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  • Displaying shifts on a timetable/calendar using C#

    - by Dave Peters
    I am very much a beginner and have experience of SQL and a tiny amount of VBA. What I am looking to do is create a tool to pull shift times from a database and to display them on a timetable/calendar. It will be part of a desktop application that the (very tech illiterate) end users will use to view and amend shift patterns. In essence it will be a grid with days on one axis and people on the other (I would however like to have the blocks proportional to shift length). In my mind it would potentially be a simple Gantt chart. All computing stuff I’ve learnt has been through trial and error and I want to use this project to get a much better understanding of C# as well as to get to the end product. I have been reading around for ways to tackle the problem and my issue is creating the timetable framework to which I will bind the data. I am using Visual Studio 2010 and SQL Server 2008 R2. Do you know of good resources which will either start me on the road to designing my own interface or give a basic framework I can adapt? All the resources I’ve found so far have been in different languages or for web based applications. Thank you for your time.

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  • jsf and huge web site

    - by darko petreski
    Hi All, I need to program a very huge web site. The site should contain public part with search engine, user registration forms, cart and all other stuff. The private part should contain administrative web application with a lot of data grids, complex edit forms, security checks, services and so on. Also I need very good support for html mailing and pdf exports. Web services are also required. I am considering to use jsf. Can you recommend me books or other stuff where I can find all this info for building what i need? Is seam good option for this? I have looked their site and page seam on production. The sites listed there are far from professional and enterprise. Is there any book that explains how to build complete web site with jsf technology from login, security, sending mails, pdf conversion, time dependent background processes and everything else that big sites needs. I do not have time reading 20 books. In every php book all this stuff is explained but I have not seen a single java book that at least from high view will explain all of this. Regards

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  • BackgroundColor of UITableViewCellStyleSubtitle labels ??!?

    - by P5ycH0
    I am trying to create a table with an image as a background. To achieve this, I started out with the background: self.view.backgroundColor = [UIColor groupTableViewBackgroundColor]; This resulted in a background image which appears in tablecells as well. That is not something I want, so I tried to set the cell's backgroundColor: cell.backgroundColor = [UIColor whiteColor]; This had no effect at all !!!. Hmmm strange. So I tried this: UIView *backgroundView = [[UIView alloc] init]; backgroundView.backgroundColor = [UIColor whiteColor]; cell.backgroundView = backgroundView; [backgroundView release]; This works almost. The only problem left is that the textLabel & the detailTextLabel still show the background behind them. Setting the backgroundColor on those labels to white doesn't do anything either. How do I proceed? Where do I go wrong? I am trying to achieve a tableView like the worldClock app has.

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  • How to show server errors in Rails 2.3.5 with JSON and jQuery

    - by Fortuity
    I've got in-place editing on a page in my app (using Rails 2.3.5 and jQuery). I want to know how to display an error on the page when the update fails. I'm using ajax (an XMLHttpRequest) to save an update to a Comment object. The controller has an update method like this: def update @comment = Comment.find(params[:id]) respond_to do |format| # if @comment.update_attributes!(params[:comment]) if false #deliberately forcing a fail here to see what happens format.json { render :nothing => true } else format.json { render :json => @comment.errors, :status => :unprocessable_entity } end end end In Firebug, I can see the server returns a "422" (an appropriate validation error status code). But it's a response to an XMLHttpRequest so there is no redirect to an error page. I think I actually want to do this: format.json { render :json => @comment.errors} or maybe this: format.json {render :json => { :status => :error, :message => "Could not be saved" }.to_json, :status => 400 } and trigger some Javascript function that iterates through (and displays) any errors. I'm using a rails plugin http://github.com/janv/rest_in_place/ to implement the in-place editing. It doesn't appear to have any callback function to handle a failure. What are my options? Can I write some Javascript to respond to a failure condition without hacking the plugin? Do I have to hack the rest_in_place plugin to handle a failure condition? Is there a better plugin (for Rails or jQuery) that handles in-place editing, including failure conditions? UPDATE This post from Peter Bui (http://paydrotalks.com/posts/45-standard-json-response-for-rails-and-jquery) was helpful in showing how to handle an error message from the server using XMLHttpRequest.status. I looked at his implementation of a blog using ajax (http://github.com/paydro/talks). I'm surprised at the complexity required to handle a simple error condition. Usually Rails has all the goodness baked in but it seems server errors with JSON are out of scope. Can that be? I also looked at grimen's validatious-on-rails (http://github.com/grimen/validatious-on-rails/) which accommodates models validations when ajax XMLHttpRequest is used. It's not clear to me how I'd use it to handle the general case of a "save" failing when validations succeed. P.S. Please vote me up... so I can use more than one HTML link when I ask my question :-)

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  • iPhone app doesn't build crash reports

    - by BankStrong
    My app formerly created useful crash logs. I synced my iPhone in the past and found crash logs in library/logs/CrashReporter About a month ago, my app stopped creating crash reports. When I first discovered this problem, I assumed it was due to memory corruption (a possibility in my app). I just created a new project and added a crash to it. // Implement viewDidLoad to do additional setup after loading the view, // typically from a nib. - (void)viewDidLoad { NSMutableArray *array = [[NSMutableArray alloc] init]; [array removeObjectAtIndex:-1]; [super viewDidLoad]; } This app does not create a crash report either. Ideas I've started to explore: My phone is corrupted (tried restoring - somehow I brought it to the state from a few months ago) My XCode is corrupt (tried reinstalling, but current download demands Snow Leopard - and I can't upgrade to Snow Leopard online). This seems possible - I may have messed with device support around a month ago (similar to http://stackoverflow.com/questions/1224867/does-iphone-os-3-0-1-ruin-your-development-phone ) The location for crash logs has somehow moved. Suggestions?

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  • Can a call to WaitHandle.SignalAndWait be ignored for performance profiling purposes?

    - by Dan Tao
    I just downloaded the trial version of ANTS Performance Profiler from Red Gate and am investigating some of my team's code. Immediately I notice that there's a particular section of code that ANTS is reporting as eating up to 99% CPU time. I am completely unfamiliar with ANTS or performance profiling in general (that is, aside from self-profiling using what I'm sure are extremely crude and frowned-upon methods such as double timeToComplete = (endTime - startTime).TotalSeconds), so I'm still fiddling around with the application and figuring out how it's used. But I did call the developer responsible for the code in question and his immediate reaction was "Yeah, that doesn't surprise me that it says that; but that code calls SignalAndWait [which I could see for myself, thanks to ANTS], which doesn't use any CPU, it just sits there waiting for something to do." He advised me to simply ignore that code and look for anything ELSE I could find. My question: is it true that SignalAndWait requires NO CPU overhead (and if so, how is this possible?), and is it reasonable that a performance profiler would view it as taking up 99% CPU time? I find this particularly curious because, if it's at 99%, that would suggest that our application is often idle, wouldn't it? And yet its performance has become rather sluggish lately. Like I said, I really am just a beginner when it comes to this tool, and I don't know anything about the WaitHandle class. So ANY information to help me to understand what's going on here would be appreciated.

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  • AVAudioPlayer only initializes with some files

    - by Brendan
    Hi everyone, I'm having trouble playing some files with AVAudioPlayer. When I try to play a certain m4a, it works fine. It also works with an mp3 that I try. However it fails on one particular mp3 every time (15 Step, by Radiohead), regardless of the order in which I try to play them. The audio just does not play, though the view loading and everything that happens concurrently happens correctly. The code is below. I get the "Player loaded." log output on the other two songs, but not on 15 Step. I know the file path is correct (I have it log outputted earlier in the app, and it is correct). Any ideas? NSData *musicData = [NSData dataWithContentsOfURL:[[NSURL alloc] initFileURLWithPath:[[NSBundle mainBundle] pathForResource:[song filename] ofType:nil]]]; NSLog([[NSBundle mainBundle] pathForResource:[song filename] ofType:nil]); if(musicData) { NSLog(@"File found."); } self.songView.player = [[AVAudioPlayer alloc] initWithData:musicData error:nil]; if(self.songView.player) { NSLog(@"Player loaded."); } [self.songView.player play]; NSLog(@"You should be hearing something now."); Thanks, Brendan

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  • Quick question - how to comment if-else structure?

    - by serg555
    Lets say you have: if(condition) { i = 1; } else { i = 2; } and you need to put comments explaining if and else blocks. What's the most readable way of doing it so someone can easily pick them up at first glance? I usually do it like this: //check for condition if(condition) { i = 1; } else { //condition isn't met i = 2; } which I find not good enough as comments are located at different levels, so at quick glance you would just pick up if comment and else comment would look like it belongs to some inner structure. Putting them like this: if(condition) { //check for condition i = 1; } else { //condition isn't met i = 2; } doesn't look good to me either as it would seem like the whole structure is not commented (condition might be big and take multiple lines). Something like that: //check for condition if(condition) { i = 1; //condition isn't met } else { i = 2; } would be probably the best style from comments point of view but confusing as a code structure. How do you comment such blocks?

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  • Extra fulltext ordering criteria beyond default relevance

    - by Jeremy Warne
    I'm implementing an ingredient text search, for adding ingredients to a recipe. I've currently got a full text index on the ingredient name, which is stored in a single text field, like so: "Sauce, tomato, lite, Heinz" I've found that because there are a lot of ingredients with very similar names in the database, simply sorting by relevance doesn't work that well a lot of the time. So, I've found myself sorting by a bunch of my own rules of thumb, which probably duplicates a lot of the full-text search algorithm which spits out a numerical relevance. For instance (abridged): ORDER BY [ingredient name is exactly search term], [ingredient name starts with search term], [ingredient name starts with any word from the search and contains all search terms in some order], [ingredient name contains all search terms in some order], ...and so on. Each of these is defined in the SELECT specification as an expression returning either 1 or 0, and so I order by those in sequential order. I would love to hear suggestions for: A better way to define complicated order-by criteria in one place, say perhaps in a view or stored procedure that you can pass just the search term to and get back a set of results without having to worry about how they're ordered? A better tool for this than MySQL's fulltext engine -- perhaps if I was using Sphinx or something [which I've heard of but not used before], would I find some sort of complicated config option designed to solve problems like this? Some google search terms which might turn up discussion on how to order text items within a specific domain like this? I haven't found much that's of use. Thanks for reading!

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  • how to save nested form attributes to database

    - by siulamvictor
    I am not really understand how's the nested attributes work in Rails. I have 2 models, Accounts and Users. Accounts has_many Users. When a new user filled in the form, Rails reported User(#2164802740) expected, got Array(#2148376200) Is that Rails cannot read the nested attributes from the form? How can I fix it? How can I save the data from nested attributes form to database? Thanks all~ Here are the MVCs: Account Model class Account < ActiveRecord::Base has_many :users accepts_nested_attributes_for :users validates_presence_of :company_name, :message => "companyname is required." validates_presence_of :company_website, :message => "website is required." end User Model class User < ActiveRecord::Base belongs_to :account validates_presence_of :user_name, :message => "username too short." validates_presence_of :password, :message => "password too short." end Account Controller class AccountController < ApplicationController def new end def created end def create @account = Account.new(params[:account]) if @account.save redirect_to :action => "created" else flash[:notice] = "error!!!" render :action => "new" end end end Account/new View <h1>Account#new</h1> <% form_for :account, :url => { :action => "create" } do |f| %> <% f.fields_for :users do |ff| %> <p> <%= ff.label :user_name %><br /> <%= ff.text_field :user_name %> </p> <p> <%= ff.label :password %><br /> <%= ff.password_field :password %> </p> <% end %> <p> <%= f.label :company_name %><br /> <%= f.text_field :company_name %> </p> <p> <%= f.label :company_website %><br /> <%= f.text_field :company_website %> </p> <% end %> Account Migration class CreateAccounts < ActiveRecord::Migration def self.up create_table :accounts do |t| t.string :company_name t.string :company_website t.timestamps end end def self.down drop_table :accounts end end User Migration class CreateUsers < ActiveRecord::Migration def self.up create_table :users do |t| t.string :user_name t.string :password t.integer :account_id t.timestamps end end def self.down drop_table :users end end Thanks everyone. :)

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  • Error when creating JFrame from JFrame

    - by Aly
    Hi, I have an application that is works fine and the JFrame for it is launched in the constructor of a GameInitializer class which takes in some config parameters. I have tried to create a GUI in which allows the user to specify these config parameters and then click submit. When the user clicks submit a new GameInitializer object is created. The error I am getting is: Exception in thread "AWT-EventQueue-0" java.lang.Error: Cannot call invokeAndWait from the event dispatcher thread at java.awt.EventQueue.invokeAndWait(Unknown Source) at javax.swing.SwingUtilities.invokeAndWait(Unknown Source) at game.player.humanplayer.view.HumanView.update(HumanView.java:43) once submit is called this code is executed: values assigned to parames... new GameInitializer(userName, player, Constants.BLIND_STRUCTURE_FILES.get(blindStructure), handState); Then code in the GameInitializer constructor is: public GameInitializer(String playerName, AbstractPlayer opponent, String blindStructureConfig, AbstractHandState handState){ beginGame(playerName, opponent, blindStructureConfig, handState); } public static void beginGame(String playerName, AbstractPlayer opponent, String blindStructureConfig, AbstractHandState handState){ AbstractDealer dealer; BlindStructure.initialize(blindStructureConfig); AbstractPlayer humanPlayer = new HumanPlayer(playerName, handState); AbstractPlayer[] players = new AbstractPlayer[2]; players[0] = humanPlayer; players[1] = opponent; handState.setTableLayout(players); for(AbstractPlayer player : players){ player.initialize(); } dealer = new Dealer(players, handState); dealer.beginGame(); } It basically cascades down and eventually calls this piece of code in the HumanView class: public void update(final Event event, final ReadableHandState handState, final AbstractPlayer player) { try { SwingUtilities.invokeAndWait(new Runnable() { public void run() { gamePanel.update(event, handState, player); validate(); } }); } catch (InterruptedException e) { e.printStackTrace(); } catch (InvocationTargetException e) { e.printStackTrace(); } if(event.equals(Event.HAND_ENDING)){ try { if(handState.wonByShowdown() || handState.isSplitPot()){ Thread.sleep(3500); } else{ Thread.sleep(1000); } } catch (InterruptedException e) { e.printStackTrace(); } } } Do you have any idea why?

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  • Previously working emberjs1.0-pre form on jsfiddle returns "error": "Please use POST request"

    - by brg
    This code ** http://jsfiddle.net/wagenet/ACzaJ/8/ ** was working a few days ago, when i returned to it today, it throws {"error": "Please use POST request"}, when i click add button Also the jsfiddle editor.js always throws exception on this line: function stop(){cc = stop; throw StopIteration;}; Does anyone knows the cause of this issue. Many thanks Update 1 Based on @Peter Wagenet's suggestions below, the form now logs entries or inputs to the console but it doesn't display on the result section of jsfiddle instead what is displayed on jsfiddle result section or page is still this error {"error": "Please use POST request"} ** http://jsfiddle.net/ACzaJ/18/ Update 2 In this fiddle, http://jsfiddle.net/ACzaJ/19/, i have successfully eliminated this error {"error": "Please use POST request"} by adding event.preventDefault(); to the submit action in Todos.TodoFormView. That allows us to use arbitrary view methods as action handlers. The existing issue is that the input to the form, only displays on the console and not on jsfiddle result section, though no error displays on the result section, there is a new error appearing in the console of the updated fiddle: Uncaught Error: Cannot perform operations on a Metamorph that is not in the DOM. Finally solved I needed to comment out App.initialize() for it to work as expected. This the working fiddle ** http://jsfiddle.net/ACzaJ/20/. I don't know why that is so, but my guess is that, App.initialize works with other parts like the router for routing, ApplicationController and ApplicationView with {{outlet}} in the handlebars, which i didn't need for this fiddle. Finally Finally and completely solved This ** http://jsfiddle.net/tQWn8/ works with App.initialize. But you have to declare all those components above and pass the router to App.initialize, like this App..initialize(router). If you don't do this, then you will get the old error Uncaught Error: Cannot perform operations on a Metamorph that is not in the DOM.

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  • Enable MEX in a Web.Config

    - by Conor
    Hi Folks, How do I enable/create a MEX endpoint in the below web config so I can view the service from my browser? I have tried a few variation from googling but VS always complains about it. (not a valid child element etc...) <configuration> <system.web> <compilation debug="true" targetFramework="4.0" /> </system.web> <system.serviceModel> <serviceHostingEnvironment aspNetCompatibilityEnabled="true"/> <services> <service name="MyApp.MyService" behaviorConfiguration="WebServiceBehavior"> <endpoint address="" binding="webHttpBinding" contract="MyApp.IMyService" behaviorConfiguration="JsonBehavior"> <identity> <dns value="localhost"/> </identity> </endpoint> </service> </services> <behaviors> <endpointBehaviors> <behavior name="JsonBehavior"> <webHttp/> </behavior> </endpointBehaviors> </behaviors> </system.serviceModel> </configuration> Cheers, Conor

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  • Spring ROO issue with UrlRewrite in STS (eclipse)

    - by user224270
    Hi. I'm having trouble figuring out how to solve this issue. I have a file called: "urlrewrite.xml" which was automatically generated by spring ROO after running the "controller" command in ROO Shell. However, I still get the following error: "Referenced file contains errors (http://tuckey.org/res/dtds/urlrewrite3.0.dtd). For more information, right click on the message in the Problems View and select "Show Details..." Here's the content of the urlrewrite.xml file: <?xml version="1.0" encoding="utf-8"?> <!DOCTYPE urlrewrite PUBLIC "-//tuckey.org//DTD UrlRewrite 3.0//EN" "http://tuckey.org/res/dtds/urlrewrite3.0.dtd"> <urlrewrite default-match-type="wildcard"> <rule> <from>/resources/**</from> <to last="true">/resources/$1</to> </rule> <rule> <from>/static/WEB-INF/**</from> <set type="status">403</set> <to last="true">/static/WEB-INF/$1</to> </rule> <rule> <from>/static/**</from> <to last="true">/$1</to> </rule> <rule> <from>/</from> <to last="true">/app/index</to> </rule> <rule> <from>/app/**</from> <to last="true">/app/$1</to> </rule> <rule> <from>/**</from> <to>/app/$1</to> </rule> <outbound-rule> <from>/app/**</from> <to>/$1</to> </outbound-rule> </urlrewrite> Any thoughts on how to get rid of this error?

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  • safely hosting a django project over apache using centos

    - by tipu
    Error can be seen at: http://djaffry.selfip.com:8080/ I had a project working great, but I had all the files under /var/www/ and with my limited understanding it's bad, according to django's site: "If your background is in PHP, you’re probably used to putting code under the Web server’s document root (in a place such as /var/www). With Django, you don’t do that. It’s not a good idea to put any of this Python code within your Web server’s document root, because it risks the possibility that people may be able to view your code over the Web. That’s not good for security. Put your code in some directory outside of the document root, such as /home/mycode." So I went to /home/tipu/stuff/ and executed django-admin.py startproject twingle. Then I went to apache and did <VirtualHost *:8080> ServerName tweet_search_engine DocumentRoot /home/tipu/stuff/twingle/ </VirtualHost> <Directory /home/tipu/stuff/twingle> SetHandler python-program PythonHandler django.core.handlers.modpython SetEnv DJANGO_SETTINGS_MODULE settings PythonOption django.root /home/tipu/stuff/twingle PythonDebug On PythonPath "['/home/tipu/stuff/', '/home/tipu/stuff/twingle/'] + sys.path" </Directory> Now I am getting a 403 Forbidden error.. any idea what I'm doing wrong? I'm newer to Linux (CentOS) and django, so I could be over looking some very simple things.

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  • Character Encoding: â??

    - by akaphenom
    I am trying to piece together the mysterious string of characters â?? I am seeing quite a bit of in our database - I am fairly sure this is a result of conversion between character encodings, but I am not completely positive. The users are able to enter text (or cut and paste) into a Ext-Js rich text editor. The data is posted to a severlet which persists it to the database, and when I view it in the database i see those strange characters... is there any way to decode these back to their original meaning, if I was able to discover the correct encoding - or is there a loss of bits or bytes that has occured through the conversion process? Users are cutting and pasting from multiple versions of MS Word and PDF. Does the encoding follow where the user copied from? Thank you website is UTF-8 We are using ms sql server 2005; SELECT serverproperty('Collation') -- Server default collation. Latin1_General_CI_AS SELECT databasepropertyex('xxxx', 'Collation') -- Database default SQL_Latin1_General_CP1_CI_AS and the column: Column_name Type Computed Length Prec Scale Nullable TrimTrailingBlanks FixedLenNullInSource Collation text varchar no -1 yes no yes SQL_Latin1_General_CP1_CI_AS The non-Unicode equivalents of the nchar, nvarchar, and ntext data types in SQL Server 2000 are listed below. When Unicode data is inserted into one of these non-Unicode data type columns through a command string (otherwise known as a "language event"), SQL Server converts the data to the data type using the code page associated with the collation of the column. When a character cannot be represented on a code page, it is replaced by a question mark (?), indicating the data has been lost. Appearance of unexpected characters or question marks in your data indicates your data has been converted from Unicode to non-Unicode at some layer, and this conversion resulted in lost characters. So this may be the root cause of the problem... and not an easy one to solve on our end.

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  • drupal_add_css not working

    - by hfidgen
    Hiya, I need to use drupal_add_css to call stylesheets onto single D6 pages. I don't want to edit the main theme stylesheet as there will be a set of individual pages which all need completely new styles - the main sheet would be massive if i put it all in there. My solution was to edit the page in PHP editor mode and do this: <?php drupal_add_css("/styles/file1.css", "theme"); ?> <div id="newPageContent">stuff here in html</div> But when i view source, there is nothing there! Not even a broken css link or anything, it's just refusing to add the css sheet to the css package put into the page head. Variations don't seem to work either: drupal_add_css($path = '/styles/file1.css', $type = 'module', $media = 'all', $preprocess = TRUE) My template header looks like this, i've not changed anything from the default other than adding a custom JS. <head> <?php print $head ?> <title><?php print $head_title ?></title> <?php print $styles ?> <?php print $scripts ?> <script type="text/javascript" src="<?php print base_path() ?>misc/askme.js"></script> <!--[if lt IE 7]> <?php print phptemplate_get_ie_styles(); ?> <![endif]--> </head> Can anyone think of a reason why this function is not working? Thanks!

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  • Multiple Out-of-Browser Applications in One Application

    - by Otaku
    I'm looking at a scenario where I need to create a single "master" Silverlight application and then add "child" applications for an out-of-browser Silverlight application. The scenario is something like this. A user will visit a gameboard web site and choose a game to play. Let's call it Checkers. He likes it, so then he installs the out-of-browser app to his desktop. He then finds Chess, and installs that too. For both games, while played on the site, he has stats (games played, win/loss records, etc.). For each game on the site, he navigates to a different page. But now he wants to play offline and view his stats and other cross-games information. He wants to have a single app to launch to play either game. From his single out-of-browser app, he sees that Go is also available, and he places a checkmark against it to download on his next connection. Does anyone have any experience at developing multiple out-of-browser Silverlight apps that reside within a single master app? What considerations need to be had for this type of design? How would this work in terms of install experience from different web pages?

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  • AVAudioPlayer making noise when playing multiple sounds at the same time

    - by Rob
    I am having an issue where AVAudioPlayer is introducing noise into playback ONLY when I play multiple sound files at the same time. If I play them each individually, they all sound perfect. But, if I play sound clip B while sound clip A is still playing, the speakers start crackling like there is noise. I have tried both m4a files AND caf files and both make the same noise, so it has to be something with how I am implementing this method or a quirk with AVAudioPlayer. Any insights? code I am using: UITouch* touch = [[event allTouches] anyObject]; NSString* filename = [soundArray objectAtIndex:[touch view].tag]; NSString *path = [[NSBundle mainBundle] pathForResource:filename ofType:@"m4a"]; AVAudioPlayer * newAudio=[[AVAudioPlayer alloc] initWithContentsOfURL:[NSURL fileURLWithPath:path] error:NULL]; self.theAudio = newAudio; // automatically retain audio and dealloc old file if new m4a file is loaded [newAudio release]; // release the audio safely theAudio.delegate = self; [theAudio prepareToPlay]; [theAudio setNumberOfLoops:0]; [theAudio setVolume: volumeLevel]; [theAudio play];

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  • Blurry UILabel as programmatic subview of UITableViewCell contentView

    - by Alex Reynolds
    I am adding a UILabel instance as a subview of my custom UITableViewCell instance's contentView. When I select the cell, the row is highlighted blue, except for the background of the label. The label text is sharp. When I set the label and content view backgroundColor property to [UIColor clearColor], the label text becomes blurry. How do I set the label background color to be clear, to allow the row highlight to come through, while still keeping the label text sharp? One suggestion I read elsewhere was to round the label's frame values, but this did not have any effect. CODE Here is a snippet of my custom UITableViewCell subview's -setNeedsLayout method: UILabel *_objectTitleLabel = [[UILabel alloc] initWithFrame:CGRectNull]; _objectTitleLabel.text = [self.awsObject cleanedKey]; _objectTitleLabel.font = [UIAppDelegate defaultObjectLabelFont]; _objectTitleLabel.highlightedTextColor = [UIColor clearColor]; //[UIAppDelegate defaultLabelShadowTint]; _objectTitleLabel.backgroundColor = [UIColor clearColor]; //[UIAppDelegate defaultWidgetBackgroundTint]; _objectTitleLabel.frame = CGRectMake( kCellImageViewWidth + 2.0 * self.indentationWidth, 0.5 * (self.tableView.rowHeight - 1.5 * kCellLabelHeight) + kCellTitleYPositionNudge, contentViewWidth, kCellLabelHeight ); _objectTitleLabel.frame = CGRectIntegral(_objectTitleLabel.frame); _objectTitleLabel.tag = kObjectTableViewCellTitleSubviewType; //NSLog(@"_objectTitleLabel: %@", NSStringFromCGRect(_objectTitleLabel.frame)); [self.contentView addSubview:_objectTitleLabel]; [_objectTitleLabel release], _objectTitleLabel = nil; ... self.contentView.backgroundColor = [UIAppDelegate defaultWidgetBackgroundTint]; self.contentView.clearsContextBeforeDrawing = YES; self.contentView.autoresizesSubviews = YES; self.contentView.clipsToBounds = YES; self.contentView.contentMode = UIViewContentModeRedraw;

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  • How i zoom perticular part of UIScrollView?

    - by Rajendra Bhole
    HI, I develop an application in which i want to implement the splash screen, on that splash screen i want to bind the scrollView and UIImage. My code as follow, -(void)splashAnimation{ window = [[UIWindow alloc] initWithFrame:CGRectMake(0, 0, 320, 420)]; //scrollView = [[UIScrollView alloc] initWithFrame:[[UIScreen mainScreen] applicationFrame]]; scrollView = [[UIScrollView alloc] initWithFrame:[window bounds]]; scrollView.pagingEnabled = NO; scrollView.bounces = NO; UIImage *image = [UIImage imageNamed:@"splash.png"]; UIImageView *imageView = [[UIImageView alloc] initWithImage:image]; imageView.userInteractionEnabled = NO; [scrollView addSubview:imageView]; [scrollView setDelegate:self]; //[scrollView release]; } - (void)applicationDidFinishLaunching:(UIApplication *)application { [self splashAnimation]; [self initControllers]; [window addSubview:[mainTabBarController view]]; [window makeKeyAndVisible]; } On my given code the one blank window comes up and stay on. I want to on that blank screen bind my splash.png. *The Above problem is solved* My current code is scrollView.pagingEnabled = NO; scrollView.bounces = NO; UIImage *image = [UIImage imageNamed:@"splash.png"]; UIImageView *imageView = [[UIImageView alloc] initWithImage:image]; imageView.userInteractionEnabled = NO; [scrollView addSubview:imageView]; scrollView.maximumZoomScale = 4.0f; scrollView.minimumZoomScale = 1.0f; CGRect rect = CGRectMake(119, 42, 208, 166); [scrollView zoomToRect:rect animated:YES]; [scrollView setDelegate:self]; [window addSubview:scrollView]; [window makeKeyAndVisible]; i want to zoom the particular part of scrollView.

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  • In JQGrid I want to add a row button that doesnt post back.

    - by snyder
    The buttons I have added to the rows still post back even if I specifiy not to do so in the onclick method of the button (onclick=' return false;'). I supose its the grid doing the post back? I am tring to prevent the postback and show my own custom popup forms. gridComplete: function(){ var ids = $('#jqGridControl1').jqGrid('getDataIDs'); for(var i=0;i < ids.length;i++){ var rowid = ids[i]; de = "<input type='image' title='Delete this record.' src='../images/icn_delete.gif' onclick=' return false;' style='border-width:0px;'/>"; ee = "<input type='image' title='Edit this record.' src='../images/icn_edit.gif' onclick=' return false;' style='border-width:0px;' />"; ve = "<input type='image' title='View related information.' src='../images/house.gif' onclick='return false;' style='border-width:0px;' />"; pe = "<input type='image' title='Print' src='../images/icn_printer.gif' onclick=' return false;' style='border-width:0px;' />"; je = "<input type='image' title='Appointment' src='../images/icn_journal.gif' onclick=' return false;' style='border-width:0px;' />"; se = "<input type='image' title='Select' src='../images/icn_select.gif' onclick=' return false;' style='border-width:0px;' />"; jQuery('#jqGridControl1').jqGrid('setRowData',ids[i],{act:de+ee+ve+pe+je+se}); }

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  • Creating a UIImage from a rotated UIImageView...

    - by Magic Bullet Dave
    I have a UIImageView with an image in it. I have rotated the image prior to display by setting the transform property of the UIImageView to CGAffineTransformMakeRotation(angle) where angle is the angle in radians. I want to be able to create another UIImage that corresponds to the rotated version that I can see in my view. I am almost there, by rotating the image context I get a rotated image: - (UIImage *) rotatedImageFromImageView: (UIImageView *) imageView { UIImage *rotatedImage; // Get image width, height of the bonuding rectangle CGRect boundingRect = [self getBoundingRectAfterRotation: imageView.bounds byAngle:angle]; // Create a graphics context the size of the boundinf rectangle UIGraphicsBeginImageContext(boundingRect.size); CGContextRef context = UIGraphicsGetCurrentContext(); // Rotate and translate the context CGAffineTransform ourTransform = CGAffineTransformIdentity; ourTransform = CGAffineTransformConcat(ourTransform, CGAffineTransformMakeRotation(angle)); CGContextConcatCTM(context, ourTransform); // Draw the image into the context CGContextDrawImage(context, CGRectMake(0, 0, imageView.image.size.width, imageView.image.size.height), imageView.image.CGImage); // Get an image from the context rotatedImage = [UIImage imageWithCGImage: CGBitmapContextCreateImage(context)]; // Clean up UIGraphicsEndImageContext(); return rotatedImage; } However the image is not rotated about its centre. I have tried all kinds of transforms concatenated with my rotate to get it to rotate around the centre but to no avail. Am I missing a trick? Is this even possible since I am rotating the context not the image? Getting desperate to make this work now, so any help would be appreciated. Dave

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  • django customizing form labels

    - by Henri
    I have a problem in customizing labels in a Django form This is the form code in file contact_form.py: from django import forms class ContactForm(forms.Form): def __init__(self, subject_label="Subject", message_label="Message", email_label="Your email", cc_myself_label="Cc myself", *args, **kwargs): super(ContactForm, self).__init__(*args, **kwargs) self.fields['subject'].label = subject_label self.fields['message'].label = message_label self.fields['email'].label = email_label self.fields['cc_myself'].label = cc_myself_label subject = forms.CharField(widget=forms.TextInput(attrs={'size':'60'})) message = forms.CharField(widget=forms.Textarea(attrs={'rows':15, 'cols':80})) email = forms.EmailField(widget=forms.TextInput(attrs={'size':'60'})) cc_myself = forms.BooleanField(required=False) The view I am using this in looks like: def contact(request, product_id=None): . . . if request.method == 'POST': form = contact_form.ContactForm(request.POST) if form.is_valid(): . . else: form = contact_form.ContactForm( subject_label = "Subject", message_label = "Your Message", email_label = "Your email", cc_myself_label = "Cc myself") The strings used for initializing the labels will eventually be strings dependent on the language, i.e. English, Dutch, French etc. When I test the form the email is not sent and instead of the redirect-page the form returns with: <QueryDict: {u'cc_myself': [u'on'], u'message': [u'message body'], u'email':[u'[email protected]'], u'subject': [u'test message']}>: where the subject label was before. This is obviously a dictionary representing the form fields and their contents. When I change the file contact_form.py into: from django import forms class ContactForm(forms.Form): """ def __init__(self, subject_label="Subject", message_label="Message", email_label="Your email", cc_myself_label="Cc myself", *args, **kwargs): super(ContactForm, self).__init__(*args, **kwargs) self.fields['subject'].label = subject_label self.fields['message'].label = message_label self.fields['email'].label = email_label self.fields['cc_myself'].label = cc_myself_label """ subject = forms.CharField(widget=forms.TextInput(attrs={'size':'60'})) message = forms.CharField(widget=forms.Textarea(attrs={'rows':15, 'cols':80})) email = forms.EmailField(widget=forms.TextInput(attrs={'size':'60'})) cc_myself = forms.BooleanField(required=False) i.e. disabling the initialization then everything works. The form data is sent by email and the redirect page shows up. So obviously something the the init code isn't right. But what? I would really appreciate some help.

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  • Segment register, IP register and memory addressing issue!

    - by Zia ur Rahman
    In the following text I asked two questions and I also described that what I know about these question so that you can understand my thinking. Your precious comments about the below text are required. Below is the Detail of 1ST Question As we know that if we have one mega byte memory then we need 20 bits to address this memory. Another thing is each memory cell has a physical address which is of 20 bits in 1Mb memory. IP register in IAPX88 is of 16 bits. Now my point of view is, we can not access the memory at all by the IP register because the memory need 20 bit address to be addressed but the IP register is of 16 bits. If we have a memory of 64k then IP register can access this memory because this memory needs 16 bits to be addressed. But incase of 1mb memory IP can’t.tell me am i right or not if not why? Suppose physical address of memory is 11000000000000000101 Now how can we access this memory location by 16 bits. Below is the detail of Next Question: My next question is , suppose IP register is pointing to memory location, and the segment register is also pointing to a memory location (start of the segment), the memory is of 1MB, how we can access a memory location by these two 16 bit registers tell me the sequence of steps how the 20 bits addressable memory location is accessed . If your answer is, we take the segment value and we shift it left by 4 bits and then add the IP value into it to get the 20 bits address, then this raises another question that is the address bus (the address bus should be 20 bits wide), the registers both the segment register and the IP register are of 16 bits each , now if address bus is 20 bits wide then this means that the address bus is connected to both these registers. If its not the case then another thing that comes into my mind is that both these registers generate a 20 bit address and there would be a register which can store 20 bits and this register would be connected to both these register and the address bus as well.

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