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  • Increment number in string

    - by iform
    Hi, I am stumped... I am trying to get the following output until a certain condition is met. test_1.jpg test_2.jpg .. test_50.jpg The solution (if you could remotely call it that) that I have is fileCount = 0 while (os.path.exists(dstPath)): fileCount += 1 parts = os.path.splitext(dstPath) dstPath = "%s_%d%s" % (parts[0], fileCount, parts[1]) however...this produces the following output. test_1.jpg test_1_2.jpg test_1_2_3.jpg .....etc The Question: How do I get change the number in its current place (without appending numbers to the end)? Ps. I'm using this for a file renaming tool.

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  • JSF-JSP cancel button returns a number format exception

    - by Barca
    I have a cancel button on a JSF-JSP page. It is handled by a method on the corresponding java class: public String cancel_action() { return "CANCEL"; This is configured in faces-config.xml as following: <navigation-rule> <from-view-id>/page2.jsp</from-view-id> <navigation-case> <from-outcome>CANCEL</from-outcome> <to-view-id>/page1.jsp</to-view-id> </navigation-case> </navigation-rule> Not sure why it is returning a number format exception. Any help will be highly appreciated.

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  • How to find the largest power of 2 less than the given number

    - by nazar_art
    I need to find the largest power of 2 less than the given number. And I stuck and can't find any solution. Code: public class MathPow { public int largestPowerOf2 (int n) { int res = 2; while (res < n) { res =(int)Math.pow(res, 2); } return res; } } This doesn't work correctly. Testing output: Arguments Actual Expected ------------------------- 9 16 8 100 256 64 1000 65536 512 64 256 32 How to solve this issue?

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  • program to determine number of duplicates in a sentence

    - by bhavna raghuvanshi
    public class duplicate { public static void main(String[] args)throws IOException { System.out.println("Enter words separated by spaces ('.' to quit):"); Set<String> s = new HashSet<String>(); Scanner input = new Scanner(System.in); while (true) { String token = input.next(); if (".".equals(token)) break; if (!s.add(token)) System.out.println("Duplicate detected: " + token); } System.out.println(s.size() + " distinct words:\n" + s); } } my program detects and prints duplicate words but i need to print the number of duplicate words also. pls help me do it.

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  • Pass variable number of variables to a class in PHP

    - by user325282
    I need to pass a variable number of strings to instantiate different classes. I can always do a switch on the size of the array: switch(count($a)) { case 1: new Class(${$a[0]}); break; case 2: new Class(${$a[0]}, ${$a[1]}); break; etc... There has to be a better way to do this. If I have an array of strings ("variable1", "variable2", 'variable3", ...), how can I instantiate a Class without manually accounting for every possibility?

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  • Find and sort by number of ocurrences of tag with Active Admin and act_as_taggable_on

    - by nunopolonia
    I'm using act_as_taggable_on and Active Admin on a Rails project. In that project there are Posts and each Post has Tags. I want to show a list of Tags in Active Admin and the number of ocurrences of each one. The way I found to do this was: index do column :name column :ocurrences do |tag| ocurrences = Post.tag_counts.find(tag.id).count end default_actions end Which will search the Tag List every time for every Post, which performance wise looks really bad. I would also like to be able to sort the tags by ocurrence. Any idea of how I can do it?

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  • How to get the number of unread gmail mails (on android)

    - by Lord Otori
    I've been trying to get the number of unread gmail mails with no luck. I've read Gmail.java and gmail4j both links taken out of this site from this question: Android - How can I find out how many unread email the user has? But still after having read all of that and a couple of other sites that talked about this particular subject my question remains: Q: How can I get the Gmail Unread Count? Sorry if it seams a bit insistent but I clearly lack the knowledge to find this out on my own from the source. PS: I would like to clarify that I want to do it without having to ask the user for credentials. Just 2 add some colors to the question let me show you the looks of my app.

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  • mysql count(*) left join group by - the number of files in a folder

    - by Flavius
    Hi I have the following tables CREATE TABLE `files` ( `fileid` int(11) NOT NULL AUTO_INCREMENT, `filename` varchar(255) NOT NULL, `filesize` int(11) NOT NULL, `folder` int(11) NOT NULL, PRIMARY KEY (`fileid`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; CREATE TABLE `folders` ( `directoryid` int(11) NOT NULL AUTO_INCREMENT, `directoryname` varchar(255) NOT NULL, PRIMARY KEY (`directoryid`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; How to get a list of all folders and the number of files they hold, including folders who have no (zero) files? Recursion must not be taken into account. Found it select folders.directoryid, folders.directoryname, count(files.fileid) as no_files from folders left join files on files.folder = folders.directoryid group by folders.directoryid, folders.directoryname I hope it will help someone.

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  • Query returning an ascending group number

    - by Dougman
    I have a query like below that has groups (COL1) and that group's values (COL2). select col1, col2 from (select 'A' col1, 1 col2 from dual union all select 'A' col1, 2 col2 from dual union all select 'B' col1, 1 col2 from dual union all select 'B' col1, 2 col2 from dual union all select 'C' col1, 1 col2 from dual union all select 'C' col1, 2 col2 from dual ) order by col1, col2; The output of this query looks like: COL1 COL2 ---- ---- A 1 A 2 B 1 B 2 C 1 C 2 What I need is a query that will return an ordered number increasing for each different group (COL1). It seems like there would be a simple way to accomplish this (maybe with analytics) but for some reason it is escaping me. GRPNUM COL1 COL2 ------ ---- ---- 1 A 1 1 A 2 2 B 1 2 B 2 3 C 1 3 C 2 I am running Oracle 10gR2.

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  • Relative probabilities using random number gen

    - by CyberShot
    If I have relative probabilities of events A, B, C occurring. i.e P(A) = 0.45, P(B) = 0.35, P(C) = 0.20, How do I do represent this using a random number generator between 0 and 1? i.e. R = rand(0,1) if (R < 0.45) event A else if(R < 0.35) event B else if(R < 0.20) event C The above works for two events A,B but I think the above is wrong for three or more since there is overlapping. This is obviously a very simple question and the answer should be immediately evident, but I'm just too stupid to see it.

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  • Find number of serialized objects

    - by tmosier
    Hello all. My issue is trying to determine a number of objects created, the objects being serialized from an XML document. The XML document should be set up for simplicity, so any developer can add an additional object and need no further modification to the code. However each of these objects need to be handled/updated seperately, and specifically, some of the objects are of different sub-classes, which need to be handled differently. Here is some pseudocode for what I am going for class A { public B myClassB; public void Update() { // for every object of whatever type in myClassB // update logic } } XML: <\data <\object1 etc... So what would be my simplest course of action, allowing other to add objects via the XML, but still ensuring the proper logic happenes for each?

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  • count number of rows to be affected before update in trigger

    - by tomaszsobczak
    Hi, I want to know number of rows that will be affected by UPDATE query in BEFORE per statement trigger . Is that possible? The problem is that i want to allow only queries that will update up to 4 rows. If affected rows count is 5 or more i want to raise error. I don't want to do this in code because i need this check on db level. Is this at all possible? Thanks in advance for any clues on that

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  • Print number in engineering format

    - by jmurrayufo
    I am trying to print a number into engineering format with python, but I cannot seem to get it to work. The syntax SEEMS simple enough, but it just doesn't work. >>> import decimal >>> x = decimal.Decimal(1000000) >>> print x 1000000 >>>> print x.to_eng_string() 1000000 I cannot figure out why this is. The two values are not equal (one is a string, the other is an int). Setting various contexts in decimal doesn't seem to help either. Any clues or ideas?

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  • Matching two sections same number of times

    - by Leszczu
    Hello, i need a HTML to parse: <span>some text<span><span><span>text</span></span></span></span> I need to remove unnecessary <span> occurrences, so that output is: <span>some text<span>text</span></span> I wrote a regex, which does this once: /<SPAN>[^<]*<\/SPAN>/i How to make this work same number of times on both <span> and </span>?

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  • Calculating number of online visitors?

    - by Syom
    i need to show the number of online visitors, but there is a problem with selecting algoritm to do it! maybe i must create a table in DB, where i'll store ip addresses of visitors and time of visit! by so i can show the count of ip addresses, which's time = NOW() - 10 minutes, for example...("now()-10 minutes" is just to show the logic, i know that this is not a function:) is this goog way to go? or maybe it's better to use AJAX methods to store the data? please give me an idea. Thanks

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  • Python: Matching & Stripping port number from socket data

    - by tobywuk
    Hello, I have data coming in to a python server via a socket. Within this data is the string '<port>80</port>' or which ever port is being used. I wish to extract the port number into a variable. The data coming in is not XML, I just used the tag approach to identifying data for future XML use if needed. I do not wish to use an XML python library, but simply use something like regexp and strings. What would you recommend is the best way to match and strip this data? I am currently using this code with no luck: p = re.compile('<port>\w</port>') m = p.search(data) print m Thank you :)

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  • Avec 1.5 millions d'unités écoulées, les Windows Phone 7 sont "les meilleurs du marché", Ballmer également satisfait de Bing

    1.5 millions de windows phone 7 HTC écoulés annonce Steve Ballmer le 17/01/2011 Selon son PDG Steve Ballmer, qui semble officialiser des propos tenus en interne par Achim Berg fin décembre 2010 (lire news précédente), le Windows Phone 7 HTC est "le meilleur sur le marché". Le dirigeant de Microsoft est apparu très optimiste quant à la réussite des mobiles et des décisions techniques de son entreprise, malgré une série de départs et la concurrence rude sur le marché des Smartphones avec Apple. Ballmer a parlé des jeux et des moteurs de recherche comme d'une réussite, notamment avec la Xbox qui selon lui n'est pas seulement une ...

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  • HTG Explains: Does Your Android Phone Need an Antivirus?

    - by Chris Hoffman
    The media is full of reports saying Android malware is exploding and that Android users are at risk. Does this mean you should install an antivirus app on your Android phone or tablet? While there may be a lot of Android malware in the wild, a look at Android’s protections and studies from antivirus companies reveals that you’re probably safe if you follow some basic precautions. How To Use USB Drives With the Nexus 7 and Other Android Devices Why Does 64-Bit Windows Need a Separate “Program Files (x86)” Folder? Why Your Android Phone Isn’t Getting Operating System Updates and What You Can Do About It

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  • Windows Phone 7 Developer Tools &ndash; January 2011 Update

    - by TechTwaddle
    Note: I am currently in the process of relocating my blog from http://www.geekswithblogs.net/techtwaddle to my new address at http://www.techtwaddle.net I suggest you point your feed readers to the new address as I slowly transition to my new shared-hosted, ad-free wordpress blog :) If you haven’t heard already, the Jan 2011 update of the windows phone 7 developer tools is out, er, in Feb. You can download the installation files from here, http://www.microsoft.com/downloads/en/details.aspx?FamilyID=49b9d0c5-6597-4313-912a-f0cca9c7d277 The performance increase with the new emulator is clearly noticeable and the first time deploy is real quick! The emulator image should also be a precursor to the windows phone 7 OS update that we’ve been waiting for ever. The emulator image includes copy-paste functionality which is enabled by default on all textboxes, password boxes and edit controls within web browser control, so existing apps get this feature for free. Go ahead and give the new tools a try. If you want to experiment more you might be interested in a unlocked emulator image, follow the link for more information. http://windowsphonehacker.com/latest_windows_phone_7_emulator_unlocked-02-05-11.php

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  • Reverse X11 forwarding

    - by Oli
    I was playing with my phone (that runs a Linux/X stack) last night and I managed to ssh into my desktop and run an application and have it show up on my phone. It was awesome. Today I'd like to sort of do the opposite. I want to view an application running on my phone on my PC. I could install a SSH server on my phone but I frankly don't fancy that purely for security reasons. I want this to be initiated from my phone. Is there a way to connect from my phone and tunnel the PC's X connection back to the phone and then run an application on the phone that show on the PC?

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  • Windows 8 et Windows Phone 8 ouvrent la voie à une fusion des OS, selon Bill Gates

    Windows 8 et Windows Phone 8 ouvrent la voie à la fusion des OS selon Bill Gates Cette période est cruciale pour Microsoft. L'éditeur va dévoiler tour à tour ses systèmes d'exploitation Windows 8 le 26 octobre et Windows Phone 8 trois jours après. Ces nouveaux OS représentent les armes de la société pour la conquête du marché des smartphones et des tablettes, et pour consolider sa position dans le secteur des PC. À l'approche de ces dates fatidiques, l'éditeur doit déployer les moyens de communication pour attirer l'attention des consommateurs. Pour l'occasion, la firme a fait appel à l'homme à l'origine de la construction de cet Empire infor...

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  • Windows Phone 7 : la mise à jour de mars pourrait être retardée, et n'arriver que le lundi 21

    Windows Phone 7 : la mise à jour de mars pourrait être retardée, et n'arriver que le lundi 21 Mise à jour du 10.03.2011 par Katleen La mise à jour de Windows Phone 7 prévue pour début mars, comme l'avait annoncé Steve Ballmer en février, pourrait être légèrement repoussée. En effet, elle "sera disponible pour la deuxième quinzaine de Mars". Cette arrivée pendant la seconde moitié du mois, voir même sa fin, est un retard comparé à ce qui était attendu. Un site américain avance même une date de sortie au 21 mars, ce qui éloigne des prédictions faites par le CEO de Microsoft. Quoiqu'il en soit, la firme ne compte pas s'arrêter là et proposera de nouvelles updates ...

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  • First Windows Phone 7 &ndash; Mobile LOB App.

    - by Richard Jones
    So I spent a couple of hours yesterday building my first Windows 7 Phone Series. application.   I still can’t get used to saying Windows 7 Phone Series.   So I think I’ll just go with WP7.   I must say I’m really impressed.    Calling web-services a breeze laying out User Interface a very straight forward.   I had made called into Dynamics NAV using web-services in under 10 minutes. Working in XAML takes a bit of getting used to,  I’m not trying to-do anything too clever yet. One thing I will point out to transition from one XAML page to the next use this.NavigationService.Navigate(new Uri("/Primary.xaml", UriKind.Relative)); Going from Compact Framework this is equivalent of a Window.Show Its so nice to be able to talk nicely again, about Windows Based Mobile Development!

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  • How to calculate square root in PHP [explained] [on hold]

    - by Enes Imsirovic
    At first code ! Don't forget embed the JQuery ! <html> <head> <title>Simple jQuery and PHP Square Root example</title> <script src="js/jquery-1.10.1.js" type="text/javascript"></script> <script type="text/javascript"> $(document).ready(function() { $('#form').submit(function(){ var number = $('#number').val(); $.ajax({type:"post",url:"calculate.php",data:"number=" +number,success:function(msg){$('#result').hide(); $("#result").html("<h3>" + msg + "</h3>").fadeIn("slow"); } }); return false; }); }); </script> </head> <body> <form id="form" action="calculate.php" method="post"> Enter number: <input id="number" type="text" name="number" /> <input id="submit" type="submit" value="Calculate Square Root" name="submit"/> </form> <p id="result"></p> </body> </html> Second code witch would be connected with first : calculate.php <?php if($_POST['number']==null){ echo "Please Enter a Number"; }else { if (!is_numeric($_POST['number'])) { echo "Please enter only numbers"; }else{ echo "Square Root of " .$_POST['number'] ." is ".sqrt($_POST['number']); } } ?> Chiefly for begginers, to see the power of PHP :) xD Load this on your localhost.. PHP files and JS : https://mega.co.nz/#!Et8zWSBb!KX2PFxa2Pzw_l-wi6QU8xi_eKTlHbtQuBsT_DvXrifk At least it look like this : http://imgur.com/vNnDRQ3

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