getting Ceil() of Decimal in python?

Posted by Gunjan on Stack Overflow See other posts from Stack Overflow or by Gunjan
Published on 2010-05-08T22:51:39Z Indexed on 2010/05/08 22:58 UTC
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python

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decimal

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ceil

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rounding

Is there a way to get the ceil of a high precision Decimal in python?

>>> import decimal;
>>> decimal.Decimal(800000000000000000001)/100000000000000000000
Decimal('8.00000000000000000001')
>>> math.ceil(decimal.Decimal(800000000000000000001)/100000000000000000000)
8.0

math rounds the value and returns non precise value

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