PHP preg_match to get function-like string

Posted by pistacchio on Stack Overflow See other posts from Stack Overflow or by pistacchio
Published on 2010-04-28T10:31:44Z Indexed on 2010/04/28 10:33 UTC
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Filed under:

php

|

regex

Hi to all,

if I have a string like 'foo(bar)', with the following code i can almost parse it the way i want:

$results = array();
preg_match( "/\w*(?=(\(.*\))?)/", 'foo(bar)', &$results );
print_r($results);

/*    
Array
(
    [0] => foo
    [1] => (bar)
)
*/

How can I modify the regex to have bar instead of (bar)? Thanks

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