Execute function without sending 'self' to it

Posted by Sergey on Stack Overflow See other posts from Stack Overflow or by Sergey
Published on 2011-03-15T14:38:41Z Indexed on 2011/03/16 16:10 UTC
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Is that possible to define a function without referencing to self this way?

def myfunc(var_a,var_b)

But so that it could also get sender data, like if I defined it like this:

def myfunc(self, var_a,var_b)

That self is always the same so it looks a little redundant here always to run a function this way: myfunc(self,'data_a','data_b'). Then I would like to get its data in the function like this sender.fields.

UPDATE: Here is some code to understand better what I mean. The class below is used to show a page based on Jinja2 templates engine for users to sign up.

class SignupHandler(webapp.RequestHandler):
    def get(self, *args, **kwargs):
        utils.render_template(self, 'signup.html')

And this code below is a render_template that I created as wrapper to Jinja2 functions to use it more conveniently in my project:

def render_template(response, template_name, vars=dict(), is_string=False):
    template_dirs = [os.path.join(root(), 'templates')]
    logging.info(template_dirs[0])
    env = Environment(loader=FileSystemLoader(template_dirs))
    try:
        template = env.get_template(template_name)
    except TemplateNotFound:
        raise TemplateNotFound(template_name)
    content = template.render(vars)
    if is_string:
        return content
    else:
        response.response.out.write(content)

As I use this function render_template very often in my project and usually the same way, just with different template files, I wondered if there was a way to get rid of having to call it like I do it now, with self as the first argument but still having access to that object.

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