I need to transform a list into dictionary as follows. The odd elements has the key, and even number elements has the value.

x = (1,'a',2,'b',3,'c') -> {1: 'a', 2: 'b', 3: 'c'}

def set(self, val_): 
        i = 0 
        for val in val_: 
            if i == 0: 
                i = 1 
                key = val 
            else: 
                i = 0 
                self.dict[key] = val 

My solution seems to long, is there a better way to get the same results?