How can I list the numbers 01 to 12 (one for each of the 12 months) in such a way so that the current month always comes last where the oldest one is first. In other words, if the number is grater than the current month, it's from the previous year.

e.g. 02 is Feb, 2011 (the current month right now), 03 is March, 2010 and 09 is Sep, 2010 but 01 is Jan, 2011. In this case, I'd like to have [09, 03, 01, 02]. This is what I'm doing to determine the year:

for inFile in os.listdir('.'):
    if inFile.isdigit():
    month = months[int(inFile)]
       if int(inFile) <= int(strftime("%m")):
           year = strftime("%Y")
       else:
           year = int(strftime("%Y"))-1
       mnYear = month + ", " + str(year)

I don't have a clue what to do next. What should I do here?

I think, I better upload the entire script for better understanding.

#!/usr/bin/env python

import os, sys
from time import strftime
from calendar import month_abbr

vGroup = {}
vo = "group_lhcb"
SI00_fig = float(2.478)
months = tuple(month_abbr)

print "\n%-12s\t%10s\t%8s\t%10s" % ('VOs','CPU-time','CPU-time','kSI2K-hrs')
print "%-12s\t%10s\t%8s\t%10s" % ('','(in Sec)','(in Hrs)','(*2.478)')
print "=" * 58

for inFile in os.listdir('.'):
    if inFile.isdigit():
        readFile = open(inFile, 'r')
        lines = readFile.readlines()
        readFile.close()

        month = months[int(inFile)]
        if int(inFile) <= int(strftime("%m")):
            year = strftime("%Y")
        else:
            year = int(strftime("%Y"))-1
        mnYear = month + ", " + str(year)

        for line in lines[2:]:
            if line.find(vo)==0:
                g, i = line.split()
                s = vGroup.get(g, 0)
                vGroup[g] = s + int(i)

        sumHrs = ((vGroup[g]/60)/60)
        sumSi2k = sumHrs*SI00_fig
        print "%-12s\t%10s\t%8s\t%10.2f" % (mnYear,vGroup[g],sumHrs,sumSi2k)
        del vGroup[g]

When I run the script, I get this:

[root@serv07 usage]# ./test.py 

VOs               CPU-time  CPU-time     kSI2K-hrs
                  (in Sec)  (in Hrs)      (*2.478)
==================================================
Jan, 2011        211201372     58667     145376.83
Dec, 2010          5064337      1406       3484.07
Feb, 2011         17506049      4862      12048.04
Sep, 2010        210874275     58576     145151.33

As I said in the original post, I like the result to be in this order instead:

Sep, 2010        210874275     58576     145151.33
Dec, 2010          5064337      1406       3484.07
Jan, 2011        211201372     58667     145376.83
Feb, 2011         17506049      4862      12048.04

The files in the source directory reads like this:

[root@serv07 usage]# ls -l
total 3632
-rw-r--r--  1 root root 1144972 Feb  9 19:23 01
-rw-r--r--  1 root root  556630 Feb 13 09:11 02
-rw-r--r--  1 root root  443782 Feb 11 17:23 02.bak
-rw-r--r--  1 root root 1144556 Feb 14 09:30 09
-rw-r--r--  1 root root  370822 Feb  9 19:24 12

Did I give a better picture now? Sorry for not being very clear in the first place. Cheers!!

This is the result from Mark's suggestion:

[root@serv07 usage]# ./test.py 

VOs               CPU-time  CPU-time     kSI2K-hrs
                  (in Sec)  (in Hrs)      (*2.478)
==========================================================
Dec, 2010          5064337      1406       3484.07
Sep, 2010        210874275     58576     145151.33
Feb, 2011         17506049      4862      12048.04
Jan, 2011        211201372     58667     145376.83

As I said before, I'm looking for the result to b printed in this order: Sep, 2010 -> Dec, 2010 -> Jan, 2011 -> Feb, 2011 Cheers!!