How can I create a new Person object correctly in Javascript?

Posted by TimDog on Stack Overflow See other posts from Stack Overflow or by TimDog
Published on 2010-05-26T22:38:40Z Indexed on 2010/05/26 22:51 UTC
Read the original article Hit count: 285

Filed under:
|

I'm still struggling with this concept. I have two different Person objects, very simply:

;Person1 = (function() {
    function P (fname, lname) {
        P.FirstName = fname;
        P.LastName = lname;
        return P;
    }
    P.FirstName = '';
    P.LastName = '';
    var prName = 'private';
    P.showPrivate = function() { alert(prName); };
    return P;
})();

;Person2 = (function() {
    var prName = 'private';
    this.FirstName = '';
    this.LastName = ''; 
    this.showPrivate = function() { alert(prName); };
    return function(fname, lname) {
        this.FirstName = fname;
        this.LastName = lname;
    }   
})();

And let's say I invoke them like this:

var s = new Array();

//Person1
s.push(new Person1("sal", "smith"));
s.push(new Person1("bill", "wonk"));
alert(s[0].FirstName);
alert(s[1].FirstName);
s[1].showPrivate();

//Person2
s.push(new Person2("sal", "smith"));
s.push(new Person2("bill", "wonk"));
alert(s[2].FirstName);
alert(s[3].FirstName);
s[3].showPrivate();

The Person1 set alerts "bill" twice, then alerts "private" once -- so it recognizes the showPrivate function, but the local FirstName variable gets overwritten.

The second Person2 set alerts "sal", then "bill", but it fails when the showPrivate function is called. The new keyword here works as I'd expect, but showPrivate (which I thought was a publicly exposed function within the closure) is apparently not public.

I want to get my object to have distinct copies of all local variables and also expose public methods -- I've been studying closures quite a bit, but I'm still confused on this one. Thanks for your help.

© Stack Overflow or respective owner

Related posts about JavaScript

Related posts about closures