Search Results

Search found 33297 results on 1332 pages for 'java java ee'.

Page 944/1332 | < Previous Page | 940 941 942 943 944 945 946 947 948 949 950 951  | Next Page >

  • Array returning Null values

    - by Nick Gibson
    Dunno why it is...heres the coding for it. http://pastebin.org/301343 I know theres a lot of repetitiveness in the coding...but its because the arrays were retuning null so I got tired of messing with them. Everything works until it reaches line 224, which returns null values.

    Read the article

  • how to tune BufferedInputStream read()?

    - by technomax
    I am reading a BLOB column from a Oracle database, then writing it to a file as follows: public static int execute(String filename, BLOB blob) { int success = 1; try { File blobFile = new File(filename); FileOutputStream outStream = new FileOutputStream(blobFile); BufferedInputStream inStream = new BufferedInputStream(blob.getBinaryStream()); int length = -1; int size = blob.getBufferSize(); byte[] buffer = new byte[size]; while ((length = inStream.read(buffer)) != -1) { outStream.write(buffer, 0, length); outStream.flush(); } inStream.close(); outStream.close(); } catch (Exception e) { e.printStackTrace(); System.out.println("ERROR(img_exportBlob) Unable to export:"+filename); success = 0; } } The file size is around 3MB and it takes 40-50s to read the buffer. Its actually a 3D image data. So, is there any way by which I can reduce this time?

    Read the article

  • Cannot submit form when disabling JSF page

    - by Steve
    Simple submit button. <h:commandButton actionListener="#{regBean.findReg}" action="#{regBean.navigate}" value="Search" /> The form tag is displayed like so: <h:form onsubmit="this.disabled=true;busyProcess();return true;"> This is so if the submit button is pressed, the page shows a "busy" icon until request is processed. The problem is, the request is never submitted and it never reaches the backend. However, if I instead take out the "disabled" call like so: <h:form onsubmit="busyProcess();return true;"> Everything works. Any ideas?

    Read the article

  • Accessing JAR resources

    - by Pablo Fernandez
    I have a jar file with resources (mainly configuration for caches, logging, etc) that I want to distribute. I'm having a problem with the relative paths for those resources, so I did what I've found in another stackoverflow question, which said that this was a valid way: ClassInTheSamePackageOfTheResource.class.getResourceAsStream('resource.xml'); Sadly this does not work. Any ideas? Thanks! PS: Obviously I cannot use absolute paths, and I'd like to avoid environment variables if possible

    Read the article

  • How to calculate the y-pixels of someones weight on a graph? (math+programming question)

    - by RexOnRoids
    I'm not that smart like some of you geniuses. I need some help from a math whiz. My app draws a graph of the users weight over time. I need a surefire way to always get the right pixel position to draw the weight point at for a given weight. For example, say I want to plot the weight 80.0(kg) on the graph when the range of weights is 80.0 to 40.0kg. I want to be able to plug in the weight (given I know the highest and lowest weights in the range also) and get the pixel result 400(y) (for the top of the graph). The graph is 300 pixels high (starts at 100 and ends at 400). The highest weight 80kg would be plot at 400 while the lowest weight 40kg would be plot at 100. And the intermediate weights should be plotted appropriately. I tried this but it does not work: -(float)weightToPixel:(float)theWeight { float graphMaxY = 400; //The TOP of the graph float graphMinY = 100; //The BOTTOM of the graph float yOffset = 100; //Graph itself is offset 100 pixels in the Y direction float coordDiff = graphMaxY-graphMinY; //The size in pixels of the graph float weightDiff = self.highestWeight-self.lowestWeight; //The weight gap float pixelIncrement = coordDiff/weightDiff; float weightY = (theWeight*pixelIncrement)-(coordDiff-yOffset); //The return value return weightYpixel; }

    Read the article

  • Hibernate (JPA) Entity with Static collection as a member

    - by Kyle Partridge
    Is it possible to have a static collection as a member of a hibernate entity? Say I have an object Question: public class Question { private String category; ... } Would it be possible to populate a static Set<String> that is a distinct set of all categories in the Database? I know I could just query this, but I was wondering if there was a more elegant solution, as it seems like something that other people may have come across.

    Read the article

  • division problems

    - by David
    This line of code: System.out.println ("aray[j], "+aray[j]+", divided by sum, "+sum+", equals: aray[j]/sum: "+ aray[j]/sum) ; is yeilding this line of text: aray[j], 21, divided by sum, 100, equals: aray[j]/sum: 0 why is it doing this? (everything is right eccept that the answer should be .21)

    Read the article

  • DataOutputStream, does it lose some bits

    - by user308806
    hello, I'm writing a client server application, but I don't receive the same bytes at the client side when they are sent from the server side. At the server side I used .write(bytes[]) method. At the client side, I used .readFully(byte[]) method. Do you have any idea ?

    Read the article

  • How to deal with the Hibernate hql multi-join query result in an Object-Oriented Way?

    - by EugeneP
    How to deal with the Hibernate hql multi-join query result in an Object-Oriented Way? As I see it returns a list of Objects. yes, it is tricky and only you who write the query know what should the query return (what objects). But are there ways to simplify things, so that it returned specific objects with no need in casting Object to a specific class according to its position in the query ? Maybe Spring can simplify things here? It has the similar functionality for JDBC, but I don't see if it can help in a similar way with Hibernate.

    Read the article

  • display tag scope issue with pagination

    - by sarah
    Hi All, I am using display tag for pagination ,i am reading the list from request scope and displaying it,i have kept the page size as 1 and the list hast 4 values,if i press next i get nothing to display this is the case with request scope but not with session scope how can i tackle this problem?

    Read the article

  • How do I get the IPv4 subnetmask on interface with both v4 and v6 address?

    - by Per Fagrell
    I have an InterfaceAddress that returns an ipv4 address (4 octets). However the network prefix length seems to be for the ipv6 address associated with the interface (it's returning as 128). How do I find the correct network prefix length? Enumeration<NetworkInterface> NetworkInterface.getNetworkInterfaces() for (; interfaces.hasMoreElements();) { final List<InterfaceAddress>interfaceAddresses = interfaces.nextElement().getInterfaceAddresses(); for (final InterfaceAddress address : interfaceAddresses) { assert(address.getAddress().getAddress().length == 4); // [sic] assert(address.getNetworkPrefixLength() < 32); // <- Fails. Actually equals 128 } }

    Read the article

  • contextpath is appended

    - by manoj
    dear all, i have created one hyperlink, and by clicking on that i am redirecting the page to another JSP, but i am not getting the correct URL that i am passing, URL is appended with another string and the page is not redirected, please anybody have any idea about that, help me out ' class="<%=tdclass% Label2" style="<%=rb.getDataStyleString(rvo,data)%"','newwindow','top=0, left=0, scrollbars=yes,status=1,resizable=yes,height= (screen.availHeight - 10),width= (screen.availWidth-5)')" <%=rb.getDataValue(data)%

    Read the article

  • Why does the compiler complain "while expected" when I try to add more code?

    - by user1893578
    Write a program with a word containing @ character as an input. If the word doesn't contain @, it should prompt the user for a word with @. Once a word with @ is read, it should output the word then terminate. This is what I have done so far: public class find { public static void main(String[] args) { System.out.println(" Please enter a word with @ "); Scanner scan = new Scanner(System.in); String bad = "@"; String word = scan.next(); do if (!word.contains(bad)) System.out.println(" Please try again "); else System.out.println(" " + word); while (!word.contains(bad)); } } I can get it to terminate after a word containing "@" is given as input, but if I try to add a Scanner to the line after "please try again", it says while expected.

    Read the article

  • out-of-the-box way to get an idmap from hibernate for a given entity?

    - by Geert-Jan
    Over and over again I notive myself getting a list from hibernate, and the first thing next is put it in an idmap like: List<House> entities = s.createCriteria(House.class).list(); Map<String,House> entitymap = new HashMap<String,House>(); for(TA_entity e:entities){ entitymap.put(e.getId(), e); } Is there a way to get this directly out of hibenerate? afterall Hibernate is familiar with the id.

    Read the article

  • How to create layout-small-land folder?

    - by codedeziner
    I want to create separate folders for my layouts, like this in my resource directory: layout-land layout-port this is ok, but this: layout-small-land layout-small-port or layout-land-small layout-port-small Results in: 'Invalid resource directory name' What gives?

    Read the article

  • How do I iterate over an Array field reflectively?

    - by kunjaan
    I have Class<? extends Object> class1 = obj.getClass(); Field[] fields = class1.getDeclaredFields(); for (Field aField : fields) { aField.setAccessible(true); if (!Modifier.isStatic(aField.getModifiers()) && Modifier.isPublic((aField.getModifiers()))) { if (aField.getType().isArray()) { for (?? vals : aField) { System.out.println(vals); } } } }

    Read the article

  • question about quicksort 3 way partition

    - by davit-datuashvili
    i want implement quicksort 3 way partition here is code public class quick3{ public static void quicksort3(int a[],int l,int r){ int k; int v=a[r]; if (r<=l) return; int i=l; int j=r; int p=l-1; int q=r; for (;;) { while (a[++i]<v); while (v<a[--j]) if (j==i) break; if (i>=j) break; swap( a,i, j); if (a[i]==v){ p++; swap(a,p,i);} if (v==a[j]){ q--; swap( a,q,j); } } swap(a,i,r); j=i-1; i=i+1; for (k=1;k<=p;k++,j--) swap(a,k,j); for (k=r-1;k>=q;k--,i++) swap(a,k,i); quicksort3(a,l,j); quicksort3(a,i,r); } public static void main(String[]args){ int a[]=new int[]{4,6,5,9,7,8,3}; quicksort3(a,0,a.length-1); for (int i=0;i<a.length;i++){ System.out.println(a[i]); } } public static void swap(int a[],int i,int j){ int t=a[i]; a[i]=a[j]; a[j]=t; } } after change result is 4 8 7 6 3 5 9 any suggestion?please help

    Read the article

< Previous Page | 940 941 942 943 944 945 946 947 948 949 950 951  | Next Page >