Mutable global variables don't get hide in python functions, right?
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by aXqd
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Published on 2010-05-06T14:11:05Z
Indexed on
2010/05/06
14:18 UTC
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Filed under:
python
|python-3.x
Please see the following code:
def good():
foo[0] = 9 # why this foo isn't local variable who hides the global one
def bad():
foo = [9, 2, 3] # foo is local, who hides the global one
for func in [good, bad]:
foo = [1,2,3]
print('Before "{}": {}'.format(func.__name__, foo))
func()
print('After "{}": {}'.format(func.__name__, foo))
The result is as below:
# python3 foo.py
Before "good": [1, 2, 3]
After "good": [9, 2, 3]
Before "bad" : [1, 2, 3]
After "bad" : [1, 2, 3]
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