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  • How to write native SQL queries in Hibernate without hardcoding table names and fields?

    - by serg555
    Sometimes you have to write some of your queries in native SQL rather than hibernate HQL. Is there a nice way to avoid hardcoding table names and fields and get this data from existing mapping? For example instead of: String sql = "select user_name from tbl_user where user_id = :id"; something like: String sql = "select " + Hibernate.getFieldName("user.name") + " from " + Hibernate.getTableName(User.class) + " where " + Hibernate.getFieldName("user.id") + " = :id";

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  • Help for creating a random String

    - by Max
    I need to create a random string which should be between the length of 6 to 10 but it sometimes generates only about the length of 3 to 5. Here's my code. Can anyone would be able to find out the problem? :( int lengthOfName = (int)(Math.random() * 4) + 6; String name = ""; /* randomly choosing a name*/ for (int j = 0; j <= lengthOfName; j++) { int freq = (int)(Math.random() * 100) + 1; if(freq <= 6){ name += "a"; }if(freq == 7 && freq == 8){ name += "b"; }if(freq >= 9 && freq <= 11){ name += "c"; }if(freq >= 12 && freq <= 15){ name += "d"; }if(freq >= 16 && freq <= 25){ name += "e"; }if(freq == 26 && freq == 27){ name += "f"; }if(freq == 28 && freq == 29){ name += "g"; }if(freq >= 30 && freq <= 33){ name += "h"; }if(freq >= 34 && freq <= 48){ name += "i"; }if(freq == 49 && freq == 50){ name += "j"; }if(freq >= 51 && freq <= 55){ name += "k"; }if(freq >= 56 && freq <= 60){ name += "l"; }if(freq == 61 && freq == 62){ name += "m"; }if(freq >= 63 && freq <= 70){ name += "n"; }if(freq >= 71 && freq <= 75){ name += "o"; }if(freq == 76 && freq == 77){ name += "p"; }if(freq == 78){ name += "q"; }if(freq >= 79 && freq <= 84){ name += "r"; }if(freq == 85 && freq == 86){ name += "s"; }if(freq == 87 && freq == 88){ name += "t"; }if(freq >= 89 && freq <= 93){ name += "u"; }if(freq == 94){ name += "v"; }if(freq == 95 && freq == 96){ name += "w"; }if(freq == 97){ name += "x"; }if(freq == 98 && freq == 99){ name += "y"; }if(freq == 100){ name += "z"; } }

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  • Explicit constructor still has default values even though a default constructor is not invoked.

    - by Phoenix
    According to my understanding a default constructor initializes the state of the object to default values, so if i provide an explicit no-arg public constructor like this then how are the values of d and e still getting initialized to zero because in this case the default constructor is not invoked. public class B extends A{ private int d; private int e; public B() { System.out.println(d); System.out.println(e); } } EDIT:: The only thing default constructor does is call to super() then how come if i have a explicitly mentioned a constructor here and A has a protected variable say c which is initialized to 17 in its constructor. Should I not be explicitly calling super() to be able to see that change since I'm using my own constructor ? Why is B still getting the value of 17 through inheritance ?

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  • Android getSelectedItem, how to use?

    - by user1881184
    Im trying use the spinner control result in order to point it to another screen that would be on the app. For example in the spinner control if the user chose chevy it would then take you to another screen which is coded in chevy.xml and Chevy.class. This is what i have thus far and need some help, as our book only used getSelectedItem and the example was only for an output statement. Please help. import android.app.Activity; import android.content.Intent; import android.os.Bundle; import android.view.View; import android.widget.AdapterView; import android.widget.AdapterView.OnItemSelectedListener; import android.widget.Spinner; public class Mainpage extends Activity implements OnItemSelectedListener { String carChoice, chevy, ford, dodge, toyota; public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); /* carChoice = group.getSelectedItem().toString(); } if (carChoice.compareTo(chevy)==0) { startActivity(new Intent(Mainpage.this, Chevy.class)); */ } public void onItemSelected(AdapterView<?> arg0, View arg1, int arg2, long arg3) { final Spinner group = (Spinner) findViewById(R.id.carGroup); group.setOnItemSelectedListener(this); // TODO Auto-generated method stub String selected = group.getItemAtPosition(1).toString(); } public void onNothingSelected(AdapterView<?> arg0) { // TODO Auto-generated method stub } }

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  • Randomised objects are assigning themselves to more than one array location

    - by Thaddeus Aid
    this.size = 9; this.populationSize = 10; Random rand = new Random(); Integer[][] easy1 = new Integer[size][size]; easy1 = this.initializeEasy1(easy1); this.sudokuArray = new Sudoku[this.populationSize]; for (int i = 0; i < this.sudokuArray.length; i++){ long seed = rand.nextLong(); System.out.println("" + seed); this.sudokuArray[i] = new Sudoku(easy1, this.size, seed); } I am building an evolutionary sudoku solver and I am having a problem where the last Sudoku object is overwriting all the other objects in the array. Where in the code did I mess up? /edit here is the constructor of the class public Sudoku(Integer[][] givensGrid, int s, long seed){ this.size = s; this.givens = givensGrid; this.grid = this.givens.clone(); Random rand = new Random(seed); System.out.println("Random " + rand.nextInt()); // step though each row of the grid for (int i = 0; i < size; i++){ ArrayList<Integer> numbers = new ArrayList<Integer>(); numbers = this.makeNumbers(numbers); // step through each column to find the givens and remove from numbers for (int j = 0; j < size; j++){ if (this.grid[i][j] != 0){ numbers.remove(this.grid[i][j]); } } // go back through the row and assign the numbers randomly for (int j = 0; j < size; j++){ if (this.grid[i][j] == 0){ int r = rand.nextInt(numbers.size()); this.grid[i][j] = numbers.get(r); numbers.remove(r); } } } System.out.println("============="); System.out.println(this.toString()); }

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  • trying to run a named query

    - by dora
    hi, I’m doing the following: @Entity @SqlResultSetMapping(name="getxxxx", entities=@EntityResult(xxxx.class, fields = { @FieldResult(name="x1", column = "x1"), @FieldResult(name="x2", column = "x2")})) @NamedNativeQuery(name=" getxxxx ", query="select x1, x2 from yyyy", resultSetMapping=" getxxxx ") } )public class xxxx{ . . . public xxxx() { } i get an error: "Table "xxxx" cannot be resolved", the class xxxx is not a table mapped into my source, I’m trying to query the DB and return the results into my class is it possible?

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  • Strange performance behaviour

    - by plastilino
    I'm puzzled with this. In my machine Direct calculation: 375 ms Method calculation: 3594 ms, about TEN times SLOWER If I place the method calulation BEFORE the direct calculation, both times are SIMILAR. Woud you check it in your machine? class Test { static long COUNT = 50000 * 10000; private static long BEFORE; /*--------METHOD---------*/ public static final double hypotenuse(double a, double b) { return Math.sqrt(a * a + b * b); } /*--------TIMER---------*/ public static void getTime(String text) { if (BEFORE == 0) { BEFORE = System.currentTimeMillis(); return; } long now = System.currentTimeMillis(); long elapsed = (now - BEFORE); BEFORE = System.currentTimeMillis(); if (text.equals("")) { return; } String message = "\r\n" + text + "\r\n" + "Elapsed time: " + elapsed + " ms"; System.out.println(message); } public static void main(String[] args) { double a = 0.2223221101; double b = 122333.167; getTime(""); /*--------DIRECT CALCULATION---------*/ for (int i = 1; i < COUNT; i++) { Math.sqrt(a * a + b * b); } getTime("Direct: "); /*--------METHOD---------*/ for (int k = 1; k < COUNT; k++) { hypotenuse(a, b); } getTime("Method: "); } }

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  • Latex + Source Code Import

    - by KP65
    Hi guys, I'm using latex to write a program listing of all my code and am following this: http://texblog.wordpress.com/2008/04/02/include-source-code-in-latex-with-listings/ It works, but my code runs of the side of the page. How can i fix this? Thanks

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  • How to find out efficiently the auto-generated id for a new object when using JPA?

    - by webstarg
    Hello, I have an attribute which is annotated with @Id. The ID is going to be generated automatically when persisting the object. That means that the ID-value is not defined before I persist the object. After persisting it, it has an ID (in the database), but unfortunately the field still remains null as long as I don't reload it from the DB. is there any easy way to find out the generated id? Or better: To configure that it will be written into the field? Thanks in advance

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  • Practicing inserting data into an array by using binary search, few problems

    - by HelpNeeder
    I'm trying to create a method which inserts and then sort elements in form of binary form. The problem I am experiencing that my code doesn't insert data correctly which means that output does not appear to be in order at all. The list is not organized, and data is added in order that is being inserted. Now, 2 questions, what am I doing wrong here? And how to fix this? public void insertBinarySearch(long value) // put element into array { int j = 0; int lower = 0; int upper = elems-1; int cur = 0; while (cur < elems) { curIn = (lower + upper ) / 2; if(a[cur] < value) { j = cur + 1; break; } else if(a[cur] > value) { j = cur; break; } else { if(a[cur] < value) lower = cur + 1; else upper = cur - 1; } } for(int k = elems; k > j; k--) a[k] = a[k-1]; a[j] = value; elems++; }

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  • Why does Eclipse crash with Xmx, XX:MaxPermSize above certain values?

    - by alex
    Running Eclipse 3.5.1, JDK 1.6.0_17 on WinXP SP3 32Bit with 3.5 gigs of RAM. I'm aware of the known Eclipse best practices, still trying to figure out eclipse.ini. This will launch: -Xmx588m and this won't: -Xmx589m. Same with -XX:MaxPermSize. Anything above -XX:MaxPermSize=140m won't launch. The screen of death is simlar to this (taken from here). Any ideas on why might this be happening?

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  • How to get JOptionPane with three text fields

    - by Dr.Mostafa
    I want to know how i can do a messageBox from three input dialog .. Like this: JOptionPane.showInputMessageDialog("Enter your FirstName"); JOptionPane.showInputMessageDialog("Enter your MiddleName"); JOptionPane.showInputMessageDialog("Enter your LastName"); But I want one message has a three input boxes.

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  • user access management in j2ee web application

    - by kawtousse
    Hi everyone, I am working with jsp/servlet project and i have to complete the module of access management to my jsps since I have more than one user with different profile. I defined a table in my database wich resume the profil and the url permitted like that: id_profil :1 url : http://localhost/...xyz.jsp id page 1 Now I am trying to let the menu modified appropriately to the id_profil of the logged user. So there are pages allowed in one profile but must be hidden to others. I have no idea since now how to realize this and it is so important for me. thanks for your help.

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  • Compilation Error related

    - by aparna
    Given: 11. public static void test(String str) { 12. int check = 4; 13. if (check = str.length()) { 14. System.out.print(str.charAt(check -= 1) +", "); 15. } else { 16. System.out.print(str.charAt(0) + ", "); 17. } 18. } and the invocation: 21. test("four"); 22. test("tee"); 23. test("to"); What is the result? A. r, t, t, B. r, e, o, C. Compilation fails. D. An exception is thrown at runtime. Answer: C Can you explain why the compilation fails please?

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  • How can i pass an object to a new thread generated anonymously in a button listener

    - by WaterBoy
    I would like to pass an object (docket for printing) to a new thread which will print the docket. My code is: private final Button.OnClickListener cmdPrintOnClickListener = new Button.OnClickListener() { public void onClick(View v) { new Thread(new Runnable() { public void run() { enableTestButton(false); Looper.prepare(); doConnectionTest(); Looper.loop(); Looper.myLooper().quit(); } }).start(); } }; How do I pass the object to it? Also - I need to generate the object in the UI thread, just before starting the new thread so where could I put this method (e.g. getDocketObject()) in relation to my code below thanks, anton

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  • Printing a list using reflection

    - by TFool
    public class Service{ String serviceName; //setter and getter } public class Version{ String VersionID; //setter and getter } public void test(Object list){ //it shd print the obtained list } List< Service list1; //Service is a Bean List< Version list2; //Version is a Bean test(list1); test(list2); Now the test method shd print the obtained list - (i.e) If the list is of type Service ,then serviceName should be printed using its getter. If the list type is Version versionID should be printed. Is it possible to achieve this without using Interface or abstract class?

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  • Is catching NumberFormatException a bad practice?

    - by integeruser
    I have to parse a String that can assume hex values or other non-hex values 0xff, 0x31 or A, PC, label, and so on. I use this code to divide the two cases: String input = readInput(); try { int hex = Integer.decode(input); // use hex ... } catch (NumberFormatException e) { // input is not a hex, continue parsing } Can this code be considered "ugly" or difficult to read? Are there other (maybe more elegant) solutions? EDIT : I want to clarify that (in my case) a wrong input doesn't exist: i just need to distinguish if it is a hex number, or not. And just for completeness, i'm making a simple assebler for DCPU-16.

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  • Counting substring, while loop

    - by user1554786
    public class SubstringCount { public static void main(String[] args) { Scanner scan = new Scanner(System.in); System.out.println("Enter a word longer than 4 characters, and press q to quit"); int count = 0; while (scan.hasNextLine()) { System.out.println("Enter a word longer than 4 characters, and press q to quit"); String word = scan.next(); if (word.substring(0,4).equals("Stir")) { count++; System.out.println("Enter a word longer than 4 characters, and press q to quit"); scan.next(); } else if (word.equals("q")) { System.out.println("You have " + count + ("words with 'Stir' in them")); } else if (!word.substring(0,4).equals("Stir")) { System.out.println("Enter a word longer than 4 characters, and press q to quit"); scan.next(); } } } } Here I need to print how many words entered by the user contain the substring 'Stir.' However I'm not sure how to get this to work, or if I've done any of it right in the first place! Thanks for any help!

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  • Is it possible to create a timer in jscript that you can manually change without it being affected by timezones?

    - by Lixorp
    is it possible to create a timer where I can manually set the hours each day to a set number of hours but still remains accurate? For example; if I set the countdown for 5 hours at 2pm I want the timer to stop as soon as it hits 7pm. Also, when I set the timer for 5 hours I would like everyone in the world to see it countdown from 5 hours, no matter what the time is in their country. In the format: days hours minutes seconds. The reason I want to do this is for a streamer's website. He needs a flexible timer which can be manually changed and is the same worldwide for his viewers to know when he starts streaming. The current timer we're using at the moment; setInterval(function(){ var currentTime = new Date(); if(currentTime.getHours() > 19){ var countdownHours = (24 - currentTime.getHours()) + 19; }else if(currentTime.getHours() < 19){ var countdownHours = 19 - currentTime.getHours(); }else{ var countdownHours = 0; } var countdownMins = 59 - currentTime.getMinutes(); var countdownSecs = 60 - currentTime.getSeconds(); $('#countdown-days h1').text('0'); $('#countdown-hours h1').text(countdownHours); $('#countdown-minutes h1').text(countdownMins); $('#countdown-seconds h1').text(countdownSecs); }, 1000); As you can tell it isn't ideal for what we need it for since it counts down to 7pm in the timezone you're in. Any help/examples would be greatly appreciated, Thank you in advance, Lixorp.

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