatsink
    Some higher-order functions for operating on lists or arrays have been repeatedly adopted or reinvented. The functions map, fold[l|r], and filter are found together in several programming languages, such as Scheme, ML, and Python, that don't seem to have a common ancestor. I'm going with these three names to keep the question focused. To show that the names are not universal, here is a sampling of names for equivalent functionality in other languages. C++ has transform instead of map and remove_if instead of filter (reversing the meaning of the predicate). Lisp has mapcar instead of map, remove-if-not instead of filter, and reduce instead of fold (Some modern Lisp variants have map but this appears to be a derived form.) C# uses Select instead of map and Where instead of filter. C#'s names came from SQL via LINQ, and despite the name changes, their functionality was influenced by Haskell, which was itself influenced by ML. The names map, fold, and filter are widespread, but not universal. This suggests that they were borrowed from an influential source into other contemporary languages. Where did these function names come from?

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  • Oracle 11g ??? – HM(Hang Manager)??

    - by Allen Gao
    Normal 0 7.8 ? 0 2 false false false EN-US ZH-CN X-NONE MicrosoftInternetExplorer4 DefSemiHidden="true" DefQFormat="false" DefPriority="99" LatentStyleCount="267" UnhideWhenUsed="false" QFormat="true" Name="Normal"/ UnhideWhenUsed="false" QFormat="true" Name="heading 1"/ UnhideWhenUsed="false" QFormat="true" Name="Title"/ UnhideWhenUsed="false" QFormat="true" Name="Subtitle"/ UnhideWhenUsed="false" QFormat="true" Name="Strong"/ UnhideWhenUsed="false" QFormat="true" Name="Emphasis"/ UnhideWhenUsed="false" Name="Table Grid"/ UnhideWhenUsed="false" QFormat="true" Name="No Spacing"/ UnhideWhenUsed="false" Name="Light Shading"/ UnhideWhenUsed="false" Name="Light List"/ UnhideWhenUsed="false" Name="Light Grid"/ UnhideWhenUsed="false" Name="Medium Shading 1"/ UnhideWhenUsed="false" Name="Medium Shading 2"/ UnhideWhenUsed="false" Name="Medium List 1"/ UnhideWhenUsed="false" Name="Medium List 2"/ UnhideWhenUsed="false" Name="Medium Grid 1"/ UnhideWhenUsed="false" Name="Medium Grid 2"/ UnhideWhenUsed="false" Name="Medium Grid 3"/ UnhideWhenUsed="false" Name="Dark List"/ UnhideWhenUsed="false" Name="Colorful Shading"/ UnhideWhenUsed="false" Name="Colorful List"/ UnhideWhenUsed="false" Name="Colorful Grid"/ UnhideWhenUsed="false" Name="Light Shading Accent 1"/ UnhideWhenUsed="false" Name="Light List Accent 1"/ UnhideWhenUsed="false" Name="Light Grid Accent 1"/ UnhideWhenUsed="false" Name="Medium Shading 1 Accent 1"/ UnhideWhenUsed="false" Name="Medium Shading 2 Accent 1"/ UnhideWhenUsed="false" Name="Medium List 1 Accent 1"/ UnhideWhenUsed="false" QFormat="true" Name="List Paragraph"/ UnhideWhenUsed="false" QFormat="true" Name="Quote"/ UnhideWhenUsed="false" QFormat="true" Name="Intense Quote"/ UnhideWhenUsed="false" Name="Medium List 2 Accent 1"/ UnhideWhenUsed="false" Name="Medium Grid 1 Accent 1"/ UnhideWhenUsed="false" Name="Medium Grid 2 Accent 1"/ UnhideWhenUsed="false" Name="Medium Grid 3 Accent 1"/ UnhideWhenUsed="false" Name="Dark List Accent 1"/ UnhideWhenUsed="false" Name="Colorful Shading Accent 1"/ UnhideWhenUsed="false" Name="Colorful List Accent 1"/ UnhideWhenUsed="false" Name="Colorful Grid Accent 1"/ UnhideWhenUsed="false" Name="Light Shading Accent 2"/ UnhideWhenUsed="false" Name="Light List Accent 2"/ UnhideWhenUsed="false" Name="Light Grid Accent 2"/ UnhideWhenUsed="false" Name="Medium Shading 1 Accent 2"/ UnhideWhenUsed="false" Name="Medium Shading 2 Accent 2"/ UnhideWhenUsed="false" Name="Medium List 1 Accent 2"/ UnhideWhenUsed="false" Name="Medium List 2 Accent 2"/ UnhideWhenUsed="false" Name="Medium Grid 1 Accent 2"/ UnhideWhenUsed="false" Name="Medium Grid 2 Accent 2"/ UnhideWhenUsed="false" Name="Medium Grid 3 Accent 2"/ UnhideWhenUsed="false" Name="Dark List Accent 2"/ UnhideWhenUsed="false" Name="Colorful Shading Accent 2"/ UnhideWhenUsed="false" Name="Colorful List Accent 2"/ UnhideWhenUsed="false" Name="Colorful Grid Accent 2"/ UnhideWhenUsed="false" Name="Light Shading Accent 3"/ UnhideWhenUsed="false" Name="Light List Accent 3"/ UnhideWhenUsed="false" Name="Light Grid Accent 3"/ UnhideWhenUsed="false" Name="Medium Shading 1 Accent 3"/ UnhideWhenUsed="false" Name="Medium Shading 2 Accent 3"/ UnhideWhenUsed="false" Name="Medium List 1 Accent 3"/ UnhideWhenUsed="false" Name="Medium List 2 Accent 3"/ UnhideWhenUsed="false" Name="Medium Grid 1 Accent 3"/ UnhideWhenUsed="false" Name="Medium Grid 2 Accent 3"/ UnhideWhenUsed="false" Name="Medium Grid 3 Accent 3"/ UnhideWhenUsed="false" Name="Dark List Accent 3"/ UnhideWhenUsed="false" Name="Colorful Shading Accent 3"/ UnhideWhenUsed="false" Name="Colorful List Accent 3"/ UnhideWhenUsed="false" Name="Colorful Grid Accent 3"/ UnhideWhenUsed="false" Name="Light Shading Accent 4"/ UnhideWhenUsed="false" Name="Light List Accent 4"/ UnhideWhenUsed="false" Name="Light Grid Accent 4"/ UnhideWhenUsed="false" Name="Medium Shading 1 Accent 4"/ UnhideWhenUsed="false" Name="Medium Shading 2 Accent 4"/ UnhideWhenUsed="false" Name="Medium List 1 Accent 4"/ UnhideWhenUsed="false" Name="Medium List 2 Accent 4"/ UnhideWhenUsed="false" Name="Medium Grid 1 Accent 4"/ UnhideWhenUsed="false" Name="Medium Grid 2 Accent 4"/ UnhideWhenUsed="false" Name="Medium Grid 3 Accent 4"/ UnhideWhenUsed="false" Name="Dark List Accent 4"/ UnhideWhenUsed="false" Name="Colorful Shading Accent 4"/ UnhideWhenUsed="false" Name="Colorful List Accent 4"/ UnhideWhenUsed="false" Name="Colorful Grid Accent 4"/ UnhideWhenUsed="false" Name="Light Shading Accent 5"/ UnhideWhenUsed="false" Name="Light List Accent 5"/ UnhideWhenUsed="false" Name="Light Grid Accent 5"/ UnhideWhenUsed="false" Name="Medium Shading 1 Accent 5"/ UnhideWhenUsed="false" Name="Medium Shading 2 Accent 5"/ UnhideWhenUsed="false" Name="Medium List 1 Accent 5"/ UnhideWhenUsed="false" Name="Medium List 2 Accent 5"/ UnhideWhenUsed="false" Name="Medium Grid 1 Accent 5"/ UnhideWhenUsed="false" Name="Medium Grid 2 Accent 5"/ UnhideWhenUsed="false" Name="Medium Grid 3 Accent 5"/ UnhideWhenUsed="false" Name="Dark List Accent 5"/ UnhideWhenUsed="false" Name="Colorful Shading Accent 5"/ UnhideWhenUsed="false" Name="Colorful List Accent 5"/ UnhideWhenUsed="false" Name="Colorful Grid Accent 5"/ UnhideWhenUsed="false" Name="Light Shading Accent 6"/ UnhideWhenUsed="false" Name="Light List Accent 6"/ UnhideWhenUsed="false" Name="Light Grid Accent 6"/ UnhideWhenUsed="false" Name="Medium Shading 1 Accent 6"/ UnhideWhenUsed="false" Name="Medium Shading 2 Accent 6"/ UnhideWhenUsed="false" Name="Medium List 1 Accent 6"/ UnhideWhenUsed="false" Name="Medium List 2 Accent 6"/ UnhideWhenUsed="false" Name="Medium Grid 1 Accent 6"/ UnhideWhenUsed="false" Name="Medium Grid 2 Accent 6"/ UnhideWhenUsed="false" Name="Medium Grid 3 Accent 6"/ UnhideWhenUsed="false" Name="Dark List Accent 6"/ UnhideWhenUsed="false" Name="Colorful Shading Accent 6"/ UnhideWhenUsed="false" Name="Colorful List Accent 6"/ UnhideWhenUsed="false" Name="Colorful Grid Accent 6"/ UnhideWhenUsed="false" QFormat="true" Name="Subtle Emphasis"/ UnhideWhenUsed="false" QFormat="true" Name="Intense Emphasis"/ UnhideWhenUsed="false" QFormat="true" Name="Subtle Reference"/ UnhideWhenUsed="false" QFormat="true" Name="Intense Reference"/ UnhideWhenUsed="false" QFormat="true" Name="Book Title"/ /* Style Definitions */ table.MsoNormalTable {mso-style-name:????; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:10.5pt; mso-bidi-font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:??; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi; mso-font-kerning:1.0pt;} ??????????oracle 11g ???—hang ???(Hang Manager) ???????????,HM ??RAC ??????? ?????????????,??????????/?? hang???????hang???,????,??????????? ??(cycle)?????hang, ???????,???????? ?????(blocker) ?????????????????????,???????,?????blocker ????????(immediate blocker)??????(root blocker)??root blocker ?????????????? 2.1 ???????????,??????,????????????? 2.2 ????????????????????(??:??I/O),??????,????????????????,?????????,????????????? ??????????, oracle??????????? ???????????11g RAC???? hang????hang ?????????? 1.?????????????hang analyze dump ??? 2.????hang analyze dump??(?????) 3. ??????dump??,??????????hang? 4. ??????????hang??? ???,??????????????? ??1: ORACLE ??????????,????? hang analysis cache,???????hang analyze dump i?????????????????????????? ??2:oracle ?????hang analyze ??,??,HM?????RAC??????,hang analyze??????????????,??????dump ????????DIA0(?????11g????)???????3????????hang analyze dump, ?10 ???????hang analyze dump? ??3:??,????????hang analyze dump ??,??,??????????????DIA0??,???????hang ?????,??RAC???,??hang????????????????,??????????DIA0 ????master,???????????????????11g??,?????????DIA0?????HM?master?????,?????????????,?(master)DIA0 ???????????????????? ??hang???,HM????????????,?HM?????hang analyze dump(?30???????,????????)?,??????????????????(???????open chain),????????????????(??,???????????),??,???????,?????????hang??????????????,?????????????????,???????????(open chain)??????,???????????????????hang.??,????(dead lock)????,????????,???????????????????????????? Normal 0 7.8 ? 0 2 false false false EN-US ZH-CN X-NONE MicrosoftInternetExplorer4 DefSemiHidden="true" DefQFormat="false" DefPriority="99" LatentStyleCount="267" UnhideWhenUsed="false" QFormat="true" Name="Normal"/ UnhideWhenUsed="false" QFormat="true" Name="heading 1"/ UnhideWhenUsed="false" QFormat="true" Name="Title"/ UnhideWhenUsed="false" QFormat="true" Name="Subtitle"/ UnhideWhenUsed="false" QFormat="true" Name="Strong"/ UnhideWhenUsed="false" QFormat="true" Name="Emphasis"/ UnhideWhenUsed="false" Name="Table Grid"/ UnhideWhenUsed="false" QFormat="true" Name="No Spacing"/ UnhideWhenUsed="false" Name="Light Shading"/ UnhideWhenUsed="false" Name="Light List"/ UnhideWhenUsed="false" Name="Light Grid"/ UnhideWhenUsed="false" Name="Medium Shading 1"/ UnhideWhenUsed="false" Name="Medium Shading 2"/ UnhideWhenUsed="false" Name="Medium List 1"/ UnhideWhenUsed="false" Name="Medium List 2"/ UnhideWhenUsed="false" Name="Medium Grid 1"/ UnhideWhenUsed="false" Name="Medium Grid 2"/ UnhideWhenUsed="false" Name="Medium Grid 3"/ UnhideWhenUsed="false" Name="Dark List"/ UnhideWhenUsed="false" Name="Colorful Shading"/ UnhideWhenUsed="false" Name="Colorful List"/ UnhideWhenUsed="false" Name="Colorful Grid"/ UnhideWhenUsed="false" Name="Light Shading Accent 1"/ UnhideWhenUsed="false" Name="Light List Accent 1"/ UnhideWhenUsed="false" Name="Light Grid Accent 1"/ UnhideWhenUsed="false" Name="Medium Shading 1 Accent 1"/ UnhideWhenUsed="false" Name="Medium Shading 2 Accent 1"/ UnhideWhenUsed="false" Name="Medium List 1 Accent 1"/ UnhideWhenUsed="false" QFormat="true" Name="List Paragraph"/ UnhideWhenUsed="false" QFormat="true" Name="Quote"/ UnhideWhenUsed="false" QFormat="true" Name="Intense Quote"/ UnhideWhenUsed="false" Name="Medium List 2 Accent 1"/ UnhideWhenUsed="false" Name="Medium Grid 1 Accent 1"/ UnhideWhenUsed="false" Name="Medium Grid 2 Accent 1"/ UnhideWhenUsed="false" Name="Medium Grid 3 Accent 1"/ UnhideWhenUsed="false" Name="Dark List Accent 1"/ UnhideWhenUsed="false" Name="Colorful Shading Accent 1"/ UnhideWhenUsed="false" Name="Colorful List Accent 1"/ UnhideWhenUsed="false" Name="Colorful Grid Accent 1"/ UnhideWhenUsed="false" Name="Light Shading Accent 2"/ UnhideWhenUsed="false" Name="Light List Accent 2"/ UnhideWhenUsed="false" Name="Light Grid Accent 2"/ UnhideWhenUsed="false" Name="Medium Shading 1 Accent 2"/ UnhideWhenUsed="false" Name="Medium Shading 2 Accent 2"/ UnhideWhenUsed="false" Name="Medium List 1 Accent 2"/ UnhideWhenUsed="false" Name="Medium List 2 Accent 2"/ UnhideWhenUsed="false" Name="Medium Grid 1 Accent 2"/ UnhideWhenUsed="false" Name="Medium Grid 2 Accent 2"/ UnhideWhenUsed="false" Name="Medium Grid 3 Accent 2"/ UnhideWhenUsed="false" Name="Dark List Accent 2"/ UnhideWhenUsed="false" Name="Colorful Shading Accent 2"/ UnhideWhenUsed="false" Name="Colorful List Accent 2"/ UnhideWhenUsed="false" Name="Colorful Grid Accent 2"/ UnhideWhenUsed="false" Name="Light Shading Accent 3"/ UnhideWhenUsed="false" Name="Light List Accent 3"/ UnhideWhenUsed="false" Name="Light Grid Accent 3"/ UnhideWhenUsed="false" Name="Medium Shading 1 Accent 3"/ UnhideWhenUsed="false" Name="Medium Shading 2 Accent 3"/ UnhideWhenUsed="false" Name="Medium List 1 Accent 3"/ UnhideWhenUsed="false" Name="Medium List 2 Accent 3"/ UnhideWhenUsed="false" Name="Medium Grid 1 Accent 3"/ UnhideWhenUsed="false" Name="Medium Grid 2 Accent 3"/ UnhideWhenUsed="false" Name="Medium Grid 3 Accent 3"/ UnhideWhenUsed="false" Name="Dark List Accent 3"/ UnhideWhenUsed="false" Name="Colorful Shading Accent 3"/ UnhideWhenUsed="false" Name="Colorful List Accent 3"/ UnhideWhenUsed="false" Name="Colorful Grid Accent 3"/ UnhideWhenUsed="false" Name="Light Shading Accent 4"/ UnhideWhenUsed="false" Name="Light List Accent 4"/ UnhideWhenUsed="false" Name="Light Grid Accent 4"/ UnhideWhenUsed="false" Name="Medium Shading 1 Accent 4"/ UnhideWhenUsed="false" Name="Medium Shading 2 Accent 4"/ UnhideWhenUsed="false" Name="Medium List 1 Accent 4"/ UnhideWhenUsed="false" Name="Medium List 2 Accent 4"/ UnhideWhenUsed="false" Name="Medium Grid 1 Accent 4"/ UnhideWhenUsed="false" Name="Medium Grid 2 Accent 4"/ UnhideWhenUsed="false" Name="Medium Grid 3 Accent 4"/ UnhideWhenUsed="false" Name="Dark List Accent 4"/ UnhideWhenUsed="false" Name="Colorful Shading Accent 4"/ UnhideWhenUsed="false" Name="Colorful List Accent 4"/ UnhideWhenUsed="false" Name="Colorful Grid Accent 4"/ UnhideWhenUsed="false" Name="Light Shading Accent 5"/ UnhideWhenUsed="false" Name="Light List Accent 5"/ UnhideWhenUsed="false" Name="Light Grid Accent 5"/ UnhideWhenUsed="false" Name="Medium Shading 1 Accent 5"/ UnhideWhenUsed="false" Name="Medium Shading 2 Accent 5"/ UnhideWhenUsed="false" Name="Medium List 1 Accent 5"/ UnhideWhenUsed="false" Name="Medium List 2 Accent 5"/ UnhideWhenUsed="false" Name="Medium Grid 1 Accent 5"/ UnhideWhenUsed="false" Name="Medium Grid 2 Accent 5"/ UnhideWhenUsed="false" Name="Medium Grid 3 Accent 5"/ UnhideWhenUsed="false" Name="Dark List Accent 5"/ UnhideWhenUsed="false" Name="Colorful Shading Accent 5"/ UnhideWhenUsed="false" Name="Colorful List Accent 5"/ UnhideWhenUsed="false" Name="Colorful Grid Accent 5"/ UnhideWhenUsed="false" Name="Light Shading Accent 6"/ UnhideWhenUsed="false" Name="Light List Accent 6"/ UnhideWhenUsed="false" Name="Light Grid Accent 6"/ UnhideWhenUsed="false" Name="Medium Shading 1 Accent 6"/ UnhideWhenUsed="false" Name="Medium Shading 2 Accent 6"/ UnhideWhenUsed="false" Name="Medium List 1 Accent 6"/ UnhideWhenUsed="false" Name="Medium List 2 Accent 6"/ UnhideWhenUsed="false" Name="Medium Grid 1 Accent 6"/ UnhideWhenUsed="false" Name="Medium Grid 2 Accent 6"/ UnhideWhenUsed="false" Name="Medium Grid 3 Accent 6"/ UnhideWhenUsed="false" Name="Dark List Accent 6"/ UnhideWhenUsed="false" Name="Colorful Shading Accent 6"/ UnhideWhenUsed="false" Name="Colorful List Accent 6"/ UnhideWhenUsed="false" Name="Colorful Grid Accent 6"/ UnhideWhenUsed="false" QFormat="true" Name="Subtle Emphasis"/ UnhideWhenUsed="false" QFormat="true" Name="Intense Emphasis"/ UnhideWhenUsed="false" QFormat="true" Name="Subtle Reference"/ UnhideWhenUsed="false" QFormat="true" Name="Intense Reference"/ UnhideWhenUsed="false" QFormat="true" Name="Book Title"/ /* Style Definitions */ table.MsoNormalTable {mso-style-name:????; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:10.5pt; mso-bidi-font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:??; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi; mso-font-kerning:1.0pt;} ??4: ???hang??????,??hang???????????????HM ??,????hang?????????????,??HM???????hang. 1. ??????????????????hang??,??:asm?????? 2. ????????????,??:TX?? 3. ???? 4. ???????????:???????“log file switch ”(?????????????????filesystem??????????HM????????,hang??????????)? ??,hang?HM???????,??HM?????????? ???HM???????,??????????????????,?????????oracle ???????,?????????crash???,HM???hang???,??????????????????"_hang_resolution_scope" ???,??????????off(???,????HM?????hang),process(??HM??????,??????????????),instance(??HM??????,??????????????????????????)? ??,????HM ????????trace ?????????? ??: _hang_resolution=TRUE ?? FALSE?????????HM????hang? _hang_resolution_scope=OFF,PORCESS?? INSTANCE?????????HM???????? _hang_detection= <number>? HM??hang?????,????30(?)? ??????????,???????????,??“Oracle 11g ??? – HM(Hang Manager)??"?

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  • adding a node to a linked list.

    - by sil3nt
    Hi there, ive been given the following code, And im just wondering, what does *&listpointer mean in the argument of the addnode function? struct Node { int accnumber; float balance; Node *next; }; Node *A, *B; int main() { A = NULL; B = NULL; AddNode(A, 123, 99.87); AddNode(B, 789, 52.64); } void AddNode(Node * & listpointer, int a, float b) { // add a new node to the FRONT of the list Node *temp; temp = new Node; temp->accnumber = a; temp->balance = b; temp->next = listpointer; listpointer = temp; }

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  • A linked list with multiple heads in Java

    - by Emile
    Hi, I have a list in which I'd like to keep several head pointers. I've tried to create multiple ListIterators on the same list but this forbid me to add new elements in my list... (see Concurrent Modification exception). I could create my own class but I'd rather use a built-in implementation ;) To be more specific, here is an inefficient implementation of two basic operations and the one wich doesn't work : class MyList <E { private int[] _heads; private List<E _l; public MyList ( int nbHeads ) { _heads = new int[nbHeads]; _l = new LinkedList<E(); } public void add ( E e ) { _l.add(e); } public E next ( int head ) { return _l.get(_heads[head++]); // ugly } } class MyList <E { private Vector<ListIterator<E _iters; private List<E _l; public MyList ( int nbHeads ) { _iters = new Vector<ListIterator<E(nbHeads); _l = new LinkedList<E(); for( ListIterator<E iter : _iters ) iter = _l.listIterator(); } public void add ( E e ) { _l.add(e); } public E next ( int head ) { // ConcurrentModificationException because of the add() return _iters.get(head).next(); } } Emile

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  • pointer and reference question (linked lists)

    - by sil3nt
    Hi there, I have the following code struct Node { int accnumber; float balance; Node *next; }; Node *A, *B; int main() { A = NULL; B = NULL; AddNode(A, 123, 99.87); AddNode(B, 789, 52.64); etc… } void AddNode(Node * & listpointer, int a, float b) { // add a new node to the FRONT of the list Node *temp; temp = new Node; temp->accnumber = a; temp->balance = b; temp->next = listpointer; listpointer = temp; } in this here void AddNode(Node * & listpointer, int a, float b) { what does *& listpointer mean exactly.

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  • Removing a node from a linked list

    - by lost_with_coding
    I would like to create a delete_node function that deletes the node at the location in the list as a count from the first node. So far this is the code I have: class node: def __init__(self): self.data = None # contains the data self.next = None # contains the reference to the next node class linked_list: def __init__(self): self.cur_node = None def add_node(self, data): new_node = node() # create a new node new_node.data = data new_node.next = self.cur_node # link the new node to the 'previous' node. self.cur_node = new_node # set the current node to the new one. def list_print(self): node = ll.cur_node while node: print node.data node = node.next def delete_node(self,location): node = ll.cur_node count = 0 while count != location: node = node.next count+=1 delete node ll = linked_list() ll.add_node(1) ll.add_node(2) ll.add_node(3) ll.list_print()

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  • Using list comprehension in Python to do something similar to zip()?

    - by jamieb
    I'm a Python newbie and one of the things I am trying to do is wrap my head around list comprehension. I can see that it's a pretty powerful feature that's worth learning. cities = ['Chicago', 'Detroit', 'Atlanta'] airports = ['ORD', 'DTW', 'ATL'] print zip(cities,airports) [('Chicago', 'ORD'), ('Detroit', 'DTW'), ('Atlanta', 'ATL')] How do I use list comprehension so I can get the results as a series of lists within a list, rather than a series of tuples within a list? [['Chicago', 'ORD'], ['Detroit', 'DTW'], ['Atlanta', 'ATL']] (I realize that dictionaries would probably be more appropriate in this situation, but I'm just trying to understand lists a bit better). Thanks!

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  • C# / this. and List<T>

    - by user3533030
    I am having trouble understanding how to initialize a List of objects and use it with methods inside of a class. I understand the mechanics of the List, but not how to initialize it inside a method and use it later. For example, I want to have a class that creates the List when it is constructed. Then, I want to use a method of that class to add elements to the list. The elements in the list are objects defined by the SolidWorks API. So, to construct the List, I used... public class ExportPoints : Exporter { public List<SldWorks.SketchPoint> listOfSketchPoints; public ExportPoints(SldWorks.SldWorks swApp, string nameSuffix) : base(swApp, nameSuffix) { List<SldWorks.SketchPoint> listOfSketchPoints = new List<SldWorks.SketchPoint>(); } public void createListOfFreePoints() { try { [imagine more code here] this.listOfSketchPoints.Add(pointTest); } catch (Exception e) { Debug.Print(e.ToString()); return; } } This fails during execution as if the listOfSketchPoints was never initialized as a List. So, I tried a hack and this worked: public ExportPoints(SldWorks.SldWorks swApp, string nameSuffix) : base(swApp, nameSuffix) { List<SldWorks.SketchPoint> listOfSketchPoints = new List<SldWorks.SketchPoint>(); this.listOfSketchPoints = listOfSketchPoints; } This approach creates the behavior that I want. However, it seems that I lack some understanding as to why this is necessary. Shouldn't it be possible to "initialize" a List that is a property of your object with a constructor? Why would you need to create the list, then assign the pointer of that new List to your property?

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  • .NET List Thread-Safe Implementation Suggestion needed

    - by Bamboo
    .Net List class isn't thread safe. I hope to achieve the minimal lock needed and yet still fulfilling the requirement such that as for reading, phantom record is allowed, and for writing, they must be thread-safe so there won't be any lost updates. So I have something like public static List<string> list = new List<string>(); In Methods that have **List.Add**/**List.Remove** , I always lock to assure thread safety lock (lockHelper) { list.Add(obj); or list.Remove(obj); } In Methods that requires **List Reading** I don't care about phantom record so I go ahead to read without any locking. In this case. Return a bool by checking whether a string had been added. if (list.Count() != 0) { return list.Contains("some string") } All I did was locking write accesses, and allow read accesses to go through without any locking. Is my thread safety idea valid? I understand there is List size expansion. Will it be ok? My guess is that when a List is expanding, it may uses a temp. list. This is ok becasue the temp list size will always have a boundary, and .Net class is well implemented, ie. there shouldn't be any indexOutOfBound or circular reference problems when reading was caught in updates.

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  • Why is this removing all elements from my LinkedList?

    - by Brian
    Why is my remove method removing every element from my Doubly Linked List? If I take out that if/else statements then I can successfully remove middle elements, but elements at the head or tail of the list still remain. However, I added the if/else statements to take care of elements at the head and tail, unfortunately this method now removes every element in my list. What am I do wrong? public void remove(int n) { LinkEntry<E> remove_this = new LinkEntry<E>(); //if nothing comes before remove_this, set the head to equal the element after remove_this if (remove_this.previous == null) head = remove_this.next; //otherwise set the element before remove_this equal to the element after remove_this else remove_this.previous.next = remove_this.next; //if nothing comes after remove_this, set the tail equal to the element before remove_this if (remove_this.next == null) tail = remove_this.previous; //otherwise set the next element's previous pointer to the element before remove_this else remove_this.next.previous = remove_this.previous; //if remove_this is located in the middle of the list, enter this loop until it is //found, then remove it, closing the gap afterwards. int i = 0; for (remove_this = head; remove_this != null; remove_this = remove_this.next) { //if i == n, stop and delete 'remove_this' from the list if (i == n) { //set the previous element's next to the element that comes after remove_this remove_this.previous.next = remove_this.next; //set the element after remove_this' previous pointer to the element before remove_this remove_this.next.previous = remove_this.previous; break; } //if i != n, keep iterating through the list i++; } }

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  • EM12c: Using the LIST verb in emcli

    - by SubinDaniVarughese
    Many of us who use EM CLI to write scripts and automate our daily tasks should not miss out on the new list verb released with Oracle Enterprise Manager 12.1.0.3.0. The combination of list and Jython based scripting support in EM CLI makes it easier to achieve automation for complex tasks with just a few lines of code. Before I jump into a script, let me highlight the key attributes of the list verb and why it’s simply excellent! 1. Multiple resources under a single verb:A resource can be set of users or targets, etc. Using the list verb, you can retrieve information about a resource from the repository database.Here is an example which retrieves the list of administrators within EM.Standard mode$ emcli list -resource="Administrators" Interactive modeemcli>list(resource="Administrators")The output will be the same as standard mode.Standard mode$ emcli @myAdmin.pyEnter password :  ******The output will be the same as standard mode.Contents of myAdmin.py scriptlogin()print list(resource="Administrators",jsonout=False).out()To get a list of all available resources use$ emcli list -helpWith every release of EM, more resources are being added to the list verb. If you have a resource which you feel would be valuable then go ahead and contact Oracle Support to log an enhancement request with product development. Be sure to say how the resource is going to help improve your daily tasks. 2. Consistent Formatting:It is possible to format the output of any resource consistently using these options:  –column  This option is used to specify which columns should be shown in the output. Here is an example which shows the list of administrators and their account status$ emcli list -resource="Administrators" -columns="USER_NAME,REPOS_ACCOUNT_STATUS" To get a list of columns in a resource use:$ emcli list -resource="Administrators" -help You can also specify the width of the each column. For example, here the column width of user_type is set to 20 and department to 30. $ emcli list -resource=Administrators -columns="USER_NAME,USER_TYPE:20,COST_CENTER,CONTACT,DEPARTMENT:30"This is useful if your terminal is too small or you need to fine tune a list of specific columns for your quick use or improved readability.  –colsize  This option is used to resize column widths.Here is the same example as above, but using -colsize to define the width of user_type to 20 and department to 30.$ emcli list -resource=Administrators -columns="USER_NAME,USER_TYPE,COST_CENTER,CONTACT,DEPARTMENT" -colsize="USER_TYPE:20,DEPARTMENT:30" The existing standard EMCLI formatting options are also available in list verb. They are: -format="name:pretty" | -format="name:script” | -format="name:csv" | -noheader | -scriptThere are so many uses depending on your needs. Have a look at the resources and columns in each resource. Refer to the EMCLI book in EM documentation for more information.3. Search:Using the -search option in the list verb makes it is possible to search for a specific row in a specific column within a resource. This is similar to the sqlplus where clause. The following operators are supported:           =           !=           >           <           >=           <=           like           is (Must be followed by null or not null)Here is an example which searches for all EM administrators in the marketing department located in the USA.$emcli list -resource="Administrators" -search="DEPARTMENT ='Marketing'" -search="LOCATION='USA'" Here is another example which shows all the named credentials created since a specific date.  $emcli list -resource=NamedCredentials -search="CredCreatedDate > '11-Nov-2013 12:37:20 PM'"Note that the timestamp has to be in the format DD-MON-YYYY HH:MI:SS AM/PM Some resources need a bind variable to be passed to get output. A bind variable is created in the resource and then referenced in the command. For example, this command will list all the default preferred credentials for target type oracle_database.Here is an example$ emcli list -resource="PreferredCredentialsDefault" -bind="TargetType='oracle_database'" -colsize="SetName:15,TargetType:15" You can provide multiple bind variables. To verify if a column is searchable or requires a bind variable, use the –help option. Here is an example:$ emcli list -resource="PreferredCredentialsDefault" -help 4. Secure accessWhen list verb collects the data, it only displays content for which the administrator currently logged into emcli, has access. For example consider this usecase:AdminA has access only to TargetA. AdminA logs into EM CLIExecuting the list verb to get the list of all targets will only show TargetA.5. User defined SQLUsing the –sql option, user defined sql can be executed. The SQL provided in the -sql option is executed as the EM user MGMT_VIEW, which has read-only access to the EM published MGMT$ database views in the SYSMAN schema. To get the list of EM published MGMT$ database views, go to the Extensibility Programmer's Reference book in EM documentation. There is a chapter about Using Management Repository Views. It’s always recommended to reference the documentation for the supported MGMT$ database views.  Consider you are using the MGMT$ABC view which is not in the chapter. During upgrade, it is possible, since the view was not in the book and not supported, it is likely the view might undergo a change in its structure or the data in it. Using a supported view ensures that your scripts using -sql will continue working after upgrade.Here’s an example  $ emcli list -sql='select * from mgmt$target' 6. JSON output support    JSON (JavaScript Object Notation) enables data to be displayed in a collection of name/value pairs. There is lot of reading material about JSON on line for more information.As an example, we had a requirement where an EM administrator had many 11.2 databases in their test environment and the developers had requested an Administrator to change the lifecycle status from Test to Production which meant the admin had to go to the EM “All targets” page and identify the set of 11.2 databases and then to go into each target database page and manually changes the property to Production. Sounds easy to say, but this Administrator had numerous targets and this task is repeated for every release cycle.We told him there is an easier way to do this with a script and he can reuse the script whenever anyone wanted to change a set of targets to a different Lifecycle status. Here is a jython script which uses list and JSON to change all 11.2 database target’s LifeCycle Property value.If you are new to scripting and Jython, I would suggest visiting the basic chapters in any Jython tutorials. Understanding Jython is important to write the logic depending on your usecase.If you are already writing scripts like perl or shell or know a programming language like java, then you can easily understand the logic.Disclaimer: The scripts in this post are subject to the Oracle Terms of Use located here.  1 from emcli import *  2  search_list = ['PROPERTY_NAME=\'DBVersion\'','TARGET_TYPE= \'oracle_database\'','PROPERTY_VALUE LIKE \'11.2%\'']  3 if len(sys.argv) == 2:  4    print login(username=sys.argv[0])  5    l_prop_val_to_set = sys.argv[1]  6      l_targets = list(resource="TargetProperties", search=search_list,   columns="TARGET_NAME,TARGET_TYPE,PROPERTY_NAME")  7    for target in l_targets.out()['data']:  8       t_pn = 'LifeCycle Status'  9      print "INFO: Setting Property name " + t_pn + " to value " +       l_prop_val_to_set + " for " + target['TARGET_NAME']  10      print  set_target_property_value(property_records=      target['TARGET_NAME']+":"+target['TARGET_TYPE']+":"+      t_pn+":"+l_prop_val_to_set)  11  else:  12   print "\n ERROR: Property value argument is missing"  13   print "\n INFO: Format to run this file is filename.py <username>   <Database Target LifeCycle Status Property Value>" You can download the script from here. I could not upload the file with .py extension so you need to rename the file to myScript.py before executing it using emcli.A line by line explanation for beginners: Line  1 Imports the emcli verbs as functions  2 search_list is a variable to pass to the search option in list verb. I am using escape character for the single quotes. In list verb to pass more than one value for the same option, you should define as above comma separated values, surrounded by square brackets.  3 This is an “if” condition to ensure the user does provide two arguments with the script, else in line #15, it prints an error message.  4 Logging into EM. You can remove this if you have setup emcli with autologin. For more details about setup and autologin, please go the EM CLI book in EM documentation.  5 l_prop_val_to_set is another variable. This is the property value to be set. Remember we are changing the value from Test to Production. The benefit of this variable is you can reuse the script to change the property value from and to any other values.  6 Here the output of the list verb is stored in l_targets. In the list verb I am passing the resource as TargetProperties, search as the search_list variable and I only need these three columns – target_name, target_type and property_name. I don’t need the other columns for my task.  7 This is a for loop. The data in l_targets is available in JSON format. Using the for loop, each pair will now be available in the ‘target’ variable.  8 t_pn is the “LifeCycle Status” variable. If required, I can have this also as an input and then use my script to change any target property. In this example, I just wanted to change the “LifeCycle Status”.  9 This a message informing the user the script is setting the property value for dbxyz.  10 This line shows the set_target_property_value verb which sets the value using the property_records option. Once it is set for a target pair, it moves to the next one. In my example, I am just showing three dbs, but the real use is when you have 20 or 50 targets. The script is executed as:$ emcli @myScript.py subin Production The recommendation is to first test the scripts before running it on a production system. We tested on a small set of targets and optimizing the script for fewer lines of code and better messaging.For your quick reference, the resources available in Enterprise Manager 12.1.0.4.0 with list verb are:$ emcli list -helpWatch this space for more blog posts using the list verb and EM CLI Scripting use cases. I hope you enjoyed reading this blog post and it has helped you gain more information about the list verb. Happy Scripting!!Disclaimer: The scripts in this post are subject to the Oracle Terms of Use located here. Stay Connected: Twitter | Facebook | YouTube | Linkedin | Newsletter mt=8">Download the Oracle Enterprise Manager 12c Mobile app

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  • How to set position for a linear-gradient background in css3

    - by Virender Sehwag
    I am trying to set the position (that is, margin or padding from top) of body tag's linear background with image. My code is background-image: linear-gradient(to bottom, rgba(255, 255, 255, 0), rgba(255, 255, 255, 0), rgba(0, 0, 0, 0.9), rgb(0, 0, 0)), url("g2hd.jpg"); background-repeat: repeat, no-repeat; background-attachment: fixed; background-position: 0% 30px, center center; but 30px is not working but it works for normal for background-image:url("g2hd.jpg"); any idea

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  • Double Linked List Insertion Sorting Bug

    - by house
    Hello, I have implemented an insertion sort in a double link list (highest to lowest) from a file of 10,000 ints, and output to file in reverse order. To my knowledge I have implemented such a program, however I noticed in the ouput file, a single number is out of place. Every other number is in correct order. The number out of place is a repeated number, but the other repeats of this number are in correct order. Its just strange how this number is incorrectly placed. Also the unsorted number is only 6 places out of sync. I have looked through my program for days now with no idea where the problem lies, so I turn to you for help. Below is the code in question, (side note: can my question be deleted by myself? rather my colleges dont thieve my code, if not how can it be deleted?) void DLLIntStorage::insertBefore(int inValue, node *nodeB) { node *newNode; newNode = new node(); newNode->prev = nodeB->prev; newNode->next = nodeB; newNode->value = inValue; if(nodeB->prev==NULL) { this->front = newNode; } else { nodeB->prev->next = newNode; } nodeB->prev = newNode; } void DLLIntStorage::insertAfter(int inValue, node *nodeB) { node *newNode; newNode = new node(); newNode->next = nodeB->next; newNode->prev = nodeB; newNode->value = inValue; if(nodeB->next == NULL) { this->back = newNode; } else { nodeB->next->prev = newNode; } nodeB->next = newNode; } void DLLIntStorage::insertFront(int inValue) { node *newNode; if(this->front == NULL) { newNode = new node(); this->front = newNode; this->back = newNode; newNode->prev = NULL; newNode->next = NULL; newNode->value = inValue; } else { insertBefore(inValue, this->front); } } void DLLIntStorage::insertBack(int inValue) { if(this->back == NULL) { insertFront(inValue); } else { insertAfter(inValue, this->back); } } ifstream& operator>> (ifstream &in, DLLIntStorage &obj) { int readInt, counter = 0; while(!in.eof()) { if(counter==dataLength) //stops at 10,000 { break; } in >> readInt; if(obj.front != NULL ) { obj.insertion(readInt); } else { obj.insertBack(readInt); } counter++; } return in; } void DLLIntStorage::insertion(int inValue) { node* temp; temp = this->front; if(temp->value >= inValue) { insertFront(inValue); return; } else { while(temp->next!=NULL && temp!=this->back) { if(temp->value >= inValue) { insertBefore(inValue, temp); return; } temp = temp->next; } } if(temp == this->back) { insertBack(inValue); } } Thankyou for your time.

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  • Efficient list compacting

    - by Patrik
    Suppose you have a list of unsigned ints. Suppose some elements are equal to 0 and you want to push them back. Currently I use this code (list is a pointer to a list of unsigned ints of size n for (i = 0; i < n; ++i) { if (list[i]) continue; int j; for (j = i + 1; j < n && !list[j]; ++j); int z; for (z = j + 1; z < n && list[z]; ++z); if (j == n) break; memmove(&(list[i]), &(list[j]), sizeof(unsigned int) * (z - j))); int s = z - j + i; for(j = s; j < z; ++j) list[j] = 0; i = s - 1; } Can you think of a more efficient way to perform this task? The snippet is purely theoretical, in the production code, each element of list is a 64 bytes struct EDIT: I'll post my solution. Many thanks to Jonathan Leffler. void RemoveDeadParticles(int * list, int * n) { int i, j = *n - 1; for (; j >= 0 && list[j] == 0; --j); for (i = 0; i < j; ++i) { if (list[i]) continue; memcpy(&(list[i]), &(list[j]), sizeof(int)); list[j] = 0; for (; j >= 0 && list[j] == 0; --j); if (i == j) break; } *n = i + 1; }

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  • this is my first time asking here, I wanted to create a linked list while sorting it thanks

    - by user2738718
    package practise; public class Node { // node contains data and next public int data; public Node next; //constructor public Node (int data, Node next){ this.data = data; this.next = next; } //list insert method public void insert(Node list, int s){ //case 1 if only one element in the list if(list.next == null && list.data > s) { Node T = new Node(s,list); } else if(list.next == null && list.data < s) { Node T = new Node(s,null); list.next = T; } //case 2 if more than 1 element in the list // 3 elements present I set prev to null and curr to list then performed while loop if(list.next.next != null) { Node curr = list; Node prev = null; while(curr != null) { prev = curr; curr = curr.next; if(curr.data > s && prev.data < s){ Node T = new Node(s,curr); prev.next = T; } } // case 3 at the end checks for the data if(prev.data < s){ Node T = new Node(s,null); prev.next = T; } } } } // this is a hw problem, i created the insert method so i can check and place it in the correct order so my list is sorted This is how far I got, please correct me if I am wrong, I keep inserting node in the main method, Node root = new Node(); and root.insert() to add.

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  • Is this good code? Linked List Stack Implementation

    - by Quik Tester
    I have used the following code for a stack implementation. The top keeps track of the topmost node of the stack. Now since top is a data member of the node function, each node created will have a top member, which ideally we wouldn't want. Firstly, is this good approach to coding? Secondly, will making top as static make it a better coding practice? Or should I have a global declaration of top? #include<iostream> using namespace std; class node { int data; node *top; node *link; public: node() { top=NULL; link=NULL; } void push(int x) { node *n=new node; n->data=x; n->link=top; top=n; cout<<"Pushed "<<n->data<<endl; } void pop() { node *n=new node; n=top; top=top->link; n->link=NULL; cout<<"Popped "<<n->data<<endl; delete n; } void print() { node *n=new node; n=top; while(n!=NULL) { cout<<n->data<<endl; n=n->link; } delete n; } }; int main() { node stack; stack.push(5); stack.push(7); stack.push(9); stack.pop(); stack.print(); } Any other suggestions welcome. I have also seen codes where there are two classes, where the second one has the top member. What about this? Thanks. :)

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  • List of registered domain names

    - by Eric Chang
    Where can I find a list of domain names that I can download in a text file? I looked around and I found many sites with lists of expired domain names or domain names that will expire soon, but that's not what I need, I need a list of CURRENTLY REGISTERED domain names. The closest I found was this site (hxxp://www.list-of-domains.org/), but what I'm looking for ideally is just a plain list of registered domains and not some web links split across many pages full with ads and no text file. I know it's possible, after all how do these sites get the list of domains that they use? Where can I find such a list?

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