Perl standard input with argument inside Bash
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            by neversaint
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        Published on 2010-04-12T08:16:20Z
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            2010/04/12
            8:23 UTC
        
        
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I want to have such pipe in bash
#! /usr/bin/bash
cut -f1,2 file1.txt | myperl.pl foo | sort -u 
Now in myperl.pl 
it has content like this
my $argv = $ARG[0] || "foo";
while (<>) {
 chomp;
 if ($argv eq "foo") {
  # do something with $_
 }
 else {
   # do another
 }
}
But why the Perl script can't recognize the parameter passed through bash? Namely the code break with this message:
Can't open foo: No such file or directory at myperl.pl line 15.
What the right way to do it so that my Perl script can receive standard input and parameter at the same time?
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