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  • View an item without republishing everything?

    - by Jesse Millikan
    I'm getting this error when trying to view a Sitecore item based on a template that contains nothing but one sublayout played in a placeholder in another layout. I can place the sublayout in other sublayouts and view it on another item, and I can preview the item, but when I go to view that item I get this: The layout for the requested document was not found. [blah blah blah] Requested Layout: {00000000-0000-0000-0000-000000000000} [blah blah blah some more] The only way I've found to view the new item is to do a "Publish Site" from the Publish tab. Is there a way to get that one item working without republishing everything?

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  • Model Fit of Binary GLM with more than 1 or 2 predictors

    - by Salmo salar
    I am trying to predict a binary GLM with multiple predictors. I can do it fine with one predictor variable however struggle when I use multiple Sample data: structure(list(attempt = structure(c(1L, 2L, 1L, 2L, 1L, 1L, 1L, 2L, 1L, 2L, 1L, 1L, 1L, 2L, 1L, 2L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 1L, 2L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 2L, 1L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 2L, 1L, 1L, 2L, 1L, 2L, 1L, 1L, 2L, 1L, 2L), .Label = c("1", "2"), class = "factor"), searchtime = c(137, 90, 164, 32, 39, 30, 197, 308, 172, 48, 867, 117, 63, 1345, 38, 122, 226, 397, 0, 106, 259, 220, 170, 102, 46, 327, 8, 10, 23, 108, 315, 318, 70, 646, 69, 97, 117, 45, 31, 64, 125, 17, 240, 63, 549, 1651, 233, 406, 334, 168, 127, 47, 881), mean.search.flow = c(15.97766667, 14.226, 17.15724762, 14.7465, 39.579, 23.355, 110.2926923, 71.95709524, 72.73666667, 32.37466667, 50.34905172, 27.98471429, 49.244, 109.1759778, 77.71733333, 37.446875, 101.23875, 67.78534615, 21.359, 36.54257143, 34.13961111, 64.35253333, 80.98554545, 61.50857143, 48.983, 63.81072727, 26.105, 46.783, 23.0605, 33.61557143, 46.31042857, 62.37061905, 12.565, 42.31983721, 15.3982, 14.49625, 23.77425, 25.626, 74.62485714, 170.1547778, 50.67125, 48.098, 66.83644444, 76.564875, 80.63189189, 136.0573243, 136.3484, 86.68688889, 34.82169565, 70.00415385, 64.67233333, 81.72766667, 57.74522034), Pass = structure(c(1L, 2L, 1L, 2L, 2L, 2L, 1L, 1L, 1L, 2L, 2L, 2L, 1L, 2L, 1L, 2L, 1L, 2L, 2L, 2L, 2L, 1L, 1L, 1L, 2L, 2L, 1L, 2L, 2L, 2L, 2L, 2L, 1L, 2L, 1L, 1L, 2L, 1L, 1L, 1L, 2L, 1L, 2L, 2L, 1L, 2L, 1L, 2L, 2L, 1L, 2L, 1L, 2L), .Label = c("0", "1"), class = "factor")), .Names = c("attempt", "searchtime", "mean.search.flow", "Pass"), class = "data.frame", row.names = c(1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 20L, 21L, 22L, 23L, 24L, 25L, 26L, 28L, 29L, 30L, 31L, 32L, 33L, 34L, 35L, 36L, 37L, 38L, 39L, 40L, 50L, 51L, 53L, 54L, 60L, 61L, 62L, 63L, 64L, 65L, 66L, 67L, 68L, 69L, 70L, 71L, 72L)) First model with single predictor M2 <- glm(Pass ~ searchtime, data = DF3, family = binomial) summary(M2) drop1(M2, test = "Chi") Plot works fine P1 <- predict(M2, newdata = MyData, type = "link", se = TRUE) plot(x=MyData$searchtime, exp(P1$fit) / (1+exp(P1$fit)), type = "l", ylim = c(0,1), xlab = "search time", ylab = "pobability of passage") lines(MyData$searchtime, exp(P1$fit+1.96*P1$se.fit)/ (1 + exp(P1$fit + 1.96 * P1$se.fit)), lty = 2) lines(MyData$searchtime, exp(P1$fit-1.96*P1$se.fit)/ (1 + exp(P1$fit - 1.96 * P1$se.fit)), lty = 2) points(DF3$searchtime, DF3$Search.and.pass) Second model M2a <- glm(Pass ~ searchtime + mean.search.flow+ attempt, data = DF3, family = binomial) summary(M2a) drop1(M2a, test = "Chi") How do I plot this with "dummy" data? I have tried along the lines of Model.matrix and expand.grid, as you would do with glmer, but fail straight away due to the two categorical variables along with factor(attempt)

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  • UISplitViewController Cannot Change the Master View Controller?

    - by Nex
    I am trying to change the master view controller (that appears in the popover in portrait, and on the left side in landscape) in a UISplitViewController. I'd like to switch between the master view controller being one of two different UIViewControllers (depending on an action taken elsewhere in my application). I am using the following: mySplitViewController.viewControllers = [NSArray arrayWithObjects:newMasterController, detailController, nil]; This correctly changes the master viewcontroller as you would expect in landscape mode. However it does not seem to change the viewcontroller used for the popover in portrait mode. I notice that the barbuttonitem to show this master view controller is just calling showMasterInPopover: on the splitviewcontroller, and so would expect it to work in portrait mode as well, but it does not. In fact, I can set the master view controller, see the new viewController correctly in landscape mode, rotate back to portrait, and the viewcontroller used in the popover is still the old one. Is this a bug?

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  • redirectToAction results in null model

    - by Maslow
    I have 2 actions on a controller: public class CalculatorsController : Controller { // // GET: /Calculators/ public ActionResult Index() { return RedirectToAction("Accounting"); } public ActionResult Accounting() { var combatants = Models.Persistence.InMemoryCombatantPersistence.GetCombatants(); Debug.Assert(combatants != null); var bvm = new BalanceViewModel(combatants); Debug.Assert(bvm!=null); Debug.Assert(bvm.Combatants != null); return View(bvm); } } When the Index method is called, I get a null model coming out. When the Accounting method is called directly via it's url, I get a hydrated model.

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  • A view "transparent" to touches in some areas

    - by Mike
    I have this transparent view that covers the whole screen. I using this view to group objects because I need to run them together around a specific anchor point. Lets call this view transparentView. At some point, transparentView contains two subviews. Two vertical bars full of icons, one on the left and one on the right of the screen. I need these bars and their icons to respond to touches, so I have to set transparentView setUserInteraction to YES. The area between the two vertical bars are totally transparent. transparentView is on top of other views and I need these other views to respond to taps but, the transparent area of transparentView are intercepting the taps and not letting them go thru to the view below. This transparent view is a UIImageView based class. I have tried to forward taps on that class, using - (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event { [self.nextResponder touchesBegan: touches withEvent:event]; } - (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event { [self.nextResponder touchesMoved: touches withEvent:event]; } - (void)touchesEnded:(NSSet *)touches withEvent:(UIEvent *)event { [self.nextResponder touchesEnded: touches withEvent:event]; } - (void)touchesCancelled:(NSSet *)touches withEvent:(UIEvent *)event { [self touchesEnded:touches withEvent:event]; } but this is not working. How can I do that? thanks.

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  • Displaying an NSString on a Custom View

    - by ilovetacos
    I have an interface that has an NSTextField, NSButton, and an NSView. When I type something in the textfield and press the button, I want the text to be drawn in the NSView. So far I have everything connected and working, except for the view. How can I connect the text and the view so that every time I press the button, the text is drawn to the view?

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  • Email as a view.

    - by Hal
    I've been in some discussion recently about where email (notifications, etc...) should be sent in an ASP.NET MVC application. My nemesis grin argues that it only makes sense that the email should be sent from the controller. I argue that an email is simply an alternate or augmented view through a different channel. Much like I would download a file as the payload of an ActionResult, the email is simply delivered through a different protocol. I've worked an extension method that allows me to do the following: <% Html.RenderEmail(model.FromAddress, model.ToAddress, model.Subject); %> which I actually include within my the view that is displayed on the screen. The beauty is that, based on convention, if I call RenderEmail from a parent view named MyView.ascx, I attempt to render the contents of a view named MyViewEmail.ascx, unless it is not found, in which case I simply email a copy of parent view. It certainly does make it testable (I still have an ISMTPService injected for testing), I wondered if anyone had any thoughts on whether or not this breaks from good practice. In use it has been extremely handy when we needed to easily send an email or modify the contents of the emailed results vs the browser rendered results. Thanks, Hal

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  • Problem Using Partial View In for each loop

    - by leen3o
    I'm a little confused here, I am trying use a partial view in a for each loop like so <% foreach (var item in (IEnumerable<MVCLD.Models.Article>)ViewData["LatestWebsites"]){%> <% Html.RenderPartial("articlelisttemaple", item); %> <% } %> And my partial view looks like this <div class="listingholders"> <h4><%=Html.ActionLink(item.ArticleTitle, "details", "article", new { UrlID = item.UrlID, ArticleName = item.ArticleTitle.ToString().niceurl() }, null)%> </h4> <p><%= Html.Encode(item.ArticleSnippet) %></p> <div class="clearer">&nbsp;</div> </div> But when I run the project I get told the partial view doesn't understand what item is?? CS0103: The name 'item' does not exist in the current context I can't see why it would be doing this as I'm passing item into the partial view?

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  • Unobtrusive Client Validation without accepting model

    - by user1010609
    I have simple form like this which accepts only two values string action and editText.Is there a way to enable Unobtrusive Client Validation on this without Data Annotations? Or do I have to accept model and use Data Annotations? I just need it to make sure editText is atleast 5 chars long. @using (Ajax.BeginForm("Action", "Controller", null, new AjaxOptions { OnFailure = "error", UpdateTargetId = "Pcedit" + @Model.ID})) { <textarea rows="3" cols="2" name="editText" style="width:100%;"></textarea> <br /> <input type="submit" name="action" value="Save"/> <input type="submit" name="action" value="Cancel"/> }

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  • How to update the filename of a Django's FileField instance ?

    - by pierre-guillaume-degans
    Hello, Here a simple django model: class SomeModel(models.Model): title = models.CharField(max_length=100) video = models.FileField(upload_to='video') I would like to save any instance so that the video's file name would be a valid file name of the title. For example, in the admin interface, I load a new instance with title "Lorem ipsum" and a video called "video.avi". The copy of the file on the server should be "Lorem Ipsum.avi" (or "Lorem_Ipsum.avi"). Thank you :)

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  • Change table view ( style grouped ) background color ?

    - by Madhup
    Hi all, I am developing an iPad application in which I need a table view ( style grouped ) having background color as clearColor. My problem is [self.tableView setBackgroundColor:[UIColor clearColor]]; works well if the table view style is plain but when I switch to group table view the background color does not changes it stays gray in color. FYI: the contentview background color of tableviewcell also does not change. Is this a bug in iPhone-sdk or I am doing something wrong. Thanks, Madhup

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  • Defining a dd/mm/yyyy field within an abstract table model

    - by Simon Andi
    I have defined an abstract table model but one of the columns should house date values as dd/mm/yyyy format not sure how to do this. I have a external global file and have hard coded the dates as dd/mm/yyyy. How can I define this column within my abstract table model so that to only allow only dates having dd/mm/yyyy format. public class OptraderGlobalParameters { public static boolean DEBUG = true; //Set DEBUG = true for Debugging /*=========================*/ /*Table Array For Dividends*/ /*=========================*/ public static String[] columnNames = {"Date", "Dividend", "Actual", "Yield (%)" }; public static Object[][] data = { {"dd/mm/yyyy", new Double(5), new Boolean(false), new Boolean(false)}, {"dd/mm/yyyy", new Double(5), new Boolean(false), new Boolean(false)}, {"dd/mm/yyyy", new Double(5), new Boolean(false), new Boolean(false)}, {"dd/mm/yyyy", new Double(5), new Boolean(false), new Boolean(false)}, {"dd/mm/yyyy", new Double(5), new Boolean(false), new Boolean(false)}, }; }

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  • uiButton should always be as top view in iPhone

    - by suse
    hello, i have a UIView UIImageview UIButton and UISlider added as subview to UIView example: [view addsubview:uiImageview_obj]; [view addsubview:uiButtonview_obj]; [view addsubview:uiSliderview_obj]; When i zoom the uiimageview_obj, it covers uislider and uibutton also, hence i cannot use uislider and uibutton when i zoom the image. So please tell me how to make uislider and uibutton to be always on top? Thank you in advance.

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  • My 3D object (opengl es) is disappearing behind the iPhone camera view

    - by KLC
    I have an augmented reality iPhone app that I am converting from Core Animation to OpenGL ES 1.1. I have added code that has been modified from the Apple OpenGL template. My problem is that my 3D object , when translating along the negative Z-axis (away from the user), appears to disappear into the camera view, until its completely gone. I have experimented with several solutions, but to no avail. What I have determined: Using the 3D icosahedron from Jeff Lamarche's blog here, the object starts it at 0,0,0 and then translates with decreasing z coordinates. By the time the z value reaches -2.0f, the object is gone. It appears as if it is disappearing behind the camera view. This is how I set my frustrum & viewport (unchanged from Apple's code) glMatrixMode(GL_PROJECTION); size = zNear * tanf(DEGREES_TO_RADIANS(fieldOfView) / 2.0); //Grab the size of the screen CGRect rect = self.bounds; glFrustumf(-size, size, -size / (rect.size.width / rect.size.height), size / (rect.size.width / rect.size.height), zNear, zFar); glViewport(0, 0, rect.size.width, rect.size.height); glMatrixMode(GL_MODELVIEW); glLoadIdentity(); What I have tried: The camera view is the main view and several other views are added to it as subviews, including the openGLView. I have commented those views out for test purposes. I have applied CATransforms to move the openGLView in the z direction -500 and +500, and done the same to the camera view. I have also changed the zFar in the above code to 1.0f, and it still disappears at z position of -2.0, which doesn't make sense (shouldn't it disappear at z=1.0?) My experimentation has got me more confused than when I started ( which usually means I am missing a key piece, but I can't figure out what). Thanks for your help.

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  • user model password field default password field in django

    - by imran-glt
    Hi, I've created a custom user model in my application. This user model is working fine, but there are a couple of problems I have with it. 1) The change password link in the my register.html page doesn't work? 2) The default password box on the add/edit page for a user is a little unfriendly. Ideally, what I'd like is the two password fields from the change password form on the add/edit user form in the admin, which will automatically turn convert the entered password into a valid encrypted password in Django. This would make the admin system MUCH friendlier and much more suited to my needs, as a fair number of user accounts will be created and maintained manually in this app, and the person responsible for doing so will likely be scared off at the sight of that admin field, or just type a clear text password and wonder why it doesn't work. Is this possible / How do I do this?

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  • How to get iPhone, not iPad view in Interface Builder

    - by dbonneville
    At first, I was not able to build a new blank project to iPhone using the new XCode 3.2 beta. I edited the project settings and was able to build the blank app to iPhone simulator. However, when I open the nib for the project in IB and click the view, it opens an iPad size view. How do I get the right sized view to work on in IB?

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  • Ruby on Rails: reducing complexity of parameters in a RESTFul HTTP POST request (multi-model)

    - by randombits
    I'm using cURL to test a RESTFul HTTP web service. The problem is I'm normally submitting a bunch of values normally like this: curl -d "firstname=bob&lastname=smith&age=25&from=kansas&someothermodelattr=val" -H "Content-Type: application/x-www-form-urlencoded" http://mysite/people.xml -i The problem with this is my controller will then have code like this: unless params[:firstname].nil? end unless params[:lastname].nil? end // FINALLY @person = People.new(params[:firstname], params[:lastname], params[:age], params[:from]) etc.. What's the best way to simplify this? My Person model has all the validations it needs. Is there a way (assuming the request has multi-model parameters) that I can just do: @person = People.new(params[:person]) and then the initializer can take care of the rest?

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  • Django - transactions in the model?

    - by orokusaki
    Models (disregard typos / minor syntax issues. It's just pseudo-code): class SecretModel(models.Model): some_unique_field = models.CharField(max_length=25, unique=True) # Notice this is unique. class MyModel(models.Model): secret_model = models.OneToOneField(SecretModel, editable=False) # Not in the form spam = models.CharField(max_length=15) foo = models.IntegerField() def clean(self): SecretModel.objects.create(some_unique_field=self.spam) Now if I go do this: MyModel.objects.create(spam='john', foo='OOPS') # Obviously foo won't take "OOPS" as it's an IntegerField. #.... ERROR HERE MyModel.objects.create(spam='john', foo=5) # So I try again here. #... IntegrityError because SecretModel with some_unique_field = 'john' already exists. I understand that I could put this into a view with a request transaction around it, but I want this to work in the Admin, and via an API, etc. Not just with forms, or views. How is it possible?

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  • filter some data(row) in zend view

    - by Behrang
    I have 1.Table:user(userId,userName,userGroup) 2.Model:userModel 3.usercontroller there i a simple code: Controller: class UserController extends Zend_Controller_Action { public function getuser() { $userModel = new userModel(); $this-view-usergroup = $userModel; } } Model: class Model_UserGroupModel extends Zend_Db_Table_Abstract { public function getuser( { $select = $this-select(); return $this-fetchAll($select); } } view: please tell me what code I must insert in view to only have user with specific row like user with group teacher also i use partialoop???

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