Search Results

Search found 6862 results on 275 pages for 'username'.

Page 95/275 | < Previous Page | 91 92 93 94 95 96 97 98 99 100 101 102  | Next Page >

  • VBscript and CMD writing into a text file

    - by Effected
    I am writing a script that executes and write everything to the file here is example, I stored the complete command in the variable 'Command' , Command = "ftp ftp.xyz.com 21 " & vbCRLF and then executing it in command prompt, shell.Run "%comspec% /c FTP " & Command & " > " & E:/abc.txt, 0, TRUE but when this program execute it won't write anything to the text file because this is an incomplete command, this command on execution prompt user to input username and password of FTP, how can i do this , that my programm automatically input username and password when prompt and then write everything to file ?

    Read the article

  • problem with TEMPORARY TABLE

    - by Z77
    Within PHP I do: 1.) A temporary table is created: CREATE TEMP TABLE new_table AS SELECT .... FROM ...; 2.) AFter that I want to use this table to create a shape file: shell_exec ("pgsql2shp .... -u username -P password ...); Separetly those two things work, but by creating a temporary table and after that using this table in pgsql2shp does not work. I pressume this is because temporary table duration is to the end of session. But to create shp file I need to use username and password what means new session starts and temporary table is dropped before I use it for shape creation. Any tip how to solve it? Thank you!

    Read the article

  • Shouldn’t GridView’s RowStyle-HorizontalAlign property overwrite CSS’s text-align property?

    - by AspOnMyNet
    a) As far as I know, GridView’s RowStyle-HorizontalAlign property should overwrite CSS’s text-align property, and thus text inside GridView's cells should be located on the left side of the cells, but is instead moved to the right side. Why is that? b) Similarly, RowStyle-Font-Bold should overwrite CSS’s font-weight property and thus fonts shouldn’t be in bold. But again, CSS’s property overwrites RowStyle’s Font-Bold property. Why? <div id="someClass"> <asp:GridView ID="gvwShowUsers" runat="server" > <RowStyle BackColor="#FFFBD6" ForeColor="#333333" Font-Bold="false" HorizontalAlign="Left" /> <Columns> <asp:BoundField DataField="UserName" HeaderText="UserName" /> </Columns> </asp:GridView> </div> CSS file: #someClass td { font-weight:bolder; text-align:right; } thanx

    Read the article

  • Doctrine: Mixing YAML markup and db manager (navicat) editing?

    - by ropstah
    I think the answer to this question should be: No. However I hope to be corrected. I'd like to edit our database using a mixture of YAML markup + Doctrine createTables() and Navicat editing. Can I maintain the inheritance which is marked up? Example (4 steps, at step 4, Doctrine is in no way able to re-create the inheritance schema... or is it?): Step 1: Create YAML with inheritance --- Entity: columns: username: string(20) password: string(16) created_at: timestamp updated_at: timestamp User: inheritance: extends: Entity type: column_aggregation keyField: type keyValue: 1 Group: inheritance: extends: Entity type: column_aggregation keyField: type keyValue: 2 Step 2: Create tables using Doctrine (and drop/create db if nessecary) Created sql: CREATE TABLE entity (id BIGINT AUTO_INCREMENT, username VARCHAR(20), password VARCHAR(16), created_at DATETIME, updated_at DATETIME, type VARCHAR(255), PRIMARY KEY(id)) ENGINE = INNODB Step 3: Edit table using Navicat Step 4: Refresh YAML file because of 'external' edits...

    Read the article

  • Can't use method return value in write context; Not sure where to go from here

    - by Morgan Green
    This is my source for the variable. <?php if ($admin->get_permissions()=3) echo 'Welcome to the Admin Panel'; else echo 'Sorry, You do not have access to this page'; ?> And the code that I'm actually trying to call with the if statement is: public function get_permissions() { $username = $_SESSION['admin_login']; global $db; $info = $db->get_row("SELECT `permissions` FROM `user` WHERE `username` = '" . $db->escape($username) . "'"); if(is_object($info)) return $info->permissions; else return ''; } This should be a simple way to call my pages that the user is authorized for by using an else if statement. Or So I thought

    Read the article

  • Create a complex SQL query?

    - by mazzzzz
    Hey guys, I have a program that allows me to run queries against a large database. I have two tables that are important right now, Deposits and withdraws. Each contains a history of every user. I need to take each table, add up every deposit and withdraws (per user), then subtract the withdraws from the deposits. I then need to return every user whos result is negative (aka they withdrew more then they deposited). Is this possible in one query? Example: Deposit Table: |ID|UserName|Amount| |1 | Use1 |100.00| |2 | Use1 |50.00 | |3 | Use2 |25.00 | |4 | Use1 | 5.00 | WithDraw Table: |ID|UserName|Amount| |2 | Use2 | 5.00 | |1 | Use1 |100.00| |4 | Use1 | 5.00 | |3 | Use2 |25.00 | So then the result would output: |OverWithdrawers| | Use2 | Is this possible (I sure don't know how to do it)? Thanks for any help, Max

    Read the article

  • Batch to copy and replace a txt file from one server to another

    - by Sunny
    I have two servers, server1 and server2 on same network but require username and password to be mapped. server1 has a text file as C:\Users\output.txt. I want to create and schedule a batch script on server1, which should copy and replace output.txt file from server1 to server2 at path E:\data\output.txt on daily basis. I don't want to map server2 manually every time I start my computer nor do I want to enter my username and password each time. I am using following commands in a batch, but not working; net use C: \\server2\E:\data server2password /user:server2domain\server2username /savecred /p:yes xcopy C:\Users\output.txt E:\data\

    Read the article

  • In Java, how do I set a return type if an exception occurs?

    - by beagleguy
    hey all, I'm new to Java and was wondering if I define a method to return a database object like import java.sql.*; public class DbConn { public Connection getConn() { Connection conn; try { Class.forName("com.mysql.jdbc.Driver").newInstance(); if(System.getenv("MY_ENVIRONMENT") == "development") { String hostname = "localhost"; String username = "root"; String password = "root"; } conn = DriverManager.getConnection("jdbc:mysql:///mydb", username, password); return conn; } catch(Exception e) { throw new Exception(e.getMessage()); } } } if the connection fails when I try to create it what should I return? eclipse is telling me I have to return a Connection object but if it fails I'm not sure what to do. thanks!

    Read the article

  • Echo-ing Only Available Database Result

    - by Robert Hanson
    I have this Associative Array : $Fields = array("row0"=>"Yahoo ID", "row1"=>"MSN ID", "row2"=> "Gtalk ID"); on the other side, I have this SQL query : SELECT YahooID, MSNID, GTalkID From UserTable WHERE Username = '$Username' LIMIT 1; the result maybe vary, because some users only have Yahoo ID and some have others. for example if I have this result : $row[0] = NONE //means YahooID = NONE $row[1] = [email protected] $row[2] = [email protected] then how to have this as an output (echo) : MSN ID = [email protected] Gtalk ID = [email protected] since Yahoo ID is not exist, then the result will be MSN and Gtalk only. 'MSN ID' and 'Gtalk ID' is variable from Associative Array, while '[email protected]' and '[email protected]' from SQL result. thanks!

    Read the article

  • A better understanding of the relations beetween database tables

    - by Nistor Alexandru
    Hi I am trying to get a better understanding of relational databases and there is something that I keep bumping into and don't understand.Let's take this two tables: In this case Login.ID is the primary key with auto_increment set and Profile.ID_LOGIN is the Foreign KEY.When a user is created and it's username and password is stored in the login database does the ID coresponding to the curesnt username and password get automaticly added into ID_LOGIN or do I have to create an SQL statement to do this? If I have to create a SQL statement how should I aproach adding the ID_LOGIN to make sure I am adding it corectly?

    Read the article

  • file_get_contents not displaying any data

    - by Lance
    I'm doing $info = file_get_contents('http://USERNAME:[email protected]/v2/sales?client_key=CLIENT_KEY'); $info returns nothing. However, when I put the URL into my browser, JSON appears. I tried using cURL without any luck. $data = array('client_key' => 'CLIENT_KEY'); $link = "http://api.appfigures.com/v2/sales"; $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $link); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch, CURLOPT_POST, count($data)); curl_setopt($ch, CURLOPT_POSTFIELDS, http_build_query($data)); curl_setopt($ch, CURLOPT_USERPWD, "username:password"); curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_BASIC); $jsonData = curl_exec($ch); curl_close($ch); print_r($jsonData); Thanks

    Read the article

  • How do search engines see dynamic profiles?

    - by Lumpy
    Recently search engines have been able to page dynamic content on social networking sites. I would like to understand how this is done. Are there static pages created by a site like Facebook that update semi frequently. Does Google attempt to store every possible user name? As I understand it, a page like www.facebook.com/username, is not an actual file stored on disk but is shorthand for a query like: select username from users and display the information on the page. How does Google know about every user, this gets even more complicated when things like tweets are involved.

    Read the article

  • How do I require a login for a user in Django?

    - by Di Zou
    In my urls.py I have this: (r'^myapp/$', 'myapp.views.views.index'), (r'^myapp/login/$', 'myapp.views.views.login_user'), In my settings.py I have this: LOGIN_URL = '/myapp/login' In my views.py I have this: @login_required((login_url='/myapp/login/') def index(request): return render_to_response('index.html') def login_user(request): #login stuff return render(request, 'registration/login.html', {'state':state, 'username': username}) I can go to mysite.com/myapp/login and the login page works. However, when I go to mysite.com/myapp/index I do not get redirected to the login page even though I am logged out. Why is that and how do I fix it?

    Read the article

  • JFileChooser returns incorrect path in OS X (folders only mode)

    - by Virat Kadaru
    I have a problem in java swing where the user has to select a folder, so I am using the code below. JFileChooser fc = new JFileChooser(); fc.setFileSelectionMode(JFileChooser.DIRECTORIES_ONLY); if(fc.showDialog(singleton, SELECT) == JFileChooser.APPROVE_OPTION) { File folder = fc.getSelectedFile(); String path = folder.getPath() + File.separatorChar + MYAPPFOLDER; } Now there are 2 ways a user may select the folder Navigate to the folder and select the folder Navigate to the folder, go into the folder, and click select Both ways work fine on windows but on OS X, I get If I do 1 : path = Users/<username>/Desktop/MYAPPFOLDER If I do 2 : path = Users/<username>/Desktop/Desktop/MYAPPFOLDER How do I avoid this 2nd case? Thanks in advance.

    Read the article

  • Jmeter Query new user

    - by Sri
    First of all apologies for the below question. Am from a Testing background for the past 8 years and very novice to Jmeter. I went through the Jmeter site, and ran a sample recording using the jmeter.apache.org site and it went fine. I want to test my knowledge and understanding. So, I did the following way. Created a thread group. Added a config element HTTP Default Requests with server name as mail.google.com. Added a Sampler as HTTP request, set the METHOD to POST and gave the username and password, and i ran the test. When i see the Results Viewer, i could see the login page of gmail, I need to know how to pass my username and password and simulate the clicking of Submit button and getting the next page. Please help, am very new and will really appreciate if it's explained as simple as possible.

    Read the article

  • rake db:create not working for legacy rails app (2.3.5) using MySQL (5.5.28)

    - by ridicter
    I'm a new Rails Developer, and I'm working on a legacy Rails app. Whenever I run the rake db:create command, I get an error that the database couldn't be created. I have found many StackOverflow questions related to this, but in troubleshooting nearly all permutations of solutions, I couldn't resolve the issue. I created the three Dbs (dev, prod, test), created the user with all access privileges to these dbs, and ran rake db:create. I'm running Mac OS X Lion, MySQL 5.5.28, Rails 2.3.5, Ruby 1.8.7. Here are my settings development: adapter: mysql encoding: utf8 database: adva_development username: adva password: **** host: localhost socket: /tmp/mysql.sock Here's the error: Couldn't create database for {"adapter"=>"mysql", "username"=>"adva", "host"=>"localhost", "encoding"=>"utf8", "database"=>"adva_development", "socket"=>"/tmp/mysql.sock", "password"=>"****"}, charset: utf8, collation: utf8_unicode_ci (if you set the charset manually, make sure you have a matching collation) I have done the following troubleshooting: Verified user and password are correct, and the user has access to the DB. (Double checked user access with SELECT * FROM mysql.db WHERE Db = 'adva_development' \G; User has all privileges.) Verify the socket is correct. I don't really understand sockets, but I can plainly see it at /tmp/mysql.sock. Checked collation and character set. I found out I had created the DB in latin charset and collation, so I recreated them. I ran show variables like "collation_database"; and show variables like "character_set_database"; and came back with utf8 and utf8_unicode_ci respectively. I followed the instructions in this question. After uninstalling mysql gem, I ran the following but came up with the same error: gem install --no-rdoc --no-ri mysql -- --with-mysql-dir=/usr/local/mysql-5.5.28-osx10.6-x86_64/bin --with-mysql-config=/usr/local/mysql-5.5.28-osx10.6-x86_64/bin/mysql_config Following Matt's suggestion, here's what a rake --trace db:create reveals: ** Invoke db:create (first_time) ** Invoke db:load_config (first_time) ** Invoke rails_env (first_time) ** Execute rails_env ** Execute db:load_config ** Execute db:create Couldn't create database for {"database"=>"adva_development", "adapter"=>"mysql", "host"=>"127.0.0.1", "password"=>"woof2adva", "username"=>"adva", "encoding"=>"utf8"}, charset: utf8, collation: utf8_unicode_ci (if you set the charset manually, make sure you have a matching collation) After 3 days and six or seven hours, I have pretty much run out of options. I tried various random things, like replacing localhost with 127.0.0.1 to no avail. Could there be something wrong related to my specific environment? Mac OS X Lion + MySQL 5.5.28? I plan on trying on setting up everything in a Linux environment. Thanks!

    Read the article

  • delete row from mysql through generated table with records

    - by HennySmafter
    I am using 2 pages. On one page it generates a table with the records and a delete button. After pressing delete it goes to the second page which should delete the record. But it doesn't. Below is the code that I am using. PS: The code is adapted from a tutorial I found through Google a while ago. delete_overzicht.php <?php // Load Joomla! configuration file require_once('../../../configuration.php'); // Create a JConfig object $config = new JConfig(); // Get the required codes from the configuration file $server = $config->host; $username = $config->user; $password = $config->password; $database = $config->db; // Connect to db $con = mysqli_connect($server,$username,$password,$database); if (!$con){ die('Could not connect: ' . mysqli_error($con)); } mysqli_select_db($con,$database); // Get results $result = mysqli_query($con,"SELECT * FROM cypg8_overzicht"); echo "<table border='1' id='example' class='tablesorter'><thead><tr><th>Formulier Id</th><th>Domeinnaam</th><th>Bedrijfsnaam</th><th>Datum</th><th>Periode</th><th>Subtotaal</th><th>Dealernaam</th><th>Verwijderen</th></tr></thead><tbody>"; while($row = mysqli_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['formuliernummer'] . "</td>"; echo "<td>" . $row['domeinnaam'] . "</td>"; echo "<td>" . $row['bedrijfsnaam'] . "</td>"; echo "<td>" . $row['datum'] . "</td>"; echo "<td>" . $row['periode'] . "</td>"; echo "<td> &euro; " . $row['subtotaal'] . "</td>"; echo "<td>" . $row['dealercontactpersoon'] . "</td>"; echo "<td><a href='delete.php?id=" . $row['id'] . "'>Verwijderen </a></td>"; echo "</tr>"; } echo "</tbody></table>"; mysqli_close($con); ?> delete.php <?php // Load Joomla! configuration file require_once('../../../configuration.php'); // Create a JConfig object $config = new JConfig(); // Get the required codes from the configuration file $server = $config->host; $username = $config->user; $password = $config->password; $database = $config->db; // Connect to db $con = mysqli_connect($server,$username,$password,$database); if (!$con){ die('Could not connect: ' . mysqli_error($con)); } mysqli_select_db($con,$database); // Check whether the value for id is transmitted if (isset($_GET['id'])) { // Put the value in a separate variable $id = $_GET['id']; // Query the database for the details of the chosen id $result = mysqli_query($con,"DELETE * FROM cypg8_overzicht WHERE id = $id"); } else { die("No valid id specified!"); } ?> Thanks to everyone who is willing to help!

    Read the article

  • Joining two select queries and ordering results

    - by user1
    Basically I'm just unsure as to why this query is failing to execute: (SELECT replies.reply_post, replies.reply_content, replies.reply_date AS d, members.username FROM (replies) AS a INNER JOIN members ON replies.reply_by = members.id) UNION (SELECT posts.post_id, posts.post_title, posts.post_date AS d, members.username FROM (posts) as b WHERE posts.post_set = 0 INNER JOIN members ON posts.post_by = members.id) ORDER BY d DESC LIMIT 5 I'm getting this error: #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'a INNER JOIN members ON replies.re' at line 2 All I'm trying to do is select the 5 most recent rows (dates) from these two tables. I've tried Join, union etc and I've seen numerous queries where people have put another query after the FROM statement and that just makes no logical sense to me as to how that works? Am I safe to say that you can join the same table from two different but joined queries? Or am I taking completely the wrong approach, because frankly I can't seem see how this query is failing despite reading the error message. (The two queries on there own work fine)

    Read the article

  • Support for multiple domains/subdomains in Rails

    - by thefactor
    I have a Rails app that has a similar setup to Tumblr, that is, you can have either: (1) Subdomain hosting (your-username.myapp.com) (2) Domain hosting (your-username.com) Both would forward to a personalized website for that user, created with my application. How can I accomplish this in Rails? I have been able to get (1) working with subdomain-fu, but I'm not sure how to get (2) working. Any pointers (plugins, gems, tutorials), etc. would be greatly helpful, I can't seem to find any. Thanks!

    Read the article

  • What do browsesr use to auto suggest values in web forms?

    - by nedlud
    If I come back to a web site after having filled in a form previously, the browser remembers my username (for example). I'm not talking about cookies remembering user names and passwords, but the way a browser will suggest a value for a previously submitted field. What controls this behaviour? My issue at the moment is that I have login forms on several small apps all running under the one domain. (eg www.example.com/app1/login/ and www.example.com/app2/login/). If I use my user name for app1, then go over to app2 where I use a different username, it only ever auto suggests my app1 user name. How can I change this behaviour? Do browsers use the fields ID to help remember this stuff? If I change the ID of the fields in the login form, will they auto suggest the correct values in future?

    Read the article

  • Error in header function

    - by user1178695
    I'm using the php header function for the redirection but it is not working.I'm using the following code. $sql=mysql_query("select * from password where username='$email' and password1 = '$pwd'"); //echo "selct * from password where username='$email' and password = '$pwd'"; $row=mysql_fetch_row($sql); $fieldset=mysql_num_rows($sql); $host=$_SERVER['HTTP_HOST']."/beta/"; if($fieldset>0 && $conEmail !="") { $_SESSION['email']=$email; $_SESSION['Email']=$email; $_SESSION['memberID']=$id; $_SESSION['status']='Admin'; header("location:http://".$host."member.php"); }

    Read the article

  • Passing values between pages in JavaScript

    - by buni
    using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.UI; using System.Web.UI.WebControls; using System.Data.SqlClient; using System.Configuration; using System.Text; using System.Web.Services; using System.IO; namespace T_Smade { public partial class ConferenceManagement : System.Web.UI.Page { volatile int i = 0; protected void Page_Load(object sender, EventArgs e) { GetSessionList(); } public void GetSessionList() { string secondResult = ""; string userName = ""; try { if (HttpContext.Current.User.Identity.IsAuthenticated) { userName = HttpContext.Current.User.Identity.Name; } SqlConnection thisConnection = new SqlConnection(@"data Source=ZOLA-PC;AttachDbFilename=D:\2\5.Devp\my DB\ASPNETDB.MDF;Integrated Security=True"); thisConnection.Open(); SqlCommand secondCommand = thisConnection.CreateCommand(); secondCommand.CommandText = "SELECT myApp_Session.session_id FROM myApp_Session, myApp_Role_in_Session where myApp_Role_in_Session.user_name='" + userName + "' and myApp_Role_in_Session.session_id=myApp_Session.session_id"; SqlDataReader secondReader = secondCommand.ExecuteReader(); while (secondReader.Read()) { secondResult = secondResult + secondReader["session_id"].ToString() + ";"; } secondReader.Close(); SqlCommand thisCommand = thisConnection.CreateCommand(); thisCommand.CommandText = "SELECT * FROM myApp_Session;"; SqlDataReader thisReader = thisCommand.ExecuteReader(); while (thisReader.Read()) { test.Controls.Add(GetLabel(thisReader["session_id"].ToString(), thisReader["session_name"].ToString())); string[] compare = secondResult.Split(';'); foreach (string word in compare) { if (word == thisReader["session_id"].ToString()) { test.Controls.Add(GetButton(thisReader["session_name"].ToString(), "Join Session")); } } } thisReader.Close(); thisConnection.Close(); } catch (SqlException ex) { } } private Button GetButton(string id, string name) { Button b = new Button(); b.Text = name; b.ID = "Button_" + id + i; b.Command += new CommandEventHandler(Button_Click); b.CommandArgument = id; i++; return b; } private Label GetLabel(string id, string name) { Label tb = new Label(); tb.Text = name; tb.ID = id; return tb; } protected void Button_Click(object sender, CommandEventArgs e) { Response.Redirect("EnterSession.aspx?session=" + e.CommandArgument.ToString()); } } I have this code when a user clicks a button www.mypage/EnterSession.aspx?session=session_name in the EnterSession.aspx i have used the code below to track the current URL _gaq.push(['pageTrackerTime._trackEvent', 'Category', 'Action', document.location.href, roundleaveSiteEnd]); Now I would also like to track in the Action parameter the session_name from the previous page.see the code below from the previous page test.Controls.Add(GetButton(thisReader["session_name"].ToString(), "Join Session")); Some idea how to do it? Thanx

    Read the article

  • $.post is not working

    - by BEBO
    i am trying to post data to Mysql using jquery $.post and php page. my code is not running and nothing is added to the mysql table. I am not sure if the path i am creating is wrong but any help would be appreciated. Jquery location: f_js/tasks/TaskTest.js <script type="text/javascript"> $(document).ready(function(){ $("#AddTask").click(function(){ var acct = $('#acct').val(); var quicktask = $('#quicktask').val(); var user = $('#user').val(); $.post('addTask.php',{acct:acct,quicktask:quicktask,user:user}, function(data){ $('#result').fadeIn('slow').html(data); }); }); }); </script> addTask.php (runs the jqeury code) <?php include 'dbconnect.php'; include 'sessions.php'; $acct = $_POST['acct']; $task = $_POST['quicktask']; $taskstatus = 'Active'; //get task Creator $user = $_POST['user']; //query task creator from users table $allusers = mysql_query("SELECT * FROM users WHERE username = '$user'"); while ($rows = mysql_fetch_array($allusers)) { //get first and last name for task creator $taskOwner = $rows['user_firstname']; $taskOwnerLast = $rows['user_lastname']; $taskOwnerFull = $taskOwner." ".$taskOwnerLast; mysql_query("INSERT INTO tasks (taskresource, tasktitle, taskdetail, taskstatus, taskowner, taskOwnerFullName) VALUES ('$acct', '$task', '$task', '$taskstatus', '$user', '$taskOwnerFull' )"); echo "inserted"; } ?> Accountview.php finally the front page <html> <div class="input-cont "> <input type="text" class="form-control col-lg-12" placeholder="Add a quick Task..." name ="quicktask" id="quicktask"> </div> <div class="form-group"> <div class="pull-right chat-features"> <a href="javascript:;"> <i class="icon-camera"></i> </a> <a href="javascript:;"> <i class="icon-link"></i> </a> <input type="button" class="btn btn-danger" name="AddTask" id="AddTask" value="Add" /> <input type="hidden" name="acct" id="acct" value="<?php echo $_REQUEST['acctname']?>"/> <input type="hidden" name="user" id="user" value="<?php $username = $_SESSION['username']; echo $username?>"/> <div id="result">result</div> </div> </div> <!-- js placed at the end of the document so the pages load faster --> <script src="js/jquery.js"></script> <script src="f_js/tasks/TaskTest.js"></script> <!--common script for all pages--> <script src="js/common-scripts.js"></script> <script type="text/javascript" src="assets/gritter/js/jquery.gritter.js"></script> <script src="js/gritter.js" type="text/javascript"></script> <script> </html> Firebug reponse: Response Headers Connection Keep-Alive Content-Length 0 Content-Type text/html Date Fri, 08 Nov 2013 21:48:50 GMT Keep-Alive timeout=5, max=100 Server Apache/2.4.4 (Win32) OpenSSL/0.9.8y PHP/5.4.16 X-Powered-By PHP/5.4.16 refresh 5; URL=index.php Request Headers Accept */* Accept-Encoding gzip, deflate Accept-Language en-US,en;q=0.5 Content-Length 13 Content-Type application/x-www-form-urlencoded; charset=UTF-8 Cookie PHPSESSID=6gufl3guiiddreg8cdlc0htnc6 Host localhost Referer http://localhost/betahtml/AccountView.php?acctname=client%201 User-Agent Mozilla/5.0 (Windows NT 6.3; WOW64; rv:25.0) Gecko/20100101 Firefox/25.0 X-Requested-With XMLHttpRequest

    Read the article

  • PHP MySQL Insert Data

    - by happyCoding25
    Hello, Im trying to insert data into a table in MySQL. I found/modified some code from w3Schools and still couldn't get it working. Heres what I have so far: <?php $rusername=$_POST['username']; $rname=$_POST['name']; $remail=$_POST['emailadr']; $rpassword=$_POST['pass']; $rconfirmpassword=$_POST['cpass']; if ($rpassword==$rconfirmpassword) { $con = mysql_connect("host","user","password"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("mydbname ", $con); } mysql_query("INSERT INTO members (id, username, password) VALUES ('4', $rusername, $rpassword)"); ?> Did I mistype something? To my understanding "members" is the name of the table. If anyone knows whats wrong I appreciate the help. Thanks

    Read the article

  • Function for getting localized path?

    - by MartinStettner
    Windows 7 (and probably Windows Vista) display localized folder names using the LocalizedResourceName entry in the desktop.ini file. For my Documents folder, this looks like [.ShellClassInfo] LocalizedResourceName=@%SystemRoot%\system32\shell32.dll,-21770 IconResource=%SystemRoot%\system32\imageres.dll,-112 IconFile=%SystemRoot%\system32\shell32.dll IconIndex=-235 (see this question) This way the explorer displays the path "C:\Users\Username\Documents" as "C:\Benutzer\Username\Dokumente" on a german Windows. I wonder, if there's any build-in shell function to automatically get this localized name or, even better, transform a whole path into its localized form (best would be anything in .NET)? This is even more interesting as the LocalizedResourceName entry is only documented for Windows CE (see here). Thanks Martin

    Read the article

< Previous Page | 91 92 93 94 95 96 97 98 99 100 101 102  | Next Page >