How do I assert that two arbitrary type objects are equivalent, without requiring them to be equal?

Posted by Tomas Lycken on Stack Overflow See other posts from Stack Overflow or by Tomas Lycken
Published on 2010-04-12T14:26:22Z Indexed on 2010/04/12 15:43 UTC
Read the original article Hit count: 285

Filed under:
|
|
|

To accomplish this (but failing to do so) I'm reflecting over properties of an expected and actual object and making sure their values are equal. This works as expected as long as their properties are single objects, i.e. not lists, arrays, IEnumerable... If the property is a list of some sort, the test fails (on the Assert.AreEqual(...) inside the for loop).

public void WithCorrectModel<TModelType>(TModelType expected, string error = "") 
    where TModelType : class
{
    var actual = _result.ViewData.Model as TModelType;
    Assert.IsNotNull(actual, error);
    Assert.IsInstanceOfType(actual, typeof(TModelType), error);
    foreach (var prop in typeof(TModelType).GetProperties())
    {
        Assert.AreEqual(prop.GetValue(expected, null), prop.GetValue(actual, null), error);
    }
}

If dealing with a list property, I would get the expected results if I instead used CollectionAssert.AreEquivalent(...) but that requires me to cast to ICollection, which in turn requries me to know the type listed, which I don't (want to).
It also requires me to know which properties are list types, which I don't know how to.

So, how should I assert that two objects of an arbitrary type are equivalent?

Note: I specifically don't want to require them to be equal, since one comes from my tested object and one is built in my test class to have something to compare with.

© Stack Overflow or respective owner

Related posts about c#

Related posts about unit-testing