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  • It is only uploading first row's file input

    - by user1304328
    I have a application which you can access here. If you open the application please click on the "Add" button a couple of times. This will add a new row into a table below. In each table row there is an AJAX file uploader. Now the problem is that if I click on the "Upload" button in any row except the first row, then the uploading only happens in the first row so it is only uploading the first file input only. Why is it doing this and how can I get it so that when then the user clicks the "Upload" button, the file input within that row of the "Upload" button is uploaded and not the first row being uploaded? Below is the full code where it appends the file AJAX file uploaded in each table row: function insertQuestion(form) { var $tbody = $('#qandatbl > tbody'); var $tr = $("<tr class='optionAndAnswer' align='center'></tr>"); var $image = $("<td class='image'></td>"); var $fileImage = $("<form action='upload.php' method='post' enctype='multipart/form-data' target='upload_target' onsubmit='startUpload();' >" + "<p id='f1_upload_process' align='center'>Loading...<br/><img src='Images/loader.gif' /><br/></p><p id='f1_upload_form' align='center'><br/><label>" + "File: <input name='fileImage' type='file' class='fileImage' /></label><br/><label><input type='submit' name='submitBtn' class='sbtn' value='Upload' /></label>" + "</p> <iframe id='upload_target' name='upload_target' src='#' style='width:0;height:0;border:0px solid #fff;'></iframe></form>"); $image.append($fileImage); $tr.append($image); $tbody.append($tr); } function startUpload(){ document.getElementById('f1_upload_process').style.visibility = 'visible'; document.getElementById('f1_upload_form').style.visibility = 'hidden'; return true; } function stopUpload(success){ var result = ''; if (success == 1){ result = '<span class="msg">The file was uploaded successfully!<\/span><br/><br/>'; } else { result = '<span class="emsg">There was an error during file upload!<\/span><br/><br/>'; } document.getElementById('f1_upload_process').style.visibility = 'hidden'; document.getElementById('f1_upload_form').innerHTML = result + '<label>File: <input name="fileImage" type="file"/><\/label><label><input type="submit" name="submitBtn" class="sbtn" value="Upload" /><\/label>'; document.getElementById('f1_upload_form').style.visibility = 'visible'; return true; }

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  • User submitted posts in wordpress 3.0

    - by user338109
    I am in the middle of building a site with user submitted posts that let the user upload a zip file along with images. At the moment I am using TDO-Miniforms and wordpress 2.9.2, but TDO-miniforms has stopped development and is broken with wordpress 3.0 that just came out. I would like to update the site to 3.0 but I don't know of any alternatives to TDO-miniforms that let logged in users submit posts with attachments and images. Any alternatives?

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  • C++ keeping a list of objects and calling a contructor through another function

    - by Nona Urbiz
    why isnt my object being created? When I do it like so, I am told error C2065: 'AllReferrals' : undeclared identifier as well as error C2228: left of '.push_back' must have class/struct/union. If I put the list initialization before the class I get error C2065: 'AllReferrals' : undeclared identifier. Thanks! #include <iostream> #include <fstream> #include <regex> #include <string> #include <list> #include <map> using namespace std; using namespace tr1; class Referral { public: string url; map<string, int> keywords; static bool submit(string url, string keyword, int occurrences) { //if(lots of things i'll later add){ Referral(url, keyword, occurrences); return true; //} //else // return false; } private: list<string> urls; Referral(string url, string keyword, int occurrences) { url = url; keywords[keyword] = occurrences; AllReferrals.push_back(this); } }; static list<Referral> AllReferrals; int main() { Referral::submit("url", "keyword", 1); cout << AllReferrals.size(); cout << "\n why does that ^^ say 0 (help me make it say one)?"; cout << "\n and how can i AllReferrals.push_back(this) from my constructor?"; cout << " When I do it like so, I am told error C2065: 'AllReferrals' : undeclared identifier"; cout << " as well as error C2228: left of '.push_back' must have class/struct/union."; cout << " If I put the list initialization before the class I get error C2065: 'AllReferrals' : undeclared identifier."; cout << "\n\n\t Thanks!"; getchar(); }

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  • Is there a way to opt-out from WP8 when submiting an Windows Phone app?

    - by Igor Kulman
    I have a Windows Phone app build using the 7.1 SDK that works great on WP7 but does not work at all on WP8 (I am using multicast using UDP and WP8 can join the group but send/receives no message for some reason, other people having the same problem: UDP multicast group on Windows Phone 8). Is there a way to opt-out from WP8 when I submit my app? I just want the app to be available t WP7 users. I am looking for something like the 256MB opt-out option.

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  • Faster alternative to file_get_contents()

    - by Rob
    Currently I'm using file_get_contents() to submit GET data to an array of sites, but upon execution of the page I get this error: Fatal error: Maximum execution time of 30 seconds exceeded All I really want the script to do is start loading the webpage, and then leave. Each webpage may take up to 5 minutes to load fully, and I don't need it to load fully. Here is what I currently have: foreach($sites as $s) //Create one line to read from a wide array { file_get_contents($s['url']); // Send to the shells }

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  • Receiving the post response using curl

    - by Larry Battle
    Hello, I'm trying to make a script that will download search results from a HTTPS website using POST. So far, I'm able to download the web page before the submission but not the response page containing the search results. The problem seems to be that curl isn't waiting long enough for the response page to appear. The website behaviors likes this. Website appears- input form data - click submit - progressing icon appears - returns new web page with search results( new data but the url doesn't change ) My code: curl -d "postData" -k url

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  • Sending/printing a key with jQuery.Trigger

    - by adir
    i think i have read every page google knows about which has these keywords, and nothing works for me. what i have is a form input, and a button next to it [not submit], and what i want is for the button click to trigger an 'enter' key click. [this will respectively run another function which is already working..] i've tried and also putting it in a function and then running it from onclick, or making a $(#'inputBtn').click(function()..... nothing works for me please help!!

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  • How to get Google Search Query Kind of Content Indexed ?

    - by Sunil
    Hello: I was looking for something like flash grabber and I came across this result http://www.giveawayoftheday.com/flash+grabber+firefox/ I am just wondering how giveawayoftheday has managed to get "flash+grabber+firefox/" indexed in Google ? Did they submit via Google Sitemap or is Google doing this on its own ? Or something else ? Kindly enlighten. Thanks.

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  • SEO for Computer Software Engineering Topics

    - by Michael Aaron Safyan
    I'm currently trying to SEO my development and coding search custom search engine as well my website that has a variety of coding and development resources. I would like to increase the number of links to my website, but I don't want to simply generate spam. What are some places that I should submit my website, where the content would be considered relevant rather than just spam? Thanks.

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  • Not allowing characters after Space. Mysql Insert With PHP

    - by Jake
    Ok so I think this is easy but I dont know (I'm a novice to PHP and MySQL). I have a select that is getting data from a table in the database. I am simply taking whatever options the user selects and putting it into a separate table with a php mysql insert statement. But I am having a problem. When I hit submit, everything is submitted properly except for any select options that have spaces don't submit after the first space. For example if the option was COMPUTER REPAIR, all that would get sent is COMPUTER. I will post code if needed, and any help would be greatly appreciated. Thanks! Ok here is my select code: <?php include("./config.php"); $query="SELECT id,name FROM category_names ORDER BY name"; $result = mysql_query ($query); echo"<div style='overflow:auto;width:100%'><label>Categories (Pick three that describe your business)</label><br/><select name='select1'><option value='0'>Please Select A Category</option>"; // printing the list box select command while($catinfo=mysql_fetch_array($result)){//Array or records stored in $nt echo "<option>$catinfo[name]</option><br/> "; } echo"</select></div>"; ?> And here is my insert code ( Just to let you know its got everything not just the select!) ?php require("./config.php"); $companyname = mysql_real_escape_string(addslashes(trim($_REQUEST['name']))); $phone = mysql_real_escape_string(addslashes($_REQUEST['phone'])); $zipcode = mysql_real_escape_string(addslashes($_REQUEST['zipcode'])); $city = mysql_real_escape_string(addslashes($_REQUEST['city'])); $description = mysql_real_escape_string(addslashes($_REQUEST['description'])); $website = mysql_real_escape_string(addslashes($_REQUEST['website'])); $address = mysql_real_escape_string(addslashes($_REQUEST['address'])); $other = mysql_real_escape_string(addslashes($_REQUEST['other'])); $payment = mysql_real_escape_string(addslashes($_REQUEST['payment'])); $products = mysql_real_escape_string(addslashes($_REQUEST['products'])); $email = mysql_real_escape_string(addslashes($_REQUEST['email'])); $select1 = mysql_real_escape_string(addslashes($_REQUEST['select1'])); $select2 = mysql_real_escape_string(addslashes($_REQUEST['select2'])); $select3 = mysql_real_escape_string(addslashes($_REQUEST['select3'])); $save=$_POST['save']; if(!empty($save)){ $sql="INSERT INTO gj (name, phone, city, zipcode, description, dateadded, website, address1, other2, payment_options, Products, email,cat1,cat2,cat3) VALUES ('$companyname','$phone','$city','$zipcode','$description',curdate(),'$website','$address','$other','$payment','$products','$email','$select1','$select2','$select3')"; if (!mysql_query($sql,$link)) { die('Error: ' . mysql_error()); } echo "<br/><h2><font color='green' style='font-size:15px'>1 business added</font></h2>"; mysql_close($link); } ?>

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  • To run two CGIs simultaneously

    - by Punit
    On my form onbutton submit following events takes place: 1) CGI is called which uploads the file 2) Javascript/Ajax function is called which opens a request for another CGI and is supposed to receive updated values from there. However, it seems that the CGI with which Ajax is communicating is not responding to Ajax requests. My question is that is it possible to run two CGIs simultaneously?

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  • What does the MVC Controller.UpdateModel<T>(T) actually try to do?

    - by unanswered
    When I submit my MVC Page I get an IvalidOperationException from System.Web.Mvc Controller object in the UpdateModel method. the MSDN documentation states that this method does the following: Updates the specified model instance using values from the controller's current value provider. Is the value provider referencing the current Request object? Or where exactly does it get the values that it is using to update the model? And what specifically does the UpdateModel method check and what does it 'mean' when it says that The model of type 'abcXYZ' was not successfully updated Thanks

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  • Script to create a table and fields in SQL wont work

    - by Jacksta
    Warning this is lenghty! attack if you knowledagble. well at least more then a newb beginner like me. This script uses three files as detailed below. It is suppoed to create the database and fields from the form input. It gets to the end and shows my_contacts has been created!. But when i go into phpMyadmin the table has not been created. I have a file named show_createtable.html which is used to create a table in MySQL <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <h1>Step 1: Name and Number</h1> <form method="post" action="do_showfielddef.php" /> <p><strong>Table Name:</strong><br /> <input type="text" name="table_name" size="30" /></p> <p><strong>Number of fields:</strong><br /> <input type="text" name="num_fields" size="30" /></p> <p><input type="submit" name="submit" value="go to step2" /></p> </form> </body> </html> This Form Posts to do_showfielddef.php <?php //validate important input if ((!$_POST[table_name]) || (!$_POST[num_fields])) { header( "location: show_createtable.html"); exit; } //begin creating form for display $form_block = " <form action=\"do_createtable.php\" method=\"post\"> <input name=\"table_name\" type=\"hidden\" value=\"$_POST[table_name]\"> <table cellspacing=\"5\" cellpadding=\"5\"> <tr> <th>Field Name</th><th>Field Type</th><th>Table Length</th><th>Primary Key?</th><th>Auto-Increment?</th> </tr>"; //count from 0 until you reach the number fo fields for ($i = 0; $i <$_POST[num_fields]; $i++) { $form_block .=" <tr> <td align=center><input type=\"texr\" name=\"field name[]\" size=\"30\"></td> <td align=center> <select name=\"field_type[]\"> <option value=\"char\">char</option> <option value=\"date\">date</option> <option value=\"float\">float</option> <option value=\"int\">int</option> <option value=\"text\">text</option> <option value=\"varchar\">varchar</option> </select> </td> <td align=center><input type=\"text\" name=\"field_length[]\" size=\"5\"></td> <td aligh=center><input type=\"checkbox\" name=\"primary[]\" value=\"Y\"></td> <td aligh=center><input type=\"checkbox\" name=\"auto_increment[]\" value=\"Y\"></td> </tr>"; } //finish up the form $form_block .= " <tr> <td align=center colspan=3><input type =\"submit\" value=\"create table\"> </td> </tr> </table> </form>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create a database table: Step 2</title> </head> <body> <h1>defnie fields for <? echo "$_POST[table_name]"; ?> </h1> <? echo "$form_block"; ?> </body> </html> Which in turn creates the table and fields with this file do_showfielddef.php //connect to database $connection = @mysql_connect("localhost", "user", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); //start creating the SQL statement $sql = "CREATE TABLE $_POST[table_name]("; //continue the SQL statement for each new field for ($i = 0; $i < count($_POST[field_name]); $i++) { $sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i]; if ($_POST[auto_increment][$i] =="Y") { $additional = "NOT NULL auto_increment"; } else { $additional = ""; } if ($_POST[primary][$i] =="Y") { $additional .= ", primary key (".$_POST[field_name][$i].")"; } else { $additional = ""; } if ($_POST[field_length][$i] !="") { $sql .= " (".$_POST[field_length][$i].") $additional ,"; } else { $sql .=" $additional ,"; } } //clean up the end of the string $sql = substr($sql, 0, -1); $sql .= ")"; //execute the query $result = mysql_query($sql, $connection) or die(mysql_error()); //get a giid message for display upon success if ($result) { $msg = "<p>" .$_POST[table_name]." has been created!</p>"; } ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create A Database Table: Step 3</title> </head> <body> <h1>Adding table to <? echo "$db_name"; ?>...</h1> <? echo "$msg"; ?> </body> </html>

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  • how to upload a audio file using REST webservice in Google App Engine for Java

    - by sathya
    Am using google app engine with eclipse IDE and trying to upload a audio file. I used the File Upload in Google App Engine For Java and can able to upload the file successfully. Now am planning to use REST web service for it. I had analyzed in developers.google but i failed. Can anyone suggest me how to implement REST Web services in google app engine using Eclipse. The code google provided is shown below, // file Upload.java public class Upload extends HttpServlet { private BlobstoreService blobstoreService = BlobstoreServiceFactory.getBlobstoreService(); public void doPost(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException { Map<String, BlobKey> blobs = blobstoreService.getUploadedBlobs(req); BlobKey blobKey = blobs.get("myFile"); if (blobKey == null) { res.sendRedirect("/"); } else { res.sendRedirect("/serve?blob-key=" + blobKey.getKeyString()); }}} // file Serve.java public class Serve extends HttpServlet { private BlobstoreService blobstoreService = BlobstoreServiceFactory.getBlobstoreService(); public void doGet(HttpServletRequest req, HttpServletResponse res) throws IOException { BlobKey blobKey = new BlobKey(req.getParameter("blob-key")); blobstoreService.serve(blobKey, res); }} // file index.jsp <%@ page import="com.google.appengine.api.blobstore.BlobstoreServiceFactory" %> <%@ page import="com.google.appengine.api.blobstore.BlobstoreService" %> <% BlobstoreService blobstoreService = BlobstoreServiceFactory.getBlobstoreService(); %> <form action="<%= blobstoreService.createUploadUrl("/upload") %>" method="post" enctype="multipart/form-data"> <input type="file" name="myFile"> <input type="submit" value="Submit"> </form> // web.xml <servlet> <servlet-name>Upload</servlet-name> <servlet-class>Upload</servlet-class> </servlet> <servlet> <servlet-name>Serve</servlet-name> <servlet-class>Serve</servlet-class> </servlet> <servlet-mapping> <servlet-name>Upload</servlet-name> <url-pattern>/upload</url-pattern> </servlet-mapping> <servlet-mapping> <servlet-name>Serve</servlet-name> <url-pattern>/serve</url-pattern> </servlet-mapping> Now how to provide a rest web service for the above code. Kindly suggest me an idea.

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  • jquery function call with parameters

    - by Kaushik Gopal
    Hi a newb question: I have a table with a bunch of buttons like so: <tr class="hr-table-cell" > <td>REcord 1</td> <td> <INPUT type="button" value="Approve" onclick="" /> <INPUT type="button" value="Reject" onclick="" /> <INPUT type="button" value="Delete" onclick="fnDeletePpAppl(222445,704);" /> </td> </tr> <tr class="hr-table-cell" > <td>REcord 1</td> <td align="center" class="hr-table-bottom-blue-border" valign="middle"> <INPUT type="button" value="Approve" onclick="" /> <INPUT type="button" value="Reject" onclick="" /> <INPUT type="button" value="Delete" onclick="fnDeletePpAppl(237760,776);" /> </td> </tr> I have my jquery like so: <script type="text/javascript"> // JQUERY stuff $(document).ready(function(){ function fnDeletePpAppl(empno, applno) { alert('Entering here'); $("form").get(0).empno.value = empno; $("form").get(0).applNo.value = applno; $("form").get(0).listPageAction.value = "delete"; $("form").get(0).action.value = "pprelreqlist.do"; $("form").get(0).submit(); } }); This doesn't seem to work.I thought this means, the function is ready only after the dom is ready. After the dom is ready and i click the button, why is not recognizing the function declaration within the .ready() function? However if i use the function directly: <script type="text/javascript"> function fnDeletePpAppl(empno, applno) { alert('Entering here'); $("form").get(0).empno.value = empno; $("form").get(0).applNo.value = applno; $("form").get(0).listPageAction.value = "delete"; $("form").get(0).action.value = "pprelreqlist.do"; $("form").get(0).submit(); } This works. I want to get my fundamentals straight here... If i do the declaration without the .ready() , does that mean i'm using plain vanilla jscript? If i were to do this with the document.ready - the usual jquery declaration way, what would i have to change to make it work? I understand there are much better ways to do this like binding with buttons etc, but I want to know why this particular way doesn't seem to be working. Thanks. Cheers. K

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  • SAS on OS X any way to run without working within virtual machine?

    - by user309284
    I would like to edit and submit SAS code from emacs (aquamacs) on OS X to SAS running on Vista (through Parallels). Any idea how to do this? I like to do everything through one place and it is really annoying to work within the windows emulator. I have run SAS from a linux server through aquamacs but wonder if something similar can be done locally. Any ideas?

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  • php how to open new tab or new window

    - by dpaksp
    in php my task here is before user downloads a file i have display a form thr where i can get details of user i.e form1...on click on submit button it will go to next php file where it process some logic...from thr i have open new tab or new window in that i have display my file or any thing ....how to do thank u

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  • Uploading photo from my website, and send it via email.

    - by Sohail
    Hello everybody, I have a form, which gathers some Information of my visitor, and when they submit the Information, it will send it to my desired email. now I need another input "file" that they can even attach their photo and send along with it to my email not on my server, I have no Idea how can I do that, I would appreciate any helps.

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  • PHP syntax error “unexpected $end”

    - by Jacksta
    I have 3 files 1) show_createtable.html 2) do_showfielddef.php 3) do_showtble.php 1) First file is for creating a new table for a data base, it is a fom with 2 inputs, Table Name and Number of Fields. THIS WORKS FINE! <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <h1>Step 1: Name and Number</h1> <form method="post" action="do_showfielddef.php" /> <p><strong>Table Name:</strong><br /> <input type="text" name="table_name" size="30" /></p> <p><strong>Number of fields:</strong><br /> <input type="text" name="num_fields" size="30" /></p> <p><input type="submit" name="submit" value="go to step2" /></p> </form> </body> </html> 2) this script validates fields and createa another form to enter all the table rows. This for also WORKS FINE! <?php //validate important input if ((!$_POST[table_name]) || (!$_POST[num_fields])) { header( "location: show_createtable.html"); exit; } //begin creating form for display $form_block = " <form action=\"do_createtable.php\" method=\"post\"> <input name=\"table_name\" type=\"hidden\" value=\"$_POST[table_name]\"> <table cellspacing=\"5\" cellpadding=\"5\"> <tr> <th>Field Name</th><th>Field Type</th><th>Table Length</th> </tr>"; //count from 0 until you reach the number fo fields for ($i = 0; $i <$_POST[num_fields]; $i++) { $form_block .=" <tr> <td align=center><input type=\"texr\" name=\"field name[]\" size=\"30\"></td> <td align=center> <select name=\"field_type[]\"> <option value=\"char\">char</option> <option value=\"date\">date</option> <option value=\"float\">float</option> <option value=\"int\">int</option> <option value=\"text\">text</option> <option value=\"varchar\">varchar</option> </select> </td> <td align=center><input type=\"text\" name=\"field_length[]\" size=\"5\"> </td> </tr>"; } //finish up the form $form_block .= " <tr> <td align=center colspan=3><input type =\"submit\" value=\"create table\"> </td> </tr> </table> </form>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create a database table: Step 2</title> </head> <body> <h1>defnie fields for <? echo "$_POST[table_name]"; ?> </h1> <? echo "$form_block"; ?> </body> </html> Problem is here 3) this form creates the tables and enteres them into the database. I am getting an error on line 37 "Parse error: syntax error, unexpected $end in /home/admin/domains/domaina.com.au/public_html/do_createtable.php on line 37" <? $db_name = "testDB"; $connection = @mysql_connect("localhost", "admin_user", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "CREATE TABLE $_POST[table_name]("; for ($i = 0; $i < count($_POST[field_name]); $i++) { $sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i]; if ($_POST[field_length][$i] !="") { $sql .=" (".$_POST[field_length][$i]."),"; } else { $sql .=","; } $sql = substr($sql, 0, -1); $sql .= ")"; $result = mysql_query($sql, $connection) or die(mysql_error()); if ($result) { $msg = "<p>" .$_POST[table_name]." has been created!</p>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create A Database Table: Step 3</title> </head> <body> <h1>Adding table to <? echo "$db_name"; ?>...</h1> <? echo "$msg"; ?> </body> </html>

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  • saving nested attributes

    - by Victor Martins
    I have a form that has a nested form like this: <%- for subscription in @task.subscriptions -% <%- semantic_fields_for "task[subscription_attributes][]", subscription do |subscription_form|% <%- subscription_form.inputs do -% <%= subscription_form.input :workhours, :label = subscription.user.full_name% <%- end -% <%- end -% <%- end -% And on the task model I have: accepts_nested_attributes_for :subscriptions attr_accessible :mission_id, :statuscode_id, :name, :objectives, :start_at , :end_at, :hours, :testimony ,:subscriptions_attributes In the form (view) I get the correct values on the workhours fields. But when I change the values and hit the submit button, the values are never changed. I can't figure out why...

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  • jquery validation plugin doesn't seem to work ....

    - by Pandiya Chendur
    asp.net mvc's Html.BeginForm() seems to work with jquery validation plugin but the validation plugin doesn't seem to work with a form which i ve added to a page.... This works, <% using (Html.BeginForm("Login", "Registration", FormMethod.Post, new { id = "Loginform" })) {%> <fieldset> <legend>Login</legend> <p> <label for="EmailId">EmailId:</label> <%= Html.TextBox("EmailId", null, new { @class = "text_box_height_14_width_150" })%> </p> <div class="status"></div> <p> <label for="Password">Password:</label> <%= Html.Password("Password",null, new { @class = "text_box_height_14_width_150" }) %> </p> <div class="status"></div> <p> <input type="submit" value="Login" id="login" /> </p> </fieldset> <% } %> But this doesn't work, <form id="Loginform" method="post" action="Registration/Login"> <table cellpadding="0" cellspacing="0" width="100%" style="border:none;"> <tr> <td width="12%">Email Id&nbsp;:&nbsp;</td><td width="15%"> <input id="EmailId" type="text" class="text_box_height_14_width_150 name="EmailId" /></td><td width="20%" class="status"></td> <td width="12%">Password&nbsp;:&nbsp;<td width="15%"><input id="Password" type="password" class="text_box_height_14_width_150 name="Password" /></td> <td width="20%" class="status"></td> <td width="5%"><input type="submit" value="Login" id="BtnLogin" /></td> </tr> </table> </form> and my jquery function has this, $(document).ready(function() { var validator = $("#Loginform").validate({ rules: { EmailId: "required", Password: { required: true, minlength: 6 } }, messages: { EmailId: "Enter your EMail ID", Password: { required: "Please Provide a password", rangelength: jQuery.format("Enter at least {0} characters") } }, // the errorPlacement has to take the table layout into account errorPlacement: function(error, element) { error.appendTo(element.parent().next()); }, // set this class to error-labels to indicate valid fields success: function(label) { // set &nbsp; as text for IE label.html("&nbsp;").addClass("checked"); } }); }); Any suggestion... Am i missing something?

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